Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The most powerful oxidising agent among the following is:

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`H_(2)SO_(4)`
`H_(3)BO_(3)`
`HPO_(3)`
`H_(3)PO_(4)`

Solution :`H_(2)SO_(4)` is most POWERFUL OXIDISING agent
2.

The most insoluble salt of sodium is

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`Na_(4)[Fe(CN)_(6)]`
`Na_(3)[Fe(CN)_(6)]`
`Na[Sb(OH)_(6)]`
`Na[Fe(CN_(5))NO].2H_(2)O`.

Solution :One of the most insoluble SALT of sodium in WATER is `Na[Sb(OH)_(6)]` or sodium hexahydroantimonate (V). The CORRESPONDING potassium salt is more soluble in water. It is used to detect the PRESENCE of `Na^(+)` ions.
3.

The most important method of prepare lower hydrocarbon is

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Cracking
Sabatier-Senderen's reaction
Heating SALTS of FATTY ACIDS with sadalime
direct synthesis

Answer :C
4.

The most important method of preparation of hydrocarbons of lower carbon number is

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PYROLYSIS of HIGHER carbon NUMBER hydrocarbons
ELECTROLYSIS of salts of FATTY acids
'Sabatier and Senderen's reaction
Direct synthesis

Answer :A
5.

The most ideal gas among real gases is

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Hydrogen 
Helium 
Carbon DIOXIDE 
NITROGEN 

ANSWER :C
6.

The most favourable position (indicated by) for an electrophilic attack is

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SOLUTION :N//A
7.

The most fundamental Alkene which can show geometrical Isomerism (under proper substitutedconditions) contains ___Number of minimum carbon's

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2
3
4
5

Solution :`X - CH= CH-X`
8.

Themost electropositiveelementin alkalimetalsis _______.

Answer»

`NA `
`K `
`RB`
`CS `

ANSWER :D
9.

The most electropositive element is

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I
MG
Cs
Li

ANSWER :C
10.

The most electronegative element possess the electronic configuration….........

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`ns^(2)NP^(2)`
`ns^(2)np^(4)`
`ns^(2)np^(5)`
`ns^(2)np^(3)`

Answer :C
11.

The most electronegative element of the periodic table is _______

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Iodine
Flourine
Chlorine
Oxygen

Answer :B
12.

The most electronegative element.....

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oxygen
chlorine
fluorine
nitrogen

Answer :C
13.

The most electro positive element of the periodic table is __________

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Gold
Platinum
Cesium
Calcium

Answer :C
14.

The most easily hydrolysed molecule under SN_(1) condition is

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ALLYL CHLORIDE
ethyl chloride
isopropylchloride
BENZYL chloride

Solution :benzyl chloride
15.

The most easily hydrolysed molecule under S_(N^2) reaction is …………………. .

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SOLUTION :TERT. BUTYL CHLORIDE
16.

The most easily hydrolysed molecule under S_(N^1)condition is ……………………. .

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ALLYL CHLORIDE
ETHYL chloride
sopropyl chloride
BENZYL chloride

SOLUTION :benzyl chloride
17.

The most commonly used reducing agent is ……..

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`AlCl_3`
`PbCl_3`
`SnCl_4`
`SnCl_2`

SOLUTION :In `SnCl_2 , Sn^(2+)`can be EASILY oxidized to `Sn^(4+)` because +4 oxidation STATE of Sn is more stable than +2 oxidation state. Hence, `SnCl_2` ACTS as a reducing AGENT.
e.g., `SnCl_2 + 2FeCl_3 to SnCl_4 + 2FeCl_2`
`SnCl_2+ 2FeCl_3 to 2FeCl_2+ SnCl_4`
`SnCl_2 +2CuCl_2 to 2CuCl_2 + SnCl_4`
18.

Why do alkenes prefer to undergo electrophilec addition reaction while arenes prefer electrophilic substitution reactions ? Explain.

Answer»


ANSWER :T
19.

The most common oxidation state of an element is -2. The number of electrons present in its outermost shell is

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2
4
6
8

Answer :C
20.

The most common oxidation state of an element is -2 The number of electrons present in its outermost shell is

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2
4
6
8

Solution :Oxygen common O.S is –2
`O(Z= 8)1s^(2) 2S^(2)2p^(4)` . VALENCY electrons 6
21.

