This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is meant by Balance of Payment ? |
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Answer» Balance of Payment refers to the statement of accounts recording all economic transactions of a given country, it receives payments from and makes payments to other countries. Balance of payments is a statement of accounts of these receipts and payments. In other words Balance of Payment is overall records of all economic transactions of a country in a given period, with rest of the world. |
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| 2. |
Distinguish between stock and flow and give two examples for each. |
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Answer» Difference between stock and flow :-
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| 3. |
Mention the features of perfect competition. |
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Answer» Characteristics of Perfect competition :- (1) Large Number of Buyers and sellers, (2) Homogeneous product, (3) Free Entry and Exit of Firms, (4) Perfect Knowledge of the Market, (5) Perfect Mobility of Factor, (6) No Transportation cost. |
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| 4. |
a person suffering from anaemia.a boy suffering from poor eye sight.a child suffering from marasmas.a lady suffering from goitre. |
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Answer» a boy suffering from poor eye sight : Vitamin A a person suffering from anaemia : Iron |
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| 5. |
Mention the meaning and characteristics of utilities. |
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Answer» Utility means – The capacity of a commodity to satisfy a particular want of consumer. Every commodity has some inherent want satisfying capacity. Characteristics of utility : (1) Utility is a psychological phenol menon. It depends upon the mental status of the consumer. (2) Utility is subjective which differs from person to person. Utility of a particular goods is not same for all consumers. (3) Utility is a relative concept because it changes from time and place. (4) Utility is related the expected satisfaction and not from actual realized satisfaction because expected satisfaction depends upon intensity of consumption. |
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| 6. |
What is macroeconomic |
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Answer» Macroeconomics is the branch of economics that studies the behavior and performance of an economy as a whole. It focuses on the aggregate changes in the economy such as unemployment, growth rate, gross domestic product and inflation. |
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| 7. |
Explain the “Micro and Macro” Level of economic activity. |
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Answer» Micro Economics – It studies the economic activities of individual unit like individual form, individual household and individual industries. Macro Economics – It is associated with the study of groups at entire economy level, For example aggregate demand and aggregate supply of all goods and services and entire economy level, national income.national saving, national investment, total employment, total production. |
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| 8. |
Difference between macro and micro economic |
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Answer» Microeconomics is the study of economics at an individual, group, or company level. Whereas, macroeconomics is the study of a national economy as a whole. Microeconomics focuses on issues that affect individuals and companies. Macroeconomics focuses on issues that affect nations and the world economy. |
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| 9. |
Solve the system of equations by Cramer's rule:7x+7y-7z=2,-x+11y+7z=1,11x+5y+7z=0 |
