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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Between O2 & O2-, which one has higher bond order? |
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Answer» O2 has higher bond order than O2- |
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| 2. |
Vitamin B12 contains-(a) Fe(II)(b) CO (III)(c) Zn(II)(d) Ca(II) |
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Answer» Vitamin B12 contains CO (III) |
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| 3. |
In paramecium, which is also a unicellular organism, the cell has a definite shape and food is taken in at a specific spot. Food is moved to this spot by the movement of cilia, which cover the entire surface of the cell.i. Depending on their environmental conditions, a paramecia can reproduce: a) Asexually b) Sexually c) Both a and b d) None ii. The significant advantages of conjugation for paramecium is: a) Genetic variation b) Rejuvenation c) Survivability d) All iii. The mutualistic relationship between paramecium and algae is called: a) Parasitic b) Symbiotic c) Endo-symbiotic d) None iv. Paramecium cell moves and collects food using: a) Flagella b) Cilia c) Both a and b d) None v. The “Specific spot” to take in food, is: a) Oval groove b) Food vacuoles c) Lysosomes d) None |
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Answer» (i) (c) (ii) (d) (iii) (c) (iv) (b) (v) (a) |
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| 4. |
The length and complexity of food chains vary greatly. Each organism is generally eaten by two or more other kinds of organisms which in turn are eaten by several other organisms. So, instead of a straight-line food chain, the relationship can be shown as a series of branching lines called a food web. i. The greatest number in trophic levels of food chain is of: a) Producers b) Primary consumers c) Secondary consumers d) Tertiary consumersii. Green plants in a terrestrial ecosystem capture ..... of the energy of sunlight that falls on their leaves and convert it into food energy. a) 1% b) 5% c) 10% d) None iii. Biological magnification is greatest in: a) Plants b) Lion c) Humans d) Micro-organisms iv. Decomposers comprises of: a) Bacteriab) Fungi c) Earthworms d) All v. Flow of energy in food web is unidirectional. This implies: a) 1% law b) 5% lawc) 10% law d) None |
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Answer» (i) (a) (ii) (a) (iii) (c) (iv) (d) (v) (c) |
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| 5. |
Define olfactory indicator name any one such stance which can be used as an olfactory indicator |
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Answer» Olfactory indicators indicate whether the solution is an acid or base by varying the smell when it is mixed with respective solutions. clove oil,vanilla and onion are the examples. |
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| 6. |
Define olfactory indicators name any one substance which can be used as olfactory indicators |
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Answer» Olfactory indicators indicate whether the solution is an acid or base by varying the smell when it is mixed with respective solutions. clove oil,vanilla and onion are the examples. |
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| 7. |
What is a partnership business in Uganda? |
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Answer» A partnership is defined under Section 2 of the Partnerships Act, 2010 as the relationship that exists among persons numbering between 2 and 20 who carry on a business together with the aim of making profits. |
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| 8. |
Which metal burn in air? |
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Answer» Magnesium burns in air by taking oxygen from air to form magnesium oxide which is basic in nature. Sodium matal burn in air. |
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| 9. |
A pump can fill a tank with water in 2 hours. Because of a leak, it took 18/5 hours to fill the tank. The leak can drain all the water of the tank in:1. 9/2 hours2. 7/2 hours3. 5 hours4. 4 hours |
