This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Explain chemical weathering with examples. |
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Answer» Disintegration and Decomposition of rocks by chemical processes is called “Chemical weathering”. In this process secondary or new minerals are developed from the original minerals of the rocks. The rain water and atmospheric gases are the main agents of chemical weathering. It is vey common in humid regions. There are four types of chemical weathering process. They are;
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| 2. |
What is a rock? Describe the different types of rocks. |
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Answer» Rock refers to the hard and resistant materials of the earth’s crust. But scientifically rock includes even soft and loose materials like chalk, clay, etc. So, rock refers to any solid materials, hard or soft of which the crust of the earth is formed. All rocks do not have the same chemical composition. But minerals have their own chemical compost in and physical prosperities. .The earth’s crust is made up of various types of rocks Types of Rocks: Rocks can be classified into three major groups on the basis of their origin or mode of formation. They are: A. Igneous rocks: The term Igneous is derived from the Latin word “Ignis”, means lire. Thus the igneous rocks are formed by the cooling and solidification of molten material which is called magma. Igneous rocks are also called primary rocks, because they were the firs to be formed. As they are the rocks from which all other types of rocks are derived, they are also called parent rocks. Igneous rocks are commonly classified on the basis of mode of formation into two major types. i. Intrusive rocks ii. Extrusive rocks. I. Intrusive rocks: The magma cannpt escape out to the earth’s surface, it cols slowly inside the earth’s crust and hardens into rock. This type of rock is known as Intrusive Igneous rock. E.g. Granite and dolerite. These rocks can be divided into two type’s a. Plutonic rocks and b. Hybabyssal rocks. a. Plutonic rocks: The rocks which are formed due to cooling of magma at great depth inside the earth are called Plutonic igneous rocks. b. Hybabyssal rocks: These are intermediate rocks between the extruded volcanic rocks and the deep plutonic rocks. They are formed due to cooling and solidification of magma in cracks, pores, crevices etc. II. Extrusive rocks: Rocks formed by cooling and solidification of lava on the surface of the Earth is called extrusive igneous rocks. E.g. Basalt. B. Sedimentary Rocks: These rocks which are formed due to aggregation and compactness of sediments are known as sedimentary. In other words, sedimentary rocks are formed bye day the deposition of sediments derived form older rocks, planets and animals remains by river, winds, glaciers etc and these sediments are hardened into rocks by pressure. As they are formed by the consolidation of sediments. They are called sedimentary rocks. They are also called stratified rocks, a. Mechanically-formed rocks: The rock which have been formed form the accumulation of rock materials, derived form other rocks and have been cemented together are known as “ Mechanically formed rocks.” The mechanically formed rocks consist of sediments which have been carried and deposited by rivers, glaciers, winds or waves and cemented together with clay or line. On the basis of rock materials. These rocks can be divided into three main categories. They are: Rudaceous rocks, Arernaceous rocks and Argilious rocks. b. Chemically formed rocks: The chemical often settle down and hardened to form rocks known as chemically formed rocks. For example: Gypsum and rock salt, running water dissolves and carries chemicals and where evaporation takes place, these chemicals are deposited at the mouth of springs, caves or caverns or in lakes. Rock salt and gypsum are formed form deposit of salt in strata on the beds of lakes. c. Organically formed rocks: Organic rocks are formed form the remains of organisms, i.e. of animals and plants. Examples: coal, limestone etc. On the basis of lime and carbon content, organically formed rocks can be divided into two kinds, namely. (i) Calcareous rocks: Calcareous rocks are formed mostly from the remains of living organisms. These rocks contain calcium carbonate or lime. They include limestoneand chalk. They are porous and soluble. (ii) Carbonaceous rocks: These are formed due to the transformation of vegetative matter. Under the impact of heat and pressure the remains of plants are turned into hard layers. E.g. coal. C. Metamorphic rocks: Rock which has been changes either in form or in composition without disintegration is called metamorphic rocks. These rocks are metamorphosed from igneous sedimentary rocks. Igneous and sedimentary rocks may undergo chemical and physical changes because of pressure and heat and form metamorphic rocks. The intense heat and pressure in the earth’s curst alters the composition and appearance of rocks completely or partially to produce a new type of rocks. In this manner metamorphic. rocks are formed. Marble, Diamond, Quartzite, Ruby, Emerald are the examples of metamorphic rock. |
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| 3. |
What is an Earthquake? Describe the causes and effects of earthquake. |
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Answer» An Earthquake is a sudden vibration or oscillation in the Crust of the Earth. It is a form of energy of wave motion transmitted through the surface layer of the Earth. The place of origin of an Earthquake in the Earth’s crust is called ‘Focus’. The point on the Earth surface which is perpendicular to the focus, receiving seismic waves is called ‘Epicentre’. Causes of Earthquake: On the basis of occurrence earthquakes can be classified into three types. They occur due to several causes such as tectonic forces, folding, faulting, volcanic eruptions landslides, avalanches, man-made factor. Tectonic Earthquakes: These are caused due to folding, faulting and displacement of blocks of rocks in the Earth’s crust. They are highly intensive and destructive seismic activities. Volcanic Earthquakes: These are associated with the volcanic activities and are usually caused at great depths. They are with low intensity and magnitude. The destruction and damage are slightly lesser than earthquakes caused by Tectonic forces. c. Earthquakes caused by man-made factors: Over interaction of man underground nuclear explosion etc, are causing great change in the crustal formation leading to seismic activity. E.g. Koyna dam (India)-1967, Hoover dam (U.S.A)-1935, Mangladam (Pakistan). Effects of Earthquakes: Earthquakes cause violent disturbances and widespread damage and destruction, especially on the epicentre region.
