

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
1. |
For car battery which one is correct statement ? (A) Cathode is Lead dioxide (PbO2) and anode is Lead (Pb) (B) Cathode is Lead dioxide (PbO2) and anode is Copper (Cu) (C) Cathode is Copper (Cu) and anode is Lead dioxide (PbO2) (D) Cathode is Copper (Cu) and anode is Lead (Pb) |
Answer» (A) Cathode is Lead dioxide (PbO2) and anode is Lead (Pb) |
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2. |
CH3MgI will give methane with (A) C2H5OH (B) CH3–CH2–NH2(C) both of these (A and B) (D) None of these |
Answer» Correct option (C) both of these (A and B) Explanation: Grignard’s reagent reacts with primary or secondary amines to give alkanes but fail to react with tertiary amines due to lack of hydrogen on nitrogen. R-MgX + R-NH₂ → R-H + Mg(NHR) The reaction between ethanol and Grignard is shown below: CH3CH2OH + R’MgX → CH3CH2O-(MgX)+ + R’-H |
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3. |
Lowering of vapour pressure is highest for (a) 0.1 M BaCl2 (b) 0.1 M glucose (c) 0.1 M MgSO4 (d) urea |
Answer» Correct option (a) 0.1 M BaCl2 Explanation: Lowering of vapour pressure is directly proportional to the van't Hoff faotor (i). For BaCl2,i = 3 (maximum) Thus, BaCl2 has highest value relative lowering of vapour pressure. |
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4. |
The IUPAC name of the compound CH3–CH(CH3)–CO–CH3 is (A) 3-methyl-2-butanone (B) 2-methyl-3-butanone (C) Isopropyl methyl ketone (D) 2ethyl-2methyl pentane |
Answer» Correct option (A) 3-methyl-2-butanone Explanation: The IUPAC name of the compound CH3–CH(CH3)–CO–CH3 is 3-methyl-2-butanone. |
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5. |
Zn converts from its melted state to its solid state, it has hcp structure, then the number of nearest atoms will be (A) 6 (B) 8 (C) 12 (D) 4 |
Answer» Correct option (C) 12 Explanation: HCP means "hexagonal close packing" structure. In hcp, the unit cell is hexagonal and coordination number is 12. |
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6. |
The number of solutions of the system of equations 2x + y - z = 7, x - 3y + 2z = 1 and x + 4y - 3z = 5 is(a) 0 (b) 1(c) 2 (d) 3 |
Answer» Correct Option: (a) 0 Explanation: Given, 2x + y - z = 7 ...(i) x - 3y + 2z = 1 and x + 4y - 3z = 5 ...(iii) Multiplying (i) by 2 and then adding (i) and (ii), we get 5x - y = 15 ...(iv) Multiplying (i) by 3 and then subtracting (iii) from (i), we get 5x - y = 16 ...(v) Eqs. (iv) and (v) shows that they are parallel and so solution does not exist. |
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7. |
The point on the line 4x + 3y = 5, which is equidistant from (1, 2) and (3, 4), is(a) (7,-4) (b) (-10,15)(c) (1/7, 8/7)(d) (0, 5/4) |
Answer» Correct option: (b) (-10,15) Explanation: Let the point (x1, y1) be on the line 4x + 3y = 5. ∴ 4x1 + 3y1 = 5 ...(i) Distance of point (x1, y1) from (1, 2) is (x1 –1)2 + (y1 - 2)2 Distance of point (x1, y1) from (3, 4) is (x1 - 3)3 + (y1 - 4)2 It is given, point (x1, y1) is equidistant from (1, 2) and (3, 4) (x1 –1)2 + (y1 - 2)2 = (x1 - 3)3 + (y1 - 4)2 => x2 + 1 - 2x1 + y2 + 4 - 4y1 = x2 + 9 - 6x1 + y12 + 16 - 8y1 => 4x1 + 4y1 = 20 => x1 + y1 = 5 ...(ii) From Eqs. (i) and (ii), we get y1 =15 and x1 = -10 |
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8. |
If the point (α, α) lies between the lines |2x + y| = 5 then select one of the most appropriate option:(A) |α| < 5/2(B) |α| < 5/3(C) |α| < 7/2(D) |α| < 11/3 |
Answer» Correct option (B) |α| < 5/3 Explanation: |α| < 5/3 as the line y = x intersect lines |2x + 5| = 5 at points (5/3,5/3) & (- 5/3, - 5/3) |
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9. |
SO2 is considered as airpollutant because (A) its concentration increases with temperature increase of atmosphere. (B) It is used as insecticide which is airpollutant (C) It reacts with O2 and H2O to produce acid rain |
Answer» Correct option (D) It is a strong oxidant and oxidizes other components of atmosphere Explanation: Sulphur dioxide (SO2) is considered as air pollutant because it readily undergoes oxidation in the atmosphere to form Sulphur trioxide (SO3). Sulphur trioxide gets convert into H2SO4 in the presence of moisture, which comes down in the form acid rain. |
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10. |
