InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3251. | 
                                    H3PO4 is more at than H2SO4 preparation of H2O2 | 
                            
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| 3252. | 
                                    The normality of 10 ml of a '20 V H2O2 solution is(1) 1.79 (2) 3.58 (3) 60.86 (4) 6.086 | 
                            
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                                   Answer»  20VH2O2 means that 1 litre of H2O2 solution would produce 20 litre of Oxygen. 2H2O2.....................>H2O+ O2 From the equation it is clear that 2 moles of H2O2 produce 1 mol of O2But 20V H2O2 will produce 20 litre of oxygen for 1 litre of H2O2.............................................⇒ (20litre/24.4litre) mol of oxygen liberated for 1 litre of H2O2So in 1 litre solution of H2O2, moles of H2O2=2*moles of oxygen = (2*20/24.4) mol/litre=1.67Mn-factor of H2O2=2So, normality=Molarity*n-factor=1.67*2=3.34N  | 
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| 3253. | 
                                    . The pH of a solution of H 2SO4 is 1. Assuming complete ionisation, find the molarity of H 2S04solution:(a) 0.1(b) 0.2(c) 0.05(d) 2.0 | 
                            
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                                   Answer»  so Option c is right  | 
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| 3254. | 
                                    Ex.2 The density of a solutioncontaining 13% by mass of sulphuricacid is 1.09 g/mL. Calculate themolarity and normality of thesolution(A) 1.445 M(B) 14.45 M(C) 144.5 M(D) 0.1445 M | 
                            
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| 3255. | 
                                    Normality of 0.1M H3PO4 is | 
                            
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                                   Answer»  Normality =molarity×n -factor And for any phosphorus containing acid ,n-factor =(no.of o-atoms-1)=(4-1) =3. Molarity =0.1M NORMALITY=0.1×3=0.3N  | 
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| 3256. | 
                                    7.8 Distinguish between homogeneous andheterogeneous catalysts. | 
                            
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                                   Answer»  Homogeneous catalysistakes place when thecatalystand the other reactants are all dissolved in the same solution.Heterogeneous catalysistypically involves the use of acatalystthat is insoluble, or perhaps only weakly soluble, in the solution in which the reaction takes place.  | 
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| 3257. | 
                                    Normality of 100 volume H2O2 is. | 
                            
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                                   Answer»  VOLUME STRENGTH= Normality x 5.6 OR Vol .Str.= MOLARITY x n-factor of H202 x 5.6 =MOLARITY x 11.2 therefore 100= Nx 5.6 Ans:N=17.8 n-factor basically tells the basicity of acid or acidity of base For eg: Monobasic acids: HCl,HNO3 They give only 1 H+ ion. Therefore its n-factor is 1/basicity=1 Dibasic acids like H2SO4 have n-factor =2 /basicity=2 Tribasic like H3PO4 have n-factor=3/basicity=3  | 
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| 3258. | 
                                    Q. 19. Explain:a) Molarityb) Molalityc) Normality | 
                            
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                                   Answer»  1.Molality, also called molal concentration, is a measure of the concentration of a solute in a solution in terms of amount of substance in a specified amount of mass of the solvent. This contrasts with the definition of molarity which is based on a specified volume of solution. 2.In chemistry,molarityis a concentration unit,definedto be the number of moles of solute divided by the number of liters of solution. 3.Normality is a measure of concentration equal to the gram equivalent weight per liter of solution. Gram equivalent weight is the measure of the reactive capacity of a molecule. The solute's role in the reaction determines the solution's normality. Normality is also known as the equivalent concentration of a solution.  | 
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| 3259. | 
                                    Ae Calculate normality of 9.8 g ofH2So, in 250 ml ofsolution? | 
                            
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                                   Answer»  Moles of solute = Mass of solute / Molar mass of solute= 9.8 g / 98 g/mol= 0.1 mol Volume of solution = 25 cm³ = 0.025 Litres Molarity = Moles of solutes / Volume of solution in litres= 0.1 mol / 0.025 litres= 4 M Molarity of given solution is 4 M  | 
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| 3260. | 
                                    The number of moles of H2 in 0.224 L of hydrogengas at STP (273 K, 1 atm) assuming ideal gasbehaviour is:MLNR 941 | 
                            
