InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 49251. |
A sugar syrup of weight 214.2 g contains 34.2gofsugar(C_(12)H_(22)O_(11)).Calculate(i)molal concentration (ii) mole fraction of sugar in the syrup. |
| Answer» <html><body><p></p>Solution :Weight of sugar syrup = 214.<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> g<br/> Weight of sugar present = 34.2 g <br/> <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> mass of sugar `(C_(12)H_(22)O_(11)) = 342` <br/> (i) <a href="https://interviewquestions.tuteehub.com/tag/calculation-907729" style="font-weight:bold;" target="_blank" title="Click to know more about CALCULATION">CALCULATION</a> of molality : <br/> Number of moles of sugar = `34.2/342 = 0.1` <br/> Weight of water `=214.2 - 34.2 = 180 g = 0.18 g` <br/> `therefore` Molecular of the solution `=("No. of moles of sugar")/("Weight of water in kg")` <br/> `=0.1/0.18 = 0.56 <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a> kg^(-1)` <br/> Hence, the <a href="https://interviewquestions.tuteehub.com/tag/molal-1100217" style="font-weight:bold;" target="_blank" title="Click to know more about MOLAL">MOLAL</a> concentration of the given solution is 0.56 m. <br/> (ii) Calculation of mole fraction : <br/> Number of moles of sugar `(n_(1))=0.1` <br/> Number of moles of water `(n_(2)) = 180/18 = 10` <br/> Total number of moles in solution `=n_(1) + n_(2) = 0.1 + 10 = 10.1` <br/> `therefore` The mole fraction of sugar `=n_(1)/(n_(1)+ n_(2)) = 0.1/10.1 = 9.9 xx 10^(-3)`</body></html> | |
| 49252. |
A sudden large jump between the value of second and third ionisation energies of elements would be associated with which of the following electronic configurations ? |
| Answer» <html><body><p>`1s^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) 2s^(2) 2p^(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) 3s^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/>`1s^(2) 2s^(2) 2p^(6) 3p^(1)`<br/>`1s^(2) 2s^(2) 2p^(6) 3s^(1) 3p^(2)`<br/>`1s^(2) 2s^(2) 2p^(6) 3s^(2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :d</body></html> | |
| 49253. |
A sudden jump between the values of second and third ionisation energies of an element is associated with configuration |
| Answer» <html><body><p>`1s^2 2s^2 2p^63s^1`<br/>`1s^2 2s^2 2p^6 3s^2 3p^1`<br/>`1s^2 2s^2 2p^6 3s^2 3p^2`<br/>`1s^2 2s^2 2p^63s^2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49254. |
A substance which promotes the activity of a catalyst is known as |
| Answer» <html><body><p>initiator<br/>catalyst<br/>promotor<br/>autocatalyst.</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49255. |
A substance which is not present in nature but added lo atmoshphere due to human activity and causes adverse effect on environment is called |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/pollutant-1158344" style="font-weight:bold;" target="_blank" title="Click to know more about POLLUTANT">POLLUTANT</a> <br/>Contaminant <br/><a href="https://interviewquestions.tuteehub.com/tag/sink-1210432" style="font-weight:bold;" target="_blank" title="Click to know more about SINK">SINK</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/receptor-620486" style="font-weight:bold;" target="_blank" title="Click to know more about RECEPTOR">RECEPTOR</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49256. |
A substance which is not present in nature but added to atmoshphere due to human activity and causes adverse effect on environment is called |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/pollutant-1158344" style="font-weight:bold;" target="_blank" title="Click to know more about POLLUTANT">POLLUTANT</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/contaminant-931619" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAMINANT">CONTAMINANT</a> <br/>Sink<br/>Receptor </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49257. |
A substance which gives brick red flame and breaks down on heating to give oxygen and a brown gas is.... |
| Answer» <html><body><p>magnesium nitrate<br/><a href="https://interviewquestions.tuteehub.com/tag/calcium-412119" style="font-weight:bold;" target="_blank" title="Click to know more about CALCIUM">CALCIUM</a> nitrate<br/>barium nitrate<br/>strontium nitrate</p>Solution :Calcium <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> brick red flame. Calcium nitrate on heating get decompose and produce calcium <a href="https://interviewquestions.tuteehub.com/tag/oxide-1144484" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDE">OXIDE</a> and mixture of `NO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` and `O_(2).NO_(2)` is <a href="https://interviewquestions.tuteehub.com/tag/brown-904764" style="font-weight:bold;" target="_blank" title="Click to know more about BROWN">BROWN</a> gas. <br/> `2Ca(NO_(3))_(2) to 2CaO+NO_(2)+O_(2)` <br/> `NO_(2)` is brown coloured gas.</body></html> | |
| 49258. |
A substance which gives brick red flame and breaks down on heating to give oxygen and a brown gas is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/calcium-412119" style="font-weight:bold;" target="_blank" title="Click to know more about CALCIUM">CALCIUM</a> carbonate<br/>calcium <a href="https://interviewquestions.tuteehub.com/tag/nitrate-1118228" style="font-weight:bold;" target="_blank" title="Click to know more about NITRATE">NITRATE</a><br/>magnesium carbonate<br/>barium nitrate, </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :calcium nitrate</body></html> | |
| 49259. |
A substance on analysis, gave the following percentage composition, Na = 43.4%, C = 11.3%, 0 = 45.3% calculate its empirical formula [Na = 23, C = 12, O = 16]. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Na_2CO_3`</body></html> | |
