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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Find the magnetic field when the magnetic vector potential is a unit vector.(a) 1(b) -1(c) 0(d) 2I have been asked this question during an internship interview.My question is from Magnetostatic Properties topic in chapter Magnetostics of Electromagnetic Theory

Answer» RIGHT option is (c) 0

Easiest explanation: We KNOW that H = -Grad(V), where is a UNIT vector. The gradient of a constant/unit vector will be zero. Thus the MAGNETIC field INTENSITY will be zero.
2.

Choose the best relation.(a) A = -Div(V)(b) V = Curl(A)(c) H = -Grad(V)(d) V = Div(E)This question was addressed to me in examination.This intriguing question comes from Magnetostatic Properties topic in division Magnetostics of Electromagnetic Theory

Answer»

The CORRECT answer is (c) H = -GRAD(V)

The best I can explain: For any magnetic FIELD, the magnetic field intensity will be the negative gradient of the potential of the field. This is given by H = -Grad(V).

3.

The permeability and permittivity of air or free space is unity. State true/false.(a) True(b) FalseThe question was asked during an online exam.This intriguing question originated from Magnetostatic Properties in chapter Magnetostics of Electromagnetic Theory

Answer» RIGHT option is (b) False

Easy EXPLANATION: The permeability and permittivity of free space or AIR is always unity. This implies that the air is always READY to store electric or magnetic CHARGES subjected to it.
4.

Which of the following relation will hold good?(a) D = μ H(b) B = ε E(c) E = ε D(d) B = μ HI had been asked this question in an interview.This interesting question is from Magnetostatic Properties in chapter Magnetostics of Electromagnetic Theory

Answer»

Correct answer is (d) B = μ H

To explain I would say: The magnetic flux density is the product the PERMEABILITY and the magnetic FIELD INTENSITY. This STATEMENT is always true for any MATERIAL (permeability).

5.

Using Maxwell equation which of the following cannot be calculated directly?(a) B(b) D(c) A(d) HThis question was addressed to me in an internship interview.This key question is from Magnetostatic Properties in portion Magnetostics of Electromagnetic Theory

Answer»

Right choice is (C) A

To ELABORATE: The Maxwell equations can be used to compute E,H,D,B and J DIRECTLY. It is not possible to FIND the magnetic vector POTENTIAL A directly.

6.

Find the energy of a coil of inductance 18mH and current passing through it 1.25A.(in 10^-3 order)(a) 14.06(b) 61(c) 46.1(d) 28.12The question was posed to me in an international level competition.Question is from Magnetostatic Properties in portion Magnetostics of Electromagnetic Theory

Answer»

Correct answer is (a) 14.06

Easiest EXPLANATION: The magnetic energy possessed by a COIL is given by E = 0.5 x LI^2. PUT L = 18 x 10^-3 and I = 1.25, thus we get E = 0.5 x 18 x 10^-3 x 1.25^2 = 14.06 x 10^-3 UNITS.

7.

Find the total flux in a coil of magnetic flux density 12 units and area 7 units.(a) 0.84(b) 0.96(c) 8.4(d) 9.6I had been asked this question by my college professor while I was bunking the class.My doubt is from Magnetostatic Properties topic in chapter Magnetostics of Electromagnetic Theory

Answer»
8.

Find the inductance when the energy is given by 2 units with a current of 16A.(a) 15.6mH(b) 16.5mH(c) 16.8mH(d) 15.8mHThe question was asked in semester exam.Asked question is from Magnostatic Energy in portion Magnetostics of Electromagnetic Theory

Answer»

The correct OPTION is (a) 15.6mH

To EXPLAIN I would say: The energy stored in an inductor is GIVEN by E = 0.5 LI^2. To get L, PUT E = 2 and I = 16 and thus L = 2E/I^2 = 2 X 2/16^2 = 15.6mH.

9.

The magnetostatics highly relies on which property?(a) Resistance(b) Capacitance(c) Inductance(d) MomentI got this question in an internship interview.My doubt is from Magnetostatic Properties in division Magnetostics of Electromagnetic Theory

Answer»

The correct option is (c) INDUCTANCE

Explanation: The magnetostatics highly relies on the inductance of the MAGNETIC materials, which decides its BEHAVIOR in the INFLUENCE of magnetic field.

