InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 501. |
The correct increasing order of trans-effect of the following species isA. `NH_(3)gtCN^(-)gtBr^(-)gtC_(6)H_(5)^(-)`B. `CN^(-)gtC_(6)H_(5)^(-)gtBr^(-)gtNH_(3)`C. `Br^(-)gtCN^(-)gtNH_(3)gtC_(6)H_(5)^(-)`D. `CN^(-)gtBr^(-)gtC_(6)H_(5)^(-)gtNH_(3)` |
|
Answer» Correct Answer - B Trans effect is the effect of a coordinated group upon the rate of substitution at the position trans to itself in a square or octahedral complex. As the rate of substitution of the trans ligand increases, the intensity of trans effect also increases. Thus, correct order is, `CN^(-)gtC_(6)H_(5)^(-) gtBr^(-)gtNH_(3)` |
|
| 502. |
A magnetic moment of 1.73 B.M. will be shown by one among the following:A. `[Ni(CN)_(4)]^(2-)`B. `TiCI_(4)`C. `p[CoCI_(6)]^(4-)`D. `[Cu(NH_(3))_(4)]^(2+)` |
|
Answer» Correct Answer - D For the compounds of the first series of transition metals, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the spin only 2 formula: `mu = sqrt(n(n + 2))` where n is the number of unpaired electrons and `mu` is the magnetic moment in units of Bohr magneton (BM) `1.73 = sqrt(n(n + 2))` `(1.73)^(2) = n(n +)` `n = 1` Thus a single unpaired electron has a magnetic moment of `1.73` Bohr magnetons (BM). Because `CN^(-)` is a strong field ligand, `[Ni(CN)_(4)]^(2-)` containing `Ni^(2+) (3d^(8))` , is a square planar complex containing zero unpaired electrons: `t_(2g)^(6)d_(z^(2))^(2)` . `TiC1_(4)` containing `Ti^(4+)` `(3d^(0))` also has zero unpaired electrons. Because `C1^(-)` is a weak field ligand, `[CoC1_(6)]^(4-)` containing `Co^(2+)` `(3d^(7))` is a high spin complex with two unpaired electrons. `[Cu(NH_(3))_(4)]^(2+)` containing `Cu^(2+) (3d^(9))` , is a square planar complex due to unsymmetrical electronic arrangement. Thus it has one unpaired electron with both types of ligands: weak field as well as strong field. |
|
| 503. |
Which of these statements about `[Co(CN)_6]^(3-)` is true?A. `[Co(CN)_(6)]^(3-)` has no unpaired electrons and will be in a high-spin configurationB. `[Co(CN)_(6)]^(3-)` has no unpaired electrons and will be in a low-spin configurationC. `[Co(CN)_(6)]^(3-)` has four unpaired electrons and will be in a lowspin configurationD. `[Co(CN)_(6)]^(3-)` has four unpaired electtrons and will be in a high-spin configuration |
|
Answer» Correct Answer - B Here cobalt is in `+3` oxidation state and has the electronic confuiguration `3d^(6)` . Since `CN^(-)` is a strong field ligand, all the d-electrons are paired leading to `d^(2)sp^(3)` hybridisation. Thus, `[Co(CN)_(6)]^(3-)` having no unpaired electrons is called an inner orbital or low spin or spin paired complex. |
|
| 504. |
In the manufacture of ions a gas `(A)` is formed in the zone of combustion of the blast furnace The gad `(A)` formed in the zone of combustion of the blast furnace. The gas `(A)` reacted with coke in the zone of fusion to from another gas `(B).X` moles of `(B)` reacts with iron at `200^(@)C` and `100` atm pressure to form a compounds `(C)` The d orbital (s) involved in the formation of the complex `(C)` will be (a) `d_(z)2` (d) ``d_(xy)` and `d_(x)2-y2` (c) ``d_(x)2-y2` and `d_(z)2` (d) `d_(x)2-_(y)2` . |
