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701.

Vaibhav Sharma was working as the Production Manager in CrescentPharmaceuticals Pvt. Ltd. To get his son admitted in school he wanted totake leave from the office but on the same day, an important meetingwith the Chief Executive Officer (CEO) of the company was scheduled todiscuss about some new medicines to be manufactured. Considering thesignificance of the meeting, he did not take leave. The CEO appreciatedhis exemplary behaviour as he gave priority to the organisational interestover his personal interest.Name and explain the principle of management being followed byVaibhav Sharma in the above case.

Answer»

ANS:- SUBORDINATION OF INDIVIDUAL INTERST INTO GENERAL INTERST

There are always all kinds of interests in an organization. In order to have an organization function well, Henri Fayol indicated that personal interests are subordinate to the interests of the organization (ethics). The primary focus is on the organizational objectives and not on those of the individual. This applies to all levels of the entire organization, including the managers.

702.

Arrange in correct sequence:Following steps arrange in the sequence for calculation of hidden Goodwill of the firm. (1) Calculate total capital of the new firm on the basis of capital brought in by new partner. (2) Existing Partners total capital (3) Deduct existing total capital of the partners from total capital of the new firm is hidden Goodwill of the firm.(a) 3 ,1, 2 (b) 1 , 2, 3 (c) 2, 2, 1 (d) 1, 3, 2

Answer»

Correct option is (b) 1 , 2, 3

703.

At the time of forfeiture of shares which were originally issued at a discount, the accounting entry involves _______________. I. A debit to Share Capital Account with the called up value of shares forfeited II. A credit to Share Forfeiture Account with the amount received on forfeited shares III. A credit to discount on issue of shares with the amount of discount allowed on forfeited shares IV. A credit to calls in arrears with the amount due but not paid on forfeited shares (a) Both (I) and (IV) above (b) Both (IV) and (III) above (c) Both (I) and (II) above (d) (I), (II), (III) and (IV) above

Answer»

Correct option is 

d) (I), (II), (III) and (IV) above

704.

A company invited applications for 25,000 equity shares of 10 each and received 30,000 applications along with the application money of 4 per share.Which of the following alternatives can be followed?I. Refund the excess applications II. Make pro rata allotment to all the applicants, and refund the excess application money III. Not to allot any shares to some applicants, full allotment to some of the applicants and pro rata allotment to the rest of the applicants. IV. Not to allot any shares to some applicants & make pro rata allotment to other applicants. V. Make pro rata allotment to all the applicants and adjust the excess money received towards call money. (a) Only (II) above (b) Both (I) and (IV) above (c) All (I), (II), (III), (IV) and (V) above (d) Only (III) above

Answer»

Correct option is (c) All (I), (II), (III), (IV) and (V) above

705.

4,000 Equity Shares of Rs. 10 each were issued at 8% premium to the promoters of a company for their services. Goodwill Account/ incorporation Cost Account will be debited with ? (A) Rs.40,000 (B) Rs.43,200 (C) Rs.3,200 (D) Rs.36,800

Answer»

Correct option is (B) Rs.43,200

706.

A Company issued 50,000 shares of 20 each at 5% premium,10 were payable on application and balance on allotment. What will be the allotment amount? (A) Rs.500,000 (B) Rs.4,75,000 (C) Rs.550000 (D) Rs.5,25,000

Answer»

Correct option is (C) Rs.550000

707.

A Company invited applications for 1,00,000 shares and it received applications for 1,50,000 shares. Applications for 30,000 shares were rejected and the remaining were allotted shares on prorata basis. How many shares an applicant for 3,000 shares will be allotted (A) 2,500 Shares (B) 3,600 Shares (C) 4,500 Shares (D) 2,000 Shares

Answer»

Correct option is (A) 2,500 Shares

708.

The subscribed capital of a company is Rs.80,00,000 and the nominal value of the share is 100 each. There were no calls in arrear till the final call was made. The final call made was paid on 77,500 shares only. The balance in the calls in arrear amounted to 62,500. Calculate the final call on share.(A) 27 (B) 20 (C) 22(D) 25

Answer»

Correct option is (D) 25

709.

