Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The value of ebulliosepic constant depends upon

Answer»

` Delta H_("SOLUTION ") `
NATURE of SOLVENT
nature of solute
FREEZING point of solution

Answer :B
Discussion
2.

Write structures and IUPAC names of different structural isomers of alkenes corresponding to C_(5)H_(10)

Answer»

SOLUTION :Structural isomers of `C_(5)H_(10)` molecular formula is as follows :
(a) `underset("Pent-1-ene")(CH_(2)-CH-CH_(2)-CH_(2)=CH_(2))`
(B) `underset("Pent-2-ene")(CH_(3)-CH=CH-CH_(2)-CH_(3))`
(c) `underset("2-Methylbut-2-ene")(CH_(3)-underset(CH_(3))underset(|)(C)=CH-CH_(3))`
(d) `underset("3-Methylbut-1-ene")(CH_(3)-underset(CH_(3))underset(|)(CH)=CH-CH_(2))`
(e) `underset("2-Methylbut-1-ene")(CH_(2)-underset(CH_(3))underset(|)(C)=CH_(2)-CH_(3))`
From the FOLLOWING (a) and (b) are position isomers of each other and (c), (d) , (e) are chain isomers of (a), (b).
Discussion
3.

Which of the following carbocations is expected to be most stable ?

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ANSWER :C
Discussion
4.

The value ofK_(p) " is " 1 xx10^(-3) " atm"^(-1) " at " 25^(@) C. " for the reaction " : 2 NO + Cl_(2)hArr2 NOCl.A flask contains NO at 0*02 "atm at " 25^(@)(C).Calculate the mol of Cl_(2)that must be added if 1 % of the NO is to be converted to NOCl at equilibrium. The volume of the flask is such that0*2mol of the gas produce 1 atm pressure at25^(@)C.( Ignore the probable association of NO toN_(2)O_(2))

Answer»

<P>

Solution :Suppose intial pressure of `Cl_(2)`added is p atm .
`{:("Then ",2NO,+,Cl_(2),hArr,2 NOCl),("Intial",0*02 "atm",,p " atm",,),("A eqm. " ,0*02 - (0*02)/100,,(p-(0*01)/100),,(0*02)/100),(,=2 xx 10^(-2)-2 xx10^(-4),,=p-10^(-4),,-2 xx 10^(-4)"atm"),(,=2 xx 10^(-4)(100-1),,,,),(,=198 xx10^(-4) "atm",,,,):}`
` K_(p) = (p_(NOCl)^(2))/(p_(NO)^(2)xx p_(Cl_(2)) )`
` 10^(-3) = ( 2xx 10^(-4))^(2)/ ((198 xx10^(-4))^(2)xx(p-10^(-4))) `
or ` (p- 10^(-4)) = 4/(198)^(2) xx 1/ (10^(-3))= 0* 102 orp= 0* 102 + 0* 0001 = 0*1021 "atm "`
Volume of the vessel can be calculated as follows :
` PV = NRT or V = (nRT)/P = (0* 2 xx 0* 082 xx 273 )/1 L = 4* 887 L `
To calculate the number of MOLES of `Cl_(2)`, again apply
` PV = nRT or n = (PV)/ (RT) = (0*1021 xx 4* 887 )/(0*082 xx 298) = 0* 204 "mol"`
Discussion
5.

The shape of molecular orbital depends upon

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SIZE of the molecule
Size of the atoms INVOLVED
SHAPE of the ATOMIC orbital
All the above

ANSWER :C
Discussion
6.

The zeolite used to convert alcohols directly into gasoline is

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ZSM -5
`Zn_(2)(SiO_(4))`
`LiAl(SiO_(3))`
`Be_(3)Al_(2)[Si_(6)O_(18)]`

SOLUTION :ZSM-5 CONVERT alcohols into gasoline
Discussion
7.

The reagent which will be suitable to distinguish 1-methoxy-3-methyl-2-butene from isomeric 4-methyl-3-pentene -1-ol is

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BROMINE in chloroform
alkaline POTASSIUM permanganate
ammoniacal silver nitrate
sodium metal suspended in HEXANE

ANSWER :D
Discussion
8.

Which of the following decreases the dissolved oxygen in water

Answer»

ORGANIC matter
Flourides
Carbonates
METHYL Mercury

Answer :A
Discussion
9.