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Answer» Correct Answer - Option 1 : 9/2 hours GIVEN: A pump can fill a tank with water in 2 hours. Because of a leak, it took 18/5 hours to fill the tank. CALCULATION: Suppose leak can drain all the water of the tank in ‘T’ hours. So, 1/2 - 1/T = 5/18 ⇒ 1/T = 1/2 - 5/18 ⇒ 1/T = 4/18 = 2/9 Hence, leak can drain all the water of the tank in 9/2 hours. |
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| 10. |
Protons , electron and neutron in nitride ion |
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Answer» As the molecular formula of nitride ion is N3- We can conclude that Nitrogen atom has 7 electrons after gaining 3 more electrons the total number of electrons became 10 electrons. The number of protons remains the same i.e 7 as the atomic number = number of protons. The number of neutrons can be calculated by subtracting the atomic number from its atomic mass. |
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| 11. |
a) l=4b) l=0,1,3 c) l=3d)All are correct |
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Answer» There are four quantum numbers for any electron : Principle quantum number (n)= It can take any value from 1, 2 .... Azimuthal quantum number (l) = values from 0 to n-1 magnetic quantum number (m) = m varies from l to -l spin quantum number = -1/2 and +1/2 Thus when n=5 , l can take values from 0 to 4. Thus l = 0,1,2,3,4 but m=3 suggest that l should be greater or equal to 3 .since m can take values from -l to +l only. Thus l = 0,1,2 does not match with the m value 3. Therefore second option is not correct.m cannot be 3 for l=0 or l=1 . |
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| 12. |
How to identify the coordinate bond in the compounds. |
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Answer» All coordination compounds like K4[Fe(CN)6] N2 O, Hydronium ion (H3O+), Ammonium ion (NH4+), NOF3 Watch this, it'll help: |
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| 13. |
X =1s2 2s2 2p6 3s2 3p6 4s2Y= 1s2 2s2 2p6 3s2 3p5 |
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Answer» 'X' is Calcium (Ca) with E-Configuration (2, 8, 8, 2). 'Y' is Chlorine (Cl) with E-Configuration (2, 8, 7). |
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| 14. |
At STP , the density of `C Cl_(4)` vapour in g/L will be nearest toA. 6.87B. 3.42C. 10.26D. 4.57 |
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Answer» Correct Answer - A 1 mole `C Cl_(4)` vapours `=12+4xx35.5=154 g` At STP , volume of 1 mole of a gas =22.4 L Thus , 154 g= 22. 4 L `:.` Density of `C Cl_(4)` vapours `=(154)/(22.4)g L^(-1)` `=6.87 g L ^(-1)` |
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| 15. |
The number of oxygen atoms in 4.4 of `CO_(2)` isA. `1.2xx10^(23)`B. `6xx10^(22)`C. `6xx10^(23)`D. `12xx10^(23)` |
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Answer» Correct Answer - A 1 mole of `CO_(2)=44g` of `CO_(2)` `=6.023xx0.1xx10^(23)` molecules `=6.023xx10^(22)` molecules `=6.023xx10^(22)` molecules of ` O_(2)` `=2xx6.023xx10^(22)` atoms of O `~~1.2xx10^(23)`atoms of O |
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| 16. |
Boron has two stable isotopes, `.^(10)B(19%)` and `.^(11)B(81%)`. The atomic mass that should appear for boron in the periodic table isA. 10.8B. 10.2C. 11.2D. 10 |
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Answer» Correct Answer - A Average of atomic weight `(% of ^(10)Bxx"atoms mass of"^(10)B+%of^(11)Bxx"atomic mass of"^(11)B)/(%of^(10)B+%of^(11)B)` `=(19xx10+81xx11)/(19+81)` `=(190+891)/(100)=10.81` |
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| 17. |
I cc `N_(2)O` at NTP containsA. `(1.8)/(224)xx10^(22)` atomsB. `(6.02)/(22400)xx10^(23)` moleculesC. `(1.32)/(224)xx10^(23)` electronsD. All of the above |
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Answer» Correct Answer - D At NTP 22400 c c of `N_(2)O` contains `=6.02xx10^(23)` molecules `:. 1 c c N_(2)O` will contain `=(6.02xx10^(23))/(22400)` molecules In `N_(2)O` molecules , number of atoms =2+1=3 Thus , number of atoms `=(3xx6.02xx10^(23))/(22400)` atoms `=(1.8xx10^(22))/(224)` atoms In `N_(2)O` molecule , number of electrons `=7+7+8=22` Hence , number of electrons `=(6.02xx10^(23))/(22400)xx22` electrons `=(1.32xx10^(23))/(224)` electrons |
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| 18. |
One litre hard water contains 12.00 mg `Mg^(2+)` millieqivalent of washing soda required to remove its hardness isA. 1B. 12.6C. `1xx10^(-3)`D. `12.16xx10^(-3)` |
