Explore topic-wise InterviewSolutions in .

1. Reflection 

2. Angle of incidence 

3. Diffused 

4. Real

A) real & inverted

(i) Ray 'B' is the correct refracted ray as a ray of light bends towards the normal while going from rarer to denser medium.

(ii) Ray 'E' is the partially reflected ray, as reflection of light takes place in the same medium.

(a) 0^o 

Reason: A ray of light which is incident normally (i.e. at angle of incidence = 0°) on the surface separating the two media, passes undeviated.

Reflection from a rough surface is called an irregular reflection.

(a) R=50cm f=? 

We know that

 f=R/2 = 50/2 = 25 cm 

(b) Convex mirror 

(c) It will diverge light rays.

B) a mirror holder, a screen holder and a scale

Correct option is C) aperture

A) convex mirror

Correct option is A) 12 cm

In regular reflection, a parallel beam of incident light is reflected as a parallel beam in one direction; while in diffuse reflection, a parallel beam of incident light is reflected in different directions. 

(a) Regular reflection 

(b) Regular reflection 

(c) Diffuse reflection 

(d) Regular reflection

C) a bulging out surface

Correct option is: (b) focus

Correct option is B) infinity

1. It is a virtual image. 

2. The image formed in a plane mirror cannot be caught on a screen.

C) concave mirror

Correct option is D) At focus

Correct option is: (a) the focus of the mirror

Correct option is: (b) pole

D) It may be any of the mirrors mentioned above.

The package in the accelerated car (a non inertial frame) experiences a Pseudo force in a direction opposite to that of the motion of the car. The frictional force on the package which acts opposite to this pseudo force is thus in the same direction (forward) as that of the car.

Correct option is B) Infinity

C) concave mirror

(a) Only the coin at the bottom is thrown away. Others will remain in the previous stage.

(b) The passengers start to move forward due to the tendency to continue in its state of motion.

(c) It is due to the tendency to continue in the state of rest.

(d) The passengers tend to fall backward due to the tendency to continue in their state of rest.

(e) The passengers inside the vehicle have the tendency to move forward due to inertia of motion.

Inertia: The inability of a body to change its state of rest or of uniform motion along a straight line by its itself. 

Inertia of rest: Inertia of rest is defined as the inability of a body to change its state of rest by itself.

Inertia of motion : Inertia of motion is defined as the inability of a body to change its state of motion by itself. Eg. When a running bus is suddenly stopped, the standing passengers fall forward due to inertia of motion. When a bus at rest starts suddenly, the standing passengers fall backward due to inertia of rest.

Correct answer is (a) Newton

Correct answer is (a) 112 km/h

Initial velocity of the car (u) = 0 m/s

Final velocity of the car (v) = 20 m/s

time taken = 10s

Acceleration = ?

Formula: Acceleration = \(\frac {20-0}{10}\) = \(\frac{20}{10}\)

Acceleration of the car = 2 m/s²

(b) can be zero or positive

(i) Velocity = \(\frac{Distance}{time}\) = \(\frac{100}{4}\) = 25 m/s

(ii) Speed of Usain Bolt = 10.43 m/s

Speed of Cheetah = 30 m/s

∴ Cheetah will be the winner

(iii) Average speed = \(\frac{Total\,distance\, covered}{total\,time}\)

= \(\frac{12 m }{21}\) = 0.571 m/s

Average velocity = 0 m/s

\(\frac{12 m }{21}\) = 0.571 m/s

Average velocity = 0 m/s 

Average velocity is zero because the starting point and the finishing point is same 

∴ Displacement is zero so, average velocity is also

∴Average velocity = \(\frac{Total\, displacement}{time}\)

1. She travelled 400 m.

2. Displacement is 100 m 

3. The object moves in a straight line in one direction without turning back.

4. The distance of a person = 30 km Displacement = 0 km.

5. (i.e.) The initial and the final position is same.

Distance : 17

Distance: 24 

Displacement: 3 

Displacement: 1 

When the rabbit moves in a straight line from A to B, the distance and displacement will be equal.

The leaf will reach the ground first by path – A, as it reaches the ground in straight line.

By choosing road A kavitha could reach the school early as the distance is less compared to road B.

Correct option is (a) depreciation

Path A is the longest among the two. as it is not a straight line.

When a curved road is unbanked force of friction between the tyres and the road provides the necessary centripetal force. Friction has to be increased which will cause wear and tear. But when the curved road is banked, a component of normal reaction of the ground provides the necessary centripetal force which reduces the wear and tear of the tyres  

(c) in accelerated motion

After refraction at two parallel faces of a glass slab, a ray of light emerges in a direction parallel to the direction of incidence of white light. As rays of all colors emerge in the same direction, i.e., the direction of the incidence of white light, there is no dispersion. However, there is lateral displacement.

मात्रक-वोल्ट/मीटर तथा विमा- [MLT^-3A^-1]

(iv) V, r पर निर्भर नहीं करेगा

1 MeV = 10⁶ eV = 10⁶ x 1.6 x 10^-19 जूल = 1.6 x 10^-13 जूल

वैद्युत क्षेत्र की तीव्रता E = – विभव प्रवणता = △V/△x

हाँ। उदाहरण के लिए, वैद्युत द्विध्रुव की निरक्षीय स्थिति में।

From the question is given that,

Base of the parallelogram = 15 cm

Area of the parallelogram = 54 cm²

∴area of the parallelogram = base × height

54 = 15 × height

Height = 54/15

Height = 3.6 cm

Hence, the height of the parallelogram is 3.6 cm

From the question is given that,

Area of the triangle = 224 m²

Base of the triangle = 28 m

∴ Area of the triangle = (1/2) × base × height

224 = (1/2) × 28 × height

224 = 1 × 14 × height

Height = 224/14

Height = 16 m

Hence, the height of the triangle is 16 m.

The length of a rectangular park = 2(its breadth)

Perimeter = 840 m (Given)

Let x be the breadth of a rectangular park then, length of a rectangular park is 2x m.

We know, Perimeter of rectangle = 2(Length + Breadth)

840 = 2(Length + Breadth)

840 = 2(2x + x)

840 = 6x

or x = 140

Breadth = x = 140 m

and Length = 2x = 2 x 140 = 280 m

Area of a rectangular park = Length x Breadth = 140 x 280 = 39200 m².

For the first triangle, given that

Base = 15 cm and altitude = 7 cm

We know that area of a triangle = ½ (Base x Altitude)

= ½ (15 x 7)

= 52.5 cm²

It is also given that the area of the first triangle and the second triangle are equal.

Area of the second triangle = 52.5 c m²

One side of the second triangle = 10.5 cm

Therefore, The other side of the second triangle = (2 x Area)/One side of a triangle

= (2x 52.5)/10.5

=10 cm

Hence, the other side of the second triangle will be 10 cm.

Given, altitude = 8 cm and area = 50 cm²

We know that the area of a triangle = ½ (Base x Height)

Therefore base of a triangle = (2 x Area)/ Altitude

Altitude = (2 x 50)/ 8

= 12.5 cm