Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

How many isomers of C_7H_8 O exists that has phenyl ring ?

Answer»


SOLUTION :
2.

How many isomers of C_(5)H_(11)OH will be primary alcohols?

Answer»

5
2
4
3

Solution :(i) `H_(3)C-CH_(2)-CH_(2)-CH_(2)-CH_(2)-OH`,
(ii) `CH_(3)-CH_(2)-UNDERSET(CH_(2))underset(|)(CH)-CH_(2)-OH`,
(iii) `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)-OH`
(iv) `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-OH`
3.

How many isomers are possible of anorganic compound having molecule formula C_(4)H_(8)O ?

Answer»

4
7
10
3

Solution :(i) `CH_(3)COCH_(2)CH_(3)` BUTANONE
(ii) `CH_(3)CH_(2)CH_(2)CHO` butanl
(iii) `CH_(3) UNDERSET(underset(CHO)(|))(C )HCH_(3)` 2-methyl PROPANAL
4.

How many isomers are possible for the formula C_5 H_(11) Br?

Answer»

11
8
4
5

Solution :8
5.

How many isomers are possible for the formula C_5H_11Br ?

Answer»

11
8
4
5

Solution :8
6.

How many isomers are possible for the formula C_4H_9Cl ?

Answer»

3
2
4
5

Solution :4
7.

How many isomers are possible for the formulaC_(3) H_(7) F? Give their structures and names

Answer»

Solution :`C_(3) H_(7) F-2` isomers are POSSIBLE
(i) `CH_(3) - CH_(2) - CH_(2) F ""` 1-fluoropropane
(II) `CH_(3) - underset(F)underset(|)(C)H- CH_(3) ""` 2-fluoropropane
8.

How many isomers are possible for monochloro anthracene?

Answer»

2
3
4
5

Solution :N//A
9.

How many isomers are possible for an aromatic compound having formula C_(7)H_(8)O ?

Answer»

3
4
5
6

Solution :o, m and p-cresols, ANISOLE and BENZYL ALCOHOL.
10.

How many isomers are possible for a disubstituted benzene ? What is the relationship between them ?

Answer»

SOLUTION :Three ISOMERS are possible. These are :

Since these isomers differ in the POSITION of the substituents on the BENZENE ring, THEREFORE, these are called position isomers.
11.

How many isomeric structural alkene on catalytic hydrogeneation gives 3-Methyl hexane

Answer»

3
4
5
6

Solution :
12.

How many isomeric structures can heptane (C_7H_16) have?

Answer»

FIVE
SIX
EIGHT
NINE

SOLUTION :Nine.
13.

How many isomeric primary alcohols are possible for C_(4)H_(9)OH ?

Answer»

1
2
3
4

Solution :TWO primary alcohols POSSIBLE for `C_(4)H_(9)OH` n-Butyl ALCOHOL and isobutyl alcohol.
14.

How many isomeric carbonyl compounds are possible with the molecular formula, C_(5)H_(10)O? Draw their structures

Answer»


ANSWER :5
15.

How many isomeric alkynes on catalytic hydrogenation gives 3-Ethyl-4-methylheptane ?

Answer»


ANSWER :3
16.

How many isomeric alkyne of hydrogenation gives 3,3 - Dimethylhexane.

Answer»


ANSWER :3
17.

How many ionisation energies can carbon have ? Electron configuration of carbon {:("in Ground state", 1s^2 2s^2 2p_x^1 2p_y^1),("in Excited state", 1s^2 2s^1 2p_x^1 2p_y^1 2p_z^1):}

Answer»

1
2
4
6

Answer :D
18.

How many ion pairs present per each unit cell of NaCl ?

Answer»


ANSWER :2
19.

How many hydroxyl ions are required for the conversion: CN_((aq))^(-) to CNO_((aq))^(-)

Answer»

Solution :`CN^(-)+OH^(-)rarrCNO^(-)`
Balancing the HALF reaction
`CN^(-)+2OH^(-)rarrCNO^(-)+H_(2)O+2e^(-)`
Number of HYDROXYL `OH^(-)` ions `= 2`
20.

How many hydrogen bonded water molecules are associated with FeSO_(4).7H_(2)O ?

Answer»

FIVE
ONE
FOUR
Three

Answer :B
21.

How many hydrogen bonded water molecule(s) are associatedwith CuSO_(4) .5 H_(2)O ?

Answer»

1
2
3
4

Solution :Only one `H_(2) O`moleculeis LINKED through
HYDROGEN bonds .
22.

How many hydrogen bonded water molecules are associated in CuSO_4. 5H_2O?

