Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The metal that is used as a deoxidiser in metallurgy is.

Answer»

`SN`
`PB`
`CU`
`MG`

ANSWER :D
Discussion
2.

The metal that gives mainly a monoxide when heated in excess of O_(2) is

Answer»

`CS`
`NA`
`K`
`LI`

ANSWER :D
Discussion
3.

The metal that can't displace hydrogen from dil. HCl is :

Answer»

AL
Fe
Cu
Zn

Answer :C
Discussion
4.

The metal that behaves odd when dissolved in a solution of caustic soda

Answer»

`AL`
`Zn`
`CU`
`SN`

Answer :C
Discussion
5.

The metal present in deposits of nitre is ______

Answer»

SOLUTION : LITHIUM
Discussion
6.

The metal ions which are precipitated when H_(2)S gas is passed in the presence of dilute HCl is :

Answer»

`Zn^(2+)`
`NI^(2+)`
`CD^(2+)`
`Mn^(2+)`

SOLUTION :`Cd^(2+)` IONS are precipitated as yellow precipitate of CDS
Discussion
7.

The metal extracted by cyanide process is

Answer»

SILVER
Copper
Iron
Sodium ALUMINIUM .

Solution :The metal OBTAINED by cyanide process is Ag.
Discussion
8.

The metal best used in photoelectric cells is

Answer»

`NA`
`MG`
`AL`
`CS`

ANSWER :D
Discussion
9.

The members of B_(n)H_(n+4) series are less stable than B_(n)H_(n+6) series.

Answer»


SOLUTION :MEMBERS of `B_(n) H_(n+6)` SERIES are less STABLE than `B_(n)H_(n+4)` series.
Discussion
10.

The members of a homologous series have

Answer»

DIFFERENT GENERAL formulae
Different MOLECULAR weights
Different METHODS of preparation
Different chemical properties.

Answer :B
Discussion
11.

The melting points of the following halides follow the order

Answer»

`LICL lt NaCl lt KCL lt RbCl`
`RbCl lt KCl lt NaCl lt LiCl`
`LiCl lt KCl lt RbCl lt NaCl`
`LiCl lt RbCl lt KCl lt NaCl`

SOLUTION :being COVALENT LiCl has the lowest m.p.
Discussion
12.

The melting points of n-pentane (I), isopentane (II) and neopentane (III) increase in the order:

Answer»

`II lt I lt III`
`III lt II lt I`
`III lt I lt II`
`I lt II lt III`

Solution :Neopentane (III) being most symmetrical has the HIGHEST m.p. followed by n pentane while isopentane(II) being LEAST symmetrical has the LOWEST m.p.
Discussion
13.

The melting point of four substances are given in bracket, then the attraction forces in a solid is more in case of

Answer»

Ice (273 K) 
NaF (1270 K) 
Phosphorus (317 K) 
Naphthalein (353 K) 

ANSWER :B
Discussion
14.

The melting point of CaI_(2) is much lower (575^(@)C) than that of CaF_(2) (1392^(@)C)-explain with reason.

Answer»

Solution :According to Fajan's rule, tendencyy of a large sized anion to be polarised is GREATER than that of a small sized anion. So a COMPOUND CONTAINING a large sized anion exhibits more covalent character than that with a small sized anion. Hence, `CaI_(2)` containing larger `I^(-)` ion possesses higher covalent character and melts at a relatively low TEMPERATURE. on the other hand, `CaF_(2)` containing smaller `F^(-)` ion possesses much lowerr covalent character and melts at very high temperature.
Discussion
15.

The melting point of a substance was quoted as 52.5^(@)C, 52.57^(@)C, 52.571^(@)C, and 52.5713^(@)C. Which of these values would be most acceptable and which will have maximum uncertanity?

Answer»

`52.5^(@)C`
`52.57^(@)C`
`52.571^(@)C`
`52.5713^(@)C`

SOLUTION :Acceptable VALUE `= 52.57^(@)C`
MAXIMUM uncertainty `= 52.5^(@)C`
Discussion
16.

The thermodynamic property that measures the extent of molecular disorder is called entropy. The direction of a spontaneous process for which the energy is constant is always the one that increases the molecular disorder. Entropy change of phase transformation can be calculated using Trouton's formula (DeltaS= (DeltaH)/(T)). In the reversible adiabatic process, however, DeltaS will be zero. The rise in temperature in isobaric and isochoric conditions is found to increase the randomness or entropy of the system. DeltaS= 2.303 C log (T_(1)//T_(2)), (C = C_(P) or C_(V)) The melting point of a solid is 300K and its latent heat of fusion is 600 cal mol^(-1). The entropy change for the fusion of 1 mole of the soli (in cal K^(-1)) at the same temperature would be:

Answer»

200
2
`0.2`
20

Answer :B
Discussion
17.

