This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Explain the following banking terms: a. Electronic Fund Transfer b. RTGS c. E-Commerce d. NRE account |
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Answer» ELECTRONIC FUND TRANSFER: It facilitates automatic transmission and processing of messages as well as funds from one bank to another bank. RTGS : Real Time Gross Settlement is an electronic form of funds transfer where the transmission takes place on real time basis. The minimum amount of fund transfer in India is Rs. 2 lakhs. E-commerce: Electronic Commerce is the paperless commerce where the exchange of business takes place in electronic means. NRE Account: Non-Resident External account can be opened by any person who is residing outside India. NRIs having this account in India are permitted to hold and maintain foreign currency earnings in Indian Rupees. |
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| 2. |
A converging lens of focal length 20 cm and diameter 5 cm is cut along the line AB . The part of the lens shown shaded in the diagram is now used to form an image of a point P placed 30 cm away from it on the line XY which is perpendicular to the plane of the lens. The image of P will be formed. A. `0.5mm` above `XY`B. `1mm` above `XY`C. on `XY`D. `1.5 mm` below `XY` |
| Answer» The optic axis of a lens does not change even on cutting it. | |
| 3. |
Write the difference between Horizontal Filing and Vertical Filing |
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| 4. |
The diagram shows the basic setup for the production of X-rays. A1 and A2 are two ammeters, reading 2.55 A and 2.566 A respectively. F is a filament which is also the cathode. The potential difference applied between P and Q is 50 000 V. Assume that all X-ray photons have the maximum possible energy and that one X-ray photon is emitted for every 100 electrons incident on the target. You may assume that the kinetic energy of the other electrons reappear as heat in the tube.The rate at which heat is produced in the X-ray tube is approximately (a) 10 W (b) 40 W (c) 200 W (d) 800 W |
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Answer» Correct Answer is:(d) 800 W |
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| 5. |
The diagram shows the basic setup for the production of X-rays. A1 and A2 are two ammeters, reading 2.55 A and 2.566 A respectively. F is a filament which is also the cathode. The potential difference applied between P and Q is 50 000 V. Assume that all X-ray photons have the maximum possible energy and that one X-ray photon is emitted for every 100 electrons incident on the target. You may assume that the kinetic energy of the other electrons reappear as heat in the tube.The momentum of each X-ray photon is approximately (a) 3 x 10-17 kg m s-1 (b) 3 x 10-20 kg m s-1 (c) 3 x 10-23 kg m s-1 (d) 3 x 10-26 kg m s-1 |
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Answer» Correct Answer is:(c) 3 x 10-23 kg m s-1 |
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| 6. |
The diagram shows the basic setup for the production of X-rays. A1 and A2 are two ammeters, reading 2.55 A and 2.566 A respectively. F is a filament which is also the cathode. The potential difference applied between P and Q is 50 000 V. Assume that all X-ray photons have the maximum possible energy and that one X-ray photon is emitted for every 100 electrons incident on the target. You may assume that the kinetic energy of the other electrons reappear as heat in the tube.The number of X-ray photons produced per second is approximately (a) 1012 (b) 1015 (c) 1018 (d) 1021 |
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Answer» Correct Answer is: (b) 1015 |
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| 7. |
The diagram shows the basic setup for the production of X-rays. `A_(1)` and `A_(2)` are two ammeters, reading `2.55A` and `2.566A` respectively. F is a filament which is alos the cathode. The potential difference applied between P and Q is `50000 V`. Assume that all X-rays photons have the maximum possible energy and that one X-ray photon is emitted for every `100` electron incident on the target. You may assume that the kinetic energy of other electrons reappear as heat in the tube. The momentum of each X-ray photon is approximatelyA. `3 xx 10^(-17) kg ms^(-1)`B. `3 xx 10^(-20) kg ms^(-1)`C. `3 xx 10^(-23) kg ms^(-1)`D. `3 xx 10^(-26) kg ms^(-1)` |