The subscribed capital of a company is Rs.80,00,000 and the nominal value of the share is 100 each. There were no calls in arrear till the final call was made. The final call made was paid on 77,500 shares only. The balance in the calls in arrear amounted to 62,500. Calculate the final call on share.(A) 27 (C) 22 (B) 20 (D) 25

Answer»

Correct option is (D) 25

710.

Explain what happens to effective nuclear charge on moving down the group in the periodic table? Give your views on why it happens so?

Answer»

Effective nuclear charge is the attractive positive charge of nuclear protons acting on valence electrons. The periodic table tendency for effective nuclear charge:

Increase across a period
Decrease down a group

711.

Bank has implemented ______for online payments for purchases as precaution while doing online banking. a) OPT b) OIC c) OTPd) OEP

Answer»

Bank has implemented OTP for online payments for purchases as precaution while doing online banking.

712.

Bayer’s reagent is ......

Answer»

dil. alkaline KMnO4.

713.

Gammexane has the formula .......

Answer»

Gammexane has the formula C6H6Cl6.

714.

In a Chemistry class, teacher asked students to write the geometrical form of dicarboxylic acid with the formula C4H4O4 . For this question, one student wroteBoth of them argued for their answers. Hearing this argument teacher told that both of them are right and she also explained the reason for it. Can you write the answer given by the teacher?

Answer»

Two geometrical isomers are possible for dicarboxylic acid. They are cis and transform. In the cis form, similar groups are present on the same side of the double bond whereas in transform, identical groups are present on different side of the double bond.

715.

1. Name the product obtained when HBr is added to propene. Why? 2. Acetylene is more acidic than ethylene or ethane. Why?

Answer»

1. When propene is treated with HBr, both 2-bromopnopane and 1-bromopropane are formed as products. The major product is2- Bromo-propane. This is due to the rule known as Markonikos rule of addition. It states that when a hydrogen halide is added to an unsymmetrical alkene, the halogen atom will goes to the doubly bonded carbon containing lesser number of hydrogen atoms.

2. In Acetylene, the hybridisation of carbon is sp and hence 50% s-character is present.

716.

Fill in the blanks after finding the correct relationship CH3 – O – CH3 : Ether, CH3 -CH3 -OH: .......

Answer»

CH3 -CH3 -OH: Alcohol

717.

The structural formula of a compound and the name given by a student to it is given below:

Answer»

The name given by the student is wrong. The correct name of the compound is 3- Ethyl -2-methyl nonane.

718.

Choose the correct answer from the brackets given below:(1) General formula of alkene (CnH2n,CnH4n-2)(2) The 2 different forms of elemental carbon (Bitumen, Diamond, Charcoal, Coke, Led, Graphite)(3) Find the odd man out. Give reason (C2H4 , C3H6 , C4H8 , C2H6)

Answer»

(1) CnH2n 

(2) Diamond, graphite 

(3) C2H6 . It is an alkane. All others are alkenes.

719.

In an inorganic compound, the mass % of Na = 14.3, S = 9.97, H = 6.22 and O = 69.5. The hydrogen and oxygen are present as water. The vapour density of the compound is 161, what is its molecular formula?

Answer»
ANSWER : 
             The Molecular Formula Of Compound is Na2SH20O14



                 
                    
ANSWER :                                                       The Empirical Formula Mass Of the Compound = 2*23+1*32+20*1+14*16
Now Calculate the Value Of N =
MOLECULAR MASS/EMPIRICAL MASS =
322/322 = 
1

∴ Vapour density of compound is  = 161

∴ Molecular weight = 2 x vapour density

 = 2 x 161 = 322 g

∴ Number oxygen atoms = \(\cfrac{322\times\frac{69.5}{100}}{16}\) = 13.986 

 = 14 Oxygen atom

Number of hydrogen atoms = \(\cfrac{322\times\frac{6.22}{100}}{1}\) = 20.02

 = 20 Hydrogen atoms

∴ Maximum number of water molecule can present = 10 H2O

∴ remaining number of oxygen atoms = 4

Number of S atom = \(\frac{322\times9.97}{32\times100}\) = 1.003

 = 1 sulphur atom

Number of sodium atoms = \(\cfrac{322\times\frac{14.3}{100}}{23}\) 

 = 2.003 = 2 sodium atoms

Therefore,  the molecular formula will be 

Na2SO4.10H2O

720.