|
Answer» Correct Answer - A `CO_(2)+Crarr2CO` `underset((B))(5CO)+Feunderset(100atm)overset(200^(@)C)rarrFeunderset((C))((CO)_(5)` Hybridisation of ` (C )` dsp^(3)` d -orbital `dz^(2)` Geometry =Trigonal bipyramid . |
|
| 505. |
The complex used as an anticancer agent isA. `mer-[Co(NH_(3))_(3)CI_(3)]`B. `cis-[Pt(NH_(3))_(2)CI_(2)]`C. `cis-K_(2)[PtBr_(2)CI_(2)]`D. `Na-(2)[CoCI_(4)]` |
|
Answer» Correct Answer - B A very important medical use of `Pt(+2)` compounds is the use of cis isomer of `[Pt(NH_(3))_(2)C1_(2)]` as an anti-canceer drug for treating several types of malignant tumours. The trans isor is ineffective. The cis isomer is called cisplatin and is highly toxic. It is injected into the bloodstream and the more reactive C1 group (ligands) bond to a N atom in guanosine (part of the DNA molecule). The cisplatin can bond to two different guanosine units and by bridging between them it upsets the normal reproduction of DNA. Those cell which are undergoing cell division are attacked by cisplatin. Tumours usually growing rapidly, but so also are the bone marrow cells (producing red and white blood cells) and cell in the testes (producing sperms), so these are also affected. Dramatic results are possible, and a large number of patients are completely cured. There is a critical balance between giving enough cisplatin to kill the tumour and leaving sufficient white blood cells to protect the body from attack by bacteria and viruses. |
|
| 506. |
Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. `CoCl_(3)cdot3NH_(3)`B. `CoCl_(3)cdot4NH_(3)`C. `CoCl_(3)cdot5NH_(3)`D. `CoCl_(3)cdot6NH_(3)` |
|
Answer» Correct Answer - A `[Co(NH_(3))_(6)]Cl_(3)to[Co(NH_(3))_(6)]^(3+)+3Cl^(-)` `[Co(NH_(3))_(3)]Cl_(3)to[Co(NH_(3))_(3)Cl_(3)]` `[Co(NH_(3))_(4)Cl_(2)]Clto[Co(NH_(3))_(4)Cl_(2)]^(+)+Cl^(-)` `[Co(NH_(3))_(5)Cl]Cl_(2)to[Co(NH_(3))_(5)Cl]^(2+)+2Cl^(-)` So, `[Co(NH_(3)_(3)Cl_(3)]` does not ionise so does not give test for chloride ions |
|
| 507. |
Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. `CoCI_(3)` . `6NH_(3)`B. `CoCI_(3)` . `3NH_(3)`C. `CoCI_(3)` . `4NH_(3)`D. `CoCI_(3)` . `5NH_(3)` |
|
Answer» Correct Answer - B No ppt. of AgC1 will be obtained if all the chlorine particles are part of the coordination sphere as in the complex `CoC1_(3)` . `3NH_(3)` or `[Co(NH_(3))_(3)C1_(3)]` . `CoC1_(3)` . `6NH_(3)` `implies [Co(NH_(3))_(6)]C1_(3) implies 3` mol AgC1 `CoC1_(3)` . `implies [Co(NH_(3))_(4)C1_(2)]C1 implies 1` mol AgC1 `CoC1_(3)` . `5NH_(3) implies [Co(NH_(3))_(5)C1]C1_(2) implies 2` mol AgC1 |
|
| 508. |
Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. (a) `CoCl_3*5NH_3`B. (b) `CoCl_3*6NH_3`C. (c) `CoCl_3*3NH_3`D. (d) `CoCl_3*4NH_3` |
|
Answer» Correct Answer - C For octahedral complexes, coordination number is 6. Hence, `CoCl_3 diamond 3NH_3`, i.e., `[Co(NH_3)_3diamondCl_3]` will not ionize and will not give test for `Cl^(-)` ions with silver nitrate. |
|
| 509. |
Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. `[Co (NH_(3))_(3)]Cl_(3)`B. `[Co(NH_(3))_(6)]Cl_(3)`C. `[Co(NH_(3))_(4) Cl_(2) ]Cl`D. `[Co)NH_(3))_(5)Cl]Cl_(2)` |
