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8101.

12 AS for the reaction: MgCO2(s) MgO(s)+ CO29(1) Zero(2) -ve+veco

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it is +ve , option 3

because formation of gasses increases randomness and thus ↑ entropy

8102.

Which of the following is acidic in nature.A) CO227.B) NOC) coD) MgO

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option A is correct as, some non-metaloxides, such as nitrous oxide(N2O) and carbon monoxide (CO), do not display any acid/base characteristics.

8103.

An element crystallises as F.C.C. with density as 5.20 g/cc and edge length of the side of unit cellas 300 pm. Calculate mass of that element which contains 3.01 x 1024 atoms.

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8104.

Two electrolytic cells containing silver nitratesolution and dilute sulphuric acid wereconnected in a series. A steady current of 2.5 Awas passed through them till 1.078 g of silverwas deposited (Ag 107.8 g/mol)(a) How much electricity was consumed?(b) What is the weight of oxygen gas(i)liberated during the reaction?

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Reaction :Ag^+ + e^- ----- Ag

a. One mole of electrons are required to deposit one mole of silver (107.8 g/mol)= Charge of one mole of electrons = 96500 C= 96500 C ----- deposit 107.8 g of Ag= x C ----- deposit 1.078 gx = 96500 * 1.078 / 107.8 = 965 C of electricity is utilized.

b. 2 H2O- ---- O2 + 4 H+ + 4e-= 96500 C ---- liberate 32 g of oxygen965 C liberate ----- 965 * 32 / 96500 = 0.32 g.

b's answer is 0.16g

8105.

Explainthefollowing5 MarKSNon metallic character increases in going from left to right in a perioi)The basic nature of oxide of the elements decreases in going from left to rightin a period

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Okay so as we move from left to right in a period in the periodic table the metallic character of the elements goes on decreasing.

This is because in a period electrons are added in the shells but the number of shells remain constant. Metals have a tendency to lose electrons. Thus when electrons are added the size of atoms decreases due to increased nuclear pull and it becomes difficult for the elements to lose electrons.

So as we move from left to right in a period in the periodic table the metallic character goes on decreasing!

8106.

18) The best method to prepare cyclohexane fromcyclohexanol is by usinga) conc. HCl ZnCl2 b) conc. H:POc) HBrd) conc. Hci

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8107.

Zncl2+MgO=?

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Magnesium + Zinc Chloride = Magnesium Chloride + Zinc OxideDouble displacement reactionMgO + ZnCl2 = MgCl2 + ZnO

8108.

40. How many carbon atoms are present in 0.35 mol of C6H1206-(A) 6.023 x 1025 carbon atoms (B) 1.26 x 1023 carbon atoms(C71.26 x 1024 carbon atoms (D) 6.023 x 1024 carbon atoms

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answer c is correct hai

6×0.35×6.023×10^23=12.64×10^23=1.26×10^23

8109.

3 20 g silver nitrate solution is added to 20 g of sodium chloridesolution. What change in mass do you expect after the reactionand why?

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The total mass of products formed will be the same as the total mass of reactants i.e. 40g because the law of chemical combination states that mass can neither be created nor can be destroyed during a chemical reaction of compounds and elements.

8110.

34. .A bond with maximum covalent character fbetweeh non-metallic elements is formed.(a) Between chemically similar atoms(b) Between identical atoms(c) Between atoms of the same size(d) Between atoms of widely different electronegativities.

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option bThis is due to the fact that covalent character is inversely proportional to the electronegativity difference. since, similar atoms will have same electronegativity, these show the maximum covalent character.

8111.

Balance the following equations:(a) N, + H, - NH(b) H2 + O HO(c) Na,O HONaOH(d) cO+ 02CO2(e) Zn + HCl ZnCl2 + H2

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1. N2 + 3 H2 ----- 2 NH3

2. 2 H2 + O2 ---- 2 H2O

3. Na2O + H2O ----- 2 NaOH

4. 2 CO + O2 ---- 2 CO2

5. Zn + 2 HCl ---- ZnCl2 + H2

8112.

Sodium hydroxide solution (in water) reacts with hydrochloricacid solution (in water) to produce sodium chloride solution andwater.