1. Acetaldehyde reacts with Fehling solution.2. Acetic acid reacts with phosphorus pentachloride.

Answer»

1. When we treat acetaldehyde with fehings solution,then the deep blue colur of fehlings solution disappears and brick red colour is formed due to the formation of copper oxide
i,e Cu2O

2. When acetic acid is heated with phosphorus pentachloride, acetyl chloride is obtained.

721.

An isentropic process is always (a) irreversible and adiabatic (b) reversible and isothermal (c) frictionless and irreversible (d) reversible and adiabatic (e) none of the above.

Answer»

(d) reversible and adiabatic 

722.

The state of a substance whose evaporation from its liquid state is complete, is known as (a) vapour (b) perfect gas (c) air (d) steam.

Answer»

(b) perfect gas 

723.

The net work done per kg of gas in a polytropic process is equal to(a) p1v1 log \(\cfrac{v_2}{v_1}\)(b) p1 (v1 – v2)(c) p2 \(\left(v_2-\cfrac{v_1}{v_2}\right)\)(d) \(\cfrac{p_1v_1-p_2v_2}{n-1}\)(e) \(\cfrac{p_2v_1-p_2v_2}{n-1}\)

Answer»

 (d) \(\cfrac{p_1v_1-p_2v_2}{n-1}\)

724.

When the gas is heated at constant pressure, the heat supplied (a) increases the internal energy of the gas (b) increases the temperature of the gas (c) does some external work during expansion (d) both (b) and (c) (e) none of the above.

Answer»

(d) both (b) and (c) 

725.

The first law of thermodynamics for steady flow (a) accounts for all energy entering and leaving a control volume (b) is an energy balance for a specified mass of fluid (c) is an expression of the conservation of linear momentum(d) is primarily concerned with heat transfer (e) is restricted in its application to perfect gases

Answer»

(a) accounts for all energy entering and leaving a control volume 

726.

The processes or systems that do not involve heat are called (a) isothermal processes (b) equilibrium processes (c) thermal processes (d) steady processes (e) adiabatic processes.

Answer»

(e) adiabatic processes.

727.

The gas constant (R) is equal to the (a) sum of two specific heats (b) difference of two specific heats (c) product of two specific heats (d) ratio of two specific heats.

Answer»

(b) difference of two specific heats 

728.

Steady flow occurs when (a) conditions do not change with time at any point (b) conditions are the same at adjacent points at any instant (c) conditions change steadily with the time (d) \(\left(\cfrac{\partial v}{\partial t}\right)\) is constant.

Answer»

(a) conditions do not change with time at any point 

729.

A reversible process requires that (a) there be no heat transfer (b) newton’s law of viscosity be satisfied (c) temperature of system and surroundings be equal (d) there be no viscous or coloumb friction in the system (e) heat transfer occurs from surroundings to system only.

Answer»

(d) there be no viscous or coloumb friction in the system 

730.

In isothermal process (a) temperature increases gradually (b) volume remains constant (c) pressure remains constant (d) enthalpy change is maximum (e) change in internal energy is zero.

Answer»

(e) change in internal energy is zero.

731.

When a gas is to be stored, the type of compression that would be ideal is (a) isothermal (b) adiabatic (c) polytropic (d) constant volume (e) none of the above.

Answer»

(a) isothermal 

732.

During throttling process (a) internal energy does not change (b) pressure does not change (c) entropy does not change (d) enthalpy does not change (e) volume change is negligible.

Answer»

(d) enthalpy does not change 

733.

In an internal combustion engine, during the compression stroke the heat rejected to the cooling water is 50 kJ/kg and the work input is 100 kJ/kg. Calculate the change in internal energy of the working fluid stating whether it is a gain or loss.