At Critical Micell Concentration (CMC), the surfactant molecules: (A) decompose (B) dissociate (C) associate (D) become completely soluble |
Answer» Correct option (C) associate Explanation: At CMC they associate |
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11. |
A 10gm bullet moving directly upward at 1000 m/s strikes and passes through the center of mass of a 10 kg block initially at rest .The bullet emerges from the block moving directly upward at 400 m/s. What will be velocity of the block just after the bullet comes out of it ?(A) 0.6 m/s (B) 1 m/s (C) 0.4 m/s (D) 1.4 m/s |
Answer» Correct option (A ) 0.6 m /s Explanation: By momentum conservation (10 x 10-3 )1000= (10 x10-3 ) x 400 +10v ⇒ v 0.6m /s |
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12. |
Cordite is a mixture of (A) nitroglycerine, guncotton and vaseline (B) borax, glycerine (C) carborundum and charcoal (D) glycerol and KMnO4 |
Answer» Correct option (A) nitroglycerine, guncotton and vaseline Explanation: Cordite is a mixture of nitroglycerine, guncotton and Vaseline used in ammunition. |
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13. |
Some pairs of ions are given below. In which pair, first ion is more stable than second ion ? |
Answer» Correct option (B) Explanation: 20 Carbocation will be more stable than 10 Substituted carbocation will more stable than simple |
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14. |
Which of these materials requires the least value of magnetic field strength to magnetize it? (A) Nickel (B) Silver (C) Tungsten (D) Sodium Chloride |
Answer» Correct option (A) Nickel Explanation: Nickel is the material that requires the least value of magnetic field strength to magnetize. |
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15. |
Which of the following is a lyophobic colloid : (A) Gelatin (B) Sulphur (C) Starch (D) Gum Arabica |
Answer» Sulphur is a lyophobic colloid. |
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16. |
Permanent magnet has properties retentivity and coercivity respectively, (a) low-low (b) high-high (c) high-low (d) low-high |
Answer» Correct option (b) high-high Explanation: Permanent magnet has high retentivity and high coercivity. |
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17. |
Two circular coils can be arranged in any of the three following situations as shown in figure. Their mutual inductance will be(a) maximum (B) (b) maximum (A) (c) maximum (C) (d) same in ail conditions |
Answer» Correct option (a) maximum (B) Explanation: Mutual inductance depends on their degree of flux linkage. In (B) and (C) the flux linkage is less than A. So, the mutual inductance of (A) will be maximum. |
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18. |
A circular disc of radius R rolls without slipping along the horizontal surface with constant velocity v0. We consider a point A on the surface of the disc. Then, the acceleration of the point A is (a) constant in magnitude (b) constant in direction (c) constant in magnitude as well as direction (d) None of the above |
Answer» Correct option (c) constant in magnitude as well as direction Explanation: The acceleration of the point A is will be constant in magnitude as well as direction |
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19. |
Considering entropy(s) as a thermodynamic parameter, the criterion for the spontaneity of any process the change in entropy is :(A) (ΔS system - ΔS surrounding) > 0(B) ΔS system > 0 only(C) ΔS surrounding > 0 only(D) (ΔS system + ΔS surrounding ) >0 |
Answer» (D) (ΔS system + ΔS surrounding ) >0 |
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20. |
If the line x + 2ky + 3 = 0 is a diameter of the circle x2 + y2 - 6x + 2y = 0, then k is equal to(a) 3 (b) -5(c) -1 (d) 5 |
Answer» Correct option: (a) 3 Explanation: Given, Equation of Circle: x2 + y2 - 6x + 2y = 0 x2 + y2 - 6x + 2y = 0 => (x - 3)2 + (y + 1)2 = 10 From the above equation, Centre: (3, -1) Radius: √10 Since centre lies on the diameter so, (3, -1) will lie on the diameter x + 2ky + 3 = 0 => 3 - 2k + 3 = 0 => 6 - 2k =0 => k = 3 |
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21. |
Let a and b be real numbers such that sin sin a + b = 1/√2 and cos a + cos b = √6/2 then the value of sin (a + b) is :(A) 1/2√2(B) 1/√3 (C) √3/2(D) 2/√3 |
