52671 + Interview Questions in Chemistry in Class 11

1.	In a compound, nithrogen atoms (N)make cubic close pakced lattice and metal atoms (M)occupyone- third tetrahedral voids present. Determine the formula of the compound formed by M andN ?
Answer»

Discussion

2.	In a compound, C, H and N are present in the ratio 9 : 1: 3.5 by weight. If the molecular weight. If the molecular weight of the compound is 108, what is the number of hydrogen atoms present in the molecular formula of the compound ?
Answer» SOLUTION :Step I. Empirical FORMULA of the COMPOUND `{:("Element","Percentage/weight (ratio)","Gram atoms (Moles)","Atomic ratio (Molar ratio)","Simplest whole no. ratio"),("C",9,(9)/(12)=0.75,(0.75)/(0.25)=3,3),("H",1,(1)/(1)=1.0,(1.00)/(0.25)=4,4),("N",3.5,(3.5)/(14)=0.25,(0.25)/(0.25)=1,1):}` Empirical formula of the compound`= C_(3)H_(4)N` Step II. Molecular formula of the compound Empirical formula mass `= 3 xx 12 + 4 xx 1 +14 = 54 u` Molecular mass = 108 u (given) `n=("Molecular mass")/("Empirical formula mass")=((108u))/((54u))=2` Molecular formula of the compound `= n xx` Empirical formula `:.` Number of HYDROGEN atoms PRESENT = 8.

Discussion

3.	In a compound C , H and N atoms are present in 9 : 1 : 3.5 by weight . Molecular weight of compound is 108. Molecular formula of compound is
Answer» `C_(2) H_(6) N_(2)` `C_(3) H_(4) N` `C_(6) H_(8)N_(2)` `C_(9) H_(12) N_(3)` Answer :C

Discussion

4.	In a compound, C, H and N are present in the ratio 9 : 1: 3.5 by weight. If the molecular weight. If the molecular weight of the compound is 108. Molecular formula of the compound is :
Answer» `C_(2)H_(6)N_(2)` `C_(3)H_(4)N` `C_(6)H_(8)N_(2)` `C_(9)H_(12)N_(3)` Solution :Percentage `C=(9)/(13.5)xx100=66.6` `H=(1)/(13.5)xx100=7.4` `N=(3.5)/(13.5)xx100=26.0` Atomic ration `C=underset(=5.5)((66.6)/(12)),H=underset(=7.4)((7.4)/(1)),N=underset(=1.86)((26.0)/(14))` Simplest ratio `C = 3,H=4,N=1` Empirical formula `= C_(3)H_(4)N` Empirical formula MASS `= 36 + 4 + 14 = 54` `n=("Molecular mass")/("Empirical formula mass")` `=(108)/(54)=2` Molecular formula `= C_(6)H_(8)N_(2)`.

Discussion

5.	In a compound, atoms of element Y form ccp lattice and those of element X occupy the corners, Y atoms in the body centred positions and Z atoms at the centres of faces of the unit cell. What is the empiricalformula of the compound ?
Answer» `XY_(2)Z_(3)` `XYZ_(3)` `X_(2)Y_(2)Z_(3)` `X_(8)YZ_(6)` SOLUTION :No. of ATOMS of X per unit CELL `=8times 1/8 = 1`(at corners) No. of atoms of Y per unit cell = 1 (at body centre) No. of atoms of Z per unit cell =`6times 1/2 = 3` (at face centres) `therefore "formula is "XYZ_(3)`

Discussion

6.	In a compound , atoms of element Y form ccp lattice and those of element X occupy 2/3rd of tetrahedral voids.The formula of the compound will be
Answer» ` X_(2)Y` ` X_(3)Y_(4)` `X_(4) Y_(3)` `X_(2)Y_(3)` ANSWER :D

Discussion

7.	In a compound, atoms of element Y form ccp lattice and those of element X occupy 2//3^(rd) of tetrahedral voids. The formula of the compound will be
Answer» `X_(3)Y_(4)` `X_(4)Y_(3)` `X_(2)Y_(3)` `X_(2)Y` Solution :NUMBER of Y atoms per unit CELL in ccp lattice (N) = 4 Number of tetrahedral voids `= 2N=2xx4=8` Number of tetrahedral voids occupied by `X=(2)/(3)rd` of the tetrahedral void `=(2)/(3)xx8=(16)/(3)` HENCE, the formula of the COMPOUND will be `X_(16//3)Y_(4)=X_(4)Y_(3)`

