Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Consider the following system. Three different aqueous solution each having volume 100 ml are taken are kept in contact as shown. After sufficient time (Consider temp constant & 100% dissociation of strong electrolyte )A. Volume of urea solution will be `100/3` ml.B. Volume of `AlCl_3` solution will be `400/3` ml.C. There will be no change in volume of KCl solutionD. Volume of both KCl and `AlCl_2` solutions will increase.

Answer» Correct Answer - BC
After sufficient time osmotic pressure of all solution will become same.
as T is same i.e. molar concentration should be same, for this ratio of volume should be the same as that of ratio moles.
`{:("Urea",:,KCl,:,AlCl_3),(20 m "moles", " " ,30 m "moles", " " ,40 m "moles"):}`
Total volume (300 ml) should be divided in 2:3:4
`V_("urea")=2/9xx300=200/3 ml`
`V_(KCl)=3/9xx300=100 ml`
`V_(AlCl_3)=4/9xx300=400/3`ml
2.

In which of the following pairs of solutions will the values of the vant Hoff factor be the same?A. `0.05 M K_4[Fe(CN)_6] and 0.10 M FeSO_4`B. `0.10 M K_4[Fe(CN)_6] and 0.05 M FeSO_4(NH_4)_2SO_4. 6H_2O`C. 0.20 M NaCl and 0.10 M `BaCl_2`D. 0.05 M `FeSO_4(NH_(4))_(2)SO_4.6H_2O and 0.02 M KCl . MgCl_2. 6H_2O`

Answer» Correct Answer - BD
Number of particles from `K_4[Fe(CN)_6]=5`
number of particles from `FeSO_4(NH_4)_2SO_4. 6H_2O=5`
number of particles from KCl. `MgCl_2. 8H_2O=5`
3.

Which of the following compound is not an antacid.A. Aluminimum hydroxideB. PhenelzineC. CimetidineD. Ranitidine

Answer» Correct Answer - B
4.

The maximum number of electrons that can have principal quantum number n = 3 & spin quantum number `m_(s)=-(1)/(2)` is :-A. 9B. 18C. 32D. 6

Answer» Correct Answer - C
n = 3, then number of orbitals `= n^(2)= 9`
each obital has one electrons with m, `= -(1)/(2)`
5.

"Most of the ores of metals ore oxides and sulphides."Bauxite is the oxide ore of which metal ?

Answer»

Aluminium (Al).

6.

2.25 g of a Non volatile substance dissolved in 250 g of `C_6H_6`.This solution shows depression in F.P. by 0.256 K.Which of the following is/are correct : Given that : (`K_b` and `K_f` for `C_6H_6` is 2.53 `"Kmolal"^(-1)` and `5.12 "Kmolal"^(-1),BP` of `C_6H_6=353.3K`)A. Molar mass of substances is =180B. B.P. of solution is =180C. Relative lowering in vapour pressure of solvent =0.0038D. All are not correct

Answer» Correct Answer - ABC
`DeltaT_f=mxxK_f=(g.wt)/(M.M)xx1000/((g.wt.)_"solvent")xxK_f`
0.256=`2.25/(M.M)xx1000/250xx5.12`
M.M=180 g/mol
`DeltaT_b=mxxK_b=(g.wt)/(M.M)xx1000/((g.wt.)_"solvent")xxK_b =2.25/(180)xx1000/250xx2.53=0.1265`
B.P. of solution =353.3+0.1265=353.425 K
`(DeltaV.P.)/P_("solvent")^@=X_B=n_B/(n_A+n_B)=(2.25/180)/(2.25/180+250/75)=0.00388`.
7.

The ratio of energy of the electron in ground state of the hydrogen to electron in first excited state of `He^+` is.A. `1:4`B. `1:1`C. `1:8`D. `1:16`

Answer» Correct Answer - B
`(E_(He)^(+))_(2)=(E_(H))_(I)xx2^(2)((1)/(2^(2)))=(E_(H))_(I)`
8.

