This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is F-centre ? |
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Answer» . It is the anion vacancy occupied by free electron in metal excess defect |
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| 2. |
What are the co-ordination numbers of octahedral voids and tetrahedral voids ? |
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Answer» 6 and 4 respectively. |
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| 3. |
Sodium is a member of which group in periodic table ?(a) Group-IA(b) Group-IIA(c) Group-IVA(d) None of these |
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Answer» Sodium is a member of Group-IA in periodic table. |
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| 4. |
What is the co-ordination number of cation and anion in Caesium chloride (bcc arrangement) ? |
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Answer» your the answer 8 and 8. |
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| 5. |
What is emulsion ? How many types of emulsion. |
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Answer» Emulsions are colloidal solution of two immicible liquids in which dispersion of tinely divided droplets in another liquid occurs. Emulsion have been classified into two types– (i) Oil in water emulsion – In this dispersed phase is oil while the dispersion medium is water. Example – Milk (liquid fat is dispersed in water) (ii) Water in oil Emulsion – In this dispersed phase is water dispersion medium is oil. Example– Butter (water is dispersed into oil) |
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| 6. |
The shape of XeF4 is–(a) Tetrahedral(b) Square planar(c) Pyramidal(d) LInear |
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Answer» The shape of XeF4 is Group-IIA |
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| 7. |
Which of the following give biuret test?(a) Glycine(b) Alanine(c) both (a) and (b)(d) None of these |
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Answer» (d) None of these The name of the test comes from the name of the compound, biuret, which gives this test. The reaction is not absolutely specific for peptide bond because many compounds containing two carbonyl groups linked through nitrogen or carbon atoms give a positive result. |
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| 8. |
What is meant by the term co-ordination number ? Find the co-ordination number is ccp and bcc. |
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Answer» It is defined as the number of nearest neighbours of a particle in a close packed structure. Co-ordination number in ccp = 12 Co-ordination number in bcc = 08 |
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| 9. |
Which one of the following elements is found in free state in nature-(a) Sodium(b) Iron(c) Zince(d) Gold |
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Answer» Gold elements is found in free state in nature. |
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| 10. |
Which one of the following is an alkaline earth element ?(a) Carbon(b) Calcium(c) Zinc(d) Iron |
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Answer» Calcium is an alkaline earth element . |
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| 11. |
Protective sols are– (a) Lyophilic(b) Lyophobic(c) Both (a) and (b)(d) None of these |
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Answer» Protective sols are Lyophilic |
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| 12. |
Which one of the metal is liquid at normal temperature ?(a) Zinc(b) Mercury(c) Sodium(d) Water |
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Answer» Mercury is liquid at normal temperature |
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| 13. |
The compound formed on heating chlorobenzene with chloral in the presence of concentrated sulphuric acid is1 gammexene2 hexacholoroethane3 freon4 DDT |
| Answer» Answer will be 4 DDT | |
| 14. |
IUPAC name of HO – CH2 – CH2 – OH is (a) Ethylene glycol(b) Ethane-1, 2-diol (c) Ethyl-1, 2-diol(d) Ethylene diol |
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Answer» IUPAC name of HO – CH2 – CH2 – OH is Ethane-1, 2-diol. |
