Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The correct set of quantum numbers for the unpaired electrons of Flourine atom is

Answer»

Electronic configuration of F is 1s2 2s2 2p5 now the unpaired electron is in 2p subshell so 
n = 2
for n = 2 we know L = 1
also possible values for m could be - L to + L
and spin quantum number has values like + 1/2  or  - 1/2

2.

Acidic character of liquid HF increases on addition of which of the following compound ? a. SiF4b. SF6c. BF3d. a and c both

Answer»
The acidity of liquid HF can be increased by adding one of several inorganic fluorides that are Lewis acids and accept F ion (for example, BF3 or SbF5).

Correct answer is (d) a and c both 

Acidity of liquid HF will increased by adding Lewis acid fluorides-

ex - BF3, SiF4, SbF5 etc.

SiF4 + 2HF → H2[SiF6\(\rightleftharpoons\) 2H+ + [SiFb]-2

BF3 + HF → HBF4 \(\rightleftharpoons\) H+ + BF4

3.

The correct order of `S_N 2//E2` ratio for the % yield of product of the following halide is- (P)`CH_3-CH-undersetunderset(I)(|)oversetoverset(Ph)(|)C-CH_3` , (Q)`CH_3-undersetunderset(Ph)(|)CH-undersetunderset(I)(|)CH-CH_3` (R)`CH_3-CH_2-I` , (S)`CH_3-CH-undersetundersetI|CH-CH_3`A. RgtSgtQgtPB. RgtQgtSgtPC. PgtRgtSgtQD. QgtPgtRgtS

Answer» Correct Answer - A
As steric hindrance increases rate of `S_(N_2)` decrease and rate of E2 increases.
4.

Observe the esterfication mechanisms for primary and tertiary alcohols. `CH_3-COOH+Ph-undersetunderset(C_2H_5)(|)oversetoverset(CH_3)(|)C-OHoverset(Conc.H_2SO_4)to(Y)`A. (X) is optically active while (Y) is optically inactiveB. Both (X) and (Y) are optically activeC. Both (X) and (Y) are optically inactiveD. (X) is optically inactive while (Y) is optically active

Answer» Correct Answer - A
X is formed by type-1 mechanism hence configuration is retained.
Y is formed by type-2 mechanism hence recemic product is obtained.
5.

Observe the esterfication mechanisms for primary and tertiary alcohols. `CH_3-COOH+C_2H_6overset(18)OHoverset(Conc.H_2SO_4)to(P)` `CH_3-COOH+(CH_3)_3C-overset(18)OHoverset(Conc.H_2SO_4)(Q)` In the above reaction (P) and (Q) are respectively :A. `CH_3-oversetoverset(O)(||)C-O-C_2H_6,CH_3-oversetoverset(O)(||)C-overset(18)(O)-undersetunderset(CH_3)(|)oversetoverset(CH_3)(|)C-CH_3`B. `CH_3-oversetoverset(O)(||)C-overset(18)(O)-C_2H_5,CH_3-oversetoverset(O)(||)C-O-undersetunderset(CH_3)(|)oversetoverset(CH_3)(|)C-CH_3`C. `C_2H_5-oversetoverset(O)(||)C-overset(18)(O)-CH_3, CH_3-oversetoverset(O)(||)C-O-undersetunderset(CH_3)(|)oversetoverset(CH_3)(|)C-CH_3`D. `CH_3-oversetoverset(O)(||)overset(18)(O)-C_2H_6,CH_3-oversetoverset(O)(||)C-overset(18)(O)-undersetunderset(CH_3)(|)oversetoverset(CH_3)(|)C-CH_3`

Answer» Correct Answer - B
P is formed by type-1 mechanism and Q is formed by type-2 mechanism.
6.

Assertion : Ethers behave as bases in the presence of mineral Reason : Due to the presence of lone electron pair on the oxygen atom.A. Both A and B are true and R is the correct explanation of A.B. A is true but R is False.C. A is False but R is True.D. Both A and R are false.

Answer» Correct Answer - A
Reason is correct explanation for assertion.
7.

