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1451.

Write true or false for the following statements:The value of G depends upon the mass of two objects.

Answer»

False

Explanation: G is also known as Universal Gravitational Constant. Value of G is 6.67×10−11 Nm2kg-2. The value of G is independent of mass of object and the distance between them.

1452.

Is the motion of the earth around the sun uniform motion?

Answer»

The earth takes 365.25 days to complete one rotation around the sun. Hence it is uniform motion.

1453.

A scooter weighing 150 kg together with its rider moving at 36 kin/hr is to take a turn of radius 30 in. What force on the scooter towards the center is needed to make the turn possible ? Who or what provides this?

Answer»

Weight of the scooter with rider = 150 kg 

Speed = 36 km/hr = 36 × \(\frac{5}{18}\) = 10 m/sec. 

Radius of the turning = 30 m 

The force needed on the scooter towards the centre is centripetal force.

Centripetal force Fc\(\frac{mv^2}{r}=\frac{150\,\times\,10\,\times\,10}{30}\) = 500 N

∴ A centripetal force of 500 N is required on the car. 

This force is provided by the friction between the tyres of the car and road.

1454.

A soft drink bottle is dropped by a water from the top of a hotel whose height is 100 m. It takes T second to reach the ground. Where will it be at T/2 second?A. 50 m from topB. 75 m from bottomC. 25 m from bottomD. 40 m from top

Answer»

Height of Tower = 100 m

Time taken to reach ground = T seconds

Acceleration = a = g = 9.8 ms-2

Initial Speed = u = 0

Final Speed = v

Now, we know that,

S = ut + \(\frac{1}{2}\)at2

100 = \(\frac{1}{2}\)gT2 At t = T and S = 100 m..........1

Let t = \(\frac{T}{2}\) and s = x

Then, x = \(\frac{1}{2}\)a\(\frac{T^2}{2}\)..........2

So, dividing equation 1 by 2, we get,

\(\frac{100}{\times}\) = 4

x = 25 m

So, 25 m from the top at t = \(\frac{T}{2}\) seconds or (100 - 25)m, that is 75 m from the bottom at \(\frac{T}{2}\)seconds.

Hence, option B is correct.

1455.

Two bodies, one held 1 m vertically above the other, are released simultaneously and fall freely under gravity. After 2 second, the relative separation of the bodies will be:A. 4.9 mB. 9.8 mC. 19.6 mD. 1 m

Answer»

Now, initial separation = 1 m

Body 1:

Initial Speed = 0

Acceleration = 9.8 ms-2

Time = 2 seconds

Now, we know that,

S = ut + \(\frac{1}{2}\)at2

So, S1\(\frac{1}{2}\)x 9.8 x 4

S1 = 19.6 m

Body 2:

Initial Speed = 0

Acceleration = 9.8 ms-2

Time = 2 seconds

Now, we know that,

S = ut + \(\frac{1}{2}\)at2

So, S2\(\frac{1}{2}\)x 9.8 x 4

S2 = 19.6 m

Since,S1 = S2 so final separation is also 1 m.

Hence, option D is correct.

1456.

Write true or false for the following statements:The force of attraction between two bodies is called gravity.

Answer»

False

Explanation: Force of attraction between two bodies is called gravitation.
Gravity is the force of attraction on any object by the earth that is a gravitational pull towards the centre of earth.

1457.

What is that force?

Answer»

The force acting on these objects to make them move around another object, instead of moving in straight line in the gravitational force.

1458.

Explain some situations where the center of gravity of man lies out side of the body.

Answer»

Centre of gravity of a human being is located interior to the second sacral vertebra. 

Centre of gravity of man lies out side the body in the following situation : 

a) While doing sit-ups. 

b) While carrying a load like bucket full of water with one hand.

c) While walking on a narrow base like walking on a rope or pole or narrow wall, etc. 

d) While walking with one leg. 

e) As age increases its position changes.

1459.

Write true or false for the following statements:If a spring balance, holding a heavy object is released, it will read zero weight.

Answer»

True

Explanation: Spring Balance gives the weight of the object.

W = m × g

If the heavy object is released, then it will read zero, since no mass implies no weight.

1460.

Where does the centre of gravity of atmosphere of the earth lie?

Answer»

The earth’s atmosphere is about 10,000 km thick, but most of its bulk is contained in the first 11 km above the earth’s surface. Since the earth and its atmosphere are roughly spherical, the centre of the earth is also the centre of gravity of the earth’s atmosphere.

1461.

Where does the center of gravity lie, when a boy is doing sit-ups? Explain.