`{:(,"Column-I",,"Column-II"),((A),"Insoluble in "H_(2)O,,(P)" ""Whit phosphorous"),((B),"Insoluble in "CS_(2),,(Q)" ""Red phosphorous"),((C),"Soluble in "H_(2)O,,(R)" ""Rhombic sulphur"),((D),"Soluble in " CS_(2),,(S)" "Br_(2)),(,,,(T)" "I_(2)):}`

Answer» Correct Answer - `ArarrP,Q,R,T;BrarrQ;CrarrS;DrarrP,R,S,T`
9.

The solubility product of silver chloride is `625xx10^(-10)" at "25^(@)C`. Find its solubility in `gL^(-1)`A. `35.87xx10^(-3)`B. `3.587xx10^(-3)`C. `35.87xx10^(-2)`D. `3.587xx10^(-5)`

Answer» Correct Answer - B
10.

A : CH4, C2H6, C3H8 .......... is a homologous series. R : A homologous series of carbon compounds in which two successive compounds differ by – CH unit. (a) A and R are true ; R is correct explanation to A (b) A and R are true ; R is not correct explanation to A (c) A is true, R is false

Answer»

(c) A is true, R is false

11.

The percentage degree of hydrolysis of a salt of weak acid (HA) and weak base (BOH) in its 0.1 M solution is found to be `10%.` If the molarity of the solution is 0.05 M, the percentage hydrolysis of the salt should be :A. `5%`B. `10%`C. `20%`D. None of these

Answer» Correct Answer - B
Degree of hydrolysis for WA - WB (h)
`= sqrt((K_(w))/(K_(a)xxK_(b)))`
does not depend on the concentration of salt So h will be the same.
12.

3.1 mole of `FeCl_(3)` and 3.2 mole of `NH_(4)SCN` are added to one litre of water. At equilibrium, 3.0 mol of `FeSCN^(2+)` are formed. The equilibrium constant `K_(c)` of the reaction : `Fe^(3+)+SCN^(-)iffFeSCN^(2+)` will be :A. `6.66 xx 10^(-3)`B. 0.3C. 3.3D. 150

Answer» Correct Answer - B
13.

Write name of the hormone secreted by thyroid gland. 

Answer»

Hormone secreted by thyroid gland is thyroxine

14.

If the molar concentration of `SnCl_(4)` is `1.5 xx 10^( –3)" mol L"^( –1)` , the concentration of chloride ions in g ion` L^( –1)` is :-A. `3.0xx10^(-3)`B. `6.0xx10^(-3)`C. `0.3xx10^(-3)`D. `0.6xx10^(-6)`

Answer» Correct Answer - B
`SnCl_(4(aq)) rArr Sn_((aq))^(+4)+4Cl_((aq))^(-)`
`[Cl^(-)]=4xx[SnCl_(4)]`
`=4xx1.5xx10^(-3)`
`=6xx10^(-3)"g ion L"^(-1)`
15.

3.1 mol `Fe^(3+)` and 3.2 mol `"SCN"^(Theta)` present in 1 L solution. At equilibrium 3 mol `FeSCN^(2+)` are formed The equilibrium constant `K_(c)` for the reaction `Fe^(3+)+SCN^(Theta)hArrFeSCN^(2+)` willA. 150B. 400C. 300D. 250

Answer» Correct Answer - A
`underset(3.1)(Fe^(3+))+underset(3.2)(SCN^(Theta)) hArr FeSCN^(2+)`

`3.1-1" "3.2-x" "x=3`
`3.1-3=3.2-3`
`=0.1=0.2`
`K_(C)=(3)/(0.1xx0.2)=(300)/(2)=150`
16.

If the concentration of` Y ^(-)` ion in the reaction `XY_(3(s)) hArr X_(aq)^(+3)+3Y^(-)(aq)` is decreased by `(1)/(2)` times, then equilibrium `conc^(n)` of `X^(+3)` will increase by :-A. 2 timesB. 4 timesC. 8 timesD. 16 times

Answer» Correct Answer - C
`K_(C)=[X^(+3)][Y^(-3)]` ....(1)
`K_(C)=[X^(+3)]{(1)/(2)[Y^(-)]}^(3)` ....(2)
(1)=(2)
`(1)/(8)[X^(+3)]^(1)=[X^(+3)]`
`[X^(+3)]^(1)=8[X^(+3)]`
17.