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| 4. |
What is an Earthquake? Describe the causes and effects of earthquake. |
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Answer» An Earthquake is a sudden vibration or oscillation in the Crust of the Earth. It is a form of energy of wave motion transmitted through the surface layer of the Earth. The place of origin of an Earthquake in the Earth’s crust is called ‘Focus’. The point on the Earth surface which is perpendicular to the focus, receiving seismic waves is called ‘Epicentre’. Causes of Earthquake: On the basis of occurrence earthquakes can be classified into three types. They occur due to several causes such as tectonic forces, folding, faulting, volcanic eruptions landslides, avalanches, man-made factor. Tectonic Earthquakes: These are caused due to folding, faulting and displacement of blocks of rocks in the Earth’s crust. They are highly intensive and destructive seismic activities. Volcanic Earthquakes: These are associated with the volcanic activities and are usually caused at great depths. They are with low intensity and magnitude. The destruction and damage are slightly lesser than earthquakes caused by Tectonic forces. c. Earthquakes caused by man-made factors: Over interaction of man underground nuclear explosion etc, are causing great change in the crustal formation leading to seismic activity. E.g. Koyna dam (India)-1967, Hoover dam (U.S.A)-l 935, Mangladam (Pakistan). Effects of Earthquakes: Earthquakes cause violent disturbances and widespread damage and destruction, especially on the epicentre region.
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| 5. |
Mention the important regions of land slides in India. |
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Answer» There are three important region. 1. Himalayan zone 2. Western Ghats 3. Southern Plateau. |
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| 6. |
Describe the size of the Earth. |
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Answer» The ancient people made attempts to determine the size of the Earth. About 2,000 years ago a Greek astronomer, Eratosthenes, who lived In Alexandria in Egypt succeeded in calculating the size of the earth almost accurately, according to him, the earth’s circumference at the equator was 41,140 kms. It was very close to the actual circumference of the earth, as known today. The actual equatorial circumference of the earth is 40,076 km, where as the polar circumference is 40,006 km. The difference between the two is 70 km. The earth’s equatorial diameter is 12,757 km and the polar diameter is 12,714 km. The difference is 43 km. The geoids shape of the earth makes the circumference through the poles little less than that along the equator. The total surface area of the earth is 510. 9 million sq kms of the surface area, 71 % is covered by water mass and 29% is covered by landmass. The water mass is 361 million sq.kms and the land area is 149 million sq.kms. The land area is divided into seven continents and many island. The continents are Asia, Africa, and North America, South America, Antarctica, Europe and Australia. The water area consist of five ocean, namely, the pacific Ocean, the Atlantic Ocean, the Indian Ocean, the Antarctic ocean and the Arctic Ocean and many gulfs, bays and seas. The globe is divided into two hemispheres, namely the northern hemisphere and the southern hemisphere, by the equator. The northern hemisphere contains 2/3 of the land and the southern hemisphere contains 1/3 of the land. The zero degree meridians decide the globe into two hemispheres, namely, the eastern hemisphere and the western hemisphere. |
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| 7. |
Which of the following information is incorrect regarding Tyndall effect.(1) The diameter of dispersed particles is much smaller than the wavelength of light used(2) In lyophobic colloids difference in refractive indice of DP & DM is appreciable therefore the Tyndall effect is quite well defined.(3) Light thrown from a projector in cinema hall is example of Tyndall effect.(4) It is used to differentiate colloidal solutions with true solution. |
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Answer» Correct option is (1) The diameter of dispersed particles is much smaller than the wavelength of light used |
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| 8. |
Why is Geography called as the ‘Science of Earth’? |