| 49260. |
A substance on analysis, gave the following percentage composition, Na = 43.4%, C = 11.3%, 0 = 43.3% calculate its empirical formula [Na = 23, C = 12, O = 16]. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Na_2CO_3`</body></html> | |
| 49261. |
A substance of crude copper is boiled in H_(2)SO_(4) till all the copper has reacted. The impurites are inert to acid. The SO_(2) liberated in the reactionis passed into 100mL of 0.4M acidified KMnO_(3). The solution of KMnO_(4)after passage of SO_(2) is allowed to react withoxalic acid and requireds 23.6mL of 1.2M oxalic acid. IF the purity of copper is 90% what was the weight of sample? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`5.06g`</body></html> | |
| 49262. |
A substance is expanded in adiabatic process from 2 L to 5 L against constant pressure of 1 bar then internal energy change will be : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> <a href="https://interviewquestions.tuteehub.com/tag/bar-892478" style="font-weight:bold;" target="_blank" title="Click to know more about BAR">BAR</a>-<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a><br/>`-3 "bar"-L`<br/>6 bar-L<br/>`-6 "bar"-L`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49263. |
A substance A_(x)B_(y) crystallizes in a face centred cubic (FCC) lattice in which atoms 'A' occupy each corner of the cube and atoms 'B' occupy the centres of each face of the cube. Identify the correct composition of the substance A_(x)B_(y) |
| Answer» <html><body><p>`AB_(3)`<br/>`A_(4)B_(3)`<br/>`A_(3)B`<br/>composition cannot be specified</p>Solution :A at corner `= (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(8) xx 8 xx A = A` ltrbgt B at face <a href="https://interviewquestions.tuteehub.com/tag/center-11455" style="font-weight:bold;" target="_blank" title="Click to know more about CENTER">CENTER</a> `= (1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) xx <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> xx B = 3B = AB_(3)`</body></html> | |
| 49264. |
A substance A_(x) B_(y) crystallises in a face centred cubic (FCC) lattice in which atoms 'A' occupy each corner of the cube and atoms 'B' occupy the centres of each face of the cube. Identify the correct composition of the substance A_(x)B_(y). |
| Answer» <html><body><p>`AB_(3)`<br/>`A_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)B_(4)`<br/>`A_(3)B`<br/><a href="https://interviewquestions.tuteehub.com/tag/composition-22493" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOSITION">COMPOSITION</a> cannotbe specified.</p>Solution :Number of A atoms per <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> =`8times1/8=1` <br/> Number of B atoms per unit cell = `6times1/2=3` <br/> Composition of solid = `AB_(3)`</body></html> | |
| 49265. |
A substance absorbs CO_2 and violently reacts with water. The substance is |
| Answer» <html><body><p>`CaCO_3`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/cao-411869" style="font-weight:bold;" target="_blank" title="Click to know more about CAO">CAO</a>`<br/>`H_2SO_4`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/zno-751438" style="font-weight:bold;" target="_blank" title="Click to know more about ZNO">ZNO</a>`.</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`CaO`</body></html> | |
| 49266. |
Chemical A is used for water softening to remove temporary hardness. A reacts with sodium carbonate to generate caustic soda. When carbondioxide is bubbled through A, it turns cloudy. What is the chemical formula of A? |
| Answer» <html><body><p>`CaCO_(3)`<br/>CaO<br/>`Ca(OH)_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`Ca(HCO_(3))_(2)`</p>Solution :Slaked lime Is usedto remove tamporary hardness of water. It <a href="https://interviewquestions.tuteehub.com/tag/converts-933341" style="font-weight:bold;" target="_blank" title="Click to know more about CONVERTS">CONVERTS</a> <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a> <a href="https://interviewquestions.tuteehub.com/tag/bicarbonates-896608" style="font-weight:bold;" target="_blank" title="Click to know more about BICARBONATES">BICARBONATES</a> of Mg and Ca into <a href="https://interviewquestions.tuteehub.com/tag/insoluble-1045950" style="font-weight:bold;" target="_blank" title="Click to know more about INSOLUBLE">INSOLUBLE</a> carbonates of Mg and Ca.</body></html> | |
| 49267. |
A substanceA hasthe followingvariationofvapour presesure with temperaturefor itssolid stateandliquildstate . Indentify the optionswhich are correct : Date: For solidA:log_(10) P=4-(200)/(T) For liquindA : log_(10)P=3.48-(1500)/(T)whereP isin mm of Hg and T in K. |
| Answer» <html><body><p>Enthalpy of vapourisationand enthalpyof fusion will betemperatureindependent.<br/>`DeltaH_(<a href="https://interviewquestions.tuteehub.com/tag/sub-1230791" style="font-weight:bold;" target="_blank" title="Click to know more about SUB">SUB</a>.)` willbe approximately`9.212 kcal//mol.`<br/>`DeltaH_(fusion)` will be approximately `2.303 kcal//mol`.<br/>`DeltaH_(<a href="https://interviewquestions.tuteehub.com/tag/vap-1442817" style="font-weight:bold;" target="_blank" title="Click to know more about VAP">VAP</a>)` will be approximately `6.909 kcal//mol`.</p>Answer :a,<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>,c,d</body></html> | |
| 49268. |
