Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

When 22.4 litres of H_(2)(g) is mixied with 11.2 litres of Cl_(2)(g), each at S.T.P, the moles of HCl (g) formed is equal to :

Answer»

0.5 mol of HCl (g)
1.5 mol of HCl (g)
1.0 mol of HCl (g)
2.0 mol of HCl (g)

SOLUTION :No. of moles in 22.4 L of `H_(2)(g)` at S.T.P = 1 mol
No. of moles in 11.2 L of `Cl_(2)(g)` at S.T.P = 0.5 mol
`underset("1 mol")(H_(2)(g))+underset("1 mol")(Cl_(2)(g))rarrunderset("2 mol")(2HCl(g))`
`Cl_(2)(g)` is the limiting REACTANT SINCE it has only 0.5 mole available for chemical reaction
`:.` No. of moles of HCl (g) formed = 1mol.
Discussion
2.

The strongest base among the following

Answer»

`C_(6)H_(5)NH_(2)`
`(CH_(3))_(2)NH`
`CH_(3)NH_(2)`
`(CH_(2))_(3)N`

Answer :B
Discussion
3.

Which of the reagent is used in Kharash effect ?

Answer»

HI
HCl
HBr
HF

Answer :C
Discussion
4.

Weak Acid HA (K_a = 1.4 xx 10^(-5)) 0.1 M so in dissow in 2 lit. Find percentage of ionization and pH of solution.

Answer»

SOLUTION :`HA_((aq)) + H_2O_((l)) HARR H_3O_((aq))^(+) + A_((aq))^(-)`
`K_a=1.4xx10^(-5)` initial concentration C=0.1 M
`[H_3O^+]=SQRT(K_axxC)`
`=(1.4xx10^(-5)xx0.1)^(1/2)`
`=1.183xx10^(-3)` M
`pH=-log [H_3O^+]`
`=-log (1.183xx10^(-3))`
=-(0.07306-3)
=2.9269 `APPROX` 2.93
`K_a=(alpha^2C)/(1-alpha)` Now, `1-alpha approx 1`
`K_a=alpha^2C`
`alpha=sqrt(K_a/C) = sqrt((1.4xx10^(-5))/0.1)`
`alpha=1.183xx10^(-2)`
% of dissociation = `alpha xx 100`
`=1.183xx10^(-2) xx100`
=1.183 %
Discussion
5.

Which of the following undergo electrophilic substitution reactions faster than benzene ?

Answer»

Phenol
Aniline
toluene
Chlorobenzene

Answer :A::B::C
Discussion
6.

Which of the following does not have any effect with water?

Answer»

SODIUM
Iron
Lead
MERCURY

ANSWER :d
Discussion
7.

What happens when ethylene is passed through cold dilutealkaline potassium permanganate

Answer»

Solution :Ethylenereactswithcolddilutealkaline`KMnO_(4)` SOLUTIONTO giveethyleneglycol
`CH_(2) = CH_(2)+ H_(2) Ounderset((O)273 K) OVERSET( KMnO_(2)OH^(@))(to)CH_(2) - UNDERSET(OH ) underset(|) (C H_(2))`
Discussion
8.

Which of the following has smaller size?

Answer»

H
`He^(+)`
`""_(1)H^(2)`
`LI^(2+)`

ANSWER :D
Discussion
9.

Write formulas for the following compounds : Thallium (I) sulphate

Answer»

SOLUTION :`Th_(2)SO_(4)`
Discussion
10.

Which one is remedy to protect depletion of ozone layer ?

Answer»

Prevent the use of ODS
Decreasing the PRODUCTION of CFC UPTO 50%.
Both (A) and (B)
By releasing more `CO_2 `

SOLUTION :Both (A) and (B)
Discussion
11.

Which of the following is not tetrahedral?

Answer»

`BF_(4)^(-)`
`NH_(4)^(+)`
`CO_(3)^(2-)`
`SO_(4)^(2-)`

Answer :C
Discussion
12.

What is the nameof Thomsonmodel ?

Answer»

SOLUTION :Thomsonmodelof ATOMIS KNOWNAS plumpuddingrisinpuddingor WATERMELON.
Discussion
13.

