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6001.

ProblemThe coagulation of 100 mL of a colloidal sol of gold is completely prevented by additionof 0.25 g of starch to it before adding 10 mL of 10% NaCl solution. Find out the gold number of starch.

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thanks

6002.

away.Arrange the following substances in increasing order of forceof attraction between the particles, water, sugar, oxygen.What is the physical state of water at-(b) 0°C(c) 100°C ?(a) 25°C

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6003.

roblem 1.6solution is prepared by adding 2 gubstance A to 18 g of water. Calcuhe mass per cent of the solute.olution

Answer»

The amount of solute is = 2g

and amount of solvent = 18g

so, % (w/w) solute = 2*100/(18+2) = 10%

thanks to u

6004.

Q.18. a) Calculate the molecular mass of the following substances:-(i) C2 H2 (Ethylene)(ii) Hcl

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(1)Molar mass of ethyne, C2H2 = Mass of C × 2 + Mass of H × 2

= 12 × 2 + 1 × 2

= 24 + 2

= 26 g / mol

(2)

Molar mass of hydrochloric acid, HCl = Mass of H + Mass of Cl

= 1 + 35.5

= 36. 5 g/ mol

6005.

Q.18. a) Calculate the molecular mass of the following su(1) C2 H2 (Ethylene) 26(ii) Hcl 36.5

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I)C2H2-26.04g/molii)HCL-36.46g/mol

6006.

EXplain ihe nybridization invoivedinmolecti12. Explain the structure of ethylene( C,H,) and acetylene( C,H,)2/74) and acetylen

Answer»

Ethylene has a double bond between the carbon atoms and four hydrogens.

Structure:

H2-C=C-H2

Acetylene also known as ethyne (note -yne suffix) has a triple bond between the carbons and two hydrogens.

Structure:

H-C≡C-H

6007.

How does vulcanization change the characteristics of natural rubber?

Answer»

Vulcanizationorvulcanisationis a chemical process for convertingrubberor related polymers into more durable materials via the addition of sulfur or other equivalent "curatives." These additivesmodifythe polymer by forming crosslinks (bridges) between individual polymer chains.

6008.

State one function of the following.(a) cell membrane(b) mitochondria

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a) The mainfunctionsof thecell wallare to provide structure, support, and protection for thecell. Thecell wallin plants is composed mainly of cellulose and contains three layers in many plants.

b)The membrane is where the chemical reactions occur and the matrix is where the fluid is held. Mitochondria are a part of eukaryotic cells. The main job of mitochondria is to perform cellular respiration. This means it takes in nutrients from the cell, breaks it down, and turns it into energy.

6009.

What are the essential qualities of drinking Water

Answer»

Cleaned of Harmful Contaminants. Including chlorine, fluoride, pharmaceutical drugs, metals (mercury, bromide, lead,arsenic), chemicals,bacteriaand more.

Replenished with Natural Minerals. ...

Alkaline pH Balanced– ...

Great Natural Spring WaterTaste.

6010.

odaWhy is potassium permanganateused for purifying drinking water?(a) It kills germs(b) It dissolves the impurities(c) It is a reducting agent(d) It is an oxidising agent

Answer»

The answer is option d.

Potassium permanganateis a point-of-entry treatment method that oxidizes dissolved iron, manganese, and hydrogen sulfide into solid particles that are filtered out of thewater. It can also beusedto control iron bacteria growth in wells.

6011.

HEMICAL KINETICS55.KJ/mole. Calculate the activation eneray of trsA) 106 kd/molA large increnses in the roact(A) inoroaso in the number of collisions(C) Lowering of activation enerayWhat is the slope of the straight line tf a reacting at temperature T?rato of reaction 1or arise in temperaturo is de to(EIrnvereaso in the number ct aeiD) Shonering ct themean tree pei7.ae for the graph arawn between in v and it,thore me rasa coabastA)2.303R(A) 40 kj mol-1RATE LAW AND MECHANISMAs already mentioned in the reaction:(B) Ea,then E.of BA vill bemol-1, E-50 k) mol(B) 50 kj mol-1(C-50 kmo

Answer»

7. slope is -Ea/R..... option B

because graph is in between lnk and 1/T

6012.

c)Expand AIDS and write its causal organisms?

