Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The weather report reads, "Temperature 20°C : Relative humidity 100%". What is the dew point ?

Answer»

Temp is 20°    Relative humidity = 100%
So the air is saturated at 20°C
Dew point is the temperature at which SVP is equal to present vapour pressure
So 20°C is the dew point.

2.

The temperature and the dew point in an open room are 20°C and 10°C. If the room temperature drops to 15°C, what will be the new dew point ?

Answer»

Temp = 20°C        Dew point = 10°C
The place is saturated at 10°C
Even if the temp drop dew point remains unaffected.
The air has V.P. which is the saturation VP at 10°C. It (SVP) does not change on temp.

3.

A glass contains some water at room temperature 20°C. Refrigerated water is added to it slowly. When the temperature of the glass reaches 10°C, small droplets condense on the outer surface. Calculate the relative humidity in the room. The boiling point of water at a pressure of 17.5 mm of mercury is 20°C and at 8.9 mm of mercury it is 10°C.

Answer»

Given
SVP at the dew point = 8.9 mm    SVP at room temp = 17.5 mm
Dew point = 10°C as at this temp. the condensation starts
Room temp = 20°C
RH =SVP at dew point/SVP at room temp
=8.9/17.5
= 0.508 ≈ 51%

4.

On an official tour in Toiryo, Mr. Sairam who was a chief development officer in Southern railway attended the seminar after taking a fast moving train. After the sernina4, he met his friend Orrtosaki. In a discussion, his friend told to Sairam, how Japanese people are focusing on energy conservation and saving of fossil fuels with the use of Maglev trains. To take idea about it, Sairam travelled from Tokyo to Osaka in Maglev train and observed that its sound is less as compared to Indian rails with smooth traveling. So all the way he was thinking that what could be our reasons that we are lagging behind Japanese in mass transporting systems. Ontosaki told to Sairam that our trains works on the principle  Mesiner's effect.(i) What values did Mr. Sairam found from Ontosaki? Mention any two(ii) What is the meissner effect? what is the value of  χ and μ for perfect diamagnetism?

Answer»

(i) Awareness about new technology, concern for energy conservation,decrease of noise pollution and air pollution i.e concern for environment.

(ii) When a superconductor is cooled in a magnetic field below its critical temperature the magnetic field lines are expelled showing diamagnetic property.this is called meissner effect.

5.

There is some liquid in a closed bottle. The amount of liquid is continuously decreasing. The vapour in the remaining part (a) must be saturated (b) must be unsaturated (c) may be saturated (d) there will be no vapour.

Answer»

(b) must be unsaturated 

6.

A current passes through a resistor. Let K1 and K2 represent the average kinetic energy of the conduction electrons and the metal ions respectively. (a) K1 < K2. (b) K1 - K2. (c) K1 > K2 (d) Any of these three may occur.

Answer»

The correct answer is (c) K1 > K2 

7.

Write two conditions when real gases obey the ideal gas equation (PV = nRT).n → number of mole.

Answer»

(i) Low pressure 

(ii) High temperature.

8.

When do the real gases obey more correctly the gas equation: PV = nRT?

Answer»

An ideal gas is one whose molecules have zero volume and no mutual force between them. At low pressure, the volume of a gas is large and so the volume occupied by the molecules is negligible in comparison to the volume of the gas. At high temperature, the molecules have large velocities and so the intermolecular force has no influence on their motion. Hence at low pressure and high temperature, the behaviour of real gases approach the ideal gas behaviour.

9.

State the Maxwell's electromagnetic theory.

Answer»

Maxwell's electromagnetic theory:

i. Maxwell postulated the existence of electromagnetic waves.

ii. According to Maxwell, light waves are electromagnetic waves which require no material medium for their propagation. So light can travel through a medium where there is no atmosphere i.e., in vacuum.

iii. Thus, Maxwell established relationship between electricity and magnetism.

iv. Electromagnetic nature of light was experimentally proved by Maxwell in 1873.

10.

How is heat polluting water?

Answer»

As water, temperature increases, the amount of dissolved oxygen decreases. So thermal pollution often reduces the aquatic life diversity in water.

11.

