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Quantum numbers are a set of values that describes the state of an electron including its distance from the nucleus, the orientation and type of orbital where it is likely to be found, and its spin. The Pauli exclusion principle states that no two electrons in an atom can have the same set of quantum numbers.

We have 200 mg of carbon dioxide. The molar mass of carbon dioxide is 44g. That is there are 6.022 × 1023molecule of CO2in 44g of CO2. Thus

number of moles of CO2in 44g of CO2= 1

number of moles of CO2in 1g of CO2= 1 / 44

number of moles of CO2in 200 mg or 200 × 10-3g of CO2= (1 × 200 × 10-3) / 44

= 4.545 × 10-3moles

We are given that after removing X molecules from 200 mg of CO2, 2.89 X 10-3moles of CO2are left. Therefore, number of moles of CO2removed will be

= total number of moles of CO2- number of moles of CO2left

= 4.545 × 10-3- 2.89 × 10-3

= 1.655 × 10-3moles of CO2

Thus, 1.655 × 10-3moles of CO2were removed. The number of molecules X can be calculated by simply multiplying this quantity with Avogadro's number. So, number of CO2molecules removed will be

= 1.655 X 10-3X 6.022 X 1023

= 9.969X 1020molecules of CO2 ~ 10^20

Hence, option (a) is correct.

Alkyl halides are formally derived fromalkanesby exchanging hydrogen for halogen (fluorine,chlorine,bromine, andiodine). Depending on the degree of substitution at thecarbon atomcarrying the halogen, alkyl halides are classified into primary, secondary and tertiary alkyl halides.

In Corey House synthesis of alkane, alkyl halide reacts with lithium dialkyl cuprate.

R2CuLi + R’X → R-R’ + RCu + LiX

option c

Ans :- Nomenclature of Alkyl Halides

Alkyl halides are formally derived from alkanes by exchanging hydrogen for halogen (fluorine, chlorine, bromine, and iodine). Depending on the degree of substitution at the carbon atom carrying the halogen, alkyl halides are classified into primary, secondary and tertiary alkyl halides.

Vinyl halides are often classified as the fourth type of alkyl halides.

In the generally accepted nomenclature of alkyl halides, the name of the alkyl residue is followed by the name of the halide,e.g.methyl iodide and ethyl chloride. The IUPAC nomenclature (shown in brackets in the illustration below), considers an alkyl halide a substituted alkane,i.e.halogens are treated the same way as alkyl groups. The name of the halogen is followed by the name of the alkane, for example, iodomethane and chloromethane. If an alkyl halide contains more than one halogen, the halogen names are noted in alphabetical order, such as 1-chloro-2-iodobutane.

In the nomenclature ofunsaturatedalkyl halides, unsaturated bonds have a higher priority than halogen substituents. This requires special attention when numbering the carbon chain.

Some commonly used chlorinated organic solvents, such as carbon tetrachloride (tetrachloromethane), chloroform (trichloromethane) and methylene chloride (dichloromethane), are known more by their trivial name than by their IUPAC name.

Alkyl halides are formally derived fromalkanesby exchanging hydrogen for halogen (fluorine,chlorine,bromine, andiodine). Depending on the degree of substitution at thecarbon atomcarrying the halogen, alkyl halides are classified into primary, secondary and tertiary alkyl halides.

option A. n= 3 , 3rd orbital l= 1 , p orbital mi = 0 , pxy subshell

its is 3pxy

option I is the correct answer

1 orbital is the answet

option (3) 3 is correct answer

n=2,l=1=2pn=4,l=0=4sn=5,l=3=5fn=3,l=2=3d

a. -2p,/ b. -4s,/ c. -5f,/ d. - 3d

When petrol is dropped on the road during a rainy day, a thin layer ofoilwill appearon thewater surface. Both the top and bottom surfaces of thisoil filmcan reflect light.The wavelength corresponding to the constructive interference also differs and this causes the reflected light to have variouscolours.

Lead is more reactive than copper. Hence, when a strip of lead is placed in a solution of copper chloride, it will displace copper from the salt and instead form lead chloride and copper metal. Following is the chemical equation for the reaction

Pb + CuCl2→ PbCl2+ Cu

Ru, Rh, Pd, Os, Ir and Pt can be applied on copper to make it attract rice grains.

option 4 is correct it is strongly basic medium

(4) is correct answer

(4) is correct answer

if ph value more than 7 then tha solution is dasic . in this condition the ph value is 13 then tihis solution is strongly basic

The reaction will be

2KMnO4 + 5 H2SO3 --> K2SO4 +2 MnSO4 +2 H2SO4 + 3H2O

As 5 mole of sulphite reacts with 2 mole of KMnO4

Then 1 mole will react with 2/5 mole of KMnO4

in what way you write the reaction?

thaku

At room temperature,

Kw= [H+][OH-]=10^-14 .