Discussion

8.	In a complex compound ligand acts as
Answer» Lewis acid Lewis BASE Lowry-Bronsted acid ARRHENIUS base SOLUTION :` SiF_4`has vacant d- orbitals but cannot add or GIVES`H^(+) ` ` CO_2`cannotadd or give ` H^(+) ` ` SO_2`has lone pair ` NH_3`can give and TAKE `H^(+) `and has lone pair

Discussion

9.	In a colloidal solution of AgCl in water the AgCl particles
Answer» do not CARRY any CHARGE carry a +ve charge carry a -ve charge may carry a +ve or -ve charge depending upon conditions. Solution :AgCl particles in colloidal solution canadsorb both `Ag^(+)` or `CL^(-)` IONS depending upon which EVER is present in excess.

Discussion

10.	In a collection of H-atoms, all the elctrons jump from n = 5 to ground level finally (directly or indirectly), without emitting any line in Balmer series. The number of possible different photons are
Answer» 10 8 7 6 Solution :NUMBER of SPECTRUM LINES `=(N(n-1))/(2)`

Discussion

11.	In a closed vessel the rate of solubility of sugar and rate of crystallization is same. What it indicate ?
Answer» SOLUTION :At this temperature SATURATED solution of SUGAR in WATER and solubility of sugar remains constant.

Discussion

12.	In a closed vessel at 25^(@)C temperature 4 mole O_(2), 3 mole Cl_(2) and 3 mole N_(2) are mixed and the total pressure found is 50 bar. Find the partial pressure of each gas.
Answer» <P> Answer :`p_(O_(2))=20` BAR, `p_(Cl_(2))=15` bar, `p_(N_(2))=15` bar

Discussion

13.	In a closed vessel at 448^@C 0.5 mol H_2 and 0.5 mol I_2 react and from hydrogen iodide. Reaction H_(2(g)) + I_(2(g)) hArr2HI_((g)) of K_c = 50. (i) At equilibrium the moles of I_2 which are unreacted. (ii) Calculate K_p.
Answer» SOLUTION :`K_c=K_p`=50, 0.11 MOL `I_2`

Discussion

14.	In a closed system A(S) hArr 3 B(g)+3C(g) If partial pressure of C is doubled, then partial pressuer of B will be ........ Time the original value.
Answer» SOLUTION :`(1)/(SQRT(2))`

Discussion

15.	In a closed system : A_((s))hArr2B_((g))+3C_((g)) if the partial pressure of C is doubled then partial pressure of B will be
Answer» TWICW the ORIGNAL PRESSURE Half of its orignal pressure `(1)/(2sqrt(2))` times, the original pressure `2sqrt(2)` times its original pressure Answer :C

Discussion

16.	In a closed room of 1000m^(3) a perfume bottle is opened up. The room develops a smell. This is due to which property of gases?
Answer» Viscosity Density DIFFUSION None Solution :PARTICLE of gas are FREELY to MOVE. Particles spread throughout the move due to the diffusion.

Discussion

17.	In a closed system: A(s) hArr 2B(g)+3C(g), if the partial pressure of C is doubled at equillibrium, then partial pressure of B will be :
Answer» TWO TIMES the original value one-half of its original value `(1)/(2sqrt2)` times the original value `2sqrt2` times the original value Answer :C

Discussion

18.	In a closed container two reactions take place simultaneously (i) PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)and (ii)CO(g)+Cl_(2)(g)hArr COCl_(2)(g) On adding more CO into the container, select the correct option : (P) Degree of dissociation of PCl_(5)(g) decreases. (Q) Conc. of CO(g) at new equilibrium position is less than that of at initial equilibrium conc. (R) Degree of dissociation of PCl_(5)(g) increases.
Answer» <P>Only (P) Only (R) Both (P) and (Q) Both (Q) and (R) ANSWER :B

Discussion

19.	In a closed container at 1 atm pressure, 2 mole of SO_(2) (g) and 1 mole of O_(2)(g) were allowed to react to form SO_(3)(g) under the influence of a catalyst. The following reaction occurred: 2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g) At equilibrium it was found that 50% of SO_(2)(g) was converted to SO_(3)(g). The partial pressure of O_(2)(g) at equilibrium will be :
Answer» 0.66 atm 0.493 atm 0.33 atm 0.2 atm Answer :D