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Answer» Correct Answer - A `underset(1 g-eq)(Mg^(2+))+underset(1 g-eq)(Na_(2)CO_(3))toMgCO_(3)+2Na^(+)` 1 g- equivalent of `Mg^(2+)=12g of Mg^(2+)` =12000 mg of `Mg^(2+)` Now , 12000 mg of `Mg^(2+)-=1000` milleequivalent of `Na_(2)CO_(3)` `:.` 12 mg of `Mg^(2+)-=1` milliequivalent of `Na_(2)CO_(3)` |
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| 19. |
The co transmitter may serve the following function/functions |
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Answer» Answer: A. Regulate the release of the primary transmitter from the nerve ending B. Alter postjunctional action of the primary transmitter C. Itself act as an alternative transmitter functions |
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| 20. |
How is benzamide obtained from benzoic acid? |
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Answer» Benzamide from benzoic acid. |
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| 21. |
At a given temperature and pressure nitrogen gas is more soluble in water than Helium gas. Which one of them has higher value of KH? |
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Answer» The answer is Helium gas. |
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| 22. |
What are Biodegradable polymers? Give an example. |
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Answer» The polymers which decompose on it own during a certain period of time are called biodegradable polymers. Ex: PHBV, Nylon–2–hycon–6. |
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| 23. |
Give the IUPAC name of the monomer of natural rubber. |
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Answer» Isoprene or 2–methyl–1, 3–butadiene. |
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| 24. |
What are condensation polymers? Give an example. |
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Answer» Condensation reacts between two different bifunctional or trifunctional monomeric units to give a polymer with the loss of simple molecules like H2O NH3 etc. is called condensation polymerisation. The polymers obtained are called condensation polymers. Ex: Nylon 6.6, Dacron etc. |
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| 25. |
Among alcohols and phenols which one is more acidic? and why? |
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Answer» In phenol charge because of resonance this facilitates the heterolytic eleavage of OH bond resulting in the formation of phenoxide ion the benzene ring with draws the negative charge from oxygen atom hence phenutide ion formed is resonance stabilizes done to this phenols are acidic in nature. But in alcohols neither does oxygen of OH group acquire positive change nor is the alkoxide ion is resonance stabilized in addition to this oxygen in alcohols is attached to electron donating alkyl groups these electron donating groups decrease the stability of alkoxide ion hence alcohol are not acidic. |
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| 26. |
What is a peptide bond? How many peptide bonds are present in a tetra peptide? |
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Answer» The -CONH – bond formed between two α–amino acids is called peptide bond. |
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| 27. |
What are carbohydrates? and how are they classified? |
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Answer» Carbohydrates are optically active polyhydroxy aldehydes or polyhydroxy ketones or those compounds which yield these on hydrolysis carbohydrates are classified into 3 types namely, monosaccharides, oligosaccharides and polysaccharides. |
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| 28. |
Name a food preservative which is most commonly used by food producers. |
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Answer» [Hint : Sodium metabisulphite (Na2S2O5).] |
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| 29. |
What is the cause of a feeling of depression in human beings ? Name a drug which can be useful in treating depression. |
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Answer» Hint : Low level of noradrenaline, a neurotransmitter causes depression in human beings. Antidepressant drugs are Iprniazid, Phenelzine.] |
