Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.	Norbornene can be converted into exo-norborneol by
Answer» hydroboration-oxidation reaction addition of water in the PRESENCE of dil. `H_(2)SO_(4)` OXYMERCURATION- demercuration reaction None of these Solution :

2.	Non - zero dipole moment is shown by
Answer» `CO_(2)` p-dichlorobenzene carbon tetrachloride water Solution :

3.	Non-stoichiometric cuprous oxidem,Cu_(2)O can bepreparedin thelaboratory. In this oxide, copper to oxygen ratio is slightly less than 2 :1 . Can you account for the fact that this substances is a a p -type semiconductor ?
Answer» Solution :The RATIO less than 2:1 in ` Cu_(2)O` shows that somecuprous `(Cu^(+))` ions have been replaced by cupric ` (Cu^(2+))` ions. To maintion electrical neutrality , EVERY two ` Cu^(+)` ionswill be DUE to presence of these POSITIVE HOLES, hence it is a p-type semiconductor.

4.	Non-stoichiometric hydrides are formed by…........
Answer» PALLADIUM,vanadium carbon,nickel manganese,lithium nitrogen,chlorine Answer :a

5.	Non-stoichiometric hydrides are formed by
Answer» PALLADIUM, vanadium carbon, NICKEL MANGANESE, lithium nitrogen, chlorine Answer :a

6.	Non-stoichiometric cuprous oxide, Cu_2O can be prepared in the laboratory. In this oxide, copper to oxygen ratio is slightly less than 2:1. Can you account for the fact that this substance is a p-type semiconductor.
Answer» Solution :The ratio less than 2:1 in `Cu_2O` shows that some cuprous `(Cu^+)` ions have been replaced by cupric `(Cu^(2+))` ions To maintain electrical neutrality, every TWO `Cu^+` ions will be replaced by one `Cu^(2+)` ION thereby creating a hole As conduction will be due to PRESENCE of these positive holes, hence it isa p-type semiconductor

7.	Non-stoichiometric Cu_(2)O in which coper to oxygen ratio is slightly less than 2:1 is
Answer» an insulator a SUPERCONDUCTOR at 273 K is a p-type semiconductor is an n-type semiconductor Solution :In a sample of non-stoichiometric `Cu_(2)O` in which CU:O ratio less than 2:1, some of the `Cu^(+)` IONS in the lattice are replaced by `Cu^(2+)` ions. A `Cu^(2+)`ION in place of `Cu^(+)` ion is equivalent to a hole as it has one electron less than`Cu^(+)`. This non-stoichiometric sample of `Cu_(2)O` will THUS act as p-type semiconductor.

8.	Non polar compounds can also solidify because of
Answer» Van DER Waals FORCES DIPOLE - dipole interaction lonic bonds Hydrogen bonds Solution :Non-polar SOLIDS have Vanderwaal.s forces.

9.	Non-Lanthanoid atom is
Answer» La Lu Pr Pm Answer :A

10.	Non-ideal gases approach ideal behaviour at:
Answer» HIGH TEMPERATURE and high pressure high temperature and LOW pressure low temperature and high pressure low temperature and low pressure Answer :B

11.	Nol. Of following reagents in which ppt A is soluble is AgNO_(3)+NaCl to A darr (i) aq. NH_(3) (ii) aq. KCN (iii) Na_(2)S_(2)O_(3) (iv) Conc. HCl (v) aq. NaoH (iv) aq. Kl
Answer» SOLUTION :`AgCl+aq.NH_(3)to[Ag(NH_(3))_(2)]^(+)CL^-` `AgCl+KCNtoK^(+)[Ag(CN)_(2)]^(-)` `AgCl+Na_(2)S_(2)O_(3)("excess")toNa_(3)[Ag(S_(2)O_(3))_(2)]` `AgCl+conc.Hclto[AgCl_(2)]^(-)` `AgCl+aq.NaOHtoAg_(2)Odarr`

12.	Non-benzenoid aromatic compound(s) is/are
Answer» Tropolone ANILINE Furan Cyclopentadienyl anion Solution :Aniline, Furan are BENZENOID AROMATIC COMPOUNDS

13.	Nominationof electronis 5200 A.At whichvelocityof electronitswavelengthis equaltophoton.
Answer» SOLUTION :`1.4 xx 10^(3) ms^(1)`

14.	Noble's oil is
Answer» Fire extinguisher Insecticide Explosive Detergent Solution :`{:(CH_(2)-ONO_(2)),("\|"),(CH-ONO_(2) " GLYCERYL trinitrate"),("\|"),(CH_(2)-ONO_(2)):}` or Nitroglycerine is called as Noble OIL.

