Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Argon is formed in meteorites due to cosmic events. Each cosmic event produces one argon atom. If 1.12 xx10^(-3)mL of argon is formed at STP from 10kg of a meteorite, the number of cosmic events that occurred is

Answer»

`4XX10^(16)`
`1.5xx10^(16)`
`6XX10^(16)`
`9XX10^(16)`

ANSWER :A
Discussion
2.

Arenium ion is formed in the reaction.

Answer»

(I)(IV)(P)
(II)(iii)(P)
(III)(iv)(R)
(IV)(ii)(S)

ANSWER :A
Discussion
3.

Are the oxidation state and covelency of Al in [AlCl (H_2O)_5]^(2+) same ?

Answer»

Solution :No. The oxidation STATE of Al is + 3 and the covalency is 6.
Discussion
4.

Are the oxidation state and covalency of Al in [AlCl(H_(2)O)_(5)]^(2+) same ?

Answer»

Solution :No. The oxidation state of Al is `+3 `and the COVALENCY is 6.
Because,
`+2 = Al + CL + 5 (H_(2) O)`
`+2 = x - 1 + 5(0)`
` :. X = +3 = ` oxidation number of Al
Al form one covalent bond Cl form one covalent bond and FIVE covalent bond from with `5 H_(2) O`,
So total 6 covalent bond is present.
Discussion
5.

The oxidation state and covalency of AI on [AICIH_(2)O_(5)]^(2+) ARE respectively

Answer»

Solution :No, the OXIDATION STATE of All is +3 and the COVALENCY is 6.
Discussion
6.

Are the oxidation state and covalency of Al in [AICI(H_2O)_5]^(2+)same?

Answer»

Solution :No, the oxidation STATE of AL is +3 and the COVALENCY is 6.
Discussion
7.

Are theoxidationstateand covalency ofA1 in[A1Cl (H_(2)O)_(6)]^(2+) same ?

Answer»

Solution :The oxidationstateof `C1 ` is-1 . Letus supposethat oxidation STATEOF a1 is x
`:.X - 1 + 6xx 0= + 2" ORX= + 3`
Thusthe oxidationstateof ALIS +3
Sincesix ligands(whichcandonate a pairof ELECTRONS ) I.e., `H_(2)O`molecules are attached to thealuminium atom, Thereforeitscovalencyis 6.
Discussion
8.

Are sodium cyanide and potassium cyanide equally poisonous ?

Answer»

SOLUTION :No. KCN is more POISONOUS than NACN.
Discussion
9.

Are all the five bonds in PCl_(5) equivalent ? Justify.

Answer»

Solution :`PCl_(5)` has trional bipyramid structure (Fig. 11.35, page 11//134). It has three equatorial BONDS inclined at angle of `120^(@)` and TWO AXIAL bonds inclined at an angle of `90^(@)`. Since two axial P-Cl bonds are repelled by three bond pairs each while three equatorial P-Cl bonds are repelled by two bond pairs each, therefore aixad bonds are longer (240 pm) and HENCE weaker as compared to more stable equatorial bonds (202 pm). Thus, all the five P-Cl bonds in `PCl_(5)` are not EQUIVALENT.
Discussion
10.

are :

Answer»

METAMER
GEOMETRICAL isomer
position isomer
chain isomer

Solution :N//A
Discussion
11.

Ar and He are both gases at room temperture. How do the average moleculr velocities (V) of their atoms compare at this temperature?

Answer»

`V_(He)=10V_(Ar)`
`V_(Ar)=10V_(He)`
`V_(He)=3V_(Ar)`
`V_(Ar)=3V_(He)`

Answer :C
Discussion
12.

Aqueous tension of water depends only on …………..and not on ………………………..

Answer»


ANSWER :TEMPERATURE, the AMOUNT of WATER
Discussion
13.

Aqueous tension of water depends on

Answer»

the AMOUNT of WATER taken
the TEMPERATURE only
both amount of water and temperature
neither temperature nor amount of water

Answer :B
Discussion
14.

Aqueous tension is very high at

Answer»

`25^(@) C`
`40^(@) C`
`100^(@) C`
`30^(@) C`

ANSWER :C
Discussion
15.

Aqueoussolutionsof twocompoundsM- O- Hand M'- O - Hhavebeenpreparedin twoseparatebeakers. It theelectronegativity ofM= 3.5M= 1.72 ,O = 3.0 andand H=2.1then thesolutions respectively are

Answer»

acidic , acidic
acidicbasic
basic , basic
basicacidic

SOLUTION :As theelectronegativityof metalincreasethe electrondensityin the O - Hbonddecreases . Inorderwords O - Hbondbecomesweakand readilyionizes toliberate`H^(+)` ThusM-O- Hbehave as an acid.
CONVERSELY as theelecronegativityof the metaldecreasesM- Obondbecomesweakandreadilyionizesto LIBERATE `OH^(-)` Thus `M- O- H` behavesas a base. combiningboththe trendsoption (b) is correct.
Discussion
16.