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| 30. |
What are anionic detergents? |
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Answer» In anionic detergents large part of the molecules is anion and it is the anionic part of the molecule which is involved in their cleansing action. |
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| 31. |
How will you account for the following?(a) Actinoids exhibit more number of oxidation states than lanthanoides. (b) Atomic radii of second and third transition series elements are almost identical. |
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Answer» (a) As in actinoids the outer electrons are less firmly held, they are easily available for bonding. (b) due to lanthanoid contraction. |
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| 32. |
(Ag=107.8u, N=14u, O=16u, Na=23u, Cl=35.5u) |
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Answer» Moles of AgNo3= 50x 16.9/100x169.8 |
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| 33. |
Calculate ksp of Mg3(PO4)2 |
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Answer» [Mg2+] = 3s [PO43-] = 2s Ksp = (3s)3 ( 2s)2 Ksp = 108 s5 |
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| 34. |
Effect of common ions on solubility. Give Reason. |
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Answer» Because of the presence of common ion the solubility of the salt decreases. |
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| 35. |
Write the significance of henry law |
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Answer» The higher the value of Henry's law constant KH at a given pressure, the lower is the solubility of the gas in the liquid. Therefore, Henry's law constantly plays an important role in atmospheric chemistry, environmental chemistry and wastewater treatment plants. |
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| 36. |
Calculate solubility of silver oxalate in 10–2 M Potassium oxalate solution given that ksp of silver oxalate = 10–10 |
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Answer» [oxalate] = 10–2 + x, where x is the solubility of silver oxalate, this can be neglected in comparison to 10–2. so, ksp = 10–10 = 10–2 × (2x)2 => 10-8/2 x 2 = x2 ⇒ x = 5 × 10–5 |
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| 37. |
During conversion of glucose into glucose cyanohydrin, what functional group/atom of glucose is replaced?A. hydrogenB. aldehyde groupC. primary alocholic groupD. secondary alcoholic group |
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Answer» Correct Answer - B It is a characteristic reaction of aldehyde group. |
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| 38. |
Two volatile liquide A and B are mixed in mole ratio 1:3, to form an ideal liquid solution Vapour pressure of pure. A and B are 600 torr and 200 torr. Volume of container for vapour is 76 litre. `(R= 1//12" " "litre" " "atm//K//"mole")` The minimum number of distillation steps required, so that mole fraction of A become `0.9` in distillate.A. `1`B. `2`C. `3`D. `4` |
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Answer» Correct Answer - C `Y_(A_(1)) = 0.5 = X _(A_(2))` `Y_(A_(2)) = 0.5 xx 600 + 0.6 xx 200 = 400` torr `Y_(A_(2)) = (0.5xx600)/(400) = (3)/(4) = X_(A_(2))` ` Y_(A_(3)) = (3)/(4) xx 600 +(1)/(4) xx 200 = 500` torr ` Y_(A_(3))xx 500 = (3)/(4) xx 600 ` `Y_(A_(3)) xx (9)/(10) = X_(A_(4))` |
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| 39. |
Two volatile liquide A and B are mixed in mole ratio 1:3, to form an ideal liquid solution Vapour pressure of pure. A and B are 600 torr and 200 torr. Volume of container for vapour is 76 litre. `(R= 1//12" " "litre" " "atm//K//"mole")` Calculate the mole of A in vapour phase at 300 K, assuming negligible amount of vapour is present compared to liquid in containerA. `2` moleB. `0.3` moleC. `1.2` moleD. `0.6` mole |
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Answer» Correct Answer - D `P_(T) = 600xx(1)/(4)+200xx(3)/(4) = (1200)/(4) = 300` torr `n_(T)=((PV)/(RT)) = ((300)/(760)xx76)/((1)/(12)xx300) = 1.2`mole `Y_(A) = (P_(A)^(0)X_(A))/(P_(T)) = (600xx(1)/(4))/(300) = 0.5` `n_(A)` in vapour `= 0.5 xx 1.2 = 0.6` mole |
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| 40. |
What is difference between alkyl halide and allyl halide? |