Assertion : `(CH_3)_(3)COH` when heated with conc. `H_2SO_4` gives isobutylene as the main product and not di-tertiary butyl ether. Reason : All alcohols are radily dehyrated with conc. `H_2SO_4`A. Both A and B are true and R is the correct explanation of A.B. A is true but R is False.C. A is False but R is True.D. Both A and R are false.

Answer» Correct Answer - C
`(CH_3)_3overset(+)C` carbocation is quite stable and loses a`H^(+)` ion to form isobutylene as the product.
8.

As `S_(N^(2))` reaction at an asymmetric carbon of a compound always gives:A. an enantiomer of the substrateB. a product with opposite optical rotationC. a mixture of diastereomersD. a single stereoisomer

Answer» Correct Answer - D
9.

In the button cells widely used in watCHMes and other devices the following reaction takes place : `Zn(s)+Ag_(2)O(s)+H_(2)O(l) rarr Zn^(2+)(aq)+2Ag(s)+2OH^(c-)(aq)` Determine `Delta_(r)G^(c-)` and `E^(c-)` for the reaction.

Answer» Correct Answer - `a. 1.104V` , `b. -2.13xx10^(5)J`
`a.` `E_(cell)^(c-)=E_((Ag_(2)O|Ag)"red")^(c-)-E_((Zn^(2+)|Zn)"red")^(c-)`
`=0.344-(-0.76)=1.104V`
`b. Delta_(r)G^(c-)=-nFE^(c-).(n_(cell)=2)`
`-2xx96500xx1.104J`
`=-2.13xx10^(5)J`
10.

Aluminium metal is not extracted directly from Bauxite ore. The ore is first purified to give pure alumina from which aluminium is isolated by electro reduction process. Explain.

Answer» Bauxite `(Al_(2)O_(3).xH_(2)O)` is associated with the impurities of ferric oxide and silica. In case, Bauxite is used directly for the extraction of aluminium, iron and silica present in it would deposit at the cathode during its electrolyte reduction. As a result, aluminium obtained from cathode gets contaminated with iron and silica. This makes the metal brittle. It is readily attacked by air and water.
11.

What do you mean by conductivity of a material ? Give its SI units.

Answer»

Conductivity is the reciprocal of the resistivity. 

It can be expressed as— 

σ = 1/P

Its S.I. unit is siemen metre–1 (Sm–1) or ohm–1 m–1

12.

The correct statement regarding the third orbit of hydrgen atom isA. it can accommodate a maximum of nine electronsB. it contains nine degenerated atomic orbitalsC. it contains nine atomic orbitals having three sets of degeneracyD. it contains nine sub-shells.

Answer» Correct Answer - B
In H-atom the orbitals (five 3d, three 3p and one 3s) have same energy so they are called degenerate orbitals
13.

The specific conductance of a saturated solution of silver bromide is `KScm^(-1)`. The limiting ionic conductivity of `Ag^(+)` and `Br^(-)` ions are x and y respectively. The solubility of silver bromide in g/L is (molar mass of `AgBr=188`)A. `(Kxx1000)/(x-y)`B. `(K)/(x+y)xx188`C. `(Kxx1000xx188)/(x+y)`D. `(x+y)/(k)xx(1000)/(188)`

Answer» Correct Answer - C
`AgBr=x+y`
`AgBr=(Kxx1000)/(M)`
M-molarity of `AgBr` solution
8 (solubility in g/L)`=(Kxx1000)/((x+y))xx188`
14.

An alternate substrate for orotate phosphoribosyl transferase is (A) Allopurinol (B) Xanthine (C) Hypoxanthine (D) Adenine

Answer»

Correct option (D) Adenine

15.

A substrate for enzymes of pyrimidine nucleotide biosynthesis is (A) Allopurinol (B) Tetracylin (C) Chloramphenicol (D) Puromycin

Answer»

(A) Allopurinol

16.

All of the following statements about puromycin are true except (A) It is an alanyl tRNA analogue (B) It causes premature termination of protein synthesis (C) It inhibits protein synthesis in prokaryotes (D) It inhibits protein synthesis in eukaryotes

Answer»

(A) It is an alanyl tRNA analogue

17.