To prepare 3-Ethylpentane-3-ol, the reagents needed are

Answer»

`CH_(3)CH_(2)MgBr+CH_(3)COCH_(2)CH_(3)`
`CH_(3)MgBr+CH_(3)CH_(2)CH_(2)COCH_(2)CH_(3)`
`CH_(3)CH_(2)MgBr+CH_(3)CH_(2)COCH_(2)CH_(3)`
`CH_(3)CH_(2)CH_(2)MgBr+CH_(2)COCH_(2)CH_(3)`

SOLUTION :
Discussion
10.

Which of the following expression correctly represents the relationship between the average kinetic energy of CO and N_(2) molecules at the same temperature?

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`vecE(CO)gtvecE(N_(3))`
`vecE(CO)ltvecE(N_(2))`
`vecE(CO)=vec(E)N_(2)`
Cannot be PREDICTED unless volumes of the gases are given

ANSWER :c
Discussion
11.

What will be the values of psi_(2_(p_(x))),phi_(2_(p_(y))) and phi_(2_(p_(z))) when the value of r=0?

Answer»

SOLUTION :When r=0, the value of `phi_(2_(px)),phi_(2_(py)) and phi_(2_(pz))` is ZERO (0).
Discussion
12.

The wavelength of a certain line in Balmer Series is observed to be 4329 Å. To what value of .n. does this correspond ? (R_(H) = 109678cm^(-1)) (Z=1)

Answer»


Solution :`1/(lambda) = R_H Z^2 [1/(n_1^2) - 1/(n_2^2)]`
`implies1/(4329xx10^(-8)) = 1.09678 XX 10^5 [1/4 - 1/(n_2^2)]`
`THEREFORE n_2 = 5`
Discussion
13.

Which of the following is a nonaromatic.

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SOLUTION :
Discussion
14.

The stability of alkyl free radicals is due to

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HYPERCONJUGATION
`+I` EFFECT
`-I` effect
Both a &B

SOLUTION :N/A
Discussion
15.

Which type of reactions are easily performed by alkane and alkene ?

Answer»

SOLUTION :Free radical SUBSTITUTION REACTION and ELECTROPHILIC ADDITION reactions respectively.
Discussion
16.

What is the normality of 250 mL aqueous solution of H_(2)SO_(4) having pH=0.00.

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0.50 M
0.25 N
2 N
1 N

Answer :A::D
Discussion
17.

Which of the following can give nucleophilic addition on alkyne

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`Cl_(2)`
`HBr`
`HCl`
`H_(2)O //HgSO_(4)//H_(2)SO_(4)`

Answer :D
Discussion
18.

What amount of ice (in g) will remain when 52 g ice is added to 100 g of water at 40^(@)C? Specific hate of water is 1 cal//g and latent heat of fusion of ice is 80 cal//g Round off your answer to next interger.

Answer»


ANSWER :19
Discussion
19.

What is the wave length of H_(b) line Balmer series of hydrogen spectrum ? (R = Rydberg constant)

Answer»

36/5R
5R/36
3R/16
16/3R

Answer :D
Discussion
20.

What is the best description of the change that occurs when Na_(2)O,(s) is dissolved in water?

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Oxidation number of OXYGEN increase
Oxidation number of SODIUM decreases
OXIDE accepts SHARING in a pair of electrons
Oxide ion donates a pair of electrons

Solution :
Discussion
21.

Which of the following is an amorphous solid ?

Answer»

Graphite (C )
Quartz GLASS (`SiO_2`)
CHROME alum
Silicon carbide (SiC)

ANSWER :B
Discussion
22.

Which of the following has maximum % of s-character-

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`N_(2)H_(2)`
`N_(2)H_(4)`
`NH_(3)`
`NH_(2)^(-)`

SOLUTION :.
Discussion
23.

Which of the following metal is not in liquid state?

Answer»

GALLIUM
Aluminium
Mercury
Caesium

Answer :B
Discussion
24.

What do you mean by critical volume (Vc)? Give the unit of coefficient of viscosity.

Answer»

SOLUTION :The VOLUME of 1 MOLE of GAS at critical temperature is called critical volume. Poise or 1 g `cm^(-1)s^(-1)`
Discussion
25.

Wrong statement regarding 'London smog' is

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Observed in WINTER season
It is reducing in nature
It is due to Carbon PARTICLES, `SO_2`
It observed when solar radiation is high

Answer :D
Discussion
26.