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AIDS orAcquired Immunodeficiency Syndromeis a communicable disease caused by HIV OR Human Immunodeficiency virus.It is transferred through sexual contact. Actually it is weakening of one's immune system which makes the victim more prone to disases.

Viruses are generally considered to be infectious agents rather than true living organisms. The aetiological agent for AIDS is the HIV(human immunodeficiency virus), a lentivirus.

6013.

How is high density polymer (HDPE) prepared?

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HDPE is made under controlled conditions by applying intense heat to petroleum. This process, also known as “cracking,” helps create ethylene gas. During its production, the gas molecules will attach to form polymers, which then produce polyethylene.

After this process, the polyethylene will have a sludgy appearance, but after it’s put through a series of molds, it forms into granules. Once the molding process is complete, you’ll have a strong polymer material.

High-density polyethylene. HDPE is manufactured at low temperatures and pressures, using Ziegler-Natta and metallocene catalysts or activated chromium oxide (known as a Phillips catalyst). ... The plastic recycling code number of HDPE is #2. The linear form of polyethylene, known as high-density polyethylene (HDPE).

High-densitypolyethylene(HDPE) orpolyethylene high-density(PEHD) is athermoplasticpolymerproduced from the monomerethylene. It is sometimes called "alkathene" or "polythene" when used forHDPE pipes.[1]With a high strength-to-density ratio, HDPE is used in the production ofplastic bottles, corrosion-resistant piping,geomembranesandplastic lumber. HDPE is commonly recycled, and has the number "2" as itsresin identification code.

In 2007, the global HDPE market reached a volume of more than 30 million tons.[2]

6014.

4. State and explain Gay Lussac's law of combinningvolumes.

Answer»

The law of combining volumes states that, when gases react together to form other gases, and when all volumes are measured at the same temperature and pressure

The ratio between the volumes of the reactant gases and the gaseous products can be expressed in simplewhole numbers.

For example, Gay-Lussac found that 2 volumes of hydrogen and 1 volume of oxygen would react to form 2 volumes of gaseous water. Based on Gay-Lussac's results,Amedeo Avogadrotheorized that, at the same temperature and pressure, equal volumes of gas contain equal numbers of molecules (Avogadro's law). This hypothesis meant that the previously stated result

2 volumes of hydrogen + 1 volume of oxygen = 2 volumes of gaseous water

could also be expressed as

2 molecules of hydrogen + 1 molecule of oxygen = 2 molecules of water.

how u find ans

6015.

State and explain Gay Lussac's law.

Answer»

Amonton'slaw statesthat the pressure of a certain mass and volume of a gas is directly proportional to its absolute temperature. ...Gay-Lussacis sometimes credited as being the first tostateDalton'slaw, which says that the total pressure of a gas is the sum of the partial pressures of individual gases.

Gay-Lussac's law is anideal gas lawwhere at constantvolume, thepressureof anideal gasis directly proportional to itsabsolute temperature(Kelvin). The formula for the law may be stated as:

Pi/Ti= Pf/Tf

wherePi= initial pressureTi= initial temperaturePf= final pressureTf= final temperature

6016.

50. Gay Lussac's law is not applicable for those gaseswhich on mixing(1) do not react(2) diffuse(3) rcact with cach othcr(4) al are wrong

Answer»

react with each other... option 3

because on reaction , the volume would not be same.

explain

6017.

-1250 %2B 380 %2B 690 %2B 450 %2B 360*570

Answer»

450+360*570+690+380-1250450+205200+690+380-1250205470

205200+450+690+380-1250 206720-1250 205470

6018.

2. Helium atom has an atorle asof 4 u and two protons in itsnucleus. How many neutronsdoes it have?

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Formula used: No. of Protons + No. of Neutrons = (No. of electrons) = Mass number.