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Answer» Correct Answer - C |
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| 8. |
The diagram shows the basic setup for the production of X-rays. `A_(1)` and `A_(2)` are two ammeters, reading `2.55A` and `2.566A` respectively. F is a filament which is alos the cathode. The potential difference applied between P and Q is `50000 V`. Assume that all X-rays photons have the maximum possible energy and that one X-ray photon is emitted for every `100` electron incident on the target. You may assume that the kinetic energy of other electrons reappear as heat in the tube. The rate at which heat is produced in the X-ray tube is approximatelyA. `10W`B. `40W`C. `200 W`D. `800W` |
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Answer» Correct Answer - D |
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| 9. |
The diagram shows the basic setup for the production of X-rays. `A_(1)` and `A_(2)` are two ammeters, reading `2.55A` and `2.566A` respectively. F is a filament which is alos the cathode. The potential difference applied between P and Q is `50000 V`. Assume that all X-rays photons have the maximum possible energy and that one X-ray photon is emitted for every `100` electron incident on the target. You may assume that the kinetic energy of other electrons reappear as heat in the tube. The number of X-ray photons produced per second is approximatelyA. `10^(12)`B. `10^(15)`C. `10^(18)`D. `10^(21)` |
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Answer» Correct Answer - B |
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| 10. |
hcho+?=ch3ch2oh |
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Answer» The reagent used in the reduction of Formaldehyde to alcohol is CH3MgBr. Mechanism: Thus we get CH3CH2OH |
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| 11. |
For a reaction A(g) ⇋ B(g) if initial pressure at 300oC is 1 atm and its Kp is 4, Then calculate PB at equilibrium state. |
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Answer» Given, T = 300oC PA = 1 atm Kp = 4 The reaction is A(g) ⇋ B(g) Kp = [PB]/[PA] ---> [PB] = Kp x [PA] = 4 x 1 atm = 4 atm Total pressure = 4 atm + 1 atm = 5 atm PB 1 atm x 4/5 = 4/5 atm |
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| 12. |
In which of the following process maximum amount of energy is released.A. `A(s) rarr A^(-)(g)`B. `A(g)rarrA^(-)(g)`C. `A(s)rarrA^(-)(aq)`D. `A^(+)(g)rarrA^(-)(aq)` |
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Answer» Correct Answer - D `(A) A(s)overset(+S.E.)rarrA(g)overset(-E.G.E.)rarrA^(-)g` `(B) A(g)overset(-E.G.E.)rarrA^(-)(g)` `(C )A(s)overset(+S.E.)rarrA(g)overset(-E.G.E)rarrA^(-)(g)overset(-H.E.)rarrA^(-)(aq)` `(D) A^(+)(g)overset(-E.G.E.)rarrA(g)overset(-E.G.E.)rarrA^(-)(g)overset(-H.E.)rarrA^(-)(aq)` |
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| 13. |
`A+Biff2C, K_(C)=0.25` Initially 1 mol A, 1 mol B and 1 and C is taken in a 10 litre flask. What will be the equilibrium concentration of C ?A. 0.6 MB. 0.2 MC. 1.2 MD. 0.4 M |
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Answer» Correct Answer - A `"A + B "iff" 2C`" `"1 1 1 "Q_(C )=1gtK_(C )`, `1+(x)/(2)" "1+(x)/(2)" "(1-x)` `((1-x)^(2))/((1+(x)/(2))^(2))=(1)/(4)implies (1-x)/(1+(x)/(2))=(1)/(2),2-2x=1+(x)/(2),1=(5x)/(2),x=(2)/(5)=0.4 .[C]=1-0.4=0.6` |
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| 14. |
Find the more stable `C^(oplus)`?A. B. C. |
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Answer» Correct Answer - A (A) Resonance + 5 `alpha-h` (B) No resonance (C ) only resonance (D) Resonance + `2alpha-H` |
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| 15. |
The period number and group number of element having atomic number 50 are respectively :A. `6^(th), 12^(th)`B. `5^(th), 15^(th)`C. `6^(th), 14^(th)`D. `5^(th), 14^(th)` |