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Answer» The word Geography is derived from the two Greek word ‘Geo’ which means earth and Graphic which means writing or study. Thus literally Geography means writing or study about the earth. Geography not only deals with a description of the earth, but it also deals with its inhabitants. So, Geography is the study of the earth and its people. |
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| 9. |
Name any two branches of Human Geography. |
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Answer» Cultural Geography, Historical Geography, Economic Geography, Agricultural Geography. |
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| 10. |
Why Geography called as the ‘Science of Earth’? |
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Answer» Geography is fundamentally a description of the earth. It deals with the varied natural or physical factors of environment, such as land forms, mountains water bodies, minerals, climate, soils, natural vegetation and plains. |
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| 11. |
Which is called ‘Mawsynram’ of South India’? |
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Answer» Agumbe of Karnataka is ‘Mawsynram’ of South India’ |
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| 12. |
What is drought? |
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Answer» The term drought is applied to an extended period when there is a shortage of water availability due to inadequate precipitation, excessive rate of evaporation and over utilization of water from the reservoirs other storages, including the ground water. |
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| 13. |
Name the longest river in South India |
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Answer» Godavari is the longest (1465km) and largest river of south India |
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| 14. |
Mention the major stream of river Ganga. |
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Answer» The two major streams are Alakananda and Bhagirathi. |
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| 15. |
In which Island of India is ‘Indira Point’ situated? |
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Answer» Indira point located at Great Nicobar Island. |
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| 16. |
In which Island of India, is ‘Indira Point’ situated? |
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Answer» Indira point located at Great Nicobar Island. |
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| 17. |
Which of the following option is correct regarding the structure of borax?A. No. of hydrated water malecule are equal to 10B. S (B-O-B) linkages are presentC. B have `sp^(3)" as well as "sp^(2)` hybridisationD. On thermal decomposition it gives transparent bead of `NaBO_(2)&B_(2)O_(3)` |
| Answer» Correct Answer - a | |
| 18. |
Define the term Biodiversity. |
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Answer» The varied range of flora and fauna found within a specified geographic region is called ‘Biodiversity’ . |
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| 19. |
For the equilibrium: `LiCl.3NH_(3(s))hArrLiCl.NH_(3(s))+2NH_(3)`, `K_(p)=9 atm^(2)` at `40^(@)C`. A `5 litre` vessel contains `0.1` mole of `LiCl.NH_(3)`. How many mole of `NH_(3)` should be added to the flask at this temperture to derive the backward reaction for completion?A. 5B. 9C. 3D. 1 |
| Answer» Correct Answer - a | |
| 20. |
What is Volcano? |
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Answer» A volcano is an opening in the crust of the Earth through which heated materials consisting of gases, hot water, lava and fragments of rocks are ejected from the interior of the Earth. |
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| 21. |
What is Salinity? |
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Answer» It refers to the amount of dissolved solids in the ocean water. In other words. It means the amount of salt in the ocean water. ” |
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| 22. |
A current of 0.1A was passed for 4hr through a solution of cuprocyanide and 0.3745 g of copper was deposited on the cathode. Calculate the current efficiency for the copper deposition. (Cu GAM 63.5 or Cu-63.5)A. `79%`B. `39.5%`C. `63.25%`D. `63.5%` |
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Answer» Correct Answer - A `m("theoretical")=(63.5xx0.1xx7200)/96500=0.4738` g `therefore % "efficiency" =0.3745/0.4738xx100=79%` |
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| 23. |