Given the reaction between 3 gases represented `X_(2),Y_(2),Z_(2)` to give the compound `XYZ_((g))` `X_(2(g))+Y_(2(g))+Z_(2(g))hArr 2XYZ_((g))` At equilibrium concentration of `X_(2)=3M, Y_(2)=6M, Z_(2)=9MXYZ=6M` If the reaction takes place in a sealed vessel at `527^(@)C`, then the value of`K_(C)` will be :A. `(27)/(2)`B. `(2)/(9)`C. 36D. 24

Answer» Correct Answer - B
`K_(C)=((6)^(2))/(3xx6xx9)=(6)/(27)=(2)/(9)`
18.

Given the reaction` b//w` 3 gases represented `X_(2),Y_(2),Z_(2) ` to give the compound `XYZ_(g)` `X_(2(g))+Y_(2(g))+Z_(2(g)) hArr 2_(g)` At equilibrium `conc^(n)` of `X_(2)=3M,Y_(2)=6M,Z_(2)`=9M `XYZ=6M` If the reaction take place in a sealed vessel at `527^(@)C`, then the value of `K_(C)` will be :-A. `(27)/(2)`B. `(2)/(9)`C. 36D. 24

Answer» Correct Answer - B
`K_(C)=(6)^(2)/(3xx6xx9)=(2)/(9)`
19.

The equilibrium constant `K_(c)` for the following reaction at `842^(@)`C is `7.90xx10^(-3)`. What is `K_(p)`at same temperature ?` (1)/(2)F_(2(g)) hArr F_(g)`A. `8.64xx10^(5)`B. `8.26xx10^(-4)`C. `7.90xx10^(-2)`D. `7.56xx10^(-2)`

Answer» Correct Answer - D
`K_(P)=(7.9xx10^(-3))xx(0.0821xx115)^(0.5)`
`K_(P)=7.56xx10^(-2)`
20.

Agaseous maxture was prepared by taking 3 mol of `H_(2)` and 1 mol of CO. If the total pressure of the mixture was found 2 atmosphere then partial pressure of hydrogen `(H_(2))` in the mixture is :-A. `(3)/(2)`B. `(1)/(2)`C. 1D. 2

Answer» Correct Answer - A
`P_(H2)=(3)/(4)xx2=(3)/(2)atm`
21.

The valve of `K_(c)` at 900 K temp for following reaction is 5 `N_(2(g))+O_(2(g)) hArr 2NO_((g))` if equilibrium `conc^(n)` of `N_(2)` and `O_(2)` is 0.5M then value of `K_(p)` is :-A. 0.02B. 0.2C. 5D. `(5)/(RT)`

Answer» Correct Answer - C
`K_(p)=K_(c)(RT)^(Deltang)," " because Deltang=0`
`K_(p)=5`
22.

A `8gm` sample of iron are containing `V%` (by wt) of iron `(Fe^(2+))` was present in `1L` solution. This solution required `V` ml of a `KMnO_(4)` solution for oxidation of `Fe^(2+)` in acidic medium. If in another titration `20ml` of same `KMnO_(4)` is required, for oxidaton of `20ml` of `H_(2)O_(2)` in acidic medium. Find volume strength of `H_(2)O_(2)`

Answer» Correct Answer - 8
Meq. of `Fe^(2+)=` meq of `KMnO_(4)=(8xxVxx1xx1000)/(100xx56)=N_(KMnO_(4))` is same in both
Meq of `KMnO_(4)=` meq of `H_(2)O_(2)`
`20xx 8/5.6=20xxN=20xxX("vol. strength")/5.6`
so vol stre. of ` H_(2)O_(2)=8`
23.

