464 + Interview Questions in ATOMS IN GENERAL AWARENESS Page 5 InterviewSolution

201.	In a sample of hydrogen atoms, all the atoms exist in two energy levels A and B. A is the ground level and B is some higher energy level. These atoms absorb photons of energy 2.7 eV and attain a higher energy level C.After this, these atoms emit photons of six different energies. Some of these photon energies are higher than 2.7 eV, some equal to 2.7 eV and some are loss than 2.7 eV. The principal quantum number corresponding to energy level B isA. 1B. 2C. 3D. 4
Answer» Correct Answer - B

Discussion

202.	In a sample of hydrogen atoms, all the atoms exist in two energy levels A and B. A is the ground level and B is some higher energy level. These atoms absorb photons of energy 2.7 eV and attain a higher energy level C.After this, these atoms emit photons of six different energies. Some of these photon energies are higher than 2.7 eV, some equal to 2.7 eV and some are loss than 2.7 eV. The principal quantum number corresponding to energy level C isA. 1B. 2C. 3D. 4
Answer» Correct Answer - D

Discussion

203.	In a sample of hydrogen atoms, all the atoms exist in two energy levels A and B. A is the ground level and B is some higher energy level. These atoms absorb photons of energy 2.7 eV and attain a higher energy level C.After this, these atoms emit photons of six different energies. Some of these photon energies are higher than 2.7 eV, some equal to 2.7 eV and some are loss than 2.7 eV. The atomic number of these atoms isA. 1B. 2C. 3D. 4
Answer» Correct Answer - A

Discussion

204.	In a sample of hydrogen atoms, all the atoms exist in two energy levels A and B. A is the ground level and B is some higher energy level. These atoms absorb photons of energy 2.7 eV and attain a higher energy level C.After this, these atoms emit photons of six different energies. Some of these photon energies are higher than 2.7 eV, some equal to 2.7 eV and some are loss than 2.7 eV. The longest wavelength emitted in the radiation spectrum observed isA. 18761 ÅB. 1216 ÅC. 6500 ÅD. 5752 Å
Answer» Correct Answer - A

Discussion

205.	What is the value of Rydberg’s constant?
Answer» The value of Rydberg’s constant : R = 1.097 x 10⁷ m^-1.

205.

What is the value of Rydberg’s constant?

Answer»

The value of Rydberg’s constant :

R = 1.097 x 10⁷ m^-1.

Discussion

206.	The total energy of an electron in the first excited state of the hydrogen atom is -3.4eV. What is the potential energy of the electron in this state ?
Answer» In `1^(st)` orbit, E=-3.4 eV Total energy `E=(KZe^(2))/(2r)-(KZe^(2))/(r )` `(KZ e^(2))/(r )=U` (say) `E=(u)/(2)-u=(-u)/(2)` `U=-2E` `therefore U=-2xx-3.4=6.8 eV`.

Discussion

207.	What is wave number of spectral line?
Answer» Wave number represents number of waves present in one metre length of the medium.

Discussion

208.	What would be the charge in radius of `n^"th"` orbit, if the mass of electron reduces to half of its original value ?
Answer» As `r prop 1/m` , therefore radius would be doubled.

Discussion

209.	Total energy of an electron in an atom is negative . What does it signify ?
Answer» Negative energy signifies that force between electron and nucleus is attractive. Electron is bound to the nucleus .

Discussion

210.	What would be the ratio of product of velocity and time period of electron orbiting in `2^"nd"` and `3^"rd"` stable orbits ?
Answer» Time period x Velocity `prop n^2` `therefore (T_2V_2)/(T_3V_3)=2^2/3^2=4/9`

Discussion

211.	with the help of Rydberg formula find the wavelength of first line of Pfund series .
Answer» `1/lambda=R(1/n_f^2- 1/n_i^2)` For first line of Pfund series, `n_i`=6 and `n_f`=5 `therefore 1/lambda=R(1/5^2-1/6^2)` `rArr lambda=900/"11R"`

Discussion

212.	The shortest wavelength which can be obtained in hydrogen spectrum `(R=10 ^(7) m^(-1))`A. 1000 ÅB. 8000 ÅC. 1300 ÅD. 2100 Å
Answer» Correct Answer - A The wavelemgth can be given as `" "(1)/(lambda)=Z^(2)R((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))` For `lambda` to the shortest `((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))` should be maximum So, `" " n_(2)=oo and n_(1)=1` Now, from Eq. (i) we get `(1)/(lambda)=R((1)/(1))rArrlambda=(1)/(R)=(1)/(10^(7))m~~ 1000Å`