The melting and boiling points of halides of alkali metals follow the trend A) Flourides B) Chlorides C) Bromides D) Iodides

Answer»

`AGT B GT C gt D`
`D gt C gt B gt A`
`A gt C gt B gt D`
`D gt B gt C gt A`

ANSWER :A
Discussion
18.

The medium present in the environment which consumes some amount of certain pollutant is called a

Answer»

sink
TARGET
neutrality
buffer ACTION

SOLUTION :Sink is the medium in the ENVIRONMENT which comsumes PARTLY or completely a certain pollutant.
Discussion
19.

The medium which reacts wi lh pollutant is called

Answer»

SINK
RECEPTOR
CONTAMINANT
SPECIATION

ANSWER :A
Discussion
20.

The mechanism of the reaction of propene with HOCI (Cl_2 + H_2O)will proceed through which of the following intermediates?

Answer»

`CH_3 - overset(oplus)(CH)-CH_2OH`
`CH-3-overset(oplus)(CH)-CH_2Cl`
`CH_3-overset(OH)(CH)-overset(oplus)(C)H_3`
`CH_3-overset(Cl)(CH)-overset(oplus)(C)H_2`

SOLUTION :The CHLORINE atom has the LESSER electronegativity and is the electrophile and the carbocation in this intermediate has the GREATER number of hyperconjugation resonance forms.
Discussion
21.

The mechanism of the reaction of propene with H_3O^(+) will proceed through which of the following intermediates?

Answer»




SOLUTION :The mechanism for the hydration of an ALKENE with dilute acid will first GO through the most stable CARBOCATION followed by the attack of water on the electropositive carbon atom yielding this INTERMEDIATE
Discussion
22.

The mechanism of an electrophilic substitution reaction is Which of the following is not ture.

Answer»

Increasing the resonance of II will increases rate of reaction
increasing the DENSITY of electron in I will increase the rate of reaction.
Treatment of base in step-II will increase the rate
Temperature increasing will accelerate the rate of reaction.

Solution :`H^(o+)` is LOST in the FAST step.
Discussion
23.

The measurement of the electron position is associated with an uncertainly in momentum , which is equal to 1xx10^(-18) "gcms"^(-1) .The uncertainty in electron velocity is , (mass of an electron is 9xx10^(-28) g)

Answer»

`1XX10^5 "CM s"^(-1)`
`1xx10^11 "cm s"^(-1)`
`1xx10^9 "cm s"^(-1)`
`1xx10^6 "cm s"^(-1)`

SOLUTION :`Delta p=1xx10^(-18)`
`DELTAV=(1xx10^(-18))/(9xx10^(-28)) RARR Deltav=1/9xx10^10`
`=0.11xx10^10 = 1.1xx10^9` cm/sec
Discussion
24.

The measurement of the pressure of dry gas collected over water is based upon

Answer»

GAY LUSSAC's LAW
CHARLE's law
Boyle's law
DALTON's law

Answer :D
Discussion
25.

The measure of attractive forces of molecules is called________.

Answer»

internal pressure
cohesion pressure
both (a) and (b)
NEITHER (a) nor (b)

ANSWER :C
Discussion
26.

The mean speed of Helium atoms is 4 times that of the molecules of a gas x at the same temperature. The molecular weight of x is

Answer»

4 
16 
32
64 

ANSWER :D
Discussion
27.

The mean lives of radioactive substance are 1620 year and 405 year for alpha- emission and beta- emission respectively. Find out the time duringwhichthree fourth of a samplewill decay, if it is decaying both by alpha- emission and beta- emission simulaneously.

Answer»


ANSWER :`449.24` YEAR
Discussion
28.

The mean free path of a gas molecule is the distance

Answer»

between the two opposite walls of the container 
which the MOLECULE travel in one SECOND 
through which a molecule MOVES between two consecutive COLLISIONS 
Which the molecule travel in one second 

Solution :`lambda` is distance between two consecutive collisions.
Discussion
29.

The maximum tendency to form unipositive ion is for the element with the electronic configuration

Answer»

`1s^(2)2S^(2)2P^(6)3s^(2)`
`1s^(2)2s^(2)2p^(6)3s^(2)3P^(1)`
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(2)`
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(3)`

Answer :B
Discussion
30.

The maximum tendency to form tripositive ion is for the element with the electronic configuration

Answer»

`1s^2 2s^2 2p^6 3s^2`
`1s^2 2s^2 2p^6 3s^2 3p^1`
`1s^2 2s^2 2p^6 3s^2 3p^2`
`1s^2 2s^2 2p^6 3s^2 3p^3`

ANSWER :B
Discussion
31.

The maximum probability of finding electron in the d_(xy) orbital is

Answer»

ALONG the x-axis
along the y-axis
at an ANGLE of `45^(@)` from the x-axis and y-axis
at an angle of `90^(@)` from the x-axis and y-axis

Solution :The `d_(xy)` ORBITAL has LOBES between x-axis and y-axis, i.e., at an angle of `45^(@)` from x-axis and y-axis.
Discussion
32.

