52671 + Interview Questions in Chemistry in Class 11

1.	Schottky defect is observed in crystal when ______
Answer» some CATIONS move from their LATTICE sites to interstitial sites equal NUMBER of cations and anions are missing from the lattice. some lattice sites are occupied by electrons some impurity is present in the lattice. ANSWER :b

Discussion

2.	Schottky defect is observed in crystal when ………
Answer» some CATIONS move from their lattice sites to interstitial sites. equal NUMBER of cations and anions are missing from the lattice. some lattice sites are occupied by ELECTRONS. Some IMPURITY is present in the lattice. Answer :B

Discussion

3.	Schottky defect generally appears in
Answer» CSCL KCL NACL All Solution :Schottky defect is common in highly ionic compounds with high coordination number and SIZE of two ions (cations and anions) are almost same. e.g. NaCl, CsCl, KCl and KBr.

Discussion

4.	Schotten Baumann reaction is
Answer» `"Phenol + BENZOYL CHLORIDE" overset(NaOH)rarr "Phenyl banzoate"` `"Sodium phenate + methyl iodide" overset(-HCl)rarr "Anisole"` `"Phenol + Chloroform" overset(NaOH)rarr "SALICYLADEHYDE"` `"Benzene DIAZONIUM chloride + Phenol"rarr beta-"Hydroxyazobenzene"` SOLUTION :The reaction of phenols with benzoyl chloride in the presence of aq. NaOH is known as Schotten Baumann reaction.

Discussion

5.	Schiff's base and Schiff's reagent are
Answer» STRUCTURAL isomers ENTIRELY DIFFERENT COMPOUNDS Anomers Disteromers Solution :Entirely different compounds

Discussion

6.	Schiff's and Piria method is used for the estimation of:
Answer» nitrogen sulphur halogens oxygen Answer :C

Discussion

7.	Scattering of light takes place in
Answer» electrolysis collodial solutions electroplating SOLUTION of electrolytes. Solution :Scattering of light TAKES PLACE in case of colloidal solution (Tyndall effect ).

Discussion

8.	Saturatedsolutionof crudeNaCl overset("x ") toPureNaCl.In thereaction ,X is___
Answer» HCIgas `NHO_(3)` gas `NH_(3)` gas `H_(2) SO_(4) `gas Answer :A

Discussion

9.	Satement 1 A solution of FeSO_(54) can be stored in a copper vessel Statement 2 2E^(@) "of" Cu "lt" E^(@) of Fe
Answer» Statement 1 is true statement 2 is true , statement 2 is a corrrect EXPLANATION for statement 1 Statement 1 is true statement 2 is true statement 2 is not a correct explanation for statement 1 Statement 1 is true statement 2 is false Statement 1 is false statement 2 is true SOLUTION :Correct statement 2 `E^(@)` of Fe is lower than `E^(@)` of Cu

Discussion

10.	Sate Gay Lussac's Law. Calculate the pressure exerted by 4 mole of agas occuping a volume of 1.5m^(3) at 100 K. Given R=8.314 J/k/mol.
Answer» Solution :GAY Lussac.s law (PRESSURE-temperature relationship) Gay Lussac.s law states that at constant volume, pressure of a fixed amount of a GAS varies DIRECTLY with the temperature. Given `n=4` moles `V=1.5m^(3),T=100klR=8.314`J/kmol, `P=?` `P=nRTimplies(nRT)/V=(4"moles"xx8.314"Jk mol"xx100k)/(1.5m^(3))=8269Pa`

Discussion

11.	Saponification of ethyl benzoate with caustic soda as alkalie, gives
Answer» Benzyl alochol, ETHANOIC ACID Sodium benzoate, ethanol Benzoic acid, Sodium ethoxide Phenol, ethanoic acid Solution :`underset("Acetaldehyde")(C_(6)H_(5)OVERSET(O)overset(\|\|)(C) - OC_(2)H_(5))overset(NaOH)rarr underset("Ethanol")(C_(2)H_(5)OH) + underset("Sodium benzoate")(C_(6)H_(5)COONA)`

Discussion

12.	Saponification means hydrolysis of an ester with
Answer» DIL. NAOH `dil.H_(2)SO_(4)` enzymes none of the above Solution :dil. NaOH.