When alcohol reacts with concentrated H_(2)SO_(4) intermediate compound formed is

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CARBONIUM ion
alkoxy ion
alkyl HYDROGEN sulphate
none of these

Solution :
Discussion
27.

Which is soluble in water

Answer»

SODIUM PALMITATE
Sodium oleate
Magnesium palmitate
POTASSIUM stearate

Answer :B
Discussion
28.

Which of the following property of water can be used to explain the sperical shape of rain droplets ?

Answer»

Viscosity
SURFACE TENSION
Criticasl phenomena
Pressure

Solution :The spherical shape of rain DROPLETS is due to surface tension. Lowest energy state of a liquid will be when the surface AREA is minimum. Surface tension tries to LOWER the surface area of a liquid to the minimum. Shape of a rain droplets is spherical because for a given volume, a sphere has minimum surface area.
Discussion
29.

What isthe atomic number of element whose outer most electrons are represented by 3s^1

Answer»

Solution :COMPLETE ELECTRONIC configuration is `1S^(2)2s^(2)2p^(6)3^(1)therefore`Atomic NUMBER of the element = 11
Discussion
30.

Which one of the following has the lowest melting point

Answer»

B
Al
Ga
Tl

Answer :C
Discussion
31.

Which of the following isomer of butanol has a chiral structure?

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`(CH_(3))_(3)COOH`
`(CH_(3))_(2)CH.CH_(2)OH`
`CH_(3)CH(OH)CH_(2)CH_(3)`
`CH_(3)(CH_(2))_(3)OH`

SOLUTION :2-Butanol has chiral STRUCTURE and is ISOMER of 1-butanol.
`CH_(3)-underset("2-Butanol")underset(H)underset(|)overset(OH)overset(|**)(C)-CH_(2)-CH_(3)`
Discussion
32.

Which of the following atoms and ions are isoelectronic i.e. have the same numbe of electrons with the neon atom

Answer»

`F^-`
oxygen ATOM
mg
`N^-`

Solution :`F^-` have the same number of ELECTRONS with the neon atom
Discussion
33.

When pressure is increased upon a gas at constant temperature

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the R.M.S. velocity DECREASES 
the R.M.S. velocity increases 
the R.M.S. velocity remains the same
the AVERAGE KINETIC ENERGY of the molecules increases 

Solution :constant T = no change .
Discussion
34.

When Na_2CO_3 . 10 H_2O is kept open in air, it(a)absorbs moisture(b)loses water to form anhydrous salt(c) loses water to form a monohydrate(d) decomposes to give CO_2 and Na_2O.

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ABSORBS moisture
loses WATER to form anhydrous salt
loses water to form a monohydrate
DECOMPOSES to GIVE `CO_2 and Na_2O`.

Solution : loses water to form a monohydrate
Discussion
35.

Which of the following are correct statements ?

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Van der WAAL constant a is a MEASURE of attractive force 
Van der Waal constant b is also CALLED co-volume or EXCLUDED volume 
b is EXPRESSED in `L mol^(-1)` 
all of the above 

Answer :D
Discussion
36.

Which one of the following has highestdipole moment ?

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`NH_(3)`
`PH_(3)`
`SbH_(3)`
`AsH_(3)`

Solution : N- Hbond is most polar
Discussion
37.

What is the minimum number of carbon atoms of an alkane must have to form an isomer?

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4
3
2
1

Answer :A
Discussion
38.

Which of the following have the highest value of electronegativity?

Answer»

Halogens
ALKALI metals
ALKALINE EARTH metals
Transition metals

SOLUTION :Halogens
Discussion
39.

Which of the following will not give a white pt. when AgNO_(3) is added to its solution?

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`C Cl_(4)`
`NaCl`
`MgCl_(2)`
KCl

Solution :`C Cl_(4)` being covalent will not furnish chloride ions which on reaction with `AG^(+)` FORM a white PPT.
Discussion
40.

What is the amount of work done when two moles of an ideal gas is comoressed from a volume of 1 m^(3) to 10 dm^(3) at 300 K against a pressure of 100 kPa?

Answer»

99 KJ
`-99` kJ
`114.9` kJ
`-114.9` kJ

Solution :`w = p_(ext)(V_(2)-V_(1))`
`p_(ext = 100 KP = 10^(5)Pa`
`therefore w = 10^(5)Pa(1 - 0.001)m^(3)`
` = 10^(5) xx 99.9 xx 10^(-2) Pam^(3)`
` = 99.9 xx 10^(3)J (because Pa m^(3) = J)`
= 99.9 kJ
Discussion
41.