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it's acid base reaction which forms salt and water

Sodium hydroxide+ hydrochloric acid =sodium chloride + waterNAOH+HCL= NACL+H2Othis is also example of neutralisation reaction.

8113.

) Solution of sodium bhydroxide in water reacts with hydrochloric(b)acid solution (in water) to produce sodium chloride solution andwater

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NaOH (aq) + HCl ⇨ NaCl (aq) + H2O (l)

8114.

12 In a metallic piece of magnesium, 8.46 x1024 atoms are present, Calculate theamount of magnesium in moles and in gram[Atomic mass of magnesium 24 u]

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We know that 6.022 *10^23 atoms = 1 mole

8.46 ×10 24 atoms * 1 mole /6.022 *10^23 atoms

= 14.05 mole Mg

8115.

Which would you expect to have a higher melting point, magnesium oxide or magnesiumfluoride? Explain your reasoning.

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MgF because it is ionic whereas MgO is slightly covalent due to Fajans rule.

Bigger the anion more is covalent character

8116.

Sodium + Water -> Sodium hydroxide + Hydrogen.

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Na +h2o = NaOH + H2 + heat

8117.

Q10. a) A 1.84 g mixture of CaCO3 and MgCO3 upon heating gave 0.96 g of residue.Calculate the % composition of the mixture.b) Empirical formula of a compound is CH. Its molecular mass is (i) 26 and (ii) 78. Whatis the molecular formula of these compounds?[3+2=5)

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8118.

How much of NaOH is required to neutralise 1500 crr' of 0.1 N HCl? (N.-23)A)40 g13.B) 4 gCy6g

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Weight of NaOH = N* E.W. * V/1000

Put the values in the above formula

Weight of NaOH required.= 0.1 *40 *1500/1000

= 6 gm

8119.

Complete the following acid-base reactions and name the products:(i) CH,CH,CH,NH,+ HCl →(ii) (CH5),N + HCI->

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8120.

Correct the formulae and balance the following equations :(0) K(s) + H2O(1) - KOH (aq) + Hg)(i) Mg,N(s) + H20() - MgOH(s) + NH3(g)(iii) NH C1(s) + Ca(OH)(s) - CaCl(s) + NH3(g) + H2O(1)(iv) H.O(1) + Cl(g) - HCl(aq) + O(g)(v) CaOH(aq) + CO2(g) - CaCO3(s) + H20(1).

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8121.

10.When zinc reacts with sodium hydroxide, the products formed are(A)(C)zinc hydroxide and sodium(B) sodium zincate and watersodium zincate and hydrogen(D) sodium zincate and oxygen

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option c) Zn + 2NaOH Na2ZnO2+ H. Zinc react with sodium hydroxide to produce zincate sodium and hydrogen. This reaction takes place at atemperature near 550°C.

8122.

3mplete the following acid-base reactions and name the products:(0 CH,CH, CH,NH,+ HCl(i) (C,H,N + HCI

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8123.

20)Which metals can be cut with a knife?(a) Sodium and iron(b) Potassium and copper (c) Sodium and potassium (d) All

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The answer c is the correct one. your answer is right.

8124.

iany atoms are present in 100 g sample ofHow many moles of CaCO3 would weigh 5 g?

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Molecular mass of CaCO3 =sum of all the masses of its components.Ca=40uO=16uC=12uMolecular mass=40+12+3x16=40+12+48=100uTherefore, molar mass of CaCO3 is 100g100g of CaCO3 contains 1 mole.? ------------------------------> 5moles=100x5/1=500 gms∴ 5moles of CaCO3 contains 500g

8125.

1 с.c of 0.1 N HCl is added to 1 litre solution ofsodium chloride. The pH of the resulting solution willbe(2) 0(4) 4(3) 10

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Volume of HCl = 1 cm3​ or 0.001 LNormality of HCl = 0.1 NNumber of gram-equivalents of HCl= Normality×Volume= 0.1×0.001= 0.0001Volume of solution = Volume of NaCl + Volume of HCl= 1 + 0.001= 1.001 LAs NaCl is salt it will not contribute towards the pH of the solution.Normality of HClin resulting solution = 0.0001 / 1.001= 0.0001 NpH = -log[H+]= - log(0.0001)= 4

8126.

