This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
यह प्रसंग पढ़ें, मिहिर और मोरपाल के जीवन अनुभवों के आधार पर टिप्पणी लिखें।जिस स्कल में बिताए समय को मैं अपने बचपन का सबसे खराब समय समझ करता था, शायद वही मोरपाल के लिए उसके जीवन का सबसे अच्छा समय होता था।’ |
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Answer» समाज के दो पहलू मिहिर एवं मोरपाल दोस्त थे। दोस्ती इतनी घनी थी कि खाने की चीज़ भी आपस में बाँट लेते थे। मोरपाल गरीब घराने का लड़का है। उसके माँ-बाप खेत-मजूरी करते थे। घर में उसे कमर तोड़ मेहनत है। फिर भी वह रोज़ स्कूल आना पसंद करता है। पंद्रह किलोमीटर दूर किसी गाँव से रोज़ साइकिल चलाता स्कूल आता था। रोज़ छाछ का डिब्बा लेकर आता था। स्कूल आकर लेखक (मिहिर) का राजमा-चावल बडी चाव से खाता था। क्योंकिक्यों उसने पहले कभी यह देखा ही नहीं।हीं स्कूल के प्रति उसका लगाव कुछ खास है इतना कि बिना नागा रोज़ स्कूल आता था। रविवार की छुट्टी का दिन उसके लिए हफ़्ते का सबसे बुरा दिन था। किसी शादी में भी स्कूल के नीली-खाकी यूनीफॉर्म पहनते दिखाई पड़ता था। बेचारे के पास जो कमीज़पैंट का एक ही जोड़ा था, वह नीली-खाकी यूनीफॉर्म था। मोरपाल का स्कूल आठवीं के बाद छूट जाता है। वह आज भी अपने पिता की तरह वहीं खेती-मजूरी करता है। मिहिर पांडेय धनी परिवार का है। घर मे सारी सुविधाएँ हैं। वह स्कूल जाने से रोया करता था। रोज़ नए बहाने बनाता था। स्कूल से इतना नफ़रत करता था कि अगर स्कूल के रास्ते में पानी भर जाने के कारण स्कूल की छुट्टी हो जाए तो घर में वह नाचता रहता था। उसे स्कूल की नीली-खाकी यूनीफॉर्म से घृणा थी। उसे पहनना हमेशा टाल देता था। स्कूल में बिताए समय को वह अपने बचपन का सबसे खराब समझा जाता था। अपने राजमा-चावल के बदले मोरपाल का छाछ का डिब्बा अपना लेता था। समाज के दो विभिन्न पहलुओं को मिहिर और मोरपाल के माध्यम से हमारे सामने पेश किया है। मोरपाल के लिए घर में कोई सुविधा नहीं है, फिर भी वह पढ़ना चाहता है। जबकि मिहिर के लिए सुविधा होते हुए भी स्कूल जाना पसंद नहीं करता। स्कूल एवं यनीफॉर्म से गहरा प्यार रखते हुए भी मोरपाल को आठवीं से स्कूल छोडना पडता है और वह पिताजी की तरह खेतीमजूरी करने को विवश होता है। मगर विशेष रुचि न रखते हुए भी मिहिर ऊँचे पद पर पहूँचता है। यहाँ सामाजिक असमता का तस्वीर खींचखीं लिया है। |
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| 2. |
DEEPAK KUMAR SHARMA |
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Answer» Hii |
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| 3. |
The atomic numbers of element which has same group number are :-A. 4, 12 ,20B. 63, 65, 67C. 5, 14, 33D. 8, 17, 34 |
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Answer» Correct Answer - A::B `K_(p)=K_(c )((1)/(12)xx600)^(-1)Deltan_(g)=1-(1+1)=-1` `K_(c ) = 50 K_(p)" therefore "K_(c )gt K_(p)` |
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| 4. |
Which of the following graph is/are incorrect for 2p orbital ?A. B. C. D. |
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Answer» Correct Answer - B::D Phenol and Carboxylic acid is always more acidic than `H_(2)O`. |
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| 5. |
At certain temperature, the equilibrium constant `(K_(c ))` is `1//16` for the reaction : `SO_(2)(g)+NO_(2)(g)iffSO_(3)(g)+NO(g)` If one mole of all the four gases are taken in 1 l container. Then select CORRECT statement(s) :A. Equilibrium concentration of NO(g) is 0.6 M.B. Equilibrium concentration of `NO_(2)(g)` is 1.6 M.C. Total moles of reaction mixture at equilibrium remains same.D. Moles of `NO_(2)(g)` greater than moles of NO(g) at equilibrium |
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Answer» Correct Answer - A::B `{:(Be,Mg,Ca,),(4,12,20,"(Group-II)"):}` Atomic number : [58 - 71] `rarr III B` group |
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| 6. |
Identify the correct option is :A. trans-2-butene `lt` cis-2-butene stability of alkeneB. , Stability of carbocationC. , Heat of hydrogenationD. trans-2-butene `lt` cis-2-butene Heat of combustion |
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Answer» Correct Answer - A::C::D For 2p orbital Radial node = 2 - 1 - 1 = 0 and `R_((r ))v//r` r start from origin. |
