52671 + Interview Questions in Chemistry in Class 11

1.	The degree of dissociation of N_(2) O_(2) into NO_(2) at one atmosphere and 40^(@)C is 0.310. For this :
Answer» `K_(P)` = 0.42 atm `K_(c)` = 0.003 mole `lit^(-)` Degree of dissociation at 10 atm pressure at same temperature `alpha` = 0.1025 Degree of dissociation (`alpha`) decreases with increase pressure a given temperature Solution :`underset(underset(0.7)(1-0.3))underset(1)(N_(2)O_(4(g))) harr underset(underset(0.6)(0.6))underset(0)(2NO_(2(g)))` Total moles = 0.7 +0.6=1.3 `Kp=(P^(2)NO_(2))/(PN_(2)O_(4))=(((0.6)/(1.3))^(2))/((0.7)/(1.3))=(0.6 xx 0.6)/(1.3 xx 0.7)` `=0.4 atm implies Kp=Kc(RT)^(Delta n_((g)))`

Discussion

2.	The degree of dissociation of phosphorous pentachloride at certain temperature at 1atm is 0.2. calculate the pressure at which phosphorous pentachloride will be half dissociated at the same temperature.
Answer» SOLUTION :0.125 ATM

Discussion

3.	The degree of dissociation of HI at a particular temperature is 0*8. Calculate the volume of2 MNa_(2)S_(2)O_(3) solution required to neutralize the iodine present in the equilibrium mixture of a reaction when 2 mole each of H_(2) and I_(2) are heated in a closed vessel of 2 litre capacity.
Answer» Solution :Degreeof disociation of `HI (alpha) = 08` `{:(,2 HI,hArr,H_(2),+,I_(2)),("Before dissociation",1,,0,,0),("Moles after disso",1-alpha,,alpha//2,,alpha//2):} ` `K_(c) = ((alpha//2)(alpha//2))/(1 -alpha)^(2) = alpha^(2)/(4(1 -alpha)^(2) )=(08)/(4(1-08)^(2))= 4` Step 2. Calculation of `I_(2)`in equilibrium MIXTURE. ` {:(,H_(2),+,I_(2),hArr,2 HI),("Intial moles",2,,2,,0), ("Moles after reaction ",(2-x),,(2-x),,2x//2), ("Molar conc.",(2-x)//2,,(2-x)//2,,2x//2):}` `K'_(c)= 1/K_(c)-(2x//2)^(2)/(((2-x)/2)((2-x)/2))=(4x^(2))/(2-x)^(2)` ` :. (4x^(2))/(2-x)^(2) = 1/4 or (2x)/(2-x) =1/2 or x=2/5 ` Thus, `I_(2) "left" = 2 - 2/5 = 8/5"mole. "` Step 3. Calculation of VOLUME of hypo solution used . `2 Na _(2) S_(2) O_(3) + I_(2) to Na_(2) S_(4) O_(6) + 2 Nal ` ` :. "Moles of " N_(2)S_(2)O_(3)" reacted " = 2 xx 8/5 "mole" = 16/5 "mole " ` Volume of 2 M ` Na_(2)S_(2) O_(3) " reacted " = 1000/2 xx 16/5 = 1600 "mL " = 16 L`

Discussion

4.	The degree of dissociation of an acid HA is 9 times the degree of dissociation of acidHA_(2) of the same concentration, then the ratio of the strengths of acid HA_(1) to HA_(2) will be
Answer» SOLUTION :`("Strength of "HA_(1))/("Strength of "HA_(2))=(alpha_(1))/(alpha_(2))=(9)/(1) = 9`.