Write down the electronic configuration of Lithium (3 electrons), chlorine (17 electrons), Potassium (19 clectronssodium (11 electrons) and carbon (6 electrons) atom.

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Lithium = 1s2 2s1 Chlorine = 1s2 2s2 2p6 3s2 3p5Potassium = 1s2 2s2 2p6 3s2 3p6 4s1Sodium = 1s2 2s2 2p6 3s1Carbon = 1s2 2s2 2p6

8127.

Multiple Choice Questions1, Valeney of the elements in the halogen group ib, twoe, threed. foura, one

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Answer is a. oneThe elements present in halogen group have 7 electrons in their outermost shell. If they accept one more electron from any other item their outermost octet becomes complete. So their valency is said to be equal to 1.

8128.

2.0 g of a sample of sodium chloride contains0.785 g of sodium and 1.775 g of chlorine. Inanother sample, 2.925 g of sodium chloridewas found to contain 1.15 g of sodium and1.775 g of chlorine. Show that these data are inagreement with the law of constant proportion.

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8129.

2.0 g of a sample of sodium chloride contains0.785 g of sodium and 1.775 g of chlorine. Inanother sample, 2.925 g of sodium chloridewas found to contain 1.15 g of sodium and1.775 g of chlorine. Show that these data are inagreement with the law of constant proportion.14.

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8130.

8 Compare aikali metals and halogens with respect to ther valency, atomic size and nature ofoxides. Predict the nature of compounds formed between them

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8131.

4.Imagine and write what type of ion can be formed generally by an atom ofelement with low ionisation energy, low electron affinity with high atomicsize ?

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Atoms can gain or lose electrons. When an atom gains an electron, energy is given off and is known as the electron affinity.Electron affinityis defined as the energy released when an electron is added to a gaseous atom or ion.When most reactions occur that involve the addition of an electron to a gaseous atom, potential energy is released.

plants with weak stems generally possess tendrils

8132.

Answer the following Quesitons5. )Na. Mg. Al. Si and Pare the first 5 elements of 3rd period. Wis more. electropositive? Why ?Arrange the above elements in the decreasing order of their atomic size

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Across the period electropositivity decreases and down the group increasesHence Mg is the most electropositive

8133.

FIVE IARNUESTROSCHEMISTRYIdentify at least 25 apparatus from the picture given belowLab Equipment for ChemistryТІ

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Beaker,puppet,burret,funnel,round bottom flask,conical flask,test tube,wire gauge,Bunsen burner,tongs,clumps,condenser,test tube holder,watch,evaporating dish,wash bottle, spatula,measuring cylinders,clamp,iron ring,utility clamp,china dish,file,forceps,thermometer, glass,glass rod graduated cylinders,

8134.

When 3.0 g of carbon is burnt in 8.00 g oxygen, 11.00 g ofcarbon dioxide is produced. What mass of carbon dioxide will

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C + O2→ CO2

3 g 8 g 11 g

Total mass of reactants = mass of C + mass of O = 3+8=11g

Total mass of reactants = total mass of products

Hence, the law of conservation of mass is proved.

Further, it also shows carbon dioxide contains carbon and oxygen in a fixed ratio by mass, which is 3 : 8. Thus it also proves the law of constant proportions. 3 g of carbon must also combine with 8 g of oxygen only. This mean that (50 – 8) = 42 g of oxygen will remain unreacted

8135.

2. When 3.0 g of carbon is burnt in 8.00 g oxygen, 11.00 g ofcarbon dioxide is produced. What mass of carbon dioxide will

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full ques.-

8136.

weigu.2. When 3.0 g of carbon is burnt in 8.00 g oxygen, 11.00 g ofcarbon dioxide is produced. What mass of carbon dioxide will

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it will be 2.0

ok

2 is the correct answer of the given question

8137.

c)Variation of Atomic sizeVariation in a group

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Atomic size increases down the group.

8138.

Carbon dioxide is neither combustible nor supporter of combustion. Explainwhat happens when a burning magnesium ribon is introduced into a jar containingcarbon dioxide ?2

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White fumes evolves when mg ribbon is burnt

white fumes evolves when magnesium ribbon burns

8139.

