Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Which of the following diagrams correctly describes behaviour of a fixed mass of an ideal gas? (T is measured in K)

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ANSWER :C
Discussion
2.

What do you understand by the term 'auto protolysis of water'? What is the significance?

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SOLUTION :For ANSWER, CONSULT Q.18
Discussion
3.

Which of the following tests can be applied to distinguish 1^(@), 2^(@) and 3^(@) alcohols?

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OXIDATION test
Lucas test
Victor MEYER's test
All the above

Answer :D
Discussion
4.

Which of the following is not an ideal solution ?

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Benzene & toluene
n-Hexane & n-Heptane
ETHYLIODIDE & ethyl bromide
ETHANOL and water

Answer :D
Discussion
5.

Which structural factor favours the formation of stable hydratesfromaldehydes ande ketones?

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The presence of ELECTRON- WITHDRAWING groups on the ALKYL carbons
The presence of basic substituents on the alkyl carbons
The presence of electron- donating groups on the alkyl carbons
The presence of acidic substituencts on the alkyl carbons

Answer :1
Discussion
6.

Which of the following is the least stable ?

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`CH_(3)-CH_(2)-OVERSET(+)(C)H_(2)`
`CH_(3)-overset(+)(C)H-CH_(2)-CH_(3)`
`CH_(3)-underset(underset(CH_(3))(|))overset(+)(C)-CH_(3)`
`CH_(3)-underset(underset(CH_(3))(|))overset(overset(CH_(3))(|))(C)-overset(+)(C)H-CH_(3)`

Solution :Stability a Hyperconjugation `alpha` no. of a hydrogen
Discussion
7.

Which of the following is least likely to behave as Lewis acid ?

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`OH^(-)`
`H_(2)O`
`NH_(3)`
`BF_(3)`

Solution :`BF_(3)` is ELECTRON deficient and HENCE behaves as Lewis acid.
Discussion
8.

Which colour is produced when alkali metals dissolved in liquid ammonia?

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Red
Green
Blue
Violet

Answer :C
Discussion
9.

Which of the following conditions show the polluted environment.

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PH of rain WATER is 5.6
amount of carbon dioxide in the atmosphere is 0.03%
biochemical oxygen DEMAND is 10 ppm
eutrophication

Solution :Biochemical oxygen demand greater than 5 ppm shows water is polluted. Eutrophication, i.e. FLOW of phosphatic fertilizers waste into lakes, resulting into the death of fish is pollution of water
Discussion
10.

Which order are correct?

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Themal stability: `BeSO_(4) lt MgSO_(4) lt CaSO_(4) ltSrSO_(4) lt BaSO_(4 )`
Basic nature : `ZnO GT BeO gt MGO gt CaO `
Solubility in water : `LIOH gt NAOH gt KOH gt RbOH gt CsOH `
Melting point :` NaCl gt KCI gt RbCI gt CSCI gt LiCI `

Answer :A::D
Discussion
11.

Which of the following hydrides of group 16 elements has the highest boiling point ?

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`H_(2)O`
`H_(2)S`
`H_(2)SE`
`H_(2)TE`

ANSWER :A
Discussion
12.

Which element has ns^(2)np^(5)type electronic configuration in its outermost shell

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CARBON
CHLORINE
NEON
Aluminium

Solution :The `ns^(2)np^(5)` electronic configuration is of the halogens. (B) Chlorine is a halogen
Discussion
13.

Which of the following is the correct IUPAC name?

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3-Ethyl-4,4-dimethylheptane
4,4-Dimethyl-3-ethylheptane
5-Ethyl-4,4-dimethylheptane
4,4-Bis(METHYL)-3-ethylheptane

Answer :A
Discussion
14.

Which of the following compounds is aromatic?

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SOLUTION :This is an aromatic compound which is CYCLIC, totally conjugated and has 4n+ 2 ? electrons where N = 2
Discussion
15.

Which of the following is not present in portland cement?

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`Ca_(3)Al_(2)O_(6)`
`Ca_(3)SiO_(5)`
`Ca_(2)SiO_(4)`
`Ca_(3)(PO_(4))_(2)`

Solution :Phosphate is not a part off COMPOSITION of PORTLAND CEMENT.
Discussion
16.

Which of the following does not exhibit hydrogen bonding in liquid phase

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Phenol
liq. `NH_3`
water
liq. `HCL`

SOLUTION :Due to LARGE SIZE of Cl, is cannot involve in H- bonding.
Discussion
17.

Which of the following is not the effect of ozone bole.