Write the disproportionation reactions of the following species : (i) ClO^(-) (ii) ClO_3^(-) (iii) Cl^(-) (iv) ClO_3^(-) (v) ClO_4^(-) (vi) Tl^+

Answer»

Solution :(i) `OVERSET(+1)(3Cl)O^(-)rarroverset(-1)(2C)l^(-)+overset(+5)(ClO_3^(-))`
(ii) `overset(+5)(4ClO_3^(-))rarroverset(-1)(Cl^-)+overset(+5)(2ClO_3^(-))`
(iii) `Cl^-` does not DISPROPORTIONATE.
(iv) `overset(+3)(ClO_2^-)rarroverset(-1)(Cl)+overset(+5)(2ClO_3^(-))`
(v) `ClO_4^(-)` does not disproportionate because in this oxoanion , chlorine is present in its highest oxidation state i.e., +7.
(iv) `3Tl^(+)hArroverset(0)(2Tl)+Tl^(3+)`
Discussion
14.

Which of the following is free radical?

Answer»

`NO_2`
`CL^-`
`Cl`
`Cl^+`

SOLUTION :`NO_2` Lewins ACID (ELECTROPHILE)
`Cl^-`: NUCLEOPHILE, `Cl^+` Electrophile
Discussion
15.

Which of the following reagent will convert Propanoic acidto Propan-1-ol?

Answer»

`KMnO_(4)`
`MnO_(2)`
`Cr_(2)O_(3)`
`LiAlH_(4)`

SOLUTION :`LiAlH_(4)` reduces `-COOH` to `-CH_(2)OH`.
Discussion
16.

Which of the following set of quantum number is vaild / invalid . In case of valid set write the symbol of the orbital it respresent [may more than one answers] &in case it is invalid mention the resason.{:("n",1,m),(3,"not known (but less than 3)",0),(-2,""-1,+1),(4,""2,-1):}

Answer»

Solution :(i)valid ,`3s//3p_(x)//3p_(y)//3p_(z)//3d_(x^(2)-y^(2))//3d_(z^2)//3d_(XY)//3d_(XZ)//3d_(YZ)`
(ii)Invaild 'n' cannot be NEGATIVE
(III) Vaild `4d_(x^(2)-_y^(2))//4d_(z^(2))//4d_(xy)//4d_(xz)//4d_(yz)`
Discussion
17.

Which of the following is wrong .

Answer»

The maximum COVALENCY of Boron is 4 where as that of Al is 6 .
The order of EN of IIIA group ELEMENTS is `B gt Al lt Ga lt In lt TI`
Down the group the oxidising power increases .
The ordder of acidic NATURE :
`N_(2)O_(3) gt P_(2) O_(3) gt As_(2) O_(3) gt Sb_(2)O_(3) gt Bi_(2)O_(3)`

Answer :C
Discussion
18.

Traces of which metal is present in the sulphide ore of Zn ?

Answer»

Indium
Aluminium
Gallium
Thallium

Answer :A
Discussion
19.

Which of the following compounds can show optical isomerism as well as geometrical isomerism?

Answer»




SOLUTION :N//A
Discussion
20.

Which of anions in the column-I showns one or more observations from the column-II?

Answer»


ANSWER :(a-s);(b-p,Q,R,s);(c-p,q);(d-p)
Discussion
21.

Which of the following properties show similar trends down the group among the elements of group 1 and 17?

Answer»

METALLIC character
mp/bp
reactivity
electronegativity

Answer :A::D
Discussion
22.

What is indicated by Psi for atomic and molecular orbitals ? How the molecular orbital is obtained by Schrodinger wave equation ? OR What is LCAO.

Answer»

SOLUTION :Atomic orbitals and `Psi` : According to wave mechanics, the atomic orbitals can be EXPRESSED by wave functions `(Psi)` which represent the amplitude of the electron WAVES. These are obtained form the solution of schrodinger wave equation.
MOLECULAR orbital and `Psi` and LCAO : Schrodinger wave equation can not be solved fore any system containing more than one electron, molecular orbitals which are one electron wave functions for molecules are difficult to obtain directly from the solution of Schrodinger wave equation. To overcome this problem, an approximate method known as linear combination of atomic orbitals (LCAO) has been adopted.
LCAO means method for solution of molecular orbitals having more than one electron by Schrodinger wave equation.
Discussion
23.

The resonance hybrid of nitrate ion is

Answer»




ANSWER :C
Discussion
24.

Which one isthe correct unit for entropy?