Discussion

5.	The degree of dissociation of a weak electrolyte is ...........one whereas that of a strong electrolyte is ............one.
Answer» ANSWER :LESS than, EQUAL to

Discussion

6.	The degreeof dissociation is 04 at 400 K and 10 atm for the gaseous reaction PCl_(5) hArr PCl_(3) + Cl_(2). ,brgt Assming ideal behaviour of all the gases , calculate the density of the equilibrium mixture at 400 K and 10 atmosphere . ( Atomic mass of P = 310 and Cl = 35*5)
Answer» SOLUTION :` {:(,PCl_(5),hArr,PCl_(3),+,Cl_(2)),("At equilibrium",06,,04,,04 "moles"):} ` Average molecular MASS of the mixture` ( 06(31 + 5 xx 355 ) + 04 (31 + 3 xx 355)+ 04 (2 xx 35 5 ))/( 06 + 0 4 + 04 )` ` =( 1251+ 55 + 426)/ (14)=148 92` For ideal gases ,`PV = nRT = w/M RT or PM = w/V RT= d RT ` `:.d= (PM)/(RT)= (1xx 148* 92 )/(0* 08205 xx 400 )= 4* 5374 g L^(-1) `

Discussion

7.	The degree of dissociation alpha of the reaction" N_(2)O_(4(g))hArr 2NO_(2(g)) can be related to K_(p) as:
Answer» `ALPHA=((K_(p))/(P))/(4+(K_(p))/(P))` `alpha=(K_(p))/(4+K_(p))` `alpha=[(K_(p)//P)/(4+K_p//P)]^(1//2)` `alpha=[(K_(p))/(4+K_(p))]^(1//2)` ANSWER :C

Discussion

8.	The degree of dissociation of an acid HA in 0.1 M solution is 0.1%. Its dissociation constant is
Answer» Solution :`k_a= Calpha^2` Since dissociation constant of acid, `K_a` is constant, `alpha ` depends UPON concentration. ` alpha^2 PROP (1)/(c )oralphaprop (1)/( sqrt(C )) or (alpha_2)/(alpha_1)= sqrt((c_1)/(c_2))` SUBSTITUTING the VALUES,`(alpha_2)/(0.006) = sqrt((0.1 )/( 0.05 ) )= sqrt(20)` solving thevalues`alpha_2= 0.006 xx sqrt(20 ) ` thedgreeof dissociationin 0.05Msolutionis `0.027`

Discussion

9.	The degree of dissociation alpha is equal to ……………
Answer» SOLUTION :`(i-1)/(n-1)`

Discussion

10.	The degree of association alphais equal to …………
Answer» SOLUTION :`((1-i)N)/(n-1)`

Discussion

11.	The decreasing size of K^(+),Ca^(2+),Cl^(-) & S^(2-) follows the order:
Answer» `K^(+)gtCa^(+2)gtS^(-2)GTCL^(-)` `K^(+)gtCa^(+2)gtCl^(-)gtS^(-2)` `CA^(+2)gtK^(+)gtCl^(-)gtS^(-2)` `S^(-2)gtCl^(-)gtK^(+)gtCa^(+2)` Answer :D

Discussion

12.	The decreasing order of the first ionization energy in kJmol^(-1) of He, Mg and Na is He > Mg > Na. The increasing order of second ionization energy in of these elements will be
Answer» NA LT MG lt He Mg lt Na lt He Mg lt He lt Na Na lt He lt Mg ANSWER :B

Discussion

13.	The decreasing order of stability of the carbonium ions C_(6)H_(5)CH_(2)^(+) (I), p-(CH_(3)O)C_(6)H_(4)CH_(2)^(+) (II), p-(NO_(2))C_(6)H_(4)CH_(2)^(+) (III), p-(CH_(3))C_(6)H_(4)CH_(2)^(+) (IV) is
Answer» `IV gt II gt I gt III` `II gt IV gt III gt I` `II gt IV gt I gt III` `IV gt II gt III gt I` SOLUTION :Electron-donating groups `(OCH_(3) gt CH_(3))` increases while electron-withdrawing groups `(NO_(2))` decreases the stability of substituted carbonium IONS. Thus,option (C) is correct.