All of the following statements about allopurinol are true except (A) It is a structural analogue of uric acid (B) It can prevent uric acid stones in the kidneys (C) It increases the urinary excretion of xanthine and hypoxanthine (D) It is a competitive inhibitor of xanthine oxidase

Answer»

(A) It is a structural analogue of uric acid

18.

All of the following statements about uric acid are true except (A) It is a catabolite of purines (B) It is excreted by the kidneys (C) It is undissociated at pH above 5.8 (D) It is less soluble than sodium urate

Answer»

(C) It is undissociated at pH above 5.8 

19.

Which pathway is correct for catabolism of purines to form uric acid? (A) Guanylate→Adenylate→Xanthine→hypoxanthine→Uric acid (B) Guanylate→inosinate→Xanthine→hypoxanthine→Uric acid (C) Adenylate→Inosinate→Xanthine hypoxanthine→Uric acid (D) Adenylate→Inosinate→hypoxanthine Xanthine→Uric acid

Answer»

(D) AdenylateInosinate  hypoxanthine XanthineUric acid

20.

what type of resistance can be used for developing strengh

Answer»

Follow the below link

https://bit.ly/2Hmf8G4

21.

In humans end product of purine catabolism is (A) Uric acid (B) Urea (C) Allantoin (D) Xanthine

Answer»

(A) Uric acid

22.

Arrange `Ce^(3+),La^(3+), Pm^(3)` and `Yb^(3+)` in increasing order of their size -A. `La^(3+) lt Ce^(3+) lt Pm^(3+) lt Yb^(3+)`B. `Yb^(3+) lt Pm^(3+) lt Ce^(3+) lt La^(3+)`C. `La^(3+) = Ce^(3+) lt Pm^(3+) lt Yb^(3+)`D. `Yb^(3+) lt Pm^(3+) lt La^(3+) lt Ce^(3+)`

Answer» Correct Answer - B
For tripositive ions of Lanthanoids size decrease regularly as atomic no. increase due to Lanthanoid contraction.
23.

निम्नलिखित गद्यांश को ध्यानपूर्वक पढ़कर पूछे गये प्रश्नों के सही विकल्प का चयन कीजिए-महात्मा गाँधी अपना काम अपने हाथ से करने पर बल देते थे। वह प्रत्येक आश्रमवासी से आशा करते थे कि वह अपने शरीर से सम्बन्धित प्रत्येक कार्य, सफाई तक स्वयं करेगा। उनका कहना था कि जो श्रम नहीं करता है, वह पाप करता है और पाप का अन्न खाता है। ऋषि-मुनियों ने कहा है बिना श्रम किये जो भोजन करता है, वह वस्तुतः चोर है। महात्मा गाँधी का समस्त जीवन-दर्शन श्रमसापेक्ष था। उनका समस्त अर्थशास्त्र यही बताता था कि प्रत्येक उपभोक्ता को उत्पादनकर्ता होना चाहिए। उनकी नीतियों की उपेक्षा करने के परिणाम हम आज भी भोग रहे हैं। न गरीबी कम होने में आती है, न बेरोजगारी पर नियंत्रण हो पा रहा है और न अपराधों की वृद्धि हमारे वश की बात रही है। दक्षिण कोरियावासियों ने श्रमदान करके ऐसे श्रेष्ठ भवनों का निर्माण किया है, जिनसे किसी को भी ईष्र्या हो सकती है।(क) महात्मा गाँधी प्रत्येक आश्रमवासी से क्या आशा करते थे?(i) वह आश्रम के सभी काम स्वयं करें(ii) वह परिश्रमशील बने ।(iii) वह अपने शरीर से सम्बन्धित प्रत्येक कार्य स्वयं करें(iv) वह आश्रम के कार्यों में सहयोग करें।(ख) ऋषि-मुनियों ने किस प्रकार के व्यक्ति को चोर कहा है?(i) जो किसी को हानि पहुँचाता है।(ii) जो चोरी करता है।(iii) जो बिना श्रम किये भोजन करता है।(iv) जो असत्य भाषण करता है।(ग) दक्षिण कोरियावासियों ने श्रमदान करके किस प्रकार की चीजों का निर्माण किया है?(i) श्रेष्ठ मन्दिरों का(ii) श्रेष्ठ भवनों का(iii) श्रेष्ठ पुलों का(iv) श्रेष्ठ बाँधों का

Answer»

(क) (iii) वह अपने शरीर से सम्बन्धित प्रत्येक कार्य स्वयं करें।

(ख) (iii) जो बिना श्रम किये भोजन करता है।

(ग) (ii) श्रेष्ठ भवनों का

24.