Answer»

Heat rejected to the cooling water, Q = – 50 kJ/kg 

(–ve sign since heat is rejected) 

Work input, W = – 100 kJ/kg 

(–ve sign since work is supplied to the system) 

Using the relation, Q = (u2 – u1) + W 

– 50 = (u2 – u1) – 100 or 

u2 – u1 = – 50 + 100 = 50 kJ/kg 

Hence, gain in internal energy = 50 kJ/kg.

734.

In an air motor cylinder the compressed air has an internal energy of 450 kJ/kg at the beginning of the expansion and an internal energy of 220 kJ/kg after expansion. If the work done by the air during the expansion is 120 kJ/kg, calculate the heat flow to and from the cylinder.

Answer»

Internal energy at beginning of the expansion,

u1 = 450 kJ/kg

Internal energy after expansion, 

u2 = 220 kJ/kg 

Work done by the air during expansion, 

W = 120 kJ/kg 

Heat flow, Q : 

Using the relation, Q = (u2 – u1) + W 

∴ Q = (220 – 450) + 120 

= – 230 + 120 = – 110 kJ/kg 

Hence, heat rejected by air = 110 kJ/kg.

735.

Internal energy of a perfect gas depends on (a) temperature, specific heats and pressure (b) temperature, specific heats and enthalpy (c) temperature, specific heats and entropy (d) temperature only

Answer»

(d) temperature only

736.

Mercury boils at `367^(@)C`. However, mercury thermometers are made such that they can measure temperature up to `500^(@)C`. This is done byA. maintaining vacuum aboves mercury column in the stem of the thermometerB. filling nitrogen gas at high pressure above the mercury columnC. filling oxygen gas at high pressure above the mercury columnD. filling nitrogen gas at low pressure above the mercury column

Answer» Correct Answer - B
737.

Determine total energy of 1 mol of photons in J/mol having λ = 600 nm Given h = 6.62 × 10-34J-sec, c = 3 x 108 ms1(1) 1.99 × 105 J/mol (2) 6.64 x 108 J/mol (3) 1.24 × 104 J/mol(4) 1.24 × 108 J/mol

Answer»

Correct option is (1) 1.99 x 105 J/mol

\(E_T = \frac{N_AhC}{\lambda}\)

\(E_T = \frac{6.02 \times 10^{23}\times 6.62 \times 10^{-34}\times 3 \times 10^8}{600\times 10^4}\)

\(= \frac{119.56 \times 10^{-3}}{600\times 10^{-9}}\)

\(= 19.93 \times 10^4J/mol\)

or 1.99 x 105 J/mol

738.

If the acceleration due to gravity experienced by a point mass at a height h above the surface of earth is same as that of the acceleration due to gravity at a depth αh (h << Re) from the earth surface. The value of α will be _____.(use Re = 6400 km)

Answer»

Correct answer is 2

g(1 - 2h/R) = g(1 - d/R)

2h/R = d/R

αh = d

α = 2

739.

The drift speed of free electrons in a conductor does not depends upon:(a) The material of the conductor(b) The temperature of the conductor (c) The potential difference applied across the ends of the conductor(d) The area of cross section of the conductor

Answer»

(d) The area of cross section of the conductor

The drift velocity is known to be primarily depends on the applied voltage and the molecular structure of the wire and hence the material of the conductor. Slight temperature depends is also observed.

740.

If in a meter bridge, area of cross section of wire is doubled, null point  (a) Increases (b) Decreases (c) Remains same(d) None of these

Answer»

(c) Remains same

Null point will remain same as resistance of both sides will decrease in the same ratio.

741.

Why did George and Harris have to pick out the tomato with a teaspoon?

Answer»

While packing the hamper, Harris packed a strawberry jam on top of a tomato and squashed it. So, they had to pick out the tomato with a teaspoon which was a messy and time-consuming task.

742.

Why did George and Harris have to pick out the tomato with teaspoon?