|
Answer» Correct Answer - A `[Co(NH_(3))_(6)]Cl_(3)to [Co(NH_(3))_(6)]^(3+)+3Cl^(-)` `[Co(NH_(3))_(3)] to [Co(NH_(3))_(3)Cl_(3)]` `[Co(NH_(3))_(4)Cl_(2)]Clto [Co(NH_(3))_(4)Cl_(2)]^(+)CL^(-)` `[Co(NH_(3))_(5)Cl]Cl_(2) to [Co(NH_(3))_(5)Cl_(2)]^(2+)+2Cl^(-)` `SO [Co (NH_(3))_(3)Cl_(3)]` does not give test for choride ions |
|
| 510. |
The `pi` acceptor ligands are those which possess vacant `pi-` orbitals in addition to the lone pairs of electrons Which of the following complex ion has lowest `M-C` bond length? (a) `[V(CO)_(6)]^(o+)` (b) `[Mn(CO)_(6)]^(o+)` (c ) `Ni(CO)_(4)` (d) `Fe(CO)_(5)` . |
| Answer» Correct Answer - A | |
| 511. |
The `pi` acceptor ligands are those which possess vacant `pi-` orbitals in addition to the lone pairs of electrons Which of the following complex ion has the highest `C-O` bond length ? (a) `[V(CO)_(6)]^(o+)` (b) `Ni(CO)_(4)` (c ) `Fe(CO)_(5)` (d) `[Mn(CO)_(6)]^(o+)` . |
| Answer» Correct Answer - A | |
| 512. |
The pi acid ligands donate their lone pairs to the metal to form a normal o bond with the latter in addition to it the vacant orbitals accepct electrons from the filled mental orbitals to form a type of pi bonand which suppliments the o bond Which of the following has lowest `M-C` bond lenght? (a) `[Fe(CO)_(4)]^(2-)` (b) `[Co(CO)_(4)]^(Θ)` (c) `[Ni(CO)_(4)]` (d) `[Mn(CO)_(6)]^(o+)` . |
| Answer» Correct Answer - D | |
| 513. |
The pi acid ligands donate their lone pairs to the metal to form a normal o bond with the latter in addition to it the vacant orbitals accepct electrons from the filled mental orbitals to form a type of pi bonand which suppliments the o bond Which of the following has lowest `C-O` bond lenght? (a) `[Fe(CO)_(4)]^(2-)` (b) `[Co(CO)_(4)]^(Θ)` (c) `[Ni(CO)_(4)]` (d) `[Mn(CO)_(6)]^(o+)` . |
| Answer» Correct Answer - D | |
| 514. |
Calculate total number of geometrical, optical and structural isomers in the compound. `[Rn(en)_(2)(NO_(2))_(2)]NO_(3)` |
|
Answer» Correct Answer - 15 `{:([Rh(en)_(2)(NO_(2))_(2)]NO_(3),"Linkage","Geo.","Optical"),(,NO_(2)" "NO_(2),Cis+trans,Cis),(,NO_(2)" "ONO,Cis+trans,Cis),(,ONO" "ONO,Cis+trans,Cis),([Rh(en)_(2)(NO)_(2)NO_(3)]NO_(2),NO_(2)" "NO_(3),Cis+trans,Cis),(,ONO" "NO_(3),Cis+trans,Cis):}` `5xx3=15` isomers. |
|
| 515. |
How may structural isomers are possible are possible for a complex consisting of `Co^(3+)` as the central metal ion, two en molecules, two `CI^(-)` ions one `NO_(2)^(-)` ion ?A. FourB. ThreeC. FiveD. Two |
|
Answer» Correct Answer - B Keeping in mind that the coordination number of `Co^(3+)` ion is six, we have following possibilities: `[CoCI_(2)(en)_(2)]NO_(2)` `[CoCI_(2)(en)+(2)NO_(2)]CI` `[CoCI_(2)(en)_(2)(ONO)]CI` Therefore only ionization and linkage isomerism are possble. Hydrate isomersm is not possible as there is no `H_(2)O` molecule. Coordination isomerism is also not possible as both positive and negative ions are complex ions. |
|
| 516. |
`K_(2)[PtCl_(6)]` is ionized to three ions when dissolved in water . Will it give white precipitate with `AgNO_(3)` solution ? |
|