The ratio of alcohol and water in to two glasses is  2 : 3 and 5 : 4 respectively. In what ratio should the liquid in both the glasses be mixed to obtain a new mixture containing alcohol and water in the ratio 1 : 1?1. 5 : 92. 9 : 73. 7 : 54. 9 : 11

Answer» Correct Answer - Option 1 : 5 : 9

Given:

Ratio of alcohol and water in first glass = 2 : 3

Ratio of alcohol and water in second glass = 5 : 4

Ratio of alcohol and water in the final mixture = 1 : 1

Calculation:

Let the ratio of amounts of liquid mixed from first glass and second glass to obtain the final mixture be p : q

Amount of alcohol in final mixture = 2/5 × p + 5/9 × q

⇒ 2p/5 + 5q/9

Amount of water in final mixture = 3/5 × p + 4/9 × q

⇒ 3p/5 + 4q/9

Final ratio of alcohol and water in the final mixture = (2p/5 + 5q/9)/(3p/5 + 4q/9)

⇒ (2p/5 + 5q/9)/(3p/5 + 4q/9) = 1/1

⇒ (2p/5 + 5q/9) = (3p/5 + 4q/9)

⇒ 5q/9 – 4q/9 = 3p/5 – 2p/5

⇒ q/9 = p/5

⇒ p/q = 5/9

∴ The ratio will be 5 : 9

25.

Xenon crystallizes in the face-centred cubic lattice and the edge of the unit cell is `620` pm. What is the nearest neighbour distance and what is the redius of xenon atom?A. 219.20pmB. 438.5 pmC. 265.5 pmD. 536.94 pm

Answer» Correct Answer - A
`(a)(2)/(sqrt(2))`
`=(620)/(2(sqrt(2)))` pm
`r=219.20` pm
26.

Arrange the following a.`CaH_(2),BeH_(2)`and `TiH_(2)` in order of increasing electrical conductance. b. `LiH,NaH` and `CsH` in order of increasing ionic character. c. `H-H,D-D` and `F-F` in order of increasing bond dissociaton enthalpy. d. `NaH,MgH_(2)` and `H_(2)O` in order of increasing reducing property.

Answer» a. The order of increasing electric conductance is
`BeH_(2)ltCH_(2)ltTiH_(2)`
Skince `CaH_(2)` is an ionic hydride, it conducts electricity in fused state, `BeH_(2)` being covalent hydride does not conduct electricity at all. `TiH_(2)`, a metallic hydride conducts electricity at room temperature.
b. The order of increasing ionic character is
`LiHltNaHltCsH`
Down the group `(darr)`, from `Li` to `Cs`, electronegativity decreases adn and hence ionic character increases.
c. Order of increasing bond dissociation enthalpy:
`F-FltH-HltD-D`
Due to greater nucleus mass, the bond pair in `D-D` bond is attracted more strongly than in `H-H` bond. Thus, the bond dissociation enthalpy of `D-D` is higher than `H-H` bond. However, due to repulsion between lone pairs of `F` and the bond, `F-F` bond dissociation enthalpy is the minimum, and hence the order.
d. Order of increasing reducing property:
`H_(2)OltMgH_(2)ltNaH`
`NaH` is ionic hydride whereas `H_(2)O` adn `MgH_(2)` are covalent hydrides. Ionic hydrides are stronger reducing agent as compared to covalent hydrides. Hence `NaH` is stronger reducing agent as compared to `H_(2)O` and `MgH_(2)`. Out of `H_(2)O` and `MgH_(2)`, hence `H_(2)O` is weaker reducing agent as compared to `MgH_(2)`.
27.