Discussion

213.	Assertion Angular momentum of single electron in any orbit or hydrogen type atom is independent of the atomic number of the element. Reason In ground state angular momentum is minimumA. If both Assertion and Reason ar true and Reason is the correct explanation of Assertion.B. If both Assertion and Reason are true but Reason is not correct explanation of AssertionC. If Assertion is true by Reason is false.D. If Assertion is false but Reason is true.
Answer» Correct Answer - B `L=n((h)/(2pi))i.e.,Lpropn.` In ground state n=1 so L= minimum.

Discussion

214.	If scattering particles are `56` for `90^(@)` angle than this will be at `60^(@)` angleA. 224B. 256C. 98D. 108
Answer» Correct Answer - A Accroding to scattering formula `" " Nprop(1)/(sin^(4)(theta//2))rArr(N_(2))/(N_(1))=[(sin(theta_(1)//2))/(sin(theta_(2)//2))]^(4)` `rArr" " (N_(2))/(N_(1))=[(sin.(90^(@))/(2))/(sin.(60^(@))/(2))]^(4)=[(sin 45^(@))/(sin30^(@))]^(4)` `rArr " " N_(2)=(sqrt(2))^(4)xxN_(1)=4xx56=224`

Discussion

215.	A radioactive sample consist of two distinct spices having equal number of atoms initially. The mean life one spices is τ and that of other 5τ. The decay products in both cases are stable. The following figure shows graphs P, Q, R, S the plot of the total number of radioactive nuclei as a function of time. Which of the graphs P, Q, R and S represent the best form of the plot?(1) P (2) Q (3) R (4) S
Answer» Correct option : (4) S Explanation: Since it is the process of radioactivity decay the total number of atoms cannot remains constant (as in option 1). Also the total number of atoms cannot ever increase (as in option 2 and 3). The total number of atoms can only decrease with time. Hence option (4) is the best plot.

215.

A radioactive sample consist of two distinct spices having equal number of atoms initially. The mean life one spices is τ and that of other 5τ. The decay products in both cases are stable. The following figure shows graphs P, Q, R, S the plot of the total number of radioactive nuclei as a function of time. Which of the graphs P, Q, R and S represent the best form of the plot?(1) P (2) Q (3) R (4) S

Answer»

Correct option : (4) S

Explanation:

Since it is the process of radioactivity decay the total number of atoms cannot remains constant (as in option 1). Also the total number of atoms cannot ever increase (as in option 2 and 3). The total number of atoms can only decrease with time. Hence option (4) is the best plot.

Discussion

216.	Which of the following cannot be the value of ionisation energy for a hydrogen atom ?A. 0.85 eVB. 3.4 eVC. 1.51 eVD. 0.27 eV
Answer» Correct Answer - D

Discussion

217.	Define ionisation energy. What is the value for a hydrogen atom?A. `3.4 Ev`B. `10.4 Ev`C. `12.09 Ev`D. `13.6 Ev`
Answer» Correct Answer - D The minimum energy required to free the electron from the ground state of the hydrogen atom is called the ionisation energy of hydrogen atom, its value is `13.6eV`.

Discussion

218.	The second member of Lyman series in hydrogen spectrum has wavelength `5400 Å`. Find the wavelength of first member.
Answer» `(1)/(lamda)=R((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))` For second member of Lyman series, `(1)/(5400)=R((1)/(1^(2))-(1)/(3^(2)))rArr(1)/(5400)=(8R)/(9)rarr(1)` For first member of Lyman series, `(1)/(lamda^(1))=R((1)/(1^(2))-(1)/(2^(2)))` `(1)/(lamda^(1))=(3R)/(4)" "rarr(2)` `((1))/((2))rArr(lamda^(1))/(5400)=(8R)/(9)xx(4)/(3R)` `therefore lamda^(1)=(32)/(27)xx5400=6400 Å`.