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                                   Answer»  USING gas law PV = nRT => 1*0.224 = n × 0.082× (273)=> n = 0.224/0.082*(273) = 0.01 moles  | 
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| 3261. | 
                                    Metal 'A'has electronic configuration 2, 8, 1 and metal B' has electronic configuration 2,8, 8, 2. Out of these, which metal is more reactive? Write the reaction of this metal withdilute HCI acid.. | 
                            
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                                   Answer»  Metal A is Sodium (Na) : 2,8,1Metal B is Calcium (Ca) : 2,8,8,2.Metal A (Sodium) is more reactive than metal B (Calcium). Reaction: -i. Sodium metal reacts violently with dilute hydrochloric acid to form sodium chlorides and hydrogen.2Na(s) + 2HCl(aq) → 2NaCl(aq) + H2(g) ii. Calcium reacts less vigorously to form calcium chloride and hydrogen.Ca + 2HCl → CaCl2 + H2  | 
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| 3262. | 
                                    24. (a) Write the electronic configuration of Cr(Z 24). Why isit different from the expected configuration? | 
                            
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                                   Answer»  it's cr not Ar  | 
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| 3263. | 
                                    Give a short definition of Homogeneous and Heterogeneous mixture... | 
                            
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                                   Answer»  HomogeneousmixtureThese are the types of mixtures in which the components mixed are uniformly distributed throughout the mixture.Ex : rainwater, vinegar HeterogeneousmixtureThis is a type of mixture in which all the components are completely mixed and all the particles can be seen under a microscope. We can easily identify the components and more than one phase can be seen by naked eyes.Ex : sea water, Thanks a lot  | 
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| 3264. | 
                                    Give a short and easy definition of Colloid.... | 
                            
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                                   Answer»  combination of molecule mixed through another substance that will not settled out Thank you so much A colloid is a mixture with particles of one component suspended in another component. Some examples include whipped cream, mayonnaise, milk, butter, gelatin, jelly, muddy water, plaster, coloured glass, and paper. In a colloid, the size of the particles is between that of a solution and a suspension. The colloid consists of a dispersed phase and a continuous phase. Thanks a lot Omvati  | 
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| 3265. | 
                                    normality definition | 
                            
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| 3266. | 
                                    A vessel of capacity 400 cm^3 contains hydrogen gas at 1 atm. pressure at 7Corder to expel 28.57 cm^3 of the gas at the same pressure to what temperature, thevessel should be heated? | 
                            
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| 3267. | 
                                    TIPS ANDhich we can make changes in the. These includedesktop.Safetyand | 
                            
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                                   Answer»  Hibernation is a mode in which a computer is turned off but saves its state to resume when it is turned on again thank you  | 
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| 3268. | 
                                    (b) A gas cylinder can hold 1 kg of hydrogen at room temperature and pressure:Find the number of moles of hydrogen present.(0)(inWhat weight of CO2 can the cylinder hold under similar conditions of temperature andpressure?(H-1, C 12, 0 16) | 
                            
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| 3269. | 
                                    write the correct electronic configuration for Sodium. | 
                            
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| 3270. | 
                                    write the correct electronic configuration of sodium? | 
                            
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                                   Answer»  Ans :- sodium electron configuration will be 1s22s22p63s1. the correct electronic configuration is 2, 8,1 Atomic no.of sodium is 11  | 
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| 3271. | 
                                    1)Atomic number of an element is 17. Identify the element, write it's electronicconfiguration and mention its valency. | 
                            
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                                   Answer»  nice fashion but I don't know what is a question so I don't do you feeling now my compartment how is my compartment in math takleef hello hello mujhe bahut takleef ho rahi hai main kya karoon kya Mai Mera compartment laga hai math math math Mera in maths my compartment p 500 rupees taken by me from me due to compartment does it ok  | 
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| 3272. | 
                                    The number of atoms in 4.25 g of NH, is approximately29 | 
                            
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                                   Answer»  Molecular mass of ammonia= 14+3=17 In 1 molecule (nh3) there are 1+3=4 atoms 1 mole (17 g) has Avogadro number of molecules 17 g= 1 mole 4.25g=4.25/17=0.25 moles 1 mole = 4×6.022×10^23 atoms 0.25 or 1/4 mole =6.022×10^23 atoms  | 
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| 3273. | 
                                    2. Calculate the number of milliequivalents in 15g of potassium chloride (Eq. mass of potassium chlorideis 74.5) | 
                            
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| 3274. | 
                                    What is atomic number , mass number , and atomic mass ? | 
                            