Answer» No, because all `Cl^(-)` are in coordination sphere and are non-ionizable. `K_(2)[PtCl_(6)] iff 2K^(+) +[PtCl_(6)]^(2-)` |
|
| 517. |
One cationic complex has to isomers `A` and `B` Each has one `Co^(3+)` five `NH_(3)` one `CI^(Θ)` and one `SO_(4)^(2-)` stoichiometically A give white precipitate with `BaCI_(2)` white `B` gives white precipitate with `AgNO_(3)` ` (B)` can be .A. `[Co(NH_(3))_(5)SO_(4)]CI`B. `[CO(NH_(3))_(5)CI]SO_(4)`C. `[Co(NH_(3))_(3)CI(SO_(4))]2NH_(3)`D. None of these |
|
Answer» Correct Answer - A B gives white ppt `AgNO_(3)` so `CI^(Θ)` is negative counter ion Hence answer is (c ) |
|
| 518. |
One cationic complex has to isomers `A` and `B` Each has one `Co^(3+)` five `NH_(3)` one `CI^(Θ)` and one `SO_(4)^(2-)` stoichiometically A give white precipitate with `BaCI_(2)` white `B` gives white precipitate with `AgNO_(3)` A can be .A. `[Co(NH_(3))_(5)]CISO_(4)`B. `[Co(NH_(3))_(5)SO_(4)]CI`C. `[Co(NH_(3))_(5)CI]SO_(4)`D. `[Co(NH_(3))_(4)SO_(4)]CI.NH_(3)` |
|
Answer» Correct Answer - C A gives white ppt. with `BaCI(2)` so `SO_(4)^(2-)` ions is outside the complex entity as negative counter ion.Hence answer is© . |
|
| 519. |
The possible number of the optical isomers in `[Cr(en)_(2)CI_(2)]^(o+)` is .A. `6`B. `3`C. `4`D. `2` |
| Answer» Correct Answer - B | |
| 520. |
The formula of complex tris ( ethylenediamine ) cobalt (III) sulphate isA. `[Co(en)_(2)SO_(4)]`B. `[Co(en)_(3)SO_(4)]`C. `[Co(en)_(3)]_(2)SO_(4)`D. `[Co(en)_(3)]_(2)(SO_(4))_(3)` |
| Answer» Correct Answer - D | |
| 521. |
The coordination number of cobalt in tris(ethylendiamine) cobalt(III) ion, `[Co(en)_(3)]^(3+)` , isA. 3B. 6C. 9D. 5 |
|
Answer» Correct Answer - B The number of ligand donor atoms to which the central metal atom/ion is directly bonded in a complex enity is called the coordination number of the metal. In the complex ion, `[Co(en_(3))^(3+)]` , the coordination number (CN) of Co is 6 because en (ethane -1,2-diamine) is a bidenate ligand and hence provides two donor atoms. |
|
| 522. |
The formula of the complex tris (ethylenediamine) cobalt (III) sulphate isA. (a) `[Co(en)_2SO_4]`B. (b) `[Co(en)_3SO_4]`C. (c) `[Co(en)_3]_2SO_4`D. (d) `[Co(en)_3]_2(SO_4)_3` |
|
Answer» Correct Answer - D tris (ethylenediamine) cobalt (III) sulphate is `[Co(en)_3]_2(SO_4)_3` |
|
| 523. |
Writh the structure and name og the following and their coordination isomers . |
|
Answer» The coordination isomer of `(A)` is `[Cr (en)_(3)][Co(CN)_(6)]` The structure name of the above two isomers are given below `(A)`implies Tris (ethylenediamine)coblt(III) hexacyanochromate (III) and its isomer Tris (ehtylenediamine)chromium (III) hexacyanocobaltate (III) (ii) Coordination isomer of `(B)` is `[Cr(NH_(3))_(6)][Co(C_(2)O_(4))_(3)]` The structure and name of these isomers are given below (B)implies Hexamminecobalt (III) tris (oxalato) chromate (III) and its isomer `[Cr(NH_(3))_(6)][Co(C_(2)O_(4))_(3)]` is Hexamminechromium (III) tris (oxalato)cobaltate(III) . |
|
| 524. |