A substance A has a normal melting point of 250 K of 250 K and normal boiling point 300 K. Using this information and other information given below calculate DeltaS_("sublimation" ) " at " 250 K["in cal"//"K-mole"] Information -1:Entropy of vapourisation at 300 K is 21 cal/K-mole Information-2 : Latest heat of fusion at 250 K is 2.5 kcal/mole Information -3: C_(p) is liquidA and gaseousA is 20 cal//"K mole" "and"10 "cal"//K-"mole" Information -4: In (6)/(3)=0.18 [Round off your answer to nearest integer.] |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/33-307818" style="font-weight:bold;" target="_blank" title="Click to know more about 33">33</a></body></html> | |
| 49269. |
A student was given a sample of colourless solution contaning three cations and was asked to identify the cations: student carried out a series of reactions as given below. White precipitate A is not soluble in: |
| Answer» <html><body><p>`NH_(3)`<br/>`2M <a href="https://interviewquestions.tuteehub.com/tag/hci-479434" style="font-weight:bold;" target="_blank" title="Click to know more about HCI">HCI</a>`<br/>`KCN`<br/>`Na_(2)S_(2)O_(3)`</p>Solution :`A rarr AgCI, B rarr BaSO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>), C rarr Zn(OH)_(2)` <br/> `A rarr` Insoluble in `HCI`, <br/> `BaSO_(4)darr +H_(2)SO_(2) ("conc") rarr <a href="https://interviewquestions.tuteehub.com/tag/ba-389206" style="font-weight:bold;" target="_blank" title="Click to know more about BA">BA</a>^(2+) +2HSO_(4)^(-)`</body></html> | |
| 49270. |
A student was given a sample of colourless solution contaning three cations and was asked to identify the cations: student carried out a series of reactions as given below. Which of the following statement is correct? |
| Answer» <html><body><p>Precipitate C gives Rinmann's green test.<br/>Precipitate <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> is appreciably soluble in boiling <a href="https://interviewquestions.tuteehub.com/tag/concentrated-409727" style="font-weight:bold;" target="_blank" title="Click to know more about CONCENTRATED">CONCENTRATED</a> `H_(2)SO_(4)`<br/>Precipitate A on exposure to <a href="https://interviewquestions.tuteehub.com/tag/sunlight-1234644" style="font-weight:bold;" target="_blank" title="Click to know more about SUNLIGHT">SUNLIGHT</a> or ultraviolet radiations <a href="https://interviewquestions.tuteehub.com/tag/turns-1429088" style="font-weight:bold;" target="_blank" title="Click to know more about TURNS">TURNS</a> black<br/>All of the above</p>Solution :`A rarr AgCI, B rarr BaSO_(4), C rarr Zn(OH)_(2)` <br/> `A rarr` Insoluble in `HCI`, <br/> `BaSO_(4)darr +H_(2)SO_(2) ("<a href="https://interviewquestions.tuteehub.com/tag/conc-927968" style="font-weight:bold;" target="_blank" title="Click to know more about CONC">CONC</a>") rarr Ba^(2+) +2HSO_(4)^(-)`</body></html> | |
| 49271. |
A student was given a sample of colourless solution contaning three cations and was asked to identify the cations: student carried out a series of reactions as given below. Precipitates A,B and C are respectively: |
| Answer» <html><body><p>`AI(OH)_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>),BaSO_(4)` and `AgCI`<br/>`AgCI, BaSO_(4)` and `zn(OH)_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`AgCI,Ca(OH)_(2)` and `ZnSO_(4)`<br/>`ZnCI_(2),BaSO_(4)` and `AI(OH)_(3)`</p>Solution :`A rarr AgCI, B rarr BaSO_(4), <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> rarr Zn(OH)_(2)` <br/> `A rarr` Insoluble in `HCI`, <br/> `BaSO_(4)darr +H_(2)SO_(2) ("<a href="https://interviewquestions.tuteehub.com/tag/conc-927968" style="font-weight:bold;" target="_blank" title="Click to know more about CONC">CONC</a>") rarr Ba^(2+) +2HSO_(4)^(-)`</body></html> | |
| 49272. |
A student was asked by his teacher to verify the law of conservation of mass in the laboratory. He prepared 5 % aqueous solutions of NaCl and Na_(2)SO_(4). He mixied 10 mL of both these solutions in a conical flask. He weighed the flask on a balance. He then stirred the flask with a rod and weighed it after sometime. There was no change in mass. Read this narration and answer the following question (i) Was the student able to verify the law of conservation of mass ? (ii) If not, what was the mixtake committed by him ? (iii) In your opinion, what he should have done ? (iv) What is the value associated with it ? |
| Answer» <html><body><p></p>Solution :(i) No. he could not verify the <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of conservation of mass <a href="https://interviewquestions.tuteehub.com/tag/inspite-1046031" style="font-weight:bold;" target="_blank" title="Click to know more about INSPITE">INSPITE</a> of the fact that there was no change in mass. <br/> (ii) No chemical reaction <a href="https://interviewquestions.tuteehub.com/tag/takes-1238575" style="font-weight:bold;" target="_blank" title="Click to know more about TAKES">TAKES</a> place between NaCl and `Na_(2)SO_(4)`. This means that no reaction actually took place in the flask <br/> (iii) He should have performed the <a href="https://interviewquestions.tuteehub.com/tag/experiment-980358" style="font-weight:bold;" target="_blank" title="Click to know more about EXPERIMENT">EXPERIMENT</a> by using aqueous solutions of `BaCl_(2) and Na_(2)SO_(4)`. A chemical reaction takes place in this case and white precipitate of `BaSO_(4)` is <a href="https://interviewquestions.tuteehub.com/tag/formed-464209" style="font-weight:bold;" target="_blank" title="Click to know more about FORMED">FORMED</a>. <br/> (iv) In order to support or verify the law of conservation of mass in laboratory, one must select those substances which actually react chemically. Moreover, all chemical reactions involving gaseous species must be carried in close containers.</body></html> | |
| 49273. |