`H_(2)O_(2)to H_(2)O+O_(2)` the rate most of this reaction is `2xx10^(-2)"min"^(-1)` (at certain temp.) & reaction is started with`0.5M` conc. of `H_(2)O_(2)`, after 23.03 min the reaction was suddenly stopped by lowering the temp & the remaining `H_(2)O_(2)` was completely reacted with `NaCl`. If no. of moles of `O_(2)` produced in second reaction is `1/a` find `a. (log1.5=0.2)`

Answer» Correct Answer - 3
`H_(2)O_(2)to H_(2)O+O_(2)`
`NaOCl+H_(2)O_(2)to O_(2)+NaCl+H_(2)O`
In 1 min 0.02 mol/lt `H_(2)O_(2)` decomposes so in 20 min
`k=(2.303)/t "log" a/(a-x)`
`0.02="log" 0.5/(a-x)` (take `log 1.5=0.2)`
`1.5=0.5/(a-x)`
`a-x=0.5/1.5=1/3`
`1/3` mole `H_(2)O_(2)` is left so `1/3` mole `O_(2)` is produced in second reaction.
24.

For a positively charged particle moving in a x-y plane initially along the x-axis, there is a sudden change in its path due to the presence of electric and/or magnetic fields beyond P. The curved path is shown in the x-y plane and is found to be non-circular.Which one of the following combinations is possible?(a) E = 0; B =bi + ck  (b) E = ai; B =ck + ai  (c) E = 0; B =cj + bk(d) E = ai; B =ck + bj 

Answer»

As the curved path is confined to the XY plane,  the component of magnetic field effective in  deflecting the particle is the Z-component only.  The other component should be the X-component since the X-component cannot deflect the charged particle proceeding along the X-direction. There has to be an electric field since the path of the particle is non-circular. All these conditions are satisfied by option (b).

25.

An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR. The magnetic field strength due to this current at the point M is H1. Now, another infinitely long straight conductor QS is connected at Q so that the current is I/2 in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field strength at M is now H2. The ratio H1/H2 is given by(a) 1/2 (b) 1 (c) 2/3 (d) 2 

Answer»

Correct Answer is: (c) 2/3

The magnetic field strength at M due to QR is zero in all cases.

When QS carries I/2 current, the field strength at M due to QS is H1/2. Then

H2 = H1 + H1/2 = 3H1/2

or H1/H2 = 2/3.

26.

A string of length 2m is fixed at two ends. it is in resonance with a tuning fork of frequency 240Hz in its third harmonic. Then speed of wave sound in string and its fundamental frequency is:(1) 240m/s, 80Hz(2) 320m/s, 80Hz(3) 640m/s, 80Hz(4) 120m/s, 40Hz

Answer»

The correct option (2) 320m/s, 80Hz   

Explanation:

f3 = 3V/2L = 240

(3 x V)/(2 x 2) = 240

V = 320m/s

 f0 = V/2L = 320/(2 x 2) = 80Hz

27.

Barium ions, `CN^(-) and Co^(2+)` form an ionic complex.If this complex is 75% ionised in aqueous solution with Vant Hoff factor (i) equal to four and paramagnetic moment is found to be 1.73 BM (due to spin only) then the hybridisation state of Co (II) in the complex will be :A. `sp^3d`B. `d^2sp^3`C. `sp^3d^2`D. `dsp^3`

Answer» Correct Answer - D
`{:(Ba_(alpha-2)[Co(CN)_x]_2 to,(x-2) Ba^(2+),+2[Co(CN)_x]^(-(x-2))),(1-alpha,(x-2)alpha, " " 2alpha):}`
`i=1-alpha+xalpha-2alpha+2alpha`
`(x-1)alpha=3 " " x-1=3/alpha`
`alpha=0.75 , " " x=5`
`:.` formula of complex is `Ba_3[Co(CN)_5]_2` and hybridisation is `dsp^3` as it is a inner orbital complex with strong field ligand
28.

An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR The magnetic field due to this current at the point M is H1. Now another infinitely long straight conductor QS is connected at Q so that the current is I/2 in QR as well as in QS, The current in PQ remaining unchanged. The magnetic field at M is now H2.The ratio H1/H2 is given byA) 12  B)  1  C)  23  D)  2

Answer»

Correct Answer: C  

Explanation : Magnetic field at any point lying on the current carrying straight conductor is zero. 

Here H1 = Magnetic field at M due to current in PQ.         