10.

The inductance is the measure of(a) Electric charges stored by the material(b) Emf generated by energising the coil(c) Magnetic field stored by the material(d) Magnetization of dipolesI had been asked this question in an online interview.I need to ask this question from Magnetostatic Properties in division Magnetostics of Electromagnetic Theory

Answer»

The correct answer is (b) Emf generated by ENERGISING the coil

To ELABORATE: The inductance is a property of an electric conductor/coil which measures the amount of emf generated by PASSING CURRENT through the coil.

11.

Calculate the energy when the magnetic intensity and magnetic flux density are 15 and 65 respectively.(a) 755(b) 487.5(c) 922(d) 645I got this question during an interview.My question comes from Magnostatic Energy topic in section Magnetostics of Electromagnetic Theory

Answer» CORRECT answer is (b) 487.5

Easy explanation: The magnetic energy can also be WRITTEN as E = 0.5 μH^2 = 0.5 BH, since B = μH. On substituting B = 65 and H = 15 we get E = 0.5 X 65 x 15 = 487.5 UNITS.
12.

Find the power of an inductor of 5H and current 4.5A after 2 seconds.(a) 25.31(b) 50.62(c) 102.4(d) 204.8I had been asked this question during an interview for a job.My doubt is from Magnostatic Energy topic in portion Magnetostics of Electromagnetic Theory

Answer»

The CORRECT OPTION is (a) 25.31

Explanation: The energy stored in an inductor is given by E = 0.5 LI^2. Thus, put L = 5 and I = 4.5 and we GET E = 0.5 x 5 x 4.5^2 = 50.625 UNITS To get power P = E/t = 50.625/2 = 25.31 units.

13.

Find the turns in an solenoid of inductance 23.4mH , current 2A and area 15cm.(a) 900(b) 400(c) 498(d) 658The question was posed to me in an interview for job.My query is from Magnostatic Energy in section Magnetostics of Electromagnetic Theory

Answer»

The correct choice is (c) 498

The BEST I can explain: The inductance of any MATERIAL(coil) is given by L = μ N^2A/I.

Put L = 23.4 x 10^-3, I = 2 and A = 0.15, we get N as 498 turns.

14.

Calculate the magnetic energy when the magnetic flux density is given by 32 units(in 10^8 order)(a) 4.07(b) 7.4(c) 0.47(d) 7.04The question was asked during an interview.This interesting question is from Magnostatic Energy in portion Magnetostics of Electromagnetic Theory

Answer»

Correct answer is (a) 4.07

To explain I would say: The magnetic energy is given by E = 0.5 μ H^2 and we know that μH = B. On substituting we GET a FORMULA E = 0.5 B^2/μ. Put B = 32 and in AIR μ = 4π x 10^-7, we get E = 0.5 x 32^2/4π x 10^-7 = 4.07 x 10^8 units.

15.

Find the inductance of a material with 100 turns, area 12 units and current of 2A in air.(a) 0.75mH(b) 7.5mH(c) 75mH(d) 753mHThis question was addressed to me in unit test.I'd like to ask this question from Magnostatic Energy in division Magnetostics of Electromagnetic Theory

Answer»

The correct choice is (a) 0.75mH

To EXPLAIN: The inductance of any MATERIAL(coil) is given by L = μ N^2A/I. On substituting N = 100, A = 0.12 and I = 2, we get L = 4π X 10^-7 x 100^2 x 0.12/2 = 0.75 units.

16.

Calculate the magnetic energy when the magnetic intensity in air is given as 14.2 units(in 10^-4 order)(a) 1.26(b) 2.61(c) 6.12(d) 1.62I got this question by my college professor while I was bunking the class.Asked question is from Magnostatic Energy in chapter Magnetostics of Electromagnetic Theory

Answer»

The CORRECT option is (a) 1.26

Easiest explanation: The MAGNETIC ENERGY is given by E = 0.5 μ H^2. PUT H = 14.2 and in air μ = 4π x 10^-7, we get E = 0.5 x 4π x 10^-7 x 14.2^2 = 1.26 x 10^-4 UNITS.

17.