A student was asked by his teacher to separate an impure sample of sulphur containing sand as the impurity. He tried to purify it with the help of sublimation. But he was not successful. Particles of sulphur of sulphur could not be separated completely from sand. (i) Why did the sublimation process succeed ? (ii) Suggest an alternate method to affect the separation. (iii) What is the value based information associated with this ? |
| Answer» <html><body><p></p>Solution :(i) Sulphur is not of volatile nature. Upon heating it melts. Therefore, <a href="https://interviewquestions.tuteehub.com/tag/sublimation-1231130" style="font-weight:bold;" target="_blank" title="Click to know more about SUBLIMATION">SUBLIMATION</a> process could not succeed. <br/> (ii) The student should have dissolved the <a href="https://interviewquestions.tuteehub.com/tag/impure-1039183" style="font-weight:bold;" target="_blank" title="Click to know more about IMPURE">IMPURE</a> sample in carbon disulphide. It is a <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> in which sulphur completely dissolves while iron does not. From the solution, can be recovered with the help of crystallization process. <br/> (iii) The process of sublimation is useful only if one of the constituents present in the <a href="https://interviewquestions.tuteehub.com/tag/mixture-1098735" style="font-weight:bold;" target="_blank" title="Click to know more about MIXTURE">MIXTURE</a> can sublime while the others do not undergo sublimation.</body></html> | |
| 49274. |
A student wants to prepared a saturated solution of Ag^(+) ion. He has got only three samples AgCI(K_(SP)=1.8xx10^(-10)). Which compound he should use to have maximum [Ag^(+)]? |
| Answer» <html><body><p>AgCI<br/>AgBr<br/>`Ag_(2)CrO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>Either of them</p>Solution :`S_(Ag^(+))=S_(AgCI)= sqrt(K_(SP))=sqrt(1.8xx10^(-10))` <br/> `=1.34xx10^(-5)M` <br/> `S_(Ag^(+))=S_(AgBr)=sqrt(K_(SP))=sqrt(5.0xx10^(-13))` <br/>`=7.07xx10^(-7)M` <br/> `S_(Ag_(2)CrO_(4))=3sqrt((K_(SP))/(4))= 3sqrt((2.4xx10^(-12))/(4))` <br/> `= 0.8xx10^(-4)M` <br/> Also `S_(Ag^(+))=2xxS_(Ag_(2)CrO_(4))` <br/> `= 0.8xx10^(-4)xx2=1.6xx10^(-4)M` <br/> This will <a href="https://interviewquestions.tuteehub.com/tag/give-468520" style="font-weight:bold;" target="_blank" title="Click to know more about GIVE">GIVE</a> <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> value.</body></html> | |
| 49275. |
A student reported the ionic radii of isocelectronic species X^(3+), Y^(2+) and Z^- as 136 pm 64 pm and 49 pm respectively. Is that order correct ? Comment. |
| Answer» <html><body><p></p>Solution :`:.` <a href="https://interviewquestions.tuteehub.com/tag/effective-966090" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECTIVE">EFFECTIVE</a> <a href="https://interviewquestions.tuteehub.com/tag/nuclear-2474" style="font-weight:bold;" target="_blank" title="Click to know more about NUCLEAR">NUCLEAR</a> charge is in the order<br/>`(Z_(<a href="https://interviewquestions.tuteehub.com/tag/eff-966053" style="font-weight:bold;" target="_blank" title="Click to know more about EFF">EFF</a>))_(z-)<a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a>(Z_(eff))_X3+` and henceionic <a href="https://interviewquestions.tuteehub.com/tag/radii-1175952" style="font-weight:bold;" target="_blank" title="Click to know more about RADII">RADII</a> should be in the order `r_z gt r_(y2+)gt r_(x3+)`<br/>`:.` The correct value are<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V01_C03_E02_005_S01.png" width="80%"/></body></html> | |
| 49276. |
A student prepared solutions of NaCl, Na_(2)CO_(3) and NH_(4)Cl. He put them separately in three test tubes. He forgot to label them. All solutions were colourless . How should he proceed to know the solutions present in thethree test tubes ? |
| Answer» <html><body><p></p>Solution :He can test with <a href="https://interviewquestions.tuteehub.com/tag/blue-899773" style="font-weight:bold;" target="_blank" title="Click to know more about BLUE">BLUE</a> and red litmus solutions. NaCl solution is <a href="https://interviewquestions.tuteehub.com/tag/neutral-1114358" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRAL">NEUTRAL</a>. It will <a href="https://interviewquestions.tuteehub.com/tag/neither-1113494" style="font-weight:bold;" target="_blank" title="Click to know more about NEITHER">NEITHER</a> <a href="https://interviewquestions.tuteehub.com/tag/turn-1429043" style="font-weight:bold;" target="_blank" title="Click to know more about TURN">TURN</a> blue litmus red nor red litmus blue. `NH_(4)<a href="https://interviewquestions.tuteehub.com/tag/cl-408888" style="font-weight:bold;" target="_blank" title="Click to know more about CL">CL</a>` solution is acidic. It will turn blue litmus red but will have no effect on red litmus `Na_(2)CO_(3)` solution is basic. It will turn red litmus blue but will have no effect on blue litmus .</body></html> | |
| 49277. |
A student prepared a sample of silicon chloride by passing chlorine over heated silicon and collecting the condensed silicon chloride in a small specimen tube. He analsed the chloride by dissolving a known mass of it in water and titrating the solution with standard silver nitrates solution. The formula of the silicon chloride as obtained by this method was SiCl_(2.6) as aganist a true formula SiCl_(4). Which of the following possible errors could have resulted in this wrong formula? |