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                                   Answer»  Atomic massis the weighted averagemassof anatomof an element based on the relative natural abundance of that element's isotopes. Themass numberis a count of the totalnumber of protons and neutrons in anatom's nucleus Theatomic numberuniquely identifies a chemical element. In an unchargedatom, theatomic numberis also equal to thenumberof electrons thank u 😃😃  | 
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| 3275. | 
                                    ASSIGNMENTX, Y and Z are the elements of a Dobereiner's triad. If the atomic mass of x is 7 and thatis 39, what should be the atomic mass of y? | 
                            
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| 3276. | 
                                    b. Calculate the amount of oxygen gasand potassium chloride formed duringthe decomposition of 49 g of potassiumchlorate. (Atomic mass of potassium39; oxygen 16 and chlorine 35.4) | 
                            
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| 3277. | 
                                    What type of reaction show in electro lysis of water what is the moleratio of H2 and O2 in it.Q.2 | 
                            
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                                   Answer»  In the electrolysis of water (a) the gas is collected at cathode is Hydrogen , H₂And the gas collected at anode is oxygen ,O₂ (b) first of all we should we reaction between Hydrogen and oxygen to form water :- 2H₂ + O₂ ⇔ 2H₂O you can see that, 2moles of H₂ and 1 mole of O₂ react to form 2moles of H₂O we can also say that , if we break 2moles of water (using electrolysis ) , we gain 2hole of H₂ and one mole of O₂ Here, P, T, are constant , So, Volume is directly proportional to number of moles ∴ if we break 2V of water, we get 2V of H₂ and 1V of O₂ .That's why the volume is collected at one electrode is double than other .  | 
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| 3278. | 
                                    48 \times 10 ^ { 4 } | 
                            
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                                   Answer»  Average reaction rate= Final concentration-(-initial concentration)/time = 0.032+0.044/25 = 0.00048 mol/lit/min  | 
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| 3279. | 
                                    Give the reason offolng1 Tensitle strength of metals | 
                            
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                                   Answer»  The termtensile strengthrefers to the amount oftensile(stretching)stressamaterialcan withstand before breaking or failing. ...Yield strengthrefers to the amount ofstressamaterialcan withstand without permanent deformation. Metalis shiniest when it is first cut. Exposure to elements such as oxygen and carbon causemetalsto lose thelusteron the surface because the elements cause a tarnish that reduces the freedom of the electrons to vibrate. The tarnish is removable through polishing or using a chemical treatment  | 
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| 3280. | 
                                    An element 'X' has mass number 35 and the number of neutrons, is 18.Identify the group number and period of X | 
                            
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                                   Answer»  Solution:Group 17Period 3 Explanation:Atomic number of X = Mass number of X – No. of neutrons Atomic number of X = 35 - 18 = 17 Electronic configuration = 2, 8, 7 Group number = 17 Period Number = 3  | 
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| 3281. | 
                                    How can you determine number of neutrons inthe nucleus of an atom from the knowledge ofmass number and atomic number? | 
                            
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                                   Answer»  To calculate the number of neutrons in the nucleus of an atom is simple. You take the atomic, or proton number of the element, and you subtract it from the element's mass number. For example, take the isotope of copper, Cu-63. It contains 29 protons and has a mass number of 63, as suggested in the name. In order to calculate the number of neutrons, you must take its mass number (63) away from its atomic number (29), which leaves you with 46. Therefore, Cu-63 contains 29 protons, and 46 neutrons.  | 
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| 3282. | 
                                    This iCaTO12X 11 atom ofC will weigh6.022 Ă 1023- 1.99x 10 2gWhich has more number of atoms, 100sodium or 100 g of iron? [Given, atomic maof Na 23 u and Fe 56 u] | 
                            
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                                   Answer»  In order to solve this problem, we should convert 100 grams of sodium into moles of sodium, and also 100 grams of iron into moles of iron. The element having more moles will have more atoms. Please note that since the atomic mass of sodium is 23 u , the molar mass of sodium will be 23 g / mol. Similarly, since the atomic mass of iron is 56 u , the molar mass of iron will be 56 g / mol. We will now calculate the moles of sodium atoms (Na) and iron atoms (Fe), one by one. (i) Mass of sodium = Mass of sodium / Molar mass of sodium = 100/23 = 4.34 (ii) Moles of iron = Mass of iron / Molar mass of iron = 100/56 = 1.78 We find that 100 grams of sodium contain 4.34 moles of atom whereas 100 grams of iron contain 1.78 moles of atoms. Since 100 grams of sodium has more moles, it contains more atoms than 100 grams of iron. Hit like if you find it useful!  | 
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| 3283. | 
                                    3. An element "X" has mass number 35 and the number of neutrons, is 18. Identify the group number andperiod of "X"12] | 
                            
