

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
51. |
The diffraction pattern of a single slit is shown in figure. The point at which the path difference of the extreme rays is two wavelengths is(A) Point 1 (B) Point 2 (C) Point 4 (D) Point 5 |
Answer» Correct option (D) Point 5 Explanation: Diffraction minima are given by ∆D = mλ , where m = 1,2,3,… The second minimum is such that m = 2. |
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52. |
Which frequency produces a sound that can be heard by a person? (A) 100 kHz (B) 40 kHz (C) 2 kHz (D) 30 kHz |
Answer» Correct option (C) 2 kHz Explanation: The audible frequency range for us human beings is about 20 Hz to 20,000 Hz (20 kHz). 2 kHZ lies between 20 Hz to 20 kHz. |
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53. |
Light from the Sun passes through a prism and a spectrum is produced on a screen. A thermometer placed at point X shows a temperature increase. For the given diagram, which type of radiation causes this temperature increase? Select the most appropriate option. (A) Infra-red Rays (B) X-rays (C) Ultraviolet Rays (D) Visible light |
Answer» Correct option (A) Infra-red Rays Explanation: The infra-red rays are responsible for the temperature increase. |
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54. |
The displacement-time (x-t) graph of a body is given asThe corresponding velocity-time (v-t) graphwill be |
Answer» We know that slope of x-t graph gives the velocity. From graph we can conclude that, the slope is initially positive, then zero and after that it becomes negative. |
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55. |
Point charges 30 C, –20 C and 10 C are located at (–1, 0, 2), (0, 0, 0) and (1, 5, –1) respectively. The total electric flux leaving cube of side 6 m centered at the origin is(A) -20/ɛ0(B) 10/ɛ0(C) 20/ɛ0(D) 20/ɛ0 |
Answer» Correct option (B) 10/ɛ0 Explanation: Use Gauss’ law. The contribution to flux is only due to charges located at (−1,0,2) and (0,0,0) since they are inside the cube. |
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56. |
Which of the following is optically active molecule? |
Answer» Correct option (C) Explanation: (A), (B) and (D) are symmetrical, hence they are optically inactive. |
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57. |
Which of the following molecules is optically active ?(A) (i) and (ii) (B) (i) and (iii) (C) (ii) and (iii) (D) (i), (ii) and (iii) |
Answer» Correct option (B) (i) and (iii) Explanation: As a plane of symmetry exist in compound(ii),there is no chirality in it. Hence (i) & (iii) will be optically active. |
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58. |
A method of removing excess solute from a colloidal solution is (A) Distillation (B) Crystallization (C) Dialysis (D) Gas chromatography |
Answer» Correct option (C) Dialysis Explanation: Dialysis is a process of removing a dissolved substance (solute) from a colloidal solution by means of diffusion through a suitable membrane. |
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59. |
For given LR circuit, growth of current as function of time t is shown in graph. Which of the following option represents value of time constant most closely for the circuit?(A) 0.4 s (B) 0.7 s (C) 1 s (D) 2.4 s |
Answer» Correct option (C ) 1s Explanation: In one time constant 63% change occurs in the value of current .T he 63% of maximum current is 1.26 A .It is obvious from graph that current 1.26A corresponds to time which is slightly greater than 0.9sec. Hence option having 1s is most appropriate. |
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60. |
The velocity of a particle is zero at time t= 2 , then (A) acceleration must be zero at t= 2 (B) displacement must be zero in the interval t = 0 to t = 2. (C) acceleration may be zero at t= 2 (D) velocity must be zero for t> 2 |
Answer» Correct option (C ) acceleration may be zero at t=2 Explanation: Let us consider an example in which particle is projected vertically upward from ground at t=0 and it reaches highest point at t=2 Then at that instant(t=2) velocity v=0 but acceleration=−g. Here displacement is non zero for the duration t=0 to t=2. For t>2 the ball again acquires velocity. In this example options(A ),(B ) and (D) are incorrect Let us consider another example in which a particle is moving on horizontal plane and it comes to rest permanently at t=1 ,then this is the one of the special case in which acceleration of particle is zero at t=2. |
