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90351.

A compound 'X' (C_(14)H_(14)O) on mild oxidation yields C_(14)H_(12)(Y). If X is treated with a dehydratingg agent, it loses a molecule of H_(2)O and resulting product on vigoporus oxidation yields two molecule of benzoic acid. Identify the structure of X and Y.

Answer»


X is `PH-overset(OH)overset(|)(CH)-CH_(2)-Ph`
y is `Ph-overset(O)overset(||)(C )-CH_(2)_Ph`

ANSWER :B,C,D
Discussion
90352.

A compound with nitro group was reduced by Sn//HCl, followed by treatment with NaNO_(2)//HCl and followed by phenol. The chromophore group in the compound is

Answer»

`NO_(2)` GROUP
`NH_(2)` group
azo group
OH group

Solution :
Discussion
90353.

A compound with nitro group was reduced by Sn//HCl, followed by treatment with NaNO_(2)//HCl and followed by phenol. The chromophore group in the final compound is

Answer»

`NO_(2)` GROUP
`NH_(2)` group
Azo group
OH group

Answer :C
Discussion
90354.

A compound with molecular mass 180 is acylated with CH_(3)COCl to get a compound with molecular mass 390. the number of amio groups present per molecule of the former compound is

Answer»

6
2
5
4

Solution :During ACETYLATION, ONE H atom (at mass=1amu) of the `NH_(2)` group is REPLACED by an acetyl group, i.e.., `CH_(3)CO` (mol. Mass=43amu).
`-NH_(2)+CH_(3)COCl to -NHCOCH_(3)+HCl`
In other words, acetylation of each `NH_(2)` group increases the mass by 43-1=42 amu. now since the mol. mass of the organic COMPOUND is 180 while that of the acetylated product is 390, therefore, increase in the mass DUE to acetylation=390-180=210amu.
`therefore`No. of `-NH_(2)` groups`=(210)/(42)=5`
Discussion
90355.

A compound with molecular mass 180 is acylated with CH_(3)COCl to get a compound with molecular mass 390. the number of amino groups present per molecules of the former compounds is

Answer»

2
5
4
6

Answer :B
Discussion
90356.

A compound with molecular mass 180 is acylated with CH_(3)COCl to get a compound with molecular mass 390. the number of amino groups present per molecule of the former compound is

Answer»

2
5
4
6

Solution :By reaction with one mole of `CH_(3)-OVERSET(O)overset(||)(C)-Cl` with one `-NH_(2)` group the MOLECULAR mass increases with 42 unit. SINCE the mass increases by `(190-180)=210`, hence the no. of `NH_(2)` groups are 5.
Discussion
90357.

A compound with molecular mass 180 is acylated with CH_3COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is :

Answer»

2
5
4
6

Solution :`R* ubrace(NH_2)_"Mol.Mass . 16" * CH_3 * oversetOoverset"||"C*Cl* *underset(HCl)* * ubrace(R * NH* oversetOoverset"||"C.CH_3)_"Mol mass . 58"`
Now since the molecular mass increases by 42 unit as a result of the reaction of ONE MOLE of `CH_3COCl` with one- `NH_2` GROUP and the given increase in mass is 210. Hence the number of-`NH_2`groups is= 210/42 = 5.
Discussion
90358.

A compound with molecular mass 180 is acylated with CH_(3)COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is :

Answer»

6
2
5
4

Answer :C
Discussion
90359.

A compoundwith molecular mass 162is acylated withCH_3COClto get a compoundwith molecular mass 456 The number of aminogroupspresenter molecule of the formercompoundsis :

Answer»


ANSWER :7
Discussion
90360.

A compound with molecular formula C_(8)H_(18)O_(4) does not give litmus test and does not give coloue with 2,4-DNP. Ir reacts with excess MeCOCL to give a compound whose vapour density is 131. Compound A contains how many hydroxy groups?

Answer»


ANSWER :2
Discussion
90361.

A compound with molecular formula C_(6)H_(14)O_(4) does not give litmus test and does not give colour with 2,4-DNP. It reacts with excess MeCOCl to give a compound whose vapour density is 117. CompoundA contains how many hydroxy groups?

Answer»


ANSWER :2
Discussion
90362.

A compound with molecular formula C_(5)H_(10)O reduces Tollens' reagent but does not undergo aldol condensation. Can it undergo cannizzaro reaction? If yes, then write the products of this reaction.