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AGEING of skin
Killing MANY phyto planktons
Increasing the MOISTURE CONTENT of the soil
Cataracts acrolein

Answer :B
Discussion
18.

What do you understand by linear combination of atomic orbitals in MO theory .

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SOLUTION :Linear combination of atomic orbitals :
The WAVE functions for the molecular orbitals can be obtained by solving Schrodinger wave equation for the molecule. Since solving the Schrodinger equation is too complex , APPROXIMATION methods are used to obtain the wave function for molecular orbitals. The most common method is the linear combination of atomic orbitals (LCAO) .
The atomicorbitals are represented by the wave function `Psi`. Let US consider two atomic orbitals represented by the wave function `Psi_(A)" and " Psi_(B)` with comparable energy, combines to form two molecular orbitals. One is bondingmolecular ORBITAL `(Psi_("bonding") )` and the other is antibonding molecular orbital `(Psi_("antibonding"))` . The wave functions for these two molecular orbitals can be obtained by the linear combination of the atomic orbitals `Psi_(A)" and "Psi_(B)` as below.
`Psi_("bonding") = Psi_(A) + Psi_(B) `
`Psi_("antibonding") = Psi_(A) - Psi_(B) `
The formation of bonding molecular orbital can be considered as the result of constructive interference of the atomic orbitals and the formation of antibonding molecular orbital can be the result of the destructive interference of the atomic orbitals. The formation of the two molecular orbitals from two1s orbitals is shown below.
Constructive interaction : The two 1s orbitals are in phase and have the same sign.

Discussion
19.

Which of the following strategy is not a correct approach to reduce global warming

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Reducing the green house has EMISSION by limiting the use of fossil fules.
Increase the vegetation cover PARTICULARLY the forest for photosynthetic utilization of `CO_2`
Minimizing the use of nitrogen fertilizers in agriculture for reducing `N_2 O` emission.
INCREASING the use of air conditioners, refrigeration unit and production of plastic FOAMS and PROPELLANTS in aerosal spray cans.

Solution :Increasing the use of air conditioners, refrigeration unit and production of plastic foams and propellants in aerosal spray cans.
Discussion
20.

Which of the following lattices has the highest packing efficiency ? (i) simple cubic (ii) body-centred cubic (iii) hexagonal close-packed lattice.

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SOLUTION :Packing EFFICIENCIES are : Simple cubic= 52.4%, Body-centred cubic=68%, Hexagonal close-packed = 74%. Thus, hexagonal close-packed LATTICE has the highest packing EFFICIENCY
Discussion
21.

When BiCl_3is dissolved in excess of D_2O,the product formed is

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`Bi(OD)_3`
`BIOCL`
`Bi(OD)_2`
`BiD_3`

Answer :B
Discussion
22.

Which one of the following has the smalJes, heat of hydrogenation per mole of the compound ?

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1-Butene
trans-2-Butene
cis-2-Butene
1,3-Butacliene

SOLUTION :More the stability of the ring LESSER is heat of HYDROGENATION
Discussion
23.

Which of the following does not contains -COOH groups ?

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Aspirin
Benzoic acid
Picric acid
all have `-COOH` group

Solution :
Discussion
24.

Which of the following is relatively stronger acid? K, values are given in brackets

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`HA (2xx10 ^(-4) ) `
` HB (3xx10 ^(-5))`
` HC ( 1.8 xx10^(-3))`
` HD (9.6xx10^(-10))`

SOLUTION :Strengthof acid `alpha , K_a`
Discussion
25.

The single plant nutrient mainly responsible for eutrophication is ________.

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ANSWER :A
Discussion
26.

Which of the two structures A and B given below is more stabilised by resonance? Explain . {:( CH_(3) COOH ," and ", CH_(3) COO), (A,"" ,B):}

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Solution :Resonating structures of A and B are as follows

` square ` II is more stable than structure I. because later carriesseparation of positive and NEGATIVE charges .
`square ` The contribution of structure II is LESS than that of I .
` square ` On the contrary , structure III and IV are of equal energy and HENCE contribute equally towards the RESONANCE hybrid of compound B .
` squaretherefore ` Structure (B) is more stable than (A) .
Discussion
27.