Metallic gold frequently is found in aluminosilicate rocks and it is finely dispersed among other minerals. It may be extracted by treating the crushed rock with aerated sodium cyanide solution. During this process metallic gold is slowly converted t `[Au(CN)_(2)]^(-)`, which is soluble in water. After equlibrium has been reached, the aqueous phase is pumped off and the metallic gold is recovered from it by reacting the gold complex with zinc, which is converted to `[Zn(CN)_(4)]^(2-)`, Gold in nature is frequently alloyed with silver is also oxidised by aerated sodium cyanide solution. Which of the follwing is/are correct for cyanide process of extraction of gold?A. Sodium cynaide is sweet in taste and is also used in making chocolatesB. Sodium cyanide if escapes into ground water then it produces hydrogen cyanide which is toxic to many animals.C. It is an example of pyrometallurgy.D. It is an example of leaching process

Answer» Correct Answer - B::D
(B) `HCN` produced with water by `NaCN` and `KCN` is poisonous and have carcinogenic activity.
28.

A cubic solid is made of two element `P` and `Q` Atoms of `Q` are the corners of the cube `P` at the body-centre. What is the formula of the compound? What are the coordination number fo `P` and `Q`?

Answer» Number of `Q` atoms per unit cell of cube `= (1)/(8) xx 8 = 1`
Number of `P` atoms `= 1//"unit cell`.
The formula of the compound is `PQ` or `QP`.
The coordinate number of each of `P` and `Q` is 8 becuause the crystal has body-centred cubic structure.
29.

Niobium crystallizes in body-centred cubic structure. If the density is `8.55 g cm^(-3)`, calculate the atomic radius of niobium using its atomic mass `93 u`.

Answer» Density, `rho = 8.55 g cm^(-3)`
Atomic mass of niobrium, `Aw = 94.0`
`rho = (Z_(eff) xx Aw)/(a^(3) xx N_(A))` or `a^(3) = (Z_(eff) xx Aw)/(rho xx N_(A))`
Or `a^(3) = (2 xx 94)/(8.55 xx 6.02 xx 10^(23)) = (108)/(51.47) xx 10^(-23)`
`= 3.27 xx 10^(-23) cm^(3)`
Or `a = (3.27 xx 10^(-23))^(1//3) cm`
`= 14.29 cm`
30.

\( 1.84 gm \) mixture of \( CaCO _{3} \) & \( MgCO 3 \) exactly produces 0.88 g  CO2 on strongly heating, calculate \( \% \) composition of original mixture.

Answer»

Let say x.g CaCO3 is present in mixture.

∴ Weight of MgCO3 in mixture = (1.84 - x)g.

\(\underset{1 mol}{CaCO_3} \overset{\Delta}\longrightarrow \underset{1 mol}{CaO} + \underset{1 mol} {CO_2}\)

∴ Number of moles of CO2 produced by CaCO3 = \(\frac x{100}\) mol

\(\underset{1 mol}{MgCO_3} \overset{\Delta}\longrightarrow \underset{1 mol}{MgO} + \underset{1 mol}{CO_2}\)

∴ Number of mole of CO2 produced by MgCO\(\frac{1.84 - x}{84}\) mol

But we have given 0.88g CO2 produced.

∴ \(\left(\frac x{100} + \frac{1.84 - x}{84}\right)\times 44 = 0.88 g\)

∴ \(\frac x{100} + \frac{1.84 - x}{84} = 0.02\)

\(84x + 184 - 100 x = 0.02 \times 8400\)

\(184 - 16x = 168\)

\(16x = 184 - 168\)

\(16x = 16\)

\(x = 1 g\)

∴ Weight of CaCO3 in mixture = 1g

and Weight of MgCO3 = (1.84 - 1)g

∴ % composition of CaCO3\(\frac1{1.84} \times 100\) = \(54.35\)%

∴ % composition of MgCO3\(\frac{0.84}{1.84} \times 100\) = \(45.65\)%

31.