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| 7. |
For 3 moles of ammonia gas, which of the following is/are trur ? `[N_(A)=6 xx 10^(23)]`A. It contains 12 `N_(A)` atomsB. Volume at 1 atm and 273 K is 67.2LC. Number of molecules is `1.8 xx 10^(24)`D. Mass % of hydrogen is 17.65 |
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Answer» Correct Answer - A::B::C PbO, ZnO `rarr` amphoteric oxides `N_(2)O rarr` neutraoxides `CO_(2),N_(2)O_(3), P_(4)O_(10),P_(4)O_(6)rarr` acidic oxides BaO = basic oxide |
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| 8. |
Consider the following equilibrium reaction at `327^(@)C`. `A(g)+B(g)iffC(g)+D(l)`. Which of the following option(s) is/are correct regarding `K_(p)` and `K_(c )` relationship ? [Given : 1/R = 12]A. `K_(c )=50 K_(p)`B. `K_(p) lt L_(c )`C. `K_(p) = K_(c )`D. `K_(p) gt K_(c )` |
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Answer» Correct Answer - B::C::D `SO_(2)(g)+NO_(2)(g)iffSO_(3)(g)+NO(g)` `"mole 1 1 1 1"` `because Q=1 gt K_(C )` At equilibrium `"1+x 1+x 1-x 1-x"` mole `(1)/(16)=((1-x)/(1+x))^(2)implies (1-x)/(1+x)=(1)/(4)" "implies x=(3)/(5)` `therefore [NO] =1-(3)/(5)=0.4, [NO_(2)] =1+(3)/(5)=1.6` |
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| 9. |
The gaseous reaction `2A(g) + nB(g) iff mC(g)` is represented by following curves. What is the value of `m + n`? |
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Answer» Correct Answer - m + n = 6 `{:(,2A,+,nB,iff,mC),("Initial moles",6,,10,,0),("At equilibrium",6-2x=4,,10-nx=8,,mx=4):}` `6-2x=4` `x = 1` `10-nxx1=8` n = 2 `mxx1=4` |
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| 10. |
Excess intake of cobalt for longer periods leads to (A) Polycythemia (B) Megaloblastic anemia (C) Pernicious anemia (D) Microcytic anemia |
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Answer» (A) Polycythemia |
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| 11. |
`H^(+)` ions are in excited state from where maximum 6 types of photons can be emitted. If E is the separation energy of electron in this excited state of `H^(+)` ion, then how many times of energy E is required to ionize Hydrogen atom ? |
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Answer» Correct Answer - 4 `6=(n(n-1))/(2)" "n=4` Separation energy, `E=+13.6 xx(z^(2))/(n^(2))=+13.6xx((2)^(2))/((4)^(2))=3.4 eV` l.E. of Hydrogen atom `=x xxE=13.6 eV` `x=(13.6)/(E)=4` |
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| 12. |
`H_(2)S` and `SO_(2)` can be distinguished by:A. Litmus paperB. `MnO_(4)^(-)`C. `(CH_(3)COO)_(2)Pb`D. none of these |
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Answer» Correct Answer - C `H_(2)S,SO_(2)` both are acidic so cannot distinguish by litmus paper. `MnO_(4)^(-)` oxidising agentt, so both are oxidised to `SO_(4)^(2-)`. `Pb^(2+)+S^(2-)rarrPbS-("black ppt.")SO_(2)` will not give black precipitate so can be distinguished. |
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| 13. |
Give an account of the magnetic properties of transition metal complexes? |
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Answer» An electron is a charged particle (negatively charged) which revolves around the nucleus and spins on its own axis. A magnetic field is generated due to the orbital motion and spin of the electron. The spinning of an electron in an orbit is very much similar to flow of electric current in a closed circuit. Therefore, an unpaired electron is regarded as a micro magnet which has a definite magnetic moment. A substance which contains an unpaired electron when placed in a magnetic field interacts with the applied field. Consequently, an attractive force is exerted and the paramagnetic property is shown. The number of unpaired electrons determines the magnitude of magnetic moment. Higher the number of unpaired electrons more is the magnetic moment and greater will be the paramagnetic behaviour of the substance. In the case of paired electrons, the electrons in each pair will have opposite spin. The magnetic field created by the electrons of same pair is equal and opposite in nature. Hence, the magnetic field which is created by one electron is cancelled by the other. So the net effect of the magnetic moment is zero. These kinds of substances show diamagnetic property and are repelled by the applied magnetic field. |