Answer»

KJ MOL
`JK^(-1)` mol
`JK^(-1) "mol"^(-1)`
KJ `mol^(-1)`

ANSWER :C
Discussion
25.

Write down the resonance structures of CO_3^(2-) and HCO_3^(-)

Answer»


ANSWER :(##ANE_PKE_CHE_0XI_C11_E01_008_S01##)
(##ANE_PKE_CHE_0XI_C11_E01_008_S02##)
Discussion
26.

What volume of dioxygen is required for complete combustion of 2 volume of acetylene gas at NTP ?

Answer»

2 volumes
5 volumes
10 volumes
4 volumes

Solution :`UNDERSET(1 VOL.)(C_2H_2)+underset(5/2vol.)(5/2O_2) to underset(2vol.)(2CO_2)+H_2O`
1 vol. of `C_2H_2` REQUIRES = `5/2 " vol. of " O_2`
2 vol. of `C_2H_2 " requires " = 5/2xx2=5 vol. " of " O_2`
Discussion
27.

Which of the following sets of compounds cannot turn clear orange solution of CrO_(3)//aq. H_(2)SO_(4) of greenish opaque solution

Answer»

I, IV
II, III
I, II
III, IV

Answer :D
Discussion
28.

What iscatenation ?

Answer»

Solution :PROPERTY of self-linkingof atoms to form chains or ringsof various sizesis calledcatenation. Carbonhas THEMAXIMUM tendencyfor catenation due to highbond STRENGTH of `C-C` BONDS.
Discussion
29.

Which of the following is a cyclic oxo acid ?

Answer»

<P>`H_(4)P_(2)O_(7)`
`H_(4)P_(2)O_(6)`
`H_(3)P_(3)O_(9)`
`H_(5)O_(5)O_(15)`

Solution :`(HPO_(3))_(3)=H_(3)P_(3)O_(9)` is a six-membered cyclic oxoacid.
`(HPO_(3))_(5)=H_(5)P_(5)O_(15)` cannot be regarded as a cyclic oxo acid since ten-membered rings are difficult of form. Therefore, it has a CHAIN STRUCTURE.
Discussion
30.

What is alkane substitution reactions ? Give different types of substitution reactoins name and possibilities.

Answer»

Solution :In alkane, one or more hydrogen is substituted can be substituted with halogen, nitro group and sulphuric acid group. These reactions in which hydrogen atoms of alkanes are substituted are known as substitution reactions.
(a) Nitration : Hydrogen of alkane is substituted with `_NO_(2)` group, Known as nitration.
(b) Sulphonation : Hydrogen of alkane is substituted with `-SO_(3)H` group, known as sulphonation.
(c) Halogenation : Hydrogen of alkane is replaced with halogen (F, Cl, Br, I) Known as halogenation. Rate of reaction of alkanes are : `F_(2) gt Cl_(2) gt Br_(2) gt I_(2)`
(d) Fluorination : Fluorination is too violent to be controlled. `(CH_(4)+F_(2)(N_(2) " or " Ar) rarr CH_(3)F + HF)`
(e) Iodination : Iodination is vert slow and a reversible reaction. It can be carried out in the PRESENCE of oxidizing aganets like `HIO_(3)` or `HNO_(3)`.
`CH_(4) + I_(2) hArr CH_(3)I + HI`
`HIO_(3) + 5HI rarr 3I_(2) + 3H_(2)O`
(f) Chlorination and bromination : They are easy reactions. If chlorine is in required amount then all the hydrogens are substituted with -Cl ATOM.
`CH_(4) underset(-HCl)overset(hv, Cl_(2))rarr CH_(3)Cl underset(-HCl)overset(hv, Cl_(2))rarrCH_(2)Cl_(2)`
`underset(-HCl)overset(hv, Cl_(2))rarrCHCl_(3) underset(-HCl)overset(hv, Cl_(2))RARRC Cl_(4)` ....(i)
`underset("Ethane")(CH_(3))-CH_(3)+Cl_(2) overset(hv) rarr underset("Chloroethane")(CH_(3))-CH_(2)Cl+HCl` ...(ii)
Chlorination and bromination takes place either at temperature 573 to 773 K or in presence of diffused sunlight or UV light.
In alkane, series of substitution of H is `3^(@) gt 2^(@) gt 1^(@)`.
e.g., `CH_(3)CH_(2)CH_(3) underset(-HCl)overset(hv, Cl_(2))rarrunderset("1-Chloropropane")underset(45%)(CH_(3)H_(2)CH_(2)Cl)+underset("1-Chloropropane")underset(55%)(CH_(3)CHCLCH_(3))`
Substitution of `2^(@)` - hydrogen `gt` Substitution of `1^(@)` hydrogen rate
(g) Bromination : Reaction is slow than that of chlorine and mainly monobromo is formed.
Discussion
31.