The molecular conductivity of acetic acid at infinite dilution is `390 S cm^(2) "mole"^(-1)` and for `0.1` acetic and solution is `5.8 cm^(3) "mole"^(-1)` .The hydrogen ion concentration of the solution isA. `15 xx 10^(-3)`B. `15 xx 10^(-4)`C. `66 xx 10^(-3)`D. `66 xx 10^(-4)`

Answer» Correct Answer - b
`alpha = (^^_C)/(^^ ^(prop)) = (5.8)/(390) ~= 15 xx 10^(-3)`
`[H^(-)] = Cu = 0.1 xx 15 xx 10^(-3) = 15 xx 10^(-4)`
32.

The first clinical gene therapy was done for the treatment of(A) AIDS (B) Cystic fibrosis (C) Cancer (D) SCID

Answer»

Correct option is: (D) SCID

33.

A 2.05MB 0.50MC 1.78MD 1.02M

Answer»

As We know that

Density of solution  = Mass of solution / Volume of solution 

therefore , volume of solution  = Mass / density =   120+1000 g/ 1.15 g ml-1 

= 1120 *100 / 115  = 973.91 ml = 974 * 10 -3 litres 

Now ,

n (no. of moles of solute) = 120 g / 60.05 g = 2 mol [since, molecular mass of urea is 60.05 g]

Now ,M(Molarity) = n (no. of moles of solute)/ Volume of solution in litres

 Molarity  = 2 / 974 * 10-3

Molarity = 2000/974 = 2.05 M

34.

An azeotropic solution of two liquids will have boiling point lower than two liquids when it.(a) Shows positive deviation from Raoult’s law (b) Shows negative deviation from Raoult’s law (c)Shows no deviation from Raoult’s law(d) None of these 

Answer»

An azeotropic solution of two liquids will have boiling point lower than two liquids when it Shows positive deviation from Raoult’s law 

35.

Assertion : Variety of fruit colours in Cucurbita pepo is result of recessive epistasis Reason : In recessive epistatsis, a recessive gene at one locus engances the expression of another gene, at a diferent locus.

Answer» Correct Answer - D
Fruit colour of summer squash (Cucurbita pepo) is governed by a gene which produced yellow colour in dominant state (Y) and green colour in recessive state (yy). There is a non-pigment forming epistatic gene which in dominant state (W-) produces white colour (W-Y-,W-yy) while in recessive state it allows the yellow (wwY-) and green (wwyy) expression. This shows dominant epistasis where a dominant epistatic allele suppresses the expression of a non allelic gene whether the latter is dominant or recessive
36.

Spices are the buds, fruits, flowers, bark, seeds and roots of plants and trees which are used in their natural / dried form to impart taste to food. Apart from this they also carry a wide range of medicinal properties, aroma and also may impart colour to the food. Which of the following spice has astringent and antifungal properties? a. Cinnamon b. Caraway c. Nigella d. Nutmeg

Answer»

a. Cinnamon

Cinnamon has astringent and antifungal properties.

37.

difference between multicellular and unicellular

Answer» Unicellular Organisms Multicellular Organisms

Unicellular organisms are composed of a single

Simple body organization 

A single cell carries out all necessary life processes

The total cell body is exposed to the environment 

Division of labour is at the organelle level 

Includes both eukaryotes and prokaryotes   

A lifespan of a unicellular organism is usually short 

 Multicellular Organisms

 Multicellular organisms are composed of more than one cell

Complex body organization

A single cell carries out all necessary life Simple body organization
 

processes Multiple cells perform different functions

The total cell body is exposed to the environment Only the outer cells are exposed to the environment

Division of labour is at the organelle level Division of labour is at cellular, tissue, organs and organ system level

Includes both eukaryotes and prokaryotes Includes only eukaryotes

A lifespan of a unicellular organism is usually short Multicellular organisms have a comparatively longer lifespan

Injury to the cell leads to the death of the organism Injury to a cell does not cause the death of the multicellular organism

38.

“All veins carry deoxygenated blood and all arteries carry oxygenated blood.” 1. Do you agree? 2. Justify your answer.

Answer»

1. Statement is incorrect. 

2. Arteries are the blood vessels which carry blood away from the heart. Veins are the blood vessels which carry blood towards the heart. All arteries carry oxygenated blood except pulmonary artery.

 All veins carry deoxygenated blood except pulmonary vein. Pulmonary artery carry deoxygenated blood towards the lungs and pulmonary vein carry oxygenated blood toward heart.