) Why is organic chemistry considered as chemistryof carbon compounds?

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Organic chemistry is the study of chemical compounds that contain carbon. Carbon has the ability to form a chemical bond with a wide variety of chemical elements and other carbon atoms. This allows a nearly unlimited number of combinations. The subject of carbon compounds is called organic chemistry because all known organisms, or living things, are made up of water and carbon compounds. Organic chemistry largely involves the synthesis, or formation, of organic products by chemical reaction using different reactants and reagents, the substances used up during a reaction. Several different areas of chemistry expand on the concepts and principles of organic chemistry, including biochemistry, microbiology, and medicine

8140.

he number of moles in 4 x10 atoms of iron are

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8141.

25. An organic substance containing carbon, Hydrogen and Oxygen gave the percentagecomposition as C = 40.67%, H = 5.085%. The vapour density of the compound is 59.Calculate the molecular formula of the compound.

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8142.

3. What causes winds?

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8143.

17. An element with density 2.8 g em-3 forms af.c.c. unit cell with edge length 4 x10-8cm. Calculate the molar mass of the element. (Given : NA-6.022 x 1023 mol-1)

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8144.

What is meant by the term "Mole"? Calculate the number of moles in(a) 3.011 x 1023 atoms of C.32 g of Oxygen gas.(Given: Avogadros number- 6.022 x 102B mol 1.Atomic mass of 0-16 u and

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A mole of a substance is defined as: The mass of substance containing the same number of fundamental units as there are atoms in exactly 12.000 g of 12C. a)6.022*10^23 atoms form 1 mole of an elementtherefore 3.011*10^23 atoms forms, 3.011*10^23/(6.022*10^23)=0.5 molesb)Two atoms are present in Otherefore O2=16*2=32=molar massno of moles= given mass/ molar mass=32/32=1 therefore no of moles of O2= 1

8145.

31. Quantitative analysis of an organic compoundgave the following resultsPercentage of carbon 92.3 and percentage ofhydrogen 7.7If the molecular weight of the compound is 78,calculate its molecular formula. [Ans: C.HJ

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8146.

If the value of Avogadro number is 6.023 x 1023 mol 1and the value of Boltzmann constant is 1.380 x 10JKthen the number of significant digits in the calculatedvalue of the universal gas constant is(2015)

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8147.

(2)(1) 1689.*when it is convert(4) M/4What is the equivalent mass of 10quivalent mass of loz when it is converted into I, in acid medium?(3) M/5(2) M7(1)M/6

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Answer:2)M/7

Explanation:

Equivalent mass=MolecularweightChangeinoxidationnumberpermole=MolecularweightChangeinoxidationnumberpermole

Suppose molecular weight is M

Oxidation number of I2inIO−4IO4−in Acidic medium i.e.,I×(−8)+1e−=+7I×(−8)+1e−=+7

So eq. wt. = M/7.

8148.

A certain amount of a metal whose equivalent massis 28 displaces 0.7 L of H2 at S.T.P. from an acidhence mass of the element is(1) 1.75 g(3) 3.50 g(2) 0.875 g(4) 7.00 g

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8149.

coper solar cells. what energy conversion takes place in a solar celleseaoral fornu, fthee ompounds A B and Cis Ch,. B has higltest boiling point and Cheslowest boiling point.(i) Mention of the type of(ii) Which of these has the minimum number of carbon atoms?compound A, B, and C.(iii) Name the homclogous series to which A, B and Cbelong.(2

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(i) CnH2n is a general formula of a hydrocarbons group

(ii) The one with the minimum number of carbon atoms is C because it has the lowest boiling point

The boiling points of hydrocarbons increases with the increase in their molecular masses whichalso increase with increase in the number of carbon atoms.

(iii) The homologous series is alkenes.

8150.

What do you understand by the following:(a) Analysis(c) Reagent(b) Qualitative analysis(d) Precipitation ?

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a. analysis is detailed examination of the elements or structure of something.

b. identification of the constituents, e.g. elements or functional groups, present in a substance.

c. a substance or mixture for use in chemical analysis or other reactions.

d. The emergence of the insoluble solid from solution is calledprecipitation.