H2 = Magnetic field at M due to QR + magnetic field at M due to QS + magnetic field at M due to PQ =0+H1/2+H1= 3/2 H1 

H1/H2 = 2/3

29.

An ionized gas contains both positive and negative ions. If it is subjected simultaneously to an electric field along the +x direction and a magnetic field along the +z direction, thenA) Positive ions deflect towards +y direction and negative ions towards -y directionB) All ions deflect towards +y directionC) All ions deflect towards -y directionD) Positive ions deflect towards -y direction and negative ions towards +y direction

Answer»

Correct Answer: C) All ions deflect towards -y direction

Exaplanation :

As the electric field is switched on, positive ion will start to move along positive x-direction and negative ion along negative x-direction. Current associated with motion of both types of ions is along positive x-direction. According to Fleming's left hand rule force on both types of ions will be along negative y-direction.

30.

A hollow cylinder having infinite length and carrying uniform current per unit length lambda along the circumference. Magnetic field inside the cylinder is:

Answer»

Magnetic field inside the cylinder is λμ•

Explanation:

As there is given that current is flowing along its circumference. 

So we already know that inside the cylinder the magnetic field will be μ•/4π (2I'/r'), where I' is the current flowing and r' is the distance from the centre.

λ is the current per unit length so, λ = I/2πr ⇒ I = λ2πr 

Current inside the cylinder at r' distance from the centre is I' = λ2πr'

Now we put the value in the equation.
B(inside) = μ•/4π (2I'/r') = μ•/4π (2 x λ x 2πr'/r')λμ•

31.

please solve it

Answer» 12 ohm is the answer
32.

Which of the graphs shown below does not represent the relationship between incident light and the electron ejected from metal surface ?

Answer»

Correct option: (3)

Explanation:

(i) No. of e doesn't depend on v

(ii) KE of e doesn't depend on light intensity 

(iii) hv = W + KE 

(iv) E = W + KE

33.

Panchayati Raj was introduced in the country in(a) 1957(b) 1952(c) 1951(d) 1959

Answer»

Panchayati Raj was introduced in the country in 1959

34.

Panchayati Raj was first introduced in(a) Andhra Pradesh(b) Bihar(c) Rajasthan(d) Gujarat

Answer»

Panchayati Raj was first introduced in Rajasthan

35.

A 2 W carbon resistor is color coded with green, block, red and brown respectively. The maximum current which can be passed through this resistor is : (1) 20 mA (2) 100 mA (3) 0.4 mA (4) 63 mA

Answer»

Correct option: (1) 20 mA

Explanation:

According to color code

R = 50 × 102 ohm

i2R = 2 watt

i = 20 mA

36.

By Convention, who of the following is the Chairman of Press Council of India?(a) An eminent journalist of India (b) A senior Civil Services Officer (c) A retired Judge of the Supreme Court of India (d) The Union Minister of Information arid Broadcasting

Answer»

(c) A retired Judge of the Supreme Court of India

37.

A carbon resistance with color band is 200Ω. If red band is replaced by green band then the new resistance is :(1) 500Ω (2) 300Ω(3) 400Ω(4) 100Ω

Answer»

Correct option: (1) 500Ω

Explanation:

Significant figure of red band is 2

and for green is 5

So new resistance 500 Ω

38.

An ice cube of edge 1cm melts in a gravity free container.what is the approximate surface area osf water formed?

Answer»

Since ice is in gravity free space, thus after melting it forms a sphere. Area of ice cube= area of sphere1 cm3 

=4/3πr3

=> r=(3/4π)1/3

Now, surfacr area is given byS.A.= 4πr2 

=4π(3/4π)2/3 

=(9π)1/3

39.

Playing time for full version of National Anthem is1. 20 seconds2. 52 seconds 3. 34 seconds 4. 45 seconds

Answer» Correct Answer - Option 2 : 52 seconds 

The correct answer is 52 seconds. 

  • Our National Anthem is Jana Gana Mana, it approximately takes 52 seconds for the full version.
  • It was composed originally in Bengali by Rabindranath Tagore.
  • It was adopted in its Hindi version by the Constituent Assembly as the National Anthem of our country on 24 January 1950.