Find the work done in an inductor of 4H when a current 8A is passed through it?(a) 256(b) 128(c) 64(d) 512I have been asked this question in an interview.The origin of the question is Magnostatic Energy in chapter Magnetostics of Electromagnetic Theory

Answer»

Right choice is (b) 128

Explanation: The WORK done in the INDUCTOR will be W = 0.5 x LI^2. On substituting L = 4 and I = 8, we get, W = 0.5 x 4 x 8^2 = 128 units.

18.

Find the induced EMF in an inductor of 2mH and the current rate is 2000 units.(a) 4(b) -4(c) 1(d) -1This question was posed to me in an international level competition.I would like to ask this question from Magnostatic Energy in division Magnetostics of Electromagnetic Theory

Answer»

The correct option is (B) -4

The best I can EXPLAIN: The induced EMF is given by e = -Ldi/dt. PUT L = 2 x 10^-3 and di/dt = 2000 in the equation. We get e = -2 x 10^-3 x 2000 = -4 units.

19.

The current element of the magnetic vector potential for a surface current will be(a) J dS(b) I dL(c) K dS(d) J dVI got this question in an international level competition.My enquiry is from Magnetic Vector Potential in portion Magnetostics of Electromagnetic Theory

Answer»

Correct ANSWER is (c) K dS

The best I can explain: The magnetic vector POTENTIAL for the surface INTEGRAL is GIVEN by A = ∫ μKdS/4πR. It is clear that the CURRENT element is K dS.

20.

The magnetic vector potential for a line current will be inversely proportional to(a) dL(b) I(c) J(d) RThe question was asked during an interview for a job.This key question is from Magnetic Vector Potential topic in division Magnetostics of Electromagnetic Theory

Answer»

Correct answer is (d) R

Explanation: The magnetic VECTOR potential for the LINE INTEGRAL will be A = ∫ μIdL/4πR. It is clear that the potential is INVERSELY proportional to the distance or radius R.

21.

Find the flux density B when the potential is given by x i + y j + z k in air.(a) 12π x 10^-7(b) -12π x 10^-7(c) 6π x 10^-7(d) -6π x 10^-7I got this question in homework.My doubt stems from Magnetic Vector Potential in portion Magnetostics of Electromagnetic Theory

Answer»

The correct option is (B) -12π x 10^-7

For explanation I would say: The field intensity H = -GRAD(V). Since the given potential is a position vector, the gradient will be 3 and H = -3. Thus the flux DENSITY B = μH = 4π x 10^-7 x (-3) = -12π x 10^-7 units.

22.

The Laplacian of the magnetic vector potential will be(a) –μ J(b) – μ I(c) –μ B(d) –μ HThe question was posed to me in homework.I would like to ask this question from Magnetic Vector Potential topic in chapter Magnetostics of Electromagnetic Theory

Answer»

The CORRECT OPTION is (a) –μ J

To explain: The Laplacian of the MAGNETIC vector potential is given by Del^2(A) = -μ J, where μ is the permeability and J is the CURRENT DENSITY.

23.

Find the vector potential when the field intensity 60x^2 varies from (0,0,0) to (1,0,0).(a) 120(b) -20(c) -180(d) 60I had been asked this question at a job interview.The above asked question is from Magnetic Vector Potential in division Magnetostics of Electromagnetic Theory

Answer»

Right answer is (b) -20

The EXPLANATION is: The FIELD intensity H = -GRAD(V). To get V, integrate H with respect to the variable. Thus V = -∫H.dl = -∫60x^2 DX = -20x^3 as x = 0->1 to get -20.

24.

Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.(a) 28(b) 16(c) 12(d) 4The question was posed to me during an interview for a job.Asked question is from Magnetic Vector Potential in section Magnetostics of Electromagnetic Theory

Answer»

The CORRECT CHOICE is (c) 12

Explanation: The field intensity is given by H = – Grad(V). The gradient is given by 0 – 12cos y. At the origin, the gradient will be -12 cos 0 = -12. Thus the field intensity will be 12 units.

25.

The value of ∫ H.dL will be(a) J(b) I(c) B(d) HThis question was addressed to me in an interview.The above asked question is from Magnetic Vector Potential topic in portion Magnetostics of Electromagnetic Theory

Answer»

Correct choice is (b) I

The explanation is: By Stoke’s theorem, ∫ H.dL = ∫ CURL(H).dS and from Ampere’s law, Curl(H) = J. Thus ∫ H.dL = ∫ J.dS which is nothing but CURRENT I.