Discussion

13.	Saponification of an oil results in the formation of
Answer» Glycol GLYCEROL Sodium SALT of an ACID Glycerol and SOAP Solution :Glycerol and soap

Discussion

14.	Sample of water has hardness 77.5ppm Ca^(2+). If this is passed through an ion exchange column where Ca^(2+) is replaced by H^(+), what is the pH of water after it has been so treated
Answer» 1.4 4.4 2.4 5.4 Answer :C

Discussion

15.	Sample of different gases are given at different conditions in column-I and column-II consisting of translational kinetic energy of these gases at given conditions. {:(,"Column-I",,"Column-II"),("(P)",2mole SO_(2)(g)at 700K,,"(1)Maximum K.E. per gram"),("(Q)",1 mole SO_(3)(g)at 400K,,"(2)Maximum total K.E."),("(R)",4 mole CH_(4)(g)at 300K,,"(3)Maximum K.E. per gram"),("(S)",2.5 mole He(g)at 450 K,,"(4)Minimum K.E. per molecule"):}
Answer» `{:("PQRS"),("4312"):}` `{:("PQRS"),("2314"):}` `{:("PQRS"),("1234"):}` `{:("PQRS"),("2341"):}` ANSWER :(d)

Discussion

16.	Same volume of two monoatomic gases A and B is mixed at same temperature. ........ .. Is (C_p)/( C_v) = ….......
Answer» `0.83` `1.67` `3.3` `3.30` SOLUTION :`C_(p) = (5)/(2) R, C_(v) = (3)/(2) R` `therefore (C_p)/( C_v) = (5)/(3) = 1.67`

Discussion

17.	Same reasons are given reagarding the limited use of H_(2) as fuel (I) Its calorific value is low (II) It availability in free state is less (III) It is difficult to store (IV) Its transportation is easy The correct statement are
Answer» I,II and III II,III and IV All are CORRECT II and III Answer :D

Discussion

18.	Same mass of diamond and graphite ( bothbeing carbon) are burnt in oxygen. Will be heat produced be same or different ? Why ?
Answer» Solution :Heat EVOLVED will be difficult . This is because they have DIFFERENT crystal STRUCTURE.

Discussion

19.	Same functional group containing different organic compounds possesses………chemical reaction
Answer» not equal sam same and not same not decided Answer :B

Discussion

20.	Same amount of metal combines with 0.1g of oxygen and lg of a halogen. Hence the equivalent mass of halogen is :
Answer» 9 35.5 80 127 Solution :0.1 GM `rarr` 1 gof halogen `8 G O_(2) rarr ? = 80` The amount of the substance which combines with the 8gm of oxygen is CALLED its eqwt.

Discussion

21.	Samarium-62 is the member of.....
Answer» s-block element p-block element d-block element f-block element Answer :d

Discussion

22.	samall quantities of solutionof componds TX ,TYand TZ are put in to separate test tubes cntaining x y and z solutoin Tx does not react with any of these TY reacts oth with x and z tz rectswithx th drcasing order of ase of oxidation of the anons X^(-) Y^(-0) and Z^(-1) id
Answer» `Y^(-),Z^(-),X^(-)` `Z^(-),X^(-),Y^(-)` `Y^(-),X^(-),Z^(-)` `X^(-),Z^(-),Y^(-)` Solution :Since TX does not react with any of the solution it means that `X^(-)` is least EASILY oxidizedsince TY reacts with both X and Z i.r `Y^(-) +XrarrX^(-)+Y` and `Y^(-)+ZrarrZ^(-)+Y` THEREFORE `Y^(-)` is mosteasily oxidizedsince tZ reacts with ony X i.r `Z^(-)`is more easily oxidized than `X^(-)` combining all the result the decreasing order of OXIDATION of anions follows the order `Y^(-)GTZ^(-)gtX^(-)`

Discussion

23.	Salts given in column-I reacts with the excess of reagents given in column-II and form white/coloured precipitates. Select the correct options for the salts given in column-I with the reagent(s) given in the column-II.
Answer» SOLUTION :`ZN^(2+)` is soluble in excess `NaOH` and `NH_(3)` solution. `CU^(2+)` is soluble in `NH_(3)` solution (excess).