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Answer» Correct Answer - D `Z=50=[Kr] 4d^(10)5s^(2)5p^(2)` Period no. = 5 Group no. = 14 |
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| 16. |
A liquid phase reaction occurring in a CSTR follows first order dynamics. The feed rate is 500m^3/min. Initial concentration of the feed is 50mol/m^3. If the reaction conversion is 50% and the reaction is carried out in a 0.5 m^3 CSTR, what is the value of rate constant?(a) 40(b) 20(c) 10(d) 5 |
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Answer» The correct answer is (b) 20 Explanation: FA0 XA = (-rA)V (-rA) = kCA0(1 – XA) 500 × 0.5 = k × 50 × (1-0.5) × 0.5 k = 20. |
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| 17. |
Densities of diamond and graphite are `3.5` and `2.3 g mL^(-1)`, respectively. The increase of pressure on the equilibrium `C_("diamond") hArr C_("graphite")`A. favours backward reactionB. favours forward reactionC. has no effectD. increase the reaction rate |
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Answer» Correct Answer - A On increasing pressure equilibrium shifted in the direction of lesser volume. `V_("diamond")ltV_("graphite")` |
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| 18. |
If a ray is refracted to denser medium then(a) Speed, wavelength and frequency remains constant(b) Speed and wavelength decreases, frequency constant(c) Speed, wavelength and frequency increases(d) Speed, wavelength and frequency decreases |
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Answer» (b) Speed and wavelength decreases, frequency constant When a ray goes from rarer medium to denser medium then its speed and wavelength decreases but frequency always remains constant. So correct answer is (B). CORRECT OPTION WILL BE B |
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| 19. |
Sodium metal on dissolution in liquid ammonia gives a deep blue solution due to the formation of (1) Sodium-ammonia complex (2) Sodium ion-ammonia complex (3) Ammoniated electrons (4) Sodamide |
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Answer» The correct option is (3) Ammoniated electrons. Explanation: Sodium metal dissolve in liquid ammonia giving deep blue solutions which are conducting in nature. Na + (x + y) NH3 ---> [Na(NH3)x ]+ + [e(NH3) y ] – Blue colour of the solution is due to ammoniated electron. |
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| 20. |
A stone is dropped from 4.9 m above water level. It entered with velocity v and then continue at constant velocity v. It took 4 seconds from throw to reach ground. Find depth of water. (a) 20.4 m (b) 29.4 m (c) 2.94 m(d) 19.4 m |
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Answer» Correct option is (b) 29.4 m Velocity after falling through a height of 4.9 m v2 - u2 = 2as v2 - 0 = 2(9.8) (4.9) v = 9.8 m/s Time taken to fall by 4.9 m 9.8 = 0 + 9.8t ⇒ t = 1 sec Rest of 3 sec it went inside water with constant speed 9.8 m/s ∴ Depth of water 9.8 x 3 = 29.4 cm |
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| 21. |
For the dissociation of `NH_(3)(g)` as `2NH_(3)(g)iffN_(2)(g)+3H_(2)(g)`, the variation of `(1 + alpha)` against `((D)/(d))` is represented as : (Given : D = initial vapour density of `PCl_(5)`, d = Vapour density of mixture at equilibriu,):A. B. C. D. |
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Answer» Correct Answer - A `2NH_(3)(g) iff N_(2) (g) + 3H_(2)(g)` `alpha=(D-d)/((n-1)d) " "because n = 2` `therefore 1 + alpha = ((D)/(d))` `therefore y = x` |
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| 22. |
The indicated carbanion is most stable when R is : A. `-NO_(3)`B. `-CH_(3)`C. D. |
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Answer» Correct Answer - A `-NO_(2)` shows -M effect. |
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| 23. |
The indicated carbanion is most stable when R is : A. `-NO_(3)`B. `-CH_(3)`C. D. |
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Answer» Correct Answer - A `-NO_(2)` shows -M effect. |
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| 24. |
The energy level for `He^(+)` ion atom depends on :A. Principal Quantum NumberB. Azimuthal Quantum NumberC. Both (A) and (B)D. Magnetic Quantum Number |
