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8001.

Carbene par sanchhipt

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In chemistry, a carbene is a molecule containing a neutral carbon atom with a valence of two and two unshared valence electrons. The general formula is R--R' or R=C: where the R represent substituents or hydrogen atoms.

8002.

, At wich of te foiooing candiions can agason condittons cao a gas21ora.LU

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The temperature of a gas should be less than the critical temperature for liquefaction to take place irrespective of the pressure.

so option D is right

8003.

43.Which of the following species is amphoteric in nature?(A) H2SO4(B) HCI(C) HSO(D) NOS

Answer»

option cHSO4- + HCl <====> H2SO4 + Cl- (HSO4- acts as a base; it accepts a proton)

HSO4- + OH- <=====> SO42- + H2O (HSO4- acts an acid; it donates a proton)

8004.

17) The UPAC name of the compoundO ferCH, -CH, -C-CH2-C-CH, is:1) Hexane -2,4-dionë2) Hexane - 2,4-diol3) Pentane -2,4-dione4) Heptane -2,4-dione -

Answer»

answer is HEXANE-2,4-diol

hexane 2,4 dione is the answer

option A is the correct answer

answer is haxane- 2,4- diol

8005.

13. Which of the following is unacceptable resonating structureof buta-1,2,3-triene?田(a) CH2-CC-CH,□(b) CH,-C-C-CH2田

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option B

8006.

Find DUPAC Name qçcOCHZ-C-CH2-C-CHzCH2CH2CH2CH

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8007.

8.The equivalent weight of a certain trivalent element is 20. Molecular weight of its oxide is(1) 168(2) 68(3) 152(4)56

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Option 1Equivalent weight is defined as the weight of an element which combines or replaceswith 8 part of oxygen.so equivalent weight of trivalent is = 20so 20 gm of element combines with 8 gm of oxygen.formula is M2O3 = 2x+ 48 = molecular wt8 gm of O2 combines with = 20 gm of element48 gm of O2 will combines with = 20x48/8 = 120so moecular wt = 120 + 48 = 168

The Answer of question is 56

8008.

(a) Write the IUPACnames of the followingNaglCoCl2Br2

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(1) IUPAC name of Fe2[Fe(CN) 6] is Iron(III) hexacyanido ferrate

8009.

ive the IUPAC names of(t) CH3-CH2 C CH

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The IUPAC name of this is Butyne

thanks

8010.

Q. 20, A solutionis 25% water, 25% ethanol and 50%acetic acid by mass. Calculate the mole fraction of each component

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Let the mass of solution is 100g then, mass of water = 25g mass of ethanol = 25g mass of acetic acid = 50g

Now, find number of moles of each components , Number of mole of water = mass of water/Molar mass of water = 25g/18g/mol [ ∵ molar mass of water = 18g/mol ] ≈ 1.4

Number of moles of ethanol = mass of ethanol/molar mass of ethanol= 25g/46g/mol [ ∵ molar mass of ethanol (C2H5OH) = 46g/mol = 0.54

Number of moles of acetic acid = mass of acetic acid/molar mass of acetic acid= 50g/60g/mol [∵ molar mass of acetic acid (CH3COOH) = 60g/mol]= 0.8 ∴ total number of moles = 1.4 + 0.54 + 0.8 = 2.74 Now, mole fraction of water = moles of water/total moles = 1.4/2.74 =0.51

similarly , mole fraction of ethanol = 0.54/2.74 = 0.197mole fraction of acetic acid = 0.8/2.74 = 0.291

8011.

) HBrRearrange the following I to IV) in the orderof increasing masses and choose the correctanswer from (a) (b) (c) and (d). Atomic masses:N=14, O = 16, Cu = 63I. 1 molecule of oxygen II. 1 atom of nitrogen111.1 × 1010 g molecular weight of oxygenIV. 1 x 10-18 g atomic weight of copper(a) I &lt;I&lt; III &lt; IVh) IV I&lt; II&lt;I

Answer»

1 molecule of oxygen weighs = 32gm and 1 atom of nitrogen weighs = 14gm

here II<I

so, 1 will have the largest mass , then 2 then 3 and 4

only option following is .. B.

correct answer is A .....

8012.