Discussion

219.	Calculate the shortest wavelength of Balmer series. Or Calculate the wavelength of the Balmer series limit. Given : `R = 10970000 m^(-1)`.
Answer» `(1)/(lamda)=R((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))` `R=10970000=1.097xx10^(7) ms^(-1)` For Balmer series limit `n_(1)=2 and n_(2)=prop` `(1)/(lamda)=R((1)/(2^(2))-(1)/(prop))rArr(1)/(lamda)=(R )/(4)` `lamda=(4)/(R )=(4)/(1.097xx10^(7))=3646.3 Å`.

Discussion

220.	Wavelength corresponding to series limit isA. `(1)/(lambda)=(2R)/(n)`B. `(1)/(lambda)=(R^(2))/(n^(2))`C. `(1)/(lambda)=(R^(2))/(n^(2))`D. `(1)/(lambda)=(R)/(n)`
Answer» Correct Answer - C

Discussion

221.	In which of the following transition will the wavelength be minimum ?A. n=5 to n=4B. n=4 to n=3C. n=3 to n=2D. n=2 to n=1
Answer» Correct Answer - D The wavelength will be minimum ffor which `((1)/(n_f^(2))-(1)/(ni^(2)))` is maximum.

Discussion

222.	Find the minimum wavelength emitted by a hydrogen atom due to electronic transition.
Answer» Solve , `1/lambda=R(1-1/oo)` `R to ` Rydberg constant

Discussion

223.	A sample of a radioactive substance has `10^(6)` radioactive nuclei. Its half life time is 20 s How many nuclei will remain after 10 s ?
Answer» Correct Answer - `7xx 10^(5)` (approx)

Discussion

224.	4g of a radioactive material of half life 10 years is kept in a store for 15 years. How much material is disntegrated ?
Answer» Correct Answer - 2.5855 g

Discussion

225.	Obtain approximately the ratio of the radii of iron `._(26)Fe^(56)` and calcium `._(20)Ca^(40)`. What is the approximate ratio of their nuclear mass densities?
Answer» Correct Answer - 1.12, 1

Discussion

226.	Define mass defect and state an expression for it.
Answer» The difference between the sum of the masses of all the individual nucleons in a nucleus and the mass of the nucleus is known as the mass defect. Mass defect, ∆m = (Zm_p+ Nm_n) – M where mp is the proton mass, mn is the neutron mass, M is the mass of the nucleus, Z is the atomic number and N = A – Z is the neutron number.

226.

Define mass defect and state an expression for it.

Answer»

The difference between the sum of the masses of all the individual nucleons in a nucleus and the mass of the nucleus is known as the mass defect.

Mass defect, ∆m = (Zm_p+ Nm_n) – M where mp is the proton mass, mn is the neutron mass, M is the mass of the nucleus, Z is the atomic number and N = A – Z is the neutron number.

Discussion

227.	Calculate the mass defect and binding energy of \(^{59}_{27}Co\) which has a nucleus of mass 58.933 u. [Take mp = 1.0078 u, mn = 1.0087 u]
Answer» Data: m_p = 1.0078 u, m_n = 1.0087 u, m_Co = 58.933 u, 1 u = 931.5 MeV/c² For \(^{59}_{27}Co\), A = 59, Z = 27 ∴ N = A – Z = 59 – 27 = 32 The mass defect, ∆m=(Zm_p + N_n) – m_Co = (27 × 1.0078 + 32 × 1.0087) – 58.933 = (27.2106 + 32.2784) – 58.933 = 59.4890 – 58.933 = 0.556 u ∴ The binding energy = ∆mc² = 0.556 uc² × 931.5 MeV/uc² = 517.8 MeV

227.

Calculate the mass defect and binding energy of \(^{59}_{27}Co\) which has a nucleus of mass 58.933 u. [Take mp = 1.0078 u, mn = 1.0087 u]

Answer»

Data: m_p = 1.0078 u, m_n = 1.0087 u,

m_Co = 58.933 u,

1 u = 931.5 MeV/c²

For \(^{59}_{27}Co\), A = 59, Z = 27

∴ N = A – Z = 59 – 27 = 32

The mass defect,

∆m=(Zm_p + N_n) – m_Co

= (27 × 1.0078 + 32 × 1.0087) – 58.933

= (27.2106 + 32.2784) – 58.933

= 59.4890 – 58.933 = 0.556 u

∴ The binding energy

= ∆mc²

= 0.556 uc² × 931.5 MeV/uc²

= 517.8 MeV

Discussion

228.	A nucleus of `Ux_(1)` has a life of 24.1 days. How long a sample of `Ux_(2)` will take to change to 90 % of it to `Ux_(2)` ?
Answer» Correct Answer - 80 days

Discussion

229.	What is nuclear energy?
Answer» Energy released in a nuclear reaction such as a spontaneous or induced nuclear fission, or nuclear fusion, or in interaction of two nuclei, is called nuclear energy. [Note : It is far greater from that released in a chemical reaction.]