Discussion

20.	In a closed container following equilibrium will be attained- A(s)+B(g)hArrAB(g) B(g)+C(g)hArrBC(g) On adding He gas (inert) to the above system at constant pressure & temperature
Answer» Amount of `AB(g)` will be increased surely Amount of `B(g)` will be decreased surely Amount of `C(g)` will be decreased surely. Amount of `BC(g)` will be decreased surely. Solution :On addign INERT gas at content temperature & pressure `2^(nd)` reaction will be shifted in backward direction.

Discussion

21.	In a closed container and at constant temperature 0.3 mole of SO_(2) & 0.2 mole of O_(2) gas at 750 torr are kept with a catalyst . If at equilibrium 0.2 mole of SO_(3) is formed the partial pressure of SO_(2) is …torr
Answer» 375 187 360 150 Answer :D

Discussion

22.	In a close vessel PCl_(5(g))is obtained by the chemical reaction between PCl_3 and Cl_2. If the equilibrium concentration in this vessel of PCl_3, Cl_2 and PCl_5 at 500 K tempe. is 1.59 M, 1.59 M and 1.41M respectively. Than find equilibrium constant. PCl_(3(g)) + Cl_(2(g)) hArr PCl_(5(g))
Answer» SOLUTION :`K_c="0.558 mol L"^(-1) , K_P = 1.3xx10^(-2)`BAR

Discussion

23.	In a chemical reaction, chlorine atom undergoes reduction and aluminium atom undergoes oxidation. Will this redox reaction affect their initial number of protons, neutrons and electrons?
Answer» Solution :Chlorine atom on accepting an electron BECOMES `Cl^(-)` and aluminium atom after donating an electron becomes `Al^(3+)` This changes will affect their number of protons, neutrons and ELECTRONS. `Cl^(-)` : No. of electrons = 17 + 1 = 18 No. of protons = 17 No. of neutrons = 35 - 17 = 18 `Al^(3+)` : No. of electrons = 13 - 3 = 10 No. of protons = 13 No. of neutrons = 27 - 13 = 14

Discussion

24.	In a chemical equilibrium, the rate constant for the forward reaction is 2.5xx10^(2) and the equilibrium constant is 50. The rate constant for the reverse reaction is.....
Answer» 11.5 5 `2XX10^(2)` `2xx10^(-3)` Solution :`K_(f)=2.5xx10^(2)`,`K_(C)=50` K=? `K_(C)=(K_(f))/(K_(R))rArr50=(2.5xx10^(2))/(K_(r))rArrK_(r)=5`

Discussion

25.	In a chemical equilibrium, the rate constant for the forward reaction is 2.5xx10^(2) and the equilibrium constant of 50. The rate constant for the revese reaction is.
Answer» 11.5 5 `2XX10^(2)` `2xx10^(-3)` ANSWER :B

Discussion

26.	In a certain sample of gas at 25^(@)C the number of molecules having speeds between 4 km sec^(-1) and 4.1 km "sec"^(-1) is N. if the total number of gas molecules at the same temperature are doubled what will happen?
Answer» Value of most probable velocity will change Area under the Maxwell's curve for distribution of speeds will INCREASES by four times. No of MOLECULES between 4 km `"SEC"^(-1)` and 4.1 km `"sec"^(-1)` will become 2N. No of molecules between 4km `"sec"^(-1)` amd 4.1 km `"sec"^(-1)` will remain same. Answer :c

Discussion

27.	In a certain polar solvent, PCl_(5) undergoes ioonisation as follows: 2PC l_(5) hArr PCl_(4)^(+)+PCl_(6)^(-), predict geometrical shapes of all the species involved.
Answer» Solution :The geometrical shapes of the molecules or ions can be PREDICTED from the hybridisation state of the central atom. for `PC l_(5):H=(1)/(2)[5+5-0+0]=(10)/(2)=5` THEREFORE, central P-atom is `SP^(3)d`-hybridised. Consequently, the molecule is trigonal bipyramidal in shape. For `PCl_(4)^(+):H=(1)/(2)[5+4-1+0]=(8)/(2)=4`. Therefore, central P-atom is `sp^(3)`-hybridised. consequently, the geometrical shape of this ion is tetrahedral. For `PCl_(6)^(-):H=(1)/(2)[5+6-0+1]=(12)/(2)=6`. Thereofore, the central P-atom is `sp^(3)d^(2)` hybridised. consequently, the geometrical shape of the ion is octahedral.