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| 15. |
For a d-electron , the orbital angular momentum is |
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Answer» Answer: √6 h/2Π Orbital angular momentum is one of the quantum numbers used to specify the position of an electron in an atom. Total orbital angular momentum is the sum of the orbital angular momentum from each of the electrons. |
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| 16. |
Is it isopentyl or sec-pentyl? |
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Answer» It is n -pentyl but also we say it as iso pentyl |
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| 17. |
give two examples where carbon atom is sp2 and sp hybridized. explain these hybridizations with the help of orbital pictures |
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Answer» Examples of sp Hybridization:
Examples of sp2 Hybridization
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| 18. |
What is metal? |
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Answer» A substance with high electrical conductivity, luster, and malleability, which readily loses electrons to form positive ions (cations). Metals are otherwise defined according to their position on the Periodic Table. |
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| 19. |
CH ≡ CH+O3 → X + Zn/CH3COOH →YThe compound Y is: |
| Answer» Ethyne on ozonolysis gives acetylene ozonide.this on addition of water produces glyoxal.this on reacting with zinc acetic acid gives CH2OH-CH2OH | |
| 20. |
Select the incorrect statement.A. Lime water produces white precipitate with both `CO_(2)^(2-)` and `SO_(3)^(2-)` species.B. Calomel reacts with ammonia solution and forms white precipitate of `Hg_(2)Cl_(2).NH_(3)`C. Both `NO_(3)^(-)` and `NO_(3)^(-)` respond to brown ring test.D. Ferric ions give prussian blue precipitate on adding potassium ferrocyanide solution. |
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Answer» Correct Answer - 2 `Hg_(2)Cl_(2)+2NH_(4)OHrarrHgdarr("black")+Hg(NH_(2))Cldarr("white")+NH_(4)Cl+2H_(2)O` |
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| 21. |
Assess the cultural consequences of globalization |
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Answer» At the same time, global economic growth and industrial productivity are both the driving force and the major consequences of globalization. They also have big environmental consequences as they contribute to the depletion of natural resources, deforestation and the destruction of ecosystems and loss of biodiversity. |
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| 22. |
Boron and silicon of very high purity can be obtained through : (1) vapour phase refining (2) electrolytic refining (3) liquation (4) zone refining |
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Answer» (4) zone refining "Boron" and "Silicon" of very high purity can be obtained through :- zone refining method only. While other methods are used for other metals/ elements i.e. (i) Vapour phase refining (ii) electrolytic refining (iii) liquation etc. |
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| 23. |
Politics is systematic study of |
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Answer» Political science, the systematic study of governance by the application of empirical and generally scientific methods of analysis. As traditionally defined and studied, political science examines the state and its organs and institutions. |
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| 24. |
Write two features of behaviourlism? |
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Answer» (1) Regularities; (2) Verification; (3) Techniques; (4) Quantification; (5) Values; (6) Systematisation; (7) Pure Science; and (8) Integration. |
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| 25. |
Determine total number of atoms in per unit formula of (A), (B) & (C). |
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Answer» The answer is (18.00) (A) = CrO2Cl2 (B) = Na2CrO4 (C) = CrO5 |
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| 26. |
Calculate ΔfH° (In kJ/mol) for C2H6(g), if ΔcH° [C(graphite)] = –393.5 kJ/mol,ΔCHº [H2(g)] = –286 kJ/mol and ΔCHº [C6H6(g)] = –1560 kJ/mol |