15.	Noble prize in green chemistry is not associated with
Answer» RICHARD `R` schrock YVES Chauvin Robert `H` Grubbs R Williamson Solution :R Williamson is not associated with Nobal PRIZE in green chemistry, other are Nobal prize WINNERS in this field.

16.	Noble gases have maximum ionisation energy. Justify.
Answer» Solution :Noble gases have completely FILLED electronic COFIGURATION and are STABLE. (ii)It is difficult to remove the ELECTRONS from the valence shell. So the ionisation energy is MAXIMUM.

17.	Noble gases have almost zero electron affinity give reason.
Answer» Solution :(i) Noble gases have completely filled ELECTRONIC CONFIGURATIONS. (ii)It has no tendency to attract the electrons TOWARDS itself. (iii)so the electron affinity of noble gases are almost ZERO.

18.	NO_2 gas is not obtained by heating which compound ?
Answer» `AgNO_3` `KNO_3` `CU(NO_3)_2` `PB(NO_3)_2` ANSWER :B

19.	NO_2 is involved in the formation of smog and acid rain.A reaction that is important in the formation of NO_3 is O_3 (g) + NO(g) iff O_2 (g) + NO_2(g) K_C = 6.0 xx 10^(34) . If the airover a section of New Delhi contained1.0 xx 10^(6) M " of " O_3, 1.0 xx 10^(-5) Mof NO, 2.5 xx 10^(-4)M of NO_2 and 8.2 xx 10^(-3) Mof O_2 , what canwe conclude ?
Answer» there will betendency to FORM more `NO` and `O_ 2` there will betendency to form more `NO_2` and `O_ 2` there will betendency to form more `NO_2` and `O_ 3` there will no tendency for chane because the REACTION is at equilibrium Solution :`Q=([O_2][NO_2])/([O_(3)][NO])=([8.2 XX 10^(-3)][2.5 xx 10^(-4)])/([1.0 xx 10^(-6)][1.0 xx 10^(-5)])` `=8.2 xx 2.5 xx 10^(4) = 20.5 xx 10^(4)` As ` Q lt K_C`, the reaction will havea tendency to move forward .

20.	NO_2^(-) , F^(-) , H^(-) , CH_3COO^(-) like weak acid's strength of their conjugate base is more than water or less than water ?
Answer» Solution :All these are STRONGER BASE than water as these all are CONJUGATE base of WEAK acid.

21.	NO_(2) and SO_(2) have some properties in common. Which property shown by one of these compounds, but not by the other?
Answer» Forms acid Is a REDUCING agent Is SOLUBLE in water Is a it is USED as a food -preservative. Answer :C

22.	NO_2 and O_3 react with unburnt hydrocarbons present in polluted air and produce
Answer» FORMALDEHYDE ACROLEIN PEROXYACETYL nitrate All of these Solution :All of these

23.	No two electrons in an orbital can have parallel spin. This statement emerges from
Answer» Hund.s rule Aufbau PRINCIPLE Pauli.s exclusion principle (n + L) rule SOLUTION :Paulis. principle STATEMENT

24.	No reaction occurs in which of the following equations?
Answer» `I^(ө)-FE^(2+)rarr` `F_(2)+2NaClrarr` `Cl_(2)+2NaFrarr` `I_(2)+2NaBerarr` Solution :Reduction potential of `F_(2) gt Cl_(2) gt Br_(2) gt I_(2)`. So `F_(2)` can diplace `CI^(ө), Br^(ө)`, and `I^(ө)` but not VICE VERSA and `Br_(2)` can displace only `I^(ө)` but not vice versa. In (a), `Fe( "not" Fe^(2+))` is a better reducing AGENT than `I^(ө)`.