The complex ion `[Co(NH_(3))_(5)CI]^(2+)(X)` undergoes a substitution reaction when reacted with `(NaNO_(2)+HCI)` An unstable scarlet red complex A is formed when dilute acid is used and a stable yellow complex `B` is formed when concentrated acid is used Both `A` and `B` are isomeric pentammine complex ions Give the structures of the ions und name the type of the isomerism involved . |
|
Answer» Since the treatment of`(X) (NaNO_(2)+ dil HCI)` gives as unstable red coplex should be pentaamminenitritocobalt (III) ion `[Co^(3+(NH_(3))_(5)(ONO)]^(2+)` Similarly the ion obtained by treating `[Co^(3+)(NH_(3))_(5)CI]^(2+)(X)` ion with `(NaNO_(2) + conc.HCI)` should be pentaammine nitrocobalt (III) ion `[Co^(3+)(NH_(3))(NH_(3))_(5)(NO_(2))]^(2+)` Thus `A = [Co^(3+)(NH_(3))_(5)(ONO)]^(2+)` and `B = [Co^(3+)(NH_(3))_(5)(No_(2))]^(2+)` Obviously `A` and `B` linking isomers and the isomerism involved is linkage isomerism . |
|
| 525. |
The formula of dichlorobis (urea) copper (II) isA. `[Cu{O=C(NH_(2))_(2)Cl}]Cl`B. `[CuCl_(2){O=C(NH_(2))_(2)}_(2)]`C. `[Cu{O=C(NH_(2))_(2)}]Cl_(2)`D. `[CuCl_(2){O=C(NH_(2))_(2)H_(2)}]` |
|
Answer» Correct Answer - B The formula of dichlorobis (urea) copper (II) is `[CuCl_(2){O=C(NH_(2))_(2)}_(2)]`. |
|
| 526. |
How many geometrical isomers are possible for the square planar complex `[Pt(NO_(2))(py)(NH_(3))(NH_(2)OH)]NO_(2)` (a) `Four (b) Five (c ) Eight (d) Three . |
|
Answer» Correct Answer - d It is `[Mabcd]^(n+-)` type complex which shows three isomers . |
|
| 527. |
Write the formulas for following coordination compounds : (1) Tris ( ehtane -1,2-diammine) cobalt (III) sulphate (2) Potassiumtrioxalatoaluminate(III) (3) Hexacaronylchromium (0) |
|
Answer» (1) `[Co(en)_(3)]_(2)(SO_(4))_(3)` (2) `K_(3)[Al(C_(2)O_(4))_(3)]` `Cr(CO)_(6)` |
|
| 528. |
The total number of possible isomers of sqaure-planar `[Pt(Cl)(NO_(2))(NO_(3))(SCN)]^(2-)` is :A. 8B. 12C. 16D. 24 |
| Answer» Correct Answer - B | |
| 529. |
IUPAC name of `[Pt(NH_(3))_(3) (Br)(NO_(2))CI] CI` isA. trimminenitrochlorobromoplatinum (IV) chlorideB. triamminebromochloronitroplatinum (IV) chlorideC. triamminebromonitrochloroplatinum (IV) chlorideD. triamminechlorobromonitroplatinum (IV) chloride |
|
Answer» Correct Answer - B The cation is named first in all ionic complexes. The ligands are named in an alphabetical order before the name of the central metal atom/ion. Names of anionic ligands end in ---O. The oxidation state of the metal in coordination entity is indicated by Roman numeral in parenthesis. |
|
| 530. |
The IUPAC name of `[Pt(NH_(3))(Br)(CI)(NO_(2))] CI` isA. triamminechlorobromonitrplatinum (IV) chlorideB. triamminebromidochloridonitroplatinum (IV) chlorideC. bromidochloridonitrotriammineplatinum (IV) chlorideD. triamminentrochloridobromidoplatinum (IV) chloride |
|
Answer» Correct Answer - B The catoin is named before the anion. When writing the name of a complex entity, the ligands are quoted in alphabetical order, regardless of their charge (followed by the metal). The oxidation state of the central metal atom/ion is shown by a Roman unmeral in brackets immediately following its name. Complex positive ions and netural molecules have no special endings but complex negative ions end in - ate. |
|
| 531. |