Answer»

While packing the hamper, Harris packed a strawberry jam on top of a tomato and squashed it. So, they had to pick out the tomato with a teaspoon which was a messy and time-consuming task.

743.

Statement-1 : The electric dipole moment of a non-polar molecule is zero. Statement-2 : In non polar molecule, the centre of charge of both the atoms lie on the same point. (1) Statement-1 is True, Statement-2 is True (2) Statement-1 is False. Statement-2 is True (3) Statement-1 is True, Statement-2 is False (4) Statement-1 is False, Statement-2 is False.

Answer»

(3) Statement-1 is True, Statement-2 is False

744.

What do you learn from this story?

Answer»

Children will answer this question on the basis of their understanding of the story.

745.

The electric and magnetic fields are1. Two conflicting phenomenon, one supressing to each other2. Two sequential phenomenon, with a retardation effect between the two fields3. Two parts of one unique phenomenon4. Two distinctly separate and isolated phenomenon

Answer» Correct Answer - Option 3 : Two parts of one unique phenomenon

The field or space around a charge particle where its force can be experienced by any other charged particle is called the electric field of former charge. The area around a magnet within which magnetic force is exerted, is called a magnetic field. It is produced by moving electric charges. Electric and magnetic field both are two parts of one unique phenomenon.

746.

“Bhagwat Singh ji was a big man with a big heart.” Comment. भगवत सिंह बड़े हृदय वाले एक बड़े आदमी थे।” टिप्पणी लिखें।

Answer»

Bhagwat Singh ji is the master of the haveli, ‘Jeevan Niwas’. He is kind, generous and merciful. He treats the maids and their children with affection. He gives Pari, the oldest maid, the regard of a mother. He scolds Heeralal, the driver, for misbehaving with Lakshmi. When he sees he is repentent, he forgives him. He arranges good schooling for Sita who is a maid’s daughter. Hence he was a big man with a big heart.

भगवत सिंह जी जीवन-निवास हवेली के स्वामी हैं। वह दयालु, उदार तथा रहम दिल हैं। वह सेविकाओं और उनके बच्चों के साथ प्यार से बर्ताव करते हैं। वह सबसे पुरानी सेविका परी को माँ का सम्मान देते हैं। वह हीरालाल ड्राईवर को सख्ती से फटकारते हैं क्योंकि उसने लक्ष्मी के साथ बदतमीजी की। जब वह देखते हैं कि वह पछतावा कर रही है तो वह उसे क्षमा कर देते हैं। वह लक्ष्मी की पुत्री सीता के लिये अच्छी शिक्षा की व्यवस्था करते हैं। अत: वह एक बड़े हृदय वाले बड़े आदमी थे।

747.

Comment on Bhagwat Singhji’s wife’s sadness when Sita was going to be married. जब सीता का विवाह हो रहा था तो भगवत सिंह जी की पत्नी की उदासी पर अपनी राय बतायें।

Answer»

Sita was a servant’s daughter whose mother had left her when she was in the suckling state. But her wedding was a family celebration as it had the full support of the mistress. But the mistress had watched the festivities with a sad heart. She could not forget Sita’s mother, Lakshmi especially when she was somewhere in the city. The mistress wept quietly. She felt that the parents’ presence was essential on the wedding of their daughter.

सीता एक नौकर की लड़की थी जिसकी माँ उसे उस समय छोड़ कर चली गई जब वह माँ का दूध पीने की अवस्था में थी। परन्तु उसका विवाह हवेली के पर्व जैसा था क्योंकि उसे मालकिन का पूरा समर्थन था। परन्तु मालकिन ने इन खुशियों को दु:खी हृदय से देखा था। वह सीता की मां लक्ष्मी को नहीं भूल सकी और विशेषकर उस समय जबकि वह शहर में थी। वह महसूस कर रही थी कि माता-पिता की उपस्थिति उनकी बेटी के विवाह पर अति आवश्यक है।

748.

