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1.252, 2.464 3.76 4.741 5.94 6.219

1) 252 2) 464 3) 76 4)741 5) 94 6) 219

okei i got it bt..hw ??T2=810 i thnk t2=799 and answer is 43.95

Since the formula of work(W)= Force.Displacement=F.s

So, the unit of Work is kg m ^2 s^-2

or you can also call it Joule which consist of Newton metre.

Using Boyle;s LawP1V1=P2V2If p1 is 1bar , V1 will be 2.27 LIf p2 = 0.2 barV2 = p1v1/p2 = 11.35 L

7 is the correct answer

option C is correct I- This is because an extra electron is added to the last orbit,hence makes it bigger..

2-Chloro Butane............

is there a joke going on

Largest size will be of Mg and smallest will be Al3+

Thank you sir

option B

option B

Periodic Trends of Atomic Radius

An atom gets larger as the number of electronic shells increase; therefore the radius of atoms increases as you go down a certain group in the periodic table of elements.

In general, the size of an atom will decrease as you move from left to the right of a certain period.

option btaiye

At(astatine) will have the largest size among the following in accordance to the concept mentioned earlier.

PV = nRT n = m/M (mass/molarmass) PV = mRT/M PM/RT = m/V = D The effective molar mass of air is 0.8x28 + 0.2x32 = 22.4 + 6.4 = 28.8g/mole. so D = 1atm x 28.8g/mole / (0.0821Latm/moleK x 301K) = 1.17g/L

Another way to think about it is: At STP the density of air is 28.8g/22.4L = 1.29g/L Gases expand when heated so the density will decrease if T increases from 273 to 301 so applying a temperature correction factor: 1.29g/L x 273/301 = 1.17g/L

thank you

ketone & aldehyde.

thankyou very much

First two shells are responsible for the screening effect hence option A is correct..

Chemical Group Forumla

Alcohol Hydroxyl OH

Aldehyde Aldehyde RCHO

Alkane Alkyl RHn

Alkene Alkenyl R2C=CR2

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Pb has an oxidation state of +4 in PbO2, but Pb+2 is more stable, due to which pb+4 has an innate ability to get converted into Pb+2, thus being able to oxidise others in the reactions.

Molar mass of methane = 16 g/mol1 mole of methane contains = 6.023 x 10^23 molecules Mass of 6.023 x 10^23 molecules of methane = 16 g​Mass of 1 molecule of methane = 16/ (6.023 x 10^23 ) g

Mass of 10 million molecules o molecules = [​16/ (6.023 x 10^23 ) ] x 10^7 = 2.65 x 10^-16 g

Thus mass of ethane sample = ​ 2.65 x 10^-16 g

​Molar mass of ethane or mass of 1 mole of ethane = 30 g/mol

If 30 g of ethane contain = 6.023 x 10^23 moleculesThen

​ 2.65 x 10^-16 g of ethane contains = [6.023 x 10^23 /30] x 2.65 x 10^-16 = 5.3203 x 10^6 molecules of ethane

determination and self confidence

r (n ) = n ^ 2*0.529* 10^ -10 / zmz = atomic number = 3n = 2 (as given 2ndorbit )just put the value in the formula and calculate it .r (n ) = 4 * 0.529* 10 ^ -10

lithium is the first element.

Water evaporates faster in a China dish as compared to a test tube 'cause the surface area of China dish is greater than that of the test tube. And, greater the surface area of water, faster the evaporation will be.

water evaporate more faster as compared to test tube because evaporation become more faster with the increase in surface area. Therefore, the surface area of China dish is more as compared to test tube. So, the evaporation become more faster.

When mixture of sand and naphthalene is heated, naphthalene undergoes sublimation and hence is converted to gas and collected by a cotton ball.

Thus the residue left is sand only.

When the china dish containing copper is heated oxygen is added to this.As a result the surface of the copper powder becomes coated with black copper oxide . Here copper gains oxygen. so this is an example for oxydation reaction

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Copper turns greenbecause of chemical reactions with the elements. Just as iron that is left unprotected in open air will corrode and form a flaky orange-red outer layer,copperthat is exposed to the elements undergoes a series of chemical reactions that give the shiny metal a palegreenouter layer called a patina.

The Law of Conservation of Mass (or Matter) in a chemical reaction can be stated thus: In a chemical reaction, matter is neither created nor destroyed. It was discovered byAntoine Laurent Lavoisier

Japan and China produce electricity from solid waste

The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exertsmall force on the wall Thepressure exertedby thegasis due to the sum of all these collision forces.The more particles that hit the walls, the higher thepressure.

