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यदि `x=z=225` और `y=226` है तो `x^(3)+y^(3)+z^(3)-3xyz` का मान ज्ञात करें।A. 765B. 676C. 674D. 576 |
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Answer» Correct Answer - B According to the question `:, x=z=225` `y=226` `implies x^(3)+y^(3)+z^(3)-3xyz=?` `x^(3)+y^(3)+z^(3)-3xyz=1/2(x+y+z)` `[(x-y)^(2)+(y-z)^(2)+(z-x)^(2)]` `=1/2[225+225+226][(225-226)^(2)+` `(+226-225)^(2)+(225-225)^(2)]` `=676/2xx[1+1+0]=676` |
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