This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The direction ratios of a straight line are (1,3,5). Its direction cosines are : |
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Answer» Answer is (a) 1/√35,3/√35,5/√35 |
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| 2. |
If vector(2i + j + k), vector(6 i - j + 2 k) and vector(14 i - 5 j + 4 k) be the position vector of the points A, B and C respectively, then(A) A, B and C are collinear(B) A, B and C are not collinear(C) (D) None of these |
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Answer» (A) A, B and C are collinear |
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| 3. |
Find the area under the Normal curve to the right of z = 1.3. |
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Answer» Area under normal curve to the right of z = 1.3 = Area from 0 to ∞ – Area from 0 to 1.3 = 0.5 – 0.4032 = 0.0968 |
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| 4. |
The direction ratios of two straight lines are l,m,n and I1,m1,n1. The lines will be perpendicular to each other if : |
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Answer» Answer is (c) ll1 + mn1 + nn1 = 0 |
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| 5. |
What is meant by defect and defectives in S.Q.C? |
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Answer» A ‘defect’ is a quality characteristic which does not conform to specifications. The presence of one or more defects in a product is ‘defective. |
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| 6. |
Mention any two features of t-distribution. |
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Answer» (a) Range is ( -∞ , ∞ ) (b) Mean = 0 (mean = median = mode = 0). |
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| 7. |
Why is Fisher’s index number called as an ‘Indeal Index Number’? |
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Answer» Fisher’s Index Number is called as ideal because, it is free from bias in use of weights ie. it takes both current and base year quantities as weights. • It is based on geometric mean which is considered as best average • It satisfies both time reversal tests and factor reversal tests |
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| 8. |
A line passing through (2,-1,3) and its direction ratios are (3,-1,2). The equation of the line is : |
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Answer» Answer is (b) (x - 2)/3 = (y + 1)/-1 = (z - 3)/2 |
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| 9. |
Mention two uses of life table. |
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Answer» They are used in computation of actuarial of premium, bonus etc, of policies by Insurance Agencies. OR • Life Tables are used in research activities in Biology, Medicine, Pharmacology, Demography, Psychology, Sociology etc. • They are used to study population growth and forecast the size and sex distribution of the Population. OR • Life Tables give Mortality and Survival ratios at different ages. • Life tables give the life expectancy at different age. OR • These are useful in public administration, heath care, planning and population control |
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| 10. |
Mention two application of tests. |
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Answer» (a) To test whether a population has given variance. (b) To test ‘goodness of fit’ of theoretical frequencies to a observed frequencies. |
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| 11. |
The lines (x - 1)/l = (y + 2)/m = (z - 4)/n and (x + 3)/2 = (y - 4)/3 = z/6 are parallel to each other if :(a) 2l = 3m = n(b) 3l = 2m = n(c) 2l + 3m + 6n = 0(d) lmn = 36 |
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Answer» Answer is (b) 3l = 2m = n |
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| 12. |
Mention two situations when replacement is carried out. |
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Answer» Replacement’s carried out when (a) Machine and their spare parts deteriorates with time. (b) The maintenance cost increases and efficiency reduces. |
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| 13. |
What is ‘Time series’? |
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Answer» Chronological arrangement of statistical data according to time is called ‘Time series’. |
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| 14. |