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Answer» The answer is (–85.00) C6H2(g) + 3.5O2(g) →2CO2(g) + 3H2O(l) 2 × (–393.5) + 3 × (–286) – (–1560) = –85 kJ/mol |
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| 27. |
A primary reason why nation conduct international trade |
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Answer» The primary reason for engaging in international trade is the unequal distribution of resources among nations. In general, a nation satisfies the demands for a scarce resource by trading with a more abundant local resource. |
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| 28. |
‘Decentralization has helped to deepen the democracy in India.’ Evaluate this statement with examples. |
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Answer» Decentralization in about 1992
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| 29. |
Discuss the functions of the welfare state in the contemporary era |
Answer»
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| 30. |
There are two compounds A and B of molecular formula C9H18O3. A has higher boiling point than B. What are the possible structures of A and B? |
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Answer» The answer is (2) In (A), extensive inter-molecular H-bonding is possible while in (B) there is no Inter-molecular Hbonding. |
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| 31. |
Among the reactions (a) - (d), the reaction(s) that does/do not occur in the blast furnace during the extraction of iron is/are : (a) CaO + SiO2 → CaSiO3 (b) 3Fe2O3 + CO → 2Fe3O4 + CO2 (c) FeO + SiO2 → FeSiO3 (d) FeO → Fe + 1/2O2 (1) (c) and (d) (2) (a) and (d) (3) (d) (4) (a) |
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Answer» Answer is (1) (c) and (d) In blast furnace (metallugy of iron) involved reactions are (a) CaO + SiO2 → CaSiO3 (b) 3Fe2O3 + CO → 2Fe3O4 + CO2 Answer is(1) (c) and (d) |
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| 32. |
∫x2/(x2 - 4) dx, x ∈ [5, 3] |
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Answer» (d) 2 - tan-1(15/7) |
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| 33. |
A spherical ball of mass `M` moving with initial velocity `u` collides elastically with another ball of mass `M`, which is fixed at one end of `L` shaped rigid massless frame as shown in Fig. (a). The `L` shaped frame contains another mass `M` connected at the other end. The speed of the striking mass after collision isA. `u//7` backwardsB. `u//3` is same directionC. `0`D. `u//2` backwards |
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Answer» Let `v_(1)` be the velocity of striking mass after collision & `v_(2)` be the velocity of centre of mass of frame after collision by momentum conservation `mv=mv_(1)+2mv_(2)`……(`1`) By angular momentum conservation `mv(L)/(2)=mv_(1)(L)/(2)+mL^(2)omega`.....(`2`) `c=1rArrv=(v_(2)+(L)/(2)omega)-v_(1)`.....(`3`) from (`1`). (`2`) and (`3`) `omega=(4v)/(7L)`, `v_(1)=-(v)/(7)` & `v_(2)=(4v)/(7)` |
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| 34. |
The point with respective position vector 60 i + 3 j, 40i - 8j, xi - 52 j are collinear if x is equal to which of the following?(a) –40 (b) 40 (c) 20 (d) –20 |
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Answer» Correct option: (a) –40 |
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| 35. |
Which of the following is a polyamide? (a)Teflon (b) Nylon-6,6 (c) Terylene (d) Bakelite |
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Answer» (b) Nylon-6,6 |
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| 36. |
A mixture of `HCI(g), PCI_(3)(g)` and `PCI_(5)(s)` each have equal number of CI-atom then their molar ratio in the mixture is :A. `1 : 3 : 5`B. `1 : 1 : 1`C. `15 : 2 : 3`D. `15 : 5 : 3` |
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Answer» Correct Answer - D A mixture of `HCI(g), PCI_(3)(g)` ……….. Let there are N atom of CI in each then moles of CI-atoms `= (N)/(N_(A))` `HCI: PCI_(3):PCI_(5)` `(N)/(N_(A)): (1)/(3)(N)/(N_(A)):(1)/(5)(N)/(N_(A))` `15:5:3` |
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| 37. |
