This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 17651. |
Do you have a school song? What does it tell you? |
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Answer» Yes, we have a school song by the name ‘The Temple of Learning’. It tells us about how a school acts as a sheltered cocoon for students preparing them to take a flight spreading their wings in the beautiful world outside. |
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| 17652. |
Chalk out detailed programmes for the following occasions:1. The Teacher’s Day programme in your school. 2. An exhibition of science projects arranged in your classroom.3. A wedding anniversary/birthday celebration for your grandparents that you have arranged with your family. |
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Answer» 1. Teacher’s Day programme: 1. Welcome Speech by the Head Boy 2. Speech on importance of teachers by the Head Girl. 3. Felicitation of teachers 4. Address by the Principal 5. Cultural Programme 6. Games 7. Vote of thanks 8. National Anthem 9. Snacks 2. Exhibition of Science projects in classroom: 1. Welcome speech by monitor 2. Ribbon cutting ceremony 3. Speech by the Principal 4. Judging of projects 5. Prize distribution 6. Vote of thanks 7. National Anthem 3. Birthday celebration for grandfather: 1. Welcome grandparents 2. Power point show on Grandfather 3. Talks by relatives and friends 4. Cake cutting 5. Snacks and refreshment 6. Vote of thanks |
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| 17653. |
I suppose it doesn’t mind. (Pick out the pronoun and state its kind) |
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Answer» I – Personal pronoun (first-person pronoun) |
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| 17654. |
In which year Ganga Action Plan came about? (a) 1980 (b) 1985 (c) 1990 (d) 1975 |
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Answer» In 1985 Ganga Action Plan came about. |
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| 17655. |
Which is the school in question? |
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Answer» The school in question is Balanand Vidyalaya. |
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| 17656. |
State two reasons of launching the “Ganga Action Plan”. Which bacteria was found in Ganga’s water indicating contamination? |
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Answer» Two reasons for launching Ganga Action plan are- a. To improve quality of water of River Ganga. b. To reduce the pollution load of River Ganga and make people aware of preventing pollution of Ganga river. This plan was launched in 1985 by Mr. Rajeev Gandhi. Coliform bacteria were found in water of Ganga indicating contamination |
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| 17657. |
Name the group of bacteria that confirms the contamination of water. |
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Answer» Coliform group of bacteria that confirms the contamination of water. |
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| 17658. |
Name two factors which can be used to find whether river water has been contaminated |
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Answer» 1. The presence of coliform bacteria in rainwater. 2. Measurement of pH of rainwater. |
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| 17659. |
Why is the lamp said to be having an amazing quality? |
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Answer» A lamp can dispel or remove darkness and also help to light a thousand other lamps from its flames. Hence it is said to possess an amazing quality. |
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| 17660. |
Write the noun form of.1. waste 2. silent 3. know 4. believe 5. rude 6. civil |
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Answer» 1. wastage 2. silence 3. knowledge 4. belief 5. rudeness 6. civility |
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| 17661. |
Name the bacteria whose presence in water indicates the contamination with disease-causing micro-organisms. |
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Answer» Coliform bacteria. |
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| 17662. |
Name the bacteria whose presence in the water indicates its contamination with disease causing microbes. |
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Answer» Coliform bacteria. |
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| 17663. |
In the figure below ‘A’ shows a cell in the normal state and ‘B’ shows the same cell after leaving it in a certain solution for a few minutes.(i) Describe the change which has occurred in the cell as seen in B.(ii) Give the technical term for the condition of the cell as reached i n B and as it was in A.(iii) Define the process which led to this condition.(iv) What was the solution- isotonic, hypotonic or h ypertonic, in which the cell was kept ?(v) How can the cell in B, be brought back to its original condition ?(vi) Name the parts numbered 1 to 3. |
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Answer» (i) Exosmosis (exit of water ) has resulted in the shrinkage of the protoplasm of cell B. (ii) Plasmolysis and deplasmolysis. (iii) When plant cells are kept in a h ypertonic solution, exosmosis takes place. This process is called plasmolysis. (iv) Hyperton ic solution. (v) The cell in B can be b rought back to its original condition by placing it in a drop of distilled water. (vi) 1. Cell wall, 2. Plasma membrane, 3. Chloroplast. |