Two flasks of equal volumes have been joined by a narrow tube of negligible volume. Initially both the flasks are 300 K and totally 9 mole of gas is present. One of the flasks is then placed in a thermostat at 600K. How many moles of gas is present in hot bulb.

Answer»


Solution :TOTAL initial MOLES = total final moles
`(n_("hot"))/(n_("cold")) = ((PxxV)/(R XX 600))/(P xx V//R xx 300) = 1/2`
`n_("hot") = 1/3 xx 9 = 3 `moles.
Discussion
32.

Vapour pressure is very high for the following liquid at room temperature

Answer»

WATER
ACETONE
DIETHYL ETHER
Benzene

Answer :C
Discussion
33.

The two equilibrium AB hArr A^(+) + B^(-) and AB+B^(-)hArrAB_(2)^(-) are simultaneously maintained in a solutio with equilibrium constant K_(1) and K_(2) respectively. The ratio of [A^(+)]to [AB_(2)^(-)] in the solution is

Answer»

directly proportional to the concentration of `B^(-)`
INVERSELY proportional to the concentration of `B^(-)`
directly proporitonal to the squar eof the concentration of `B^(-)`
Inversely proportional to the SQUARE of the concentration of `B^(-)`.

ANSWER :D
Discussion
34.

Writethe mechanism of freidel craft acylation

Answer»

Solution :STEP :1Generationof `.^(@) CH_(3) COCI to`electrohile
Step :2 Attackof theelectrophileon benzenering toformareniumion.

Step :3rearomatiosationof ARENIUMION.
Discussion
35.

Write electron configuration, bond order and Magnetic property of Hydrogen (H_(2)) molecule.

Answer»

SOLUTION :Electron CONFIGURATION : It is formed by the combination of two hydrogen atoms (1s).
Total number of electron in ` H_(2)` molecule = 2
In `H_(2)` molecule BMO : `sigma_(1s) and sigma_(1s)^(*)`
`THEREFORE e^(-)` configuration of `H_(2)` molecule : `(sigma_(1s))^(2) (sigma_(1s)^(*))^(0)`
bond order : BMO : `sigma`(1s) = 2 electron and
ABMO : `(sigma_(1s)^(*)) = 0 ` electron
`therefore ` Bond order = `(N_(b) - N_(a))/(2) = ((2 - 0))/(2) = 1 `
This MEANS two H atoms are bonded together by a single covalent bond.
Magnetic property : In `H_(2)` molecule, no unpair~d electron is present and only electron paired present . `therefore H_(2)` molecule is diamagnetic .
Discussion
36.

Which of the following has the highest positive electron gain enthalpy ?

Answer»

F
`O^(-)`
`Na^(+)`
`MG^(2+)`

Answer :B
Discussion
37.

The rms speed of hydrogen molecules at room temperature is 2400 ms^(-1). At room temperature the rms speed of oxygen molecules would be:

Answer»

`400 MS^(-1)`
`300 ms^(-1)`
`600 ms^(-1)`
`1600 ms^(-1)`

Solution :`(C_(O_(2)))/(C_(H_(2))) = sqrt((M_(H_(2)))/(M_(O_(2))))`
Discussion
38.

Which of the following compounds have finite dipole moments ?

Answer»

trans-2-Pentene
cis-2-Pentene
1-Butyne
2-Butyne

Answer :A::B::C
Discussion
39.

Which is not evidence used to support the delocalisation model for benzene?

Answer»

Benzene has 6 equal length bonds, not alternating long/short bonds.
Benzene does not undergo electrophilic addition with HYDROGEN bromide.
Benzene shows IR absorption at AROUND 3000 `cm^(-1)`
The hydrogenation of benzene produces less energy than expected.

Solution :This is TRUE for all hydrocarbons as this corresponds to the region for the C-H absorption. It does not SUPPORT any particular model for benzene.
Discussion
40.