Discussion

24.	Salt (W) gives golden yellow colouration in Bunsen flame. When (W) is oxidised by acidified K_(2)Cr_(2)O_(7), a colourless gas (X) is evolved which turns lime water milky and the milkiness disappears on passing excess of gas (X). However gas (X) does not decolourise pink solution of acidified KMnO_(4). when aqueous solution of salt (W) is added slowly to hydrated MnO_(2), red coloured solution is obtained due to formation of soluble complex (Y) along with evolution of gas (X). The red coloured complex (Y) is:
Answer» `[Mn(C_(2)O_(4))_(3)]^(2-)` `[Mn(C_(2)O_(4))_(3)]^(3-)` `[MnCI_(4)]^(-)`0 `[Mn(NH_(3))_(6)]^(2+)` Solution :`underset((W))(Na_(2)C_(2)O_(4))+K_(2)Cr_(2)OP_(7) rarr underset((X))(CO_(2)),` `7C_(2)O_(4)^(2-)+2MnO(OH)_(2)darr +8H^(+) rarr 2[Mn(C_(2)O_(4))_(3)]^(3-)+2CO_(2)uarr +6H_(2)O`

Discussion

25.	Salt (W) gives golden yellow colouration in Bunsen flame. When (W) is oxidised by acidified K_(2)Cr_(2)O_(7), a colourless gas (X) is evolved which turns lime water milky and the milkiness disappears on passing excess of gas (X). However gas (X) does not decolourise pink solution of acidified KMnO_(4). when aqueous solution of salt (W) is added slowly to hydrated MnO_(2), red coloured solution is obtained due to formation of soluble complex (Y) along with evolution of gas (X). The salt (W) is:
Answer» `HCOONa` `CH_(3)COONa` `Na_(2)C_(2)O_(4)` `Na_(2)SO_(3)` Solution :`underset((W))(Na_(2)C_(2)O_(4))+K_(2)Cr_(2)OP_(7) rarr underset((x))(CO_(2)),` `7C_(2)O_(4)^(2-)+2MnO(OH)_(2)darr +8H^(+) rarr 2[Mn(C_(2)O_(4))_(3)]^(3-)+2CO_(2)uarr +6H_(2)O`

Discussion

26.	Salt (W) gives golden yellow colouration in Bunsen flame. When (W) is oxidised by acidified K_(2)Cr_(2)O_(7), a colourless gas (X) is evolved which turns lime water milky and the milkiness disappears on passing excess of gas (X). However gas (X) does not decolourise pink solution of acidified KMnO_(4). when aqueous solution of salt (W) is added slowly to hydrated MnO_(2), red coloured solution is obtained due to formation of soluble complex (Y) along with evolution of gas (X). Gas (X) is:
Answer» `CO_(2)` `SO_(2)` `SO_(3)` `NO_(2)` Solution :`underset((w))(Na_(2)C_(2)O_(4))+K_(2)Cr_(2)OP_(7) rarr underset((x))(CO_(2)),` `7C_(2)O_(4)^(2-)+2MnO(OH)_(2)DARR +8H^(+) rarr 2[Mn(C_(2)O_(4))_(3)]^(3-)+2CO_(2)uarr +6H_(2)O`

Discussion

27.	Salt solution of 'A' + dil. HCI rarr only 'B' gas{:(("suffocating odour of burning sulphur")),(""darrBaCI_(2)),('C'["white ppt"]rarr"Soluble in dilHCI and gives 'B' gas"),(""darr"Reagent M"),("White ppt.of"[D]("insoluble in dilHCI")):} Find the total number of reagents 'M': (conc. HNO_(3)),O_(2),H_(2)O_(2),N_(2),NH_(3),(Br_(2)+H_(2)O)
Answer» <BR> Solution :`HNO_(3),O_(2),H_(2)O_(2),(Br_(2)+H_(2)O)`

Discussion

28.	Salt is a mixed form of acidic and basic radical. The confirmatory test of basic and acidic radicals by using chemical reagent is called qualitative analysis. Precipitation reaction is used for the confirmatory test of radicals. Which of the following is an example of IIA group basic radical sulphide?
Answer» `MNS` `FES` `CDS` `Na_(2)S` Answer :C

Discussion

29.	Salt is a mixed form of acidic and basic radical. The confirmatory test of basic and acidic radicals by using chemical reagent is called qualitative analysis. Precipitation reaction is used for the confirmatory test of radicals. Which of the following iodide has scarlet red colour?
Answer» `PbI_(2)` `HgI_(2)` `AgI` All of these Answer :B