Discussion

14.	The decreasing order of power of boron halides to act as Lewis acids is
Answer» `BF_(3) GT BCI_(3) gt BBr_(3)` `BBr_(3) gt BCI_(3) gt BF_(3)` `BCI_(3) gt BF_(3) gt BBr_(3)` `BCI_(3) gt BBr_(3) gt BF_(3)` ANSWER :B

Discussion

15.	The decreasing order of rates of diffusion of H_2 , N_2 , O_2, and CO_2,is
Answer» `H_2gtN_2gt CO_2gt O_2` `H_2gt N_2gt O_2gt CO_2` `CO_2gt O_2gt N_2gt H_2` `H_2 GT O_2gt N_2 gt CO_2` ANSWER :B

Discussion

16.	The decreasing order of nucleophilicity among the nucleophiles is (a) CH_(3) underset(O)underset(\|\|)(C) - O^(-) (b) CH_(3)O^(-) (c) CN^(-) (d)
Answer» a, b, c, d d, c, b, a b, c, a, d c, b, a, d Solution :

Discussion

17.	The decreasing order of electron density on the ring is :
Answer» `IIIgtIIgtI` `IIgtIIIgtI` `IgtIIIgtII` `IIIgtIgtII` ANSWER :A

Discussion

18.	The decreasing order of C-C bond length in overset(4)(C )H_(3)- overset(3)(C )H_(2)- overset(2)(C )H= overset(1)(C )H_(2) is……
Answer» `C_(4) - C_(3) GT C_(2) - C_(1) gt C_(3) - C_(2)` `C_(3) -C_(2) gt C_(2) -C_(1) gt C_(4) -C_(3)` `C_(2) -C_(1) gt C_(4) - C_(3) gt C_(3)-C_(2)` `C_(4) -C_(3) gt C_(3) -C_(2) gt C_(2)-C_(1)` SOLUTION :Inductive effect DECREASES as we MOVE away from (C= C) `:. (C_(4)-C_(3)) gt (C_(3)-C_(2)) gt (C_(2)-C_(1))`

Discussion

19.	The decreasing order of bond length among alkyl halides (CH_3I, CH_3Br, CH_3F, CH_3Cl) is in the order in the order ……………………… .
Answer» SOLUTION :`CH_3F LT CH_3Cl lt CH_3 BR lt CH_3I`

Discussion

20.	The decreasing order of bond dissociation energies of C-C,C-H and H -H bonds is
Answer» `H-Hgt-C-Hgt-C-C` `-C-C-gt-C-HgtH-H` `-C-H-gt-C-C-gtH-H-` `-C-C-gtH-Hgt-C-H` ANSWER :A

Discussion

21.	The decreasing order of bond dissociation energies of C-C, C-H and H-H bonds is
Answer» `H - H GT -C-Hgt -C-C ` `-C-C -gt -C-Hgt - H-H ` `- C-H-gt -C-C-gt -H-H` `-C-C-gt -H-H- gt -C-H` ANSWER :C

Discussion

22.	The decreasing order of bond angles in ethane, ethylene, acetylene and benzene is
Answer» `C_(2)H_(6)gtC_(2)H_(4)gtC_(2)H_(2)gtC_(6)H_(6)` `C_(2)H_(6)gtC_(2)H_(4)=C_(2)H_(2)gtC_(6)H_(6)` `C_(2)H_(2)gtC_(2)H_(4)=C_(6)H_(6)gtC_(2)H_(6)` `C_(6)H_(6)gtC_(2)H_(2)gtC_(2)H_(4)gtC_(2)H_(6)` ANSWER :C

Discussion

23.	The decreasing order of boiling points is
Answer» n-pentane `GT` iso-pentane `gt` neo-pentane iso-pentane `gt` n-pentane `gt` neo-pentane neo-pentane `gt` iso-pentane `gt` n-pentane n-pentane `gt` neo-pentane `gt` iso-pentane Answer :A

Discussion

24.	The decreasing order of boiling points among the isomeric pentanes is neo gt iso gt n.
Answer» ANSWER :F

Discussion

25.	The decreasing order of boiling point of haloalkanes CH_3Br, CH_3Cl, CH_3F, CH_3I is ……………….. .
Answer» SOLUTION :`CH_3I GT CH_3Br gt CH_3Cl gt CH_3F`

Discussion

26.	The decreasing order of basic character of K_(2)O BaO , CaO and MgO is
Answer» `K_(2)O gt BaO gt CaO gt MGO` `K_(2)O gt CaO gt BaO gt MgO` `MgO gt BaO gt CaO gt K_(2)O` `MgO gt CaO gt BaO gt K_(2)O` Solution :Alkali metal oxides are more BASIC than their corresponding alkaline EARTH metal oxides . Thus , `K_(2)O` is the most basic . Further , basic character of alkaline earth metal oxides increases down the GROUP as the electropositive character of the metal increases , i.e., `BaO gt CaO gt MgO`. Combining the two trends , basic character increases in the order : `K_(2)O gt BaO gt CaO gt MgO` , i.e., option (a) is correct .

