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यदि `x=(4ab)/(a+b)a!=b` है तो `(x+2a)/(x-2a)+(x+2b)/(x-2b)` का मान ज्ञात करें?A. aB. bC. 2abD. 2 |
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Answer» Correct Answer - D `x=(4ab)/(a+b)` `implies x/(2a)=(2b)/(a+b)` `(x+2a)/(x-2a)=(2b+a+b)/(2b-a-b)=(3b+a)/(b-a)` (By C-D rule) `implies` again `x/(2b)=(2a)/(a+b)` `(x+2b)(x-2b)=(2a+a+b)/(2a-a-b)=(3a+b)/(a-b)` `implies (x+2a)/(x-2a)+(x+2b)/(x-2b)=(3b+a)/(b-a)+(3a+b)/(a-b)` `implies (3b+a-3a-b)/(b-a)` `(2b-2a)/(b-a)=(2(b-a))/((b-a))=2` |
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