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61. |
An electromagnetic wave propagating along north has its electric field vector upwards. Itsmagnetic field vector point towards (a) East (b) North (c) West (d) downwards |
Answer» Correct option (a) East Explanation: According to thumb rule magnetic field will point towards the east |
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62. |
If 5p2 - 7p - 3 = 0 and 5q2 - 7q - 3 = 0, p ≠ q , then the equation whose roots are 5p– 4q and 5q – 4p is :(A) 5x2 + x - 439 = 0(B) 5x2 + 7x - 439 = 0(C) 5x2 - 7x - 439 = 0(D) 5x2 + 7x + 439 = 0 |
Answer» Correct option (C) 5x2 - 7x - 439 = 0 Explanation: Obviously p,q satisfy the equation 5x2 - 7x - 3 = 0. Hence p + q = 7/5, pq = -3/5 given α = 5p - 4q & β = 5q - 4p. The required equation x2 - (α + β) x + αβ = 0 5x2 + 7x - 439 = 0 |
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63. |
If a mixture of FeO and Fe3O4 contains 75% Fe, what will be the percentage amount of each oxide in the mixture? (A) 64.10% FeO and 35.90% Fe2O3 (B) 50% FeO and 50% Fe2O3 (C) 75% FeO and 25% Fe2O3 (D) 35.90% FeO and 64.10% Fe2O3 |
Answer» Correct option (A) 64.10% FeO and 35.90% Fe2O3 Explanation: The mixture contains 64.10% FeO and 35.90% Fe2O3. |
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64. |
Which of the following material is known as lunar caustic ? (A) NaNO3 (B) AgCl (C) AgNO3 (D) NaOH |
Answer» AgNO3 is known as lunar caustic . |
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65. |
Which of the following material is not ferromagnetic in nature ? (A) Al (B) Fe (C) Co (D) Ni |
Answer» Al material is not ferromagnetic in nature. |
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66. |
A very long solenoid is made out of a wire with n turns per unit length. The radius of the cylinder is a and is negligible compared to its length l. The interior of the cylinder is filled with materials such that the linear magnetic permeability varies with the distance r from axis according toThe self inductance of the solenoid is(A) πn2l[μ1b2+μ2a2](B) πn2l[μ1+μ2]a2(C) πn2l [μ1b2 +μ2(a2-b2)](D)πn2 [μ1b2+(μ1+μ2)a2] |
Answer» Correct option (C) πn2l [μ1b2 +μ2(a2-b2)] Explanation: Use the formula for self inductance of the solenoid which is given as L=nΦ/l Here, n is the number of turns and Φ is the magnetic flux. |
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67. |
The front solid cylinder has mass M/3 while the back one solid cylinder has mass 2M/3. The centers of these cylinders are connected by massless rod as shown. Both the cylinders have same radii R. The system is released from rest on the inclined plane. The cylinders roll down. The speed of the rod after system descending a vertical distance h is |
Answer» The correct option is (C). |
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68. |
TEL is a compound used as (a) antibiotic (b) antiseptic (c) antiknocking (d) antioxidant |
Answer» Correct option (c) antiknocking Explanation: TEL(Tetra ethyl Lead) is used as antiknocking agent. |
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69. |
A chord of the parabola y = x2 - 2 + 5 = joins the point with the abscissas x1 x 1 , x2 = 3 Then the equation of the tangent to the parabola parallel to the chord is :(A) 2x - y + 5/4 = 0(B) 2x – y + 2 = 0(C) 2x – y + 1 = 0(D) 2x + y + 1 = 0 |
Answer» Correct option (C ) 2x - y + 1 = 0 Explanation: Equation of chord joining the points Equation of chord joining the points P(1,4) & (3,8) on the parabola is 2x - y + 2 = 0 Tangent parallel to this chord will have the slope i.e dy/dx = 2 ∴ Equation of tangent at (α ,β) on the curve with slope 2 is 2x - y + 1 = 0 |
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70. |
The point of inflection of the function y = ∫(t2 - 3t + 2)dt x ∈[0,x] is :(A) (1/2, 3/2)(B) (3/2, 3/4)(C) (-3/2, -3/4)(D) (-1/2, - 3/2) |
