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i. ConcentatedHNO3renders Al passive due to the formation of thin oxide coating on the surface of the metal which prevents further reaction. thereforeconc HNO3 can be transportedin Alcontainers

ii. Graphite is used as a lubricantdue to its slippery nature.Graphitehas layers of carbon atoms, with weak forces, residing in between its layers because of which itisquite slippery.

iii. Because diamonds are very hard (ten on the Mohs scale) they are often used as an abrasive. Most industrial diamonds are used for these purposes.

Small particles of diamond are embedded insaw blades, drill bits and grinding wheels for the purpose ofcutting,drillingor grinding hard materials.

Aluminium utensils should not be kept in water overnightbecausealuminiumis readily corroded bywater.

S - BLOCK=> The elements in which the last electron enters the S orbital of their outermost energy level are called as block elements . It consists of element of group 1 and 2 having the ground state electronic configuration of outermost shell as ns1 and ns2 respectively. where and stands for outermost energy cell the elements corresponding to ns1 configuration are called the alkali metals while those corresponding to ns2 configuration are called alkaline earth metals has the general electronic configuration of S block elements may be expressed as ns^1-2.

P -BLOCK=> The elements in which the last electron enters the P orbital of the outermost energy level are called p block elements .The elements of group 13 to 18 involving addition of one (ns^1np^1) ,two (ns^2np^2),three (ns^2np^3),four (ns^2np^4),five(ns^2np^5),six(ns^2np^6)electrons respectively in p orbitals and S orbitals are already filled in their atoms constitute P block the general electronic configuration for the atoms of this block may be written as ns^2np^1-6.

D - BLOCK => The elements in which the last electron enters the d orbital of their last but one called penultimate energy level constitute D Block Elements this block consists of the elements line between s and p block starting from fourth period and onwards them constitut group 3 to 12 in the periodic table in this element the outermost shell contains one or two electrons in their S orbitals and as but the last electron enters the last but one D subshell that is (n-1)d the general electronic configuration of the atoms of D block may be written as (n-1)d^1-10 ns^0-2.

F - BLOCK=> the elements in which the last electron enters the f orbitals of the atoms are called F block elements in this element the last electron is added to the third to the outermost called anti penultimate energy level and -2 if this consists of two series of elements placed at the bottom of the periodic table first them first series follows lanthanum Z is equal to 57 and the elements present in this series are called lanthanoids and the lanthanides these are also called rare Earth elements 2nd series follows actinium a c z is equal to 89 and the elements present in this series are called actinoids and the actor needs this hour of radioactive nature the general electronic configuration of F block elements may be written as (n-2)f^1-14(n-1)d^0-2 ns^2.

Look for the larger surface area. The presence of beads in tube (a) would provide a larger surface area for cooling

Carbon hasthe ability to form long chains. ... Itisbecause of catenation thatcarbonforms alargenumber ofcompounds.Carbon hasfour electrons in its valence shell. These four electronsareavailable to thecarbonatom to form bonds with other atoms; be itcarbonor other elments.

kp/kc = (RT)^{∆n(gases)} here ∆n of gases is -1 . as on product side only 1 gas is formed , but at reactant side.. 2 are there so, 1-2 = -1

so, kp/kc = (RT)^{-1}Kp/Kc = 1/RT . option D.

option C is the correct answer

Hyrogen gas is producedWe can test it by putting a burning candle in the front of the place from where the gas is evolving, as Hydrogen gas is a flammable gas it will burn with little explosions giving a 'pop' sound.

The solution is then distilled with a small quantity of sodium hydroxide, which converts the ammonium salt to ammonia. The amount of ammonia present, and thus the amount of nitrogenpresent in the sample, is determined by back titration. The end of the condenser is dipped into a solution of boric acid.

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Substituting these values in the above equation we get,

v = 5.45 x 106ms-1.

R = 0.529n²/z

for He 3rd orbit R = 0.529*(3)²/2

for H 5th orbit R = 0.529*(5)²/1

so ratio of circumference He/H = 2π(0.529)9/2/2π(0.529)*(25) = 9/2*25 = 9/50

option C

The formula forureais (NH2)2CO. The molar mass forureais 14*2+1*4+12+16= 60 g/mole. In this 60 g ofurea,nitrogenhas a mas of 28 g. So by simple proportion in5 kg of urea,nitrogenhas a mass =5 kg*28 g/60 g = 2.3kg

Ans :- Theanode, by definition, is the electrode where electricity flows into. In contrast, thecathodeis the electrode where the electricity flows out of. In this case, the roles are reversed, and the positive terminal becomes theanodeand the negative terminal is thecathode.

2,3-dimethylbutane

C-C-C-C | | C C

so, the alkyl halide Will be C-C-X. iso-propyl halide.. | C

Ans:Sodium chloride is an ionic molecule. There exists electronegativity difference between Sodium and Chlorine, which gives polarity to the molecule. Thus sodium chloride is polar molecule.Generally polar molecules will soluble in polar solvents and insoluble in non-polar solvents. Non-polar molecules will soluble in non-polar solvents and insoluble in polar solvents.As sodium chloride is polar molecule it will be soluble in polar solvents like water. And insoluble in kerosene (as it is non-polar solvent).

option c is the correct answer .