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Answer» Given linear programming problem is 7x + 7y - 7z = 2 -x + 11y + 7z = 1 11x + 5y + 7z = 0 It's matrix form is AX = B. Where, A = \(\begin{bmatrix}7&7&-7\\-1&11&7\\11&5&7\end{bmatrix},\) x = \(\begin{bmatrix}x\\y\\z\end{bmatrix},\) B = \(\begin{bmatrix}2\\1\\0\end{bmatrix}\) D = |A| = \(\begin{vmatrix}7&7&-7\\-1&11&7\\11&5&7\end{vmatrix}\) = \(7\begin{vmatrix}11&7\\5&7\end{vmatrix}-7\begin{vmatrix}-1&7\\11&7\end{vmatrix}\)\(-7\begin{vmatrix}-1&11\\11&5\end{vmatrix}\) = 7(77 - 35) - 7(-7 - 77) - 7(-5 - 121) = 7 x 42 - 7x - 84 - 7x - 126 = 294 + 588 + 882 = 1764 Dx = \(\begin{vmatrix}2&7&-7\\1&11&7\\0&5&7\end{vmatrix}\) = \(2\begin{vmatrix}11&7\\5&7\end{vmatrix}-7\begin{vmatrix}1&7\\0&7\end{vmatrix}\)\(-7\begin{vmatrix}1&11\\0&5\end{vmatrix}\) = 2(77 - 35) - 7(7 - 0) - 7(5 - 0) = 2 x 42 - 49 - 35 = 84 - 84 = 0 Dy = \(\begin{vmatrix}7&2&-7\\-1&1&7\\11&0&7\end{vmatrix}\) = \(7\begin{vmatrix}1&7\\0&7\end{vmatrix}-2\begin{vmatrix}-1&7\\11&7\end{vmatrix}\)\(-7\begin{vmatrix}-1&1\\11&0\end{vmatrix}\) = 7( 7 - 0) - 2(-7 - 77) - 7(0 - 11) = 49 - 2x - 84 + 77 = 49 + 168 + 77 = 294 Dz = \(\begin{vmatrix}7&7&2\\-1&11&1\\11&5&0\end{vmatrix}\) = = \(7\begin{vmatrix}11&1\\5&0\end{vmatrix}-7\begin{vmatrix}-1&1\\11&0\end{vmatrix}\)\(+7\begin{vmatrix}-1&11\\11&5\end{vmatrix}\) = 7(0 - 5) - 7(0 - 11) + 2(-5 + 121) = -35 + 77 - 252 = -287 + 77 = -210 x = \(\frac{D_x}{D}=\frac{0}{1764} = 0,\) y = \(\frac{D_y}{D}=\frac{294}{1784} =\frac16\) z = \(\frac{D_z}{D}=\frac{-210}{1764} =\frac{-10}{84}=\frac{-5}{42}\) Hence, solution of given linear programming is x = 0, y = 1/6 and z = -5/42 |
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| 10. |
4x - 3y = 11 and 6x + 5y =7 |
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Answer» 4x - 3y = 11;6x + 5y = 7 The matrix equation is \(\binom{4\,\,-3}{6\,\,-5}\) \(\binom{x}{y}\) = \(\binom{11}{7}\) A X = B Now Δ =\( \begin{vmatrix} {4} & {-3} \\ {6}& {5} \\ \end{vmatrix}\) = 20 + 18 = 38 ≠ 0 ∴ we can apply Cramer's rule Δx = \(\begin{vmatrix} {11} & {-3} \\ {7}& {5} \\ \end{vmatrix}\) = 55 + 21 = 76 Δy =\(\begin{vmatrix} {4} & {11} \\ {6}& {7} \\ \end{vmatrix}\) = 28 - 66 = -38 x = \(\frac{Δx}{Δ}\) = \(\frac{76}{38}\) = 2, y = \(\frac{Δy}{Δ}\) = \(\frac{-38}{38}\) = -1 solution is (2,-1) |
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| 11. |
The some amount is to be distributed in between three friends A, B and C in the ratio of 7 : 8 : 12. The share of C is 20 more than the share of B. Find the difference between the share of B and A.1. Rs.52. Rs.123. Rs.104. Rs.85. Rs.11 |
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Answer» Correct Answer - Option 1 : Rs.5 Given: Let amount shares of A, B and C be Rs.7a, Rs.8a and Rs.12a respectively. ⇒ 12a = 8a + 20 ⇒ a = 5 Shares of A, B and C is Rs.35, Rs.40 and Rs.60 respectively. ∴ Required difference = 40 - 35 = Rs.5 |
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| 12. |
Learn Cube and Cube Root formula Class 8 Maths here, It will more helpful to solve all questions of Cube and Cube Root. |
Answer» Cube and cube rootRamanujan, the great mathematician India ever had. He loved numbers experimented with numbers to a vast extent. Once G.H Hardy came to meet him in India. The taxi which he booked has a number 1729. When he met S. Ramanujan he said that this is a very dull number. Ramanujan replied quickly that this is not a dull number but its interesting number. Then also explained about cube and cube root. He said that 1729 is the smallest number which can be expressed as the sum of two cubes in two different ways. After that day 1729 is known as Hardy-Ramanujan number. Perfect cubes or cube number:When any number is obtained when a number is multiplied by itself three times is perfect cube or cube number. or, Properties of perfect cube number:
1 = 1 = 13 3 + 5 = 8 = 23 13 + 15 + 17 + 19 = 64 = 43 21 + 23 + 25 + 27 + 29 = 125 = 53 The number of odd numbers in cube of any number is same as the number whose cube is obtained.