Answer»
  • The centre of gravity of a boy when he start erect, falls in the foot. 
  • When he is doing sit-ups, the centre of gravity shifts from foot to his base.
  • The weight vector also move from the base. 
  • Hence the boy stretches his hands or bends slightly towards the earth. While doing sit ups, in order to make the weight vector pass through base, so that he acquire stability.
1462.

Write true or false for the following statements: The value of G is high if the radius of the body is more and less if radius is less.

Answer»

False

Explanation: G is universal gravitational constant and is always constant.
G = 6.67×10−11 Nm2kg-2

It does not change with radius of the body and thus is independent of it.

1463.

Write true or false for the following statements:The centre of mass and centre of gravity for a small body lie at the same point.

Answer»

True

Explanation: Centre of mass means the mean position of all the matter in the body.

Centre of Gravity is a point at which the weight of body is considered.
If the object is small then gravitational field is uniform and both lie at the same point.

1464.

Write true or false for the following statements:The gravitational force between two bodies’ changes if a material body is placed between them.

Answer»

False

Explanation: Gravitational Force between two bodies does not change if a material body is placed between them, since according to Newton’s law,

F = G\(\frac{m_1\times m_2}{R^2}\)

Where, G = Universal gravitational Constant

m1, m2 = Masses of bodies

R = Distance between two bodies

Here, F does not depend on the material medium and hence it will not change due to change in medium.

1465.

Two identical satellites A and B are circulating round the earth at the height of R and 2 R respectively, (where R is radius of the earth). The ratio of kinetic energy of A to that of B isA. `1/2`B. `2/3`C. `2`D. `3/2`

Answer» Correct Answer - C
1466.

Assuming that the earth is a solid sphere of radius R, the mass M of the earth would be given byA. `(gR^(2))/(G)`B. `(GR^(2))/(g)`C. `Rsqrt((G)/(g))`D. `Rsqrt((g)/(G))`

Answer» Correct Answer - a
`F=(GmM)/(R^(2)) and =(GM)/(R^(2))`
1467.

In a gravitational field `vectorg = (2hati + 3hatj) N//kg`. What is the work done in moving particle from `(1,1)` to `(2,1//3)` along the line `2x + 3 y = 5`.

Answer» Correct Answer - Zero
1468.

A particle of mass m lies at a distance r from the centre of earth. The force of attraction between the particle and earth as a function of distance is F(r ),A. `F(r) prop 1/(r^(2))` for `r lt R`B. `F(r) prop 1/(r^(2))` for `r ge R`C. `F(r) prop r` for `r lt R`D. `F(r) prop 1/r` for `r lt R`

Answer» Correct Answer - B::C
1469.

Figure shows a uniformly charges hemispherical shell. The direction of electric field at point `p` that is off centre (but in the plane of the largest circle of the hemisphere), will be along A. aB. bC. cD. d

Answer» Correct Answer - C
1470.

The earth attracts a body of mass 2 kg on its surface with a force ofA. `9.8N`B. `19.6N`C. `6.67xx10^(-11)N`D. `2xx6.67xx10^(-11)N`

Answer» Correct Answer - B
`F=W=mg=2xx9.8=19.6N`
1471.

Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.A. `v=1/(2R)sqrt((1/(Gm)))`B. ` v=sqrt(((Gm)/(2R)))`C. `v=1/2sqrt(((Gm)/R))`D. `v=sqrt(((4Gm)/R))`

Answer» Correct Answer - C
`F_(G)=(Gm^(2))/(4R^(2))implies(Mv^(2))/R(Gm^(2))/(4R^(2))`
`:. v=1/2sqrt((GM)/R`
1472.

If `W_(1) W_(2)` and `W_(3)` represent the work done in moving a particle from `A` to `B` along three different paths `1.2` and`3` respectively (asshown ) in the gravitational fieled of a point mass m, find the correct relation between ` `W_(1) W_(2)` and `W_(3)` A. `W_(1)gtW_(2)gtW_(3)`B. `W_(1)=W_(2)=W_(3)`C. `W_(1)ltW_(2)gtW_(3)`D. `W_(2)gtW_(1)gtW_(3)`

Answer» Correct Answer - B
As gravitatonal force is a conservative force, work done is independent of path.
`:. W_(1)=W_(2)=W_(3)`
1473.

Why G is called a universal constant?

Answer»

It is so because the value of G is the same for all the pair of the bodies (big or small) situated anywhere in the universe.

1474.

Moon travellers tie heavy weights to their backs before landing on the moon. Why?

Answer»

The value of 'g' on the moon is small, therefore, the weight of moon-travellers will also be small.

1475.