26.

Find the magnetic field intensity when the magnetic vector potential x i + 2y j + 3z k.(a) 6(b) -6(c) 0(d) 1I got this question in a national level competition.My question comes from Magnetic Vector Potential in division Magnetostics of Electromagnetic Theory

Answer»

The correct choice is (b) -6

Easiest explanation: The magnetic FIELD intensity is given by H = -GRAD(Vm). The gradient of Vm is 1 + 2 + 3 = 6. Thus H = -6 units.

27.

The magnetic vector potential is a scalar quantity.(a) True(b) FalseI had been asked this question in an internship interview.I would like to ask this question from Magnetic Vector Potential in chapter Magnetostics of Electromagnetic Theory

Answer»

Correct OPTION is (b) False

Explanation: The magnetic vector POTENTIAL could be learnt as a scalar. But it is ACTUALLY a vector quantity, which means it has both magnitude and DIRECTION.

28.

Find the magnetic flux density B when E is given by 3sin y i + 4cos z j + ex k.(a) ∫(4sin z i – ex j – 3cos y k)dt(b) -∫(4sin z i – ex j – 3cos y k)dt(c) ∫(4sin y i – ex j + 3cos y k)dt(d) -∫(4sin y i + ex j + 3cos y k)dtThis question was posed to me in a job interview.My question is from Magnetic Field Density in chapter Magnetostics of Electromagnetic Theory

Answer»

Right option is (b) -∫(4sin z i – ex J – 3cos y k)dt

The explanation is: We know that Curl (E) = -dB/dt. The curl of E is (4sin z i – ex j – 3cos y k). To GET B, integrate the -curl(E) with respect to TIME to get B = -∫(4sin z i – ex j – 3cos y k)dt.

29.

Find the magnetic flux density when a flux of 28 units is enclosed in an area of 15cm.(a) 178.33(b) 186.67(c) 192.67(d) 124.33This question was addressed to me in an interview.This is a very interesting question from Magnetic Field Density in division Magnetostics of Electromagnetic Theory

Answer»

The correct answer is (B) 186.67

To explain I WOULD SAY: The total flux is the product of the magnetic flux density and the area. Total flux = B x A. To GET B, put flux/area. B = 28/0.15 = 186.67 units.

30.

If ∫ H.dL = 0, then which statement will be true?(a) E = -Grad(V)(b) B = -Grad(D)(c) H = -Grad(Vm)(d) D = -Grad(A)The question was asked by my college director while I was bunking the class.Query is from Magnetic Field Density in portion Magnetostics of Electromagnetic Theory

Answer»

Right choice is (c) H = -GRAD(Vm)

The EXPLANATION is: The given CONDITION shows that the magnetic field intensity will be the NEGATIVE gradient of the magnetic vector potential.

31.

Find the magnetic flux density of the material with magnetic vector potential A = y i + z j + x k.(a) i + j + k(b) –i – j – k(c) –i-j(d) –i-kThis question was posed to me by my school principal while I was bunking the class.Asked question is from Magnetic Field Density in portion Magnetostics of Electromagnetic Theory

Answer»

Right option is (b) –i – j – k

For explanation I WOULD say: The magnetic flux density is the curl of the magnetic vector POTENTIAL. B = Curl(A). THUS Curl(A) = i(-1) – j(1) + k(-1) = -i – j – k. We get B = -i – j – k.

32.

Find the magnetic field intensity when the flux density is 8 x 10^-6 Tesla in the medium of air.(a) 6.36(b) 3.66(c) 6.63(d) 3.36I got this question in an online interview.The question is from Magnetic Field Density topic in section Magnetostics of Electromagnetic Theory

Answer»

Right answer is (a) 6.36

The explanation: We how that, B = μH. To get H = B/μ, PUT B = 8 X 10^-6 and μ = 4π x 10^-7. Thus H = 8 x 10^-6/ 4π x 10^-7 = 6.36 units.

33.