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Answer» Correct Answer - A Energy level for a single electron depends only on principal quantum number. |
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| 25. |
We do not transmit low frequency signal to long distances because (a) The size of the antenna should be comparable to signal wavelength which is unreal solution for a signal of longer wavelength. (b) Effective power radiated by a long wavelength baseband signal would be high. (c) We want to avoid mixing up signals transmitted by different transmitter simultaneously.(d) Low frequency signal can be sent to long distances by superimposing with a high frequency wave as wellTherefore, the most suitable options will be : (A) All statements are true (B) (a), (b) and (c) are true only (C) (a), (c) and (d) are true only(D) (b), (c) and (d) are true only |
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Answer» (C) (a), (c) and (d) are true only (a) For low frequency or high wavelength size of antenna required is high. (b) E P R is low for longer wavelength. (c) yes we want to avoid mixing up signals transmitted by different transmitter simultaneously. (d) Low frequency signals sent to long distance by superimposing with high frequency. |
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| 26. |
Consider the following equilibrium reaction at T K in a 1L flask. (I) `A(g)iffB(g)+C(g), K_(C_(1))=3` (II) `B(g)iff D(g)+C(g), K_(C_(2))=?` If initially 2 moles of A(g) are taken and allowed attain equilibrium, concentration of C(g) was formed to be 3M. What is the value of `K_(C )` of second reaction ?A. `(200)/(3)`B. `(266)/(9)`C. 12D. `(3)/(200)` |
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Answer» Correct Answer - C `" "A(g) iff B(g) + C(g), K_(C_(1)) = 3` At equilibrium mole `" "2-x " (x-y) (x+y)"` `" "B(g) iff D(g) + C(g), K_(C_(2)) = ?` At equilibrium mole `" "(x-y) " y (x+y)"` `K_(C_(1)) = 3 = ((x-y)(x+y))/(2-x)" ".....(1)` `K_(C_(2)) = (y(x+y))/(x-y) " ".....(2)` `x + y = 3 " "....(3)` 2 - x = x - y 2 = 2x - y x + y = 3 `x = 5//3, y = 3 - (5)/(3) = (4)/(3)` `K_(C_(2)) = ((4//3)(3))/((5//3-4//3)))=12` |
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| 27. |
The pKa of weak acid is 4.3. 600 ml of 0.1 M weak acid HA is added to 250 ml of 0.2 M NaOH. The pOH of resulting solution is : (log5 = 0.7) |
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Answer» Correct Answer - 7 The E.C. of element = [Ar] `3d^(5)4s^(2)`, Group = `7^(th)` |
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| 28. |
How many geometrical isomers are possible for following compound |
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Answer» Correct Answer - 9 HA(aq) `" + NaOH(aq) "rarr NaA(aq) + H_(2)O(l)` 60 millimoles 50 millimoles `" - "` `" 10 0 50"` `pH=pKa+log.(50)/(10)` pH = 4.3 + 0.7 = 5 , pOH = 14-5 = 9 |
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| 29. |
A stationary observer receives a sound from a source of frequency `2000Hz` moving with constant velocity. The apparent frequency varies with as shown in the figure The value of `f_(m)` is `(2300-10x)Hz`. Find the value of `x`. (Take speed of sound `=30m//s` and neglect the time taken by sound to reach the stationary observer). |
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Answer» `t_(m)=(v)/((v-v_(s)costheta)_("min"))xxf` `1800=(v)/((v+v_(s)costheta)_("min"))xxf` On solving `f_(m)=2250 Hz` `=2300-50` |
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| 30. |
If ratio of area enclosed in `6^(th)` orbit in H atom to 2nd orbit in `Li^(+2)` ion is `3^(x)` then find the value of x ? |
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Answer» Correct Answer - 1 `2C(s)+O_(2)(g)iff2CO(g),K_(2)` `CO_(2)(g)iffC(s)+O_(2)(g),1//K_(1)` `C(s)+CO_(2)(g)iff2CO(g),K_(3)` `K_(3)=(K_(2))/(K_(1))=(10^(-3))/(10^(-2))=10^(-1)` `C(s)+O_(2)(g)iffCO_(2)(g), K_(1)` `2CO(g)iffC(s)+CO_(2)(g)" "1//K_(3)` `2CO(g)+O_(2)(g)iff2CO_(2)(g), K_(4)` `K_(4)=(K_(1))/(K_(3))=(10^(-2))/(10^(-1))=10^(-1)` `(x)/(y)=1` |
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| 31. |