Cube roots:Cube root is simply the converse of cube of any number. Example related to cube and cube root:
Solution: Thus, (8)3 = 8 x 8 x 8 = 512
Solution:
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| 13. |
The sum of three numbers is 245. If the ratio of the first and second numbers is 2 : 3 and the ratio of the second and third numbers is 5 : 8, then find the second number:A. 50B. 75C. 90D. 4201. C2. A3. B4. D |
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Answer» Correct Answer - Option 3 : B Given: Sum of three numbers = 245 The ratio of first and second number = 2 : 3 The ratio of second and third number = 5 : 8 Calculation: Let the three numbers be A, B, and C. A : B = 2 : 3 ----(1) B : C = 5 : 8 ----(2) Multiply (1) with 5 and (2) with 3, to make the B ratio equal ⇒ A : B : C = 10 : 15 : 24 Let A = 10x, B = 15x, C = 24x ⇒ A + B + C = 245 ⇒ 10x + 15x + 24x = 245 ⇒ 49x = 245 ⇒ x = (245/49) ⇒ x = 5 Second Number ⇒ 15 × 5 ⇒ 75 ∴ The second number is 75. |
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| 14. |
Learn Square and Square root formula Maths class 8 here for better understanding of concepts. |
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Answer» Square and square root: A natural number m is said to be square number or perfect square if it can be expressed in terms of n2, where n is also a natural number. It is necessary to know about square and square root to solve number system related problems. Properties of perfect square: 1. All perfect square numbers end with 0, 1, 4, 5, 6 or 9 at unit’s place. 2. None of these end with 2, 3, 7 or 8 at unit’s place. 3. If a number has 1 or 9 in the unit’s place, then it’s square ends in 1. 4. when a perfect square number ends in 6, the number whose square it is will have either 4 or 6 in unit’s place. 5. There are 2n non-perfect square numbers between n2 and (n + 1)2 6. sum of first n odd natural numbers is n2 also Remember it for square and square root related terms. 7. Any perfect square number can be represented as sum of odd natural numbers starting from 1. 8. Also, Any odd perfect square number can be represented as sum of two consecutive natural number. 9. For any natural number (n + 1) × (n – 1) = n2 – 1. 10. Square numbers can only have even number of 0’s at the end. 11. If a perfect square is of n-digits, then its square root will have \(\frac{n}{2}\) digits if n is even, or \(\frac{n + 1}{2}\) if n is odd? Pythagorean triplet: For any natural number a > 1, we have (2a)2+(a2 – 1)2=(a2 + 1)2 So, 2a, a2 – 1 and a2+ 1 forms a Pythagorean triplet. By this rule, if any one of the members of Pythagorean triplet is given then you can find the rest. this also necessary for getting knowledge of square and square root. Example: 2. If 5 is one of the members of the Pythagorean triplet then find the rest. Solution: 2a = 4 Thus, Pythagorean triplet are 3, 4, 5. Square root: It is simply the inverse operation of square. Square and square root are in converse of each other. 1. By just inversion of square. 2. By repeated subtraction of odd numbers. 3. By prime factorization. 4. By division method. |
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| 15. |
Solve:2x - y - 3,5x + y - 4 |
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Answer» 2x - y = 3....(i) 5x + y = 4....(ii) Adding (i) and (ii), we get 7x = 7 ⇒ x = 7/7 = 1 y = 2x - 3 = 2 x 1 - 3 = -1 Hence, the solution of given equations are x = 1 and y - 1 |
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| 16. |
How _____ have you been to Germany? A) much time B) long for C) many times D) long ago |
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Answer» Correct option is C) many times |
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| 17. |
Learn Linear Equation in One Variable Formula Maths Class 8 here |
Answer» Linear equation in one variable:Earlier, we learnt about algebraic expression and algebraic equation. It is clear about the difference between algebraic expression and algebraic equation that algebraic equation involves equality and on the other hand there is no equality involved in algebraic expression. Let’s clear it by seeing the examples: Algebraic expressions are: 2x, 2x + 5, 8xy – 3, 7xy Linear expression:We can say linear expression as the algebraic expression which has only single degree on its variables. Linear Equation:We denote linear equation the algebraic equation in which the highest power on the variables is equal to one. Now it is clear that the linear equation can be of many types when number of variables is counted. In this section we will read