Discussion

30.	Salt bridge maintains ……………………in the solution of two half cells
Answer» ANSWER :electroneutraliy

Discussion

31.	Salt (A) on heating gives a colourless neutral gas which supports combustion. From the aforesaid, flow diagram, answer the following questions. Which of the following statement is correct?
Answer» Salt (A) gives yellow PRECIPITATE with chloroplantinic acid as well as with SODIUM cobaltinitrite. The brown RING is formed DUE to the formation of nitroso ferrous sulphate `[Fe(NO)]^(2+) SO_(4)^(-)`. Salt C reacts with silver nitrate solution to form white precipitate (a) and (b) both Solution :(A) Contains `NO_(3)^(-) (C) rarr NaNO_(3)` `(B) rarr NH_(3) (C) [Fe(H_(2)O)_(5)NO] SO_(4)` or `FeSO_(4).NO` `(A) rarr NH_(4)NO_(3)`

Discussion

32.	Salt (A) on heating gives a colourless neutral gas which supports combustion. From the aforesaid, flow diagram, answer the following questions. The compound (A) contains the following acidic radical:
Answer» `NO_(2)^(-)`<BR>`NO_(3)^(-)` `Br^(-)` `SO_(3)^(2-)` Solution :(A) Contains `NO_(3)^(-) (C) RARR NaNO_(3)` `(B) rarr NH_(3) (C) [Fe(H_(2)O)_(5)NO] SO_(4)` or `FeSO_(4).NO` `(A) rarr NH_(4)NO_(3)`

Discussion

33.	Salt (A) on heating gives a colourless neutral gas which supports combustion. From the aforesaid, flow diagram, answer the following questions. The basic radical of salt (A) and gas (B) both gives brown precipitate with Nessler's reagent. the composition of the brown precipitate is:
Answer» `(NH_(4))_(2)[HgI_(4)]` `Hg(NH_(2))NO_(3)` `HgO.Hg(NH_(2))I` `(NH_(4))_(3)[Co(NO_(2))_(6)]` SOLUTION :(A) Contains `NO_(3)^(-) (C) rarr NaNO_(3)` `(B) rarr NH_(3) (C) [FE(H_(2)O)_(5)NO] SO_(4)` or `FeSO_(4).NO` `(A) rarr NH_(4)NO_(3)`

Discussion

34.	Salol is prepared from
Answer» SALICYLIC ACID and phenol Salicylic acid and METHYL alcohol Both None Solution :

Discussion

35.	Salol is
Answer» ACETYL SALICYLIC acid Phenol benzoate Acetyl SALICYLATE PHENYL salicylate Solution :SALOL is phenyl salicylate.

Discussion

36.	Salol can be used as
Answer» Anseptic Antipyretic Both None Solution :As INTERNAL ANTISEPTIC

Discussion

37.	Saline hydrides are known to react violently with water producing fire, Can CO_(2), a well known extinguisher, be used in this case? Explain.
Answer» SOLUTION :Whenever a saline hydride `(NaH or CaH_(2))` reacts with water, the reaction is so HIGHLY exothermic that the hydrogen evolved catched fire. For example, `NaH(s)+H_(2)O(aq) to NaOH(aq)+H_(2)(g)+"heat"` `CaH_(2)(s)+2H_(2)O(aq) to Ca(OH)_(2)(aq)+2H_(2)(g)+"heat"` `CO_(2)` which is normally used as fire EXTINGUISHER cannot be used in this case beacuse it will react with the hydroxide formed in the reaction to form a carbonate. This will INCREASE the rate of the forward reaction in which heat is evolved. `2NaOH(aq)+CO_(2)(g) to Na_(2)CO_(3)(aq)+H_(2)(aq).`

Discussion

38.	Saline hydrides are known to react with water violently producing fire. Can CO_2 a well known fire extinguisher be used inthis case? Explain.
Answer» Solution :No.The FIRE produced by the action of water on SALINE hydrides cannot be put out by `CO_2`because the HOT METAL hydride reduces `CO_2` readily. `NaH+CO_2rarrHCOONa`(spadium formate)

Discussion

39.	Saline hydrides are known to react with water violently poducing fire. Can CO_(2) , a well known fire entingiusher, be used in this case? Explain .
Answer» Solution :Saline hydrides (such as NaH, `CaH_(2)`, etc.) , react with water violently to form the corresponding metal hydroides with the evolution of dihyrogen . (`NaH(s) + H_(2)O(l) to NaOH(aq) + H_(2)(g)` `CaH_(2)(s) + 2H_(2)O(l) to Ca(OH)_(2) (aq) +2H_(2)(g)` These REACTIONS are so much exothermic that the evolved `H_(2)` catches fire. The fire so produced cannot be extinguished by`CO_(2)` because it gets reduced by the HOT metal hydride to form sodiym FORMATE. `NaH+ CO_(2) to HCOONa` `However, sand is useful since it is a highly STABLE solid

