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यदि `xy+yz+zx=0`, तो `(1/(x^(2)-yz)+1/(y^(2)-zx)+1/(z^(2)-xy)) (x,y,z!= 0)` किसके बराबर है?A. 3B. 1C. `x+y+z`D. `0` |
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Answer» Correct Answer - D `xy+yz+zx=0` `:. xy+zx=-yz` `implies xy+yz=-zx` `implies yz+zx=-xy` `:. 1/(x^(2)-yz)+1/(y^(2)-zx)+1/(z^(2)-xy)` Putting values of `-yz, -zx, -xy` from above `implies 1/(x^(2)+(xy+zx))+1/(y^(2)+(xy+yx))` `+1/(z^(2)+(yx+zx))` `implies 1/(x(x+y+z))+1/(y(x+y+z)` `+1/(z(x+y+z))` `implies 1/((x+y+z))(1/x+1/y+1/z)` `implies 1/(x+z+z)((zy+xz+xy)/(xyz))` `implies 1/(x+y+z)xx0=0` |
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