Answer»

SOLUTION : Only one WATER molecule, which is outside the COORDINATION sphere, is hydrogen BONDED with sulphate ion. The other four MOLECULES of water are coordinated with copper cation.
`CuSO_4.5H_2O-= [ Cu(H_2O)_4]SO_4. H_2O`
23.

How many hydrogen-bonded water molecule(s) are associated in CuSO_4. 5H_2O ?

Answer»

SOLUTION :Only one water molecule, which is outside the BRACKETS (COORDINATION sphere), is hydrogen bonded. The other four MOLECULES of water are coordinated.
24.

How many hydrogen atoms are replaced by D in the following tautomerization? CH_(3)-overset(Ph)overset(|)C=underset(Ph)underset(|)C-overset(O)overset(||)C-CH_(3)underset(D_(2)O)overset(D^(o+))rarr

Answer»


Solution :H-atoms which are PRESENT in conjugation with
`-overset(O)overset(||)C-` are replaced by D.
`CH_(3)-overset(CH_(3))overset(|)C=underset(CMe_(3))CH_(3) underset(D_(2)O"Longtime")overset(D^(+))rarrCD_(3)-overset(CMe_(3))overset(|)C=underset(CMe_(3))underset(|)C-CD_(3)`
25.

How many hydrogen atoms in the ground state are exited by means of monochromatic radiation of wavelength 970.6 Ã…. How many different lines are possible in the resulting emission spectrum? Find the longest wavelength among these .

Answer»


SOLUTION :`E_(n)=E_(1)=(HC)/(lamda)`
`(-21.69xx10^(-19))/(n^(2))+(21.69xx10^(-19))/(1)=(6.626xx10^(-34)xx3xx10^(8))/(970.6xx10^(-10))`
`n=4`
`(1)/(lamda)=RZ^(2)((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`
`(1)/(lamda)=109677.77xx1^(2)((1)/(1^(2))-(1)^(2^(2)))`
`lamda=1215.68`Ã…
.
26.

How many hydrogen-bonded water molecule (s) are associated in CuSO_(4).5 H_(2)O ?

Answer»

Solution :Only one water molecule, which is outside the BRACKETS (coordination sphere), is HYDRODEN bonded to `SO_(4)^(2-)` ion as shown below . The remaining four molecules are linked to `CU^(2+)` ion by COORDINATE bonds.
27.

How many hydrogen atoms are replaced by D in the following tautomerization?

Answer»


SOLUTION :N//A
28.

How many hydrocarbons having molecular mass 68 can give white precipitate with Tollen's reagentsodium bicarbonate, but B can not . The structure of A & B are respectively.

Answer»

1
2
3
4

Solution :
29.

How many H_(2)O molecules are there in a snowflake weighing 1 mg?

Answer»

`3.35xx10^(19)`
`6.023xx10^(23)`
`3.35xx10^(19)`
100

Solution :1 mg `H_(2)O`
Molar mass of `H_(2)O`=2+16=18g
1 Mole CONTAINS `6.023 xx 10^(23)` water MOLECULE
18 g contains `6.023 xx 10^(23)` water molecule
`:.` 1 mg contains `(6.023xx10^(23))/18xx1g//1000mg=3.35xx10^(19)H_(2)O` molecule.
30.

How many H will be replaced by D in product having 6 carbon on prolonged keeping?

Answer»

4
5
6
8

Solution : is the PRODUCT.
31.

How many H-bonds are formed by each H_(2) Omolecule and how many water moleculasare attached to each water molecule and in what diraction ?

Answer»

Solution :Each `H_(2) O `molecula FORMS four H-bonds, two O-atom and two with H-atoms. Futher , each ` H_(1)O`
molecule in linked to four ` H_(2)O`molecules through H-bonds tetrahedrally
32.

How many H atoms are directly attached with Patom in hypophosphorus acid ?

Answer»

0
3
2
1

Answer :C
33.

How many H-bonded water moelcule (s) are associated in CuSO_(4)5H_(2)O

Answer»


SOLUTION :Only ONE water MOLECULE which is outside of the complex is H -BONDED. The other `4.H_2O` molecules are COORDINATED
34.

How many H are replaced by D on prolonged treament in the following? CH_(3)-overset(O)overset(||)C-underset(Ph)underset(|)Ph=overset(Ph)overset(|)C-Me underset(D_(2)O)overset(D^(o+))rarr

Answer»


SOLUTION :`CD_(3)-overset(O)overset(||)C-underset(PH)underset(|)C=overset(Ph)overset(|)C-CD_(3)`
6 H will be replaced by deuterium.
35.

How many grams of sodium hydroxide must be dissolved in one litre of water to prepare its N/10 solution ? What will be its pH value ?