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                                   Answer»  Given :Mass number of element is 35Number of neutrons= 18 Formula to find number of protons: Mass number = number of protons + number of neutrons.35=× +18×=35 - 18X=17.Number of protons =17 and number of electrons also will be 17 as atom is electrically neutral. Hence Element is chlorine Electronic configuraton:1s2 2s2 2p6 3s2 3p5 Group number= 17Period number =3Valency =1  | 
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| 3284. | 
                                    . An element X has mass number 35 and the number of neutrons in its atom is 18.(a) To which group of the periodic table element X belongs?(b) To which period of the periodic table element X belongs?(c) What will be the formula of chloride of element X? | 
                            
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                                   Answer»  Mass number of element is 35Number of neutrons= 18 Formula to find number of protons: Mass number = number of protons + number of neutrons.35=× +18×=35 - 18X=17.Number of protons =17 and number of electrons also will be 17 as atom is electrically neutral. Hence Element is chlorine Electronic configuraton:1s2 2s2 2p6 3s2 3p5 Group number= 17Period number =3Valency =1 thank you.  | 
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| 3285. | 
                                    What mass of NaCl must be dissolved in65.0 g of water to lower the freezing point ofwater by 7.50°C? The freezing pointdepression constant (K,) for water is1.86°C/mol. Assume van't Hoff factor forNaCl is 1.87. (molar mass of NaCl58.5 g mol-1). All India 2011, 2010; Foreign 2010 | 
                            
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                                   Answer»  pura solve hi krke dedete bhai  | 
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| 3286. | 
                                    Express the relation between depression in freezing point and molar mass of the solu | 
                            
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| 3287. | 
                                    Write the dimension and unit of the mechanical equivalent (J) ofenergy | 
                            
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                                   Answer»  Mechanical equivalentof heat (J) is dimensionless quantity. SIunit of Mechanical equivalentof heat (J) is Joules/calorie (J calorie-1 ).  | 
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| 3288. | 
                                    State the rule regarding attraction andrepulsion of charges. | 
                            
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| 3289. | 
                                    8. Calculate the group number, block and period number of zinc and chromium. | 
                            
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                                   Answer»  Both are in D block and 4th periodgroup number forZn-13Cr-8  | 
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| 3290. | 
                                    2 gm of urea when dissolved in 200 g of certain solventdecreases the freezing point by 0.2°C .3.2 g of a unknown substance when dissolved in 160 g of same solvent depresses the freezing point by 0.3°C. Calculate molar mass of unknown substance . | 
                            
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                                   Answer»  This is wrong friend  | 
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| 3291. | 
                                    What is Electro chemical series | 
                            
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                                   Answer»  Electrochemical series is a series of chemical elements arranged in order of their standard electrode potentials. The hydrogen electrode H+(aq) + e-→←1/2H2(g) is taken as having zero electrode potential. An electrode potential is, by definition, a reduction potential. Elements that have a greater tendency than hydrogen to lose electrons to their solution are taken as electropositive; those that gain electrons from their solution are below hydrogen in the series and are called electronegative. The series shows the order in which metals replace one another from their salts; electropositive metals will replace hydrogen from acids.  | 
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| 3292. | 
                                    About electro magnetic effect | 
                            
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                                   Answer»  The electromagnetic force usually exhibits electromagnetic fields such as electric fields, magnetic fields and light, and is one of the four fundamental interactions (commonly called forces) in nature.  | 
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| 3293. | 
                                    11. What is electro osmosis ? Explain | 
                            
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                                   Answer»  Electroosmotic flow (or electro-osmotic flow, often abbreviated EOF; synonymous with electroosmosis or electroendosmosis) is the motion of liquid induced by an applied potential across a porous material, capillary tube, membrane, microchannel, or any other fluid conduit.  | 
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| 3294. | 
                                    The density of 3M solution of sodium thiosulphate (Na2S2O3) is 1.58 g/ml. Calculate(i) amount of Na2S2O3 in % w/w(ii) mole fraction of Na2S203(ii) molality of Na and S2O3 ions. | 
                            