Discussion

28.	In a certain electronic transition from the quantum level, 'n' to the ground state in atomic hydrogen in one or more steps, no line belonging to the Bracket series is observed. What wave number may be observed in the Balmer series ? (R = Rydberg Constant)
Answer» Answer :BAR(vartheta) = (3R)/(16); bar(vartheta) = (5R)/(36)`

Discussion

29.	In a ccp structure of X atoms, Y atoms occupy all the octahedral holes. If 2X atom are removed from corners and replaced by Z, then the formula of the compound will be
Answer» `X_(15)Y_(16)Z` `X_(7)Y_(8)Z` `X_(7.5)Y_(8)Z` `X_(8)Y_(8)Z_(3)` Answer :A

Discussion

30.	In a carius determination, 0.234g of an organic substance gave 0.334g of barium sulphate. Calculate the weight percentage of sulphur in the given compound
Answer» ANSWER :0.1966

Discussion

31.	In a buffer solution consisting NaH_2PO_4 and Na_2HPO_4select the correct statement among the following
Answer» `NaH_2PO_4 ` is ACID and `Na_2HPO_4` is SALT The PH of solution can be calculated using the relation ` :pH =pK_2+ log _(10) "" ([HPO_4^(2-)])/([H_2PO_4^(-) ]) ` `Na_2HPO_4` is acid and `NaH_2PO_4` is salt The pH cannot be calculated Solution :`H_2 PO_4^(-)to HPO_4 ^(2- )` ` A "" " salt of Wa" ` ` pH =pKa_2 +log ""(["salt"])/(["acid"]) `

Discussion

32.	In a bonded molecule, the order of repulsion between the bonded and non-bonded electrons is
Answer» LONE PAIR - lone pair `GT` BOND pair - bond pair `gt` lone pair - bond pair bond pair - bond pair `gt` lone pair - lone pair `gt` lone pair - bond pair lone pair - lone pair `gt` lone pair - bond pair `gt` bond pair - bond pair bond pair - bond pair `gt` lone pair - bond pair `gt` lone pair - lone pair. Answer :C

Discussion

33.	In a bomb calorimeter , volume is constant. Do you think thatDeltaH = DeltaU? Why or why not ?
Answer» Solution :No, `DeltaH cancel(=) DeltaU`. This is BECAUSETHE relation `DeltaH = DeltaU + P DeltaV` holds good only at constant PRESSURE. This may be seen as FOLLOWS `:` `H =U +P Delta V :. Delta H= Delta U + Pdelta V + V DeltaP` At constant pressure, `Delta p = 0 ,:.DeltaH = Delta U +P DeltaV` At constant VOLUME, `Delta V = 0 , ,' DeltaH = Delta U + VDeltaP`

Discussion

34.	In a Bohr's model of atom when an electron jumps from n=1 to n=3 , how much energy will be emitted or absorbed
Answer» `2.15xx10^(-11)` ERG `0.1911xx10^(-10)` erg `2.389xx10^(-12)` erg `0.239xx10^(-10)` erg Solution :According to Bohr's model `DeltaE=E_1-E_3` `=2.179xx10^(-11)-(2.179xx10^11)/9` `=8/9xx2.179xx10^(-11)=1.91xx10^(-11)=0.191xx10^(-10) ` erg Since ELECTRON is GOING from n=1 to n=3 HENCE energy is absorbed

Discussion

35.	In a body-centred cubic crystal of an element , the ratio of the readius of the radius of the atom toi the edge of the unit cell is ……
Answer» ANSWER :No. of atoms PER unitcell, AVOGADRO, NUMBER

Discussion

36.	In a body-centred cubic crystal of an element, the ratio of the radius of the atom to the edge of the unit cell is __________
Answer» ANSWER :0.433

Discussion

37.	In a body centred cubic cell, an atom at the body of centre is shared by:
Answer» 1 unit CELL 2 unit CELLS 3 unit cells 4 unit cells ANSWER :A

