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यदि `x=y=333` और `z=34` है तो `x^(3)+y^(3)+z^(3)-3xyz` का मान क्या होगा? |
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Answer» Correct Answer - C `x=y=333,z=334` `implies x^(3)+y^(3)+z^(3)-3xyz=1/2` `(x+y+z)((x-y)^(2)+(y-z)^(2)+(z-x)^(2))` `implies 1/2(333+333+334)[(333-333)^(2)+(333-334)^(2)+(334-333)^(2)]` `implies 1/2(1000)(0+1+1)=1000` |
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