Mass number of He = 4No.of Protons in He = 2

Using the formula, No. of Protons + No. of Neutrons = Mass number. No. of Neutrons = Mass number - No.of Protons No. of Neutrons =4-2 = 2

Therefore,No.of Neutrons in Helium atom = 2

6019.

68. Bromine particles are almost twice as heavy as chlorine particles. Which gas will diffuse faster ; bromine(vapour) or chlorine ? Explain your answer.

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In periodic table as we move top to bottom in group the size of atom increase gradually so due to increase in size of bromine the diffusion rate of bromine is lesser than the chlorine. The size of chlorine is lesser than the bromine.

6020.

/en the basis of Thomson's modelof an atom, explain how the atomis neutral as a whole.

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6021.

The heat of neutralization of strong base and strong acid is 570kj.The heat released when 0.5 mole of HNO3 solution is added to 0.20 mole of NaOH solution is-

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In the given reaction HNO3 reacts with NaOH in the ratio of 1mole:1mole.This implies that only 0.2 mol of the strong base and strong acid will react andwhich will lead to 0.2*57KJ of heat = 11.4KJ of heatbeing released.

6022.

The heat of neutralization of strong base and strong acid is 57.0 kJ. The heat released when 0.5mole of HNO3, solution is added to 0.20 mole of NaOH solution is-

Answer»

one mole of each can react so 0.3 mole of each can react

1 mole= -57.5KJ0.2mole= 57.5*0.2= -11.5KJ

6023.

What is high density polythene?

Answer»

High-density polyethylene or polyethylene high-density is a polyethylene thermoplastic made from petroleum. With a high strength-to-density ratio, HDPE is used in the production of plastic bottles, corrosion-resistant piping, geomembranes, and plastic lumber.

6024.

You have two solutions A and B. The pH ofsolution A is 6 and pH of solution B is 8.

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Solution "A" is acid . because the value is less than 7.

Solution "B" is Vase , because the value is greater than 7.

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6025.

8018, How is serap iron separated from a heap of waste materials in factories ?ucd ou il srane to separate scrap iron objects from a heap of

Answer»
6026.

B. Answer the following questions:1. Will Cps and Cl37 have different valencies? Justify your answer.

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No, 35CI and 37CI have the same valency. 35CI and 37CI are the isotopes. So, they have the same number of protons and electrons and have the same atomic number viz. 17 Hence, their electronic configuration and valencies are also the same K L MElectronic configuration = 2, 8, 7 Valency 8-7 = 1Therefore, both of them have valency = 1

6027.

Intext Qust0.2 Why is sulphuric acid not used during the reaction of alcohols with KI?

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6028.

A chemical compound having a strong smellof chlorine is used to disinfectwater:(a) Identify the compound(b) Write the chemical equation of its preparation.(c) Write its uses

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a)The said chemical compound is bleaching powder, chemically known as calcium oxychloride. It is represented by the chemical formula CaOCl2. b)It is produced by the action of chlorine on dry slaked lime. Following is the chemical equation for the reaction

Ca(OH)2+ Cl2→ CaOCl2+ H2O

c)Bleaching powder is used for bleaching cotton and linen in the textile industry, wood pulp in paper factories and washed clothes in laundries.like if you find it useful

6029.

What is Lanthanide Contraction? What is its cause and˝what are Atsconsequences ?Or

Answer»

Lanthanide Contraction:The steady decrease in the size of lanthanide ions (M3+) with the increase in atomic no. is called lanthanide contraction.Causes:As we move down the group from left to right in a lanthanide series, the atomic no. increases and for every proton in the nucleus the extra electron goes to 4f orbital. The 4f orbital is too diffused to shield the nucleus effectively, thus there is a gradual increase in the effective nuclear charge experienced by the outer electrons. Consequently , the attraction of the nucleus for the electrons in the outermost shell increases with the increase of atomic number, thus size decreases.Consequence of Lanthanide Contraction:Separation of Lanthanides:Due to the similar sizes of the lanthanides, it is difficult to separate them but due to lanthanide contraction their properties slightly vary (such as ability to form complexes). The variation in the properties is utilized to separate them.Basic Strength of Hydroxide:Due to the lanthanide contraction, size of M3+ions decreases and there is increase in covalent character in M–OH and hence basic character decreases.Similarity of second and third transition series:The atomic radii of second row transition elements are almost similar to those of the third row transition elements because the increase in size on moving down the group from second to third transition elements is cancelled by the decrease in size due to the lanthanide contraction

6030.