Moon travelers tie heavy weight at their back before landing on the moon. Why?

Answer»

The value of g on moon is small, therefore, the weight of moon travelers will also be small.

1476.

Read the following paragraph carefully and answer the following: Tie a stone to one end of a string. Take the other end in your hand and rotate the string so that the stone moves along a circle. As long as we are holding the string, we are pulling the stone towards us i.e. towards the centre of the circle and are appliying a force towards it. The force stops acting on it if we release the string. In this case, the stone will fly off along a straight line which is the tangent to the circle at the position of the stone when the string is released, because that the directionn of its velocity at that instant of time. You may recall a similar activity in which a 5 rupee coin kept on a rotating circular disc flies off the disc along the tangent to the disc. Thus, a force acts on any object moving along a circle and it is directed towards the centre of the circle. This is called the Centripetal force. What happens if the string is released?

Answer» The stone will fly off in a straight line along the tangent to the circle.
1477.

Read the following paragraph carefully and answer the following: Tie a stone to one end of a string. Take the other end in your hand and rotate the string so that the stone moves along a circle. As long as we are holding the string, we are pulling the stone towards us i.e. towards the centre of the circle and are appliying a force towards it. The force stops acting on it if we release the string. In this case, the stone will fly off along a straight line which is the tangent to the circle at the position of the stone when the string is released, because that the directionn of its velocity at that instant of time. You may recall a similar activity in which a 5 rupee coin kept on a rotating circular disc flies off the disc along the tangent to the disc. Thus, a force acts on any object moving along a circle and it is directed towards the centre of the circle. This is called the Centripetal force. What is centripetal force?

Answer» The force exerted towards the centre of the circle on an object moving along a circular path is called centripetal force. It is a centre seeking force.
1478.

Read the following paragraph carefully and answer the following: Tie a stone to one end of a string. Take the other end in your hand and rotate the string so that the stone moves along a circle. As long as we are holding the string, we are pulling the stone towards us i.e. towards the centre of the circle and are appliying a force towards it. The force stops acting on it if we release the string. In this case, the stone will fly off along a straight line which is the tangent to the circle at the position of the stone when the string is released, because that the directionn of its velocity at that instant of time. You may recall a similar activity in which a 5 rupee coin kept on a rotating circular disc flies off the disc along the tangent to the disc. Thus, a force acts on any object moving along a circle and it is directed towards the centre of the circle. This is called the Centripetal force. The impressed force on the same is in which direction?

Answer» On the stone, the force is directed towards the centre of the circle.
1479.

For a satellite to orbit around the earth, which of the following must be true?A. It must be above the equator at some timeB. it cannot pass over the poles at any timeC. its height above the surface cannot exceed `36,000 km`D. its period of rotation must be `gt2pisqrt(R//g)` where `R` is radius of earth

Answer» Correct Answer - a,d
`T=2pisqrt((r^(3))/(GM))`
`T_(min)=2pisqrt((R^(3))/(GM))`
`T_(min)=2pisqrt(R/g)`
So choice (A) and (D) are correct choice.
1480.

A satellite S is moving in an elliptical orbit around the earth. The mass of the satellite is very small compared to the mass of the earth.A. the acceleration of `S` is always directed towards the centre of the earthB. the angular momentum of `S` about the centre of the earth chagnes in direction, but its magnitude remains constantC. the total mechanical energy of `S` varies periodically with timeD. the linear momentum of `S` remains constant in magnitude

Answer» Correct Answer - a
1481.

Graviational acceleration on the surface of plane fo `(sqrt6)/(11)g.` where g is the gracitational acceleration on the surface of the earth. The average mass density of the planet is `(2)/(3)` times that of the earth. If the escape speed on the surface of the earht is taken to be `11 kms^(-1)` the escape speed on teh surface of the planet in `kms^(-1)` will beA. `3`B. `6`C. `9`D. `12`

Answer» Correct Answer - A
`g=(GM)/(R^(2))=(G(4/3piR^(3))rho)/(R^(2))`
`gproprhoR, Rpropg/rho`
Now escape velocity, `v_(e)=sqrt(2gR)`
`v_(e)propsqrt(gR), v_(e)propsqrt(gxxg/rho)propsqrt((g^(2))/rho)`
`(v_(e))_("planet")=(11kms^(-1))sqrt(6/121xx3/2)=3 km s^(-1)`
1482.

