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Since the empirical formula of the compound is CH2O, its molecular formula can be written as n(CH2O) = C(n)H(2n)O(n),

It is given that 0.0835 moles of the compound contains 1g of H i.e 0.0835 mol -> 1g of H,

This means (2n)(0.0835) moles of H in the compound contains 1g of H i.e (2n)(0.0835) -> 1g,

(2n)(0.0835) = 1,

2n = 12 or n = 6,

So the molecular formula of CH2O is C6H12O6

and question🙋 please and nakscjch

A does not reduce Tollen's reagent. So it must be a ketone. Since it answers Iodoform test, it must be a methyl ketone (i.e. containing CH3CO- group). So, according to formula, compound A must be CH3COCH2CH2CH3.

This implies B must be CH3CH2COOH, and C must be CH3CH​2CH2CH3(remember that the Kolbe's electrolysis gives an alkane having twice the no. of carbon atoms as in the carboxylate salt).

Rainwater is generally soft. So it will produce foam. However calcium ions in test tube B will make water hard, due to which less foam will be produced.

A:B:C=1.33:1:1.5=8:6:9⟹Empirical Formula=A8B6C9A:B:C=1.33:1:1.5=8:6:9⟹Empirical Formula=A8

Kohlrausch's lawstates that the equivalent conductivity of an electrolyte at infinite dilution is equal to the sum of the conductances of the anions and cations. If a salt is dissolved in water, the conductivity of the solution is the sum of the conductances of the anions and cations.

Applications of Kohlrausch's Law. ... However, values for weak electrolytes can be determined by using theKohlrausch'sequation. (ii) Determination of the degree of ionisation of a weak electrolyte: TheKohlrausch's lawcan be used for determining the degree of ionisation of a weak electrolyte at any concentration.

Liquefaction is the process by which metals obtained from metal oxide

C) Reduction is the right answer

Denaturationis a process in whichproteinsor nucleic acids lose the quaternary structure, tertiary structure, and secondary structure which is present in their native state, by application of some external stress or compound such as a strong acid or base, a concentrated inorganic salt, an organic solvent

Rancidity is defined as chemical decomposition of oils and fats which in another words is spoiling food materials that difficult for consumption.

It can be prevented by following methods: (i) The packing of food materials should be replaced the air with Nitrogen. (ii) The food materials should be placed at very low temperatures. (iii) Addition of antioxidants also prevents rancidity process.

RANCIDITY: It is the process of slow oxidation of oil and fats Present in food materials ( which are volatile in nature ) resulting in the change in taste and smell in them . METHODS TO PREVENT RANCIDITY :

the reaction of formation of ammonia is N2+3H2-2NH3hencefor 1 mole nitrogen 3 mole hydrogen gives 2 moles of ammonia hence for 2 moles of nitrogen and 6 moles of hydrogen 4 moles of ammonia will be formed.

Ans :- Ovulation is the release of eggs from the ovaries. In humans, this event occurs when the ovarian follicles rupture and release the secondary oocyte ovarian cells. After ovulation, during the luteal phase, the egg will be available to be fertilized by sperm.

First we should calculate the number of moles of the gas under the given condition by the relation

PV = nRT

Here P = 7.6 * 10-10 mm Hg

= 7.6 *10-10/760 atm.

= 1 * 10-12 atm.

V = 1 litre

T = 273 + 0 = 273K

R = 0.082 litre atm./K/mol

Putting the values in equation

n = PV/RT

= 1 *10^{-12} *1/0.082 *273 moles

now since 1 mole = 6.023 * 1023 molecules

10^{-12}/0.082 *273 moles = 6.023 *1023 *10^{-12}/0.082 *273 molecules

= 2.7 * 10^10 molecules

Energy of one photon is given by the expression E = hVwhere, h = PlancKs constant = 6.636 x 10^-34J s-1V= Frequency of radiation = 5x 10^10Hz= 5 x 10^10s-1.E= (6.636 x 1034J s-1 x 5 x 10^10s-1)= 33.18 x 10^-24JOne mole of photon = 6.023 x 10^23photonsTherefore, Energy of one mole of photon = (6.023 x 10^23x 33.18 x 10^-24J) = 199.84 x 10-1JEnergy of one mole of photon = 199.84 kJ

बुध की पूर्व जन्म की कथा को जातक कहते हैं

किसी की पुर्व की कथा को जातक कहते है

Vapor-compression refrigerationorvapor-compression refrigeration system(VCRS),in which therefrigerantundergoesphase changes, is one of the manyrefrigeration cyclesand is the most widely used method forair-conditioningof buildings and automobiles. It is also used in domestic and commercial refrigerators, large-scale warehouses for chilled or frozen storage of foods and meats, refrigerated trucks and railroad cars, and a host of other commercial and industrial services.Oil refineries,petrochemicalandchemicalprocessing plants, andnatural gas processingplants are among the many types of industrial plants that often utilize large vapor-compression refrigeration systems.