1 \\ hich one is lanthanoid?A. CmB. AmC. FmD. Pmकौन सा लैंथेनोइड है?

Answer»

Promethium(Pm) is a lanthanoid.Hence, option (d) is correct.

option (D) Pm is the right answer.

B)Am is correct answer

D) is correct answer

d) is the correct answer of the following

d is the correct answer of this question

6031.

Intext Question8.10 Actinoid contraction is greater from element to element thanlanthanoid contraction. Why?

Answer»

Actinoid contraction is greater from element to element than lanthanoid contraction. ... These 5f orbitals have a poorer shielding effectthan4f orbitals (inlanthanoids). Thus, the effective nuclear charge experienced by electrons in valence shells in case ofactinoidsis muchmorethatthanexperienced bylanthanoids.

6032.

QQuestionActinoid contraction is greater from element to element thlanthanoid contraction. Why?

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6033.

The correct order of melting points of the compounds given below is() NaCl < NaBr < Nal < NaFil Nal < NaBr < NaCl < NalF(üi) NaP < NaCl < NaBr <Nal(iv) NaCl < NaBr < NaP < Nal

Answer»

while going top to down in periodic table size of element is decrease so inter nuclear attraction also decrease

due to smaller size and higher electronegativity of flourine NaF will have the highest melting point as there is higher forces of attractiondown the group the force of attraction will decrease due to increase in size of anion this option b

6034.

15. In which of the following reaction, there is no changein oxidation number(a) So, + 2H, 2H,0 + 3S(b) 2Na + 02 - Na 202(c) Na2O + H2SO4- Na2SO4 + H2O(d) 4KCIO, 3KCIOA + KCI

Answer»

I think its... (c) .....

6035.

29. Rutherford's α particle scattering experiment eventually led to the conclusion thatA) neutrons are buried deep in the nuclcusB) the point of impact with matter can be precisely determinedC) electrons occupy space around the nucleusD) mass and energy are related

Answer»

Conclusion of Rutherford's scattering experiment:

Most of the space inside the atom is empty because most of the α-particles passed through the gold foil without getting deflected.

Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.

A very small fraction of α-particles were deflected by very large angles, indicating that all the positive charge and mass of the gold atom were concentrated in a very small volume within the atom.

Rutherford's Nuclear Model Of Atom

On the basis of his experiment,Rutherford put forward the model of an atom, which had the following features:

There is a positively charged centre in an atom called the nucleus. Nearly all the mass of an atom resides in the nucleus.

The electrons revolve around the nucleus in well-defined orbits.

The size of the nucleus is very small as compared to the size of the atom.

option C is most accurate A, is also partially correct

6036.

4. Give two examples from your daily life, where you find use of the fact that, all matter occupy space.fort

Answer»

All matter occupy spaceBed,table books everything occupy space

All matter occupy spaceCup, table, book, tv

6037.

What are the dilferent ways in whuch water geta contaminaied

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6038.

59. Select the correct order for the stability of given possible structures of CIF,90°90°F.F.120°120°120°(b) III >111(c) II 기 기11

Answer»

no. 1 will have the least repulsion between loan pairs and bond pairs.. so, it is the most stable..

option A.

6039.

2.Give the equations of two lines passing through (2, 14). How many more such linesare there, and why?

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6040.

Diagonal Relations

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Diagonal relationshipsoccur because of the directions in the trends of various properties as you move across or down the periodic table. Many of the chemical properties of an element are related to the size of the atom.

6041.

. What is iodoform test ?

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a solution of I2 is added to a small amount of unknown followed by just enough of NaOH to remove the colour.the formation of pale yellow precipitate of iodoform is a positive result.

