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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Area of isosceles triangles |
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Answer» Area of an isosceles triangle can be calculated by construction a median then 2× area of any smaller triangle. Sides Two are equal and one is unequal |
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| 2. |
Your are any avidance because trigonometry all formula is correct |
| Answer» Prove all the formula | |
| 3. |
Solve 3(2u+v)=7uv , 3(u+3v)=11uv |
| Answer» See the last examoles of Chapter 3,Tab bhi na samajh aaye to call me on 8109577348 | |
| 4. |
Difference between rhombus and square |
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Answer» square-all sides are equal and each 90degree.rhombus-eacg diagonal is 90 degree the sides of square make 90 degree angle where as the Rhombus sides does not Square has 90° but rhombus has not..... |
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| 5. |
For all real values of c, the pair of equationsx – 2y = 8, 5x + 10y = c |
| Answer» Sometimes missing | |
| 6. |
What is assummed mean |
| Answer» Assume means to pretend to have or be somebody/something. | |
| 7. |
Difference between consistent and inconsistent. |
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Answer» Consistent=It has unique solution or infinitely many solution.Inconsistent= no solution Consistent system of equation has at least one solution but inconsistent system of equation has no solution |
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| 8. |
The distance of the point (-3,x) from x-axis is. |
| Answer» The distance from x axis is - x | |
| 9. |
What is lemma division method |
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Answer» Thanks Euclid division Lemma is proved statement which is used to prove other statements a=bq+r if we have two positive integers a and b, then there exist unique integers q and r which satisfies the condition a = bq + r where 0 ≤ r ≤ b. |
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| 10. |
Solve the pair of the linear equation by the substitution method x+y=4 |
| Answer» Question is incomplete | |
| 11. |
(X -2 ) (X +1 ) ch -4 |
| Answer» (X -2 ) (X +1 )= x ( x + 1) - 2 (x + 1)= x2 + x - 2x - 2= x2 - x - 2 | |
| 12. |
How many sides of triangle |
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Answer» 3 3 3 three 3 |
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| 13. |
If angle B and angle Q are acute angles such that sin B=sin Q,then prove that angle B=angle Q |
| Answer» Let there be two triangles ABC and PQR such that angle C=90⁰ and angle R=90⁰now, sinB = AC/AB and SinQ=PR/PQsince, sinB = SinQ ⇒ AC/AB = PR/PQ⇒ AC/PR = AB/PQ and also angleC = angleR⇒ by SAS similarity, ∆ABC is similar to ∆PQRsince corresponding angles of similar triangle are equal ⇒ angleB = angleQ | |
| 14. |
Is there any changes in class 10syllabus |
| Answer» No | |
| 15. |
If alfa and beta are roots of n^+5n-1=0 then find 1) alfa^3+beta^32) alfa^2+beta^2 |
| Answer» | |
| 16. |
The difference between the roots of the equation x^2-13x+k=0 is7 find k |
| Answer» k=12 | |
| 17. |
By,the herons formula, the area of triangle ABC is given by triangle= so. unit |
| Answer» | |
| 18. |
If alfa and bita are two roots of quadratic equation 2x^2+6x-5 then find alfa+bita and alfa×bita |
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Answer» C by A =-5 by 2C/A=-5/2 =alpha* beta=c/a=-5/2 =alpha+ beta= -b/a=-6/2=-3 |
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| 19. |
3x^2- 2root6x +2=0 |
| Answer» 3 x^{2} -2√6x+2=03 x^{2} -√6x-√6x+2=0√3 x^{2} *√3 x^{2} -√3x*√2x-√3x*√2x+√2*√2=0√3x(√3x-√2)-√2(√3x-√2)=0(√3x-√2)(√3x-√2)=0x=√2/√3Therefore the equation has two equal roots √2/√3 | |
| 20. |
How many term of AP 17,15,13, 11 whose n th term is -47 |
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Answer» a=17, d=-2,an=a+(n-1)d___-47=17+(n-1)(-2)___-47=17-2n+2___-47=19-2n___-47-19=-2n___-66=-2n___n=33 How we solve linear equation |
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| 21. |
If theeta=1/√7,then cosec2theeta-sin2theeta/cosec2theeta+sec2theeta = |
| Answer» | |
| 22. |
How to do factorisation process for quadratic equation for large numbers |
| Answer» | |
| 23. |
Find an of 96 , 87 ........................ |