Discussion

27.	The decreasing order of acidity among following compounds, ethanol (I), 2, 3, 2-trifluoroethanol (II), the fluoroacetic acid (III) and acetic acid (IV) is
Answer» `III gt II gt IV gt I` `IV gt III gt II gt I` `I gt II gt III gt IV` `III gt IV gt II gt I` Solution :Carboxylic ACIDS are stronger acids than alcohols and fluoroacids are stronger acids than the substituted acids and fluoro alcohols are stronger than unsubsituted alcohols. This acidity DECREASES in the ORDER trifluoro acetic acid (III), `gt` acetic acid IV `gt` trifluoro ethanol `gt` ethanol

Discussion

28.	The decreasing order of acidic character among ethane (I), ethene (II), ethyne (III) and propyne (IV) is
Answer» `(I) gt (II) gt (III) gt (IV)` `(II) gt (III) gt (I) gt (IV)` `(III) gt (IV) gt (II) gt (I)` `(IV) gt (III) gt (II) gt (I)` Solution :The correct order of decreasing acidity is `UNDERSET((III))(CH-=CH) gt underset((IV))(CH-=C-CH_(3))gt underset((II))(CH_(2)=CH_(2)) gt underset((I))(CH_(3)-CH_(3))` HYDROGEN atoms attached to SP-hybridised CARBON-atom are most acidic, followed by those attached to `sp^(2)`-hybridised carbon-atom, and those attached to `sp^(3)`-hybridised carbon are least acidic.

Discussion

29.	The decrease in number of neutrons when ._(a)^(x)U changes the ._(b)^(y)Pb is represented as :
Answer» (x-a)+(y+B) (x-a)-(y+b) (x+a)-(y-b) (x-a)-(y-b) Solution :No. of NEUTRONS in = `._(a)A^(X)U=(x - a)` No. of neutrons in `._(b)^(y)Pb = (y - b)` `THEREFORE`The CHANGE in no. of neutrons = (x - a) - (y - b)

Discussion

30.	The decomposition temperature is lowest for
Answer» `BeCO_(3)` `MgCO_(3)` `SrCO_(3)` `BaCO_(3)` Solution :`BeCO_(3)` is least stable (LOW decomposition temperature) due to SMALL size of `Be^(+2)` ION which is unstable to stablize biggest `CO_(3)^(2-)` ion.

Discussion

31.	The decomposition of solid ammonium carbamate, (NH_(4))(NH_(2)CO_(2)), to gaseous ammonia and carbon dioxide is an endothermic reaction. 9NH_(4))(NH_(2)CO_(2)))(s)hArr2NH_(3)(g)+CO_(2)(g) (a) When solid (NH_(4))(NH_(2)CO_(2)) is introduced into and evacuated flask at 25^(@)C, the total pressure of gas at equilibrium is 0.3 atm. What is the value of K_(p) "at" 25^(@)C? (b) Given that the decomposition reaction is at equilibrium. how would the following changes affect the total quatity of NH_(3) in the flask once equilibrium is re-established? (i) Adding CO_(2) (ii) Adding (NH_(4))(NH_(2)CO_(2)) (iii) Removing CO_(2) (iv) Increasing the total volume (v) Adding neon (vi) Increasing the temperature
Answer» Solution :`(NH_(4))(NH_(2)CO_(2))(S)hArr2NH_(3)(g)+CO_(2)(g)` 2P P Total pressure`=2P+P=0.3` `P=0.1`atm `K_(P)=(2P)^(2)P=4P^(3)` `=4XX10^(-3) atm^(3)`

Discussion

32.	The decomposition of KClO_3 " to"KCl and O_2on heating is an example of
Answer» Intermolecular redox change Intramolecular redox change DISPROPORTIONATION or auto redox change Comproportionation reaction SOLUTION :`2Koverset(+5-2)(2KClO_3)rarr2overset(-1)(KCL)+3overset(0)O_2 ` It is an EXAMPLE of intermolecular redox change .