25.	No. of unit in SI system = ...........
Answer» 5 7 11 12 Answer :B

26.	No. of sigma - and pi - bonds in acrylonitrile
Answer» `3PI` and `6sigma` `7sigma` and `2PI` `7sigma` and `3pi` `2pi` and `6sigma` ANSWER :A

27.	No of revolutions made by the electron in one sec in 2^(nd) orbit of Be^(3+)
Answer» `1.31 XX 10^(16)` `2.13xx10^(16)` `1.23xx10^(15)` `2.68xx10^(14)` Solution :No. of revolutions (RPS) `=(Z^2)/(n^3) (6.65xx10^(15)) Hz`

28.	No. of possible isomers C_(4)H_(10)O formula does have……
Answer» 7 3 5 4 Solution :`C_(4)H_(10)O`: `CH_(3)-CH_(2)-CH_(2)-CH_(2)-OH` `CH_(3)-underset(underset(OH)(\|))(CH)-CH_(2)-CH_(3)` `CH_(3)-underset(underset(CH_(3))(\|))(CH)-CH_(2)-OH` `CH_(3)-underset(underset(OH)(\|))overset(overset(CH_(3))(\|))(C )-CH_(3)` `CH_(3)-O-CH_(2)-CH_(2)-CH_(3)` `CH_(3)-CH_(2)-O-CH_(2)-CH_(3)` `CH_(3)-O-underset(underset(CH_(3))(\|))(CH)-CH_(3)`

29.	No. of possible isomeric dioic acids for the molecular formulae C_(4)H_(4)O_(4) are
Answer» SOLUTION :3 DIO

30.	No. of moles of H_(2) gas evolved when one mole of the following compound reacts with sodium.
Answer» ANSWER :2

31.	No. of moles in 100 mg of heptane is â€¦â€¦â€¦â€¦than those in 10 mg of propyne
Answer» 4 times greater 4 times lesser 2.5 times greater 2.5 times lesser Solution :No. of moles in 100 mg of heptane `(C_(7)H_(16))` `= ((100xx10^(-3)g))/(("100g mol"^(-1)))=1xx10^(-3)` No. of moles in 10 mg of PROPYNE `(C_(3)H_(4))` `= ((10xx10^(-3)g))/(("40 g mol"^(-1)))=(1)/(4)xx10^(-3)` No. of moles of heptane are FOUR times the no. of moles of propyne.

32.	No. of moles of acetylene required for cyclic polymerization in a red hot copper tube to form2 moles of benzene is ________
Answer» SOLUTION :`6C_2 OVERSET(DELTA)to 2C_6H_6`

33.	No. of H_(2)O molecules in a drop of water weighing 0.05 g is :
Answer» `1.15 xx 10^(23)` `1.672 xx 10^(21)` `1.5 xx 10^(20)` `6.022 xx 10^(22)` Solution :18.0 g of `H_(2)O` contain molecules `=6.022 xx 10^(23)` 0.05 g of `H_(2)O` contain molecules `= ((0.05g))/((18.0g))xx6.022xx10^(23)` `=1.673xx10^(21)` molecules.

34.	No.of geometrical isomers possible for the compound CH_(3)-CH=CH-CH=CH-C_(2)H_(4)
Answer» 2 3 4 5 Solution :No of GEOMETRICAL ISOMERS = `2^n = 2^2 = 4`

35.	No. of electrons in 1.8 mL of H_2O (l) is:
Answer» `6.02 XX 10^(23)` `3.01 xx 10^(23)` `0.6022 xx 10^(23)` `60.22 xx 10^(23)` ANSWER :A

36.	No form of elemental silicon is comparable to graphite.
Answer» Solution :In graphite, carbon is `sp^(2)`-hybridizedand eachcarbon is liked to three other carbon atoms by forming hexagonalrings.Eachcarbonis now LEFT with on unhybridized p-orbital which undergoes sidewaysoverlap to form three `ppi-ppi`double bonds.Thus,graphite has two dimensional sheet like (layered) structureconsistingof a number of benzenerings fusedtogether. Siliconon the other hand,does notforman anlogue ofcarbon becauseof the FOLLOWING REASON : DUE to bigger size kand smallerelectronegativityof Si than C, it does not undergo `sp^(2)`-hybridization and hence it does not form`ppi-ppi`double bondsneededfor graphite like structure. Instead, it PREFERS to undergoonly `sp^(3)`-hybridization and hencesiliconhas diamondlike three-dimensional network structure.