Answer» Correct option (B) (3/2, 3/4) Explanation: Given y = ∫(t2 - 3t + 2)dt x ∈[0,x } Differentiating w.r.to x, we have dy/dx = x2- 3x + 2 & d2y/dx2 = 2x -3. At the point of inflection d2y/dx2 = 0 & second derivative changes sign while passing through the point of inflection. Clearly P(3/2, 3/4). |
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71. |
A long silver tea spoon is placed in a cup filled with hot tea. After some time, the exposed end (the end which is not dipped in tea) of the spoon becomes hot even without a direct contact with the tea. This phenomenon can be explained mainly by: (A) thermal expansion (B) conduction (C) reflection (D) radiation |
Answer» Correct option (B) conduction Explanation: A s atoms in the spoon vibrates about their equilibrium positions and transfer energy from one end to other end. T his process is conduction. |
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72. |
A colloidal system having a solid substanceas a dispersed phase and a liquid as adispersion medium is classified as (a) solid sol (b) gel (c) emulsion (d) sol |
Answer» Correct option (c) emulsion Explanation: It is classified as sol. |
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73. |
Setting of plaster of paris is (a) dehydration (b) oxidation with atmospheric oxygen (c) combination with atmospheric CO2 (d) hydration to yield another hydrate |
Answer» Correct option (d) hydration to yield another hydrate Explanation: Setting of plaster of Paris is exothermic process. |
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74. |
The equation of the normal to the curve y = -√x + 2 at the point of its intersection with the bisector of the first quadrant is : (A) 2x – y + 1 = 0(B) 4x – y + 16 = 0 (C) 4x – y = 16 (D) 2x – y – 1 = 0 |
Answer» Correct option (D) 2x – y – 1 = 0 Explanation: The point of intersection of the curve y = √x + 2 with the bisector of the first quadrant i.e. y = x is (1,1) {Neglect the point (4,0) as it does not satisfy y = x}. Equation of normal to the curve at (1,1) is 2x - y = 1. |
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75. |
Suppose the area of the ΔABC is 10√3 . Length of segments AC and AB be 5 and 8 respectively. Then the angle A is (are) :(A) 45° or 135° (B) 30° or 150°(C) 90° (D) 60° or 120° |
Answer» Correct option (D) 60° or 120° Explanation: Let sides A B , BC & A C be c,a,b respectively in ΔABC . Area of triangle =1/2 bc sin A ⇒ 10√3 = 1/2 5.8 sin A ⇒sin A = √3/2 ∴ 60° or 120° |
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76. |
Let the equation of a curve is given in implicit form as y = tan(x + y). Then d2y/dx2 in terms of y is :(A) 2(1 + y2)2/y2(B) 2(1 + y2)/y6(C) -2(1 + y2)/y6(D) -2(1 + y2)/y5 |
Answer» Correct option (D) (D) -2(1 + y2)/y5 Write y = tan(x + y) as (x + y) tan-1 = y, then differentiating directly implicitly ,we get dy/dx = -2(1 + y2)/y5 |
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77. |
In terms of polar character which one of the following orders is correct?(A) NH3 < H2O < HF <H2S(B) H2S < NH3 < H2O < HF(C) H2O < NH3 < H2S < HF(D) HF < H2O < NH3 <H2S |
Answer» (B) H2S < NH3 < H2O < H F |
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78. |
A body floats in a liquid contained in a beaker. If the whole system falls under gravity, then the upthrust on the body due to liquid is (a) zero (b) equal to the weight of the immersed part of thebody (c) equal to the weight of the body in liquid (d) equal to the weight of the body in air |
Answer» Correct option (d) equal to the weight of the body in air Explanation: There will be no change in the volume immersed and hence the thrust on the body due to liquid is equal to the weight of the body in air. |
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79. |
The average value of rotational kinetic energy of one mole of oxygen gas at temperature T will be (A) RT (B) 3/2 RT(C) 5/2 RT(D) 1/2 RT |
Answer» Correct option (A) RT Explanation: The degree of freedom of 1 mole of O2 gas is 5. Out of which 3 are translational and 2 are rotational. Now, the average kinetic energy is given as F/2 RT where f is degree of freedom for rotational motion. Therefore, the average kinetic energy is RT . |
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80. |