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| 17664. |
Differentiate between Active transport and Passive transport. |
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Answer» Active Transport: Minerals in solution are transferred from a region of their lower concentration to one of their higher concentration by using metabolic energy. Passive Transport: Minerals are transferred from a region of their higher concentration to a region of their lower concentration without using metabolic energy. |
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| 17665. |
Differentiate between Permeable and Semi-permeable membrane. |
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| 17666. |
A closed can of dried seeds bursts open if some water enters it by accident. Give Reasons. |
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Answer» If some water enters in a closed can of dried seeds, the seeds absorb water by imbibition and osmosis and swell up. The swelling up of seeds exerts a force on the walls of the can, and hence the can bursts open. |
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| 17667. |
Define Osmosis. |
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Answer» Osmosis: Osmosis is a special type of diffusion which involves the movement of solvent molecules from a region of their higher concentration to their lower concentration. |
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| 17668. |
The space between the cell wall and plasma membrane in a plasmolysed cell is filled with:(a) Isotonic solution (b) Hypotonic solution(c) Hypertonic solution (d) Water |
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Answer» The space between the cell wall and plasma membrane in a plasmolysed cell is filled with Isotonic solution. |
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| 17669. |
Marine fish when thrown under tap water bursts because of:(a) Endosmosis (b) Diffusion(c) Exosmosis (d) Plasmolysis |
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Answer» Marine fish when thrown under tap water bursts because of Endosmosis. |
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| 17670. |
The apparatus arranged here signifies an important process.(i) Name the process.(ii) Where does this process occur in plants?(iii) What solution is placed inside the dialysis tubing?(iv) What happens to the level of the solution in the capillary tube ?(v) Define the process mentioned in Q. (i) above. |
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Answer» (i) The process is called osmosis. (ii) This process occurs in the root hair cells of plants. (iii) The solution placed inside the dialysis tubing is generally strong sugar solution or salt solution. (iv) The level of the solution in the capillary tube rises above the original level. (v) Osmosis is a physiological process where the water molecules or solvent molecules move through a semipermeable membrane from a solution having a higher concentration of solvent molecules to the solution having a lower concentration of water or solvent molecules. |
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| 17671. |
Given below is the figure of an experimental set up to demonstrate root pressure.(i) Define root pressure.(ii) What change would you observe in the water level after sometime?(iii) What role is being played by the root pressure in the given experiment?(iv) Why the oil has been sprinkled on water? |
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Answer» (i) The collective force exerted by the cortical cells of the root in forcing water upward into the xylem is known as root pressure. (ii) The water level will rise in the glass tube. (iii) Root pressure is forcing the water up in the stem. (iv) To prevent evaporation of water from the tube. |
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| 17672. |
The diagram below represents an experimental set up to demonstrate a vital process. Study the same and then answer the questions that follow:(i) Name the process.(ii) Define the above named process.(iii) What would you observe in the experimental setup after an hour or so ?(iv) What control experiment can be set up for the above experiment ?(v) Keeping in mind the root hair cell and its surrounding name the par t that corresponds to (1) Concentrated sugar solution, (2) Parchment paper, (3) Water in the beaker.(vi) Name any other substance that can be used instead of parchment paper in the above experiment.(vii) Mention two advantages of this process to the plant. |
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Answer» (i) Osmosis. (ii) Transfer of water or solvent molecules from a solution of lower concentration to a solution of higher concentration through a semi-permeable membrane is called osmosis. (iii) Level of sugar solution rises in the stem of thistle funnel, whereas water level in the beaker falls. (iv) A non-permeable membrane can be used in place of parchment paper for a control experiment. (v) (1) Root hair cell sap corresponds to concentrated sugar solution. (2) Cell membrane of root hair cell corresponds to parchment paper. (3) Soil solution corresponds to water in the beaker. (vi) Goat’s bladder or pig’s bladder. (vii) (1) Helps in water absorption. (2) Helps in stomatal opening and closing thus facilitating gaseous exchange. |