57 Vapour density of a volatile subsnis 4 (CH4 1).Its molecular weight would be( 8 (2) 2 (3) 64 (4) 128

Answer»

hence, molecular weight = 2*4 = 8

8013.

The vapour density of a gas is 11.2, then 11.2 g of this gas atN.T.P. will occupy a volume-(a) 11.2L (b) 22.4L (c) 11.2mL (d) 22.4mL

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b is a correct answer

i think 22.4L is the write answer

a) is the correct answer

8014.

Write down the possible isomers and give their IUPAC names using the formula c

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8015.

24.Givethe IUPAC names of following organiccompounds.i)Cliv)1VOH

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8016.

43. When you add about 2 ml of acetic acid toa test tube containing an equal amout ofdistilled water and leave the test tube tosettle after shaking its contents, what willyou observe in the test tube after about 5minutes ?(A) A white precipitate settling at itsbottom(B) A clear colourless solution(C) A layer of water over the layer of(D) A layer of acetic acid over the layer ofa few drops of ethanoicacetic acidwater7 containing

Answer»

Acetic acid dissolves completely in distilled water and gives a clear, colourless and transparent solution. Hence, the correct option is B.

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8017.

.It takes 2.56 x 103 equivalents of KOH to neutralize0.50176 g H2XO4. The atomic weight X would be(a) 16 (b) 8 (c) 18 (d) 32

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8018.

A gas is found to have a formula [COlx. If itsvapour density is 70 the value of x is-

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8019.

In a chemical reaction the heat change is positivethen the reaction is(1) Thermal decomposition(2) Thermal absorption(3) Exothermic(4) Endothermic

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In a chemical reaction the heat change is positive then the reaction is Endothermic

8020.

Waec IUPAC names of the following compounds.1. I vul 13 molecular formulCH-CH-CH-¢-CH3-CH,CH, CH,b)CH-çıl-çı-CI-CH,CH-CH,Cyll, CH,CHCH,

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8021.

Write the complete structural formula and giveIUPAC names to the following alkanes.3/2(CH) CHCH,C(CH), (iv) CH(CH)1s CH

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8022.

Properties of Ethanoic Acid

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Ans :- Water freeacetic acidis known as glacialacetic acid. When dissolved in water,acetic acidundergoes dissociation to form hydrogen (H+) ion. ... It turns blue litmus paper red, indicating that it isacidicin nature. However, it is a weakacidbecause it does not dissociate completely in aqueous solution.

properties- >it is a colourless liquid>it has a vinegar like smell>its boiling point is 118°C>it is missible in water in all proportion>when it is cooled, it freezes to form a colourless, ice like solid which looks like a glacier>it turns blue litmus red>pH of this acid is 4

8023.

Section-C (Che1. In an experiment to study the properties 41.of ethanoic acid, a student takes about 3mL of ethanoic acid in a dry test tube. Headds an equal amount of distilled water toit and shakes the test tube well. After sometime he is likely to observe that:(A) a colloid is formed in the test tube.(B) the ethanoic aid dissolves readily inwater(C) the solution becomes light orange.(D) water floats over the surface ofethanoic acid.out 2 ml ethanoic acid 42

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The answer is option B

On addition of 3 ml of ethanoic acid to a test tube containing 3 ml of distilled water, a clear solution will be formed having no color due to high Solubility of ethanoic acid in water.

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8024.

Question 1: What is the product of water andpentyl ethanoate under acidic conditions?A. Ethanoic acid and pentanolB. Butanol and waterC. Ethanoic acid, two equivalentsD. Pentanol, two equivalents

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When mixed with water under acidic or basic conditions, esters undergo hydrolysis. The products are a carboxylic acid and an alcohol.

A. Ethanoic acid and pentanol, correct.

B. Butanol and water, incorrect. Pentyl ethanoate does not lose its ester group to become a four-carbon alcohol.

C. Ethanoic acid, two equivalents, incorrect. Hydrolysis of an ester forms carboxylic acid and alcohol.

D. Pentanol, two equivalents, incorrect. Hydrolysis of an ester forms carboxylic acid and alcohol.

8025.

The vapour density of undecomposed N,0, is 46. When heated, vapour density decreases to24.5 due to its dissociation to NO2. The precentage dissociation of N at the final temperatureis(1) 87(3) 40(4) 70(2) 60

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8026.