Answer» Correct option (C) √3/2 Explanation: Given L : sin a + sin b = 1/√2 & M : cos a + cos b = √6/2, So L2 + M2 implies cos (a - b) = 0 while L M (using cos (a - b) = 0) gives sin (a + b) = √3/2 |
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22. |
How benzene is converted into n-propyl benzene (A) Friedel-crafts Alkylation (B) Friedel-crafts Acylation (C) Friedel-crafts Alkylation followed by clemmensen reduction (D) Friedal-crafts Acylation followed by clemmensen reduction |
Answer» Correct option (D) Friedal-crafts Acylation followed by clemmensen reduction Explanation: Friedel-Crafts Acylation followed by clemmensen reduction of ketone will give n-propyl benzene. Clemmensen reduction is a chemical reaction described as a reduction of ketones (or aldehydes) to alkanes using zinc amalgam and hydrochloric acid. |
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23. |
Two tunning forks P and Q when set vibration, gives 4 beats s-1 . If a prong of the fork P is filled, the beats are reduced to 2 beats s-1 . What is frequency of P, if that of Q is 250 Hz? (a) 250 Hz (b) 246 Hz (c) 252 Hz (d) 254 Hz |
Answer» Correct option (b) 246 Hz Explanation: Possible frequencies of P are: (250 ± 4) Hz i.e. 246 Hz, 254 Hz When the prong of P is filled, its frequeney becomes greater than the original frequeney of P. Also the frequency of P when the prong is filled reduces to 2 beats s-1 . New possible frequencies of P are: (250 ± 2) Hz i.e. 248 Hz, 252 Hz Since the new frequency increases from the original frequency. So, the new frequency will be 246 Hz. |
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24. |
Which of the following type of forces are present in vulcanised rubber? (a) Weakest intermolecular forces (b) Hydrogen bonding (c) Three dimensional network of bonds (d) Metaluc bonding |
Answer» Correct option (a) Weakest intermolecular forces Explanation: Vulcanised rubber is highly elastic, so weakest intermolecular forces are present in it. |
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25. |
Which of the following electron has minimum energy?(A) n = 3, l = 2, m = –2, s = +1/2(B) n = 4, l= 0, m = 0, s = +1/2(C) n = 4, l= 1, m = +1, s = +1/2(D) n = 5, l = 0, m = 0, s = + 1/2 |
Answer» Correct option (B) n = 4, l= 0, m = 0, s = +1/2 Explanation: For option (A ) electron is in 3d For option (B) electron is in 4s For option (C) electron is in 4p For option (D) electron is in 5s According to A ufbau principle 4s<3d<4p<5s. Hence Answer will be n=4,l=0, m=0,s= +1/2 |
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26. |
Van der waals' real gas, acts as an ideal gas atwhich condition? (a) High temperature. low pressure (b) Low temperature, high pressure (c) High temperature, high pressure (d) Low temperature, low pressure |
Answer» Correct option (a) High temperature. low pressure Explanation: At higher temperature and low pressure real gas acts as an ideal gas. |
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27. |
Gravitational force acts on a particle due to fixed uniform solid sphere. Neglect other forces. Then particle : (A) experiences a force directed along the radial direction only. (B) always moves normal to the radial direction (C) always moves in the radial direction only. (D) always moves in circular orbit. |
Answer» Correct option (A ) experiences a force directed along the radial direction only. Explanation: Circular motion is a special case in gravitational field. T here may be straight line,elliptical paths, but force will be always directed toward the centre of the sphere. |
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28. |
The addition of Br2 to (E) – but – 2 – ene gives (A) (R, R) 2 - 3- dibromobutane (B) (S, S) - 2 - 3 - dibromobutane (C) (R, S) - 2 - 3 - dibromobutane (D) a mixture of (R, R) and (S, S) 2, 3 dibromobutane |
Answer» Correct option (C) (R, S) - 2 - 3 - dibromobutane Explanation: The addition of Br2 to (E) – but – 2 – ene gives (R, S) - 2 - 3 – dibromobutane. |
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29. |
How many σ bonds and π bonds are present in(A) 5 σ + 8 π (B) 9 σ + 7 π (C) 9 σ + 9 π (D) 5 σ + 9 π |
Answer» Correct option (C) 9 σ + 9 π We know that, In 1 single bond = 1 σ bond, In 1 double bond = 1 σ bond + 1 π bond In 1 triple bond + 1 σ bond + 2 π bonds The given compound has 4 single bonds which is equal to 4 σ bond. Also, the given compound has 1 double bond which is equal to 1 σ bond and 1 π bond. In the given compound there are 4 triple bonds which mean 4 σ bond and 8 π bond. Therefore, the given compound has 9 σ and 9 π bonds. |