Aqueous tension at 25^@C is given as 23.8 mm, If 1.5 L of nitrogen gas is collected over water at 25^@C and 735 mm Hg, find the mass of dry gas collected in the experiment.

Answer»


ANSWER :16.07g
Discussion
17.

Aqueous solution of KCI is neutral because

Answer»

`K^(+) ` UNDERGOES hydrolysis
`CL^(-) ` undergoes hydrolysis
Both `K^(+) and Cl^(-) ` undergoes hydrolysis
No hydrolysis takes places

SOLUTION :`K^(+) and Cl^(-) `do not undergo hydrolysis
Discussion
18.

Aqueous solution of which of the following compounds is the best conductor of electric current ?

Answer»

Ammonia, `NH_3`
Fructose, `C_6H_12O_6`
Acetic acid, `C_2H_4O_2`
Hydrochloric acid, HCL

SOLUTION :AQUEOUS solution HCl is the best CONDUCTOR of electric current because HCl is STRONG acid, so it dissociates completely into ions.
Discussion
19.

Aqueous solution of the detergents are

Answer»

NEUTRAL
Acidic
Basic
Amphoteric

Answer :C
Discussion
20.

Aqueous solution of sodium carbonate is alkaline due to

Answer»

HYDROLYSIS of `NA^(+)`
Hydrolysis of `CO_(3)^(2-)`
Hydrolysis of both `Na^(+)` and `CO_(3)^(2-)`
Hydration of `Na^(+)`

ANSWER :B
Discussion
21.

Aqueous solution of (P) and (Q) are violet. (P) turns green on oxidatioin while (Q) turns green on reduciton. They may respectively be:

Answer»

`VCl_(2),CrO_(3)`
`VCl_(3),KMnO_(4)`
`VSO_(4),KMnO_(4)`
`VOSO_(4),K_(2)MnO_(4)`

ANSWER :C
Discussion
22.

Aqueous solution of NaHCO_(3) is alkaline

Answer»

because of CATIONIC HYDROLYSIS
because of ANIONIC bydrolysis
because it is ACIDIC salti
because it is basic-sálf

Answer :B
Discussion
23.

Aqueous solution of Na_(2)S_(2)O_(3) on reaction with Cl_(2) with Cl_(2) gives

Answer»

`Na_(2)S_(4)O_(6)`
`NaHSO_(4)`
NaCl
NAOH

Solution :`Na_(2)S_(2)O_(3) +4Cl_(2)+5H_(2)O to 2NaHSO_(4) +8HCl`
Discussion
24.

Aqueous solution of Na_(2)CO_(3) is

Answer»

Acidic
Basic
Neutral
Highly acidic

Answer :B
Discussion
25.

Aqueous solution of H_(3)BO_(3) is treated with salicyclic acid which of the following are incorrect ?

Answer»

No product is formed because both are acids.
Product is formed 4 - CO - ordinate complex and optically resoluable
Like ORGANIC benzene, borazine does not GIVE addition product
Products are formed 4 - co - ordinate complex and optically not resolable

Solution :`B[OH]_(3)+H_(2)O rarr [B(OH)_(4)]^(-)+H` ,
`[B(OH)_(4)]^(-)rarr BO_(2)^(-)+2H_(2)O`
It is optically resolvable because of assymmetric structure.
Discussion
26.

Aqueous solution of CaCl_(2) is

Answer»

Acidic
Basic
Neutral
None of these

Solution :`CaCl_(2)+2H_(2)OtoCa(OH)_(2)+2HCL`
Discussion
27.

Aqueous solution of Ba(OH)_2 is labelled as 0.25M. Calculate the concentrations of OH^(-)and H^(+).

Answer»

SOLUTION :`(OH^(-)) = 0.5M, [H^(+)]= 2 xx 10^(-15) M`
Discussion
28.

Aqueous solution of BeCl_(2) is

Answer»

Acidic
Basic
Neutral
None of these

Solution :`[BeCl_(2)+4H_(2)O to [Be(H_(2)O)_(4)]Cl_(4)}` , `[[Be(H_(2)O)_(4)]^(2+) to [Be(H_(2)O)_(3)(OH)]^(+)+H^(OPLUS)}`
HENCE the AQUEOUS solution of `BeCl_(2)` is acidic.
Discussion
29.

Aqueous NaOH solution is labelled as 10% by weight mole fraction of the solute in it is

Answer»

0.05
0.0476
0.052
0.52

Answer :B
Discussion
30.