Find the current when the magnetic field intensity is given by 2L and L varies as 0->1.(a) 2(b) 1(c) 0.5(d) 0I have been asked this question by my school teacher while I was bunking the class.This interesting question is from Magnetic Field Density topic in chapter Magnetostics of Electromagnetic Theory

Answer»

Right answer is (B) 1

Best explanation: From Ampere law, we GET ∫ H.dL = I. Put H = 2L and L = 0->1. On integrating H with respect to L, the current will be 1A.

34.

Find the flux contained by the material when the flux density is 11.7 Tesla and the area is 2 units.(a) 23.4(b) 12.3(c) 32.4(d) 21.3This question was posed to me in exam.My enquiry is from Magnetic Field Density topic in division Magnetostics of Electromagnetic Theory

Answer»

The correct option is (a) 23.4

The best EXPLANATION: The TOTAL FLUX is given by φ = ∫ B.ds, where ∫ds is the area. Thus φ = BA. We get φ = 11.7 x 2 = 23.4 units.

35.

The divergence of H will be(a) 1(b) -1(c) ∞(d) 0This question was posed to me in an interview for job.This question is from Magnetic Field Density topic in division Magnetostics of Electromagnetic Theory

Answer»

Correct CHOICE is (d) 0

To explain: We KNOW that the divergence of B is zero. Also B = μH. THUS divergence of H is also zero.

36.

Find the magnetic field intensity of a toroid of turns 40 and radius 20cm. The current carried by the toroid be 3.25A.(a) 103.45(b) 102(c) 105.7(d) 171This question was posed to me by my college director while I was bunking the class.My enquiry is from Magnetic Field Intensity topic in division Magnetostics of Electromagnetic Theory

Answer»

Correct OPTION is (a) 103.45

To explain: The MAGNETIC FIELD intensity of a toroid is given by H = NI/2πrm. Put N = 40, I = 3.25 and RM = 0.2, we get H = 40 x 3.25/2π x 0.2 = 103.45 units.

37.

Identify which of the following is the unit of magnetic flux density?(a) Weber(b) Weber/m(c) Tesla(d) Weber^-1This question was posed to me in a national level competition.The query is from Magnetic Field Density topic in section Magnetostics of Electromagnetic Theory

Answer»

Correct answer is (C) Tesla

The BEST explanation: The unit of MAGNETIC flux density is weber/m^2. It is ALSO called as tesla.

38.

Find the magnetic field intensity at the radius of 6cm of a coaxial cable with inner and outer radii are 1.5cm and 4cm respectively. The current flowing is 2A.(a) 2.73(b) 3.5(c) 0(d) 1.25The question was posed to me during an interview.Question is taken from Magnetic Field Intensity topic in chapter Magnetostics of Electromagnetic Theory

Answer»

The correct choice is (c) 0

For explanation: The inner radius is 1.5cm and the outer radius is 4cm. It is clear that the magnetic field intensity NEEDS to be CALCULATED outside of the conductor ie, r>4cm. This will lead to zero, SINCE H outside the conductor will be zero.

39.

Find the height of an infinitely long conductor from point P which is carrying current of 6.28A and field intensity is 0.5 units.(a) 0.5(b) 2(c) 6.28(d) 1The question was asked in examination.Origin of the question is Magnetic Field Intensity in division Magnetostics of Electromagnetic Theory

Answer»

Right choice is (b) 2

The explanation: The MAGNETIC FIELD intensity of an INFINITELY long conductor is given by H = I/2πh. Put I = 6.28 and H = 0.5, we get h = 1/0.5 = 2 units.

40.

Find the magnetic field intensity due to a solenoid of length 12cm having 30 turns and current of 1.5A.(a) 250(b) 325(c) 175(d) 375The question was asked in an interview for job.The query is from Magnetic Field Intensity topic in section Magnetostics of Electromagnetic Theory

Answer» RIGHT option is (d) 375

Easiest explanation: The magnetic field intensity of a SOLENOID is GIVEN by H = NI/L = 30 X 1.5/0.12 = 375 units.
41.

Find the electric field when the magnetic field is given by 2sin t in air.(a) 8π x 10^-7 cos t(b) 4π x 10^-7 sin t(c) -8π x 10^-7 cos t(d) -4π x 10^-7 sin tI had been asked this question in an internship interview.This intriguing question comes from Magnetic Field Intensity topic in chapter Magnetostics of Electromagnetic Theory

Answer»

Right CHOICE is (a) 8π x 10^-7 cos t

The BEST I can explain: Given H = 2sin t. We GET B = μH = 4π x 10^-7 x 2sin t = 8πx10^-7sin t.