The most basic oxide amongst the following

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`BAO`
`MGO`
`BEO`
`CAO`

ANSWER :A
22.

The most basic one is

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ANSWER :D
23.

The most basic hydroxide is

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`LIOH`
`NAOH`
`KOH`
`CSOH`

ANSWER :D
24.

The most basic one is :

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ANSWER :D
25.

The most basic nitrogen in the following compound is

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I
II
III
IV

Answer :C
26.

The most appropriate reagent for converting pentan-2-one to butanoic acid is

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Sodium HYPOCHLORITE followed by acidic hydrolysis
`O_(2)`
`H_(2)O_(2)`
`KMnO_(4)//H_(2)SO_(4)`

Solution :`UNDERSET("Pent-2-one")(CH_(3) - overset(O)overset(||)(C) - CH_(2) CH_(2) CH_(3))overset(NaOCl)rarr CH_(3)Cl + CH_(3)CH_(3)CH_(2)COONa overset(H_(2)O // H^(+))rarr underset("BUTANOIC acid")(CH_(3)CH_(2)CH_(2)COOH)`
27.

The most adsorbed gas on activated charcoal is

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`N_(2)`
`H_(2)`
`CO_(2)`
`CH_(4)`

Solution :More EASILY liquefiable gas (i.e., higher the CRITICAL temperature) more is the ADSORPTION.
28.

The most acidic hydrogen atoms are present in

Answer»

Ethane
ethene
ethyne
benzene

Answer :C
29.

The most abundant metal on the surface of the earth is

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Fe
AL
Ca
Hg

Solution :Al is the most ABUNDANT METAL on the SURFACE of the EARTH.
30.

The most abundant hydrocarbon pollutant is

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Ethane
Methane
Propane
Butane

ANSWER :B
31.

The most abundant elements by mass in the body of a healthy human adult are : Oxygen (61.4 %): Carbon (22.9 %): Hydrogen (10.0 %) and Nitrogen (2.6 %). The weight which a 75 g person would gain if all ""^(1)H atoms are replaced by ""^(2)H atoms is .....

Answer»

15 KG
37.5 kg
7.5 kg
10 kg

Solution :Weight will be DOUBLE, if all the hydrogen is REPLACED by` ""^(2)H`. 7.5 kg will increase because person having 75 kg weight has 10% hydrogen .
32.

The most abund ant element in the universe is __________

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SOLUTION :HYDROGEN
33.

The most abundant element among the following is

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`MG`
`Ca`
`SR`
`RA`

Answer :B
34.

The most abundant and least abundant isotopes of hydrogen respectivley are

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<P>P,T
P,D
D,P
T,P

Answer :1
35.

The most abundant amounts by mass in the body of a healthy human adult are oxygen (61.4%), carbon (22.96%) hydrogen (10.0%) and nitrogen (2.6%). The weight which a 75 kg person would gain if all ""^(1)Hatoms are replaced by ""^(2)Hatoms is

Answer»

15 KG
37.5 kg
7.5 kg
10 kg

ANSWER :C
36.

The more positive the value of E^(@) the greater is the tendency of the species to get reduced using the standard electrode potential of redox couples given below find out which of the following is the strongest oxidising agent E^(@) "values" : (F^(3+))/(Fe^(2+))=+0.77, I_(2)(s)//I^(-)=+0.54,(Cu^(2+))/(Cu^(2+))=+0.34, (Ag^(+))/(Ag(s))=+0.80,Cu^(2+)//Cu(s)=+0.34 (I_(s))/(I)^(-)=+0.54

Answer»

Solution :SINCE `E^(@)` of the redox couple `Ag^(+)//Ag` is the most positive i.e 0.80 V therefore `Ag^(+)` is the STRONGEST OXIDISING agent
37.

The more positive the value ofE^(Ө), the the greater is the tendency of the species to get reduced. Using the standard electrode potential of redox couples given below find out which of the following is the strongest oxidising agent ? E_(Fe^(+3)//Fe^(+2))^(Ө)=+0.77"volt",E_(I^(2)//I^(-))^(Ө)=+0.54"volt" E_(Cu^(+2)//Cu)^(Ө)=+0.34"volt",E_(Ag^(+)//Ag)^(Ө)=+0.80"volt"

Answer»

`FE^(+3)`
`I_(2(s))`
`Cu^(+2)`
`Ag^(+)`

Solution :Since, `E^(@)` of he redox COUPLE `Ag^(+)//Ag` is the most positive, i.e., +0.80 V, THEREFORE, `Ag^(+)` is strongest oxidising agnet.
38.