What is meant by inventory? |
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Answer» An Inventory is a physical stock of goods, which is held for the purpose of future production or sales. |
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| 15. |
Which weights are used in the construction of Paasche’s price index number? |
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Answer» Current year quantity (q1). |
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| 16. |
The length of the perpendicular from the point (0, -1, 3) to the plane 2x + y - 2z + 1 = 0 is : (a) 0(b) 2√3(c) 2/3(d) 2 |
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Answer» Answer is (d) 2 |
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| 17. |
Mention a need of replacement of an item. |
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Answer» • As the equipment grow older, its maintenance cost would be costlier. • Production cost would be lesser in new equipments. |
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| 18. |
If P(A) = 3/8, P(B) = 1/2, P(A ∩ B) = 1/4, then P(A/B).(a) 1/4(b) 1/2(c) 2/3(d) 3/8 |
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Answer» Answer is (b) 1/2 |
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| 19. |
If A and B are two independent events, then- |
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Answer» Answer is (b) P(AB') = P(A) P(B') |
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| 20. |
The matrix [(3,5),(2,k)] has no inverse if the value of k is :(a) 0(b) 5(c) 10/3(d) 4/9 |
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Answer» Answer is (c) 10/3 |
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| 21. |
From the following T.P. test whether the solution is nondegenerate: |
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Answer» Here no. positive allocations = 4; m + n – 1 = No. of rows + No. of columns -1 = 3 + 3 -1 = 5 Here no. of allocations < (m + n – 1) the solution is degenerate / not a non-degenerate. |
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| 22. |
What is defect? |
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Answer» • A defect is a quality characteristic, which does not conform to specifications. • The presence of one or more defects in a product/article is a defective. |
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| 23. |
|(2,3,5),(0,4,7),(0,0,5)| = (a) 40(b) 0(c) 3(d) 25 |
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Answer» Answer is (a) 40 |
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| 24. |
tan-1 (2x/(1 + x2)) = (a) 2sin-1 x(b) sin-1 2x(c) tan-1 2x(d) 2tan-1 x |
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Answer» Answer is (d) 2tan-1 x |
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| 25. |
The origin and the roots if the equation z2+pz+q from an equitorial triangle if(a) p2=q(b) p2=3q(c) q2=3p(d) p2=q |
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Answer» z2+pz+q=0 z1+z2 = p, z1z2=q If z1,z2,z3 are the vertices of an equilateral triangle then z12+z22+z32 = z1z2+z2z3+z3z1 If z3 is origin then z12+z22=z1z2 => (z1+z2)2=3z1z2 => p2 = 3q |
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| 26. |
Find the condition that x3 – px2 + qx – r = 0 may have the roots in G.P. |
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Answer» Let , a/R, a, aR be the roots of x3 – px2 + qx – r = 0 Then product of the roots = a/R .a. aR = a3 = r ⇒ a = r1/3 ∵ a is a root of x3 – px2 + qx – r = 0 ⇒ a3 – pa2 + qa – r = 0 But a = r1/3 ⇒ (r1/3)3 – p(r1/3)2 + q(r1/3) – r = 0 ⇒ r – p. r2/3 + q. r1/3 – r = 0 ⇒ p. r2/3 = q r1/3 By cubing on both sides ⇒ p3r2 = q3r ⇒ p3r = q3 is the required condition. |
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| 27. |
If Z = (1+ 2i)/(1 - (1 - i)2), then find Arg (Z). |
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Answer» Given Z = (1 + 2i)/(1 - (1 - i)2) = (1 + 2i)/(1 - (1 - 2i + i2)) = (1 + 2i)/(1 + 2i) = 1 = cos0° + isin0° ∴ Arg(Z) = 0° |
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| 28. |
Find the value of (– 16)1/4 |
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Answer» (–16) = 16(–1) = 16(cosπ + isinπ) = 24(cos(2k + 1)π + isin(2k + 1)π], k ∈ z (–16)1/4 = (24)1/4[cos(2k + 1)π + i sin (2k + 1)π]1/4 = 2cos(2k + 1)π/4, k = 0, 1, 2, 3 The value of (–16)1/4 is 2cos(2k + 1)π/4, k = 0, 1, 2, 3 |