Read the following passage and answer the questions that follow :Not because I pretend to be wise or pose as unusual. There are two chief reasons : because I don’t really like the telephone, and because I find I can still work and play, eat, breathe, and sleep without it. Why don’t I like telephone? Because I think it is a pest & time-waster. It may create unnecessary suspense and anxiety, as when you wait for an expected call that doesn’t come, or irritating delay, as when you keep ringing a number that is always engaged.As for speaking in a public telephone box, that seems to me really horrible. You would not use it unless you’re in a hurry and because you are in a hurry you will find other people waiting before you. When you do get into the box, you are half asphyxiated by stale, unventilated air, flavoured with cheap face powder and chain smoking; and by the time you have begun your conversation your back is chilled by the cold looks of somebody who is fidgeting to take your place.If you have a telephone in your house, you will admit that it tends to ring when you least want it to ring-when you are asleep, or in the middle of a meal or a conversation, or when you are just going out or when you are in your bath. Are you strong minded-enough to ignore it, to say to yourself, ‘Ah well, it will all be the same in a hundred years’ time? You are not. You think there may be some important news or message for you. Have you never rushed dripping from the bath, or chewing from the table, or dazed from bed, only to be told that you are a wrong number? You were told the truth. In my opinion all telephone numbers are wrong numbers. If, of course, your telephone rings and you decide not to answer it, then you will have to listen to an idiotic bell ringing and ringing in what it supposed to be the privacy of your own home. You might as well buy a bicycle bell and ring it yourself.If, like me, one is without a telephone, somebody is sure to say ! Oh, but don’t you find you have to write an awful lot of letters?’ The answer to that is ‘Yes, but I should have to write an awful lot of letters anyway. This may bring the remark ‘Ah, well, if you don’t have a telephone, at least you must have a typewriter.’ And the answer to that is ‘No’. What, no telephone and no typewriter! Do please explain why.’ Well, I am a professional man of letters, and when I was younger.I thought a typewriter would be convenient. I even thought it was necessary, and that editors and publishers would expect anything sent to them to be typewritten. So I bought a typewriter and taught myself to type, and for some years I typed busily. But I didn’t enjoy typing. I happen to enjoy the act or writing. I enjoy forming letters or words with a pen, and I never could enjoy tapping the key of a typewriter.There again, there was a bell-only a little bell that rang at the end of each line-but still, a bell. And the fact is, I am not mechanically minded, and the typewriter is a machine. I have never been really drawn to machines. I don’t like oiling, cleaning, or mending them. I do not enjoy making them work. To control them gives me no sense of power-or not of the kind of power that I find interesting. And machines do not like me. When I touch them they tend to break down, get jammed, catch fire, or blow up.1. Does the author find telephone a nuisance? Why?2. Do you agree with all that is said in the above passage?3. Describe the author’s observation while using a telephone box4. Are you mechanically minded to use all types of gadgets? If so, what do you think can be done for those who are not?5. What irritates the author the most while using a typewriter?

Answer»

1.The author finds telephone a nuisance because it is a pest and time-waster. And also it may create unnecessary suspense and anxiety.

2. Yes, to some extent I agree with it all. Any gadget should be used only when it is re quired.

3. Use of a telephone box is a horrible experience for the writer. Due to unventilated air, smoking and other things, it is suffocating.

4. People who want to use all type of gadgets should develop their interest in them.

5. They should look at both positive and negative aspects of any machinery.

749.

Name two types of animal feed and write their functions.

Answer»

The two types of animal feed are:-

  1. Fodder
  2. Forage

Functions of fodder feed:

  • It keeps the animal in good health.
  • It is palatable and easy for digestion.
  • It provides fresh nutrients in their natural form.

Functions of forage feed:

  • It helps in providing excellent,generally dilute sources of nutrients.
  • It supplies particularly valuable fibre for rumen digestion.
  • Being home grown and, in many cases, more sustainable and economic than other feeds.

(i) Roughage is largely fibre. 

(ii) Concentrates are rich in proteins and nutrients.

750.

Which one of the following nutrients is not available in fertilizers?(a) Nitrogen(b) Phosphorus(c) Iron(d) Potassium

Answer»

Correct answer is (c) Iron