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| 14. |
An `alpha`-particle having kinetic energy x MeV falls on a Cu-foil. The shortest distance from the nucleus of Cu to which `alpha`-particle reaches is `1.67 xx 10^(-14) m`. What is the value of x ? [Given : Atomic number of Cu = 29, K = `9 xx 10^(9) Nm^(2)//C^(2)`] |
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Answer» Correct Answer - 5 `K.E.=(KZe.2e)/(r ), " "K.E.=(9xx10^(9)xx29xx2(1.6 xx 10^(-19))^(2))/(1.67xx10^(-14))=5Mev` |
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| 15. |
Assertion: Systermatics is the branch of biology that deals with classification of living organisms. Rerson: The aim of classification is to group the organisms.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reson is false.D. If both assertion and reason are false. |
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Answer» Correct Answer - B Syntematics is the science of identification, naming and classification of the organisms into groups. |
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| 16. |
What are the advantages of CFT over VBT |
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Answer» The VBT has some short comings: (i) It does not provide insight into the origin of the characteristic colour of the complex ion (ii) It does not distinguish between weak and strong ligands. (iii) It does not give quantitative interpretation of the thermodynamic or kinetic stabilities of coordination compounds. (iv) There is no quantitative interpretation of magnetic data (magnetic moment). (v) It does not explain why some complexes are inner-orbital and other are outer-orbital complexes. So to remove most of these short comings Crystal Field Theory (CFT) is introduced.... |
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| 17. |
Which of the following will not give positive chromyl chloride test?A. Sodium chloride, `NaCl`B. Mercuric chloride, `HgCl_(2)`C. Zinc chloride `ZnCl_(2)`D. Aniline hydrochloride`C_(6)H_(5)NH_(2).HCl` |
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Answer» Correct Answer - B `HgCl_(2)` due to covalent characters, sufficient chloride ions are not obtained. |
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| 18. |
Determine the value of `((x+y^(2)))/(2)` for `Cr^(3+)` ion Where x = number of unpaired electron in `Cr^(3+)` y = Manetic moment of `Cr^(3+)` |
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Answer» Correct Answer - 9 Electronic configuration of `Cr^(3+)` `implies[Ar]3d^(3)4s^(@)` x = 3 unpaired electron `y = sqrt(3(3+2))=sqrt(15)` `(x+y^(2))/(2)" implies "(3+(sqrt(15))^(2))/(2)=9` |
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| 19. |
a carbon compound containing two double bond |
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Answer» Ketene CH2=C=O |
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| 20. |
मनुष्य में कार्बन डाइऑक्साइड का उत्सर्जन किससे होता है?A. वृक्कB. फेफड़ाC. त्वचाD. यकृत |
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Answer» Correct Answer - B |
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| 21. |
கோட்டை என்னும் சொல் திராவிட மொழிகளில் எவ்வாறு எடுத்தாளப்பட்டுள்ளது? |
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Answer» கோட்டை என்வைட் சொல் தமிழில் கோமுடை நோக எனப்படுகிறது. மலையாளத்தில் கோட்ட கோடு லெப்படுகிறது.