Discussion

33.	The decomposition of HI in closed vessel at 731 K take place. Calculate equilibrium constant . What is the result on the base of problem 7.7 and 7.8 ?
Answer» Solution : (i) The VALUE of experiment-5, 6 is same as experiment-1, 2, 3, 4. So value of `K_c` at given temp. is constant. (ii) In experiment-5, 6 reaction is CARRIED by taking HI, So equilibrium established in any direction. (III) MOLES of `H_2` per `L^(-1)` = Moles of `I_2` per `L^(-1)`

Discussion

34.	The decay of mass during nuclear fusion and nuclear fission are respectively:
Answer» `0.1%, 0.231` `0.231%, 0.1%` `0.2%,0.4%` `0.3%, 0.6%` SOLUTION :It is a FACT.

Discussion

35.	The decay constant for an alpha- decay of Th^(232) is 1.58xx10^(-10) sec^(-1). Find out the no. of alpha- decays thatoccur form 1gsample in 365 days.
Answer» ANSWER :`1.298xx10^(19) ALPHA-` ATOM

Discussion

36.	The de-Broglie equation treats an electron to be
Answer» particle wave ray (1) and (2) ANSWER :D

Discussion

37.	The threshold wavelength for certain metal is lambda _(0). When a light of wavelength(lambda_(0))//(2)is incident on it , the mximum velocity of photelectrons is 10^(6) m//s. If the wavelength of the incident radiation is reduced to (lambda _(0) // (5), then the maximum velocity of the photoelectrons in m//s will be ,
Answer» SOLUTION :`(lambda_1)/(lambda_2) = SQRT((T_2)/(T_1))= sqrt((1200)/(300)) = 2 `

Discussion

38.	The de-Brogilc wavelength of an electron in the first Bohr orbit is
Answer» `LAMBDA =(1.23)/(sqrt(m))` `lambda = (1.23)/(sqrt(h)) m` `lambda = (1.23)/(sqrtV)` nm `lambda = (1.23)/(V)` SOLUTION :`lambda = 1/(sqrt(2xx 1.6 xx 10^(-19) vm))` `lambda = 1/(sqrt(2xx 1.6 xx 10^(-19) xx v xx 9.11 xx 10^(-31))) = (1.23)/(sqrtV) nm`

Discussion

39.	The de Broglie wavelength of a tennis ball of mass 60 g moving with a velocity of 10 metres per second is approximately
Answer» ANSWER :`1.1 XX 10^(-33)m`

Discussion

40.	The de Broglie wavelength of a ball of mass 10g moving with a velocity of 10 ms^(-1) is (h = 6.626 xx 10^(-34) Js)
Answer» `6.626 XX 10^(-33) m` `6.626 xx 10^(-29) m` `6.626 xx 10^(-31) m` `6.626 xx 10^(-36) m` ANSWER :A

Discussion

41.	The de Broglie wavelength associated with a moving particle of fixed mass is inversely proportional to
Answer» Its KINETIC energy Square ROOT of its kinetic energy Square of its kinetic energy Cube of its kinetic energy Answer :B

Discussion

42.	The de-Broglie wavelength associated with a matter particle is
Answer» Directly proportional to the MOMENTUM of the PARTICLE Directly proportional to the velocity of the particle INVERSELY proportional to the momentum of the particle Inversely proportinal to Plank's CONSTANT. Answer :C

Discussion

43.	The de Broglie wavelength associated with a ball of mass, 200g and moving at a speed of 5 metres/hour, is in the order of (h = 6.625 xx 10^(-34)Js)
Answer» ANSWER :`10^(-30)m`