, Number of deutrium exchanged with hydrogen |
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Answer» Correct Answer - 5 Si, Se, Ba, Sn, Ga |
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| 32. |
The total number sets in which first species is more acidic than second species. `(i) (CO_(2), CO) (ii) (Al (OH)_(3), Li_(2)O) (iii) (N_(2)O_(3), P_(2)O_(3)) (iv) (CO_(2), N_(2)O_(5))(v) (N_(2)O, N_(2)O_(3))(vi)(SO_(2), SO_(3))` |
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Answer» Correct Answer - 4 a,b,c,e |
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| 33. |
In an isobaric process (`lambda` is adiabatic exponent of the gas)A. The heat given to gas is `(lambda)/(lambda-1)` times the work done by gas.B. The work done by gas is `(lambda-1)` time the change in internal energy.C. The temperature of gas in increased.D. The temperature of gas is decreased. |
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Answer» At constant pressure. If volume increases. Temperature also increases volume decreases, In isobaric process, `DeltaQ=lambda.DeltaU` `therefore DeltaQ=DeltaU+DeltaW` `therefore DeltaW=lambda.DeltaU-DeltaU=(y-1)DeltaU` `DeltaW=(y-1)DeltaU` `thereforeDeltaQ=(lambda)/((y-1))DeltaW` |
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| 34. |
Which of the given periodic properties is/are following order : `F gt O gt N`A. Electron affinityB. ElectronegativityC. Ionisation energyD. `Z_("eff")` on valence shell electron |
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Answer» Correct Answer - A::C `C^(4+)gtSn^(4+)` (on moving top to bottom, higher oxidation state gradually become less stable) `Cl gt S gt P` (correct order of Electronegativity) |
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| 35. |
The correct order of ionisation energy is `(i) He(g)rarrHe^(+)(g)(I.E_(1))" "(ii)Ne(g)rarrNe^(+)(g) (I.E_(1))` `(iii) Na(g)rarrNa^(+)(g)(I.E_(1))" "(iv)N(g)rarrN^(+)(g)(I.E_(1))`A. `(ii) gt (i) gt (iii) gt(iv)`B. `(iv) gt (i) gt (ii) gt(iii)`C. `(i) gt (ii) gt (iv) gt(iii)`D. `(i) gt (ii) gt (iii) gt(iv)` |
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Answer» Correct Answer - C Addition of more than one electron in an atom is always an endothermic process `P(g)overset(+3e^(-))rarrP^(3-)(g)` |
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| 36. |
find the total number of compounds having non-zero dipole moment. 1,4-cyanobenzene,1,2-dihydroxy bezene, 1,4-dichlorobenzene, `H_(2)O_(2),O_(2)F_(2),Cl_(2)O_(2),PF_(2)Cl_(3),PF_(3)Cl_(2),CHCl_(3),SF_(6),XeF_(4),NO_(2),SO_(2)` |
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Answer» Correct Answer - 8 `1,4` -dihydroxybenzene, `H_(2)O_(2),O_(2)F_(2),Cl_(2)O_(2),PF_(3)Cl_(2),CHCl_(3),NO_(2)` and `SO_(2)` have non zero dipole moment |
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| 37. |
(4) (i) Calculate the no of \( e^{-} \)required for charging a body by an electric charge of \( 0.0000016 C \). |
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Answer» Use formula - Q=ne where Q is given charge and n is no of electrons and e is charge on electron
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| 38. |
Which of the following statements is not true about RNA? (1) It controls the synthesis of protein (2) IL is present in the nucleus of the cell (3) It usually does not replicate (4) It has always double stranded α-helix structure |
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Answer» Correct option (4) It has always double stranded α-helix structure Explanation: RNA is single stranded helix structure |
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| 39. |
Which of the following will form geometrical isomersA. B. `CH_(3)-CH=NOH`C. D. All of above |
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Answer» Correct Answer - C He = `1s^(2)` Ne = `1s^(2)2s^(2)2p^(6)` N = `1s^(2)2s^(2)2p^(3)` Na = `1s^(2)2s^(2)2p^(6)3s^(1)` |
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| 40. |
Tautomerism is exhibit byA. B. C. D. |
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Answer» Correct Answer - A::B `Fe~=Ca," "Ga lt ln` `Mg lt Ba` `Cu lt Zn` |