Which of the following type of pollution causes the out break of jaundice? (a) Air pollution (b) Water pollution (c) Soil pollution (d) Thermal pollution

Answer»

(a) Air pollution

12.

Principal value of tan-1(- 1) is :(a) 45°(b) 135°(c) – 45°(d) – 60°

Answer»

Answer is (c)

∵ tan-1(- x)= – tan-1 x

tan-1 (-1) = – tan-1(1)

Let tan-11 = θ

∴ tan θ = 1

⇒ tan θ = tan 45°

∴ θ = 45°

∴ tan-1(-1) = – 45°

13.

If wrong, give the correct modified version of his statement.

Answer»

For an uninterrupted motion of a body, an additional external force is required for overcoming opposing/resistive forces.

14.

If the coordinates of the points A, B, C, D be (1, 2, 3), (4, 5, 7), (- 4, 3, – 6) and (2, 9, 2) respectively, then find the angle between the lines AB and CD.

Answer»

Dr’s of AB = (3, 3, 4), 

Direction CD = (6,6, 8) 

\(\frac{3}{6} = \frac{3}{6} = \frac{4}{8}\)

Dr’s are proportional. 

Hence they are parallel 

∴ Angle between them = 0°

15.

If the lines \(\frac{x - 1}{-3} = \frac{y - 2}{2k} = \frac{z - 3}{2}\) and \(\frac{x - 1}{3} = \frac{y - 1}{1} = \frac{z - 6}{- 5}\)are perpendicular, find the value of k.

Answer»

Here Dr’s of the lines are (-3, 2k, 2) and (3k, 1,-5) . 

since the lines are perpendicular -3 x 3k + 2k x 1 x 2 x -5 = 0

-9k + 2k - 10 = 0

⇒ - 7k = 10 ⇒ k = \(\frac{-10}{7}\)

16.

If the lines \(\frac{x - 1}{-3} = \frac{y - 2}{-2k} = \frac{z - 3}{2},\; \frac{x - 1}{k} = \frac{y - 2}{1} = \frac{z - 3}{5}\) are ⊥r, find k

Answer»

Directions of tines are (-3, -2K, 2) and (K, 1,5) 

since lines are ⊥r a1b1 + a2b2 + a3b3 = 0 

-3 x K – 2K x 1 + 2 x 5 = 0 

-3K – 2K + 10 = 0, 

-5K = -10, K = 2

17.

What is the least number of planes that can enclose a solid? What is the name of the solid.

Answer»

The least number of planes that can enclose a solid is 4. 

The name of the solid is Tetrahedron.

18.

Do you like to hear predictions about your future? Give reason.

Answer»

Yes, I would like to hear but I will not believe this because I don't believe in astrology and no one knows our future. One more reason is our future is based on our actions of today. So, future can change.

19.

Do you like to hear predictions about your future? Give reasons.

Answer»

No, I do not like to hear predictions about my future. I do not believe that any person can foretell what is going to happen in someone’s life. Astrology is just a way of making money from gullible people. I believe that one must work hard and be a good human being if one wants to be successful in life.

20.

Find from the extract the antonyms of the following words: 1. light 2. noise 3. few 4. dead

Answer»

1. light × darkness 

2. noise × silence 

3. few × many 

4. dead × alive

21.

बहुपद kr4 + 3x3 + 6 को (x – 2) से भाग देने पर प्राप्त शेषफल, दूसरे बहुपद 2x3 + 17x + k को (x – 2) से भाग देने पर प्राप्त शेषफल का दोगुना है। k का मान ज्ञात कीजिए।

Answer»

बहुपद kr4 + 3x3 + 6 को (x – 2) से भाग किया जाता है तो x – 2 = 0 या x = 2 रखने पर शेषफल

= k(2)4 + 3(2)3 + 6

= 16k + 24 + 6 = 16k + 30

और जब 2x3 + 17x + k को (x – 2) से भाग किया जाता है तो x – 2 = 0 या x = 2 रखने पर

शेषफल = 2(2)3 + 17(2) + k = 2 × 8 + 34 + k = 50 + k

प्रश्नानुसार,

16k + 30 = 2(50 + k)

16k + 30 = 100 + 2k

16k – 2k = 100 – 30

14k = 70

k = 70/14 = 5

22.