Answer»

Solution :Since compound with `MFC_(5)H_(10)O` REDUCES tollen's reagent but does not undergo aldol CONDENSATION, it must be an aldehyde with no `alpha`-hydrogens, i.e., it is 2,2-dimethylpropanal. Further, since the aldehyde, 2,2-dimethylpropanal does not contain `alpha`-hydrogens, it undergoes Cannizzaro reaction. for PRODUCTS of the reaction.
Discussion
90363.

A compound with molecular formula C_(7)H_(16) shows optical isomerism, the compound will be:

Answer»

2,3-dimethylpentane
2,2-dimethylpentane
2-methylhexane
none of the above.

Answer :A
Discussion
90364.

A compound with molecular formula C_4H_6 may contain:

Answer»

A DOUBLE bond
Two TRIPLE bond
All SINGLE BONDS
Two double bonds or a triple bond

Answer :C
Discussion
90365.

A compound with molecular formula, C_(4)H_(10)O_(3) on acetylation with acetic anhydride gives a compound with molecular weight 190. find out the number of hydroxyl grouops present in the compound.

Answer»

Solution :During acetylation, one H-atom (at. Mass=1amu) of the OH group is repalced by an acetyl group i.e., `CH_(3)CO` (mo mass=43amu).
`-OH+(CH_(3)CO)_(2)Oto-O-COCH_(3)+CH_(3)COOH`
in other WORDS, acetylation of each OH group increases the mass by 43-1=42 amu. now the mol. mass of `C_(4)H_(10)O_(3)=106` amu while that of the acetylated PRODUCT is 190 amu, therefore, the NUMBER of OH groups in the compound `=(190-106)/(42)=2`
Discussion
90366.

A compound with molecular formula C_4H_(10)O_3 is converted by the action of acetyl chloride to a compound with molecular weight 190. The original compount has :

Answer»

OneOH group
Two OH groups
Three OH groups
No OH group

Answer :B
Discussion
90367.

A compound with molar mass 180 is acylated with CH_(3) COCl to geta compound withmolar mass 390. Thenumber of aminogrouppresent per molecule of the formercompound is

Answer»

2
5
4
6

Answer :B
Discussion
90368.

A compound with mlecular mass 180 is acylated with CH_(3)COCl to get a compound with molecular mass 390. The number of amino group present per molecule of the former compound is

Answer»

6
2
5
4

Solution :In acetylation, one H-atom (at mass = 1 amu) of `NH_(2)` group is REPLACED by an acetyl group, i.e., `CH_(3)CO` (mol mass = 43 amu)
`-NH_(2)+CH_(3)COCl RARR NHCOCH_(3)+HCl`
It mean acetylation of each `NH_(2)` group increases the mass by 43-1=42 amu
Since the mol.mass of ORGANIC compound is 180 while that of the acetylated product is 390
`:.` increase in the mass DUE to acetylation `=390-180=210` amu
`:.` number of `NH_(2)=210//42 =5`
Discussion
90369.

A compound whose aqueous solution will have the highest pH

Answer»

NACL
`Na_(2)CO_(3)`
`NH_(4)Cl`
`NaHCO_(3)`

SOLUTION :`Na_(2)CO_(3)` when react with water form strong BASE and WEAK acid. So its aqueous solution is basic.
Discussion
90370.

A compound which on reaction with aqueous nitrous acid gives an oilly nitrosoamine is :

Answer»

Methylamine
Ethylamine
Diethylamine
Triethylamine

Answer :C
Discussion
90371.

A compound which leaves behind no residue on heating is

Answer»

`KNO_(3)`
`Cu(NO_(3))_(2)`
`NH_(4)NO_(3)`
NONE of the above

Answer :C
Discussion
90372.

A compound which leaves behind no residue on heating is :

Answer»

`CU(NO_3)_2`
`KNO_3`
`NH_4NO_3`
NONE of these

Answer :C
Discussion
90373.

A compound which does not give iodoform test on treatment with alkale and iodine is

Answer»

Ethanol
Acetone
Diethylketone
Isopropyl alcohol.

Solution :`CH_(3)CH_(2)COCH_(2)CH_(3)` is not a methyl KETONE while the rest are either methyl KETONES or form the same UPON oxidation in the REACTION.
Discussion
90374.

A compound which does not give a positive test in the Lassaigne's test for N is :

Answer»

Hydrazine
Phenyl hydrazine
Urea
Azobenzene

Answer :D
Discussion
90375.

A compound which does not give a positive test in Lassaigne's test for nitrogen is :

Answer»

urea
hydrazine
azobenzene
phenyl hydrazine

Solution :`NH_(2)-NH_(2)` (INORGANIC COMPOUND give -ve Lassigne's TEST)
Discussion
90376.