Discussion

40.	Saline hydrides are known to react with water violently producing fire can CO_2, a well known fire extinguisher be used in this case ? Explain.
Answer» Solution :Saline hydrides react violently with WATER PRODUCING DIHYDROGEN gas `NaH_((s)) + H_2O_((aq)) to NaOH_((aq)) + H_(2(g))` But A well known fire extinguisher `CO_2` is used then FOLLOWING red will be obtained `NaH+CO_2 to HCOONa`

Discussion

41.	Salient features of Molecules Orbital Theory(MOT)
Answer» Solution :1. The electrons in an atom are found in atomic orbtials, the electrons, in a MOLECULE are found in molecuar orbitals. 2. The molecule orbitals are formed by the COMBINATION of atomic orbitals of comparable energies ande proper symmetry. 3. The BMOhas LOWER energyand hence GREATER STABILITY than the corresponding b ABMO. 4 The molecular orbitals are filled by electrons in accordance with Aufau principle, Pauli.s exclustion principle and the Hung.s rule.

Discussion

42.	Salicylic acid is prepared from phenol by
Answer» REIMER Teimann reaction Kolbe's reaction Kolbe-electrolysis reaction None of these Solution :REFER to A-Level INFORMATION of PHENOLS.

Discussion

43.	Salicylic acid is a stronger acid than p-hydroxybenzoic acid due to
Answer» STERIC hindracne Hygrogen bonding Mesomeric effect Solvation energy Answer :B

Discussion

44.	Salicyladehyde can be prepared from
Answer» PHENOL and CHLOROFORM phenol, chloroform and SODIUM hydroxide phenol, CARBON TETRACHLORIDE and NaOH None Solution :

Discussion

45.	Salicyaldehyde involves________hydrogen bonding .
Answer» SOLUTION :INTRAMOLECULAR

Discussion

46.	Sacchrin an artificial sweetener, is manufactured from :
Answer» CELLULOSE starch cyclohexane toluene Answer :D

Discussion

47.	Saccharin, an artificial sweetener, is manufacturered from :
Answer» cellulose toluene cyclohexane starch Answer :C

Discussion

48.	S_((8)) + 8O_(2) rarr 8SO_(2), DeltaH = -QKJ, then DeltaE
Answer» `-8` `-Q` `(-Q)/(8)` `(+Q)/8` ANSWER :C

Discussion

49.	S_(4)N_(x) in vapour state is subjected to decompoition totally to get octaatomic sulphur vapour and nitrogen gas . Under similar conditions the volume of products is 2.5 times to the reactants. Deduce the molecular formula of the nitride of sulphur. Calculate the weight percentage of nitrogen.
Answer» Solution :The decompoition is given as `UNDERSET((G))(S_(4)N_(x))to underset((g))((1)/(2))S_(8) +underset((g))((x)/(8))N_(2)` By analysing the given data , 1+x=5:x=4 MOLECULAR formula =`S_(4)N_(4)` Weight percentage of NITROGEN `(4xx14)/(4(32+14))xx10=30.43%`

Discussion

50.	S^(2-) and SO_(3)^(2-) ions can be distinguished by using
Answer» `(CH_(3)COO)_(2) Pb` `Na_(2) [Fe(CN)_(5) NO]` Both (a) & (B) None of these Solution :Distinction can be made by both `(CH_(3) C O O)_(2)Pb` and `Na_(2) [Fe(CN)_(5)NO]` `Pb(CH_(3)COO)_(2)` gives a BLACK ppt with `S^(2-)` ions (e.g., `H_(2)S`) while no precipitate is formed with `SO_(3)^(2-)` ions. `Pb(CH_(3)COO)_(2) + H_(2)S rarr PBS rarr + underset(("Black ppt"))(2CH_(3) COOH)` `Na_(2) [Fe(CN)_(5)NO]` gives a purple colouration with `S^(2-)` ions `(Na_(2)S)` while no precipitate is formed with `SO_(3)^(2-)` ions. `Na_(2) [Fe(CN)_(5) NO] + Na_(2)S rarr Na_(4) [Fe(CN)_(5)NOS]`