There will be no action ondry litmus paper.dioxidereacts with moisture to form sulphurous acid

dry litmus paper is answer

chlorine gas,aluminum foil,sulphur powder,iron powder,iodine vapour

Any additional details are mentioned?

Thankyou👍🏻so much

It is carried by a protein called ferritin

ferritine is a right answer

Hydrogen peroxideis a highly reactive metal that can react with light or heat to produce water. To prevent it's reaction with light and heat to make water it isstored in coloured bottlesso that light does'nt pass through it.

Here, depression in freezing point ∆ T f = 9 . 3 0 C , here mass of glycol = 50 gm, then mass of water W =delta Tf =Kf*mm is the molality of the solutiondelta Tf is the depresion in freezing point9.3=1.86*50*1000/w*62w=161.29 gmHence, the mass of ice separated from water = 200 -161.29 =38.71 gm

Volume of one virus = voume of cylinder = π r²h

= 22/7 × 7 × 7 × 10 A°³

=22 × 7 × 10 A°³

=1540 × 10^-30 m³

=1.54 × 10^-27 m³

so, volume of one mole of virus = 6.023 × 10²³ × volume of one virus

= 6.023 × 10²³ × 1.54 × 10^-27 m³

= 9.27542 × 10^-4 m³

= 9.27542 × 10² cm³

now, molecular weight = volume of 1mole/ specific volume

= 9.27542 ×10² / 6.02 × 10^-2 g/mol= 1.54 × 10⁴ g/mol

Weight of acetic acid =2.05×60=123

Weight of the solution =1000×1.02=1020∴∴Weight of water=(1020−123)=897g

∴∴Molality =2.05×1000/897=2.285

this question answer is option 2.28 m kg 1-

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While in use,solar panelscreate absolutely no waste or emissions. Unlikefossil fuel powerplants, they produce clean,renewable energyfrom afuelsource that requires no locating, excavation, transportation, or combustion. It's a simpler, cheaper, cleaner, and all-aroundbetter energysolution.

I) Ethyl bromide(Bromoethane)ii) Formaldehyde(Methanal)

The last of the p block families we will be looking at is theboron family-- Group 13. This group includes the elements boron, aluminum, gallium, indium, and thallium. All five have three electrons in their outer energy level. Only one member of this family is a metalloid -- boron. The others are classified as metals, forming positive ions by giving up their three outermost electrons.

Yes, Mercury is capable of existing in three distinct states of matter.

Intermolecular forces are the forces which mediate interaction between molecules, including forces of attraction or repulsion which act between molecules and other types of neighboring particles, e.g., atoms or ions. Ion-induced dipole forces. Ion-dipole forces. Hydrogen bonding.

STARS IN THEIR CORES GIVE A LOT OF AMOUNT OF ENERGY BY CONVERTING HYDROGEN TO HELIUM . TWO HYDROGEN ATOM[ DEUTRIUM ( TWO NEUTRONS) ] IS COMBINED TO FORM A HELIUM ATOM AND A NEUTRON . THIS RELEASES A LOT OF ENERGY .

let the volume of methane be a and Ethane be b.

CH4 + 2O2 ---> CO2 + 2H2O a 2a a 2a

C2H4 + 3O2 ------> 2CO2 + 2H2O b 3b 2b 2b

now a+b = 12

and a+2b = 19 ,

so, a+2b-(a+b) = 19-12 = 7=> b = 7ml , and a = 5 ml

volume of methane = 5 ml and ethane = 7 ml

In the classical physics observed in everyday life, matter is any substance that has mass and takes up space by having volume

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any substance which occupies space and have mass

Any thing which has mass and occupied in the earth is called matter

A substance or a thing which have a mass and capture the place such substance or a thing are known as matter

a substance which is occupied space and mass is called matter

Lotions: Topical application to affect the unbroken surface skin layers.Liniments: Topical application to "reach deep" in to the area to relieve pain in muscles and joints.

enzymes are chemical released in the body to speed up reaction of various life processes

Meaning:A savings account is a deposit account which allows limited transactions, while a current account is meant for daily transactions.

Suitability:A savings account is most suitable for people who are salaried employees or have a monthly income, whereas, current accounts work best for traders and entrepreneurs who need to access their accounts frequently.

Interest:Savings accounts earn interest at a rate of around 4%, while there is no such earning from a current account. A current account is actually a no interest-bearing deposit account.

Minimum balance:The minimum balance required to maintain a savings account is usually low, but for a current account it is much higher in comparison.

Nitrogen is a 2nd period element which has no vacant d-orbital whereas Phosphorus is the element of 3rd period which hasvacantd-orbital. Hence Phosphorus can form bonds with 5 Chlorine atoms but Nitrogen can't.

no of subshell isno. of orbital is 28e can be filled in 3×orbital =3×28=84

Here according the equation, 1 mole of A will combine with 3 mole of B and so if x mole of A is consumed then it will combine with 3x mole of B and similarly we can calculate the number of mole of C and D formed.Now from the question given that, at equilibrium,

(a/2)-3x = 2x

a/2= 5x,

x=a/10

so amount of B reacted=3x=3a/10Initial amount of B=a/2

so % of B reacted= {3a/10}/{a/2} *100

=6/10 *100=60%Hence, option (4) is correct.

xo2f2 is the correct answer