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17251.

Prepare a questionnaire for estimating the demand of LP Gas as a domestic fuel. Questionnaire

Answer»

1. Name of the head of family:

2. Age:

3. Residential Address :

4. Martial Status: Married ☐ Unmarried ☐

5. No. of members of family (dependent)

6. Occupation: Service ☐ Self employed ☐

7. Average monthly income (in Rs.)

  • Up to Rs. 1000 ☐
  • Between Rs. 1000 to Rs. 2000 ☐
  • Between Rs. 2000 to Rs. 5000 ☐
  • Between Rs. 5000 to Rs. 10,000 ☐
  • More than Rs. 10,000 ☐

8. Which type of fuel do you use

  • Wood coal
  • Kerosene
  • Oil Gas

9. Do you use gas yes ☐ No ☐

10. Do you use only gas Yes ☐ No ☐

11. If you do not use gas, what is the main reason? 

  • Not getting the gas connection. ☐
  • Insufficient money to get connection ☐
  • Use of gas is unsafe ☐

12. If you use other fuel goods along with the use of gas, what is the main reason?

  • Non – availability of sufficient gas. ☐
  • Limited use of gas due to high price of gas ☐
  • For the point of view of health, use of gas for all activities is not right ☐

13. If you use gas, why?

  • Cheap than other types of fuel ☐
  • Use of gas is conveninent ☐
  • Any other reason ☐

14. How far is gas distribution agency from residence?

  • up to 1 km ☐
  • Between 1 km and 5 km. ☐
  • More than 5 km. ☐
17252.

Which one of the following is the standard for atomic mass? (a) 1H1 (b) 66C12 (c) 6C14 (d) 8O16

Answer»

(b) 66C12 

Standard element used to determine atomic mass is 6 Cl2

17253.

In a reaction x + y + z2 → xyz2 , identify the limiting reagent if any, in the following reaction mixtures. (a) 200 atoms of (x + 200) atoms of (y + 50) molecules of z2 (b) 1 mol of (x + 1) mol of (y + 3) mol of z2 (c) 50 atoms of (x + 25) atoms of (y + 50) molecules of z2(d) 2.5 mol of (x + 5) mol of (y + 5) mol of z2

Answer»

(a) 200 atoms of (x + 200) atoms of (y + 50) molecules of z2 

According to the reaction, 

1 atom of x reacts with one atom of y and one molecule of z to give product. In the case (a) 200 atoms of x, 200 atoms of y react with 50 molecules of z2 (4 part) 

i.e. 50 molecules of z2 react with 50 atoms of x and 50 atoms of y. 

Hence z is the limiting reagent.

(b) 1 mol of (x + 1) mol of (y + 3) mol of z2 

According to the equation, 

1 mole of z2 only react with one mole of x and one mole of y. If 3 moles of z2 are there, z2 is limiting reagent.

(c) 50 atoms of (x + 25) atoms of (y + 50) molecules of z2

25 atoms of y react with 25 atoms of x and 25 molecules of z2 . So y is the limiting reagent.

(d) 2.5 mol of (x + 5) mol of (y + 5) mol of z2

2.5 mol of x react with 2.5 mole of y and 2.5 mole of z2 . So x is the limiting reagent.

17254.

What is meant by limiting reagent?

Answer»

A large excess of one reactant is supplied to ensure the more expensive reactant is completely converted to the desired product. The reactant used up first in a reaction is called the limiting reagent.

17255.

What is meant by Plasma state? Give an example.

Answer»

Gaseous state of matter at very high temperature containing gaseous ions and free electron is referred to as the Plasma state. 

e.g, Lightning

17256.

Which one of the following is a diatomic molecule? (a) Ozone (b) Copper (c) Hydrogen (d) Gold

Answer»

Answer: (c) Hydrogen

17257.

Which of the following is a mono-atomic molecule?(a) Hydrogen (b) Oxygen (c) Sodium (d) Ozone

Answer»

Answer: (c) Sodium

17258.

Differentiate an element and an atom.

Answer»

\(\bullet\)  An atom is the ultimate smallest electrically neutral, being made up of fundamental particles such as proton, neutron and electron. 

 \(\bullet\)  An element consists of only one type of atoms. Elements are further divided into metals, non-metals, and metaloids.

17259.

Distinguish between a molecule and a compound.

Answer»

Molecule: 

\(\bullet\)  A molecule is the smallest particle made up of one or more than one atom in a definite ratio having stable and independent existence. 

 \(\bullet\)  e.g. Na – Mono atomic molecule O2 – Diatomic molecule P4 – Poly atomic molecule

Compound: 

 \(\bullet\)  A molecule which contains two or more atoms of different elements are called a compound molecule. 

 \(\bullet\)  e.g. CO2 – Carbon dioxide CH4 – Methane H2O – Water

17260.