(d) Electrolytic dissociation and thermal dissociation.

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ELECTROLYTIC DISSOCIATION:The process due to which an ionic compound dissociates into ions in the fused state or in aqueous solution is called electrolytic dissociation. It is a reversible process.Dissociates into charged particles i.e. ions. Electrodes help to attract oppositely charged ions.

THERMAL DISSOCIATION:The decomposition of a compound into its element by heat is called thermal dissociation. It is not a reversible process. Ions are not found. Electrodes are not present.

8027.

In a 0.25 L tube dissociation of 4 mol of NO is takeplace. If its degree of dissociation is 10%. The valueof Kp for reaction 2 NON2+O2is-(18)(D) 32(C) 16

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why you multiplied A

8028.

20.How will you convert:(a) Ethanoic acid into methanamine ?(b) Hexanenitrile into 1-aminopentane?(c) Methanol to ethanoic acid ?

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8029.

5. Fill in the blanksS.No Molecular formula Common Name IUPAC NamesEthanoic acidCH COOH2HCHOFormaldehyde

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1.Acetic acid2.Methanal

Thx a lot

8030.

932.5 to 8 per cent cthanoic acid in waterVinegar is a solution of about:1.5 to 8 per cent ethanoic acid in alcohol3.50 to 80 per cent ethanoic acid in water4.50 to 80 per cent ethanoic acid in alcoholSalent bydride IVF

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8031.

UUU2.5 to 8 per cent ethanoic acid in water1.-OH93. Vinegar is a solution of about:1.5 to 8 per cent ethanoic acid in alcohol3.50 to 80 per cent ethanoic acid in water4.50 to 80 per cent ethanoic acid in alcoholhidrogen when heated, to form a covalent hyd

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8032.

Qela (UICHCOCI(4) HCN, PBT, IT(3) KCN, H44. Which one of the following pairs gives effervescence with aq.West Bengal JEE 2008)NaHCO,?ICH COCH,III. CH.COOCH IV. CH.CO.O.COCH,(1) Iand II Ca (2) I and IV(3) II and III 10h (4) Tand III13. Which of the following acids has the smallest dissociationmant Bengal JEE 2008!Inchest

Answer»

option no 4 is correct.

I & III.

8033.

Explain the properties of carbon.Ans: Properties of carbon:

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Thephysicalandchemical propertiesof carbon depend on the crystallinestructureof theelement. Itsdensityfluctuates from 2.25 g/cm³ (1.30 ounces/in³) for graphite and 3.51 g/cm³ (2.03 ounces/in³) fordiamond. Themelting pointof graphite is 3500ºC (6332ºF) and the extrapolatedboiling pointis 4830ºC (8726ºF).

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8034.

8. Give one point to differentiate the following thermodynamic terms:(a) Extensive properties and intensive properties.Jobs Isothermal process and isobaric process.

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a)AnExtensive Property, is one that depends on the amount of substance present (e.g Mass and Volume).

An Intensive Propertydoes not depend on the amount of matter present (e.g Density and Color).

b)Anisothermal processis one where the temperature stays constant, and the pressure and volume change relative to each other.

An isobaric process is one in which the pressure remains constant

8035.

Isotopes of an element contains(A Similar physical propertiesB) Different chemical properties(C) Different no. of NeutronsD) Different atomic number

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The answer is OPTION A.

8036.

20 /८५/०८०/02 ् Md , (| /5 ८2SR

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8037.

which quantum number Distinguishes the electron in the same orbital? name the principle involve.

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The spin quantum number is responsible for that distinction. The electron, being a fermion, has a half integer (1/21/2) spin of either−1/2−1/2or1/21/2. This value is the value of the spin quantum number of the electron. The maximum no. of electrons that can reside in an orbital is 2, with one being spin up (1/21/2) and the other being spin down (−1/2−1/2).

The reason for this is because of the Pauli Exclusion principle which states that two or more electrons (or fermions) cannot occupy the same state at the same time. In this case, the electrons in the orbitals have the same first three quantum number values (principal, azimuthal, and magnetic) but do not violate the exclusion principle by having different spin.

8038.