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| 22. |
A right angled triangular prism of refractive index `mu_(1)` is kept floating on a liquid (surface) having refractive index `mu_(2)`. The condition such tat light incident normally passes through base of prism as shown in figure.A. `mu_(1)=Cos2theta//Costheta`B. `mu_(2)=Cos2theta//Costheta`C. `mu_(1)=Sin2theta//Costheta`D. `mu_(2)=Sin2theta//Sintheta` |
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Answer» Correct Answer - B `sin(90-theta)=(1)/(mu_(1))impliescostheta=(1)/(mu_(1))to(1)` `sin(90-2theta)=(1)/((mu_(1)//mu_(2)))` `cos2theta=(mu_(2))/(mu_(1))=(mu_(2))/((1//costheta))thereforemu_(2)=(cos2theta)/(costheta)` |
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| 23. |
if `E=E_(0)sin(kz-omegat)` and `B=B_(0)(kz-omegat)` are electric and magnetic field produced by an electromagnetic wave travelling in +z direction in a medium. Then if `eta=(E_(0))/(B_(0))`, then the value of `eta` is `[mu`=permeability of a medium `epsilon=`permittivity of medium]A. `sqrt(in//H)`B. `sqrt(mu//en)`C. `sqrt(mu in)`D. `(1)/(sqrt(muin))` |
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Answer» Correct Answer - B Dimensional analysis. |
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| 24. |
If a polarised light of intensity `l_(0)//2` is passed through two polariods `P_(1)` and `P_(2)` as shown in figure. Then the intensity of light observed by an observer on other side of `P_(2)` (if the polaroid `P_(1)` is rotated clockwise) as a funtion of angle `theta`.A. B. C. D. |
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Answer» Correct Answer - D `l=((l_(0))/(2))cos^(2)theta.sin^(2)theta=(l_(0))/(2)[(sin2theta)/(2)]^(2)=(l_(0))/(8)sin^(2)2theta` |
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| 25. |
A small pulse is generated on a ring rotating with constant angular velocity `omega` as shown in the figure. Then the speed of pulse with respect to ground.A. `omegaR`B. `omegaR//2`C. `2omegaR`D. zero |
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Answer» Correct Answer - D `2Tsintheta=dmomegat^(2)R` `approx2Ttheta=mudlomega^(2)R` `approx2Ttheta=muR^(2)thetaomega^(2)R` `implies(T)/(mu)omega^(2)R^(2)` or `v_(wave)=omegaR` Note `v_(wave)` obtained is always with respect to medium. `thereforev_("wave/ground")=omegaR-omegaR` `=0` |
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| 26. |
A point source of sound is vibrating with a frequency of 256 vibrations per second in air and propagating energy uniformly in all directions at the rate of 5 joules per second. Calculate the amplitude of the wave at a distance of 25 m from the source. Assume non-dissipative medium `[c=330m//s` & density of air `=1.29kg//m^(3)]`A. `0.8xx10^(-2)m`B. `0.8xx10^(-8)m`C. `10^(-6)m`D. `10^(-4)m` |
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Answer» Correct Answer - C `l=2pi^(2)rhovA^(2)upsilon^(2)=(w)/(4pir^(2))` `thereforeA=[(W)/(8pi^(3)rhovupsilon^(2))]^(1//2).(1)/(r)cong10^(-6)m` |
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| 27. |
Which Ligand is strongest among them?A. `Cl^(-)`B. `Br^(-)`C. `I^(-)`D. `CN^(-)` |
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Answer» Correct Answer - D |
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| 28. |
`C_6H_5COOH`isA. phenyl carboxylix acidB. benzene - 1 -oic acidC. benzanoic acidD. None of these |
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Answer» Correct Answer - C |
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| 29. |
Ligand should have ________ to form coordinate bond with Central metal.A. Vacant d-OrbitalB. Fully filled Orbital.C. Half filled OrbitalD. None of these |
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Answer» Correct Answer - B |
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| 30. |
`C_6H_5COCH_3` isA. methyl benzyl etherB. ethyl phenyl etherC. methyl phenyl etherD. none of these |
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Answer» Correct Answer - C |
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| 31. |
53 ppm of `Na_2CO_3` isA. 53 g of `Na_2CO_3` in `10^(6)` g of solutionB. 53 g of `Na_2CO_3` in `10^(9)` g of solutionC. 53 g of `Na_2CO_3` in 100 g of solutionD. none of these |