Distinguish between oxidation and reduction.

Answer»

Oxidation: 

According to the classical concept, oxidation is a process of addition of oxygen or removal of hydrogen. 

Removal of hydrogen 

2H2S + O2 → H2O + 2S 

Addition of oxygen C + O2 → CO2 

According to the electronic concept, loss of electrons is called oxidation reaction.

Ca → Ca2+ + 2e- 

During oxidation, oxidation number increases. 

Dining oxidation, reducing agent gets oxidised.

Reduction: 

Reduction is a process of removal of oxygen or addition of hydrogen. Addition of hydrogen 

Ca + H2 → CaH2 

Removal of oxygen 

Zn O + C → Zn + CO 

According to the electronic concept, gain of electrons is called reduction reaction.

Zn2+ + 2e- → Zn 

During reduction, oxidation number decreases. 

During reduction, oxidising agent gets reduced.

17261.

Define equivalent mass.

Answer»

The equivalent mass of an element is the number of parts of the mass of an element which combines with or displaces 1.008 parts of hydrogen or 8 parts of oxygen or 35.5 parts of chlorine.

17262.

What do you understand by the term mole?

Answer»

The mole is defined as the amount of a substance which contains 6.023 x 1023 particles such as atoms, molecules or ions. It is represented by the symbol

17263.

What do you understand by the term oxidation number?

Answer»

Oxidation number refers to the number of charges an atom would have in a molecule or an ionic compound, if electrons were transferred completely. The oxidation numbers reflect the number of electrons “transferred”.

17264.

Calculate the equivalent mass of barium hydroxide.

Answer»

Barium hydroxide = Ba(OH)2 

Molecular mass of Ba(OH)2 = 137 + (16 x 2) + (1 x 2) 

= 171.0 g / mol. 

Acidity = 2 

Equivalent mass of Ba(OH)2 = 171.0 / 2

= 85.5

17265.

What do you understand by the terms acidity and basicity?

Answer»

Acidity:

The number of hydroxyl ions present in one mole of a base is known as the acidity of the base.

Basicity: 

The number of replaceable hydrogen atoms present in a molecule of the acid is referred to as its basicity.

17266.

Would you expect the first ionization enthalpies of two isotopes of the same element to be the same or different? Justify your answer.

Answer»

Ionization enthalpy, among other things, depends upon the electronic configuration (number of electrons) and nuclear charge (number of protons). Since isotopes of an element have the same electronic configuration and same nuclear charge, they have same ionization enthalpy.

17267.

Calculate the equivalent mass of bicarbonate ion.

Answer»

Bicarbonate ion = HCO3

Equivalent mass of an ion = (Formula mass of the ion) / (Negative charge of the ion)

Formula mass of HCO3 = 1 + 12 + 48 = 61 

Equivalent mass of HCO3 = 61/1 = 61

17268.

Calculate the mass of sodium (in kg) present in 95 kg of a crude sample of sodium nitrate whose percentage purity is 70%.

Answer»

Sodium Nitrate = NaNO3 

Molecular mass of Sodium Nitrate = 23 + 14 + 48 = 85 

100% pure 85 g of NaNO3 contains 23 g of Sodium. 

100% pure 95 x 103 g of NaNO3 will contains 23/85 x 95 x 103 

= 25.70 x 103 g of Sodium.

100% pure NaNO3 contains 25.70 x 103 g of Sodium. 

∴ 70% pure NaNO3 will contains = 1 mg 

= 17990 g (or) 17.99 Kg of Na.

17269.

Calculate the weight of 0.2 mole of sodium carbonate.

Answer»

Sodium carbonate = Na2CO3 

Molecular mass of Na2CO3 = (23 x 2)+(12 x 1)+(16 x 3) 

= 46 + 12 + 48 = 106 g 

Mass of 1 mole of Na2CO3 = (106 x 0.2)/1

= 21.2 g

17270.

In what period and group will an element with Z = 118 will be present?

Answer»

The element with atomic number Z = 118 is present in 7th period and 18th group.

17271.

The electronic configuration of an atom is one of the important factor which affects the value of ionization potential and electron gain enthalpy. Explain.

Answer»
  • Electronic configuration of an atom affects the value of ionization potential and electron gain enthalpy. 
  • Half filled valence shell electronic configuration and completely filled valence shell electronic configuration are more stable than partially filled electronic configuration. 
  • For e.g. Beryllium (Z = 4) 1s2 2s2 (completely filled electronic configuration)Nitrogen (Z = 7) 1s2 2s2 2px1 2py1 2pz1 (half filled electronic configuration) Both beryllium and nitrogen have high ionization energy due to more stable nature. 
  • In the case of beryllium (1s2 2s2), nitrogen (1s2 2s2 2p3 ) the addition of extra electron will disturb their stable electronic configuration and they have almost zero electron affinity. 
  • Noble gases have stable ns2 np6 configuration and the addition of further electron is unfavorable and they have zero electron affinity.
17272.