Answer»


Solution :For 1 L of 1 N NaOH solution, NaOH DISSOLVED = 1 G EQ. = 40 g
`:. ` For 1 L of N/10 NaOH sol. NaOH dissolved `= 40xx(1)/(10) = 4 g`
`[OH^(-)]=10^(-1) M :. [H_(3)O^(+)]=10^(-13)M`.
`PH = - log 10^(-13)=13`
36.

How many grams of potassium dichromate are required to oxidise 20.0 g of Fe^(2+) in FeSO_4 " to " Fe^(3+) if the reaction is carried out in an acidic solution ?

Answer»

SOLUTION :When dissolved in water , `K_2Cr_2O_7` dissociates into `K^+ and Cr_2O_7^(2-)` ions and `FeSO_4` dissociates into `FE^(2+) and SO_4^(2+)` ions. The skeleton EQUATION is :
`Fe^(2+) + Cr_2O_7^(2-) rarr Fe^(3+) +2Cr^(3+)`
The BALANCED equation is
`Cr_2O_7^(2-)+6FE^(2+)+14H^(+)rarr6Fe^(3+)+2Cr^(3+)+7H_2O`
Formula weight of
`K_2Cr_2O_7=2xx39+2xx52+7xx16=294`
Formula weight of `FeSO_4`
`=56+32+4xx16=152`
`:.` 1 mol `K_2Cr_2O_7=6 mol FeSO_4`
`294 ""6xx152`
`6xx152` g of `FeSO_4` require `K_2Cr_2O_7 = 294 g`
20 g of `FeSO_4` require `K_2Cr_2O_7`
`=(294)xx(6xx152)xx20=6.45g`
`K_2Cr_2O_7` required to oxidise 20 g of `FeSO_4`
`=6.45 g `
37.

How many grams of potassium dichromate are required to oxidise 20.0 g of Fe^(2+) "in" FeSO_(4) "to" Fe^(3+) if the reaction is carried out in acidic medium? Molar masses of K_(2)Cr_(2)O_(7)"and"FeSO_(7) are 294 and 152respectively

Answer»

6.45 g
7.45 g
8.45 g
9.45 g

Answer :A
38.

How many grams of potassium dichromate are required to oxidise 20.0 g of Fe^(2+) inFeSO_(4) to Fe^(3+) if the reaction is carried out in an acidic medium ? (Molar mass of K_(2)Cr_(21)O_(7) and FeSO_(4)) are 294 and 152 respectively

Answer»


Solution :`Kr_(2)Cr_(2)O_(7)+4H_(2)SO_(4)rarrK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+4H_(2)O+3[O]`
`2FeSO_(4)+H_(2)SO_(4)+OrarrFe_(2)(SO_(4))_(3)+H_(2)Oxx3`
balanced REDOX reaction
`K_(2)Cr_(2)O_(7)+6FeSO_(4)+7H_(2)SO_(4)rarrK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+3Fe_(2)(SO_(4))_(3)+7H_(2)O`
It is evident from balanced equation that 6 moles of `FeSO_(4)=1` mole of `K_(2)Cr_(2)O_(7)`
`therefore` 20 g of `FeSO_(4)` will require `K_(2)Cr_(2)O_(7)`
`=(294)/(6xx152)xx20=6.45 g`
39.

How many grams of potassium dichromate are required to oxidise 15.2 g of FeSO_(4) in acidic medium?

Answer»

Solution :To write balanced chemical equation of the redox reaction
`Cr_(2)O_(7)^(2-)+14 H^(+)+6 e^(-) rarr 2Cr^(3+)+7 H_(2)O`
`Fe^(2+) rarr Fe^(3+)+e^(-)]xx6`
`Cr_(2)O_(7)^(2-)+6 Fe^(2+)+014 H^(+) rarr 2Cr^(3+)+6Fe^(3+)+7 H_(2)O`
step 2 To calculate the amount of`K_(2)Cr_(2)O_(7)` REQUIRED
It is EVIDENT from balanced equation that
1 mole of `Cr_(2)O_(7)^(2-)=6 "moles of" Fe^(2+) "or 1 mole" k_(2)Cr_(2)O_(7)=6 "moles" FeSO_(4)`
But 1 mole of `K_(2)Cr_(2)O_(7)=2xx39+2xx52+16xx7=294g`
and 6 moles of `FeSO_(4)=6xx(56+32+16+45)=6xx152g FeSO_(4)`
Now `6xx152 g "if"FeSO_(4)` are oxidised by `K_(2)Cr_(2)O_(7)=(294xx152)/(6xx152)=4.9g`
40.

How many grams of nitric acid can be prepared from 50.0 g of KNO_3 of 80% purity ?