A compound which contains both ……….. And …………..is called amino acid. The amino acids in polypeptide chain arejoined by …………bonds.

Answer»

amino, carboxylic , group , ESTER
amino, carboxylic group, PEPTIDE.
NITROGEN , carbon , GLYCOSIDIC
hydroxy, carboxylic group, peptide.

Answer :B
Discussion
90377.

A compound was found to contain nitrogen and oxygen in the ratio nitrogen 28g and oxygen 80 g. the formula of the compound is:

Answer»

NO
`N_(2)O_(3)`
`N_(2)O_(5)`
`N_(2)O_(4)`

Answer :C
Discussion
90378.

A compound which catalyses a chemical reaction in a living organism is called a (n) :

Answer»

Carbohydrate
Enzyme
Lipid
Vitamin

ANSWER :B
Discussion
90379.

A compound was found of contain 14.34% oxygen. The minimum molecular weight of the compound is

Answer»

111.5 g
223.15 g
97.62 g
195.26 g

Answer :A
Discussion
90380.

A compound was dissolved in water at 27^@C. It is found that the vapour pressure lowering at 27^@Cis 0.72 mm. If the vapour pressure of water at 27^@C is 26.74 mm, calculate the osmotic pressure of the solution.

Answer»

SOLUTION :0.028 ATM
Discussion
90381.

A compound used in the metallurgy of aluminium to remove impruities is

Answer»

FLUX
BASIC flux
ACIDIC flux
Slag

Answer :B
Discussion
90382.

A compound undergoes the following sequence of reactions: C_(3)H_(5)N overset("Hydrolysis")to underset((A))(C_(3)H_(6)O_(2)) overset(Cl_(2)//P)to underset((B))(C_(3)H_(5)O_(2)Cl) overset(NH_(3))to underset((C))(C_(3)H_(7)NO_(2)) The compound C is

Answer»

1-nitropropane
2-nitropropane
2-aminopropanoic acid
2-hydroxypropanamide.

Solution :`UNDERSET("Acetonitrile "(C_(3)H_(5)N))(CH_(3)CH_(2)CN) OVERSET("Hydrolysis")to underset(C_(3)H_(6)O_(2)(A))(CH_(3)CH_(2)COOH) overset(Cl_(2)//P)to underset(C_(3)H_(5)O_(2)Cl(B))(CH_(3)CHClCOOH) overset(NH_(3))to underset("2-Aminopropanoic acid (C) "(C_(3)H_(7)NO_(2)))(CH_(3)-CHNH_(2)-COOH)`
Discussion
90383.

A compound undergoes the following sequence of reactions: C_(3)H_(5)Noverset("Hydrolysis")tounderset((A))(C_(3)H_(6)O_(2))overset(Cl_(2)//p)tounderset((B))(C_(3)H_(5)O_(2)Cl)overset(NH_(3))tounderset((C))(C_(3)H_(7)NO_(2)) The compound (C) is:

Answer»

1-nitropropane
2-aminopropionic acid
2-nitropropane
2-hydroxypropanamide

Answer :B
Discussion
90384.

A compound used as pistachio flavour in ice cream is ……….

Answer»

vanillin
ACETOPHENONE
muscone
butyraldehyde

Solution :acetophenone
Discussion
90385.

A compound that will react most readily with NaOH to form methanol is

Answer»

`(CH_(3))_(4)N^(+)I^(-)`
`CH_(3)OCH_(3)`
`(CH_(3))_(3)S overset(+)(I)^(-)`
`(CH_(3))_(3)C Cl`.

Solution :Due to greater electronegativity of N over S, +ve CHARGE on N will make `CH_(3)` group more electron dificient than + charge on S. HENCE `(CH_(3))_(4)NI^(+)` will UNDERGO nucleophilic substitution reaction more readily than `(CH_(3))_(3)S^(+)I^(-)`
Discussion
90386.

A compound that gives a positive iodoform test is:

Answer»

a.1- Pentanol
b.3-Pentanone
c.2- Pentanal
d.

Solution :
(It CONTAINS `(Me-CO-)` GROUP and GIVES positive iodoform test.)
Discussion
90387.

A compound that gives positive iodoform test Is :

Answer»

Pentan-1-ol
Pentan-2-one
Pentan-3-one
Pentanal

Answer :B
Discussion
90388.