only the linear equation where only one variable is involved. Linear equation in one variable:As we have seen that algebraic equation has equality involved in it. The same is in linear equation. There are two parts in these equations, the symbol of equality separates them. One part is LHS (left Hand Side) and the other side is RHS (Right Hand Side). Any linear equation in one variable containing equations on both side, we solve it simply transposing the variables or literals on one side and the numeral on the other side. You can solve any linear equations involving a single variable by simply transposing like to like side. In some cases, the algebraic equation is not a linear equation but after simplification, it converts into linear equation in one variable then it becomes easy to solve. We will have to identify for the given equation that if it can be simplified or not. There are many applications of linear equation in one variable in everyday life. We can clearly see its uses in calculating numbers, ages, currency, perimeters and several other parameters. Examples on linear equation in one variable:
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| 18. |
This lesson is ______ than I expected. A) much harder B) the hardest C) most hard D) more hard |
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Answer» Correct option is A) much harder |
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| 19. |
Combine the pairs of sentences given below’ into a single sentence using the noun form of the highlighted words.1. He is an honest person. Everyone likes him.2. Sathya gave an explanation. The police wanted her to prove it.3. He speaks well. It attracts all.4. Suresh is always punctual and regular. It has earned him a good job.5. The policeman arrived quickly. It made us happy. |
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Answer» 1. Everyone likes him for his honesty. 2. The police wanted a proof from Sathya for her explanation. 3. His speech is an attraction to all. 4. The punctuality and regularity of Suresh has earned him a good job. 5. The quick arrival of the policemen made us happy. |
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| 20. |
Jack is not only a good student _____ a fine athlete. A) rather than B) as well as C) but also D) in addition |
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Answer» Correct option is C) but also |
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| 21. |
The police wanted _____ our car to a side street. A) us to move B) well to move C) we moved D) is moved |
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Answer» Correct option is A) us to move |
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| 22. |
I don’t think I could ________ another night without sleep. A) stand B) support C) put up D) carry |
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Answer» Correct option is A) stand |
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| 23. |
They ________ on holiday in Switzerland and became good friends. A) found B) knew C) met D) encountered |
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Answer» Correct option is C) met |
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| 24. |
It will do you ________ to have a holiday. A) well B) better C) good D) fine E) great |
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Answer» Correct option is C) good |
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| 25. |
A body cools in 7 min from `60^@C` to `40^@C` What will be its temperature after the next 7 min? The temperature of surroundings is `10^@C`. |
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Answer» Rate of cooling `(triangleT)/(trianglet)=K(T-T_(0))` For cooling from `60^(@)C` to `40^(@)C` `implies(60-40)/(7)=K((60+40)/(2)-10)` `impliesK=(20)/(7xx40)=(1)/(14)` For cooling from `40^(@)C` to T `(40-T)/(7)=K((40+T)/(2)-10)implies(40-T)/(7)=(1)/(14)((40+T-20)/(2))` `implies160-4T=20+T` `implies140=5T` `impliesT=(140)/(5)=28^(@)C` `T=28^(@)C` |
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| 26. |
The rate constant of a first order reaction at `27^@C` is 10–3 min–1. The temperature coefficient of this reaction is 2. What is the rate constant (in min–1) at `17^@C` for thisreaction :-A. 10–3B. 5 × 10–4C. 2 × 10–3D. 10–2 |
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Answer» Correct Answer - B `K_(T_2)/K_(T_1)=(mu) (DeltaT)/10 = 2^(10/10) =2` `10^(-3)/K_(T_1) =2` `L_(T_1)=5 x 10-4 min -1` |
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| 27. |