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Answer» Allyl group contains sp3 hybridized allylic carbon atoms and sp2 hybridized vinyl carbon atoms. The allylic carbon atom is more reactive than normal alkanes. It can easily form a stable carbocation. An alkyl group is a molecule with the general formula CnH2n+1, where n is integer. |
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| 41. |
Which of the following proteins is globular?A. CollagenB. AlbaniumC. MyosinD. Fibroin |
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Answer» Correct Answer - B Aluminium is globular proteins |
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| 42. |
Diethyl amine when trated with nitrous acid yeildsA. Diethyl ammonium nitriteB. Ethyl alcoholC. N-nitroso diethyl amineD. Triethyl ammonium nitrite |
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Answer» Correct Answer - C `(C_(2)H_(5))_(2)NH + HONO overset(NaNO_(2) + HCl) underset("Cold") to underset("N-nitrosodiethyl amine")((C_(2)H_(5))_(2)N-N= O + H_(2)O)` |
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| 43. |
Match the atomic number 2,4,8,15, and 19 with each of the following:A solid non metal belonging to the third period. |
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Answer» A solid non metal belonging to the third period with atomic number of 15 is phosphorus with symbol P. A metal of valency 1 is potassium with symbol K. Its atomic number is 19 and is an alkali metal. A gaseous element with valency 2 is helium. Its symbol is He and atomic number is 2. It is an inert gas. An element belonging to Group 2 (alkaline earth metals) is beryllium (Be). It has atomic number of 4. A rare gas (or inert gas) is helium. Its symbol is He and atomic number is 2. Its valency is 2. |
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| 44. |
The replacement of diazonium group by fluorine is known asA. Gattermann reactionB. Sandmeyer reactionC. Balz-Schiemann reactionD. Etard reaction |
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Answer» Correct Answer - C It is known as Balz-Schiemann reaction. |
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| 45. |
Calculate ksp of Li3 Na3[AlF6]2. |
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Answer» ksp = 33 .33 .22 .(s)8 = 36 .4 (s)8 = 2916 s8 |
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| 46. |
Which of the following is the most stable diazonium salt?A. `C_(6)H_(5)CH_(2)N_(2)^(+)X^(-)`B. `CH_(3)N_(2)^(+) X^(-)`C. `CH_(3)CH_(2)N_(2)^(+)X^(-)`D. `C_(6)H_(5)N_(2)^(+)X^(-)` |
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Answer» Correct Answer - D Benzene diazonium salt is most stable due to resonance. |
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| 47. |
Which of the following compounds is most acidic in nature ?A. 4-chlorobutanoic acidB. 3-Chlorobutanoic acidC. 2-Chlorobutanoic acidD. Butanoic acid |
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Answer» Correct Answer - C Electron withdrawing groups increases the acidic strength of carboxylic acid, when electron withdrawing group goes away from 2-chlorobutanoic acid is more acidic. |
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| 48. |
A mixture of benzaldehyde and formaldehyde when treated with `50%` NaOH yields.A. Sodium benzoate and sodium formateB. Sodium formate and benzyl alcoholC. Sodium benzoate and methyl alcoholD. Benzyl alcohol and methyl alcohol |
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Answer» Correct Answer - B More reactive aldehyde undergoes oxidation to form sodium formate and benzyl alcohol, `H-CHO +C_(6)H_(5) -CHO + NaOH to H-COONa + C_(6)H_(5) -CH_(2)OH` Formaldehyde is more reactive than benzaldehyde. |
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| 49. |
What is a limiting reagent in a reaction? |
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Answer» The reactant which gets completely consumed or limits the amount of product formed in a reaction. |
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| 50. |
Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds? |
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Answer» Answer is (1) Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene C6H5NO2. because reaction with H2SO4, nitrobenzene can not give ammonia. Answer is (1) C6H5NO2 |
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