In a closed jar having water vapours in equilibrium with liquid suddenly all the vapours of the jar is transferred to another identical jar and is subjected to compression.Assume initial temperature to be the same and negligible volume occupied by the liquid water.Select the observation in the record jar.A. Liquid water will start forming in the jarB. Vapour will undergo gradual compression without any condensationC. Temperature of the vapour will increaseD. Final pressure will be the same as initial pressure |
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Answer» Correct Answer - A,D liquid water will start forming in the jar by compression since temperature remain same so pressure also remain same `(P prop T)` |
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| 24. |
Consider two equilibrium `2Cl_2(g)+2H_2O(g)hArr4HCl(g)+O_2(g) and N_2(g)+O_2(g)hArr2NO(g)` simultaneously established in a closed vessel.When some amount of HCl is added at equilibrium, which of the following statements is/are correct :A. Amount of `N_2` gas will increaseB. Amount of `O_2` gas will increaseC. Amount of `O_2` gas will decreaseD. Nothing can be said with certainty about amount of `O_2`gas. |
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Answer» Correct Answer - A,C When some amount of HCl is added to equilibrium, the first eq. will shift in backward direction leading to decrease in amount of `O_2`.Then , the second eq. will shift in backward direction to increase the amount of `O_2`.Thus, amount of `N_2` gas will increase. |
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| 25. |
138 gm of `N_2O_4(g)` is placed in 8.2L container at 300 K.The equilibrium vapour density of mixture was found to be 30.67.Then (R=0.082 L atm `"mol"^(-1) K^(-1)`)A. `alpha`=degree of dissociation of `N_2O_4=0.25`B. `K_p` of `N_2O_4 hArr 2NO_2` (g) will be 9 atmC. Total pressure at equilibrium =6.75 atmD. The density of equilibrium mixture will be 16.83 gm/litre. |
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Answer» Correct Answer - B,C,D `{:(,N_2O_4" "hArr,2NO_2),(t=0,a,0),(t,a(1-alpha),2aalpha):}` vapour density`=46/(1+alpha)=30.67` so `1+alpha=1.5=0.5=50%` Total pressure`=(1.5xx1.5xx0.082xx300)/8.2=6.75` atm So, `K_p=(4alpha^2)/(1-alpha^2)P=9` atm and for density of mixture `=138/8.2` gm/L=16.83 gm/L |
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| 26. |
Calculate the number of moles of gas present in the container of volume 10L at 300K. If the manometer containing glyceric shown 3.8m difference in level as shown diagram. [volume of gas in limb is negligible] [Take R=0.08 atm-lit `K^(-1)"mol"^(-1)`, Density of glyceric`=2.72 gm//ml, `d_("mercury")=13.6gm//ml`] A. 0.81 moleB. 0.49moleC. 0.64moleD. 0.55mole |
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Answer» `P_("gas")=P_("atm")+[3.8mtxx(d_("glycerine"))/(d_(Hg))]` `=76+76cm=152 cm "of" Hg "or" 2` atm `n=(PV)/(RT)=(2xx10)/(0.08xx300)=(20)/(24)=0.81` mol |
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| 27. |
1 mole each of `N_2(g)` and `O_2(g)` are introduced in a 1L evacuated vessel at 523 K and equilibrium `N_2(g)+O_(2)ghArr2NO(g)` is established.The concentration of `NO(g)` at equilibrium :A. Changes on changing volume of vesselB. Changes on changing temperatureC. Changes on changing pressureD. Remains same even when a platinum gauze is introduced to catalyse the reaction |
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Answer» Correct Answer - A,B,C,D `N_2(g)+O_2(g)hArr 2NO(g)` (A)For changing pressure volume has to be changed, though number of moles of NO(g) do not get changed but its concentration will get changed. (B)Temperature change will change `K_P` and hence concentration. ( C)Volume change will change concentration, not the number of moles. (D)Catalyst does not change equilibrium concentrations. |
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| 28. |
Mole fraction of x M aqueous urea solution is : [Given : density of solution is `d gm//ml` ]A. `(18x)/(1000d - 42 x)`B. `(18 x)/(1000d - 60x)`C. `(18x)/(1000d - 18x)`D. None of these |
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Answer» Correct Answer - A x moles of Urea in 1000 ml of solution mass of solution = 1000 d gm mass of solute `60 x gm` mass of solvent `= (1000d - 60x) gm` Mole fracction of urea `= (x)/(x + ((1000d - 60x)/(18)))` `= (18x)/(18x + 1000d - 60x)` `x_("urea") = (18x)/(1000d - 42x)` |
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| 29. |
Consider the following balanced chemical equation: `2A+4B_(2)+6C_(3)rarrP+2Q` If initially 6.023xx `10^(24)` atoms orf A, 448L of `B_(2)` gas at NTP and 960 gm of `C_(3)` gas are taken, which of the following is incorrect? [Given : Atomic mass of C=8]A. total number of species in final mixture is 4B. total number of species in final mixture is 3C. A and `B_(2)` both are present in limited amount amount.D. `C_(3)` is in excess. |