Which is the equation showing the relation between K_p and K_c ?

Answer»

`K_p=K_c(RT)^(DELTAN)`
`K_p=K_c R^n`
`K_p=K_c(PT)^(Deltan)`
`K_p=K_c(RT)^(-Deltan)`

ANSWER :A
Discussion
42.

Volume of a molecule is related to Vander Waal's constant 'b' and Avagadro Number 'N_(0)' by the equation :

Answer»

`V = b/(N_0)`
`V = 4bN_0`
`V = (4B)/(N_0)`
`V = b/(4N_0)`

SOLUTION :`4N_0 V_("MOLECULE") = b IMPLIES V = b/(4N_0)`
Discussion
43.

What would bethe IUPACname andsymbol for theelementwithatomicnumber120 ?

Answer»

SOLUTION :Fromtable3.6gage `3//12` the rootsfor 1,2and o are un , BI and NIL respectively.
`:. ` the IUPAC name of theelement =un + bi + nil + ium = UNBINILIUM and symbolof the element = ubn.
Discussion
44.

What happen when calcium oixde is treated with carbondioxide?

Answer»

SOLUTION :Calcium oixde on TREATING with `CO_(2)` give calcium CARBONATE.
`CAO + CO_(2) to CaCO_(3)`
Discussion
45.

The wavelength of the electron emitted, when in a hydrogen atom, electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097 xx 10^(7) m^(-1))

Answer»

91 nm
192 nm
406 nm
`9.1 xx 10^(-8) nm`

SOLUTION :`bar(v) = (1)/(lamda) = R ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
`= 1.097 xx 10^(7) m^(-1) ((1)/(1^(2)) - (1)/(OO^(2)))`
`= 1.097 xx 10^(7) m^(-1)`
or `lamda = (1)/(1.097 xx 10^(7)) m = 0.91 xx 10^(-7) m = 91 nm`
Discussion
46.

Which of the following is named as perhydrol and used as an antiseptic?

Answer»

`D_(2)O`
`H_(2)O_(2)`
NAH
`B_(2)H_(6)`

Answer :b
Discussion
47.

Write the equilibrium expression and equilibrium constant for the given reverse reaction.

Answer»

Solution :`N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g),K=0*50` at 6734
`K_(c)=([N_(2)][H_(2)]^(3))/([NH_(3)]^(2))`. For the reverse reaction, `K_(c)=0.50rArrK_(E)'=1/K_(e)=1/0.50=2`.
Discussion
48.

Write the general electronic configuration of group 14 elements.

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SOLUTION :[Rare GAS ] `NS^(2) np^(2)`
Discussion
49.

What volume of 5M Na_2SO_4 must be addedto 25 mL of 1M BaCl_2 to produce 10 g of BaSO_4 ?

Answer»

8.58 mL
7.2 mL
10 mL
12 mL

Solution :`Na_2SO_4+BaCl_2 to BaSO_4 + 2NaCl`
No. MOLES of `BaSO_4=w/M=10/233=0.0429`
`THEREFORE " No. of moles of " Na_2SO_4 " NEEDED " = (MxxV)/(1000)`
or `0.0429=(5xxV)/(1000) RARR V=8.58mL`
Discussion
50.

What volume of hydrogen at N.T.P would be liberated by the action of 50 mL of dilute H_(2)SO_(4) of 40 % purity and having a specific gravity of 1.3 g mL^(-1) on 65 g of zinc ? (Atomic mass of Zn = 65) ?

Answer»


Solution :Mass of 50 mL of dilute `H_(2)SO_(4)` = VOLUME `XX` density
`=(50 mL )xx ("1.3 g mL"^(-1))=65g`
Mass of pure `H_(2)SO_(4)` in the sample `= ((65g)xx40)/(100)=26g`
The balanced chemical equation is :
`Zn+underset(underset(98g)("1 mol"))(H_(2)SO_(4))rarrZnSO_(4)+underset(underset(22.4L)("1 mol"))(H_(2))`
98 g of `H_(2)SO_(4)` EVOLVE `H_(2)` at N.T.P = 22.4 L
26 g `H_(2)SO_(4)` evolve `H_(2)` at N.T.P `= ((22.4L))/((98.0g))xx(26.0g)=5.94L`.
Discussion