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| 17673. |
Plasma membrane controls:(a) Passage of water only(b) Passage of water and solutes in and out of the cell(c) Passage of water and solutes into the cell(d) Movement of cell contents out of the cell |
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Answer» (b) Passage of water and solutes in and out of the cell |
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| 17674. |
Given below is the diagram of a cell as seen under the microscope after having been placed in a solution :(i) What is the technical terms used for the state/condition of the cell given above ?(ii) Give the technical term for the solution in which the cell was placed.(iii) Name the parts numbered 1 to 4.(iv) Is the cell given above a plant cell or an animal cell ? Give two reasons in support of your answer as evident from the diagram.(v) What would you do to bring this cell back to its original condition. |
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Answer» (i) Plasmolysis (ii) Hypertonic solution (iii) (1) Nucleus, (2) Sugar drops, (3) Small vacuole, (4) Large vacuole. (iv) Plant cell (1) Presence of cell wall, (2) Presence of large vacuole. (v) It has to be placed in a hypotonic solution. |
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| 17675. |
On sprinkling common salt on grass growing in a lawn, the grass is killed. Give Reasons. |
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Answer» Sprinkling salt makes soil solution hypertonic hence grass lose water due to exosmosis. |
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| 17676. |
The below diagram represents a plant cell after being placed in a strong sugar solution. Guidelines 1 to 5 indicate the following :1. Cell wall2. Plasma membrane.3. Protoplasm4. Large vacuole5. NucleusStudy the diagram and answer the questions that follow :(i) What is the state of the cell shown in the diagram ?(ii) Name the structure which acts as a selectively permeable membrane.(iii) If the cell had been placed in distilled water instead of strong sugar solution which feature : would not have been present ?(iv) If the cell in the diagram possessed chloroplasts where would these be present ?(v) Name any one feature of this plant cell which is not present in animal cells. |
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Answer» (i) Flaccid. (ii) Plasma membran e. (iii) If the cell had been placed in distilled water it remains in a fully distended condition. Its plasma membrane remains in close contact with the cell wall and presses against it. (iv) Chloroplast will be present in the protoplasm outside the vacuole. (v) Cell wall. |
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| 17677. |
The inward movement of solvent molecules through the plasma membrane of a cell. Name it. |
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Answer» The inward movement of solvent molecules through the plasma membrane of a cell Endosmosis. |
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| 17678. |
Salt and sugar are used in preserving food. Give Reasons. |
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Answer» Salt and sugar increase concentration of food, destroying bacteria by plasmolysis. |
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| 17679. |
The solution outside the cell having lower solute concentration than the fluids. |
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Answer» The solution outside the cell having lower solute concentration than the fluids is Hypotonic. |
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| 17680. |
A solution whose concentration is greater than that of the cell sap. |
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Answer» A Hypertonic solution concentration is greater than that of the cell sap. |
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| 17681. |
Process of endosmosis stops:(a) When equal(b) When solution becomes isotonic(c) When the leaves fall .(d) When there is no light |
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Answer» (b) When solution becomes isotonic |
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| 17682. |
Differentiate between Turgor pressure and Wall pressure. |
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| 17683. |
It is necessary to maintain a normal osmotic concentration of the blood. Give Reasons. |
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Answer» Osmotic pressure is maintained in blood to prevent dehydration leading to shrinkage of cells. |
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| 17684. |
A solution whose concentration is equal to the cell sap. |
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Answer» Isotonic solution concentration is equal to the cell sap. |
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| 17685. |
What is Endosmosis? |
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Answer» Endosmosis: It is the movement of water molecules from the surroundings into the cell. |
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| 17686. |
Differentiate between Turgor pressure and Root pressure. |
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| 17687. |
Differentiate between Endosmosis and Exosmosis. |
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| 17688. |
Solutions which have the same osmotic pressure. |
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Answer» Isotonic Solutions have the same osmotic pressure. |