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Answer» Correct Answer - A |
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| 32. |
Common name for propan-2-ol isA. n-propyl alcoholB. iso-propyl alcoholC. neo-propyl alcoholD. none of these |
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Answer» Correct Answer - B |
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| 33. |
‘In ethane there are 6 covalent bonds. Five are strong σ bonds and the remaining one is a weak π bond.’ 1. Do you agree with this? 2. How is a bond different from π bond in the mode of formation? |
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Answer» 1. Yes. 2. Sigma bond is formed by the end to end overlapping of bonding orbitals along the internuclear axis, π bond is formed by the lateral or sidewise overlap of half filled atomic orbitals. |
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| 34. |
Depending upon the type of overlapping, covalent bonds are of two types. a) Name them and give any two difference between them. b) Find the total number of these two types of bonds ’ in propane and 2-butene |
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Answer» (a) Sigma (σ) bond and pi (π) bond. Sigma (σ) bond: This type of covalent bond is formed by the end to end overlapping of half-filled atomic orbitals along the internuclear axis. The overlap is also known as head on overlap or axial overlap. The electrons constituting sigma bond are called sigma electrons. Pi (π) bond: This type of covalent bond is formed by the lateral or sidewise overlap of half-filled atomic orbitals. The atomic orbitals overlap in such a way that their axes remain parallel to each other and perpendicular to the internuclear axis. (b) 10 σ bond in propane 11 σ bond and 1π bond in 2-butene |
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| 35. |
In tank slaking, the second tank (60-75cm deep) is filled with:(a) Water(b) Lime-milk(c) Lime(d) Limestone |
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Answer» The correct answer is (b) Lime-milk The explanation is: Lime is gradually added to water present in the first tank and stirred continuously. It results in formation of milk of lime, which is allowed to falls through a sieve into the second tank. |
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| 36. |
Densities for ________ and ________do not change significantly at ordinary conditions with pressure.(a) Gas, liquids(b) Liquids, solids(c) Solids, gas(d) None of the mentioned |
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Answer» Right answer is (b) Liquids, solids The best explanation: Densities for liquids and solids do not change significantly at ordinary conditions with pressure. |
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| 37. |
Oxides of non-metals are....... in nature. a) acidic b) basic c) neutral d) none of the above. |
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Answer» Oxides of non-metals are acidic in nature. |
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| 38. |
Iron is galvanized by coating with......a) nickel b) tin c) zinc d) copper |
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Answer» Iron is galvanized by coating with zinc. |
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| 39. |
Name the non-metal which is applied on wounds as an antiseptic. a) Iodine b) Nitrogen c) Chlorine d) Carbon |
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Answer» Iodine non-metal which is applied on wounds as an antiseptic. |
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| 40. |
The velocity- time graph of car moving on a straight track is given below. The car weight 1000kg. The distance travelled by the car during the whole motion is:A. 50mB. 75mC. 100mD. 150m |
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Answer» Correct Answer - B Distance travelled by the car in 10 second and it is same as area under the v-t curve. `:. Distance =1/2xx2xx10+10xx5+1/2xx3xx10` `=10+50+15` `=75 m` Hence(B) |
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| 41. |
Which of the following element will form basic oxides? a) Sulphur b) Nitrogen c) Sodium d) Carbon |
