Zeroes of polynomial of 5x2-4-8x

1.	Zeroes of polynomial of 5x2-4-8x
Answer» p(x) = 5x2 + 8x - 4 = 0=\xa05x2 + 10x - 2x - 4 = 0= 5x(x + 2) - 2(x + 2) = 0= (x + 2)(5x - 2) = 0Hence, zeroes are -2 and\xa0{tex}\\frac 25{/tex}Verification:Sum of zeroes =\xa0{tex}- 2 + \\frac { 2 } { 5 } = \\frac { - 8 } { 5 }{/tex}Product of zeroes =\xa0{tex}( - 2 ) \\times \\left( \\frac { 2 } { 5 } \\right) = \\frac { - 4 } { 5 }{/tex}Again sum of zeroes =\xa0{tex}- \\frac { \\text { Coeff. of } x } { \\text { Coeff. of } x ^ { 2 } } = \\frac { - 8 } { 5 }{/tex}Product of zeroes =\xa0{tex}\\frac { \\text { Constant term } } { \\text { Coeff. of } x ^ { 2 } }{/tex}\xa0=\xa0{tex}\\frac{-4}{5}{/tex}Verified.

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