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30. |
Which of the following are addition polymers? (a) Nylon (b) Melamine formaldehyde resin (c) Orlon (d) All of these |
Answer» Correct option (c) Orlon Explanation: Orlon is an addition polymer as its molecular mass is integral rnultiple of molecular mass of its monomer. |
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31. |
Ionisation energy in group 1A varies in the decreasing order as (a) Li > Na > K > Cs (b) Na > Li > K >Cs (c) Li > Cs > K > Na (d) K > Cs > Na > Li |
Answer» Correct option (a) Li > Na > K > Cs Explanation: In a group atomic size inereases as we move from top to bottom. So, the amount of energy required for ejection of an electron from atom decreases i.e. ionisation energy decreases. So, the decreasing order of ionisation energy in group 1A is as follows: Li > Na > K > Cs |
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32. |
During the adiabatic expansion of 2 moles of an ideal gas, the increase in internal energy was found to be equal to (–200 J). The work done by the gas during the process will be equal to (A) 0 (B) 400 J (C) –200 J (D) 200 J |
Answer» Correct option (D) 200 J Explanation: According to first law of thermodynamics, ∆Q − ∆W = ∆U For adiabatic process, ∆Q = 0 ∆W = −∆U Therefore, the work done during adiabatic process is negative of the change in internal energy. Thus, the work done by the gas during the process will be equal to 200 J. |
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33. |
Which of the following effects of –NO2 group operates on –NH2 group in this molecule?(A) Only –I effect (B) Only +M effect (C) Only –M effect (D) Both –I and –M effect |
Answer» Correct option (A) Only –I effect Explanation: Due to SIR effect –NO2 group goes out of plane of the paper (-I) |
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34. |
Aldol condensation reaction is not given by (a) C6H5CH2CHO (b) C6H5CHO (c) CH3CHO (d) CH3COCH3 |
Answer» Correct option (b) C6H5CHO Explanation: C6H5CHO has no H and α-carbon. Thus, no aldol condensation reaction is given by C6H5CHO |
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35. |
The Markonvikov's rule is best applicable to the reaction(A) C2H4 + HCl (B) C3H6 + Br2 (C) C3H6 + HBr (D) C3H8 + Cl2 |
Answer» Correct option (C) C3H6 + HBr Explanation: Markovnikoc’s rule states that when a protonic acid (HX, where X can be any group with a higher electronegativity than hydrogen) is added to an asymmetric alkene (The groups on the two sides of the double bond are not the same), the hyfrogen atom is added to the carbon with the greatest number of hydrogen atoms while the X is added to the carbon with the least number of hydrogen atoms. For example CH3CH=CH2+HBr → CH3CHBrCH3 |
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36. |
Which one is least reactive in a nucleophilic substitution reaction?(a) CH3CH2CI (b) CH2 =CHCH2CI (c)CH2=CHCI (d)(CH3)3CCI |
Answer» Correct option (c)CH2=CHCI Explanation: Vinyl chloride is least reactive for nucleophilic substitution reaction due to resonance stabilisation of C —Cl bond. |
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37. |
Which compound will be most reactive for electrophilic addition reaction? (A) CH3 – CH = CH – CH3 (B) CH3 – C C≡ CH3 (C) CH3–CH = CHCOOCH3 |
Answer» Correct option (D) Explanation: The compound given in the last option will be most reactive for electrophilic addition reaction. |
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38. |
A train travels east towards Hubli at 80 km/hr. A man on the train runs from the front of the train toward the rear of the train at 10 km/hr with respect to train. As he runs, he carries a plate of fruit with him. He notices a giant spider on the plate and throws the plate away from him (toward the rear of the train) at 20 km/hr with respect to him. Just after that instant, the startled spider jumps towards the man at 5 km/hr with respect to plate. The instant after the spider jumps toward the man, how fast is the spider approaching Hubli?(A) 45km/hr (B) 115 km/hr (C) 55 km/hr (D) 95 km/hr |
