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Zeroes of p(x) = x^2 - 2x - 3 are (a) 1, -3 (b) 3, -1 (c) -3, -1 (d) 1, 3 |
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Answer» 3 , -1 Ya exactly, I am getting the same answer. But in the book the answer is written as (a) 1, -3 b) 3, -1 |
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