The vapor-compression uses a circulating liquidrefrigerantas the medium which absorbs and removes heat from the space to be cooled and subsequently rejects that heat elsewhere. Figure 1 depicts a typical, single-stage vapor-compression system. All such systems have four components: acompressor, acondenser, athermal expansion valve(also called athrottlevalve or metering device), and an evaporator. Circulating refrigerant enters the compressor in the thermodynamic state known as asaturated vaporand is compressed to a higher pressure, resulting in a higher temperature as well. The hot, compressed vapor is then in the thermodynamic state known as a superheated vapor and it is at a temperature and pressure at which it can becondensedwith either cooling water or cooling air flowing across the coil or tubes. This is where the circulating refrigerant rejects heat from the system and the rejected heat is carried away by either the water or the air (whichever may be the case)

Let the mass of CaCO3 be X gramSo,the mass of MgCo3 will be 1.84-X grams.Now,X grams of CaCO3 will give Cao=56X/100 gAnd,1.84-X grams of MgCO3 will give MgO=40(1.84-X)/84 gTotal mass of residue is 0.96 gSo,o.56+40(1.84-X)/84 g=0.96 g.°. X=1gramHence, % composition of CaCO3 =1/1.84×100=54.35%And,% composition of MgCO3=100%-54.35%=45.65%

start button, is the answer.

It is not advisable to shut all the doors and windows during the storm because during a storm the pressure outside the house is very low or low pressure is created outside the house so inside the room the pressure is high so if all the doors and windows are shut then the air cannot go out and it will force up to break the doors and windows

4) 4:1 one is the answer

Payload can be explained as the difference between the mass of the air displaced and that of the mass of the balloon. It is important to note that the mass of the balloon is the sum total of mass of balloon skin itself and the mass of the Helium filled in it.

Hence, Payload = 5108 Kg - (50 Kg + 685.2 Kg) = 4372.8 Kg.

Payload can be explained as the difference between the mass of the air displaced and that of the mass of the balloon. It is important to note that the mass of the balloon is the sum total of mass of balloon skin itself and the mass of the Helium filled in it.

Hence, Payload = 5108 Kg - (50 Kg + 685.2 Kg) = 4372.8 Kg.

Anadiabatic processis one that occurs without transfer of heat or matter between a system and its surroundings & it helps in explaining first law of thermodynamics

. Hence, under adiabatic conditions,q= 0.

Mass = Number of neutrons + Number of proton

so for isobar it must be same,P = X+2 + Z-1 = X+Z+1S = X -4 + Z+5 = X+Z +1

option (2) is correct

option a is the correct answer

iska answer (c) hoga

c is the right answer........

option (b) is correct .Because if gas is compressed at constant temperature then the collision between the gas molecules will increase

There are twosalts that are usedin the creation of the black and white photography which are Silver chloride and the silver Iodide. Silver halides are quite sensitive to the light, and when the photon particles fall, they start photochemical reactions to complete the job.

The two salts used in black and white photography are:1. Silver Chloride (AgCl)2. Silver Iodide (AgI)When photons which comes from the sunlight, photons fall and photochemical reaction occurs.Reaction:2AgCl(s) ----> 2Ag(s) + Cl2(g)Due to sunlight.

Temple bells are made up of metals neither than wood because metals have a common physical property that is 'sonority '

continue ans. to the previous question

which means that all metals produce a ringing sound when we stuck it on its surface

thank you let god bless tour family

Bells are not made of wood but of metals because when they are banged they create good sound beacuse of their property of being sonorous.Non-metals do not posses this ability.

Soap is actually a sodium or potassium salt made by combining an organic acid with an alkali. Soap is prepared from oils or fats. Oils like olive oil, castor oil, palm oil or any animal fat can be used in the manufacture of soap.

When oils or fats are heated with a solution of sodium hydroxide, they split up to form sodium salt of the respective fatty acid.

Oil or fat + sodium hydroxide -> soap + glycerol

This process is called saponification.