Themoleculesare continually colliding with each other and with the walls of the container. When a molecule collides with the wall, theyexertsmall force on the wall Thepressureexerted by thegasis due to the sum of all these collision forces.The more particlesthat hit the walls, the higher the pressure.

The no. of electrons in the outermost shell decides the valency of the element(atom).If the no. of electrons in the last shell is5 or more than 5simply subtract it frm 8(maximum number of electrons in the outermost shell) the difference is the valency.Eg: S (16)=2,8,66 is greater than 5.So the valency is 8-6=2.If it isless than 5the number itself is the valency.Eg:Na (11)=2,8,11 is less than 5.So the valency is 1.

The no. of electrons in the outermost shell decides the valency of the element(atom).If the no. of electrons in the last shell is5 or more than 5simply subtract it frm 8(maximum number of electrons in the outermost shell) the difference is the valency.Eg: S (16)=2,8,66 is greater than 5.So the valency is 8-6=2.If it isless than 5the number itself is the valency.Eg:Na (11)=2,8,11 is less than 5.So the valency is 1.

because,They Have Fixed VolumeFix Shape etc..

They take the shape of the container as their particle size is small but the particle have fixed shape.

The no. of electrons in the outermost shell decides the valency of the element(atom).If the no. of electrons in the last shell is5 or more than 5simply subtract it from 8(maximum number of electrons in the outermost shell) the difference is the valency.Eg: S (16)=2,8,66 is greater than 5. So the valency is 8-6=2.If it isless than 5the number itself is the valency.Eg:Na (11)=2,8,11 is less than 5.So the valency is 1.

When an iron nail dipped in the copper sulphate solution than iron displaces copper from the copper sulphate because iron is more reactive than copper. Therefore the colour of the copper sulphate solution changes.

Carbon dioxide is also used widely as a coolant, a refrigerant, and an ingredient in the manufacture of frozen foods. Carbon dioxide fire extinguishers are often used to control electrical andoilfires, which cannot be put out withwater.

Electron‐donor‐acceptor complexes (EDA) can be established through halogen‐bonding interactions between the N lone electron pair from organic bases (or N‐/O‐centered anions) and perfluoroalkyl iodides RF–I. These EDA complexes can be activated thermally or photochemically, and will be shown to be responsible for new C–RFbond formation reactions, bypassing the use of visible‐light photocatalysts (either organic or organometallic) or harsh reaction conditions, thus simplifying reaction protocols, work‐up and analysis. Through this strategy, diverse reaction types can be realized, such as atom transfer radical additions, homolytic aromatic substitutions, and multicomponent reactions.

2 molal solution means 1000g solvent contains 2 moles sucrose.It means 1000g solvent contains 2x342 = 648g sucroseMass of solution = 1648 g.Volume of solution = 1648/1.4 = 1.17LMolarity of solution = 2/1.17= 1.709M

Osmotic pressure = CRTOsmotic pressure = 1.709x0.0821x298 = 40.6 atm

very correct

order of the reaction is 1/2+1 = 3/2.

In substitution reactions, there are two mechanisms that will be observed. An Sn2 and Sn1 reaction mechanism.

Sn2 reactions are bimolecular in rate of reaction and have a concerted mechanism. The process involves simultaneous bond formation by the nucleophile and bond cleavage by the leaving group. The transition state looks like this. Because the reaction is concerted, Sn2 mechanisms will always lead to an inversion of stereochemistry! For reactivity using an Sn2 mechanism, primary >> secondary >> tertiary carbon centers.

On the other hand, Sn1 reactions are unimolecular in rate of reaction and have a step-wise mechanism. This process first involves bond cleavage by the LG to generate a carbocation intermediate. The stability of carbocation formation will determine if Sn1 or Sn2 reactions occur. In the second step, the electronegative nucleophile attacks the carbocation to form the product. The steps look like this. Because the nucleophile can attach either side of the carbocation, which adopts an sp2-hybridized orbital with a trigonal planar geometry, an equal amount of inversion and retention is seen, referred to as a racemic mixture. For reactivity using an Sn1 mechanism, tertiary >> secondary >>> primary carbon centers.

The strength of nucleophiles used help to determine the reaction mechanism. Strong bases will almost always proceed to Sn2 mechanism. Weak nucleophiles will generally proceed to Sn1 mechanism when a stable carbocation is present.