| Answer» Sol: a1\xa0= 96 a2\xa0= 87 d = a2\xa0- a1 = 96 - 87 = 9 an \xa0= a1 + (n-1) d an \xa0= 96 + (n-1) 9 an \xa0= 96 + 9n - 9 an \xa0= 87\xa0+ 9n . If the value of the \'n\' is given, then put it into the above equation.Otherwise, the equation is the final answer.:-) | |
| 24. |
One equation of a pair of dependent linear equations is – 5x+ 7y – 2 = 0. The second equation can be |
| Answer» For what kind of dependency you are asking? | |
| 25. |
what is trigonometric |
| Answer» The branch of mathematics in which we study about triangles is known as trigonometry. | |
| 26. |
17/40 write the answer by not divide them. |
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Answer» 17/40Prime factorise both number17=17/ 40=2×2×2×5There is terminating decimal because is in form of2^n 5^ m. So we multiple both number by 5×5=5^217 ×5×5 /40×5×5 =425/1000=425. 17/5^1*2^3 = 17*5^2/5^3*2°3 = 17*25/10^3 =425/1000=0.425 |
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| 27. |
If alpha and beta are the quadratic polynomial x square + PX + q are the |
| Answer» Can you write the questions clearly | |
| 28. |
How many Two digit number divisible by 6 |
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Answer» By A.P. 12,18,24,........96a=12. d=6. l=96l= a+(n-1)d96= 12+(n-1)696-12=(n-1)684=(n-1)684/6=(n-1)14=(n-1)14+1=n15=n 6 is multiple of 2 and 3 thus it has two combination to test i.e.,test for 2 and test for 3 hence total number of two digits number divisible by 6=15 15 |
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| 29. |
What is reciprocal of -6 |
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Answer» -0.1666666667 6 -1/6 -1/6 1/-6 |
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| 30. |
quadrilateral equation |
| Answer» A\xa0quadratic equation\xa0is an\xa0equation\xa0of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.\xa0The Babylonians came up with a technique called “completing the square” to solve common problems with areas by 400 BC. The first purely mathematical try to come up with a\xa0quadratic formula\xa0was done by Pythagoras in 500 BC. Euclid did the same thing in Alexandria, Egypt. Euclid used a purely geometric method. | |
| 31. |
56+368 |
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Answer» 424 424 424 424 |
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| 32. |
What is mid-point theorem |
| Answer» Great answer | |
| 33. |
Yaar ye quadratic equation kitna hard chapter hai |
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Answer» If you want then visit to youtube (Unacademy channel of class 9th and 10th)Teacher\'s name is Surabhi gangwar... She is the best mentor... I\'ll suggest you to watch her videos Simple h Toda aasan hai |
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| 34. |
1/x -1/x-2 =3 |
| Answer» 1/x–1=3x–61–x/x=3x–61–x=3x²–63x²–7+x=0x=–1±√85/6 | |
| 35. |
_ 2/3×3/5+5/2_ 3/5×1/6 |
| Answer» | |
| 36. |
Agar hamare pass 4 zeroes hai to kitne product banega |
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Answer» if you have four zeroes, let say\xa0{tex}\\huge \\alpha, \\beta,\\gamma,\\delta{/tex}Then it belongs to a bi-quadratic or 4th power equation. 0 |
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| 37. |
12.11 |
| Answer» 132 | |
| 38. |
O.4x+0.3 y=1.7O.7x+0.2y=0.8Solve the equationby substitution methos |
| Answer» | |
| 39. |
Find all other zeroes of polynomial f(x) = 2x^4+x^3-14x^2-19x-6 if two of its zeroes are -2 and -1 |
| Answer» 0 | |
| 40. |
Steps of polynomial long division?? |
| Answer» | |
| 41. |
To conduct sports day activities in your rectangular shaped |
| Answer» | |
| 42. |
Exercise 5.1 of chapter five |
| Answer» | |
| 43. |
Who discover mathsmatics |
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Answer» Sorry Archimedes to father h maths Archimedes Maybe Aryabhatt |
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| 44. |
State whether the following are True or false. 1.the value of tan A is always less than 1 |
| Answer» False | |
| 45. |
( sec A + Tan A) ( 1-sin A) = |
| Answer» Cos A answer h i think so .please check it. | |
| 46. |
9 sec A-9 ten A= |
| Answer» 9 answer hoga maybe check it please | |
| 47. |
Working model of mathematics and concept of heart the table up to 20 |
| Answer» | |
| 48. |
monthly planning of the chapters |
| Answer» | |
| 49. |
Prove 15+17√3 |
| Answer» | |
| 50. |
What r the important topics in maths 10th??? |
| Answer» | |