| Answer» <html><body><p>The silicon chloride contained excess dissolved chlorine.<br/>More silicon chlorine than the student supposed was actually <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> owing to inaccurate weighing<br/>The small <a href="https://interviewquestions.tuteehub.com/tag/speciment-3053935" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIMENT">SPECIMENT</a> tube was not dry<br/>The reaction between the silicon and the chlorine stopped permaturely <a href="https://interviewquestions.tuteehub.com/tag/leaving-1070834" style="font-weight:bold;" target="_blank" title="Click to know more about LEAVING">LEAVING</a> some unreacted silicon in the reaction tube</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49278. |
A student performs a titration with different buretts and fins titre value of 25.2 ml, 2.25 ml, 25.0 ml. The number of significant figures in the average titre value i. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`25.2rarr1` <a href="https://interviewquestions.tuteehub.com/tag/sd-629953" style="font-weight:bold;" target="_blank" title="Click to know more about SD">SD</a> after decimal <br/> `25.25rarr2` SD after decimal <br/> `25.0rarr1` SD after decimal <br/> `therefore` Final <a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> can have <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> SD after decimal and <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> SD before decimal</body></html> | |
| 49279. |
A student forgot to add the reaction mixture to the round bottomed flask at 27 ^(@)C but instead he/she placed the flask on the flame. After a lapse of time, he realized his mistake, and using a pyrometer he found the temperature of the flask was 477 ^(@)C. What fraction of air would have been expelled out? |
| Answer» <html><body><p></p>Solution :When an open flask is heated, its volume and pressure may be regarded as <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a>. Suppose the <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of moles of air in the flask before and after heating are `n_1 and n_2` <a href="https://interviewquestions.tuteehub.com/tag/respectively-1186938" style="font-weight:bold;" target="_blank" title="Click to know more about RESPECTIVELY">RESPECTIVELY</a>. According to the <a href="https://interviewquestions.tuteehub.com/tag/ideal-1035490" style="font-weight:bold;" target="_blank" title="Click to know more about IDEAL">IDEAL</a> gas equation, <br/> `PV =n_1 RT_1 = n_1 xx R xx (273+27)` <br/> (before heating ) ...(i) <br/> and `PV =n_2 RT_2 = n_2 xx R xx (273+477)` <br/> (after heating) ...(ii) <br/> Dividing eq. (i) by (ii), we have<br/> `1 = (n_1 xx 300)/(n_2 xx 750)` <br/> `:."" n_2 = 300/750 xx n_1 = 2/5 n_1` <br/> Hence, number of moles of air expelled on heating<br/> `=n_1 - n_2 =n_1 - 2/5 n_1 = 3/5 n_1` <br/> <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, the fraction of air expelled `=(3/5 n_1)/n_1=3/5`</body></html> | |
| 49280. |
A student forgot to add the reaction mixture to the round bottomed flask at 27^(@)C but instead he/she placed the flask on the flame. After a lapse of time, he realized his mistake, and using a pyrometer he found the temperature of the flask was 477^(@)C. What fraction of air would have been expelled out ? |
| Answer» <html><body><p></p>Solution :Here vessel is not changed hence the pressure remain <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> as atmoshperic pressure.<br/>Initial <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> `= <a href="https://interviewquestions.tuteehub.com/tag/27-298706" style="font-weight:bold;" target="_blank" title="Click to know more about 27">27</a>^(@)C = (27+273)=300 K=T_(1)`<br/>Let Initial volume of gas (Vessel) `= <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> dm^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>Tempe. at the end `= (477^(@)C+273^(@)C)=750 K = T_(2)`<br/>The volume of the gas in vessel `= V_(2)`<br/>As per Charle.s law `(V_(1))/(T_(1))=(V_(2))/(T_(2))`<br/>`therefore V_(2)=(V dm^(3)xx750K)/(300 K)=2.5V dm^(3)`<br/>The air expelled out `= (V_(2)-V_(1))=(2.5 V-V)dm^(3)`<br/>`= 1.5 V`<br/>Fraction of the air expelled out `(1.5V)/(2.5V)=(3)/(5)=0.6`</body></html> | |
| 49281. |
A student forgot to add the reaction mixture to the round bottomed flask at 27^(@)C but instead, he/she placed the flask on the flame. After a lapse of time, he realized his mistake, and using a pyrometer, he found the temperature of the flask was 477^(@)C. What fraction of air would have been expelled out ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Suppose <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of vessel =V `cm^(3)`,i.e.,volume of air in the flask at `<a href="https://interviewquestions.tuteehub.com/tag/27-298706" style="font-weight:bold;" target="_blank" title="Click to know more about 27">27</a>^(@)C=V cm^(3)`. <br/> `(V_(1))/(T_(1))=(V_(2))/(T_(2)),""i.e.,""(v)/(<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a>)=(V_(2))/(<a href="https://interviewquestions.tuteehub.com/tag/750-335306" style="font-weight:bold;" target="_blank" title="Click to know more about 750">750</a>)"or"V_(2)=2.5" V"` <br/> `:. """Volume expelled"=2.5" V"-V=1.5" V"` <br/> `:. """Fraction of air expelled" `=(1.5" V")/(2.5" V")=(3)/(5)`</body></html> | |
| 49282. |
A studend gets fingerprints on a cuvette before using it to determine the concentration of a coloured species using its known extinction coefficient. What is the effect on the absorbance and reported concentration ? |