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Answer» `n_(A)=10` `n_(B)=20` `n_(C)=(960)/(24)=40` `2A+4B_(2)+6C_(3)rarrP+2Q` Limiting reagent `rarrA & B_(2)` so only 3 species will be left in final mixture. |
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| 30. |
In a flask, colourless `N_(2)O_(4)` is in equilibrium with brown-coloured `NO_(2)`. At equilibrium, when the flask is heated to `100^(@)C` the brown colour deepens and on cooling, the brown colour became less coloured. The change in enthalpy `DeltaH` for the ayatem isA. (a)NegativeB. (b)PositiveC. (c )ZeroD. (d)Undefined |
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Answer» Correct Answer - B On heating ` N_(2)O_(4) hArr 2NO_(2)` if `NO_(2)` is formed more, it more it means `DeltaH=+ve` because endothermic reaction are favoured with increase in temperature. |
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| 31. |
To what volume should an HCl soln (w/w% 75%) should be diluted such that its concentration becomes 0.1 M, if initial volume of soln is 500ml. |
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Answer» Let say density of solution is g/ml. ∵ 100 g of solution contain = 75g HCl ∴ 500g of solution contain = \(\frac{75 \times 500}{100} = 75 \times 5g\; HCl\) ∴ Number of moles of HCl = \(\frac{75\times 5}{36.5} = 10.27\, mol\) ∴ Initial concentration of HCl solution = \(\frac{10.27}{500}\times 1000= 20.55 M\) Let say, After dilution the volume of solution become V then, \(V \times 0.1 = 20.55 \times 500\) \(V = \frac{20.55\times 500}{0.1}\) \(= 102750 \,ml\) \(V = 102.75 \,l\) |
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| 32. |
In an aqueous solution of urea, mole fraction of urea is 0.4. Then w/w% of urea is:A. 0.155B. 0.31C. 0.345D. 0.69 |
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Answer» Mole fraction of urea =0.4 0.4 moles of urea +0.6 moles of `H_(2)O` `%(w//w)=(0.4xx60)/((0.4xx60)+(0.6xx18))=(24)/(24+10.8)xx100` `=(24)/(34.8)xx100=69%` |
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| 33. |
The chemical energy during metabolism is released in what form |
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Answer» Chemical energy stored within organic molecules such as sugars and fats is transferred and transformed through a series of cellular chemical reactions into energy within molecules of ATP. |
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| 34. |
Which of the following statements about photochemical smog is wrong ?A. it has high concentration of oxidizing agentsB. it has low concentration of oxidizing agents.C. it can be controlled by controlling te release of `NO_(2)`, hydrocarbons ozone etc.D. plantation of some plants like pinus helps ini controlling photochemical smog. |
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Answer» Correct Answer - B Photochemical smog has high concentration of oxidizing agents. |
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| 35. |
Write down the steps to implement bag of words algorithm. |
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Answer» The steps to implement bag of words algorithm are as follows: 1. Text Normalisation: Collect data and pre-process it 2. Create Dictionary: Make a list of all the unique words occurring in the corpus. (Vocabulary) 3. Create document vectors: For each document in the corpus, find out how many times the word from the unique list of words has occurred. 4. Create document vectors for all the documents. |
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| 36. |
Name the procedure used to transform 3D platform to a 2D platform. |
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Answer» Projection used to transform 3D platform to a 2D platform. |
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| 37. |
What is Dead reckoning? |
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Answer» The process of calculating one's position, especially at sea, by estimating the direction and distance travelled rather than by using landmarks or astronomical observations. |
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| 38. |
The continued product `2.6.10.4…..`(`n` times) in equal toA. `.^(2n)C_(n)`B. `.^(2n)P_(n)`C. `(n + 1)(n + 2)(n + 3) …….(n + n)`D. `4^(n)` |
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Answer» Correct Answer - B::C `E = 2.6.10.14….` `=2^(n)[1,3,5,7…..]` `= (2^(n)[1,2,3…..2n])/(2.4.6(2n-2)(2n)) = (2^(n).(2n)!)/(2^(n).n!) = .^(2n)P_(n)(B)` Also `(2n!)/(n!) = ((1.2.3…….n)(n+1)(n+2)….2n)/(n!) :.` (C) |
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| 39. |