229.

What is nuclear energy?

Answer»

Energy released in a nuclear reaction such as a spontaneous or induced nuclear fission, or nuclear fusion, or in interaction of two nuclei, is called nuclear energy.

[Note : It is far greater from that released in a chemical reaction.]

Discussion

230.	If the number of nuclei of a radioactive substance becomes 1/e times the initial number in 10 days, what is the decay constant of the substance ?
Answer» N(t) = N₀e^-λt ∴ In this case, \(\cfrac{N(t)}{N_0}\) = \(\cfrac1e\) = e^-λt\(\cfrac1{e^{λt}}\) ∴ λt = 1 ∴ The decay constant, λ = \(\cfrac1t\) = \(\cfrac1{10}\) day^-1 = 0.1 day^-1

230.

If the number of nuclei of a radioactive substance becomes 1/e times the initial number in 10 days, what is the decay constant of the substance ?

Answer»

N(t) = N₀e^-λt

∴ In this case,

\(\cfrac{N(t)}{N_0}\) = \(\cfrac1e\) = e^-λt\(\cfrac1{e^{λt}}\)

∴ λt = 1

∴ The decay constant,

λ = \(\cfrac1t\) = \(\cfrac1{10}\) day^-1

= 0.1 day^-1

Discussion

231.	The binding energy of a H-atom considering an electron moving around a fixed nuclei (proton), is `B = - (me^(4))/(8n^(2)epsi_(0)^(2)h^(2))` (m= electron mass) If one decides to work in a frame of refrence where the electron is at rest, the proton would be movig around it. By similar arguments, the binding energy would be : `B = - (me^(4))/(8n^(2)epsi_(0)^(2)h^(2))` (M = proton mass) This last expression is not correct, becauseA. n would not be integralB. bohr- quantisation applies only to electronC. the frame in which the electron is at rest is not inertialD. the motion of the proton would not be in circular orbits, even approximately
Answer» Correct Answer - C In the frame of reference, where electron is at rest the given expression cannot be true for binding energy as the frame in which electron is at rest would not be inertial. In hydrogen atom, electron revolving around a fixed proton nucleus has some centripetal acceleration.

Discussion

232.	In which model atoms become unstable?
Answer» In Rutherford atom model. (An accelerating electron radiates energy and spiral around the nucleus. Ultimately electrons should fall inside the nucleus.)

Discussion

233.	What is meant by a stationary orbit?
Answer» n the Bohr model of the hydrogen atom, a stationary orbit refers to any of the discrete allowed orbits such that the electron does not radiate energy while it is in such orbits.

Discussion

234.	What is a stationary orbit?
Answer» A stationary orbit is one in which the revolving electron does not radiate energy.

Discussion

235.	Are the electron orbits equally spaced?
Answer» No. Electron orbits are unequally spaced.

Discussion

236.	Give the relation between radius and principle Quantum number of an atom.
Answer» Relation between radius and principle Quantum number of an atom. r_n ∝ n²

236.

Give the relation between radius and principle Quantum number of an atom.

Answer»

Relation between radius and principle Quantum number of an atom.

r_n ∝ n²

Discussion

237.	What is the relation between the energy of an electron and the principle Quantum number?
Answer» Relation between the energy of an electron and the principle Quantum number E_n ∝ 1/n²

237.

What is the relation between the energy of an electron and the principle Quantum number?

Answer»

Relation between the energy of an electron and the principle Quantum number

E_n ∝ 1/n²

Discussion

238.	What is excited state of an atom?
Answer» When atom is given sufficient energy, the transition takes place to an orbit of higher energy. The atom is then said to be in an excited state.