37.	No gas is ideal gas, all gases are real gases.
Answer» ANSWER :1

38.	No crystal is found to be prefect at room temperature . The defects present in the crystals can be stoichiometric or non-stoichiometric. Due to non-stoichiometric defects, the formula of the ionic compound is different from the ideal formula. For example , the ideal formula of ferrous oxide should be FeO but actually in one sample , it was found to be Fe_0.93 O. This is because the crystal may have some ferric ions in place of ferrous ions. These defects change the properties of the crystals. In some cases , defects are introduced to havecrystals of desired properties as required in the field of electronics . Doping of elements of Group 14 with those of Group 13 or 15 is most common. In ionic compounds , usually impurities are introduced in which the cation has higher valency than the cation of the parent crystal , e.g. of SrCl_2 into NaCl NaCl was doped with 10^(-3) mol % SrCl_2. The concentration of cation vacancies is
Answer» `6.02xx10^18 "MOL"^(-1)` `6.02xx10^15 "mol"^(-1)` `6.02xx10^21 "mol"^(-1)` `6.02xx10^12 "mol"^(-1)` ANSWER :C

39.	No crystal is found to be prefect at room temperature . The defects present in the crystals can be stoichiometric or non-stoichiometric. Due to non-stoichiometric defects, the formula of the ionic compound is different from the ideal formula. For example , the ideal formula of ferrous oxide should be FeO but actually in one sample , it was found to be Fe_0.93 O. This is because the crystal may have some ferric ions in place of ferrous ions. These defects change the properties of the crystals. In some cases , defects are introduced to havecrystals of desired properties as required in the field of electronics . Doping of elements of Group 14 with those of Group 13 or 15 is most common. In ionic compounds , usually impurities are introduced in which the cation has higher valency than the cation of the parent crystal , e.g. of SrCl_2 into NaCl Which one of the following defects does not affect the density of the crystal ?
Answer» SCHOTTKY DEFECTS Interstitial DEFECT Frenkel defect Both in (b ) and(c ) Solution :Frenkel defect does not AFFECT the density of the CRYSTAL because cations are missing from lattice sites and occupy interstitial sites.

40.	No crystal is found to be prefect at room temperature . The defects present in the crystals can be stoichiometric or non-stoichiometric. Due to non-stoichiometric defects, the formula of the ionic compound is different from the ideal formula. For example , the ideal formula of ferrous oxide should be FeO but actually in one sample , it was found to be Fe_0.93 O. This is because the crystal may have some ferric ions in place of ferrous ions. These defects change the properties of the crystals. In some cases , defects are introduced to havecrystals of desired properties as required in the field of electronics . Doping of elements of Group 14 with those of Group 13 or 15 is most common. In ionic compounds , usually impurities are introduced in which the cation has higher valency than the cation of the parent crystal , e.g. of SrCl_2 into NaCl Which one of the following doping will produce p-type semiconductor ?
Answer» Silicon doped with arsenic Germanium doped with phosphorus Germanium doped with aluminium Silicon doped with phosphorus SOLUTION :Germanium belongs to GROUP 14 while aluminium belongs to Group 13. Hence, germanium doped with aluminium will produce p-type SEMICONDUCTOR .

41.	No crystal is found to be prefect at room temperature. The defects present in the crystals can be stoichimetric or non-stoichiometric. Due to non-stoichimetric defects, the formula of the ionic compound isdifferent from the ideal formula. For example , the ideal formula of ferrous oxide should be FeO but actually in one sample , it was found to beFe_(0.93)O.This is because the crystal may have some ferric ions in place of ferrous ions.These defects change the propeties of the crystals. In some cases, defects are introduced to have crystals of desired properties as required in the field of electronics. Dopingof elments of Group 14 with those of Group13 or 15 is most common. In ionic compounds, usually impurities are introduced in which the cation has higher valency than the cation of the parent crystal, e.g,SrCl_(2)into NaCl.NaCl was doped with10^(-3) " mol % " SrCl_(2) . The concentreation of cation vancancies is
Answer» ` 6.02 xx 10^(18) " mol"^(-1)` `6.02 xx 10^(15) " mol"^(-1)` `6.02 X 10^(21) "mol"^(-1)` `6.02 xx 10^(12) "mol"^(-1)`