Intramolecular hydrogen bond is present in (a) water (b) o-nitrophenol (c) p-nitrophenol (d) methylamine |
Answer» Correct option (b) o-nitrophenol Explanation: It is present in orth o-nitrophenol. |
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81. |
Among the following compounds of Boron, the species which also forms π- bond in addition to σ- bonds is :(A) BF-4(B) BH3(C) B2H6(D) BF3 |
Answer» Correct option(D) BF3 Explanation: B F3 can form π bond also in addition to σ bond. As F is more electronegative and octate in B is not complete. |
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82. |
Total number of stereoisomers of the following compounds are respectively : (A) 4, 6 (B) 8, 0 (C) 6, 6 (D) 8, 8 |
Answer» 4, 6 number of stereoisomers of the following compounds are respectively. |
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83. |
Identify the Bronsted acid in the following equation: PO3-4 + H2O (l) →HPO2-4 (aq) + OH- (aq)(A) OH- (B) PO43- (C) HPO4 (D) H2O |
Answer» Correct option (D) H2O Explanation: H2O will act as Bronsted acid as provided H+ ion. |
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84. |
Which among the following compounds will have meso form? (A) CH2OH – CHOH – CHOH – CHO(B) CH2OH – CHOH – CHOH – COOH (C) CH2OH – (CHOH)2 – CH2OH (D) C6H3 – CHCl – CHOH – CH3 |
Answer» Correct option (A) CH2OH – CHOH – CHOH – CHO Explanation: The compound CH2OH – (CHOH)2 – CH2OH will have meso form. |
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85. |
Let A = {u, v, w, z} and B= {3 , 5} , then the number of relations from A to B is :(A) 64 (B) 256(C) 1024 (D) 512 |
Answer» Correct option (B) 256 Explanation: If cardinality of A = m & cardinality of B is n, then total no. of relations from A to B Here m = 4 , n = 2 ∴ 28 = 256 |
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86. |
Which among the following will show anisotrophy? (a) Glass (b) Plastic (c) Barium chloride (d) Wood |
Answer» Correct option (c) Barium chloride Explanation: Crystalline solids such as NaCl, BaCl2. etc, will show anisotrophy. |
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87. |
An example of a non-stoichiometric compound is (a) PbO (b) NiO2. (c) Al2O3 (d) Fe3O4 |
Answer» Correct option(d) Fe3O4 Explanation: Non-stoichiometric compound are those compounds in which the ratio of the cations to the anions becomes different from that indicated by the chemicalformula Fe3O4 is a non-stoichiometric compound. |
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88. |
A solution of D-glucose in water rotates the plane of polarised light (a) to the left (b) to the right (c) to either side (d) None of these. |
Answer» Correct option (b) to the right Explanation: D-glucose rotate the plane polrised light to the right. |
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89. |
D – Glucose units in cellulose are joint by (A) α – 1, 4 glycosidic bond (B) β – 1, 6 glycosidic bond (C) β – 1, 4 glycosidic bond (D) Peptide bond |
Answer» Correct option (C) β – 1, 4 glycosidic bond Explanation: Cellulose serves as structural material in plants, providing structural strength and rigidity to plants. It is a linear polymer of D-glucose units joined by β –1,4 glycosidic bonds. |
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90. |
Most reactive alcohol towards esterification is (A) Primary alcohol (B) Secondary alcohol (C) Tertiary alcohol (D) All are same reactive |
Answer» Correct option (A) Primary alcohol Explanation: The order of reactivity for O & H of an alcohol cleavage is goes down from primary to tertiary alcohol (as stability of alcoxide ions is lower in tertiary alcohol). Therefore, tertiary alcohols will be the least reactive towards this reaction, hence the order of increasing reactivity will be Tertiary < Secondary < Primary alcohol. |
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91. |
The basic idea of MASER was first given by (A) Max Planck (B) Einstein (C) Townes (D) Fresnel |
Answer» Correct option (C) Townes Explanation: The basic idea of Microwave Amplification by Stimulated Emission of Radiation (MASER) was first given by Townes. |
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