Discussion

38.	In a binary solution.
Answer» SOLVENT my be LIQUID solvent may be SOLID SOLUTE may be gas any of THSES Answer :D

Discussion

39.	In a basic buffer, 0.0025 mole of NH_(4)Cl and 0.15 mole of NH_(4) OH are present. The pH of the solution will be (pK_(a)=4.74)
Answer» 11.04 10.24 6.62 5.48 Solution :From Henderson's equation, `POH = pK_(b) + log. (["Salt"])/(["Base"])` `=4.74+log.(0.0025//V)/(0.15//V)=4.74+log. (1)/(60)` `=4.76-1.78=2.96`. HENCE, pH = 14 - pOH = 14 - 2.96 = 11.04.

Discussion

40.	In a bcc-arrangement which of the marked planes have maximum spatial density of atoms ?
Answer» 1 2 3 4 Answer :A

Discussion

41.	In a balanced redox reaction net gain of electron (s) is equal to net loss of electrons (s).n_("factor") isa reaction specific parameter and for intermolecular redox reaction n-factor of oxidising reducing agent is the no. of moles of electron gained /lost by one mole of compound. 50mL 0.1 M CuSO_(4) are mixed with 50mL of 0.1 M KI then, number of moles of electrons involved in the reaction will be:
Answer» 4 2.5 `2.5xx10^(-3)` NONE of these Answer :C

Discussion

42.	In a balanced equation H_(2)SO_(4)+xHIrarrH_(2)S+yI_(2)+zH_(2)O. The values of x,y and z are
Answer» 3, 5 & 2 4, 8 & 5 8, 4 & 4 5, 3 & 4 Answer :C

Discussion

43.	In a attempt to prepare propane by Wurtz reation 1 mole of methyl bromide and 1 mole of ethyl bromide are treated with sodium . Assuming equal probability for all possible reaction . How many 'g' of propane will be obtained ?
Answer» `44G` `22G` `33G` `14.67g` ANSWER :A::D

Discussion

44.	In A^(+)B^(-) ionic compound, radii of A^(+) and B^(-) ions are 180 and 187pm respectively. The crystal structure of the compound will be
Answer» NaCl type CsCl type ZnS type similar to diamond Solution :(b) `(R^(+))/(r^(-))=(180)/(187)=0.96`, this VALUE lies in the RANGE of 0.732-1.000

Discussion

45.	In a 7.0 L evacuated chamber, 0.50 mole H_(2) and 0.50 mole I_(2) react at 427^(@) C. According to reaction H_(2)(g)+I_(2)(g)hArr2HI(g) At the given temperature, K_(c)=49 for the reaction. What is the partial pressure (atm) of HI in the equilibrium mixture?
Answer» 6.371 12.77 40.768 646.58 Answer :A

Discussion

46.	In a 7.0 L evacuated chamber, 0.50 mole H_(2) and 0.50 mole I_(2) react at 427^(@) C. According to reaction H_(2)(g)+I_(2)(g)hArr2HI(g) At the given temperature, K_(c)=49 for the reaction. What is the value of K_(p)?
Answer» 7 49 24.35 None of these Answer :B

Discussion

47.	In a 7.0 L evacuated chamber, 0.50 mole H_(2) and 0.50 mole I_(2) react at 427^(@) C. According to reaction H_(2)(g)+I_(2)(g)hArr2HI(g) At the given temperature, K_(c)=49 for the reaction. How many moles of the iodine remain unreached at equilibrium?
Answer» 0.388 0.112 0.25 0.125 Answer :B

Discussion

48.	In a 7.0 L evacuated chamber, 0.50 mole H_(2) and 0.50 mole I_(2) react at 427^(@) C. According to reaction H_(2)(g)+I_(2)(g)hArr2HI(g) At the given temperature, K_(c)=49 for the reaction. What is the total pressure (atm) in the chamber?
Answer» 83.14 831.4 8.21 None of these Answer :C

Discussion

49.	In a 7.0 Levacuated chamber, 0.50 mol H_(2) and 0.50 mol I_(2) react at 427^(@) C. H_(2) (g) + I_(2) (g) hArr HI (g)+ Heat , At the given temperature, K_(c) = 49for the reaction.What is the total pressure (atm) in the chamber ?
Answer» <P>83.14 831.4 8.21 None of these Solution :PV=nRT `IMPLIES p=(nRT)/(V)=(1 xx 0.0821 xx 700)/(7)=8.21` atm