42.	No crystal is found to be prefect at room temperature. The defects present in the crystals can be stoichimetric or non-stoichiometric. Due to non-stoichimetric defects, the formula of the ionic compound isdifferent from the ideal formula. For example , the ideal formula of ferrous oxide should be FeO but actually in one sample , it was found to beFe_(0.93)O.This is because the crystal may have some ferric ions in place of ferrous ions.These defects change the propeties of the crystals. In some cases, defects are introduced to have crystals of desired properties as required in the field of electronics. Dopingof elments of Group 14 with those of Group13 or 15 is most common. In ionic compounds, usually impurities are introduced in which the cation has higher valency than the cation of the parent crystal, e.g,SrCl_(2)into NaCl.which one of the following defects does not affect the density of the crystal ?
Answer» SCHOTTKY DEFECT Interstitial defect Frenkel defect Both in (b) and (c ) Solution :Frenkel defect does not affect the DENSITY of the crystal because cations are missing from LATTICE sites and occupy intersitial sites.

43.	No crystal is found to be prefect at room temperature. The defects present in the crystals can be stoichimetric or non-stoichiometric. Due to non-stoichiometric defects, the formula of the ionic compound isdifferent from the ideal formula. For example, the ideal formula of ferrous oxide should be FeO but actually in one sample, it was found to beFe_(0.93)O.This is because the crystal may have some ferric ions in place of ferrous ions.These defects change the properties of the crystals. In some cases, defects are introduced to have crystals of desired properties as required in the field of electronics. Dopingof elements of Group 14 with those of Group13 or 15 is most common. In ionic compounds, usually impurities are introduced in which the cation has higher valency than the cation of the parent crystal, e.g,SrCl_(2)into NaCl.which one of the following doping will produces p-type semiconductor?
Answer» Silicon doped with arsenic GERMANIUM doped with phosphorus Germanium doped with aluminium Silicon doped with phosphours Solution :Germanium belongs to GROUP 14 while aluminium belongs to Group 13. Hence, germanium doped with aluminium will PRODUCE p-type semiconductor.

44.	No crystal is found to beperfect at room temperature. The defects present in the crystals can be stoichiometric or non-stoichiometric. Due to non-stoichiometricdefects, the formula of the ionic compound is different from the ideal formula. For example, the ideal formula of ferrous oxide should be FeO but actually in one sample, it was found to be Fe_(0.93)O. This is because the crystal may have some ferric ions in place of ferrous ions. These defects change the properties of the crystals. In some cases, defects are introduced ot have crystals of desired properties as required in the field of electronics. Doping of elements of group 14 with those of group 13 or 15 is most common. In ionic compounds, usually the impurities are introduced in which the cation has higher valency than the cation of the parent crystal e.g.,SrCl_(2) into NaCl. Which one of the following defects does not affect the density of the crystal ?
Answer» Schottky defect Interstitial defects Frenkel defect Both (A) and (B) Solution :Frenkel defect does not affect the density of the CRYSTAL because CATIONS are missing from lattice SITES and OCCUPY interstitial sites.