0.5 g mixture of K2CO3 and Li2CO3 required 30 mL of 0.25 N HCl for neutralization. What is the % composition of mixture. (K=39, Li=7)

Answer»

Correct answer is

% of K2CO3 = 96% 

% of Li2CO3 = 4%

23.

A solution containing 4.2 g of KOH and Ca(OH)2 is neutralized by an acid. If it consumes 0.1 2 equivalent of acid, calculate composition of sample in solution.

Answer»

Correct answer is 

% of KOH = 35%

% of Ca(OH)2 = 65%

24.

What happens if a simple pendulum is pulled aside and released ?

Answer»

If a simple pendulum is pulled aside and released, it oscillates freely about its equilibrium position at its natural frequency which is inversely proportional to the square root of its length and directly proportional to the square root of the acceleration of gravity at the place. These oscillations, called as free oscillations, are periodic and tautochronous if the displacement of its bob is small and the dissipative forces can be ignored.

25.

What is the minimum distance between any two particles of a medium which always have the same speed when a sinusoidal wave travels through the medium ?

Answer»

When a sinusoidal wave travels through a medium the minimum distance between any two particles of the medium which always have the same speed is \(\cfrac{\lambda}{2}\).

Such particles are opposite in phase, i.e., their instantaneous velocities are opposite in direction.

[Note : The minimum distance between any two particles which have the same velocity is λ]

26.

What happens when a guitar string is plucked ?

Answer»

When a guitar string is plucked, two wave pulses of the same amplitude, frequency and phase move out from that point towards the fixed ends of the string where they get reflected. For certain ratios of wavelength to length of the string, these reflected pulses moving towards each other will meet in phase to form standing waves on the string. The vibrations of the string cause the air molecules to oscillate, forming sound waves that radiate away from the string. The frequency of the sound waves is equal to the frequency of the vibrating string. In general, the wavelengths of the sound waves and the waves on the string are different because their speeds in the two mediums are not the same.

27.

The string of a guitar is 80 cm long and has a fundamental frequency of 112 Hz. If a guitarist wishes to produce a frequency of 160 Hz, where should the person press the string ?

Answer»

Data : L1 = 80 cm n1 = 112 Hz, n2 = 160 Hz According to the law of length, n1L1 = n2L2

∴ The vibrating length to produce the fundamental frequency of 160 Hz,

L\(\frac{n_1L_1}{n_2}\) = \(\frac{112(80)}{160}\) = 56 cm

28.

Give reasons : The notes of a sitar and a guitar sound different even if they have the same loudness and the pitch.

Answer»

The quality or timbre of the sound of a sitar is different from that of a guitar. The number of overtones or partials present and their relative intensities determine the quality or timbre of the sound of a musical instrument. Therefore, even if the pitch and the loudness are the same, the notes of a sitar and a guitar sound different.

29.

The molecular motion ceases at :(A) 273 K. (B) 273° C (C) – 273 K(D) -273° C 

Answer»

Answer is (D) -273° C

30.

The mean kinetic theory of a mono atomic gas molecule is :(A) zero. (B) 1/2 kT. (C) kT. (D) 3/2 kT

Answer»

Answer is (D) 3/2 kT

31.

Consider the decay of a free neutron at rest: n → p + e. Show that the two-body decay of this type must necessarily give an electron of fixed energy and, the therefore, cannot account in the observed continuous energy distribution in the β-decay of a neutron or a nucleus (Fig.)

Answer»

If the decay of neutron (inside the nucleus) into proton and electron is according to the given scheme, then the available energy in the decay must be carried out by the electron coming out of the nucleus and therefore the emitted electron should always possess a fixed value of K.E. However, the graph shows that the emitted electron can have any value of energy between zero and maximum value. Therefore, the given decay mode cannot account for the abserved continuous energy spectrum in the β-decay.

32.

State two characteristic which a source of energy must have.

Answer»

Two characteristics which a source of energy must have are as listed below:

i. It should provide an adequate amount of useful energy at a steady rate over a longer period of time.

ii. It should be safe and convenient to use and economical.

33.