Write the IUPAC names of the following coordination compounds: (a)`[Pt(NH_(3))_(2)Cl(NO_(2))]` (b) `K_(3)[Cr(C_(2)O_(4))_(3)]` (c) `[CoCl_(2)(en)_(2)]Cl` (d) `[Co(NH_(3))]Cl` (e) `Hg[Co(SCN)_(4)]` |
|
Answer» (a) Diammine chlorid onitrito-N-platinum (II) (b) Potassium trioxalatochromate (III) (c) Dichloridobis (ethane -1,2-diamine) cobalt (III) chloride (d) Pentaammine carbonato cobart (III) chloride (e) Mercury (I) tetrathio cyanato -S- cobaltate (III) |
|
| 532. |
Assertion The total number of isomers shown by `[Co(en)_(2)CI_(2)]^(o+)` complex ion is three `[Co(en)_(2)CI_(2)]^(2+)` complex ion has an octahedral geometry .A. If both `(A)` and ` (R )` are correct and `(R )` is the correct explanation of `(A ) ` .B. If both `(A)` and ` (R )` are correct and `(R )` is the correct explanation of `(A ) ` .C. If`(A)` is correct, but `( R )` is incorrect .D. Both `(A)` and `(R ) ` are incorrect . |
| Answer» Correct Answer - B | |
| 533. |
Write IUPAC names of following compounds : (1) `[Co(NH_(3))_(5)(CO_(3))]Cl` (2) `Hg[Co(SCN)_(4)]` (3) `[Pt(NH_(3))_(2)Cl(NO_(2))]` |
|
Answer» (1) Pentaamminecarbonatocobalt(III) chloride (2) Mercury tetrathiocyanatocobaltate(III) (3) Diamminechloridonitrito-N-platinum(II) |
|
| 534. |
IUPAC name of `[Pt(NH_(3))_(3) (Br) (NO_(2))Cl]Cl` isA. triamminebromochloronitroplatinum (IV) chlorideB. triamminebromonitrochloroplatinum (IV) chlorideC. triamminechlorobromonitroplatinum (IV) chlorideD. triamminenitrochlorobromoplatinum (IV) chloride |
|
Answer» Correct Answer - A The IUPAC name of `[Pt(NH_(3))_(3)(Br)Cl` is triamminebromochloronitroplatinum chloride. (Oxidation number of Pt = + 4, and ligands are arranged in alphabetical order) |
|
| 535. |
Give the number of total possible ionisation isomers in `[Pt(NH_(3))_(4)CI_(2)]Br_(2)` . |
| Answer» Correct Answer - 4 | |
| 536. |
The IUPAC name of `K_(2)[Cr(CN)_(2)O_(2)(O)_(2)(NH_(3))]` is :A. potassium amminecyanoperoxodioxochromatic(V)B. potassium amminedicyanoperoxodioxochromium(VI)C. potassium amminecyanoperoxodioxochromium (VI)D. potassium amminedicyanodioxoperoxochromate (VI |
|
Answer» Correct Answer - D `2K^(+)[Cr overset(-2)((CN)_(2))overset(-2)(O_(2)) overset(-4)((O)_(2))(overset(0)(NH_(3)))]^(2-)` Oxidation state of chromium `=x+2(-1)+(-2)+2(-2)+(0)=-2`. `:. X=+6`. As per IUPAC name. Complex is anionic, so metal ion will be named as chromate with +6 oxidation state. So, potassium amminedicyanodioxoperoxochromate(VI). |
|
| 537. |
The correct IUPAC name `[Co(NH_(3))_(3)(NO_(2))_(3)]` isA. tetrammine trinitro -N- cobalt (III )B. Triammine trinitro -N-cobalt (II)C. Triammine cobalt (III ) nitriteD. Triammine trinitro -N - cobaltate (III) |
|
Answer» Correct Answer - A The IUPAC name of `[Co(NH_(3))_(3)(NO_(2))_(3)]` is triammine trinitro -N cobalt (III ). |
|
| 538. |
Consider the following isomers. (i) [Pt`(NH_(3))_(4)Cl_(2)]Br_(2) " " (ii) [Pt (NH_(3))_(4) Br_(2)]Cl_(2)` (iii) `[Co(NH_(3))_(4)Cl_(2)] NO_(2)` Which of the following observations is correct ?A. (i) will give a part yellow and (ii) will give a white precipitate with `AgNO_(3)` solution .B. (iii) will give a white precipitate with `AgNO_(3)` solution .C. (i) , (ii) and (iii) will give white precipitate with `AgNO_(3)` solution .D. None of the above isomers will give white precipitate with `AgNO_(3)` solution . |