Describe the experiment that proved that DNA is the genetic material.

Answer»

Proof for DNA as the Genetic Material 

▪ Hershey and Chase conducted experiments on bacteriophage to prove that DNA is the genetic material. 

▪ Procedure: 

i. Some bacteriophage virus were grown on a medium that contained radioactive phosphorus (32P) and some in another medium with radioactive sulphur (35S). 

ii. Viruses grown in the presence of radioactive phosphorus (32P) contained radioactive DNA. 

iii. Similar viruses grown in presence of radioactive sulphur (35S) contained radioactive protein. 

iv. Both the radioactive virus types were allowed to infect E. coli separately. 

v. Soon after infection, the bacterial cells were gently agitated in blender to remove viral coats from the bacteria. 

vi. The culture was also centrifuged to separate the viral particle from the bacterial cell. 

▪ Observations and Conclusions: 

i. Only radioactive 32P was found to be associated with the bacterial cell, whereas radioactive 35S was only found in surrounding medium and not in the bacterial cell. 

ii. This indicates that only DNA and not protein coat entered the bacterial cell. 

iii. This proves that DNA is the genetic material which is passed from virus to bacteria and not protein.

17273.

What is binocular vision?

Answer»

When both the eyes can be focused simultaneously on a common object it is called binocular vision e.g., humans.

17274.

State Pascal’s law in fluids.

Answer»

If the pressure in a liquid is changed at a particular point, the change is transmitted to the entire liquid without being diminished in magnitude.

17275.

What is Pascal’s Law ? Give an examples.

Answer»

The increase in pressure at one point of the enclosed liquid in equilibrium of rest is transmitted equally to all other points of the liquid and also to the walls of the container, provided the effect of gravity is neglected. 

Example : Hydraulic lift, hydraulic press and hydraulic brakes.

17276.

An electric dipole is placed at the centre of a sphere. Mark the correct options: (a) The flux of the electric field through the sphere is zero. (b) The electric field is zero at every point of the sphere. (c) The electric field is not zero anywhere on the sphere. (d) The electric field is zero on a circle on the sphere.

Answer»

The correct answer is aa(A) (C)

(a) The flux of the electric field through the sphere is zero.

(c) The electric field is not zero anywhere on the sphere.

17277.

A large nonconducting sheet M is given a uniform charge density. Two uncharged small metal rods A and B are placed near the sheet as shown in figure (30-Q4). (a) M attracts A. (b) M attracts B. (c) A attracts B. (d) B attracts A.

Answer» The correct answer is all.
17278.

A charge Q is uniformly distributed over a large plastic plate. The electric field at a point P close to the centre of the plate is 10V/m. If the plastic plate is replaced by a copper plate of the same geometrical dimensions and carrying the same charge Q, the electric field at the point P will become(a) zero (b) 5V/m (c) 10V/m (d) 20V/m.

Answer» The correct answer is (c) 10V/m.
17279.

A charge q is placed at the centre of the open end of a cylindrical vessel (figure 30-Q3). The flux of the electric field through the surface of the vessel is (a) zero (b) q/ε0 (c) q/2ε0 (d) 2q/ε0.

Answer»

The correct answer is (c) q/2ε0 

17280.

Mark the correct options: (a) Gauss's law is valid only for symmetrical charge distributions. (b) Gauss's law is valid only for charges placed in vacuum. (c) The electric field calculated by Gauss's law is the field due to the charges inside the Gaussian surface. (d) The flux of the electric field through a closed surface due to all the charges is equal to the flux due to the charges enclosed by the surface.

Answer»

(d) The flux of the electric field through a closed surface due to all the charges is equal to the flux due to the charges enclosed by the surface.

17281.

A thin, metallic spherical shell contains a charge Q on it. A point charge q is placed at the centre of the shell and another charge q1 is placed outside it as shown in figure (30-Q1). All the three charges are positive. Theforce on the charge at the centre is(a) towards left (b) towards right(c) upward (d) zero.

Answer» The correct answer is (d) zero.
17282.

A positive point charge Q is brought near an isolated metal cube.(a) The cube becomes negatively charged.(b) The cube becomes positively charged.(c) The interior becomes positively charged and the surface becomes negatively charged.(d) The interior remains charge free and the surface gets nonuniform charge distribution.

Answer»

(d) The interior remains charge free and the surface gets nonuniform charge distribution.