`5.85 g NaCI` is dissolved in 1 litre water. The total number of ions of `Na^(+)` and `CI^(-)` in 1 mL of this solution will be :A. `6.02xx10^(19)`B. `1.2xx10^(22)`C. `1.2xx10^(20)`D. `6.02xx10^(20)` |
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Answer» Correct Answer - C `5.85 g NaCI` is dissolved in ………… Number of moles of NaCI = Mass/Molar Mass `= 5.85//58.5` `= 0.1 mol` Number of ions `(Na^(+)+Cr)` in 1 L `= 2xx0.1xx6.02xx10^(23)` `= 12.04xx10^(22)` Number of ions in 1 mL `= 12.04xx10^(22)//1000` `1.2xx10^(20)` |
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| 40. |
Which of the following statements is true ?1. Intuition has no role in generating mathematical knowledge.2. Mathematical statements can be conditional.3. Mathematics consists of all the theorems proved in mathematics books.4. A person good in arithmetical computation is also good in Mathematics and vice-versa. |
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Answer» Correct Answer - Option 2 : Mathematical statements can be conditional. Mathematics is the study of numbers, shapes, quantities, and patterns. Mathematics is the ‘queen of all sciences’ and its presence is there in all the subjects. It acts as the basis and structure of other subjects. Some points to remember:
Hence, a mathematics statement can be conditional. |
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| 41. |
In which of the folloing `m gt n(m, n in R)` ?A. `m (log_(2)5)^(2)` and `n = log_(2)20`B. `m =log_(10)2` and `n = log_(10)3sqrt(10)`C. `m = log_(10)5. log_(10)20` and `n = 1`D. `m = log_(1//2)((1)/(3))` and `n = log_(1//3)((1)/(2))` |
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Answer» Correct Answer - A::D (A) `m - n = (log_(2)5)^(2) - (log_(2)5 + 2)` `= (log_(2)5 - 2)(log_(2)5 + 1) gt 0` `:. m gt n` (B) `2^(3) lt 10` or `2 lt 10^(1//3)` or `log_(10)2 lt log_(10)10^(1//3)` `:. m lt n` (C) `m = log_(10)5.log_(10)20` `= (log_(10)10 - log_(10)2)(log_(10)10 + log_(10)2)` `=(1 - log_(10)2)(1 + log_(10)2)` `=1 - (log_(10)2)^(2)` `lt 1` `:. m lt n` (D) `m = log_(1//2) ((1)/(3)) = log_(2)3` and `n = log_(1//3)((1)/(2)) = log_(3)2` `:. (m)/(n) = (log_(2)3)/(log_(3)2) = (log_(2)3)^(2) gt 1` `:. m gt n` (as `n gt 0)` |
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| 42. |
The ratio between the monthly salary of P and Q is 20 : 21. The ratio between the expenditure of P and Q is 5 : 7. The difference between the salary of Q and P is Rs.2000 and the savings of Q is Rs.14000. Find the ratio between the savings of P and Q.1. 2 : 72. 12 : 73. 5 : 24. 7 : 125. 10 : 7 |
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Answer» Correct Answer - Option 5 : 10 : 7 Given: Let salary of P and Q be Rs.20a and Rs.21a respectively. Calculation: ⇒ 21a - 20a = 2000 ⇒ a = 2000 The monthly salary of P and Q is Rs.40000 and Rs.42000 respectively. ⇒ Expenditure of Q = 42000 - 14000 = Rs.28000 Then, ⇒ (Expenditure of P) : 28000 = 5 : 7 ⇒ Expenditure of P = 28000 × 5/7 = Rs.20000 ⇒ Savings of P = 40000 - 20000 = Rs.20000 Required ratio = 20000 : 14000 = 10 : 7 ∴ the correct answer is 10 : 7 |
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| 43. |
The missing number in the series 4, 4, 6, 12, 30, ? is:1. 972. 923. 904. 85 |
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Answer» Correct Answer - Option 3 : 90 4, 4, 6, 12, 30, ? Above series follows given below pattern: 4 × 1 = 4 4 × 1.5 = 6 6 × 2 = 12 12 × 2.5 = 30 30 × 3 = 90 ∴ The missing number in the series 4, 4, 6, 12, 30, ? is 90 |
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| 44. |
Consider the following statements :A = If n is even, then n2 is even.B = If n2 is not even, n is not even.C = If n2 is even, then n is even.D = If n is not even, then n2 is not even.Which of the following statements is true?1. B is inverse of A.2. D is contraposition of A.3. C is converse of A.4. D is converse of A. |
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Answer» Correct Answer - Option 3 : C is converse of A. Mathematical reasoning is a topic of mathematics which deals with truthfulness and falsehood of a statement. A statement is a sentence which is either true or false, but can not be both at the same time. There are certain terms that are frequently used in mathematical reasoning:
Hence, we conclude that the above relation is of contraposition. |
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| 45. |
The half lives of a radioactive sample are 30 years and 60 years from `alpha`- emission and `beta`- emission respectively If the sample decays both by alpha-emission and `beta`-emission simultaneously, the time after which, only one-fourth of the sample remain isA. 10 yearsB. 20 yearsC. 40 yearsD. 45 years |