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| 29. |
Z = x + iy represents a point in the Argand plane. Find the locus of Z such that |Z| = 2. |
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Answer» Let Z = x + iy. Then |Z| = 2. If and only if |x + iy| = 2. If and only if √(x2 + y2) = 2. If and only if x2 + y2 = 4 x2 + y2 = 4 represents a circle with centre at (0, 0) and radius 2! ∴ The locus of |z| = 2 is the circle x2 + y2 = 4. |
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| 30. |
Evaluate: ∫logc xdx(A) xlogx + x + c (B) x logx – x + c (C) logx + x + c (D) logx – x + c |
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Answer» (B) x logx – x + c |
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| 31. |
Domain of function f (x) = √sin-1 x(A) [0,1] (B) [–1,1] (C) [–1,0] (D) {0,1} |
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Answer» Correct option : (A) [0,1] |
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| 32. |
If A and B are any two events such that P(A) = 0.2, P(B) = 0.6, then P(A ∪ B) + P(A ⋂ B)(A) 0.9 (B) 0.7 (C) 0.8 (D) None of these |
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Answer» correct option : (C) 0.8 |
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| 33. |
Let A and B be two events such that P(A) = 1/3, P(B) = 1/4 and P(A ⋂ B) = 1/5 then P(A/B)(A) 1/5(B) 2/5(C) 3/5(D) 4/5 |
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Answer» Correct option: (D) 4/5 |
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| 34. |
The differential equation of family of lines passing through the origin is |
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Answer» (A) x dy/dx = y |
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| 35. |
The solution of x dy/dx - y = x2 is (A) y = x + k (B) y2 = x + k (C) y = x2 + kx (D) y2 = x2 – kx |
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Answer» (C) y = x2 + kx |
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| 36. |
There are 20 girls and 15 boys in a class, what is the ratio of numbers of girls to the number of boys.What is the ratio of number of girls to the total number of students in the class. |
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Answer» Ratio of girls an boys= 20:15=4:3 Ratio of number of girls to the total number of students = 20:(20+15)=20:35=4:7 |
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| 37. |
The order of differential equation (d2y/dx2)3 + 2(dy/dx)4 + 9y = sin x is(A) 3(B) 4 (C) 2(D) None of these |
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Answer» Correct option: (C) 2 |
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| 38. |
The order of the differential equation 2x2 d2y/dx2 + y = 0 is (A) 2 (B) 1 (C) zero (D) None of these |
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Answer» correct option: (A) 2 |
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| 39. |
What is best reagent would you choose to convert `MnO_(4)^(2-)` to `MnO_(4)^(-)`.A. `Cl_(2)` waterB. `O_(3)`C. A and B bothD. None of these |
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Answer» Correct Answer - C `2K_(2)MnO_(4)+Cl_(2)overset(Delta)rarr2KCl+2KMnO_(4)` `2K_(2)MnO_(4)+O_(3)+H_(2)Orarr2KMnO_(4)+2KOH+O_(2)uarr` |
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| 40. |
The solution of dy/dx = 1 + x + y + xy is (a) x - y = k(1 + xy)(b) log(1 + y) = x + (x2/2) + k(c) log(1 + x) = y + (y2/2) + k (d) none of these |
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Answer» Answer is (b) log(1 + y) = x + (x2/2) + k |
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| 41. |
Let A and B be two events such that P(A) = 1/3, P(B) = 1/4, P(A ∩ B) = 1/5, then P(A/B) = (a) 1/5(b) 2/5(c) 3/5(d) 4/5 |
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Answer» Answer is (d) 4/5 |
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| 42. |
Number of integral values of \( x \) satisfying the inequation \( \frac{x}{x+2} \leq \frac{1}{|x|} \) is (a) 2 (b) 8 (c) 4 |
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Answer» \(\frac{x}{x+2}\leq\frac1{|x|}\) ⇒ \(\frac{x|x|}{x+2}\leq1\) (Multiplying both sides by positive value |x|) I6 x = -3, then \(\frac{x|x|}{x+2}=\frac{-3\times3}{-3+2}=\frac{-9}{-1}=9>1\) (Not satisfies) (\(\therefore\) I6 x < -2, then x|x| < 0 & x + 2 < 0 ⇒ \(\frac{x|x|}{x+2}>1\)) x = -2 is not possible x = -1 then \(\frac{x|x|}{x+2} = \frac{-1\times1}{-1+2}=\frac{-1}1=-1<1\) (Satisfies) x = 0 then \(\frac{x|x|}{x+2} = 0<1\) (Satisfies) x = 1 then \(\frac{x|x|}{x+2} = \frac13<1\) (Satisfies) x = 2 then \(\frac{x|x|}{x+2} = \frac{2\times2}{2+2}=\frac44=1\) (Satisfies) I6 x > 2 then x|x| = x2 > x + 2 ⇒ \(\frac{x|x|}{x+2} >1\) (Not satisfies) \(\therefore\) Number of integral values which satisfies given inequality are 4. |