Discussion

239.	Hydrogen atom is exited from ground state to another state with principal quantum number equal to `4` Then the number of spectral line in the emission spectra will beA. 2B. 3C. 5D. 6
Answer» Correct Answer - D If n-4, then lines `=(n(n-1))/(2)=6`

Discussion

240.	In column-I name of the spectral series are given and column-II gives wavelength formula corresponding to series and region of series.
Answer» Correct Answer - A::B::C::D

Discussion

241.	The orbital frequency of an electron in the hydrogen atom is proportional toA. `n^(3)`B. `n^(-3)`C. nD. `n^(0)`
Answer» Correct Answer - D Time period of orbital motion electorn `T=(4epsi_(0)^(2)n^(3)h^(3))/(mZ^(2)e^(4))` `rArrTpropn^(3)rArr(1)/("Frequency(f)")propn^(3)` `rArrfpropn^(-3)`

Discussion

242.	Column-II give some quantities associated with electron of hydrogen like atom. The quantities are proportional to entries given in column-I . Match the column appropriately
Answer» Correct Answer - A::B::C::D

Discussion

243.	Regarding the spectrum of hydrogen, match the entries in column-I with all the entries in column-II. Match the following :
Answer» Correct Answer - A::B::C::D

Discussion

244.	In the Bohr model of the hydrogen atgomA. The radius of nth orbit is proportional to `n^(2)`B. The total energy of electron in nth orbit is proportional to nC. The angular momentum of an electron in an orbit is an intergal multiple of `h//2pi`D. The magnitude of the potential energy of an electron in any orbit is greater than its kinetic energy
Answer» Correct Answer - B

Discussion

245.	A gas of hydrogen - like ion is perpendicular in such a way that ions are only in the ground state and the first excite state. A monochromatic light of wavelength `1216 Å` is absorved by the ions. The ions are lifted to higher excited state and emit emit radiation of six wavelength , some higher and some lower than the incident wavelength. Find the principal quantum number of the excited state identify the nuclear charge on the ions . Calculate the values of the maximum and minimum wavelengths.
Answer» Correct Answer - D

Discussion

246.	Which of the following parameters are the same for all hydrogen like atoms and ions in their ground state?A. Radius of the orbitB. speed of the electronsC. Energy of the atomD. Orbital angular momentum of the electron
Answer» Correct Answer - D

Discussion

247.	Assertion A beam of charged particles is employed in the treatment of cancer. Reason Charged particles on passing through a material medium loss their energy by causing ionisation of the atoms along their path.A. If both Assertion and Reason are true and Reason is the correct explanation of Assetion.B. If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.C. If Assetion is true but Reason is false.D. If both Assertion and Reason are false.
Answer» Correct Answer - B A raditation consists of a beam of a charged particles. When radiation is used for cancer treatement , them on falling upon the concerous , it destryos, cancer cells.

Discussion

248.	In Bohr model of hydrogen atom, the force on the electron depends on the principal quantum number (n) asA. independent of nB. `Fprop(1)/(n^(5))`C. `Fprop(1)/(n^(4))`D. `Fprop(1)/(n^(3))`
Answer» Correct Answer - C We have, `Fprop(v^(2))/(r)` Also, `vprop(1)/(n)an dr propn^(2)rArrFprop(1)/(n^(4))`

Discussion

249.	The wavelength of `K_(alpha)` X-ray for an element is 21.3 pm. It takes 12.5 ke V to knock out an electron out an electron from the L-shell of the atom of the element. What should be the minimum accelerating voltage across on X-ray tube having the element as target which allows production of `K_(alpha)` X-ray?
Answer» Since `E_(K)-E_(L)=(hc)/(lambda_(K_(alpha)))` It is given that `lambda_(K_(alpha))=21.3"pm" =0.0213 "nm"` Also, `" " E(eV) =(1242)/(lambda(nm))=(1242)/(0.0213)=58.3 eV` `rArr" " E_(K)-E_(L)=E` `rArr" " E_(K)-12.5=58.3` `rArr" "E_(K)=70.8 keV` `:.` Acceleration potential =70.8 keV

Discussion

250.	Find the absolute mass of oxygen.
Answer» The atomic mass of oxygen is 16u We know 1u = 1.6605 x 10^–24 g Therefore, Absolute mass of oxygen = 1.6605 x 10^–24 x 16 g = 26.568 x 10^–24= 2.6568 x 10^–25 g

250.

Find the absolute mass of oxygen.

Answer»

The atomic mass of oxygen is 16u

We know 1u = 1.6605 x 10^–24 g

Therefore, Absolute mass of oxygen = 1.6605 x 10^–24 x 16 g

= 26.568 x 10^–24= 2.6568 x 10^–25 g

Discussion

Explore topic-wise InterviewSolutions in .