Gravitational force is a conservation and medium independent force. Its nature is attractive. Gravitational field intensity and gravitational potential gives information about gravitational fied in vector and scaler form respectively. Actually gravitational fied intensity is equal to the negative of the negative of teh potential gradient. potential energy is defined for only conservation force. it is also equal to the total energy in escaping condition. gravitational potential is either negative or zero but can never be positive due to attractive nature of gravitational force. The gravitational potential inside a hollow sphere (mass `M`, radius `R`) at a distance `r` from the centre is:A. zeroB. `-(GM)/R`C. `-(GM)/r`D. `-(GM)/(r^(2))`

Answer» Correct Answer - b
1483.

Gravitational force is a conservation and medium independent force. Its nature is attractive. Gravitational field intensity and gravitational potential gives information about gravitational fied in vector and scaler form respectively. Actually gravitational fied intensity is equal to the negative of the negative of teh potential gradient. potential energy is defined for only conservation force. it is also equal to the total energy in escaping condition. gravitational potential is either negative or zero but can never be positive due to attractive nature of gravitational force. Gravitational potential versus distance `r` graph is represented in figure. The magnitude of gravitational field intensity is equal to A. `8` Newton `// kg`B. `4` Newton `// kg`C. `6` Newton`// kg`D. `2` Newton`//kg`

Answer» Correct Answer - a
1484.

A particle of mass `m` is placed at a distance `x` from the centre of ring along the line through the centre of the ring and perpendicular to its plane. Gravitational potential energy of this system.A. `-(GMm)/(sqrt(a^(2)+x^(2)))`B. `(GMm)/a`C. `(GMm)/x`D. None of these

Answer» Correct Answer - a
1485.

A particle of mass `m` is placed at a distance `x` from the centre of ring along the line through the centre of the ring and perpendicular to its plane. The force, when `x=0` :A. `(GMm)/(x^(2))`B. `(GMmx)/(sqrt(a^(2)+x^(2)))`C. `(GMmx)/((a^(2)+x^(2))^(3//2))`D. Zero

Answer» Correct Answer - d
1486.

A particle of mass `m` is placed at a distance `x` from the centre of ring along the line through the centre of the ring and perpendicular to its plane. if `xlt lta`, the particle of mass `m` will:A. perform oscillatory motionB. perform `S.H.M.`C. bothD. None

Answer» Correct Answer - b
1487.

Define relative density of a solid. State its unit. How is it related to its density? Write mathematical expression for relative density. What conclusion do you draw if relative density of a substance is (a) greater than 1, (b) less than 1 and (c) equal to 1?

Answer»

Relative density refers to the ratio of the density of a substance to the density of water. 

Relative Density = \(\frac{Density\,of\,a\,substance}{density\,of\,water}\)

(a) greater than 1: If the relative density is greater than 1, that means that the density of a substance is greater than the density of water. 

(b) less than 1: If the relative density is less than 1, that means that the density of a substance is less than the density of water. 

(c) equal to 1: If the relative density is equal to 1, that means that the density of a substance is equal to the density of water.

1488.

It was raining heavily one day. Prateek made a paper boat and started playing with it in a water pool at road side. He then got his toys and dolls and made them boat riders the boat sank in water. Prateek did not lose courage. He made another boat and used lighter toys as passengers and this time boat did not sink in water. (a) Why did not sink when loaded with dolls and toys? (b) Which force is exerted by water on objects immersed in it? (c) What qualities are shown by Prateek?

Answer»

(a) The boat did not sink when Prateek used lighter dolls as the density of the dolls and the boat is much less than the density of water. 

(b) Buoyant Force is exerted by water on the objects immersed in it. The gravitational pull exerted on them is much more than the buoyant force therefore they sank. 

(c) Prateek is very patient as well as determined to achieve his goals. He does not lose hope and keeps on trying to fulfil what he wants.

1489.

A sheet of a paper falls slower than a coin under gravity through the air. Why?

Answer»

Gravitational force depends on the mass of the object. The coin has more mass than the sheet of paper, therefore, force exerted on the coin will be more. On the other hand surface area of the sheet is more than coin; therefore air resistance will be more on the sheet of paper causing it to fall slow.

1490.

State Archimedes’ principle. List its two applications.

Answer»

Archimedes’ principle states that when an object is fully or partially immersed in a fluid, it experiences an upward force that is equal to the weight of the fluid displaced by it. 

The two applications of Archimedes principle are: 

i) It is used to design ships and submarines. 

ii) It is used to design hydrometer which is used to measure the density of different liquids.

1491.

A wooden block is kept on a table top. The mass of the wooden block is 5 kg and its dimensions are 40 cm × 20 cm × 10 cm. Find the pressure exerted by the wooden block on the table top if it is made to lie on the table top with its sides of dimensions (a) 20 cm × 10 cm and (b) 40 cm × 20 cm.