|
Answer» Correct Answer - A `[Pt(NH_(3))_(4) Cl_(2) ] Br_(2) to [Pt(NH_(3))_(4) Cl_(2) ] ^(2+) + 2 Br^(-)` `Br^(-) + Ag NO_(3) to underset("pale yellow")(AgBr + ) NO_(3)^(-)` `[Pt(NH_(3))_(4)Br_(2)]Cl_(2) to [Pt(NH_(3))_(4) Br_(2)]^(2+) + 2Cl^(-)` `Cl^(-) + AgNO_(3) to underset("white")(AgCl) + NO_(3)^(-)` |
|
| 539. |
Arrange the following compounds in order of increasing molar conductivity (a) `K[Co(NH_(3))_(2)(NO_(2)_(4)]` (b) `[Cr(NH_(3))_(3)(NO_(2))_(3)]` (c) `[Cr(NH_(3))_(5)(NO_(2))]_(3)[Co(NO_(2))_(6)]_(2)` (d) `Mg[Cr(NH_(3))(NO_(2))_(5)]` |
| Answer» The larger the number of ions and larger the charge on each , the larger the conductivity . The compounds from lowest conductivity to highest conductivity are `b lt a lt d lt c `. | |
| 540. |
The hydridizoation states of the central metal ion in the complexes `[Co(NO_(2))_(6)]^(3-)` and `[Fr(CN)_(6)]^(4-)` areA. all `sp^(3) d^(2)`B. all `d^(2) sp^(3)`C. `sp^(3) d^(2)` , `d^(2) sp^(3)` and `d^(20 sp^(3)`D. `d^(2) sp^(3)` , `sp^(3) d^(2)` and `sp^(3 d^(2)` |
|
Answer» Correct Answer - B `Co(3d^(7)4s^(2)) rarr Co^(3+) (3d^(6))` `Fe(3d^(6)4s^(2)) rarr Fe^(3+)(3d^(5))` `Fe(3d^(6)4s^(2))rarr Fe^(3+)(3d^(6))` All six coordinate complexes are octahedral. Strong field ligands such as `NO_(2)^(-)` and `CN^(-)` reshuffle the 3d electronic configuration to provide two unoccpied 3d orbitals for `d^(2) sp^(3)` hybridisation. |
|
| 541. |
The number of geometric isomers possible for the complex `[CoL_(2)Cl_(2)]^(-) ( L = H_(2) NCH_(2) CH_(2)O^(-))` is |
|
Answer» Correct Answer - 5 |
|
| 542. |
The IUPAC name for `[Co(NH_(3))_(6)] [Cr(CN)_(6)]` isA. hexacynochromate (III) hexaamminecobalt (III)B. hexaaamminecobalt (III)hexacyanidochromate (III)C. hexaamminechrominum cobalt hexaammine (VI)D. hexamminecobalt (III) hexacyanochomium (III) |
|
Answer» Correct Answer - B In the given ionic coordination compound, both positive and negative ions. Ionic species are written as two words with the cation first. The central metal atom is identified by name, followed by the formal oxidation number in Roman numerals in parenthese. If the complex is an anion, the ending-ate adds to the metla name or replacees any -ium, -en, -or-ese ending . Thus, we have cobaltate and nickelate, but chromate and tungstate (not chromiumate). For a few metals, the element: ferrate (iron), argentate (silver), cuprate (copper) and aurate (gold). |
|
| 543. |
The correct statement on the isomerism associated with the following complex ions , `(a) [Ni(H_(2)O)_(5)NH_(3)]^(2+), (b) [Ni(H_(2)O)_(4)(NH_(3))_(2)]^(2+) and ( c) [Ni(H_(2)O)_(3)(NH_(3))_(3)]^(2+)` is :A. (a) and (b) show only geometrical isomerismB. (b) and ( c) show geometrical and optical isomerismC. (b) and (c ) show only geomterical isomerismD. (a) and (b) show geometrical and optical isomerism |
| Answer» Correct Answer - C | |
| 544. |
Oxidation state of `Fe` in `K_3[Fe(CN)_6]` isA. (a) `2`B. (b) `3`C. (c) `0`D. (d) None of these |
|
Answer» Correct Answer - B `3xx(+1)+x+6xx(-1)=0` or `x=6-3+3` Oxidation state of `Fe=+3`. |