Two reactionshaving their energy of activation E_(1) and E_(2) temperature coefficients T_(c_(1)) and T_(c_(2)) respectively within the temperature 300 and 310K. The ratio of their temperature coefficient is:

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`e^(E_(1)//E_(2))`
`e^((E_(1)-E_(2))xx10^(-4)//R)`
`10^(E_(1)//E_(2))`
`e^((E_(1) - E_(2))//4)`

SOLUTION :`2.303 logt_(C_(1)) = (E_(1))/(R) [(T_(2) - T_(1))/(T_(1) T_(2))]`
`2.303 log T_(c_(2)) = (E_(2))/(R) [(T_(2) - T_(1))/(T_(1) T_(2))]`
`2.303 [log T_(C_(1)) - log T_(C_(2))]`
`= ((E_(1) - E_(2)))/(R) xx [(310 - 300)/(300xx310)]`
`:. 2.303 log ((T_(C_(1)))/(T_(C_(2)))) = [(E_(1) - E_(2))/(R)] xx 1.07xx10^(-4)`
or In `(T_(c_(1)))/(T_(C_(2))) = [(E_(1) - E_(2))/R] xx 10^(-4)`
`:. (T_(c_(1)))/(T_(c_(2))) = e^([(E_(1) - E_(2))/(R)]xx10^(-4))`
Discussion
28.

When an ideal gas expands in vaccum, there is neither absorption nor evolution of work ? Why ?

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<P>

SOLUTION :It is because no WORK is done.
i.e., `w = 0 ""w = -p_(ext) XX Delta V = 0 xx Delta V = 0`.
In `Delta U = q + w`
q = 0 because the gas CHAMBER is insulated.`Delta U = 0 + 0 = 0`.
Discussion
29.

What is the -O-O-H bond angle in solid form of H_2O_2 ?

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SOLUTION :In SOLID FORM of `H_2O_2 -O-O-H` BOND ANGLE is `101.9^@`.
Discussion
30.

What is the maximum numbers of electrons that can be associated with the following set of quantum numbers ? n=3, I=1 and m=-1

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4
6
2
10

Answer :C
Discussion
31.

Which of the following compounds undergo disproportionation in aqueoussolution ?

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`TlCl_(3)`
`GaCl`
`InCl`
`TlCl`

Solution :The MAXIMUM O.S. of TL is `+3`, therefore, Tl in `TlCl_(3)` cannot increases its O.S. beyond +3. Further, since +1 O.S. of Tl is muchmore STABLE than +3, therefore, Tl in `TlCl` is not LIKELY to INCREASE its O.S. to +3 . Thus, both `TlCl_(3)`and `TlCl`do not undergodisproportionation. Thus. options (b) and (c ) not correct.
Discussion
32.

Which of the following statements is INCORRECT for a real gas ?

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At Boyl TEMPERATURE, compressibility FACTOR, Z = 1
Above Boyle temperature, compressibility factor, `z gt 1 `
Below Boyletemperature, compressibility factor, `z lt 1`
REAL GAS follows ideal gas equation below Boyle temperature.

Answer :d
Discussion
33.

Which pump is important in biological reaction in human body?

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Ca - Be PUMP
NA - K pump
Fe - Ca pump
Ca - MG pump

Answer :B
Discussion
34.

Three structures P,Q and R having seme molecular formula, i.e., C_(5)H_(8)O. Structure (P) shows geometrical isomerism and optical isomerism but not tautomerism. Structure (Q) shows optical isomerism and toutomerism but not gemetrical isomerism. tautomerism but not optical isomerism. The structure of P, Q and R are respectively :

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SOLUTION :N//A
Discussion
35.

Which of the following chemical reaction depicts the oxidising behaviour of H_(2)SO_(4)?

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(a)NaCI`H_(2)SO_(4) rarrNaHSO_(4)+HCI`
`2PCI_(5)+H_(2)SO_(45)rarr2POCI_(3) +2HCI+SO_(2)CI_(2)`
`2HI+H_(2)SO_(4)rarrI_(2)+SO_(2)+2H_(2)O`
`CA(OH)_(2)+H_(2)SO_(4)rarrCaSO_(4)rarrrCaSO_(4)+2H_(2)O`

Answer :c
Discussion
36.

Which of the following is not exhibited by

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MILK
BLOOD
solution of urea
ICE cream

Answer :C
Discussion
37.

Which of the following statement is incorrect.

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`H_(2)O_(2)` can acts as an OXIDISING agent
`H_(2)O_(2)` can ACT as REDUCING agent
`H_(2)O_(2)` has acidic PROPERTIES
`H_(2)O_(2)` has basic properties

Answer :D
Discussion
38.

Write the significance of a plus and a minus sign shown in representing the orbitals.