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| 17689. |
Define Exosmosis. |
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Answer» Exosmosis: It is the movement of water molecules from the cell into the outer surroundings. |
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| 17690. |
Differentiate between Plasmolysis and Deplasmolysis. |
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| 17691. |
Give the technical name Phenomenon of absorption of water by surface attraction. |
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Answer» Phenomenon of absorption of water by surface attraction is Imbibition. |
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| 17692. |
Condition of cell in which the cell content are shrunken. |
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Answer» Condition of cell in Plasmolysed the cell content are shrunken. |
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| 17693. |
What is Plasmolysis? |
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Answer» Plasmolysis: It is the shrinkage of protoplasm from cell wall when a cell is placed in a hypertonic solution. |
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| 17694. |
Column ‘II’ is a list of items related to ideas in Column ‘I’. Match the term in Column ‘II’ with the suitable idea given in Column ‘I’.Column IColumn II(i) Diffusion(a) The exit or flow of water from the cell to the outer environment.(ii) Xylem(b) The shrinkage of protoplasm when the cell is kept in a hypertonic solution.(iii) Root pressure(c) The tissue through which water and mineral salts move upward in a plant.(iv) Isotonic solution(d) Two solutions which have equal osmotic pressure.(v) Exosmosis(e) The process by which the molecules of perfume spread in the room when the bottle is open.(vi) Osmosis(f) The process by which roots absorb water from the soil.(vii) Plasmolysis(g) The pressure by which water rises upto some feet in a lofty tree.(viii) Hypotonic solution(h) The concentration of the solution when lower than that of the cell sap. |
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| 17695. |
Mention, if the following statements are True or False. If false rewrite the wrong statement in its correct form:1. Plasmolysis makes the cell turgid. 2. Cells that have lost their water content are said to be deplasmolysed. 3. Fladdity is the reverse of turgidity. |
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Answer» 1. False, It makes the cell flaccid. 2. False, The cells that have lost their water content are said to be plasmolysed. 3. True |
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| 17696. |
When cell is fully turgid, which of the following will be zero?(a) Osmotic pressure(b) Turgor pressure(c) Wall pressure(d) Suction pressure (SP) or diffusion pressure deficit (DPD) |
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Answer» (d) Suction pressure (SP) or diffusion pressure deficit (DPD) |
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| 17697. |
The process by which raisins swell up when placed in a beaker of water. |
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Answer» The process by Osmosis raisins swell up when placed in a beaker of water. |
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| 17698. |
The diagram given below is of an experiment just at the start. Study the diagram carefully and answer the following questions :(i) What does the experiment demonstrate ?(ii) Define, the process demonstrated in the experiment.(iii) What changes are observed after a few hours?(iv) Give two examples of a semi permeable membrane.(v) Which limb of the U-tube contains more concentrated sucrose solution,, A or B?(vi) Why is the membrane separating the two solutions labeled as semi permeable membrane? |
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Answer» (i) The process of osmosis. (ii) Osmosis is a special type of diffusion of solvent molecules through a semi-permeable membrane from region of their higher concentration to the lower concentration region, but not vice-versa. (iii) The level of water in column A will rise along with passage of time and will ultimately stop when concentration of water molecules are equal on both sides of the membrane. (iv) (a) Parchment paper, (b) Egg membrane. (v) Solution A. (vi) It permits the movement of only water molecules to pass through it. |
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| 17699. |
Name the process by which water enters the root hair cell. |
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Answer» The process by Osmosis water enters the root hair cell. |
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| 17700. |
The below figure shows a root hair:(i) Label the parts 1 to 4.(ii) What is the role of pa rt 4 ?(iii) Why is the root hair one-celled ?(iv) What will happen to the root hair if some fertilizer is added to the soil near the root hair? |
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Answer» (i) 1. Nucleus 2. Vacuole 3. Cell wall 4. Cell membrane (ii) Part 4 is the cell membrane. It is semi-permeable. It allows only water molecules to pass through it. (iii) Because it is an extension of epiblema cell. (iv) By the addition of fertilizer, root hair becomes flaccid, because water will move out of it as soil water becomes hypertonic. |
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