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Answer» Sodium element will form basic oxides. |
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| 42. |
The green coating on the top of the copper vessel is a mixture of .... a) CuSO4 and CuCO3 b) Cu(OH)2 and CO2 c) CuSO4 and CuO d) Cu(OH)2 and CuCO3 |
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Answer» (d) Cu(OH)2 and CuCO3 |
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| 43. |
Why do copper objects develop a green coating in air? |
| Answer» Copper reacts with moist carbon dioxide in the air and gains a green coating of basic copper carbonate | |
| 44. |
The velocity- time graph of car moving on a straight track is given below. The car weight 1000kg. The braking force rewquired to boring the car to a stop with in one second from the maximum speed is:A. `(10000)/3N`B. `5000N`C. `10000N`D. `(5000)/3N` |
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Answer» Correct Answer - C Retardation `=(10ms^(-1))/5 =10ms^(-2)` :. Braking force =ma `=1000xx10=10000` N Hence(C) |
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| 45. |
Why does a copper vessel develop with green coating in rainy season? |
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Answer» Oxygen, carbon dioxide and water vapour of the air attack copper metal forming green coloured basic copper carbonate. The formula is CuCO3, Cu(OH)2 |
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| 46. |
Will Current flow more easily through a thick wire or thin wire of the same material when connected to the same source? Why? |
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Answer» The current will flow more easily through thick wire because the resistance of a conductor is inversely proportional to area of cross section. If thickness of the wire less is resistances and hence more easily the current flows. |
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| 47. |
Why does distilled water not conduct electricity whereas rain water does? |
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Answer» Distilled water cannot conduct electricity because it does not contain ions while rainwater conducts electricity as it contains ions due to presence of dissolved salts in it. |
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| 48. |
`BF_3 & C Cl_4` on reaction with water produce _____ & _______ respectively:A. `H_3BO_3+HF , H_2CO_3` + HClB. `H_3BO_3+HBF_4` , No reactionC. `H_3BO_3+HBF_4 , H_2CO_3 + HCl`D. `H_3BO_3+HF` No reaction |
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Answer» Correct Answer - B `BF_3+H_2O to H_3BO_3+HBF_4` `C Cl_4 + H_2O to` No reaction (since no vacant orbitals are present on carbon.) |
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| 49. |
The ratio of P to V at any instant is constant and is equal to 1. for a monoatomic ideal gas undergoing a process. What is the molar heat capacity of the gas?A. `(3R)/2`B. `(4R)/2`C. `(5R)/2`D. `0` |
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Answer» Correct Answer - B From first law of Thermodynamics , `DeltaE=q+w implies nC_vdT=nCdT-PdV` .. (1) Now according to process , P=V and according to ideal gas equation , PV=nRT We have , `V^2=nRT` On differentiating , 2VdV=nRdT and PdV=VdV=`(nRdT)/2` So from first equation we have, `nC_vdT=nCdT-(nRdT)/2` So, `C_v=C-R/2` Hence C`=(4R)/2` |
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| 50. |
At a certain temperature the following equilibrium is established `CO(g)+NO_2(g)hArrCO_2(g)+NO(g)` One mole of each of the four gas is mixed in one litre container and the reaction is allowed to reach equilibrium state.When excess of baryta water `(Ba(OH)_2)` is added to the equilibrium mixture, the weight of white ppt. `(BaCO_3)` obtained is 236.4 gm.The equilibrium constant `K_C` of the reaction is (Ba=137)A. 1.2B. 2.25C. 2.1D. 3.6 |
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Answer» Correct Answer - B `{:(,CO(g)+,NO_2(g)hArr , CO_2(g)+,NO(g)),(t=0,"1 mole","1 mole","1 mole","1 mole"),(At eq. , 1-x,1-x,1+x,1+x):}` `CO_2+Ba(OH)_2 to BaCO_3` mole of `BaCO_3=263.4/197=1.2` So mole of `CO_2` at eq. =12 or 1+x=1.2 x=0.2 `K_C=((1+x)/(1-x))^2=((1.2)/(0.8))^2 =2.25` |
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