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| 41. |
If 1 litre of 9.8% w/w `H_(2)SO_(4)` (d = 1.5 g/ml) solution is mixed with 4 litre of 1M KOH solution then pH of resultant solution will be given (log 2 = 0.3, `H_(2)SO_(4)` is strong diprotic acid):A. 0.7B. 0.5C. 13.3D. 10.3 |
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Answer» Correct Answer - A Stability of carbocation by resonance of benzene |
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| 42. |
The velocity at the maximum height of a projectile is half of its velocity of projection `u`. Its range on the horizontal plane isA. `(2u^(2))/(3g)`B. `(sqrt(3)u^(2))/(2g)`C. `(u^(2))/(3g)`D. `(u^(2))/(2g)` |
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Answer» Correct Answer - B At maximum height `v=u cos theta` `(u)/(2)=vrArrcos theta=(1)/(2)rArrtheta=60^(@)` `R=(u^(2)sin2theta)/(g)=(u^(2)sin(120^(@)))/(g)` `=(u^(2)cos30^(@))/(g)=(sqrt(3)u^(2))/(2g)` |
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| 43. |
Which of the following noble gas is not present in atmosphere?(1) He(2) Ne(3) Kr(4) Rn |
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Answer» Correct option: (4) Rn Explanation: Radon is not naturally occuring in atmosphere. |
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| 44. |
The one that is not a carbonate ore is : (1) malachite (2) bauxite (3) calamine (4) siderite |
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Answer» Correct option (2) bauxite Explanation: Malachite = CuCO3. Cu(OH)2 Bauxite = Al2O3 . 2H2O or AlOx . (OH)3–2x (where D < x < 1) Calamine = ZnCO3 Siderite = FeCO3 ∴ is Bauxite option-2. |
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| 45. |
The noble gas that does not occur in the atmosphere is : (1) Ne (2) He (3) Kr (4) Ra |
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Answer» Correct option (4) Ra Explanation: Radon is not naturally occurring in the atmosphere. Because radon is produced by the radioactive decay of radium – 226. |
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| 46. |
The correct statement is : (1) zincite is a carbonate ore. (2) Sodium cyanide cannot be used in the metallurgy of silver. (3) aniline is a froth stabilizer. (4) zone refining process is used for the refining of titanium. |
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Answer» Correct option (3) aniline is a froth stabilizer. Explanation: Aniline is a froth stabiliser |
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| 47. |
Among the following compounds, which one is found in RNA? |
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Answer» The correct option is (4). Explanation: Structure of uracil which is present in RNA. |
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| 48. |
A metal surface is illuminated by a light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one-fourth of its original value, then the maximum KE of emitted photoelectrons will become.A. unchangedB. 1/16 th of original valueC. twice the original valueD. four time the original value |
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Answer» Correct Answer - A As the maximum kinetic energy depend on the wave length/frequency but not on intensity. |
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| 49. |
Consider the following reversible chemical reactions:The relation between K1 and K2 is:(1) K2 = K31(2) K2 = K-31(3) K1K2 = 3(4) K1K2 = 1/3 |
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Answer» The correct option (2) K2 = K-31 Explanation: K2 = (K1)-3 = 1/K31 |
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| 50. |
Expand the given expression:(1/3x - 1/4y - 1/6z)2 |
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Answer» Given polynomial (1/3x - 1/4y - 1/6z)2 represents identity (a + b + c)2, Where a = -1/3x, b = -1/4y and c = -1/6z (1/3x - 1/4y - 1/6z)2 = (-1/3x)2 + (-1/4y)2 + (-1/6z)2 + 2(-1/3x)(-1/4y) + 2(-1/4y)(-1/6z) + 2(-1/6z)(-1/3x) = 1/9x2 + 1/16y2 + 1/36z2 + 2(-1/3x)(-1/4y) + 2(-1/4y)(-1/6z) + 2(-1/6z)(-1/3x) Solve multiplication process and we get: = 1/9x2 + 1/16y2 + 1/36z2 + 1/6xy + 1/12yz + 1/9zx |
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