Explore topic-wise InterviewSolutions in Current Affairs.

a. A- C₆H₁₂ O₆B – C₂H₅ – OH

b. Ethyl Propanoate 

c. CH₃ – CH₂ – COOH + HO – CH₂ – CH₃ → CH₃ – CH₂ – COO – CH₂ – CH₃ + H₂O

a. Ethanoic acid 

b. Teflon 

c. Methanol 

d. Power alcohol

a. Avogadro’s law 

b. Boyle’s law

a. A — CH₃ – COOH 

B– Methanol/CH₃ – OH

C – CH₃ – COO – CH₃

b. Esters, Methyl ethanoate

Solubility product of weak electrolyte is defined as the product of molar concentration of ions of electrolyte raised to appropriate power within saturated solution of that electrolyte.

1. tied; 

2.was seen; 

3.was blamed; 

4.was sent; 

5. was not paid; 

6. would be asked.

H_2(g) + I_2(g) ⇌ 2HI_g

a. Polymerization 

b. Substitution reaction 

c. Addition reaction

d. Combustion 

e. Thermal cracking

The total mass of the products in a reaction is equal to mass of the reactants ‘or’ the mass neither be created nor be destroyed.

 (b) 10^–8

Explanation:

[(10^–15) / (100 × 10^–9)] = 10^–8

[(1 Femtometer) / (100 nanometer)] 

= [(10^–15) / (100 × 10^–9)] = 10^–8    

a. Molasses is mother liquor left after the crystallization of sugar from sugar cane juice.

b. Poisonous chemical methanol (CH₃ – OH) is known as wood spirit. 

c. 5-8% ethanoic acid (CH₃ – COOH) is known as vinegar. 

d. esters are salts formed by the reaction ale ‘ whole and organic acids. They have the smell of fruits and flowers.

The correct option (3) U_E = U_E 

Explanation:

U_A = U_B

(Noble Gas) (n - 1)d^1-10 ns^1-2

\(\frac{50000}{5}\) = 10000

Yes, it becomes easy.

5 x 1000 = 5000g

a. A, D2g Hydrogen, 8g Helium 

B, C 16g Oxygen, 14g Nitrogen 

b. A, D – 2 x 6.022 × 10²³ 

B,C – 6.022 x 10²³

 (b) 2 (ΔR / R)

Explanation:

g = [(GM) / R²]

 ∵ G & M are constant g is function of (1/R²) i.e. (1/R)² fractional error (Δg / g) = 2(ΔR / R)  

a. CHCl₃ 

b. Substitution Reaction 

c. CH₄ Cl₂ + sunlight → CH₃Cl + HCl

CH₂Cl + Cl₂ → CH₂Cl₂ + HCI

CH₂Cl₂ + Cl₂ → CHCl₃ + HCI

a. 6.022 × 10²³ 

b. i.6.022 × 10²³ 

ii. 2 x 6.022 × 10²³ 

iii.  \(\frac{32}{12}\) x 6.022 x 10²³

(a) Her father wanted her to became a great mathematician or scientist.

(b) She wrote her first poem when she was eleven.

(c) Edmund was disappointed because her poems had nothing of the cast in them.

(d) She went to England for higher education.

CH₃ - CH₂ - CH₂ - CH₃ +  13/2O₂ → 4CO₂ + 5H₂O, Combustion.

A. CH₃ – CH₂ – OH

B. CH₃ – COOH – OH 

C. H₂O

(i) Position isomerism 

(ii) Position isomerism arises as a result of the difference in the position of double bond, triple bond or functional group.

(1) 4 – Ethyl -2, 3-dimethyl heptane 

(2) 3, 4-Dimethyl hex – 3-ene 

(3) 4, 5, 5- triethyl 3 methyl 2 heptyne 

(4) 3ethyl-2, 5, 5, trimethylheptane

Isomer pairs 

a – ii – functional group isomerism 

b – i – chain isomerism 

c - iv- position isomerism 

d – iii – metamerism 

The hydrocarbon formed when Beryllium carbide is treated with water is Methane.

It will give Fe4+ and Mn4+ respectively in Alkaline medium

Under alkaline conditions, Mn2+ is oxidized to Mn4+ (as MnO2). and same is the case for Fe4+

(i) Order- Zero order reaction Molecularity = 2

(ii) Mol L^-1 sec^-1

(i) Electrode potential value is the sum of three factors, enthalpy of atomisation, ionisation enthalpy and hydration enthalpy. In case of copper the sum of enthalpy of atomisation and ionisation enthalpy is higher than hydration enthalpy. 

Therefore E⁰ Cu²⁺ I Cu value is exceptionally positive. 

(ii) Mn²⁺ has stable electronic configuration (3d⁵). The ionisation enthalpy is less than that of hydration enthalpy. Therefore E⁰ value is more negative. 

(iii) Cr²⁺ is stronger reducing agent than Fe²⁺ due to more negative E⁰ value

(i) CH₃CH=CH₂ + H₂SO₄/H₂O ⟶ CH₃CH(OH)CH₃

(ii) CH₃CHCl + KOH ⟶ CH₃CH₂OH + Cu/573K ⟶ CH₃CHO

(I) Transition metals form a large number of compounds due to: 

(a) Comparatively small size 

(b) High ionic charges 

(c) Availability of d-orbitals 

(ii) Iron has great number of unpaired electrons than copper, hence higher the enthalpy of atomisation. 

(iii) The electronic configuration of Mn²⁺ is 3d⁵ which is stable. In Fe²⁺ the configuration is 3d⁶ , it can lose an electron easily to give stable 3d⁵ configuration.

Evans went to Chipping Norton and after a stroll around the centre of Chipping Norton he returned to Golden Lion hotel.

(i) AgCl shows Frenkel defect due to large difference in their ionic size. 

(ii) No. of Y atoms per unit cell = \(\frac{1}{8}\) x 8 + \(\frac{1}{2}\) = 1 + 3 = 4

No. of tetrahedral voids = 2 x 4 = 8

No. of X atoms = \(\frac{1}{3}\) x 8 = \(\frac{8}{3}\) 

Formula of compound = X_8/3Y₄ = X₂Y₃

(i) 2XeF₂ + 2H₂O ⟶ 2Xe + 4HF + O₂ 

(ii) XeF₂+ PF₅ ⟶ [XeF]⁺ [PF₆]^–

Evans is a genius and a master in planning his escapes. He uses all tactics-psychology, emotional display, great acting skills, convincing powers, and amiability—to carry out his plan. The governor, despite being overcautious, is not able to prevent his escape. However, after a lot of efforts he is able to trace and capture Evans, arrest him and send him to the prison house. But at this point also, he is outsmarted by Evans. In fact, the prison officials are no one else but his friends in disguise. Once again Evans escapes due to the carelessness of the Governor. He has the last laugh.

(i) 1-Bromopentane, 2-Bromopentane, 2-Bromo-2-methylbutane 

(ii) 1-Bromo-3-methylbutane, 3-Bromo-2-methylbutane, 2-Bromo-2-methylbutane

When Stephens comes back to the cell, he finds a man covered with blood in Evans’ cell. He jumps to the conclusion and does not bother to check the identity of the injured McLeery. Definitely it was a hasty conjecture on his part which prevented him from seeing the obvious. If he had identified McLeery then and there, Evans would have been caught as this man was no one but Evans himself. Evans is able to predict such negligence because he understood the psychology of the officer. Evans was smart and very observant.