What is the value of Rydberg’s constant?

The total energy of an electron in the first excited state of the hydrogen atom is -3.4eV. What is the potential energy of the electron in this state ?

What is wave number of spectral line?

What would be the charge in radius of `n^"th"` orbit, if the mass of electron reduces to half of its original value ?

Total energy of an electron in an atom is negative . What does it signify ?

What would be the ratio of product of velocity and time period of electron orbiting in `2^"nd"` and `3^"rd"` stable orbits ?

with the help of Rydberg formula find the wavelength of first line of Pfund series .

The shortest wavelength which can be obtained in hydrogen spectrum `(R=10 ^(7) m^(-1))`A. 1000 ÅB. 8000 ÅC. 1300 ÅD. 2100 Å

If scattering particles are `56` for `90^(@)` angle than this will be at `60^(@)` angleA. 224B. 256C. 98D. 108

Which of the following cannot be the value of ionisation energy for a hydrogen atom ?A. 0.85 eVB. 3.4 eVC. 1.51 eVD. 0.27 eV

Define ionisation energy. What is the value for a hydrogen atom?A. `3.4 Ev`B. `10.4 Ev`C. `12.09 Ev`D. `13.6 Ev`

The second member of Lyman series in hydrogen spectrum has wavelength `5400 Å`. Find the wavelength of first member.

Calculate the shortest wavelength of Balmer series. Or Calculate the wavelength of the Balmer series limit. Given : `R = 10970000 m^(-1)`.

Wavelength corresponding to series limit isA. `(1)/(lambda)=(2R)/(n)`B. `(1)/(lambda)=(R^(2))/(n^(2))`C. `(1)/(lambda)=(R^(2))/(n^(2))`D. `(1)/(lambda)=(R)/(n)`

In which of the following transition will the wavelength be minimum ?A. n=5 to n=4B. n=4 to n=3C. n=3 to n=2D. n=2 to n=1

Find the minimum wavelength emitted by a hydrogen atom due to electronic transition.

A sample of a radioactive substance has `10^(6)` radioactive nuclei. Its half life time is 20 s How many nuclei will remain after 10 s ?

4g of a radioactive material of half life 10 years is kept in a store for 15 years. How much material is disntegrated ?

Obtain approximately the ratio of the radii of iron `._(26)Fe^(56)` and calcium `._(20)Ca^(40)`. What is the approximate ratio of their nuclear mass densities?

Define mass defect and state an expression for it.

Calculate the mass defect and binding energy of \(^{59}_{27}Co\) which has a nucleus of mass 58.933 u. [Take mp = 1.0078 u, mn = 1.0087 u]

A nucleus of `Ux_(1)` has a life of 24.1 days. How long a sample of `Ux_(2)` will take to change to 90 % of it to `Ux_(2)` ?

What is nuclear energy?

If the number of nuclei of a radioactive substance becomes 1/e times the initial number in 10 days, what is the decay constant of the substance ?

In which model atoms become unstable?

What is meant by a stationary orbit?

What is a stationary orbit?

Are the electron orbits equally spaced?

Give the relation between radius and principle Quantum number of an atom.

What is the relation between the energy of an electron and the principle Quantum number?

What is excited state of an atom?

Hydrogen atom is exited from ground state to another state with principal quantum number equal to `4` Then the number of spectral line in the emission spectra will beA. 2B. 3C. 5D. 6

In column-I name of the spectral series are given and column-II gives wavelength formula corresponding to series and region of series.

The orbital frequency of an electron in the hydrogen atom is proportional toA. `n^(3)`B. `n^(-3)`C. nD. `n^(0)`

Column-II give some quantities associated with electron of hydrogen like atom. The quantities are proportional to entries given in column-I . Match the column appropriately

Regarding the spectrum of hydrogen, match the entries in column-I with all the entries in column-II. Match the following :

Which of the following parameters are the same for all hydrogen like atoms and ions in their ground state?A. Radius of the orbitB. speed of the electronsC. Energy of the atomD. Orbital angular momentum of the electron

In Bohr model of hydrogen atom, the force on the electron depends on the principal quantum number (n) asA. independent of nB. `Fprop(1)/(n^(5))`C. `Fprop(1)/(n^(4))`D. `Fprop(1)/(n^(3))`

Find the absolute mass of oxygen.