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| 43. |
`H_(2)S` gas is not evolved when `SO_(3)^(2-)` ion reacts with following reagents.A. An+dil.`H_(2)SO_(4)`B. Al + conc. NaOHC. Al + dil. HClD. None of these |
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Answer» Correct Answer - B `SO_(3)^(2-)+2Al+2OH^(-)+3H_(2)OrarrS^(2-)+2[Al(OH)_(4)]^(-)` `H_(2)S` does not evolve as liberated `H_(2)S` is neutralised by NaOH and `Na_(2)S` is formed. |
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| 44. |
Prove that \[ \frac{\cot x-\tan x}{\cot x+\tan x}=\sin x \]. |
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Answer» LHS = {cosx / sinx - sinx / cosx} / {cosx / sinx + sinx / cosx} LHS = {cos2x - sin2x / sinxcosx} / {cos2x + sin2x / sinxcosx} LHS = cos2x - sin2x = cos2x... (cos2x + sin2x = 1) LHS = cos2x = sinx = RHS. Hence, proved. \(\frac{cotx-tanx}{cotx+tanx}=\cfrac{\frac{cosx}{sin x}-\frac{sin x}{cos x}}{\frac{cosx}{sinx}+\frac{sinx}{cosx}}\) \(=\cfrac{\frac{cos^2x-sin^2x}{sinxcosx}}{\frac{cos^2x+sin^2x}{sinxcosx}}\) = \(\frac{cos^2x-sin^2x}{sin^2x+cos^2x}\) \(= cos^2x-sin^2x\) (\(\because\) sin2x + cos2x = 1) = cos 2x (\(\because\) cos 2x = cos2x - sin2x) \(\therefore\) \(\frac{cotx-tanx}{cotx+tanx}=cos2x\neq sinx\) |
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| 45. |
When redox reaction occurs within the reactant , in which one component acts as oxidising agent and other component acts as reducing agent, then it is named as intra-molecular redox reaction, which usually occur in thermal decomposition of ionic compounds. Which of the following compounds does not give nitrogen gas on heating ?A. `NH_(4)NO_(2)`B. `(NH_(4))_(2)SO_(4)`C. `NH_(4)ClO_(4)`D. `(NH_(4))_(2)Cr_(2)O_(7)` |
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Answer» Correct Answer - B (A)`NH_(4)NO_(2)overset(Delta)rarrN_(2)+2H_(2)O` (B)`(NH_(4))_(2)SO_(4)overset(Delta)rarrNH_(3)+H_(2)SO_(4)` (C)`2NH_(4)ClO_(4)overset(Delta)rarrN_(2)+Cl_(2)+2O_(2)+4H_(2)O` (D) `(NH_(4))_(2)Cr_(2)O_(7)overset(Delta)rarrN_(2)+Cr_(2)O_(3)+4H_(2)O` |
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| 46. |
When redox reaction occurs within the reactant , in which one component acts as oxidising agent and other component acts as reducing agent, then it is named as intra-molecular redox reaction, which usually occur in thermal decomposition of ionic compounds. Which of hte following salt does not give `NO_(2)` gas on heating ?A. `Pb(NO_(3))_(2)`B. `Hg(NO_(3))_(2)`C. `KNO_(2)`D. `AgNO_(3)` |
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Answer» Correct Answer - C (A) `2Pb(NO_(3))_(2)overset(Delta)rarr2PbO+4NO_(2)+O_(2)` (B) `Hg(NO_(3))_(2)overset(Delta)rarrHg+2NO_(2)+O_(2)` (C)`KNO_(2)overset(Delta)rarrKNO_(2)+(1)/(2)O_(2)` (D) `2AgNO_(3)overset(Delta)rarr2Ag+2NO_(2)+O_(2)` |
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| 47. |
What is the approximate mass of one atom of tungsten? |
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Answer» The mass of a single tungsten atom is 3.05 × 10-22 grams. |
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| 48. |
Discuss the properties of Dot product and Cross product. |
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Answer» Dot Product Properties:
Properties of the Cross Product:
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| 49. |
Derive the equation for time period of a simple pendulum using the method of dimensions and hence obtain the equation. |
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Answer» We know that T \(\propto\) ma la gc T = K ma la gc----(1) Putting the dimension each parameter both side [T] = [M]a [L]b[LT-2]c [T] = [M]a[Lb+c][T-2c] comparing both sides power a = 0 b + c = 0 -2c = 1 c = -1/2 these value put in equation (1) we get T = K m0 l1/2 g-1/2 T = K\(\sqrt{\frac lg}\) \(\because k = 2\pi\) T = 2\(\pi\sqrt{\frac lg}\) |
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| 50. |
In the given figure (circle), `P T=5,P D=7a n dP A=2,`then the value of `P B-P C=?`Fig |
| Answer» Correct Answer - `125/14` | |