What is the correct sequence of reagents for the following conversion : CH_3-undersetunderset(Br)(|)CH-CH_3 to CH_3-CH_2-CH_2-I

Answer»

`OVERSET(alc. KOH)to overset(HI)to`
`overset(aq.KOH)to undersetDeltaoverset(H_2SO_4)to overset(HI)to`
`overset(alc. KOH) to overset(HBr//R_2O_2)to UNDERSET("acetone")overset(KI)to`
`overset(alc.KOH)to overset(HCL) to underset("acetone")overset(KI)to`

Solution :
Discussion
41.

Which compound given below has sp^3, sp^2 and sp orbitals in the ratio of 6:3:2

Answer»

`CH_3 - CH = CH - CH_2- C = C - CH_2`
`CH_3 -CH = CH - CH_2 - C = CH`
`CH_3 - CH_2 - C -= C -CH = CH_2`
`CH_3 - CH = CH - C -= CH`

ANSWER :A
Discussion
42.

Which of the following statements are correct regarding hydrogen? i) The largest single use of dihydrogen is in the synthesis of NH_(3). Which is used in the manufacture of HNO_(3) and nitrogenous fertilizers. (ii) It is used to reduce heavy metal oxide (iii) It is used as rocket fuel. (iv) Atomic hydrogen and oxy hydrogen torches find use for cutting and welding purpose.

Answer»

i, III
i, II
i, ii, iv
i, ii, iii, iv

Answer :D
Discussion
43.

Titration curves for 0.10 M solution of three weak acids HX, HY and HZ with ionization constants H_(1), K_(2) and K_(3) respectively are plotted as shown in the figure below:

Answer»

`K_(2) = (K_(1) + K_(2))/(2)`
`K_(1) lt K_(3)`
`K_(1) GT K_(2)`
`K_(2) gt K_(3)`

Solution :N//A
Discussion
44.

The vapour pressures of benzene at 303k and 333k are respectively 1.53xx10^(4) and 5.2xx10^(4)Nm^(-2) Calculate the latent heat of evaporation of benzene over this temperature.

Answer»

SOLUTION :LOGE `P_(2)/P_(1)=(DeltaHv)/(2.30R)[(T_(2)-T_(1))/(T_(1)T_(2))]`,where `DeltaHv`is LATENT HEAT of evportation.
`2.303"log" "(5.2xx10^(4))/(1.52xx10^(4))=(DeltaHv)/8.314[(333-303)/(333xx303)]`
`DeltaH_(v)=34215J=34.215KJ`
Discussion
45.

Which of the following pairs is isostructural?

Answer»

`BC l_(3) and BrCl_(3)`
`NH_(3) and NO_(3)^(-)`
`NF_(3) and BF_(3)`
`BF_(4)^(-)and NH_(4)^(+)`

SOLUTION :If number of BOND pairs and lone pairs are same for

.
Discussion
46.

What happens when formic acid is heated with Cone. H_(2)SO_(4)? Give theequation.

Answer»

Solution :Dehydration takes place or CO is FORMED `H-COOH UNDERSET(A)OVERSET(H_(2)SO_(4))(to)CO+H_(2)O`
Discussion
47.

Which element has smallest size?

Answer»

B
N
Al
P

Answer :B
Discussion
48.

What is the correct IUP AC name for CH_(3)-underset(CH_(3))underset(|)overset(H)overset(|)C-CH=CH-CH_(2)-overset(O)overset(||)C-OH ?

Answer»

5-Methyl-3-hexenoic ACID
5-Carboxyl-2-methylpentene
4-Isopropyl-3-butenoic acid
NONE of above

Solution :IUPAC NOMENCLATURE of Rules
Discussion
49.

Which changes of properties of periods shows reactivity ?

Answer»

SOLUTION :(i) Tendency of reduction and oxidation.
(ii) Metallic and non-metallic property.
(iii) Reaction of Halogen and oxygen.
(IV) ACIDIC, basic, NEUTRAL and properties of oxide.
Discussion
50.

Which of the following configurations represent atoms of elements having the highest second ionisation energy?

Answer»

`1S^(2) 2s^(2) 2p^(4)`
`1s^(2) 2s^(2) 2p^(6)`
`1s^(2) 2s^(2) 2p^(6) 3S^(1)`
`1s^(2) 2s^(2) 2p^(6) 3s^(2)`

Answer :c
Discussion