  • It was sung for the first time in the Calcutta Session of the Indian National Congress on 27 December 1911.
  • It comprises of 5 Stanzas.
40.

The advantages of connecting devices in parallel. Write them down.

Answer»
  • Devices work according to the marked power.
  • Devices can be controlled using switches as per need.
  • The bulbs will get the required voltage.
41.

Observe and record the meter reading in your house for 10 consecutive days. Based on this, find out the average consumption per day. Find out methods to reduce consumption and record them. Present your findings in the Energy Club.

Answer»

Average usage = \(\cfrac{Total\,usage}{no.\,of\,days}\)

Methods to reduce the usage of electricity.

  • Use devices of good efficiency.
  • Use electricity only when required.
  • Reduce cooking using electricity.
  • Reduce the use of air conditioners and refrigerators.
42.

In a house, 5 CF lamps each of 20 W, works for 4hours, 4 fans each of 60 W work for 5 hours and a TV of 100 W works for 4 hours in a day. What will be the daily consumption shown by the watt-hour meter?

Answer»

4 hour’s consumption of 5 CFL having 20 W.

\(\cfrac{5 \times 20\, \times\, 4}{1000}= 0.4\) kWh

5 hour’s consumption of 4 Fan having 60 W

\(\cfrac{4 \times 60\, \times\, 5}{1000}= 1.2\) kWh

4 hour’s consumption of one T.V having 100 W

\(\cfrac{1 \times 100\, \times\, 4}{1000}= 0.4\) kWh

Total unit = 2 kWh

43.

1. Which are the circumstances that lead to the flow of excess current in a house hold circuit?2. What happens to the circuit when there is an excess current in a circuit?3. How does a safety fuse protect a circuit?

Answer»

1. Over loading or Short circuit.

2. More heat is generated. So appliances and circuit will get damaged.

3. The current in the circuit may increase due to reasons such as short circuit, overload, excess flow of current or any problems in the insulation. As the higher temperature produced in the circuit due to these reasons makes the fuse wire to melt and the flow of current stops. Thus the circuit and the appliances are protected.

44.

What are the differences between ordinary fuse and MCB?

Answer»

Ordinary fuse works making use of heating effect of electricity while MCB works making use of heating and magnetic effects of electricity. The current in the circuit may increase due to reasons such as short circuit, overload, excess flow of current or any problems in the insulation.

As the higher temperature produced in the circuit due to these reasons makes the fuse wire to melt and the flow of current stops. Thus the circuit and the appliances are protected. MCB automatically breaks the circuit whenever there is an excess flow of current due to short circuit or overloading. After rectifying the circuit we can switch on the MCB and make the circuit as it was.

45.

A freshly prepared radioactive source of half-life `2 h` emits radiation of intensity which is 64 times the permissible safe level. The minimum time after which it would be possible to work safely with this source isA. `12 h`B. `24 h`C. `6 h`D. `130 h`

Answer» Correct Answer - a
For working safely, the activity must reduce to `(1)/(64)`
`(N)/(N_(0))=((1)/(2))^(n)=(1)/(64)`
`n=6`
`t= nt=6 xx 2= 12H`
46.

Define ‘Electric dipole’

Answer»

Two equal and opposite charges separated by a small distance constitute an electric dipole.

47.

The materials used in Robotics are……(a) Aluminium and silver (b) Silver and gold (c) Copper and gold (d) Steel and aluminium

Answer»

(d) Steel and aluminium

48.

What is the general definition of electric dipole moment?

Answer»

The electric dipole moment vector lies along the line joining two charges and is directed from  – q to +q. The SI unit of dipole moment is coulomb meter (cm).

\(\vec p\) = qa\(\hat i\) - qa(-\(\hat i\)) = 2qa \(\hat i\)

49.

What is the role of the two conducting stationary brushes in a simple electric motor?

Answer» The brushes are connected to the battery and touch the outer side of two halves of the split ring whose inner sides are insulated and attached to the axle.
50.

Who is the father of the modem robotics industry formed the world’s first robotic company in 1956? (a) Joliot(b) Cormark (c) Engelberger (d) Edward purcell

Answer»

(c) Engelberger