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SOLUTION :Plus and minus sign CORRESPONDS to sign of electron wave. The CRESTS of a wave are usually GIVEN `+ve` sign and troughs of a wave given `-ve` sign.
Discussion
39.

The total number of orbitals associated with the principal quantum number n = 3 is………………… .

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9
8
5
7

Solution :n=3, 1 =0 , `m_1 = 0 ` - ONE s ORBITAL
n=3 ,1 , `m_1 =-1,0,1 -three p ORBITALS
n=3, 1=2, `m_1 =-2, -1 , 0, 1,2` - five d orbitials , OVERALL nine orbitals are possible.
Discussion
40.

What would be the molality of a solution obtained by mixing equal volumes of 30% by weight H_(2)SO_(4) ( d= 1.218 g mL^(-1)) and 70% by weight H_(2)SO_(4) ( d= 1.610g mL^(-1)) ? If the resulting solution has density 1.425g//mL, calculate its molarity.

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ANSWER :`7.61, 11.22`;
Discussion
41.

Which of the following is the smallest ring that can accommodate a triple bond?

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Cyclohexyne
cycloheptyne
cyclooctyne
cyclononyne

SOLUTION :Cyclooctyne
Discussion
42.

Water pollution does not cause

Answer»

CHANGE in COLOUR and salinity of water
increased fish POPULATION
DECREASE in quality of water
uncontrolled growth of WEEDS in water

Answer :B
Discussion
43.

What is the number of significant figures in each of the following measurement ? (a) 4.425 g (b) 5.6 xx 10^(3) cm (c) "0.000124 m"^(3)

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ANSWER :(a) Four (b) Two (C) THREE
Discussion
44.

Two sparnigly soluble salts AX and BX_(2) have their solubility product constant equal . Which of the following is (are) correct deduction(s) ?

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Solubility of `AX` ISW greater than solubility of `BX_(2)`.
If `S_(1)` and `S_(2)` are molar solubility of `AX` and `BX_(2)` then `S_(1) = (S_(2))^(3//2)`
If X is a conjugate BASE of a weak acid, addition of `HNO_(3)` will increase solubility of both AX with `BX_(2)`.
INCREASING the temperature, increase the solublity of both `AX` and `BX_(2)`.

Solution :`K_(sp) = (AX) = S_(1)^(2)`
`K_(sp) = (BX)_(2) = 4S_(2)^(3)`
If `S_(1)^(2) = 4S_(2)^(3)`, then `S_(1) = sqrt(4S_(2)^(3)) = 2(S_(2))^(3//2)`
`S_(1) gt S_(2)`
Discussion
45.

Which of the statements given below are true for the structure of water molecule ? (i) Oxygen undergoes sp^(3) hybridisation. (ii) Due to presence of two lone pairs of electrons on oxygen the H - O - H bond angle is 118.4^(@). (iii) Due to angular geometry the net dipole moment of water is not zero, mu = 1.84 D.

Answer»

(i) and (ii)
(ii) and (III)
(i) and (iii)
only (ii)

Solution :DUE to presence of two lone PAIRS of electrons on oxygen atom the bond ANGLE H-O-H is `104.5^(@)`.
Discussion
46.

Which of the following reaction conditions are used for the conversion of ethanol to ethylene?

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con `H_(2)SO_(4)//70^(@)C`
DIL `H_(2)SO_(4)//140^(@)C`
dil `H_(2)SO_(4)//100^(@)C`
CONC `H_(2)SO_(4)//170^(@)C`

ANSWER :D
Discussion
47.

Which gas has maximum kinetic energy between N_(2) and O_(2) at 300 K ?

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SOLUTION :KINETIC energy of both GAS have equal because TEMPERATURE is same of both. KE `prop` T.
Discussion
48.

What happened with halogen when AgNO_(3) is added in lassaigne solution of acidify with HNO_(3) ?

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Solution :Precipitate of silver HALIDE is FORMED with HALOGEN. `Ag^(+) + X^(-) RARR AGX darr`
Discussion
49.

When the hybridisation state of carbon atom changes from sp^(3) to sp^(2) and finaly to sp, the angle between the hybrid orbitals

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Decreases gradually
DECREASED considerably
No CHANGE
INCREASES PROGRESSIVELY

ANSWER :D
Discussion
50.

What is Empirical formula? Give an example for a compound whose Empirical formula and molecular formula are the same.

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Solution :It is SIMPLEST formula of a compound which REPRESENTS RATIO of ATOMS of DIFFERENT atoms in a compound. Eg. `CH_(4)`
Discussion