39.

What are lower level of organization in a multicellular organism ? Are these levels also present in unicellular organism

Answer»

Lower levels of organization in multicellular organisms are cells, tissues and organs. These are followed by organ system and finally organisms. These levels are absent in unicellular organisms as they have only one cell and therefore no tissue and further levels.

40.

Free ammonia is liberated during the catabolism of (A) Cytosine (B) Uracil (C) Thymine (D) All of these

Answer»

(D) All of these

41.

β -Aminoisobytyrate is formed from catabolism of (A) Cytosine (B) Uracil (C) Thymine (D) Xanthine

Answer»

Correct option (C) Thymine

42.

Okasaki fragments are small bits of (A) RNA (B) DNA (C) DNA with RNA heads (D) RNA with DNA heads

Answer»

(C) DNA with RNA heads

43.

DNA does not contain (A) Thymine (B) Adenine (C) Uracil (D) Deoxyribose

Answer»

Correct option (C) Uracil

44.

The genine of φ×174 bacteriophage is interesting in that if contains (A) No DNA (B) DNA with uracil (C) Single stranded DNA (D) Triple standard DNA

Answer»

(C) Single stranded DNA

45.

If a smart material generates voltage due to temperature difference, it is a. Pyroelectric b. photovoltaic c. piezoelectric d. liquid crystal

Answer»

a. Pyroelectric

46.

If a smart material generates electricity due to deformation, it is a. Photochromic b. photovoltaic c. piezoelectric d. liquid crystal 

Answer»

c. piezoelectric 

47.

Intermetallic compounds a. Easily deform b. easily cross-slip c. easily slip across grain boundaries d.have high Peierls stress

Answer»

d.have high Peierls stress

48.

Hydrostatic pressure in renal glomerular capillaries A. Is lower than pressure in efferent arterioles.B. Rises when afferent arterioles constrict. C. Is higher than in most capillaries at heart level. D. Falls by 10 per cent when arterial pressure falls by 10 per cent. E. Falls along the length of the capillary.

Answer»

A. False It must be higher to maintain blood flow.

B. False The pressure drop across the afferent arterioles increases as they constrict. 

C. True The afferent arterioles offer relatively little resistance. 

D. False Redistribution of renal vascular resistance due to autoregulation tends to maintain glomerular hydrostatic pressure and hence filtration. 

E. True Hydrostatic pressure falls due to vascular resistance; oncotic pressure rises due to loss of protein-poor filtrate; both these factors reduce filtration pressure along the length of the glomerular capillary.

49.

Secretion of renin A. Occurs in the stomach during infancy. B. Is stimulated by the hormone angiotensin I. C. Leads to raised levels of angiotensin II in the blood. D. Is stimulated by a fall in extracellular fluid volume. E. Inhibits ACTH secretion by the pituitary gland.

Answer»

A. False Rennin is the enzyme secreted by infant’s gastric mucosa which curdles milk. 

B. False Renin promotes angiotensin I formation from a circulating precursor. 

C. True Angiotensin I is converted to angiotensin II by a converting enzyme in the lungs. 

D. True Renin’s action helps to restore this volume. 

E. False There is no direct feedback between the two systems.

50.

7 years ago a father was 7 times as old as his son, 3 years hence he will be only 3 times to the age of his son. Their present ages are:1. 45, 122. 42, 123. 36, 74. 48, 15

Answer» Correct Answer - Option 2 : 42, 12

Given:

7 years ago father was 7 times as old as his son

3 years from now father will be 3 times to the age of his son

Calculation:

Let the present age of the son be x

Age of the father 7 years ago = 7 × (x - 7)

Age of the father 3 years from now = 3 × (x + 3)

Also, Age of the father 3 years from now = 7 × (x - 7) + 10

7 × (x - 7) + 10 = 3 × (x - 3)

⇒ 7x - 49 + 10 = 3x - 9

⇒ 4x = 48 

⇒ x = 12

Present age of the father = 3 × (x + 3) - 3

⇒ 3 × 15 - 3

⇒ 42 

∴ Present age of father and son is 42 and 12 years respectively.