| Answer» <html><body><p>`{:("<a href="https://interviewquestions.tuteehub.com/tag/absorbance-846164" style="font-weight:bold;" target="_blank" title="Click to know more about ABSORBANCE">ABSORBANCE</a>",,"Reported concentration"),("<a href="https://interviewquestions.tuteehub.com/tag/increased-1040402" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASED">INCREASED</a>",,"too <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a>"):}`<br/>`{:("Absorbance",,"Reported concentration"),("Increased",,"too high"):}`<br/>`{:("Absorbance",,"Reported concentration"),("<a href="https://interviewquestions.tuteehub.com/tag/decreased-7266469" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASED">DECREASED</a>",,"too low"):}`<br/>`{:("Absorbance",,"Reported concentration"),("decreased",,"too high"):}`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49283. |
A stronger hydrogen bonding is present in |
| Answer» <html><body><p>Ethanol<br/>Diethylether <br/><a href="https://interviewquestions.tuteehub.com/tag/ethylchloride-2621212" style="font-weight:bold;" target="_blank" title="Click to know more about ETHYLCHLORIDE">ETHYLCHLORIDE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/dimethylamine-439817" style="font-weight:bold;" target="_blank" title="Click to know more about DIMETHYLAMINE">DIMETHYLAMINE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 49284. |
A strong current of trivalent gaseous boron passed through a germanium crystaldecreases the density of the crystal due to part replacement of germanium by boron and due to interstital vacancies created by missing Ge atoms . In one such experiment , 1g of germanium is taken and the boron atoms are found to be 150 ppm by weight , when the density of the Ge crystal decreases by 4 % . calculate the percentage of missing vacancies due to germination , which are filled up by boron atoms . (Awof Ge = 72.6 and B = 11 ) (assume volume constant ) |
| Answer» <html><body><p>`23%`<br/>`2.3%`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/46-317673" style="font-weight:bold;" target="_blank" title="Click to know more about 46">46</a>%`<br/>`80%`</p>Solution :Assume here that the decrease in density is not <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to volume change but due to loss of Ge <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> only. Let x be the tota numberof Ge atoms missing and y be the number of B atoms <a href="https://interviewquestions.tuteehub.com/tag/replacing-2248205" style="font-weight:bold;" target="_blank" title="Click to know more about REPLACING">REPLACING</a> Ge atoms. Assuming the volumne of crystal reamining saem, than 4% decrease in density will also decrease weight of the crstal (sample) by 4%. <br/> `therefore 1-(x xx(72.<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)/(N_(A)))+(y xx(11)/(N_(A)))=0.96` <br/> `0.04=(x xx(72.6)/(N_(A)))-(y xx (11)/(N_(A)))` <br/> `y=((150N_(A))/(10^(6)xx11)xx0.96)` or `(yxx11)/(N_(A))=((150xx0.96)/(10^(6)))` <br/> `thereforex=((0.04+1.44xx10^(-4))N_(A))/(72.6)=(0.04N_(A))/(72.6)` <br/>`therefore(y)/(x)=(150N_(A)xx0.96xx72.6)/(10^(6)xx11xx0.04N_(A))=2.376xx10^(-2)` <br/> `therefore (y)/(x)xx100=2.376xx10^(-2)xx100=2.376%`</body></html> | |
| 49285. |
A strong argument in favour of the particle nature of cathode rays is that they |
| Answer» <html><body><p>produce fluorescence<br/>travel through vacuum<br/>can <a href="https://interviewquestions.tuteehub.com/tag/rotate-614912" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATE">ROTATE</a> a light paddle wheel <a href="https://interviewquestions.tuteehub.com/tag/placed-591674" style="font-weight:bold;" target="_blank" title="Click to know more about PLACED">PLACED</a> in their path<br/>cast shadow of the objects <a href="https://interviewquestions.tuteehub.com/tag/lying-1081801" style="font-weight:bold;" target="_blank" title="Click to know more about LYING">LYING</a> in their path</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49286. |
A strong argument for the particle nature of cathode rays is: |
| Answer» <html><body><p>they can <a href="https://interviewquestions.tuteehub.com/tag/propagate-592982" style="font-weight:bold;" target="_blank" title="Click to know more about PROPAGATE">PROPAGATE</a> in vacuum<br/>they <a href="https://interviewquestions.tuteehub.com/tag/produce-1167752" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCE">PRODUCE</a> fluorescene<br/>they cast shadoes<br/>they are deflected by <a href="https://interviewquestions.tuteehub.com/tag/electric-967871" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRIC">ELECTRIC</a> and <a href="https://interviewquestions.tuteehub.com/tag/magnetic-551115" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNETIC">MAGNETIC</a> fields</p>Answer :A</body></html> | |
| 49287. |
(A) Strength of acidic character of oxyacids lies in the following sequence: HClO_(4) gt HBrO_(4) gt HIO_(4) (R) Greater is the oxidation state of a halogen, more is the acidic character of its oxyacid. |
| Answer» <html><body><p>Both (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) and (A) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and reason is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of assertion.<br/>Both (R) and (A) are true but reason is not correct explanation of assertion<br/>Assertion (A) is true but reason (R) is false<br/>Assertion (A) and reason (R) both are false</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49288. |
A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference of V esu. If e and m are charge and mass of the electron respectively, then the value of h//lamda (where lamda is the wavelength associated with the electron wave) is given by |