Discussion

44.	The de-Broglie wavelength associated with a ball of mass 1 kg having kinetic energy 0.5 J is
Answer» `6.626 xx 10^(-34) m` `13.20 xx 10^(-34) m` `10.38 xx 10^(-21) m` `6.626 xx 10^(-34) Å` Solution :`(1)/(2) MV^(2) = 05 J` `(1)/(2) xx 1KG xx v^(2) = 0.5 J or v^(2) = 1 or v = 1 ms^(-1)` `LAMDA = (h)/(mv) = (6.626 xx 10^(-34) kg m^(2) s^(-1))/(1kg xx 1MS^(-1))` `= 6.626 xx 10^(-34) m`

Discussion

45.	The de Broglie wavelength of a particle with mass 1 g and velocity 100 m/s is
Answer» `6.63xx10^(-33)m` `6.63xx10^(-34)m` `6.63xx10^(-35)m` `6.63xx10^(-36)m` ANSWER :A

Discussion

46.	The de Broglie wave length of a riffle bullet of mass 2 grams moving with a velocity of 2m/sec of
Answer» `(6.6xx10^(-34))/(2xx2)m` `(6.6xx10^(-27))/(2xx10^(-3)xx2)CM` `(6.6xx10^(-34))/(2xx10^(-3)xx2)m` `(6.6xx10^(-27))/(2xx2)m` Answer :C

Discussion

47.	The de Broglie wave length associated with a particle of mass 1 mg moving with a velocity of 1m/sec is
Answer» `6.63xx10^(-29)m` `6.63xx10^(-31)m` `6.63xx10^(-28)m` `6.63xx10^(-22)m` Answer :C

Discussion

48.	The d-orbitals involved in sp^(3)d^(2) hybridisation are (z-axis is the internuclear axis)-
Answer» `d_(X^(2)-y^(2))` `d_(XY)` `d_(Z^(2))` `d_(YZ)` ANSWER :A::C

Discussion

49.	The d-orbital involved in the hybridization in PCl_(3) molecule is
Answer» <P>`3d_(x^(2) - y^(2))` `3d_(z^(2))` ` 3 DXY ` `4d _(x^(2) - y^(2))` Solution :In`PCl_(3)` , Hybridisation of P atom is `sp^(3) d ` . The d- orbital involved in `D_(z)^(2)` .

Discussion

50.	The cylindrical shape of an alkyne is due to the fact that it has
Answer» Three sigma C-C BONDS TWO sigma and one PI C-C BOND Three Pi C-C bonds Lindlar 'scatalyst+H SOLUTION :One sigma two pi C-C bonds.

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

The degree of dissociation of N_(2) O_(2) into NO_(2) at one atmosphere and 40^(@)C is 0.310. For this :

The degree of dissociation of phosphorous pentachloride at certain temperature at 1atm is 0.2. calculate the pressure at which phosphorous pentachloride will be half dissociated at the same temperature.

The degree of dissociation of HI at a particular temperature is 0*8. Calculate the volume of2 MNa_(2)S_(2)O_(3) solution required to neutralize the iodine present in the equilibrium mixture of a reaction when 2 mole each of H_(2) and I_(2) are heated in a closed vessel of 2 litre capacity.

The degree of dissociation of an acid HA is 9 times the degree of dissociation of acidHA_(2) of the same concentration, then the ratio of the strengths of acid HA_(1) to HA_(2) will be

The degree of dissociation of a weak electrolyte is ...........one whereas that of a strong electrolyte is ............one.

The degreeof dissociation is 0*4 at 400 K and 1*0 atm for the gaseous reaction PCl_(5) hArr PCl_(3) + Cl_(2). ,brgt Assming ideal behaviour of all the gases , calculate the density of the equilibrium mixture at 400 K and 1*0 atmosphere . ( Atomic mass of P = 31*0 and Cl = 35*5)

The degree of dissociation alpha of the reaction" N_(2)O_(4(g))hArr 2NO_(2(g)) can be related to K_(p) as:

The degree of dissociation of an acid HA in 0.1 M solution is 0.1%. Its dissociation constant is

The degree of dissociation alpha is equal to ……………

The degree of association alphais equal to …………

The decreasing size of K^(+),Ca^(2+),Cl^(-) & S^(2-) follows the order:

The decreasing order of the first ionization energy in kJmol^(-1) of He, Mg and Na is He > Mg > Na. The increasing order of second ionization energy in of these elements will be