Which one of the following quantity is dependent on path?(A) molar internal energy(B) volume(C) \( w \)(D) \( q+w \) |
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Answer» Work is a path dependent quantity. It is known as a path function. |
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| 28. |
One end of string of length l is connected to a particle of mass 'm' and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed 'v' the net force on the particle (directed towards centre) will be (T represents the tension in the string) :- |
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Answer» (4) Net force on particle in uniform circular motion is centripetal force (mv2/l)which provided by tension in string so the net force will be equal to tension i.e., T. |
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| 29. |
4 kg of ice at `-20^(@)C` is mixed with 5 kg of water at `40^(@)C`. The water content in the equilibrium mixture is `(S_("water")=1kcal//kg-C,S_(ice)=0.5kcal//kg-c,L_(f(water))=80kcal//kg)`A. 6 kgB. 7 kgC. 8 kgD. 9 kg |
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Answer» Correct Answer - B Equilibrium temperature of mixutre is `0^(@)C` Total heat released by water `=m_(W)s_(W)Deltatheta=5xx1xx40=200kcal` Heat taken by ice to increase its temperature from `-20^(@)C` to `0^(@)C=4xx0.5xx20=40kcal` `therefore` mass of ice melted `=(200-40)/(80)=(160)/(80)=2kg` `therefore` water content in the equilibrium mixture `=5+2=7kg` |
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| 30. |
Enthalpy of solution (ΔH) for BaCl2 .2H2O and BaCl2 are 8.8 and –20.6 kJ mol–1 respectively. Calculate the heat of hydration of BaCl2 to BaCl2 .2H2O. |
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Answer» We are given (i) BaCl2 .2H2O (s) + aq → BaCl2 (aq), Δsol ΔH°1 = 8.8 kJ mol–1 (ii) BaCl2 (s) + aq → BaCl2 (aq), Δsol ΔH°2 = – 20.6 kJ mol–1 We aim at BaCl2 (s) + 2H2O → BaCl2 .2H2O (s), Δhyd H° = ? ΔH = ΔH2 – ΔH1 = – 29.4 kJ mol–1 |
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| 31. |
Name the solvent in which ionic compounds are generally soluble. |
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Answer» Water is the solvent in which ionic compounds are generally soluble. |
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| 32. |
State any four physical properties of non-metals. |
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Answer» The four physical properties of non-metals are: 1. Non-metals are brittle, i.e. they cannot be beaten into sheets. 2. Non-metals are non-ductile, i.e., they cannot be drawn into wires. 3. They are bad conductors of heat and electricity except carbon (in the form of graphite). 4. They are dull [non-lusturous] [do not shine] except iodine and graphite. 5. They have comparitively low melting & boiling points. 6. They have low densities. 7. They may be solid, liquid or gas at room temperature. 8. Most of the solid non-metals are soft except carbon (in the form of diamond) 9. They are not strong i.e. they have low tensile strength. |
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| 33. |
An electric motor takes 5 A from a 220 V line determine the power of the motor and the energy consumed in 2h. |
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Answer» Here, I = 5A, V = 220 V, t = 2h = 7200 sec |
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| 34. |
State Ohm's law. Give its mathematical expression. |
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Answer» Ohm's law—“At constant temperature, current is directly proportional to its potential difference.” Mathematical expression on can be given as— V = IR Where, V represents potential difference; I represents current and R = Resistance (constant). |
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| 35. |
What are fallopian tubes? Write two functions of fallopian tubes (oviducts). |
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Answer» These are the two tubes attached to the uterus one on either side. (i) The fallopian tubes carry egg (ova) from ovary to the womb (uterus) (ii) Fertilisation of the egg by the sperm may take place in the fallopian tube |
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| 36. |
Name the substance that is exodised in the body during respiration. |
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Answer» Glucose is oxidised in the body during respiration. |
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| 37. |
Why are lungs divided into very small sac like structures? |