{:("Aqueous green soln.of" (A)overset(NH_(4)OH)rarr,"Greenish ppt"(B)),(,""darrNa_(2)O_(2)),("Bright yellow"overset(Aq.Pb(NO_(3))_(2))larr."Orange colour",overset(AcOH)larr"Yellow soln".(C)):} Identify 'D'.

Answer»

`Na_(2)CrO_(4)`
`PbCrO_(4)`
`Na_(2)MnO_(4)`
`FE(OH)_(3)`

ANSWER :B
Discussion
31.

{:("Aqueous green soln.of" (A)overset(NH_(4)OH)rarr,"Greenish ppt"(B)),(,""darrNa_(2)O_(2)),("Bright yellow"overset(Aq.Pb(NO_(3))_(2))larr."Orange colour",overset(AcOH)larr"Yellow soln".(C)):} Identify 'A'.

Answer»

`AICI_(3)` and `KOH`
`Cr(OH)_(3)`
`CrCI_(3)`
`FeCI_(3)`

ANSWER :C
Discussion
32.

Aqueous ethanol is labelled as 2 molal. Find the mole fraction of alcohol.

Answer»

Solution :1000G of WATER HA 2 MOLE of ethanol
55.5 moles of water has 2 mole of ethanol or `X=(m)/(m+55.5)`
Mole fraction alcohol`=(2)/(2+55.5)=(2)/(57.5)=0.0348`
Discussion
33.

Aquenous solution of which of the following compounds is the best conductor of electric current ?

Answer»

Ammonia, `NH_(3)`
Fructose, `C_(6)H_(12)O_(6)`
Acetic acid, `C_(2)H_(4)O_(2)`
HYDROCHLORIC acid HCl

Solution :Fructose is a non-electrolyte, `NH_(4)OH` and `CH_(3)COOH` are weak electrolytes, HCI is a strong electrolyte. Hence, HCI dissociates completely in aqueous solution and, therefore is the best CONDUCTOR of electricity .
Discussion
34.

Applying VSEPR theory, how to predict the shape of IF_7?

Answer»

Solution :`IF_7` : It is an `AB_7` type molecule. This molecules has 7 BOND PAIR of ELECTRONS and no lone pair of elctrons . Due to bond pair-bond pair INTERACTION of elections, `IF_7` has PENTAGONAL bipyramidal shape.
Discussion
35.

Applyingbohr.smodelwhenelectronofH atom comesfromn=4to n=2calculate itswavelength

Answer»

4866 A
5272 A
4634 A
5084A

ANSWER :A
Discussion
36.

Applying Bhor's model when electron in H atom comes from n = 4 to n = 2, calculate the wavelength of the line. In this process, write whether energy is released or absorbed. Also write the range of radiation (R_(H) = 2.18 xx 10^(-18)J, h = 6.63 xx 10^(-34) J)

Answer»


Solution :Apply Rydberg's formula, `E = (hc)/(LAMDA) = R_(H) Z^(2) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
For H-atom, Z = 1
N = 4 or n= 2 means `n_(2) = 4, n_(1) = 2`
Calculate `lamda`
Discussion
37.

Apply the VSEPR model to XeF_(4), which of the following molecular shape is consistent with the model?

Answer»

SQUARE PLANAR
Tetrahedral
Square pyramidal
Octahedral

Solution :Square planar
Discussion
38.

Application of the heat of combustion ?

Answer»

Solution :Heat of combination is used
(i) to calculateheat of FORMATION
(II) to find the calorific VALUE of food and FUEL
Discussion
39.

………apparatus is used in differential extraction

Answer»

SOLUTION :Separatory FUNNEL
Discussion
40.

Apart from tetrahedral geometry, another possible geometry for CH_(4) is square planar with the four H atoms at the corners of the square and the O atom at its centre. Explain why CH_(4) is not square planar ?

Answer»

SOLUTION :Experimentally dipole moment of `CH_(4)` is `MU` = ZERO so, `CH_4)` molecule is NONPOLAR.
Discussion
41.

Apart from tetrahedral geometry, another possible geometry forCH_(4) is square planar with four H atoms at the corners of the square and the C atom as its centre . Explain why CH_(4)is not square planar .