| Answer» <html><body><p>`me V`<br/>`2 me V`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(me V)`<br/>`sqrt(2 meV)`</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/lamda-536483" style="font-weight:bold;" target="_blank" title="Click to know more about LAMDA">LAMDA</a> = (h)/(p) or (h)/(lamda) = p = <a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>` <br/> `KE = (1)/(2)mv^(2)` so that `v = sqrt((2KE)/(m)) " But " KE = eV` <br/> `:. v = sqrt((<a href="https://interviewquestions.tuteehub.com/tag/2ev-1837250" style="font-weight:bold;" target="_blank" title="Click to know more about 2EV">2EV</a>)/(m)) :. (h)/(lamda) = mv = m sqrt((2eV)/(m)) = sqrt(2meV)`</body></html> | |
| 49289. |
A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference V esu. If e and m are charge and mass of an electron, respectively, then the value of h//lambda (where lambda is wavelength associated with electron wave) is given by |
| Answer» <html><body><p>`sqrt(2meV)`<br/>meV<br/>2meV<br/>`sqrt(meV)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :K.E of an electron`rarr` <a href="https://interviewquestions.tuteehub.com/tag/charge-914384" style="font-weight:bold;" target="_blank" title="Click to know more about CHARGE">CHARGE</a> x <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> <br/> `rarr e <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> v` <br/> `therefore lambda=(h)/sqrt(2xxK>Exxm)` <br/> `(h)/(lambda)=sqrt(2eVm)`</body></html> | |
| 49290. |
A straight glass tube has two inlets X and Y at the two ends. The length of the tube is 200 cm. HCl gas through inlet X and NH_3gas through inlet Y are allowed to enter the tube at the same time. White fumes first appear at a point Pinside the tube. Find the distance of P from X. |
| Answer» <html><body><p></p>Solution :This <a href="https://interviewquestions.tuteehub.com/tag/problem-25530" style="font-weight:bold;" target="_blank" title="Click to know more about PROBLEM">PROBLEM</a> can easily be understood with the help of the following figure. <br/> White fumes appear at point P due to the formation of `NH_4Cl`according to the equation <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/NTN_HCS_ISC_CHE_XI_P1_C05_SLV_032_S01.png" width="80%"/> <br/> `NH_3 (g) + HCl(g) to NH_4 CI(g)` <br/>At point P, HCl gas and `NH_3` gas meet together and react to form fumes of `NH_4 <a href="https://interviewquestions.tuteehub.com/tag/cl-408888" style="font-weight:bold;" target="_blank" title="Click to know more about CL">CL</a>`. <a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a> the distance of point P from the inlet X is x cm.<br/> `:.`The distance travelled by HCl gas = x cm and, the distance travelled by `NH_3 " gas " = (200 - x) cm`. The time <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> by HCl gas to reach point P will be the same as the time taken by `NH_3` to reach point P. Let this time be equal to t.<br/> Rate of diffusion of HCl gas <br/> `(r_1) = (" distance travelled ")/("time") =X/t` <br/>Rate of diffusion of `NH_3 " gas " (r_2) (200-x)/t`<br/><a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> mass of `HCl (M_1) = 36.5` <br/> Molecular mass of `NH_3 (M_2) = 17` <br/>According to Graham.s law of diffusion, <br/>`r_1/r_1 =sqrt(M_2/M_1)` <br/> `:.(x//t)/((200 - x)//t)= sqrt(17/(36.5))` <br/> or `x/(200-x) = 0.6825 " or " x = 81.13 cm`<br/>Hence, white fumes appear at a distance of 81.13 cm from the inlet X.</body></html> | |
| 49291. |
A steel sample is to be analysed fo rCr and Mn simultaneously. By suitable treatment the Cr is oxidised to Cr_(2)O_(7)^(2-) andthe Mn to MnO_(4)^(-) . A 10.00g sample of steel is used to produce250.0mL of a solution containing Cr_(2)O_(7)^(2-) and MnO_(4)^(-) (a) A 10.00mL portion of this solution is added to a BaCl_(2) solutionand by proper adjument of theacidity, the chromimum is completeleyprecipitated as 0.0549g BaCrO_(4). (b) A second 10.00mL portion of this soltuion requires exactily 15.95mL of 0.0750M standard Fe^(2+) solution for its titaration(in acid solution). Calculatethe % of Cr in the steel sample. (Cr = 52, Mn = 55, Ba = 137) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`%` of `<a href="https://interviewquestions.tuteehub.com/tag/cr-427229" style="font-weight:bold;" target="_blank" title="Click to know more about CR">CR</a> = 2.821%` of `<a href="https://interviewquestions.tuteehub.com/tag/mn-548487" style="font-weight:bold;" target="_blank" title="Click to know more about MN">MN</a> = 1.496%`</body></html> | |
| 49292. |
A steel sample is to be analysed fo rCr and Mn simultaneously. By suitable treatment the Cr is oxidised to Cr_(2)O_(7)^(2-) andthe Mn to MnO_(4)^(-) . A 10.00g sample of steel is used to produce250.0mL of a solution containingCr_(2)O_(7)^(2-) and MnO_(4)^(-).10 mL of this solution is added to BaCl_(2) solution and by prooper adjumentof the pH, the chromium is completely precipitate as BaCrO_(4) (0.0549g). The second 10 mL solution protion requires exactly 15.95 mL of 0.0750 M standardfor complete reduction of this solution. Calculate %ofMn and Cr in this sample. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/cr-427229" style="font-weight:bold;" target="_blank" title="Click to know more about CR">CR</a> = 2.823%, <a href="https://interviewquestions.tuteehub.com/tag/mn-548487" style="font-weight:bold;" target="_blank" title="Click to know more about MN">MN</a> = 3.29%`</body></html> | |
| 49293. |
A steel cylinder of 8 litres capacity contain hydrogen gas at 12atm pressure. At the same temperature how many cycle tubes of 4 litres capacity at 2 atm can be filled up with this gas. |
| Answer» <html><body><p>12<br/>48<br/>5<br/><a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a></p>Solution :`N_b = (P_CV_C - P_bV_C)/(P_b V_b) = (12 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> - 2 xx 8)/(4 xx 2) = 10` .</body></html> | |