After Saponification some amount of sodium chloride is also added to precipitate down the soap molecules

B) is the correct answer

no unbalance chemical equation

it is chapter 3 or not

A-18 ,B-63 I hope it's help

(a) Atomic mass of hydrogen = 1u, oxygen = 16 u Molecular mass of water = 2 × 1+ 1×16 = 18 u(b) The molecular mass of HNO3 = 1 + 14 + 48 = 63

A-18,B-63 I hope it's help

(a) Atomic mass of hydrogen = 1u, oxygen = 16 u Molecular mass of water = 2 × 1+ 1×16 = 18 u(b) The molecular mass of HNO3 = 1 + 14 + 48 = 63

b)

c wala do

The electron configuration for krypton is 1s22s22p63s23p63d104s24p6.answer is b

The dissociation of water at various temperatures changes because the (endothermic) enthalpy favours an increase in its value (Kw) with increasing temperature (acc LeChatelier principle).hence option a

Increasing the pressure on a reaction involving reacting gases increases the rate of reaction. Changing the pressure on a reaction which involves only solids or liquids has no effect on the rate.

An example

In the manufacture of ammonia by the Haber Process, the rate of reaction between the hydrogen and the nitrogen is increased by the use of very high pressures.

In fact, the main reason for using high pressures is to improve the percentage of ammonia in the equilibrium mixture, but there is a useful effect on rate of reaction as well.

Reaction rate = [H2S]2.[O2] If pressure is increased 3 times then (at same temperature) volume must decrease 3 times as well. So [H2S] and [O2] both increase 3 times. This is because [H2S] and [O2] is inversely proportional to volume. So reaction rate increases 3^2*3 =27 times

92 is the correct answer

correct answer is 1

please like and accept as best answer

answer is 1 because we take sin values in cos

cos^2(20)+ cos^2(70)/ sin^2(59)+ sin^(31)= cos^2(90-20)+ cos^2(70)/ sin^3(59)+ sin^2(90-31)= sin^2(70)+ cos^2(70)/sin^2(59)+ sin^2(90-31)= sin^2(70)+ cos^2(70) / sin^2(59)+ cos^2(59)= 1/1=1

Number of moles of CO2 = given weight/molecular weight= 22/44= ½Number of moles per V liters of volume = ½V2:Number of moles of H2 = given weight/molecular weight= 3/2Number of moles per V liters of volume = 3/2V3:Number of moles of N2 = given weight/molecular weight= 7/28= ¼Number of moles per V liters of volume = ¼V

Total number of moles = nCO2+ nH2+ nN2= ½V + 3/2V +¼V= 9/4V

Ratio of number of moles in comparison with total number of moles:= (½V)/(9/4V) : (3/2V)/(9/4V) : (¼V)/(9/4V)= 2/9 : 6/9 : 1/9

Ratio of active masses of gases = 2 : 6 : 1

1.I think the answer is one because the NO2 is a strong acid

benzoic sulphuric acid 3rd one is correct

HCOOH, H2CO3 does not present in the acid rains. HCOOH is called acetic acid.It was present in veniger.H2Co3 is called carbonic acid.It present in cool drinks.

Calculate the amount of benzoic acid (C6H5COOH) required for preparing 250mL of 0.15 M solution in methanol.

Solution

In this problem molarity = 0.15M is given



Let take volume of solution = 1 liter= 1000 mL

Us the above formula we get number of moles of solute = 0.15 moles

Molar mass of benzoic acid (C6H5COOH) = 12 × 6 + 5 × 1 + 12 + 16 + 16 +1

= 72 + 5 + 12 + 32 + 1

= 122 g mol-1

Mass of 0.15 mole of benzoic acid = number of moles x molar mass

=0.15 × 122 g

= 18.3 g

Thus, 1000 mL of the solution has mass of benzoic acid = 18.3 g

So250 mL of the solution has mass of benzoic acid = 18.3 × 250/1000

= 4.58 g.

First write the reaction:C2H5OH......+......CH3COOH......................=.CH3COOC2H5.....+.....H2Oa mole...................a mole.......................................0........................0......(initially)a-x......................a-x............................................x.................x..(At equilibrium)Here equimolar of both the reactants are mixed.

Let the number of mole of reactant is a, V is the volume of the solution and x is mole reacted till equilibrium is reached.[K={[H2O]*[CH3COOC2H5]}/{[CH3COOH]*[C2H5OH]}][K={x/V*x/V}{(a-x)/V*(a-x)/V}]

plz complete this solution i also done this but my answer is not coming.

Cl-CH2-COOH >HCOOH>CH3-COOH