Which one of the following polymers is prepared by condensation polymerization? (a) Teflon (b) Rubber (c) Styrene (d) Nylon-6,6 |
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Answer» (d) Nylon-6,6 |
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| 38. |
Which of the following pair can be distinguished by NaOH and `I_(2)` (Iodoform test)?A. `CH_(3)-CH_(2) -OH` and `CH_(3)-overset(O)overset(||)C -H`B. `CH_(3)-overset(O)overset(||)C-H` and `CH_(3) -overset(O)overset(||)C-CH_(3)`C. `CH_(3)-OH` and `CH_(3)-CH_(2)-OH`D. none of these |
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Answer» Correct Answer - C With NaOH and `I_(2)` (Iodorom test) shown by ony `CH_(3)-overset(O)overset(||)C-` and `CH_(3)-overset(OH)overset(|)C-H-` |
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| 39. |
Which of the following compound will be most reactive toward `S_(N)^(1)` reaction?A. `CH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)C-1`B. `CH_(3)-overset(I)overset(|)(CH)-CH_(3)`C. `Ph-overset(Ph)overset(|)underset(CH_(3))underset(|)-I`D. `CH_(3)CH=CH-I` |
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Answer» Correct Answer - C Rate of `S_(N)^(1) propto` stability of carbocation |
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| 40. |
Arrange the following in order of their reactivity toward decarboxylation with sodalime (i) (ii) `CH_(2)=CH-overset(O)overset(||)C-OH` (iii) `CH-=C-overset(O)overset(||)C-OH` (iv) `CH_(3)-CH_(2)-overset(O)overset(||)C-OH`A. III `gt` I `gt` II `gt` IVB. II `gt` III `gt` IV `gt` IC. I `gt` II `gt` III `gt` IVD. IV `gt` I `gt` III `gt` II |
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Answer» Correct Answer - A Rate of decarboxylation `propto` stability of carbanion |
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| 41. |
A Solution is prepared by dissolving certain amount of solute in 500 g water. The % by mass of a solutions is 2.38 . Calculate mass of the solute. |
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Answer» Correct Answer - Mass of the solute =12. 19 g Given : `W_(1)`= Mass of a solvent (water) = 500 g `W_(2)` Mass of a solute =? % by mass = % `(W//W) = 2. 38` Let mass of the solute `=W_(2) =x g` `:.` Mass of the solution `= W_(1) + W_(2) = (500 + x) g` Now per cent by mass of solute `= ("mass of solute")/("mass of solution") xx 100` `= ("mass of solute")/("mass of solvent + mass of solute") xx 100` `:. 2.38 = (X )/((500 + X)) xx 100` `:. 2. 38 (500 + X) =100 x` `:. 2.38 xx 500 + 2.38 X =100 x` `:. 1190 + 2.38 X = 100 x` `:. 100 x -2.38 x= 1190` `:. (100 -2.38) x= 1190` `:. 97 .62 x = 1190` `:. x = (1190)/(96.62) =12.19` |
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| 42. |
Calculate mole fraction of HCI in a solution containing 24.8% of HCI by mass. |
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Answer» Correct Answer - Mole fraction HCI= 0.1398 Given : % by weight of HCI = 24.8 , Mole fraction of HCI= `X_(HCI)= ?` Consider 100 gram HCI solution . `:.` Weight of a solute (HCI) =24.8 g Weight of a solvent (water) = 100 -24.8 = 75.2 g `:. ` Moles of solvent = `n_(H_(2)O) = .(W_(H_(2)O))/(M_(H_(2)O))=(75.2)/(18) =4.178 mol H_(2)O` Moles of solute `=n_(H_(2)O) =(W_(H_(2)O))/(36.5) =(24.8)/(36.5)=0.6795 mol` `:. ` Total moles in solution `= n_(H_(2)O) + n_(HCI)` `=4. 178 + 0.6795 =4. 8575` Mole fraction of HCI `X_("HCI") =("moles of HCI")/("total moles in solution")` `= (0.6795)/(4.8575)= 0.1398` |
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| 43. |
Mole fraction of urea in its aqueous solution is 0.25 .What is the mass of urea present in 200 g urea solution ? (Molecular mass of urea is 60 g `mol^(-1)`) |
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Answer» Correct Answer - Mass of urea present =33.33 g Given : Mole fraction of urea = 0.25 Mass of urea in 200 g solution = ? Mole fraction of water = 1- 0.25 =0.75 Mass of urea = 0.25 `xx 60 =15 g` Mass of water = 0.75 `xx 100 = 75 g` `:.` Mass of solution = 15+ 75 = 90 g `:.` 90 g solution contains 15 g urea `:.200` g solution will contain `(200 xx 15)/(90) ` = 33.33 g urea |
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| 44. |
Which metal among the following has the highest packing efficiency?A. IronB. TungstenC. AluminiumD. Polonium |