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Answer» Lungs are divided into very small sac like structures to increase the respiratory surface area. This facilitates efficient exchange of oxygen and CO2 between the air and the blood. |
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| 38. |
What is a neutralisation reaction? Give example. |
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Answer» The reaction between an acid and a base to give salt and water is called neutralization reaction. Base + Acid ⇒ Salt + Water Eg: HCl + NaOH → NaCl + H2O |
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| 39. |
Which mechanism plays an important role in transportation of water in plants?1. During day time2. At night. |
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Answer» 1. During day time suction pressure creates by transpiration (evaporation of water) helps in absorption and upward movement of water and minerals dissolved in it from roots to the leaves, us to the top of the plant. 2. At night, the effect of root pressure [created by movement of water from the soil to the xylem of roots] in transport of water is more important. |
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| 40. |
Why are the coils of electric toasters and electric irons made of an alloy rather than a pure metal? |
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Answer» This is because of two reasons: 1. Alloys have higher resistivity than that of their constituent metals. 2. Alloys do not oxidise [or burn] readily at high temperature. |
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| 41. |
What is the need of using combination of resistances in electrical circuits ? Define equivalent resistance? |
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Answer» The need of using combination of resistances is to obtain a desired value of current in an electrical circuit, it can be done in three ways they are i) series combination, ii) parallel combination and iii) mixed combination. Equivalent resistance: If a single resistance can replace the combination of resistances in such a manner that the current in the circuit remains unchanged, then that single resistance is called the equivalent resistance. |
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| 42. |
Calculate the enthalpy of combustion of ethylene (gas) to form CO2 (gas) and H2O (gas) at 298 K and 1 atmospheric pressure. The enthalpies of formation of CO2 , H2O and C2H4 are –393.5, –241.8, + 52.3 kJ per mole respectively. |
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Answer» We are given : (i) C (s) + O2 (g)→ CO2 (g), ΔH°1 = – 393.5 kJ mol–1 (ii) H2(s) +1/2 O2 (g) →H2O(g) ΔH°2 = – 241.8 kJ mol–1 (iii) 2C (s) + 2H2 (g) → C2H4 (g),ΔH°3 = + 52.3 kJ mol–1 We aim at : C2H4 (g) + 3O2 (g) → 2CO2 (g) + 2H2O(g) ΔH = – ΔH3 + 2ΔH1 + 2ΔH2 = –1322.9 kJ mol–1 |
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| 43. |
In the given arrangement of capacitors, `6muC` charge is added to point a. Find the charge on upper capacitor. A. `3muC`B. `1muC`C. `2muC`D. `6muC` |
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Answer» Correct Answer - A a. `(q_(1))/(1)=(q_(2))/(2)=(q_(3))/(3)=K` `q_(1)+q_(2)_q_(3)=6` Solving. We get `K=1` or `q_(1)-3muC` |
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| 44. |
Calculate the enthalpy of hydrogenation of ethylene, given that the enthalpy of combustion of enthylene, hydrogen and ethane are – 1410.0, – 286.2 and – 1560.6 kJ mol–1 respectively at 298 K. |
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Answer» We are given (i) C2H4 (g) + 3O2 (g) → 2CO2 (g) + 2H2O (l) ΔH = – 1410 kJ mol–1 (ii) H2 (g)+ 1/2 O2(g)→ H2O (l), ΔH = – 286.2 kJ mol–1 (iii) C2H6 (g) + 31/2 O2(g)→ 2CO2 (g)+ 3H2O (l), ΔH = – 1560.6 kJ mol–1 We aim at: C2H4 + H2 (g) → C2H6 (g), ΔH = ? Equation (i) + Equation (ii) – Equation (iii) gives C2H4 (g) + H2 (g) → C2H6 (g), ΔH = – 1410.0 + (–286.2) – (1560.6) = – 135.6 kJ mol–1 |
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| 45. |
Increasing the focus-to-film distance while keeping the film exposure constant: a. Improves radio graphic contrast b. Reduces patient dose c. Reduces magnification d. Reduces geometric unsharpness e. Improves field uniformity |
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Answer» a. False. It does not influence the radio graphic contrast. b. True. c. True. d. True. e. True. |
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| 46. |
Regarding the construction of a radiation grid: a. It is made of 0.05–0.07 mm lead strips b. The line density of a grid is usually 12–16 cm-1 c. The gaps between the lead strips are filled with air d. The grid ratio is the ratio of the depth of the inter space channel divided by its width e. A typical grid ratio is 30:1–80:1 |