|
| 545. |
IUPAC name `[Co(NH_(3))_(5)(NO_(2))]Cl_(2)` isA. Nitrito-N-pentaamminecobalt(III)chlorideB. Nitrito-N-pentaamminecobalt(II) chlorideC. Pentaamminenitrito-N-cobalt(II)chlorideD. Pentaamminenitrito-N-cobalt (III) chloride |
| Answer» Correct Answer - D | |
| 546. |
Name the following complexes according to the IUPAC system of nomenclature (i) `[Co(NH_(3))_(4)(H_(2)O)Br](NO_(3))_(2)` (ii) `Na[Au(CN)_(2)]` (iii) `Na_(3)[Fe(C_(2)O_(4))_(3)]` (iv) `[Co(en)_(3)[Cl_(3)` |
|
Answer» (i) Bromoaquatetraamminecobalt (III) nitrate (ii) Sodiumdicyanoaurate (I) (iii) Sodiumtrioxalatoferrate (III) (iv) Tris (ethylenediamine) cobalt (III) chloride |
|
| 547. |
Identify the complex which are expected to be coloured Explain (a) `[Ti(NO_(3))_(4)]` (b) `[Cu(NCH_(3))]^(o+) BF_(4)^(Θ)` (c ) `[Cr(NH_(3))_(6)]^(3+) 3CI^(Θ)` (d) `K_(3)[VF_(6)]` . |
|
Answer» `[Ti(NO_(3))_(4)]` The oxidation state of `Ti` is `+4` The atomic number of titanium is `22` `Ti =[Ar] 3d^(2) 4s^(2)` `Ti^(4+) =[Ar]` No unpaired electrons So it is colourless (ii) `[Cu(NCCH_(3))]^(4) BF_(4) Θ` The oxidation state of `Cu` is `+1` The atomic number of copper is 28 `Cu =[Ar] 3d^(10) 4s^(1)` `Cu = [Ar] 3d^(9)` No unpaired electrons So it is colouless (iii) `[Cr(NH_(3))_(6)]^(3+)3CI^(Θ)` The oxidation sate of `Cr` is `+23` The atomic number of chromium is 24 `Cr[Ar]3d^(10) 4s^(1)` `Cr = [Ar] 3d^(8)` It has 3 unpaired elctrons So it is coloured (iv) `K_(3)[VE_(6)]` The oxidation state of `V` is `+3` The atomic number of vanadium is `+3` The atomic number of vanatium is `+3` `V =[Ar]3d^(3) 4s^(2)` `V^(3+) = [Ar]3d` It has 3 unpaired electrons So it coloured . |
|
| 548. |
Amongst the following pair of enantiomers is given byA. `[Cr(NH_(3))_(6)]Co(CN)_(6)]`B. `[Co(en)_(2) CI_(2)]CI`C. `[Co(NH_(3))_(4)CI_(4)]NO_(2)`D. `[Pt(NH_(3))_(4)]PtCI_(6)` |
| Answer» (b) Pair of enantiomers are non-superimposable mirror images. The complex `[Co(en)_(2) CI_(2)]CI` exhibites a pair of enantiomres. | |
| 549. |
The IUPAC name for `[(NH_(3))_(5)Cr - (OH) - Cr(NH_(3))_(5)]` isA. `mu` - hydroxido- bis[pentaaminechromium(III)]B. `mu` - hydroxo-bis(octaamminechromium)`(5+)` ionC. `mu` - hydroxo-bis(pentaamminedichromium) `(5+)`D. m-hydroxyl-bis(decaamminedichromium) `(5+)` ion |
|
Answer» Correct Answer - A It is polynuclear complex. The bridginig ligand OH which links the two Cr metal atoms together is indicated by the prefix `my-` . For multiple ligands already containing numerical prefixes (such as 1,2 - diaminoethane), the prefixes used are bis-, tris-, and tetrakis - for 2,3 and 4. |
|
| 550. |
The IUPAC name for `[A](OH_(2))_(5)(OH)]^(+2)` isA. aquametaalumination ionB. pentahydroaluminium hydroxideC. pentaaquahydroxidoaluminium (III) ionD. pentaaquaaluminate (III) hydroxide |
|
Answer» Correct Answer - C Within a complex ion the ligands `(OH^(-)` and `H_(2)O)` are named first, in alphabetical order and the metal ion is named last. Anionic ligands with endings - ide are changed to - ido. Finally the oxidation number of the central metal is written in Raman numerals following the name of the metal. |
|