Answer»


SOLUTION :The coresponding equation is:
`underset(2 xx 101.11 g)(2KNO_(3)) + H_(2)SO_(4) to underset(2 xx 63.018 g)(2HNO_(3)) + K_(2)SO_(4)`
Since, the given sample of `KNO_(3)` in 50.0 g of it `(50.0 xx 80)/100= 40.0 g`
`THEREFORE 2 xx 101.11 g` of `KNO_(3)` GIVE `HNO_(3) = 2 xx 63.018 g`
`therefore 40.0 g` of `KNO_(3)` will give `HNO_(3)`
`=(2 xx 63.018)/(2 xx 101.11) xx 40.0 = 24.9 g`
Hence, the given sample of `KNO_(3)` can give 24.9 g of `HNO_(3)`
41.

How many grams of oxygen are present in a decimol of washing soda.

Answer»


ANSWER :20.8g
42.

How many grams of NaOH must be dissolved in one litre of the solution to giveit a pH value of 12 ?

Answer»

SOLUTION :`pH=-LOG[H_(3)O^(+)] :. Log[H_(3)O^(+)]=-pH=-12`
`:. [H_(3)O^(+)]`= ANTILOG (-12) = antilog `(bar(12))=10^(-12)` g ions/litre
But we know that `[H_(3)O^(+)][OH^(-)]=K_(w)=10^(-14) :. [OH^(-)]=(K_(w))/([H_(3)O^(+)])=(10^(-14))/(10^(-12))=10^(-2)` g ions/litre
Since NaOH is a strong electrolyte, it undergoes COMPLETE ionization as : `NaOH rarr Na^(+)+OH^(-)`
`:. [OH^(-)]=[NaOH]=10^(-2)M = 10^(-2) "mol" L^(-1)`
Mol. mass of NaOH = 40 `:.` Amountof NaOH dissolved PER litre `=10^(-2) xx 40 = 0.4 g`
43.

How many grams of NaOH will be required to prepare 500 g solution containing 10% w/w prepare solution ?

Answer»

100 GM
50 gm
0.5 gm
5.0 gm

Answer :B
44.

How many grams of NaOH must be dissolved in IL of the solution to give it a pH value of L^(2) ?

Answer»


ANSWER :`0.4 G`
45.

How many grams of NaOH is to be added to one litre of1 M H_2CO_3 to get a HCO_3^(-) //CO_3^(-2)buffer of maximum capacity ?

Answer»

90 gram
60 gram
20 gram
50 gram

SOLUTION :Buffer of max capacity `rArr [HCO_3^(-)]= [CO_3^(2-) ]`
` rArr H_2CO_3` was NEUTRALIZED and `HCO_3^(-) ` was `1//2` neutralized
i.e.,NaOH required `= 1xx 1 + 1 xx (1)/(2) = (3)/(2)" moles weight " = 40 xx (3)/(2)= 60 gms `
46.

How many grams of NaOH is dissolved in 2 L 0.5NaOH aqueous solution ? Molecular weight of NaOH : 40 g /mol.

Answer»

0.4 g
40 g
0.4 g
8.0 g

Answer :B::D
47.

How many grams of NaOH can neutralise 100 ml ofH_2SO_4solution with P^(H)solution with P^(H)value 3.301?

Answer»

2mg
3 mg
4 mg
0.4 mg

Solution :` pH = 3.3 rArr [H^(+) ] = 5XX 10 ^(-4) `
` therefore ` moles of acid ` = 0.1 xx 5 xx 10 ^(-4)= 5 xx 10 ^(-5) `
to NEUTRALIZE , MOLESOF NaOH`= 5 xx 10 ^(-5) `
` therefore ` weight` = 40 xx 5 xx 10 ^(-5)= 2 xx 10 ^(-3)= 2 mg `
48.

How many grams ofMgC_2O_4 (formula weight =112 )will dissolve in 1.5 Lof water ?(K_(sp) =8.1 xx 10^(5))

Answer»

`1.0`
`1.29`
`1.512`
`4.65`

Solution :` K_(Sp)=8.1 XX 10 ^(5) `
` s= 9 xx 10 ^(-3)MOL//"LT" =9 xx 10 ^(-3)xx 112 gm//"lt"`
1 LIT ___________ ` 9 xx 112 xx 10^(-3)gm `
1.5 lit ____________ ?
49.

How many grams of KMnO_(4) required for the redox reaction of 1 L of 1NMnO_(4)in acidic medium ?

Answer»

31.6
78
63.2
158

Answer :A::C
50.

How many grams of Al_2(SO_4)_3, will be required to prepare 4 litres of 0.025M solution ?

Answer»


ANSWER :34.2g