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| 3295. | 
                                    a The density of 3M solution of sodium thiosulphate (Na2S0s)is1.58 g/ml.Calculate(i) amount of Na2S2O3 in % w/we (ii) mole fraction of Na2S203o (ii) molality of Na* and S2032- ions. | 
                            
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                                   Answer»  Let us consider 1.0 L solution for all the calculation. (i) Weight of 1 L solution = 1580 g Weight of Na2S2O3 = 3 × 158 = 474 g ⇒ Weight percentage of Na2S2O3 = (474/1580 )× 100 = 30%(ii) Weight of H2O in 1 L solution = 1580 – 474 = 1106 g Mole-fraction = 3/(3+ 1106/18) = 0.0465 (iii) Molality of Na+ = (3 ×2)/1106 × 1000= 5.42 m Molality of S2O_3^(2-) = (3 )/(1106 ) × 1000 = 2.71 m  | 
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| 3296. | 
                                    Why is sodium thiosulphate not considered as a primary standard? | 
                            
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                                   Answer»  Sodium thiosulphate comes as a nominal pentahydrate. But it is quite difficult to ascertain the water of crystallization, as the exact composition of the pentahydrate is highly dependent on temperature and humidity.In simpler words, when the humidity is high the crystals absorb water and at lower humidity and higher temperature there is loss of water of crystallization.We can thus not know exact composition to get an exact molecular weight. Without exact molecular weight one cannot prepare a standard solution.  | 
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| 3297. | 
                                    The density of a 3M sodium thiosulphate solution is 1.25 gm cm. Calculate themolalities of Na" and S O ions; and mole fraction of sodium thiosulphate. | 
                            
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                                   Answer»  (i) Mole fraction = Moles of substance/Total moles (ii) 1 mole of Na2S2O3gives 2 moles of Na+and 1 mole S2O32- Molecular wt. of sodium thiosulphate solution (Na2S2O3) = 23 * 2 + 32 * 2 + 16 * 3 = 158 (ii) Mass of 1 litre solution = 1.25 * 1000 g = 1250 g [∵ density = 1.25g/l] Mole fraction of Na2S2O3 = Number of moles of Na2S2O3/Total number of moles Moles of water = 1250 – 158 *3/18 = 43.1 Mole fraction of Na2S2O3= 3/3 + 43.1 = 0.065 (iii) 1 mole of sodium thiosulphate (Na2S2O3) yields 2 moles of Na+and 1 mole of S2O2-3 Molality of Na2S2O3= 3 * 1000/776 = 3.87 Molality of Na+= 3.87 * 2 =7.74m Molality of S2O2-3=3.87m  | 
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| 3298. | 
                                    One mole of a mixture ofCO and CO2 requires exactly 20 gramof NaOH in solution for complete conversion of all the Cointo Na, CO, How many moles more of NaOH would itrequirefor conversion into Na2CO3 if the mixture (one mole) iscompletely oxidised to CO,(a) 0.2(c) 0.418.(b) 0.5uon ofwate | 
                            
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                                   Answer»  Let CO = x moles So, CO2= 1-x moles. Now 2NaOH + CO2 ----> Na2CO3 + H2O2 moles NaOH react with 1 mole CO2So, 20g NaOH = 0.5 Mole NaOH will react with 1/4 = 0.25 mole CO2 = 1-x moles So, x=0.75moles ie moles of CO = 0.75 moles.Now On oxidation CO + 1/2O2 -----> CO20.75------------------> CO2(0.75moles)Total Moles of CO2 = 0.25 + 0.75 = 1mole1 mole CO2 will react with 2 moles NaOH ie 40 x 2 = 80g.  | 
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| 3299. | 
                                    (Q18)pimCrystal str. of MgO is identical to that of NaCl , if the edge length of the unit cell is 421[1] 3.56 gm/cms [2] 8.24 gm/cmthe density would be?cm | 
                            
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| 3300. | 
                                    13. A certain current liberated 0.504 gm ofhydrogen in 2 hours. How many gramsof copper can be liberated by the samecurrent flowing for the same time in a coppersulphate solution | 
                            
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                                   Answer»  in the same time 2 hours the copper will be 0.502 2 hours the copper be 0.502 2 hours the copper will be 0.502 16.0 gram is the answer of the 0.502 is the right answer In two hrs the copper will be 0.52  | 
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