The decreasing order of stability of the carbonium ions C_(6)H_(5)CH_(2)^(+) (I), p-(CH_(3)O)C_(6)H_(4)CH_(2)^(+) (II), p-(NO_(2))C_(6)H_(4)CH_(2)^(+) (III), p-(CH_(3))C_(6)H_(4)CH_(2)^(+) (IV) is

The decreasing order of power of boron halides to act as Lewis acids is

The decreasing order of rates of diffusion of H_2 , N_2 , O_2, and CO_2,is

The decreasing order of nucleophilicity among the nucleophiles is (a) CH_(3) underset(O)underset(||)(C) - O^(-) (b) CH_(3)O^(-) (c) CN^(-) (d)

The decreasing order of electron density on the ring is :

The decreasing order of C-C bond length in overset(4)(C )H_(3)- overset(3)(C )H_(2)- overset(2)(C )H= overset(1)(C )H_(2) is……

The decreasing order of bond length among alkyl halides (CH_3I, CH_3Br, CH_3F, CH_3Cl) is in the order in the order ……………………… .

The decreasing order of bond dissociation energies of C-C,C-H and H -H bonds is

The decreasing order of bond dissociation energies of C-C, C-H and H-H bonds is

The decreasing order of bond angles in ethane, ethylene, acetylene and benzene is

The decreasing order of boiling points is

The decreasing order of boiling points among the isomeric pentanes is neo gt iso gt n.

The decreasing order of boiling point of haloalkanes CH_3Br, CH_3Cl, CH_3F, CH_3I is ……………….. .

The decreasing order of basic character of K_(2)O BaO , CaO and MgO is

The decreasing order of acidity among following compounds, ethanol (I), 2, 3, 2-trifluoroethanol (II), the fluoroacetic acid (III) and acetic acid (IV) is

The decreasing order of acidic character among ethane (I), ethene (II), ethyne (III) and propyne (IV) is

The decrease in number of neutrons when ._(a)^(x)U changes the ._(b)^(y)Pb is represented as :

The decomposition temperature is lowest for

The decomposition of KClO_3 " to"KCl and O_2on heating is an example of

The decomposition of HI in closed vessel at 731 K take place. Calculate equilibrium constant . What is the result on the base of problem 7.7 and 7.8 ?

The decay of mass during nuclear fusion and nuclear fission are respectively:

The decay constant for an alpha- decay of Th^(232) is 1.58xx10^(-10) sec^(-1). Find out the no. of alpha- decays thatoccur form 1gsample in 365 days.

The de-Broglie equation treats an electron to be

The de-Brogilc wavelength of an electron in the first Bohr orbit is

The de Broglie wavelength of a tennis ball of mass 60 g moving with a velocity of 10 metres per second is approximately

The de Broglie wavelength of a ball of mass 10g moving with a velocity of 10 ms^(-1) is (h = 6.626 xx 10^(-34) Js)

The de Broglie wavelength associated with a moving particle of fixed mass is inversely proportional to

The de-Broglie wavelength associated with a matter particle is

The de Broglie wavelength associated with a ball of mass, 200g and moving at a speed of 5 metres/hour, is in the order of (h = 6.625 xx 10^(-34)Js)

The de-Broglie wavelength associated with a ball of mass 1 kg having kinetic energy 0.5 J is

The de Broglie wavelength of a particle with mass 1 g and velocity 100 m/s is

The de Broglie wave length of a riffle bullet of mass 2 grams moving with a velocity of 2m/sec of

The de Broglie wave length associated with a particle of mass 1 mg moving with a velocity of 1m/sec is

The d-orbitals involved in sp^(3)d^(2) hybridisation are (z-axis is the internuclear axis)-

The d-orbital involved in the hybridization in PCl_(3) molecule is

The cylindrical shape of an alkyne is due to the fact that it has

The degreeof dissociation is 04 at 400 K and 10 atm for the gaseous reaction PCl_(5) hArr PCl_(3) + Cl_(2). ,brgt Assming ideal behaviour of all the gases , calculate the density of the equilibrium mixture at 400 K and 10 atmosphere . ( Atomic mass of P = 310 and Cl = 35*5)