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Schottky defect is observed in crystal when ______

Schottky defect is observed in crystal when ………

Schottky defect generally appears in

Schotten Baumann reaction is

Schiff's base and Schiff's reagent are

Schiff's and Piria method is used for the estimation of:

Scattering of light takes place in

Saturatedsolutionof crudeNaCl overset("x ") toPureNaCl.In thereaction ,X is___

Satement 1 A solution of FeSO_(54) can be stored in a copper vessel Statement 2 2E^(@) "of" Cu "lt" E^(@) of Fe

Sate Gay Lussac's Law. Calculate the pressure exerted by 4 mole of agas occuping a volume of 1.5m^(3) at 100 K. Given R=8.314 J/k/mol.

Saponification of ethyl benzoate with caustic soda as alkalie, gives

Saponification means hydrolysis of an ester with

Saponification of an oil results in the formation of

Sample of water has hardness 77.5ppm Ca^(2+). If this is passed through an ion exchange column where Ca^(2+) is replaced by H^(+), what is the pH of water after it has been so treated

Same volume of two monoatomic gases A and B is mixed at same temperature. ........ .. Is (C_p)/( C_v) = ….......

Same reasons are given reagarding the limited use of H_(2) as fuel (I) Its calorific value is low (II) It availability in free state is less (III) It is difficult to store (IV) Its transportation is easy The correct statement are

Same mass of diamond and graphite ( bothbeing carbon) are burnt in oxygen. Will be heat produced be same or different ? Why ?

Same functional group containing different organic compounds possesses………chemical reaction

Same amount of metal combines with 0.1g of oxygen and lg of a halogen. Hence the equivalent mass of halogen is :

Samarium-62 is the member of.....

samall quantities of solutionof componds TX ,TYand TZ are put in to separate test tubes cntaining x y and z solutoin Tx does not react with any of these TY reacts oth with x and z tz rectswithx th drcasing order of ase of oxidation of the anons X^(-) Y^(-0) and Z^(-1) id

Salts given in column-I reacts with the excess of reagents given in column-II and form white/coloured precipitates. Select the correct options for the salts given in column-I with the reagent(s) given in the column-II.

Salt is a mixed form of acidic and basic radical. The confirmatory test of basic and acidic radicals by using chemical reagent is called qualitative analysis. Precipitation reaction is used for the confirmatory test of radicals. Which of the following iodide has scarlet red colour?

Salt bridge maintains ……………………in the solution of two half cells

Salt (A) on heating gives a colourless neutral gas which supports combustion. From the aforesaid, flow diagram, answer the following questions. Which of the following statement is correct?

Salt (A) on heating gives a colourless neutral gas which supports combustion. From the aforesaid, flow diagram, answer the following questions. The compound (A) contains the following acidic radical:

Salt (A) on heating gives a colourless neutral gas which supports combustion. From the aforesaid, flow diagram, answer the following questions. The basic radical of salt (A) and gas (B) both gives brown precipitate with Nessler's reagent. the composition of the brown precipitate is:

Salol is prepared from

Salol is

Salol can be used as

Saline hydrides are known to react violently with water producing fire, Can CO_(2), a well known extinguisher, be used in this case? Explain.

Saline hydrides are known to react with water violently producing fire. Can CO_2 a well known fire extinguisher be used inthis case? Explain.

Saline hydrides are known to react with water violently poducing fire. Can CO_(2) , a well known fire entingiusher, be used in this case? Explain .

Saline hydrides are known to react with water violently producing fire can CO_2, a well known fire extinguisher be used in this case ? Explain.

Salient features of Molecules Orbital Theory(MOT)

Salicylic acid is prepared from phenol by

Salicylic acid is a stronger acid than p-hydroxybenzoic acid due to

Salicyladehyde can be prepared from

Salicyaldehyde involves________hydrogen bonding .

Sacchrin an artificial sweetener, is manufactured from :

Saccharin, an artificial sweetener, is manufacturered from :

S_((8)) + 8O_(2) rarr 8SO_(2), DeltaH = -QKJ, then DeltaE

S_(4)N_(x) in vapour state is subjected to decompoition totally to get octaatomic sulphur vapour and nitrogen gas . Under similar conditions the volume of products is 2.5 times to the reactants. Deduce the molecular formula of the nitride of sulphur. Calculate the weight percentage of nitrogen.

S^(2-) and SO_(3)^(2-) ions can be distinguished by using