| 49294. |
A steel box is 2.5 m in length, 1.8 m in breadth and 1.2 m in height. Find its volume in litres. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of the box is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> by Volume = length x breadth x height `= 2.5 m xx <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.8 m xx 1.2 m = 5.4 m^3` <br/>1 <a href="https://interviewquestions.tuteehub.com/tag/litre-1075864" style="font-weight:bold;" target="_blank" title="Click to know more about LITRE">LITRE</a> (L) = `<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3) m^3` <br/>`1 m^3 = 10^3` L Hence, the conversion factor would be: <br/> `1=(10^(3) L)/(1 m^(3))` <br/> Volume of box `=5.4 m^(3) xx 1 = 5.4 m^(3) xx (10^(3) L)/(1 m^(3))` <br/> `=5.4 xx 10^(3) L`</body></html> | |
| 49295. |
A state of equilibrium is reached when |
| Answer» <html><body><p>The rate of <a href="https://interviewquestions.tuteehub.com/tag/forward-464460" style="font-weight:bold;" target="_blank" title="Click to know more about FORWARD">FORWARD</a> reaction is <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than the rate of the reverse reaction <br/>The concentration of the products and reactants are <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> <br/>More product is <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> than reactant <br/>The concentration of the products and reactants have reached constant value </p>Answer :D</body></html> | |
| 49296. |
(a) State Mendeleev's periodic law. (b) Describe about the merits of Mendeleev's periodic table. |
| Answer» <html><body><p></p>Solution :(a) Mendeleev.s periodic law:<br/>Mendeleev.s periodic law states that the physical and chemical properties of <a href="https://interviewquestions.tuteehub.com/tag/elements-969381" style="font-weight:bold;" target="_blank" title="Click to know more about ELEMENTS">ELEMENTS</a> are a periodic function of their atomic weights. <br/> (b) Merits of Mendeleev.s periodic table: <br/>(i) The <a href="https://interviewquestions.tuteehub.com/tag/comparative-423427" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARATIVE">COMPARATIVE</a> studies of elements were made easier. <br/>(ii) The table shows the relationship in properties of elements in a <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a>. <br/>(iii) The table <a href="https://interviewquestions.tuteehub.com/tag/helped-7270941" style="font-weight:bold;" target="_blank" title="Click to know more about HELPED">HELPED</a> to correct the atomic masses of some elements later on. At the time on Mendeleev, the atomic weight of Au and Pt were known as 196.2 and 196.7 respectively. However, Mendeleev placed Au (196.2) after Pt (196.7) saying that atomic weight of A is incorrect, which was later on found to be 197. <br/>(<a href="https://interviewquestions.tuteehub.com/tag/iv-501699" style="font-weight:bold;" target="_blank" title="Click to know more about IV">IV</a>) At the time of Mendeleev, about 70 elements were known and thus blank spaces we for unknown elements which helped further discoveries. <br/>Both Gallium (Ga) in III group and Germanium (Ge) in IV group. were unknown at that time by Mendeleev predicted their existence and properties. He referred the predicted elements as eka-aluminium and eka-silicon. After discovery of the actual elements, their properties were found to match closely to those predicted by Mendeleev.</body></html> | |
| 49297. |
(a) State Heisenbergs uncertainty principle. Give its mathematical expression. Also give its significance. (b) Calculate the uncertainity in the position of a dust particle with mass equal to 1 mg if the uncertainity in its velocity is 5.5 xx 10^(-20) ms^(-1) . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`9.55xx10^(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>) m`</body></html> | |
| 49298. |
(a) Statede Broglie equation .Write its significance . (b) A beam of helium atoms moves with a velocityof2.0 xx 10^(3) ms^(-1) . Find the wavelength of the particle constitutingthe beam . (h=6.626 xx 10^(-34) Js ) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :49.9</body></html> | |
| 49299. |
A standing wave in a string 35 cm long has a total of six nodes including those at the ends. Hence, wavelength of the standing wave is |
| Answer» <html><body><p>5.8 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a><br/>4.6 cm<br/>10.4 cm<br/><a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a> cm</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_01_XI_C02_E19_007_S01.png" width="80%"/> <br/>`2.5 <a href="https://interviewquestions.tuteehub.com/tag/lamda-536483" style="font-weight:bold;" target="_blank" title="Click to know more about LAMDA">LAMDA</a> = <a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a> cm or lamda = (35)/(2.5) = 14 cm`</body></html> | |
| 49300. |
A Standard hydrogen electrode has zero electrode potential beacause |
| Answer» <html><body><p>hydrogen is easiest to <a href="https://interviewquestions.tuteehub.com/tag/oxidise-1144503" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDISE">OXIDISE</a> <br/>the electrode <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> is assuemed to be zero <br/>hydrogen <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> has only <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> electron <br/>hydrogen is the lightest <a href="https://interviewquestions.tuteehub.com/tag/element-969236" style="font-weight:bold;" target="_blank" title="Click to know more about ELEMENT">ELEMENT</a> </p>Solution :Conceptual question</body></html> | |