Answer»

Mass of wooden block = 5 kg

Dimension of the block = 40 cm × 20 cm × 10 cm= 0.4 m × 0.2 m × 0.1 m 

Force = mass × acceleration due to gravity= 5 kg × 9.8 m/s2 

= 49 N 

(a) 20 cm × 10 cm 

Area = 20 cm × 10 cm = 0.2 m × 0.1 m = 0.02 m2 

Pressure =\(\frac{Force}{Area}\)\(\frac{49}{0.02}\) = 2450 N/m2 

(b) 40 cm × 20 cm 

Area = 40 cm × 20 cm = 0.4 m × 0.2 m = 0.08 m2 

Pressure =\(\frac{Force}{Area}\) = \(\frac{49}{0.08}\) = 612.5 N/m2.

1492.

The relative density of silver is 10.8. The density of water is 103kgm–3 . What is the density of silver in SI units?

Answer»

Relative density of silver = 10.8 

The density of water = 103 kg-m–3 

Relative Density =\(\frac{Density\,of\,a\,substance}{density\,of\,water}\) = \(\frac{Density\,of\,silver}{density\,of\,water}\)

10.8 x 103 kgm–3 = Density of silver 

The density of silver = 10800 kg-m–3

1493.

How will the magnitude of buoyancy exerted by a liquid change if its volume is doubled?

Answer»

As the magnitude of buoyant force depends on the density of the liquid therefore if volume increases it will decrease the density and hence there will be no effect on the magnitude of buoyant force as it depends both on density and volume proportionally.

B = ρfvg

B- buoyant force in N

ρffluid density in kg/m3

V - displaced body volume of liquid in kg/m3

g = 9.806 m/s2 ( standard gravity)

1494.

A student was asked a question ‘why are there summer and winter for us? He replied as ‘since Earth is orbiting in an elliptical orbit, when the Earth is very faraway from .the Sun (aphelion) there will be winter, when the Earth is nearer to the Sun (perihelion) there will be winter. Is this answer correct? If not, what is the correct explanation for the occurrence of summer and winter?

Answer»

Early astronomers proved that Earth is spherical in shape by looking at the shape of the shadow cast by Earth on the Moon during lunar eclipse.

1495.

At present the acceleration due to gravity at latitude `45^(@)` on earth is `9.803ms^(-2)`. If earth stops rotating, the acceleration due to gravity at the same place would be`" "(Romega^(2)=0.034ms^(-2))`A. `9.837ms^(-2)`B. `9.82ms^(-2)`C. `9.81ms^(-2)`D. `9.786ms^(-2)`

Answer» Correct Answer - b
`g_(phi)=g-Romega^(2)cos^(2)phi`
`=g-Romega^(2)((1)/(sqrt2))^(2)=g-(Romega^(2))/(2)`
`g=g_(phi)+(Romega^(2))/(2)=9.803+(0.034)/(2)` ltbRgt `=9.82ms^(-2)`.
1496.

The depth `d`, at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R = radius of the earth)A. `(R)/(n)`B. `R((n-1)/(n))`C. `(R)/(n^(2))`D. `R((n)/(n+1))`

Answer» Correct Answer - b
`g_(d)=g(1+(d)/(R))`
`(1)/(n)g=g(1-(d)/(R))`
`(1)/(n)-1=-(d)/(R)`
`(1)/(n)-1=-(d)/(R)`
`-1(1)/(n)=(d)/(R)`
`((n-1)/(n))R=d`
`therefore" "d=((n-1)/(n))R.`
1497.

Gravitational force is a weak force but still it is considered the most important force. Why?

Answer»

Gravitational force plays an important role for initiating the birth of stars, for controlling the entire structure of the universe and evolution of the universe. It helped to explain many natural phenomena.

1498.

Assertion : The difference in `g` at the poles and the equator of the earth is directly proportional to the square of its angular velocity. Reason : The value of `g` is minimum at the equator and maximum at poles.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If the assertion and reason both are false.

Answer» Correct Answer - B
1499.

The gravitional force between two point masses `m_(1)` and `m_(2)` at separation `r` is given by `F=k (m_(1)m_(2))/r^(2)` The constant `k`A. Depends on system of units onlyB. Depends on medium between masses onlyC. Depends on both (a) and (b)D. Is independent of both (a) and (b)

Answer» Correct Answer - A
1500.

Statement -1: Gravitational force between two particles is negligibly small compared to the electrical force. Statement-2 :The electrical force is experienced by charged particles only.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If the assertion and reason both are false.

Answer» Correct Answer - B