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यदि `x=222,y=223,z=225` हो तो `x^(3)+y^(3)+z^(3)-3xyz` का मान क्या है?A. 4590B. 4690C. 4950D. 4960 |
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Answer» Correct Answer - B `x^(3)+y^(3)+z^(3)-3xyz=1/2(x+y+` `z)[(x-y)^(2)+(y-z)^(2)+(z-x)^(2)]` `=1/2(222+223+225) (222-223)^(2)` `+(223-225)^(2)+(225-222)^(2)]` `=1/2(970)[1+4+9]` `=1/2(670)[1+4+9]` `=1/2xx670xx14=4690` |
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