To get E, integrate B with respect to time, we get 8πx10^-7cos t.

42.

Given the magnetic field is 2.4 units. Find the flux density in air(in 10^-6 order).(a) 2(b) 3(c) 4(d) 5I have been asked this question in an internship interview.My doubt is from Magnetic Field Intensity topic in portion Magnetostics of Electromagnetic Theory

Answer»

Right ANSWER is (b) 3

Easy explanation: We know that B = μH. On SUBSTITUTING μ = 4π X 10^-7 and H = 2.4, we get B = 4π x 10^-7 x 2.4 = 3 x 10^-6 UNITS.

43.

Ampere law states that,(a) Divergence of H is same as the flux(b) Curl of D is same as the current(c) Divergence of E is zero(d) Curl of H is same as the current densityI have been asked this question during an interview for a job.The doubt is from Magnetic Field Intensity topic in chapter Magnetostics of Electromagnetic Theory

Answer»

The correct option is (d) Curl of H is same as the current density

For explanation: Ampere circuital law or Ampere law states that the closed integral of the MAGNETIC FIELD INTENSITY is same as the current enclosed by it. It is given by Curl(H) = J.

44.

The magnetic flux density is directly proportional to the magnetic field intensity. State True/False.(a) True(b) FalseThe question was asked in unit test.The question is from Magnetic Field Intensity topic in section Magnetostics of Electromagnetic Theory

Answer»

Correct answer is (a) True

Explanation: The MAGNETIC FIELD intensity is directly proportional to the magnetic field intensity for a PARTICULAR material (Permeability). It is given by B = μH.

45.

Find the flux enclosed by a material of flux density 12 units in an area of 80cm.(a) 9.6(b) 12/80(c) 80/12(d) 12/0.8This question was addressed to me by my college director while I was bunking the class.This key question is from Maxwell Law in portion Magnetostics of Electromagnetic Theory

Answer» RIGHT choice is (a) 9.6

To elaborate: The total flux in a MATERIAL is the PRODUCT of the flux DENSITY and the area. It is GIVEN by flux = 12 x 0.8= 9.6 units.
46.

The H quantity is analogous to which component in the following?(a) B(b) D(c) E(d) VI have been asked this question in final exam.I need to ask this question from Magnetic Field Intensity in division Magnetostics of Electromagnetic Theory

Answer»
47.

In metals which of the following equation will hold good?(a) Curl(H) = J(b) Curl(J) = dD/dt(c) Curl(H) = D(d) Curl(J) = dB/dtI had been asked this question in an online interview.Query is from Maxwell Law topic in section Magnetostics of Electromagnetic Theory

Answer»
48.

The charge build up in the capacitor is due to which quantity?(a) Conduction current(b) Displacement current(c) Convection current(d) Direct currentThis question was posed to me in an internship interview.Question is from Maxwell Law in section Magnetostics of Electromagnetic Theory

Answer»

Right ANSWER is (b) Displacement CURRENT

To explain I would SAY: The charge in the CAPACITOR is due to displacement current. It is the current in the presence of the dielectric placed between two parallel metal plates.

49.

In which of the following forms can Maxwell’s equation not be represented?(a) Static(b) Differential(c) Integral(d) HarmonicThe question was posed to me during an online exam.I'm obligated to ask this question of Maxwell Law topic in section Magnetostics of Electromagnetic Theory

Answer»

The correct option is (a) Static

Explanation: MAXWELL equations can be represented in differential/point form and integral form alternatively. SOMETIMES, it can be represented by time varying fields called HARMONIC form.

50.

The Faraday’s law states about which type of EMF?(a) Transformer EMF(b) Back EMF(c) Generator EMF(d) Secondary EMFThe question was posed to me in an interview for internship.My question is from Maxwell Law in chapter Magnetostics of Electromagnetic Theory

Answer»

Correct choice is (a) Transformer EMF

The BEST I can explain: The stationary loop in a varying magnetic field results in an induced emf DUE to the change in the flux LINKAGE of the loop. This emf is called as induced or transformer EMF.