6042.

Accetone reacts with iodine to form iodoform in the presence ofO (a) Caco,19)0 (b) NaOHO (c) KOHo (d) MgCO

Answer»

In the presence of NaOH

6043.

12 AS for the reaction. MgCO,(s) MgO(s)+CO2(9(1) Zero(3) +ve(2) -ve(4) o0

Answer»

entropy is positive because gases have more entropy than solids.

option (3) is correct

Samj nahi aya

6044.

breadth 3m andLength of a room is 5mheight 2.5m. If temp. of room is reaised from20°C to 25°C. Then calculate the %age ofthe initial volume of air constant pressurewhich will come out from the room?(3)(Ans. 1.706%)

Answer»

initial volume of air = volume of room = 5*3*2.5 = 37.5 m³

now since pressure is constant..

so, V1/T1 = V2/T2

=> 37.5/(273+20) = V2/(273+25)

=> V2 = 37.5*(298)/(293) = 38.13m³

now, the volume of air expanded is = 38.13-37.5 = 0.64m³

so, in % it is (0.64*100%)/37.5 = 1.70%

6045.

The solutions having basic character from the following are:i. Lemon juiceii. Washing soda solutionii. Vinegariv.Milk of magnesiaCoffee

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6046.

2KCI2MgMgOFind9 mo53.)In the following reaction,CaCO3 +2HCI CaCh +H20+CO2when 10g CaCO3 is reacted with 10gHCl,2.2g CO2 is obtained. Find the percentyield of COz(1) 25%(3) 100%50%75%(4)

Answer»

Here moles of CaCO3 is 10/100 = 0.1 moles and moles of HCl = 10/36.5 , which is greater than CaCO3 so, CaCO3 is the limiting reagent

now , for 0.1 mole of CaCO3 , 0.1 mol of CO2 aill be formed having weight = 0.1*(44) = 4.4g .. theoretically.

but actually 2.2g is yielded

so, % yield =2.2/4.4× 100 = 50%

6047.

A sample was found to contain 15 gm of KNO3, 2 gmof silica, 5.1 gm of sodium chloride and 3 gm ofCaCO3 per liter. Find the hardnessAns: 3000 ppm

Answer»

hardness in water is only due to the presence of. CaCO3 having mass = 3gm

and ppm is reported in mg/L

so, mass of CaCO3 in mg = 3000mg

so, hardness = 3000mg/1L = 3000ppm.

6048.

29. An LPG (liquefied petroleum gas) cylinder weighs 14.8 kgwhen empty. When full, it weighs 29.0 kg and shows apressure of2.5 atm. In the course of use at 27° C, the weightof the full cylinder reduces to 23.2 kg. Find out the finalpressure inside the cylinder. Assume LPG to be n-butane 36.with normal boiling point of 0°C.Tricky(a) 1.450 atm(b) 1.478 atm(d) 1.425 atm(c) 1.480 atm

Answer»
6049.

29.AnLPG (liquefied petroleum gas) cylinder weighs 14.8 kgAherwhen empty. When full, it weighs 29.0 kg and shows apressure of 2.5 atm. In the course of use at 270 C, the weightof the full cylinder reduces to 23.2 kg. Find out the final1200 Kis fothe originalpressure inside the cylinder. Assume LPG to be n-butane 36. Two closewith normal boiling point of 0°CTrickyat pressu(a) 1.450 atmb (c) 1.480 atm(b) 1.478 atm(d) 1.425 atm

Answer»
6050.

Thetable indicates the value of van der wals constant a' in(ám')i atm.mol?NH3一一! 4.170CIL2.253Gas| | 1360 | 1.390The gas which can be most easily liquefied isa) O2b) N2c) NHd) CH

Answer»

Answer: c)NH3

Sol. The ease of liquification of a gas depends on their intermolecular force of attraction which in turn is measured in terms of van der Waals’ constant ‘a’. Hence, higher the value of ‘a’, greater the intermolecular force of attraction, easier the liquification. In the present case, NH3 has highest ‘a’, can most easily be liquefied.

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