What does each quantum number signify?

Answer»

The quantum numbers signify the probability of finding electron in the space around nucleus.

34.

In Milikan's experiment static charge on the oil drops has been obtained by shining x-rays. If the static electric charge on the oil drop is -1.282 x 10-18 C, calculate the number of electrons present on it.

Answer»

q = ne or n = q/e

= {-1.282 x 10-18}/{1.6 x 10-19} = 8

35.

What is the maximum value of/for n = 4?

Answer»

The maximum value of / for n = 4 is 3.

36.

How many values can l have for n = 4?

Answer»

l takes values from 0 to n – 1. So l has 4 values for n = 4. Those values are 0, 1,2, 3.

37.

Do all the p-orbitals have the same energy? 

Answer»

Orbitals in the sub-shell belonging to same shell possess same energy but they differ in their orientations.

38.

Calculate the energy required for the processHe+ (g) → He2+ (g) + e-The ionization energy for the H atom in the ground state is 2.18 x 10-18 J atom-1.

Answer»

Ionisation potential (energy) for the ground state H atom = 2.18 x 10-18 J

The nuclear charge of helium is 2. Therefore,

EHe+ → He2+ = Z2 x EH→H+

Energy required for removing one electron from

He+ = 22 x (2.18 x 10-18 J)

= 4 x 2.18 x 10-18 J

= 8.72 x 10-18 J

39.

If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

Answer»

Length of the scale = 20 cm = 20 x 107 nm = 2 x 108 nm

Diameter of the carbon atom = 0.15 nm

Number of carbon atoms which can be placed side by side across the scale = {(2 x 108 nm)}/{0.15 nm} = 1.33 x 109

40.

How are two electrons in the Helium atom arranged?

Answer»

They are arranged in pair in Is orbital and the electronic configuration is 1s².

41.

State the law of conservation of energy.

Answer»

According to the law of conservation of energy, energy can neither be created nor can it be destroyed. It only changes from one form to another.

42.

Give an example when work done by the force of gravity acting on a body is zero even though the body gets displaces from its initial position.

Answer»

When a coolie carries a load while moving on a ground, the displacement is in the horizontal direction while the force of gravity acts vertically downward. So the work done by the force of gravity is zero.

43.

Name two examples in which the mechanical energy of a system remains constant.

Answer»

Motion of a simple pendulum and motion of a freely falling body.

44.

What do you understand by the conservation of mechanical energy? State the condition under which the mechanical energy is conserved.

Answer»

According to the law of conservation of mechanical energy, whenever there is an interchange between the potential energy and kinetic energy, the total mechanical energy (i.e., the sum of kinetic energy K and potential energy U) remains constant i.e., K + U = constant when there are no frictional forces.

Mechanical energy is conserved only when there are no frictional forces for a given system (i.e. between body and air). Thus, conservation of mechanical energy is strictly valid only in vacuum, where friction due to air is absent.

45.

Name the form of mechanical energy, which is put to use.

Answer»

Kinetic energy.

46.

In an electric cell which in use, the change in energy is from:(a) electrical to mechanical(b) electrical to chemical(c) chemical to mechanical(d) chemical to electrical

Answer»

Chemical to electrical

Hint: When current is drawn from an electric cell, the chemical energy stored in it changes into electrical energy.

47.

Which of the following is paramagnetic?a. O2-b. CN- c. COd. NO+

Answer»

Correct option is a. O2-

48.

What kind of energy transformations take place at a hydroelectric power house?

Answer»

The potential energy of water changes into K.E. and then into electrical energy.

49.

In the compound CH2=CH–CH2–CH2–C=CH, the hybridisation of carbon atoms involved in C2–C3 bond isa. sp–sp2b. sp3 –sp2 c. sp–sp3d. sp2 –sp3

Answer»

Correct option is d. sp2 –sp3

50.

According to MO theory.a. O2+ is paramagnetic and bond order greater than O2 b. O2+ is paramagnetic and bond order less than O2 c. O2+ is diamagnetic and bond order is less than O2 d. O2+ is diamagnetic and bond order is more than O2

Answer»

Correct option is a. O2+ is paramagnetic and bond order greater than O2