Discussion

50.	In a 7.0 Levacuated chamber, 0.50 mol H_(2) and 0.50 mol I_(2) react at 427^(@) C. H_(2) (g) + I_(2) (g) hArr HI (g)+ Heat , At the given temperature, K_(c) = 49for the reaction.what is the value of K_(p) ?
Answer» <P>7 49 24.5 None of these Solution :`K_(P)=K_(c), DELTA ng =0`

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

In a compound, nithrogen atoms (N)make cubic close pakced lattice and metal atoms (M)occupyone- third tetrahedral voids present. Determine the formula of the compound formed by M andN ?

In a compound, C, H and N are present in the ratio 9 : 1: 3.5 by weight. If the molecular weight. If the molecular weight of the compound is 108, what is the number of hydrogen atoms present in the molecular formula of the compound ?

In a compound C , H and N atoms are present in 9 : 1 : 3.5 by weight . Molecular weight of compound is 108. Molecular formula of compound is

In a compound, C, H and N are present in the ratio 9 : 1: 3.5 by weight. If the molecular weight. If the molecular weight of the compound is 108. Molecular formula of the compound is :

In a compound, atoms of element Y form ccp lattice and those of element X occupy the corners, Y atoms in the body centred positions and Z atoms at the centres of faces of the unit cell. What is the empiricalformula of the compound ?

In a compound , atoms of element Y form ccp lattice and those of element X occupy 2/3rd of tetrahedral voids.The formula of the compound will be

In a compound, atoms of element Y form ccp lattice and those of element X occupy 2//3^(rd) of tetrahedral voids. The formula of the compound will be

In a complex compound ligand acts as

In a colloidal solution of AgCl in water the AgCl particles

In a collection of H-atoms, all the elctrons jump from n = 5 to ground level finally (directly or indirectly), without emitting any line in Balmer series. The number of possible different photons are

In a closed vessel the rate of solubility of sugar and rate of crystallization is same. What it indicate ?

In a closed vessel at 25^(@)C temperature 4 mole O_(2), 3 mole Cl_(2) and 3 mole N_(2) are mixed and the total pressure found is 50 bar. Find the partial pressure of each gas.

In a closed vessel at 448^@C 0.5 mol H_2 and 0.5 mol I_2 react and from hydrogen iodide. Reaction H_(2(g)) + I_(2(g)) hArr2HI_((g)) of K_c = 50. (i) At equilibrium the moles of I_2 which are unreacted. (ii) Calculate K_p.

In a closed system A(S) hArr 3 B(g)+3C(g) If partial pressure of C is doubled, then partial pressuer of B will be ........ Time the original value.

In a closed system : A_((s))hArr2B_((g))+3C_((g)) if the partial pressure of C is doubled then partial pressure of B will be

In a closed room of 1000m^(3) a perfume bottle is opened up. The room develops a smell. This is due to which property of gases?

In a closed system: A(s) hArr 2B(g)+3C(g), if the partial pressure of C is doubled at equillibrium, then partial pressure of B will be :

In a closed container following equilibrium will be attained- A(s)+B(g)hArrAB(g) B(g)+C(g)hArrBC(g) On adding He gas (inert) to the above system at constant pressure & temperature

In a closed container and at constant temperature 0.3 mole of SO_(2) & 0.2 mole of O_(2) gas at 750 torr are kept with a catalyst . If at equilibrium 0.2 mole of SO_(3) is formed the partial pressure of SO_(2) is …torr

In a close vessel PCl_(5(g))is obtained by the chemical reaction between PCl_3 and Cl_2. If the equilibrium concentration in this vessel of PCl_3, Cl_2 and PCl_5 at 500 K tempe. is 1.59 M, 1.59 M and 1.41M respectively. Than find equilibrium constant. PCl_(3(g)) + Cl_(2(g)) hArr PCl_(5(g))

In a chemical reaction, chlorine atom undergoes reduction and aluminium atom undergoes oxidation. Will this redox reaction affect their initial number of protons, neutrons and electrons?

In a chemical equilibrium, the rate constant for the forward reaction is 2.5xx10^(2) and the equilibrium constant is 50. The rate constant for the reverse reaction is.....