14. If magnetic quantum number of a given electron is represented -3, then what will be its principalquantum number?(a) 2(b) 3

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since magnetic quantum number is -3

so, the value l is 3

and for a value of l = 3, the possible value of n is 4.

as n = (l+1)

so option C.

8039.

Problem 2.17What is the total number of orbitalsassociated with the principal quantumnumber n 3?

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For n = 3There are 3 subshell possiblei.e. 3s having one orbital3p having 3 orbitalsAnd 3d having 5 orbitalsTotal number of orbitals is 9

8040.

what information do you get from principle quantum number

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It tells the main energy level occupied by the electron. moreover give information about main energy level.

it is 5 marks question

Principle quantum number:•Given by- Bohr•it represents the name, size and energy of the shell to which electron belongs.•indicates the distance of electron from the nucleus.•The value of n lies between 1 to ∞.i.e., n= 1,2,3,4....∞ =K,L,M,N.....•Greater the value of n greater is the distance from the nucleus. r=0.529×n²/Z A° r1<r2<r3<r4<....•Greater the value of n is greater is the energy of shell. E= -13.6×Z²/n² eV/atom E1<E2<E3<....•The angular. momentum of revolving electron is mvr=nh/2π•The number of electrons in a perticular shell is equal to 2n².

8041.

2. What information do you get from principal quantum number?

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Principle quantum number (nn)- indicates the orbital size. Electrons in atoms reside in atomic orbitals. These are referred to ass,p,d,f..type orbitals. A1sorbital is smaller than a2s orbital. A2porbital is smaller than a3p orbital. This is because orbitals with a largernvalue are getting larger due to the fact that they are further away from the nucleus. The principle quantum number is an integer value wherenn= 1,2,3... .

8042.

73.According to V.B. theory, the bonds inmethane are formed due to the overlapping(1)los-.3 os -(2) los - p. 3 os-S(3) 205-s, 2 os - P(4) osp – s

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i think option 3 it may be correct but draw it and do answer

Option 3 is the correct answer because carbon has two S orbitals which will hybridized with two S orbital of two hydrogen atom and other two hydrogen atoms is orbital will hybridized with the P orbital of carbon.

8043.

I. Define Reports.

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An account given of a particular matter, especially in the form of an official document, after thorough investigation or consideration by an appointed person or body.

8044.

1. Write the molecułar formula of the 2d and the 3'd member of thehomologous series whose first member is methane.

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As the first member is Methane

It has the suffix “ane” so this means that the compound is an alkane

The 2nd member of the series will be Ethane

The general formula for alkane is CnH2n+2

So the n is the number of Carbon atoms. The number of Carbon atoms in Ethane is 2

The formula is C2H6

The 3rd member of the homologous series will have 3 carbon atoms

The name of the compound is Propane

The formula is C3H8

vgghgzfnbdfngxvngxfnc

8045.

Q.15. Write structural formula of (any one). Ix 2= 2a) two homologous isomers; b) two position isomers

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a)Analkylgroup is obtained by removing one atom of hydrogen atom from analkanemolecule.CnH2n+1is the genral formula of the homologous series.

8046.

The IUPAC name of CH3CHO is

Answer»

The IUPAC name of CH3CHO isethanal.

The IUPAC name of CH3CHO isMethanal

8047.

How many structural isomers can you draw for pentane?

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8048.

i) Write the structural formula for Iso-Pentaneii) How detergents are different from soaps

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1) Isopentane, C5H12, also called methylbutane or 2-methylbutane, is a branched-chain alkane with five carbon atoms.

8049.

what is IUPAC name of CH4?

Answer»

methaneis the correct answer

methane is the right answer.

methane is the right ansy

methane is true answer

methane if the correct answer

methane is the right answer.

8050.

oon which at 100 m depth in a sea form sea levelHow much pressure will be f(A) 100 Paelt by a gas ball(B) 98 Pa(D)1.08 x10° Pa(C) 9.8x 10 Pa

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Pressure at surface of sea = 760 mm Hg

= 1033.3 cm H2O

= 10.3 m H2O

Pressure at 100 m depth = 100 + 10.3 = 110.3 m H2O

Assuming temperature to constant,

P1V1(at surface) = P2V2(at 100 m depth)

10.3 x V1= 110.3 x V2

V2= 0.093 V1

= 9.3% of V1.