It is given that[H+]=10^-9, hence [OH-]=10^-5.

So, pOH=-log[OH-]= 5. But pH+pOH=14. So pH= 9.

it will be basic

ph range is from 1 to 14 where 1-3 shows strong acidic nature and 12-14 shows strong basic nature

LPG is cleaner fuel as it releases much less pollutants than wood. Thus, using LPG as fuel makes our environment pollution free.

Iron is solidWater is liquidLog is gasDue to intermolecular attraction

worst answer

rate of reaction for 2nd order is given by

R = k[A]²

so when [A] → 2[A]

R = k[2A]² = 4k[A]²

option d

The acidic hydrolysis of ethyl acetate is a first order reaction because water is present in excess and does not affect the rate of reaction and acid is present in trace amounts while the alkaline hydrolysis of esters is a second order reaction because in alkaline hydrolysis the amount of NaOH influences the rate of reaction.

thanku very much

can you please tell me why base is consumed fully and not h+

Given weight = 9g molecular weigh = 2 + 16= 18g no. of molecules = 9/18=0.5

molecules

The molar mass of nitrogen is 14 g while that of hydrogen is 1g. The chemical formula for ammonia is NH3, so the molar mass of ammonia will be

= molar mass of nitrogen + 3 X (molar mass of hydrogen)

= 14 + 3 X (1) = 17 g

Thus the molar mass of ammonia is 17 g. This means that there are 6.023 X 1023molecules of ammonia present in 17 g of ammonia. That is

17 g of NH3= 6.023 X 1023molecules of ammonia

Atomicity of sucrose (C12H22O11) is = 12 + 22+11 = 45

Molarity = concentration/ Molecular weightMolecular weight = 342.2965Concentration = 300g/L (30%)Therefore, Molarity = 300/342.2965 = 0.8764 moles/Litre

what will be the final equation then.thanks for answering.

pKa = -log(10)[Ka]

Ka for acetic acid is [H+][CH3COO-]/[CH3COOH] where [] indicates the concentration.

pKa = log(10)[CH3COOH] - log(10)[H+] - log(10)[CH3COO-]

as [H+] = [CH3COO-]

pKa = log(10)[CH3COOH] - 2*log(10)[H+]

For acetic acid pKa = 4.76 and -log(10)[H+] = pH

4.76 = log(10)(0.1) + 2*pH

=> 2*pH = 4.76 + 1

=> pH = 5.76/2

=> pH = 2.88

The required pH of 0.1 M solution of acetic acid is 2.88

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enthalpy of combustion of ethyl alcohol C2H5oH is _ 950 kj mol .how much is evolved whemn one gram of ethyl alcohol burns ?

k = 2.5 × 10−4mol−1L s−1Order of reaction = 0Decomposition reaction of NH3Here NH3 has 2 mol then N2and H2has 1 and 3 moles respectivelyUse the formula of rate of reactionUse this formula we getAnother formula of rate, Rate = k[NH3]xGiven that order of reaction x = 0Plug the values we getPlug the value of k we getRate of production of N2= k = 2.5 × 10−4mol L-1s−1Rate of production of H2= 3k = 3 x 2.5 × 10−4mol L-1s−1= 7.5 × 10−4mol L-1s−1

ans is option B

Here you can see that the 2nd equation is reverse of 1st and the coefficients is reduced by 1/2

so, if k1 = 100the k2 will be (1/100)½ = 1/10= 0.10

option C

option 4 is correct

options 3 is correct because CaO is a solid and it is not considered so rate of forward reaction is K[CO2]

49 bcoz in first reaction there is two ab and product produced in 1:1 ratio and in second eqn ab is 1 it converts in 1/2:1/2

your ans is wrong

equilibrium constant for 1st is written as Keq = [A2]¹[B2]¹/[AB]²

and for 2nd reaction it is

K'eq = A2]½[B2]½/[AB]

that is K'eq = √Keq = √49 = 7

option 1

Ans :- Characteristics of Equilibrium Constant: It has a definite value for every chemical reaction at a particulartemperature. It is independentof initial concentrations of the reacting species. It changes with the change in thetemperature.

C answer is right.

option cas the keq is given by the concentration of products raise to power there number of moles/concentration of reactants raise to power there moles