A compound that undergoes bromination easily is

Answer»

toluene
benzoic acid
phenol
benzene

Solution :`PhCH_(3),PhCOOH,PhOH,PhH`.
Among the given compounds, `PhCH_(3) and PhOH` have activating groups, `-OH and -CH_(3),-OH` has a strong +R EFFECT and `CH_(3)` has +I effect and hyperconjugative effect, +R effect being stronger than the +I and hyperconjugative effect, PhOH will undergo the REACTION more readily than `PhCH_(3)`. Again PhCOOH have DEACTIVATING group. PhH has neither a deactivating nor an activating group, so it will be more REACTIVE than the compounds with deactivating groups.
Discussion
90389.

A compound that easily undergoes bromination is

Answer»

Phenol
Toluence
Benzene
Benzoic acid

Solution :Compound that undergoes bromination easily is PHENO. DUE to presence of -OH group the ring BECOMES MUCH more active in substitution rections. The bromination occurs due to availability of electrons on ORTHO and para position.
Discussion
90390.

A compound that easily undergoes bromination is …………………….. .

Answer»

PHENOL
Toluene
benzene
DIETHYL ETHER

SOLUTION :Phenol
Discussion
90391.

A compound reduces Tollen's reagent but does not reduce Fehling's or Benedict solution. It is

Answer»

Glucose
Benzaldehyde
Acetophenone
Acetaldehyde

Answer :B
Discussion
90392.

A compound reacts with sodium and liberates hydrogen and on oxidation gives ketone. The formula of the compound could be

Answer»

`CH_(3)CH_(2)OH`
`CH_(3)CHOHCH_(3)`
`CH_(3)CH_(2)CH_(2)OH`
`CH_(3)CH_(2)CH_(2)CH_(2)OH`

ANSWER :B
Discussion
90393.

A compound P(C_(7)H_(8)O) is insouble in water, dilute HCl, NaHCO_(3) but dissolve in dilute NaOH. When P is treated with bromine water, it is converted into a compound of formula C_(7)H_(7)Obr. Compound P is:

Answer»




ANSWER :C
Discussion
90394.

A compound P(C_(5)H_(6)) gives positive Bayer test and on hydrogentation from a hydrocarbon B(C_(5)H_(10)) which gives only monochloro product. The compound 'P' is.

Answer»




SOLUTION :Due tounsaturation PINK colour of BAEYER's REAGENT DECOLOURISES
Discussion
90395.

A compound (P) having molecular formula C_(6)H_(10) contains two DU. Ityields Q(C_(6)H_(12)) when reacts with excess of H_(2) of the presence of Ni. On ozonolysis P gives cyclopentanone and compound Y. The compound Q gives the number of of monochlorination products

Answer»

`3`
`4`
`5`
`6`

SOLUTION :
Discussion
90396.

A compound (P), obtained as an ozonolysis product of (Q) gives brisk effervescence with Na, violet coloration with neutral FeCl_(3) and silver mirror with Tollen's reagent (Q) may be :

Answer»




All of these

Solution :N//A
Discussion
90397.

A compound (P) having molecular formula C_(6)H_(10) contains two DU. Ityields Q(C_(6)H_(12)) when reacts with excess of H_(2) of the presence of Ni. On ozonolysis P gives cyclopentanone and compound Y. Which of the following is not functional group isomer of cyclopentanone.

Answer»




SOLUTION :
Discussion
90398.

A compound (P) having molecular formula C_(6)H_(10) contains two DU. Ityields Q(C_(6)H_(12)) when reacts with excess of H_(2) of the presence of Ni. On ozonolysis P gives cyclopentanone and compound Y. Identify the structure of the compound P

Answer»




SOLUTION :
Discussion
90399.

A compound on treatment with 50% aueous NaOH gives furoic acid and furfuryl alcohol . What is the structure of the parent compound ?

Answer»




Solution :Functional GROUP lies in the SIDE chain ALCOHOL hence it is named as DERIVATIVE of ETHANONE.

(Cyclohexa-2, 4-diemyl) ethanone)
Discussion
90400.

A compound on anayalysis , was found to have the following composition. (i) Sodium=14.31%. (ii) Sulphur =9.97% (iii) Oxygen=69.50%, (iv) Hydrogen =6.22%. Calcualte the molecular formula of the compound assuming that whole of hydrogen in the compound is present as water of crystallisation Molecualr mass of the compound is 322.

Answer»

Solution :
The empirical formula`=Na_(2)SH_(20)O_(14)`
Empirical formula MASS `=(2xx23)+32+(20xx1)+(14xx16)`
=322
Molecular mass=`Na_(2)SH_(20)O_(14)`
Whole of the hydrogen is present in the FORM of WATER. Thus, 10 water molecules are present in the molecule.
So, molecular formula `=Na_(2)SO_(4).10H_(2)O`.
Discussion