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Answer» Correct Answer - C `lambda_(1)=1/30` `lambda_(2)=1/60` `lambda=lambda_(1)+lambda_(2)` `lambda=1/20` `N=(N_(0))/(2^(t)//t^(1//2))` `N_(0)/4 = (N_(0))/((2)^(t//t^(1//2)))` `:. t=2t_(1//2)=2xx(0.693)/lambda` `t=2xx0.693xx20yrs` `=27.72yrs` |
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| 46. |
For a given figure to be a triangle, the condition that it is a union of three segments is 1. both necessary and sufficient condition. 2. neither necessary nor sufficient condition. 3. a necessary but not a sufficient condition. 4. a sufficient but not a necessary condition. |
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Answer» Correct Answer - Option 3 : a necessary but not a sufficient condition. A triangle is a two-dimensional figure which has three sides and the sum of whose angles is 180 degrees. There are certain conditions for a figure to be triangle as stated below:
Hence, we conclude that for a given figure to be a triangle, the condition that it is a union of three segments is a necessary but not a sufficient condition. |
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| 47. |
Which of the following is a desirable strategy for assessing students' learning in mathematics?1. Students' justification of their responses should be an important basis of assessment.2. Development of mathematical vocabulary should not be a basis of assessment.3. Same tasks should be given to all students for parity.4. Students' incorrect answers should be ignored. |
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Answer» Correct Answer - Option 1 : Students' justification of their responses should be an important basis of assessment. Assessment is a process of collecting relevant information on student learning. It is one of the crucial components of the teaching-learning process. The Assessment Strategies that can be used to encourage interdisciplinary in Mathematics as stated below.
Hence, Students' justification of their responses should be an important basis of assessment. |
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| 48. |
What is the purpose of formative evaluation in Mathematics?1. Identification of minor learning difficulties of students2. Identification of major learning difficulties of students3. Identification of entry behaviour of students4. Diagnose the severe learning difficulties of students |
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Answer» Correct Answer - Option 1 : Identification of minor learning difficulties of students Formative Evaluation: Evaluation is called formative evaluation when its purpose is to modify the educational proposals and to make them more relevant to the individual student’s needs. When the evaluation of the learning activity is based on the formative approach, it must be as analytical as possible. Formative evaluation is a tool for providing feedback to the teaching/learning process. This type of instruction motivates the teacher and the student and reinforces learning by providing feedback to both of them. The process of ‘self-assessment’ serves the purpose of formative evaluation. Formative assessment is concerned with identifying learner weakness in attainment with a view to helping the learner and the teacher overcome/remedy those. Characteristics of the formative assessment:
Hence, we conclude that the purpose of formative evaluation in Mathematics is the identification of minor learning difficulties of students. |
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| 49. |
Mutations can be induced withA. IAAB. ethyleneC. gamma radiationsD. infra red radiations |
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Answer» Correct Answer - C Gamma radiatins are ionising raditions and are physical mutagens .They are used as mutagens in such material s where nucleus is deep seatd e.g seeds stem cuttings etc sharbati sonora varieyt of wheat has been developed by gamma radiations on sonaora 64 nvariety (mexican dwarf wheat variety) |
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| 50. |
Breeding of crops with high levels of minerals vitamins and proteins calledA. somatic hybridisation fusion of two diverse cellsB. biofortificationC. bimoagnificationD. micropropagation |
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Answer» Correct Answer - B Breeding of crops with higher levels of vitamins and minerla or higher oroten and helthier fats is called biofortification .This is the most practical aspect to improve the health of the people |
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