45.	No crystal is found to beperfect at room temperature. The defects present in the crystals can be stoichiometric or non-stoichiometric. Due to non-stoichiometricdefects, the formula of the ionic compound is different from the ideal formula. For example, the ideal formula of ferrous oxide should be FeO but actually in one sample, it was found to be Fe_(0.93)O. This is because the crystal may have some ferric ions in place of ferrous ions. These defects change the properties of the crystals. In some cases, defects are introduced ot have crystals of desired properties as required in the field of electronics. Doping of elements of group 14 with those of group 13 or 15 is most common. In ionic compounds, usually the impurities are introduced in which the cation has higher valency than the cation of the parent crystal e.g.,SrCl_(2) into NaCl. The percentage of iron as Fe_(III)inFe_(0.93)O_(1.0)is
Answer» 0.177 0.0784 0.115 `9.6%` Solution :`Fe_(0.93)O or Fe_(93)O_(100)` `"TOTAL -ve charge on "O^(2-)"IONS" = 2times100 = 200` `"LET no. of "Fe^(2+)"ions" = x` `therefore"""no. of "Fe^(3+)"ions" = 93-x` `therefore" Total +ve charge on "Fe^(2+)andFe^(3+)"ions"` =`2x+3(93-x)` For electrical neutrality of crystal, `2x+3(93-x)=200` `2x+279-3x = 200` x=79 `thereforeFe^(2+)=x=79`, `Fe^(3+)=93-x=93-79=14` `therefore"formula of oxide is ,"` `Fe_(79)^(2+)" " Fe_(14)^(3+) O_(100)orFe_(0.79)^(2+) "" Fe_(0.14)^(2+) O` `"Molar mass" = 0.93times56+16 = 68.08` `%" of Fe as "Fe^(3+) = (0.14times56)/(68.08)times100 = 11.5%`

46.	No crystal is found to beperfect at room temperature. The defects present in the crystals can be stoichiometric or non-stoichiometric. Due to non-stoichiometricdefects, the formula of the ionic compound is different from the ideal formula. For example, the ideal formula of ferrous oxide should be FeO but actually in one sample, it was found to be Fe_(0.93)O. This is because the crystal may have some ferric ions in place of ferrous ions. These defects change the properties of the crystals. In some cases, defects are introduced ot have crystals of desired properties as required in the field of electronics. Doping of elements of group 14 with those of group 13 or 15 is most common. In ionic compounds, usually the impurities are introduced in which the cation has higher valency than the cation of the parent crystal e.g.,SrCl_(2) into NaCl. NaCl was doped with 10^(-3) mol % SrCl_(2).The concentration of the cation vacancies is
Answer» `6.02times10^(18)"mol"^(-1)` `6.02times10^(15)"mol"^(-1)` `6.02times10^(15)"mol"^(-1)` `6.02times10^(12)"mol"^(-1)` Solution :Doping of NACL with `10^(-3)" MOLE " SrCl_(2) " means that 100 moles of NaCl are doped with " 10^(-3) " mol of " SrCl_(2)` `therefore "1 mole of NaCl is doped with "SrCl_(2)` =`(10^(-3))/100"mole"= 10^(-5)"mole"` Since `Sr^(2+)`ion introduces one cation vacancy, therefore, concentration of cation vacancies `= 10^(-5)"mol//mol of NaCl"` =`10^(-5)times6.02times10^(23)"mol"^(-1)` =`6.02times10^(18)"mol"^(-1)`.

47.	No crystal is found to beperfect at room temperature. The defects present in the crystals can be stoichiometric or non-stoichiometric. Due to non-stoichiometricdefects, the formula of the ionic compound is different from the ideal formula. For example, the ideal formula of ferrous oxide should be FeO but actually in one sample, it was found to be Fe_(0.93)O. This is because the crystal may have some ferric ions in place of ferrous ions. These defects change the properties of the crystals. In some cases, defects are introduced ot have crystals of desired properties as required in the field of electronics. Doping of elements of group 14 with those of group 13 or 15 is most common. In ionic compounds, usually the impurities are introduced in which the cation has higher valency than the cation of the parent crystal e.g.,SrCl_(2) into NaCl. Which of the following dopings will produce p type semiconductor ?
Answer» Silicon doped with ARSENIC Germanium doped phosphorus Germanium doped with aluminium Silicon doped with phosphorus. Solution :Germanium belongs to group 14 while aluminium belongs to group 13. Hence, germanium doped with aluminium will PRODUCE p-type semiconductor.

48.	NKg^(-1) is the unit of
Answer» Momentum Veloity Pressure Acceleration Answer :D

49.	Nitromethane exists in the aci-form but nitrobenzene does not. Explain why ?
Answer» Solution :Nitromethane has `alpha`-HYDROGEN and hence it exists in the aci-form. In contrast, NITROBENZENE does not have an `alpha`-hydrogen and hence it does EXIST in the aci-form.

50.	Nitrogen trihalides are
Answer» Lewis acid Lewis BASE Lowry-Bronsted acid ARRHENIUS base Solution :`NX_3 ` have LONE PAIR of ` e^(-) `