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Answer» Correct Answer - C Iron and Tungsten have BCC, Poloniumhas SCC while Al has FCC type structure. The order of packing efficiency is SSC `(52.4%) lt B"CC" (68.04 %) lt F"CC" (74%)` |
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| 45. |
It is important that he _______ his reservations by Saturday. A) will confirm B) confirm C) confirms D) must confirm |
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Answer» Correct option is B) confirm |
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| 46. |
Calculate mole fraction of solute in its 2 molal aqueous solution . |
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Answer» Correct Answer - Mole fraction of the solute = 0.0347 Given : Concentration of solution =2 molal = 2 m Hence 2 moles of a solute are present in 1000 grams water . `:. W_(H_(2)O) =100 g` `:.` Number of moles of water `=n_(H_(2)O) =(W_(H_(2)O))/(M_(H_(2)O))` `= (1000)/(18)` `=55.56 `mol `:. ` Total moles in solution `=n_(H_(2)O) + n_(solute)` `=55.56 +2` ` = 57 .56 `mol `:. ` Mole fraction of a solute `=("Number of moles of solute" )/("Total moles in solution ")` `:. X_("solute") =(2)/(56.56) = 0.0347` |
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| 47. |
The vapour pressure of 2.1% solution of a non- electrolyte in water at `100^(@) C` is 755 mm Hg. Calculate the molar mass of the solute . |
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Answer» Correct Answer - Molar mass of non- electrolyte= 58. 69 g `mol^(-1)` At `100^(@)C` vapour pressure of water `=P_(o)`= 760 mm Hg Vapour pressure of the solutions = P= 755 mm Hg Since the solution is 2.1 by mass Mass of solute (non- electrolyte ) =`W_(2) =2.1 g` Mass of water `=W_(1) =100 -2.1 =97.9 g` Molar mass of water = `M_(1) =18 g mol^(-1)` Molar mass of non- electrolyte `=M_(2)= ?` `(P_(o) -P)/(P_(o)) = (W_(2) xx M_(1))/(W_(1) xx M_(2))` `:. M_(2) = ((P_(o))/(P_(o) - P)) xx (W_(2) xx M_(1))/(W_(1)) = (700xx 2.1 xx 18)/((760 - 755) xx 97.9) = 58.69 g mol^(-1)` |
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| 48. |
What is the volume of consumed during acid hydrolysed of 1.398 kg of sucrose? (Given: molar masses of sucrose water =18, density of water = 1g/`cm^(3)`)A. `0.072 dm^(3)`B. `0.720 dm^(3)`C. `0.18 dm^(3)`D. `0.018 dm^(3)` |
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Answer» Correct Answer - A Hydrolysis of sucrose is as `C_(12)H_(22)O_(11) + H_(2)O to C_(6)H_(12)O_(6) + C_(6)H_(12)O_(6)` `therefore w = (1368 g xx 18 g)/(343) = 72 g = 72 cm^(3)` `(therefore d = 1g cmp^(-3))` But `1 dm^(3) = 10^(-3) cm^(3)` `therefore` Volume of `H_(2)O = 72 xx 10^(-3) dm^(-3)` `=0.072 dm^(3)` |
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| 49. |
Aqueous solution of NaOH is marked 10% `(w//w)`. The density of the solution is 1.070 g `cm^(-3)`. Calculate (i) molarity and (ii) molality of NaOH. |
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Answer» Correct Answer - (i) Molarity of NaOH solution =2. 675 M (ii) Molality of NaOH solution = 2.778 m Given : Percentage by weight of NaOH `=10% (w//w)` Density of NaOH solution =D =1.070 g `cm^(-3)` Molar mass of NaOH =40 g `mol^(-1)` (i) Molarity of NaOH solution = ? (ii)Molality of NaOH solution = ? (i) For molarity of solution : Consider 100 g NaOH solution `:. ` Weight `H_(2)O+` Weight of NaOH =100 g `:. ` Weight of `H_(2)O = 100 - 10 = 90 g` Number of moles of NaOH `= (W_(NaOH))/(M_(NaOH))` `:. n_(NaOH) = .(10)/(40)` `=0.25 `mol Density of solution `(D) = ("Weight of solution " )/(" volume of solution " ) = (W)/(V)` `:. V = (W)/(D)` `=(100)/(1.070)` `=93 . 46 cm^(3)` `=0.09346 dm^(3)` Molarity `=(n)/(V)= (0.25)/(0.09346) =2.675 "mol" dm^(-3) (or M)` (ii) For molality of NaOH solution : Molality `=("Molar of NaOH ") /("Mass of solvent in gram ") xx 1000` `=(0.25)/(90) xx 1000` `=2.779 "mol" kg^(-1) (or m)` |
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| 50. |
What will be the value of molality for an aqueous solution of 10% w/W NaOH?A. 2.77B. 5C. 10D. 3.52 |
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Answer» Correct Answer - A `10% w//w to 10g NaOH+90gH_(2)O` `m=((10//40))/(90)xx 1000=2.77` |
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