The maximum production of hydrogen is obtain from

Answer»

METAL REACT with acid
Petrochemicals
By coal
By electrolysis

Answer :B
Discussion
33.

The maximum probability of finding an electron of a particular energy in an orbital is about

Answer»

`80%`
0.85
0.95
0.99

Answer :C
Discussion
34.

The maximum prescribed concentration of cadmium in drinking water in ppm is

Answer»

0.05
3
2
0.005

Answer :D
Discussion
35.

The maximum pH of a solution which is 0.10 M in Mg ^(2+ )from which Mg (OH) _ 2 is not precipitated is : ( Given K_(sp) " of " Mg (OH)_2 =1.2 xx 10^(-11) M)

Answer»

`4. 96`
`6.96`
`7. 54 `
` 9. 04`

Solution :` Ag_2Cr O_4 HARR 2Ag^(+)+CrO_4^(-2) `
` "" 2S "" S `
` (i)0.1 M Ag^(+)" IONS is common ION "`
` 9 xx 10 ^(-12) = ( 2S)^(2)(0.1 )^(2)xx S RARR S =9 xx 10 ^(-10 )M`
` (ii)0.1 M CrO_4^(-2)" ions is commonion " `
` 9xx 10 ^(_12)=( 2S)^(2)(0.1)rArr 9 xx 10 ^(_12)= 4S^(2)0.1 `
` S = sqrt( (9)/(4) xx 10 ^(-11))~~4.5 xx 10^(_6)M`
`[Mg^(+2) ][OH^(-)] ltKsp , (0.1)[OH^(-) ]^(2)lt 1.2 xx 10 ^(-11)`
` [OH^(-)] lt sqrt(1.2 xx 10 ^(-10)), [OH^(-) ] lt 1.09xx 10 ^(-5)POH = 4. 96 , PH = 9. 04`
Discussion
36.

The maximum oxidaton state that fluorine exhibits is

Answer»

`-1`
ZERO
`+1`
`+2`

Solution :The MAXIMUM oxidation STATE of fluorine is0, i.e., in `F_2` .
Discussion
37.

The maximum numbers of electrons in a sub shell is given by the expression

Answer»

`2N^(2)`
`21+1`
`41+2`
none of these

Solution :`2(21 + 1) = 41 + 2`
Discussion
38.

The maximum number of oxidation states which nitrogen can show in its compounds is.

Answer»


SOLUTION :9 oxidation states are POSSIBLE, i.e., -3, -2, -1, 0, +1, +2, +3, +4, and +5.
Discussion
39.

The maximum number of possible hydrogen molecules formed from its isotopes is

Answer»

3
6
9
12

Answer :B
Discussion
40.

The maximum number of linear atoms in propyne molecule are

Answer»

3
4
2
6

Solution :`H-C-=CH-CH_(3)`. The MAXIMUM NUMBER of hinear ATOMS are 4.
Discussion
41.

The maximum number of isomers (including stereoisomers ) that are possible on monochlorination of the following compound is :

Answer»
Discussion
42.

The maximum number of hydrogen bonds that a water molecule can form is

Answer»

1
2
3
4

Solution :Each `H_(2)` moleculecan FORM TWO H-bond through
O-atom and two H-bonds through two H-atoms
Discussion
43.

The maximum number of isomers for an alkene with molecular formula C_(4)H_(8) is….

Answer»

two
three
four
six

Answer :B
Discussion
44.

The maximum number of hydrogen bonds formed by a water molecule in ice is

Answer»

4
1
2
3

Answer :A
Discussion
45.

The maximum number of eletrons with s = +1/2 in an orbital for which l=2 is

Answer»

1
3
5
7

Answer :A
Discussion
46.

The maximum number of electrons with s = +1/2 in an orbital for which 1=2 is

Answer»

1
3
5
7

Solution :Any ORBITAL can ACCOMMODATE 2 `E^-` only
Discussion
47.

The maximum number of elements available in elemental form

Answer»

26
92
111
118

Answer :B
Discussion
48.

The maximum number of electrons that p-orbital can accommodate is

Answer»

6
2
10
14

Answer :A
Discussion
49.

The maximum number of electrons that can have principal quantum number, n = 3, and spin quantum number, m_(s) = -(1)/(2), is

Answer»


Solution :Number of orbitals in the SHELL with n = 3 will be `= n^(2) = 3^(2) = 9`. Each orbital can have maximum 2 electrons one with spin `+(1)/(2)` and the other with `- (1)/(2)`. HENCE, number of electrons with `m_(s) = - (1)/(2)` will be 9
Discussion
50.

The maximum number of electrons that can have principal quantum number, n = 3 and spin quantum number m_s= - 1//2 is ________.

Answer»


Solution :Total NUMBER of electrons with (n=3) `=2n^2 =18`
Out of these 18 electrons, 9 electrons will have anticlcokwise SPIN `(m_s = -1/2)`
Discussion