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Answer» a. True. b. False. The line density of a grid (number of lead strips per cm) is usually 30–80 cm–1 (typically 40). c. False. Usually aluminium, carbon fibre or plastic are used as inter space material. d. True. e. False. It is typically 8:1. High-ratio grids (12:1–16:1) are used with very large fields and high peak kV (kVp). |
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| 47. |
Regarding the construction of a rotating anode X-ray tube: a. The entire anode disc is usually made of tungsten b. The anode stem is made of molybdenum to improve the conduction of heat away from the anode disc c. The rotor bearings are lubricated with a soft metal d. The electric brushes of the X-ray tube motor are made of graphite e. The filament assembly is aligned with the anode stem |
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Answer» a. False. It is usually made of molybdenum, in which the target annulus (made of tungsten alloy) is embedded. b. False. The opposite is true. Molybdenum has a low heat conductivity, which slows the conduction of heat towards the rotor bearings, protecting them from heat damage. c. True. They are usually lubricated with silver powder. d. False. Induction motors are used. These are brush less. e. False. The filament is offset towards the edge of the anode, in line with the target annulus. |
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| 48. |
With regard to the cooling of a rotating anode X-ray tube: a. Heat produced in the focal spot is transferred to the glass envelope by convection b. Heat is transferred out of the tube housing into the atmosphere by conduction c. The anode assembly is blackened to improve radiation of heat d. The major thermal limiting factor for single exposures is the heat capacity of the focal spot area e. In the case of continuous/repeated exposures, the major limiting factor is the heat capacity of the anode disc and the tube housing |
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Answer» a. False. It is conducted to the anode disc and transfers to the glass envelope by radiation. It cannot be transferred between the anode and glass by convection as the tube is evacuated. Some heat is transferred via conduction through the anode stem (this becomes the main process at lower temperatures as heat radiation becomes less significant). From the glass, heat is transferred to the insulating oil and the tube housing by convection. b. False. It is transferred by radiation and convection. c. True. Blackening substantially increases the emissivity coefficient. d. True. e. True. |
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| 49. |
Concerning entrance surface doses (ESDs) in adults (national diagnostic reference levels, 2007) a. Chest posterior–anterior (PA) radio graph = 0.2 mGy b. Abdominal radio graph = 2 mGy c. A lumbar spine anterior–posterior (AP) radio graph is greater than a pelvis AP radio graphd. Imaging the vertebral column typically requires a greater dose for the AP view compared with the lateral (LAT) view e. A LAT view of the skull is greater than a PA view |
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Answer» a. True. b. False. It is 6 mGy. c. True. (6 mGy versus 4 mGy). d. False. The reverse is true and is related to the amount of tissue that the X-ray beam needs to pass through. e. False. The skull has a greater sagittal length than coronal length. |
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| 50. |
A three phase induction Motor delivers an output of 15 h.p. at 83 % efficiency. The motor is d (delta) connected and is supplied by 440 V, three phase, 50 Hz supply. Line current drawn by motor is 22.36 Amp. What is motor power factor ? It is now decided to improve the power factor to 0.95 lag by connecting three similar capacitors in delta across the supply terminals. Determine the value of the capacitance of each capacitor. [Note : 1 h.p. = 745 watts] |
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Answer» Power factor = (15 x 745)/(0.83 x 1.732 x 440 x 22.36) = 0.79, Lagging φ = cos−1 0.79 = 37.8º I1 = Iph = 22.36/1.732 = 12.91 amp Active Current Ia = I1 cos φ1 = 12.91 × 0.79 = 10.2 amp New Power-factor cos φ2 = 0.95, φ2 = 18.2º I2 = 10.2/0.95 = 10.74 amp Capacitive current per phase = I1 sin φ1 − Ι2sin φ2 = 4.563 Capacitive reactance per phase = 440/4.563 = 96.43 ohms Capacitance per phase = 33 μf These have to be delta-connected |
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