In a chemical equilibrium, the rate constant for the forward reaction is 2.5xx10^(2) and the equilibrium constant of 50. The rate constant for the revese reaction is.

In a certain sample of gas at 25^(@)C the number of molecules having speeds between 4 km sec^(-1) and 4.1 km "sec"^(-1) is N. if the total number of gas molecules at the same temperature are doubled what will happen?

In a certain polar solvent, PCl_(5) undergoes ioonisation as follows: 2PC l_(5) hArr PCl_(4)^(+)+PCl_(6)^(-), predict geometrical shapes of all the species involved.

In a certain electronic transition from the quantum level, 'n' to the ground state in atomic hydrogen in one or more steps, no line belonging to the Bracket series is observed. What wave number may be observed in the Balmer series ? (R = Rydberg Constant)

In a ccp structure of X atoms, Y atoms occupy all the octahedral holes. If 2X atom are removed from corners and replaced by Z, then the formula of the compound will be

In a carius determination, 0.234g of an organic substance gave 0.334g of barium sulphate. Calculate the weight percentage of sulphur in the given compound

In a buffer solution consisting NaH_2PO_4 and Na_2HPO_4select the correct statement among the following

In a bonded molecule, the order of repulsion between the bonded and non-bonded electrons is

In a bomb calorimeter , volume is constant. Do you think thatDeltaH = DeltaU? Why or why not ?

In a Bohr's model of atom when an electron jumps from n=1 to n=3 , how much energy will be emitted or absorbed

In a body-centred cubic crystal of an element , the ratio of the readius of the radius of the atom toi the edge of the unit cell is ……

In a body-centred cubic crystal of an element, the ratio of the radius of the atom to the edge of the unit cell is __________

In a body centred cubic cell, an atom at the body of centre is shared by:

In a binary solution.

In a basic buffer, 0.0025 mole of NH_(4)Cl and 0.15 mole of NH_(4) OH are present. The pH of the solution will be (pK_(a)=4.74)

In a bcc-arrangement which of the marked planes have maximum spatial density of atoms ?

In a balanced equation H_(2)SO_(4)+xHIrarrH_(2)S+yI_(2)+zH_(2)O. The values of x,y and z are

In a attempt to prepare propane by Wurtz reation 1 mole of methyl bromide and 1 mole of ethyl bromide are treated with sodium . Assuming equal probability for all possible reaction . How many 'g' of propane will be obtained ?

In A^(+)B^(-) ionic compound, radii of A^(+) and B^(-) ions are 180 and 187pm respectively. The crystal structure of the compound will be

In a 7.0 L evacuated chamber, 0.50 mole H_(2) and 0.50 mole I_(2) react at 427^(@) C. According to reaction H_(2)(g)+I_(2)(g)hArr2HI(g) At the given temperature, K_(c)=49 for the reaction. What is the partial pressure (atm) of HI in the equilibrium mixture?

In a 7.0 L evacuated chamber, 0.50 mole H_(2) and 0.50 mole I_(2) react at 427^(@) C. According to reaction H_(2)(g)+I_(2)(g)hArr2HI(g) At the given temperature, K_(c)=49 for the reaction. What is the value of K_(p)?

In a 7.0 L evacuated chamber, 0.50 mole H_(2) and 0.50 mole I_(2) react at 427^(@) C. According to reaction H_(2)(g)+I_(2)(g)hArr2HI(g) At the given temperature, K_(c)=49 for the reaction. How many moles of the iodine remain unreached at equilibrium?

In a 7.0 L evacuated chamber, 0.50 mole H_(2) and 0.50 mole I_(2) react at 427^(@) C. According to reaction H_(2)(g)+I_(2)(g)hArr2HI(g) At the given temperature, K_(c)=49 for the reaction. What is the total pressure (atm) in the chamber?

In a 7.0 Levacuated chamber, 0.50 mol H_(2) and 0.50 mol I_(2) react at 427^(@) C. H_(2) (g) + I_(2) (g) hArr HI (g)+ Heat , At the given temperature, K_(c) = 49for the reaction.What is the total pressure (atm) in the chamber ?

In a 7.0 Levacuated chamber, 0.50 mol H_(2) and 0.50 mol I_(2) react at 427^(@) C. H_(2) (g) + I_(2) (g) hArr HI (g)+ Heat , At the given temperature, K_(c) = 49for the reaction.what is the value of K_(p) ?