Answer» Correct option (C) 55 km/hr Explanation: The relative velocity of man with the respect to train is 80 – 10 = 70 km/hr towards Hubli The relative velocity of plate with respect to man is 70 – 20 = 50 km/hr towards Hubli Therefore, velocity of spider approaching Hubli is 50 + 5 = 55 km/hr. |
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39. |
Petroleum refining involves (A) Vaccum distillation (B) Fractional distillation (C) Steam distillation (D) Simple distillation |
Answer» Correct option (B) Fractional distillation Explanation: Fractional distillation is used in refining of Petroleum, |
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40. |
The increasing order of the first ionization enthalpies of the elements B, P, S and F is: (A) B < P < S < F (B) B < S < P < F (C) F < S < P < B (D) P < S < B < F |
Answer» Correct option (B) B < S < P < F Explanation: I.P. in period increases ↑ left to right. I.P. in group up to down↓ decreases |
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41. |
If two sets A and B are having 39 elements in common, then the number of elements common to each of the sets A x B and B x A are(a) 239 (b) 392(c) 78 (d) 351 |
Answer» Correct option: (b) 392 Explanation: If in two sets A and B n elements are common, then the number of elements common to each of the sets A x B and B x A are n2. So, the number of elements common to each set is 39 x 39 = (39)2. |
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42. |
The sides of a rectangle are 7.01m and 12m. Taking the significant figures into account , the area of the rectangle is :(A) 84m2 (B) 84.1m2 (C) 84.00m2 (D) 84.12m2 |
Answer» Correct option (A ) 84m2 Explanation: Result should have only two significant numbers (same as 12m). |
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43. |
The value of lim (x → ∞) [x√(x2 + 4) - √(x4 + 16)] is equal to(A) 4(B) 8(C) 2(D) 16 |
Answer» Correct option: (C) 2 |
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44. |
If vector a, b, c are non planar vectors, then [vector a x b,b x c, c x a] is equal to(A) 0 |
Answer» Correct option: (b) |
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45. |
If vector a, b, c are non three non-coplanar unit vectors, then [vector a b c] is equal to (A) ±2(B) ±3(C) ±1(D) 2 |
Answer» Correct option: (C) ±1 |
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46. |
Which element is not in first transition series? (A) Fe (B) V (C) Ag (D) Cu |
Answer» Correct option (C) Ag Explanation: The first transition series contain elements from atomic number 21 to 30. But the atomic number of Silver (Ag) is 47. Therefore, Ag is not in first transition series. |
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47. |
Which reagent is capable of giving test both of Aldehyde and Ketones? (A) Tollen reagent (B) Fehling solution (C) 2, 4 dinitrophenylhydrazine (D) Shift reagent |
Answer» Correct option (C) 2, 4 dinitrophenylhydrazine Explanation: 2, 4 dinitrophenylhydrazine is capable of giving test both of Aldehyde and Ketones. As Aldehydes & Ketones both contain the carbonyl group, >C=O, but in aldehydes the carbonyl group is attached to one or two hydrogen atoms whereas in ketones it is linked to two alkyl or aryl groups. |
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48. |
Which reaction will not occur out of the following?(A) Fe + H2SO4 → H2 + FeSO4 (B) Cu + 2AgNO3 → Cu(NO3)2 + 2Ag (C) 2KBr + I2 → 2KI + Br2 (D) CuO + H2 → Cu + H2O |
Answer» Correct option (C) 2KBr + I2 → 2KI + Br2 Explanation: According to the reactivity series, Iodine is less reactive than Potassium. Therefore, Iodine cannot displace Potassium from KBr. So, 2KBr + I2 → 2KI + Br2 will not occur. |
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49. |
The population inversion in helium-neon laser is produced by (a) photon excitation (b) chemical reaction (c) inelastic atomic collision (d) electron excitation |
Answer» Correct option (d) electron excitation Explanation: In helium-neon laser population inversion is produced by electron excitation. |
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50. |
The population inversion in helium-neon laser is produced by (a) photon excitation (b) chemical reaction (c) inelastic atomic collision (d) electron excitation |
Answer» Correct option (d) electron excitation Explanation: In helium-neon laser population inversion is produced by electron excitation. |
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