Explanation:

Since the cube is metallic, the charge gets distributed on the surface and the interior remains charge-free. However, when a positive point charge Q is brought near the metallic cube, a negative charge gets induced on the face near the positive charge Q and an equal positive charge gets induced on the face, which is away from the charge Q. Thus, the metallic surface gets a non-uniform charge distribution. 

17283.

Consider the situation of the previous problem. The force on the central charge due to the shell is (a) towards left (b) towards right (c) upward (d) zero.

Answer»

(d) Zero

The charge q, which is kept at the centre of metallic spherical shell transfered to the outer surface of shell and inside the shell the electric field is zero and hence force is also zero.

17284.

A metallic particle having no net charge is placed near a finite metal plate carrying a positive charge. The electric force on the particle will be (a) towards the plate (b) away from the plate (c) parallel to the plate (d) zero.

Answer»

(a) towards the plate.

As the negative charge will be induced.

17285.

Electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10cm surrounding the total charge is 25V-m. The flux over a concentric sphere of radius 20cm will be (a) 25V-m (b) 50V-m (c) 100V-m (d) 200V-m.

Answer» The correct answer is (a) 25V-m.
17286.

A charge Q is placed at a distance a/2, above the centre of a horizontal, square surface of edge a as shown in figure (30-E1). Find the flux of the electric field through the square surface.

Answer»

Given – A charge is placed o a plain surface with area = a2, about a/2 from its centre.
Assumption : let us assume that the given plain forms a surface of an imaginary cube. Then the charge is found to be at the centre of the cube.
Hence flux through the surface = Q/ε0 x 1/6 = Q/6ε0

17287.

Figure (30-Q5) shows a charge q placed at the centre of a hemisphere. A second charge Q is placed at one of the positions A, B, C and D. In which position(s) of this second charge, the flux of the electric field through the hemisphere remains unchanged? (a) A(b) B (c) C (d) D.

Answer» The correct answer is (a) (C).
17288.

A closed surface S is constructed around a conducting wire connected to a battery and a switch (figure 30-Q6). As the switch is closed, the free electrons in the wire start moving along the wire. In any time interval, the number of electrons entering the closed surface S is equal to the number of electrons leaving it. On closing the switch, the flux of the electric field through the closed surface(a) is increased (b) is decreased(c) remains unchanged (d) remains zero.

Answer»

The correct answer is (c) (d)

(c) remains unchanged 

(d) remains zero.

17289.

If the flux of the electric field through a closed surface is zero.(a) the electric field must be zero everywhere on the surface(b) the electric field may be zero everywhere on the surface(c) the charge inside the surface must be zero(d) the charge in the vicinity of the surface must be zero.

Answer»

The correct answer is (b) (c) 

(b) the electric field may be zero everywhere on the surface
(c) the charge inside the surface must be zero

17290.

Figure (30-Q7) shows a closed surface which intersects a conducting sphere. If a positive charged is placed at the point P, the flux of the electric field through the closed surface(a) will remain zero (b) will become positive(c) will become negative (d) will become undefined.

Answer» (b) will become positive
17291.

What is the height of the object and height of the image if measured upward ?

Answer»

The height of the object and height of the image is positive, if measured upward.

17292.

What is magnification ?

Answer»

Magnification is positive for erect images and negative for the inverted images.

17293.

What is the angle of reflection?

Answer»

The angle of reflection (∠r): The angle between normal and reflected rays is called the angle of reflection.

17294.

What is the angle of incidence?

Answer»

The angle of incidence (∠i): The angle between the incident ray and normal is called the angle of incidence.

17295.

What is curved Surface?

Answer»

Curved Surface: The surfaces which are not flat are called curved surface

17296.

What is magnification?

Answer»

Magnification (m): Ratio of the size of the image to the size of the object.

17297.

What are the significance of Specific Heat of Gases ?

Answer»

There are two special significance :

(1) Specific heat of a gas at constant volume (Cv) : It is defined as the quantity of heat required to raise the temperature of unit mass of gas through 1 K when its volume is kept constant. 

(2) Specific heat of a gas at constant pressure (Cp) : It is defined as the quantity of heat required to raise the temperature of unit mass of gas through 1 K when its pressure is kept constant.

17298.

Differentiate Statements of Affairs and Balance sheet. 

Answer»
Statement of affairsBalance sheet
1.It is prepared under single entry system1.It is prepared under double entry system
2.It states estimated value of assets and liabilities.2.It states real value of assets and liabilities of a business concern.

17299.

What is Mayer’s Formula ?

Answer»

Cp – Cv = R 

This relation is called Mayer’s formula and shows that Cp > Cv i.e., molar specific heat at constant pressure is greater than that at constant volume.

17300.

The quantity pV/kT represents  (a) mass of the gas (b) kinetic energy of the gas (c) number of moles of the gas (d) number of molecules in the gas.

Answer»

(d) number of molecules in the gas.