The most abundant alkali metal in the earth's crust is

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Lithium
Sodium
Caesium
Potassium

Answer :B
39.

The more viscous liquid is

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`H_2O`
`H_2O_2`
`D_2O`
`C_2H_5OH`

ANSWER :B
40.

The more basic oxide is

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`CAO`
`MGO
`K_2O`
`Na_2O`

ANSWER :C
41.

The monomers used in the manufacture of nylon-6,6 are

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sebacic ACID and hexamethylene DIAMINE
ADIPIC acid and butadiene
seback acid and butadiene
seback acid and butadiene

ANSWER :D
42.

The momentum of a particle of wave length 1 Å is

Answer»


ANSWER :`6.6 XX 10^(-19)g.cms^(-1)`
43.

The molecules that can exhibit tautomerism are

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I, IV
II , III
III, IV
I,II

Answer :C
44.

The molecules that will have dipole moment

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2,2-dimethylpropane
trans-2-pentene
cis-3-hexene
2,2,3,3-tetramethylbutane

ANSWER :C::D
45.

The molecules of PCl_(5) in the solied state is ………..in nature consisting of tetrahedral…………cation and octahedral……………anion.

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ANSWER :IONIC, `PCl_(4)^(+),PCl_(6)^(-)`
46.

The molecules or ions in which the central atom has only bond pairs of electrons are

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`NH_(4)^(+)`
`NO_(3)^(-)`
`SnCI_(2)`
`SF_(4)`

ANSWER :A::B
47.

The molecules having same hybridisation, shape and number of lone pairs of electrons are. . . . . . . . .

Answer»

`SeF_(4),XeO_(2)F_(2)`
`Se_(4),XeF_(2)`
`XeOF_(4),TeF_(4)`
`SeCl_(4),XeF_(4)`

Solution :`SeF_(4),XeO_(2)F_(2)-sp^(3)d` HYBRIDISATION T- SHAPED, one lone pair on CENTRAL atom.
48.

The molecules having same hybridisation , shape and number of lone pairs of electons are

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`SeF_(4), XeO_(2) F_(2)`
`SF_(4), XeF_(2)`
`XeOF_(4), TeF_(4)`
`SeCl_(4),XeF_(4)`

Solution :The molecules `SeF_(4), XeO_(2) F_(2)` has `sp^(3)d` hybridisation, one pair of LONE pair electrons and see-saw shape.
49.

The molecules having dipole moment are _______

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2,2-Dimethylpropane
trans-Pent-2-ene
cis-Hex-3-ene
2,2,3,3-Tetramethylbutane

Solution :
Since the +I-effect of `CH_3CH_2` group is higher than that of `CH_3` group, therefore , the dipole moments of `C-CH_3` and `C-CH_2CH_3` BONDS are unequal . Although these two dipoles oppose each other, YET they do not exactly cancel out each other and HENCE trans-2-pentene has small but finite dipole moment.In cis-hex-3-ene , although the dipole moment of the two `C-CH_2CH_3` bonds are equal , they are inclined to each other at angle of `60^@` and hence have a finite resultant.
Further, 2,2-dimethylpropane and 2,2,3,3-tetramethylbutane have zero dipole moments because of the following two reasons :
(i)C-C and C-H bonds in alkanes are almost non-polar and have no FIXED orientations in SPACE , therefore, their resultant dipole moment, if any , are almost negligible .
(ii)Both these are symmetricalmolecules and hence their dipole moments is zero.
50.

The molecules having dipole moment are …….

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2,2-Dimethylpropane
trans-pent-2-ene
cis-hex-3-ene
2,2,3,3-Tetramethylbutane

SOLUTION :Trans-pent-2-ene shows NET dipole moment because of different group attached and cis-Hex-3-ene shows dipole moment because both `C_(2)H_(5)` groups are INCLINED to each other at an angle of `60^(@)` so, has resultant dipole moment.