Answer»

Solution :Electronic configuration of C-atom is ` 2S^(2) 2s^(2) 2p_(x)^(1) 2p_(y)^(1)` in the ground state and ` 1s^(2) 2s^(1) 2p_(x) ^(1) 2p_(y)^(1) 2p_(z)^(1)` in
The excited state . Hence,it undergoes ` sp^(3)`hybridisation which gives a tetrahedral shape. For square
Plana, the hybridisation required is `dsp^(2)`which is not possible for C-atom in `CH_(4)` . ALSO according to
VSEPR theory ,if ` CH_(4)` wereplanar, the bond angle would be `90^(@)`. for tetrahedral structure , the
bond angle is ` 109^(@) 28`'. Thus ,in the square planer structure , repulsions between the bond pairs would be
more and , THEREFORE , the stability will be less.
Discussion
42.

Apart from tetrahedral geometry, another possible geometry for CH_(4) isSquare planar With four H atoms at the corners of the square and C atom at its centre. Explain why CH_(4) is not square planar?

Answer»

SOLUTION :ELECTRONIC configuration of carbon atom: C : `SIGMA1S^(2)2s^(2)2p^(2)`
In the excited state, the orbital picture of carbon can be represented as:

Hence. carbon atom undergoes `sp^(3)` hybridisation in `CH_(4)` molecule and takes tetrahedral shape.

ror a SQUARE planar shape, the hybridisation of the central atom has to be `dsp^(3)`. However, an atom of carbon does not have d-orbitals to undergo `dsp^(3)` hybridisation. Hence, the structure of `CH_(4)`is tetrahedral.
Discussion
43.

Aoverset(O_(3))underset(Zn//H_(2)O)to2 Identify A and name the reaction

Answer»




SOLUTION :
Discussion
44.

A(OH)_(2)is a partially soluble substance and its K_(sp)value is 4 xx 10^(-12) . Which of the following statement is / are correct ?

Answer»

The solubility is unaffected by pH of the MEDIUM
Its solubility increases in a bufferedmediumhaving pH = 2
Its solubility decreases in a buffered medium having pH= 9
Its saturated solution has pH =10.3

Solution :` A(OH) _2 HARR A^(+2) +2OH^(-) `
` "" S "" 2S `
` 4 xx 1 0^(_12) =4S ^(3) rArr S =1 0 ^(_4) M`
` [OH^(-)] = 2 xx 10^(_4)M`
` pOH =4- log 2 = 3.7 rArr pH =10.3`
Discussion
45.

A(OH)_2is a partially soluble substance and itsK_(sp) "value is " 4xx10 ^(-12)Which of the following statement is/are correct ?

Answer»

The solubility is unaffected by pH of the medium
Its solubility increases in a bufferedmediumhaving pH = 2
Its solubility decreases in a BUFFERED medium having pH= 9
Its SATURATED solution has pH =10.3

Solution :` A(OH) _2 HARR A^(+2) +2OH^(-) `
` "" S "" 2S `
` 4 xx 1 0^(_12) =4S ^(3) rArr S =1 0 ^(_4) M`
` [OH^(-)] = 2 xx 10^(_4)M`
` pOH =4- log 2 = 3.7 rArr pH =10.3`
Discussion
46.

Anything that influences the valence electrons will affect the chemistry of the element. Which one of the following factors does not affect the valence shell ?

Answer»

VALENCE principal quantum number (n)
Nuclear charge (Z)
Nuclear mass
Number of CORE electrons.

Answer :C
Discussion
47.

Anything which separates the system from its surroundings is called ____

Answer»

SOLUTION :BOUNDARY
Discussion
48.

Anything thatinfluencesthe valenceelectronswill affectthe chemistryof theelement . Whichoneof the followingfactors does not affectthe valenceshell ?(a ) Valenceprincipal quantumnumber (n )( b)Nuclear charge (Z) ( c)nuclear mass(d ) Numberof coreelectrons.

Answer»

SOLUTION :Nuclearmass does not affect THEVALENCE shellbecausenucleus consists ofprotons and neutrons. Whereas proton i.e.,nuclearchargeaffects thevalenceshellbut neutronsdo not. Thusoption ( C)is WRONG.
Discussion
49.

Any alkyl bromide (a) reacts with sodium in ether to form 4,5 -diethylocatane the compound

Answer»

`CH_(3)(CH_(2))BR`
`CH_(3)(CH_(2))_(5)Br`
`CH_(3)(CH_(2))_(3)CH(Br)CH_(3)`
`CH_(3)-(CH_(2))_(2)-CH(Br)-UNDERSET(CH_(3))underset(|)CH_(2)`

Answer :d
Discussion
50.

Anunknown compound 'A' has a molecular formula of C_(4)H_(6) when 'A' is treated with an excess of Br_(2) a new substance 'B' with formula C_(4)H_(6)Br_(2) is formed. A forms a white precipitate with ammonical silver nitrate solution 'A' may be

Answer»

BUTYNE
Butyne - 2
Butene
Butene - 1

Solution :Butyne -1 has ACIDIC HYDROGEN
Discussion